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PHP - Get, Return Api(xml)results, Then Display Each Returned Record In <div></div>
I am looking to accomplish the following but have been hitting a brick wall:
* User enters a single keyword into a text field, and conducts a search keyword search. * The results are pulled from the campusbooks.com API(API docs attached) * result are then output in <div> class and includes all the book details and its corresponding url./img etc I'm trying to simplify this process but I continue to receive syntax errors. A step by step practical explanation would do me justice! Similar TutorialsHi guys, I am working with an old script at the moment, there is one page which just will not populate the table results. I have tried running multiple debugging commands but the only one it flags is the line displaying Quote last; saying it's not a used function. If I comment out this line, no errors are produced but the results do not enter the table. Can anyone shed some light on this please, I've spent hours and hours and banging my head against a brick wall would probably be more constructive right now. Many thanks indeed for any help or advice. <?php mysql_connect("localhost", "$db_user","$db_upwd") or die ("Error - Could not connect: " . mysql_error()); mysql_select_db("$database"); $query="select host,count(*) from badc_mis_prog group by host"; $result = mysql_query($query) or die ("Error - Query: $query" . mysql_error()); $count=0; $hosts=array(); while ($row = mysql_fetch_array($result, MYSQL_NUM)) { $html_hlname=$row[0]; $html_hlname=preg_replace("/</","<",$html_hlname); $html_hlname=preg_replace("/>/",">",$html_hlname); array_push($hosts, $html_hlname,$row[1],0); $count++; } $query="select host,count(*) from badc_mis_prog where reported=1 group by host"; $result = mysql_query($query) or die ("Error - Query: $query" . mysql_error()); while ($row = mysql_fetch_array($result, MYSQL_NUM)) { $html_hlname=$row[0]; $html_hlname=preg_replace("/</","<",$html_hlname); $html_hlname=preg_replace("/>/",">",$html_hlname); for ($i=0; $i<($count*3); $i+=3) { if ($hosts[$i] == $html_hlname) { $hosts[($i+2)]=$row[1]; last; } } } for ($i=0 ; $i<(($count-1)*3); $i+=3){ for ($j=$i+3 ; $j<($count*3); $j+=3){ if ($hosts[($i+1)] < $hosts[($j+1)]){ $temp=array(); $temp[0]=$hosts[$i]; $temp[1]=$hosts[($i+1)]; $temp[2]=$hosts[($i+2)]; $hosts[$i]=$hosts[$j]; $hosts[($i+1)]=$hosts[($j+1)]; $hosts[($i+2)]=$hosts[($j+2)]; $hosts[$j]=$temp[0]; $hosts[($j+1)]=$temp[1]; $hosts[($j+2)]=$temp[2]; } } } print "<br><br><br><center><table border=\"1\">\n"; print "<tr><td>Host Name</td><td>Hosted</td><td>Reported</td><td>Ratio H/R</td></tr>\n"; for ($i=0; $i<($count*3); $i+=3) { if ($hosts[($i+1)]<15){ break;} printf ("<tr><td> %s </td><td> %d </td><td> %d </td><td>%.1f %%</td></tr>\n",$hosts[$i],$hosts[($i+1)],$hosts[($i+2)],(($hosts[($i+2)]/$hosts[($i+1)])*100)); } print "</table></center>\n"; ?> Hello. I am interested in taking a result returned from a database and having it displayed in a certain way/style on the user's screen; For example, the user enters text into a field and hits "submit" - the data is saved in the database then displayed to the user (This part I have working just fine so far due to help I received here.) My question is if I would like to, for example, have said text not simply dumped to the top of the screen, inline, but nicely formatted in a boxed, text area, I assume I will use HTML/CSS, and I was wondering if anyone had any good links/tutorials regarding this topic so I may look further into it (my search thus far has not turned up the correct topic or results). Thank-you in advance for any assistance. ~Matty Greetings! This n00b has a "search engine" dedicated to extracting relevant information from log files. It works by parsing preset fields in the log filename. I'd like to have some notification when the search returns no rows as I am planning to add more search options. Here's my code: <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"> <html><head> <title>LogFile Search</title> <style type="text/css"> <<irrelevant stuff removed>> </style> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"> <script type="text/javascript" language="javascript" src="js/UI.js"></script> </head> <body> <h3 id="myh3">Log File Search</h3><h5>Version 1.0.1</h5> <h4 id="myh4"><ul><li> <<irrelevant stuff removed>> </li></ul></h4> <form method="post" name="LogFile_Search" action="<?php echo $_SERVER['PHP_SELF']; ?>"> <table id="mytable"> <tbody> <tr> <td id="mytd">Result(P|F|N): <input type="text" id="Result_PFN" name="Result_PFN" size="31"/></td> <td id="mytd">Script Version: <input type="text" id="ScriptVersion" name="ScriptVersion" size="31"/></td> </tr> </tbody> </table> <br> <input type="submit" value="Search" onclick="doForm();"> <input type="button" value="Reset" onclick="resetForm();"> </form> <div id="searchResult"> <?php /* Where the logs files are dropped by external process. */ $mydir = $_SERVER['DOCUMENT_ROOT'] . "/LogFile_Search/LogFiles"; /* Handle to directory. */ $dir = opendir($mydir); /* Form variables. */ $Result_PFN = $_POST['Result_PFN']; $ScriptVersion = $_POST['ScriptVersion']; /* Test each field -- triggers JS alert if all are empty. */ if (!empty($Result_PFN)) { doResult_PFN(); } elseif (!empty($ScriptVersion)) { doScriptVersion(); } /* Function for Search on Script version in logfile contents. */ function doScriptVersion() { global $dir; global $mydir; global $ScriptVersion; echo '<table id=\'mytable\'><tbody><tr><td id=\'mytd\'>Log File Name.</td></tr>'; //grabs all log files matching the script version number that's input in the form. $cmd = "find " . $mydir . " -type f -print0 | xargs -0 grep -e 'Test_Version=" . $ScriptVersion . "'"; exec($cmd, $output); //Sort the array using a case insensitive "natural order" algorithm. natcasesort($output); if (count($output) > 0) { foreach ($output as $v) { //Display file name without full path as URL. echo '<tr><td><a href="' . basename($mydir) . '/' . array_pop(explode("/", array_shift(explode(":", $v)))) . '" target="_blank">' . array_pop(explode("/", array_shift(explode(":", $v)))) . '</a></td></tr>'; } } else { echo "<html><body style=\"background-color:#0080c0\"> <script type=\"text/javascript\" language=\"javascript\">alert( 'Nothing found' + '.');</script> </body></html>"; } closedir($dir); echo "</table></body>"; } /* Function for Search on Result marker in file name. */ function doResult_PFN() { global $dir; global $mydir; global $Result_PFN; echo '<table id=\'mytable\'><tbody><tr><td id=\'mytd\'>Log File Name.</td></tr>'; if ($dir) { //List files in directory while (($file = readdir($dir)) !== false) //Ignores OS stuff. if ($file != "." && $file != "..") { //Pattern match for result. if (preg_match("/~(P|F|N)*" . $Result_PFN . "~/i", $file)) { //Sort the array using a case insensitive "natural order" algorithm. natcasesort($file); echo '<tr><td><a href="' . basename($mydir) . '/' . $file . '" target="_blank">' . $file . '</a></td></tr>'; } } else { echo "<html><body style=\"background-color:#0080c0\"> <script type=\"text/javascript\" language=\"javascript\">alert( 'Nothing found' + '.');</script> </body></html>"; } closedir($dir); } echo "</table></body>"; } ?> </div> </body> </html> When doResult_PFN() returns no result, the ELSE portion is never evaluated and no notification is sent to the user. However, I have no problem with doScriptVersion(): it returns an alert. What am I missing? Thanks, Al. I've had a bit of a search around to see if this is possible but have yet to find something. I'm looking to be able to offset the results from opendir or similar function without returning all the files/folders. In other words i'd like to display the file/folder results over multiple pages when there are a lot of files/folders to display. Is this at all possible? Search not functioning. The drop down box to search on Club_Name and Email is blank, clicking search results unchanged ... all suggestions appreciated ... newbie at php. Thanks. <!-- Code below is not functional, trying to query search results, search box with drop down box for two fields--> <table width="50%"> <tr> <td height="30" align="left" bgcolor="#FFFFFF" class="form1" > {$letter_links} </td> <td height="30" align="right" bgcolor="#FFFFFF" class="form1" > <input type=hidden name="sorter" value="{$sorter}"> <table><tr> <form name="search_form" action="{$form.action}" method="post"> <td class="form1" ><input type="text" name="search" value="{$search}"></td> <td class="form1" ><select name="s_type" style=""> {section name=s loop=$types} <option value="{$smarty.section.s.index_next}" {if $types .sel}selected{/if}>{$types .value}</option> {/section} </select></td> <td class="form1"><input type="button" value="{$button.search}" class="button" onclick="javascript: document.search_form.submit();" name="search_submit"></td> </form> </tr></table> </td> </tr> </table> <!-- Code below successfully displays query results --> <form method="post" action="{$file_name}?sel=approve" enctype="multipart/form-data" name="form1" onsubmit="foo(); return false;"> <table cellspacing="2" cellpadding="10" border="1"> <tr align="center"><td>Num</td><td>Club Name</td><td>Login</td><td>Country</td><td>Region</td><td>City</td><td>Address</td><td>Web site</td><td>Email</td><td>Contact Name</td><td>Contact Phone</td><td>Swinging</td><td>Alcohol</td><td>Food</td><td>Entertainment</td><td>Fees</td><td>Approved/<br/>Rejected</td><td>Actions</td></tr> {foreach item=item from=$contest key=key name=foo} <tr align="center"><td><input type="hidden" name="all_approves[{$item.id}]" value="{$item.id}"/>{$key+1}</td><td>{$item.name}</td><td>{$item.login}</td><td>{$item.country_name}</td><td>{$item.region_name}</td><td>{$item.city_name}</td><td>{$item.address}</td><td>{$item.web_site}</td><td>{$item.email}</td><td>{$item.contact_name}</td><td>{$item.contact_phone}</td> <td> {math equation="x - 1" x=$item.swinging assign=index_pos} {$xml_swing[$index_pos].value}</td> <td>{math equation="x - 1" x=$item.alcohol assign=index_pos}{$xml_alco[$index_pos].value}</td> <td>{math equation="x - 1" x=$item.foot assign=index_pos}{$xml_foot[$index_pos].value}</td> <td>{math equation="x - 1" x=$item.entertainment assign=index_pos}{$xml_entertainment[$index_pos].value}</td> <td>{math equation="x - 1" x=$item.fees assign=index_pos}{$xml_fees[$index_pos].value}</td><td> <span> {if $item.is_approved eq '1'} Approved {else} Rejected {/if}</span></td><td align="center"><a href="{$file_name}?sel=edit&id_content={$item.id}">[ Edit ]</a><br/><a href="{$file_name}?sel=delete&id_content={$item.id}">[ Delete ]</a><br/><a href="{$file_name}?sel=approve&id_content={$item.id}">[ Approve ]</a><br/><a href="{$file_name}?sel=reject&id_content={$item.id}">[ Reject ]</a></tr> {/foreach} </table> </form> here is my code... please help <form method="get" action="shit3.php"> <input maxlength="50" size="50" type="text" name="q"> <input type="submit" value="SEARCH"> </form> <?php if (@$_GET['q']) { $var = $_GET['q'] ; $trimmed = trim($var); $limit=1; if ($trimmed == "") { echo "Please enter a search..."; exit; } if (!isset($var)) { echo "Container not found!"; exit; } mysql_connect("localhost", "xxx", "yyy") or die(mysql_error()); mysql_query("SET NAMES 'cp1251'"); mysql_select_db("agaexpor_container") or die("Unable to select database"); //select which database we're using $query = "select * from containertracking where vin like \"%$trimmed%\" order by vin"; $numresults=mysql_query($query); $numrows=mysql_num_rows($numresults); if (empty($s)) { $s=0; } $query .= " limit $s,$limit"; $result = mysql_query($query) or die("Couldn't execute query"); $count = 1 + $s ; while ($row= mysql_fetch_array($result)) { $vin = $row["vin"]; $container = $row["container"]; echo "$count.) VIN: $vin <br />"; echo "container is: $container <br />"; $count++ ; } } ?> I'm hoping this is a simple question. When I use the code below, my twitter search query appears in BOLD within the returned results. I would like to style the search term differently. I can use CSS to style the avatar, author, and other information within the returned results etc, but I can't figure out how to style the search term ($q) within the returned twitter information. Any help would be much appreciated. <?php class twitter_class { function twitter_class() { $this->realNamePattern = '/\((.*?)\)/'; $this->searchURL = 'http://search.twitter.com/search.atom?lang=en&q='; $this->intervalNames = array('second', 'minute', 'hour', 'day', 'week', 'month', 'year'); $this->intervalSeconds = array( 1, 60, 3600, 86400, 604800, 2630880, 31570560); $this->badWords = array('somebadword', 'anotherbadword'); } function getTweets($q, $limit=15) { $output = ''; // get the search result $ch= curl_init($this->searchURL . urlencode($q)); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt($ch, CURLOPT_USERAGENT, $_SERVER['HTTP_USER_AGENT']); $response = curl_exec($ch); if ($response !== FALSE) { $xml = simplexml_load_string($response); $output = ''; $tweets = 0; for($i=0; $i<count($xml->entry); $i++) { $crtEntry = $xml->entry[$i]; $account = $crtEntry->author->uri; $image = $crtEntry->link[1]->attributes()->href; $tweet = $crtEntry->content; // skip tweets containing banned words $foundBadWord = false; foreach ($this->badWords as $badWord) { if(stristr($tweet, $badWord) !== FALSE) { $foundBadWord = true; break; } } $tweet = str_replace('<a href=', '<a target="_blank" href=', $tweet); // skip this tweet containing a banned word if ($foundBadWord) continue; // don't process any more tweets if at the limit if ($tweets==$limit) break; $tweets++; // name is in this format "acountname (Real Name)" preg_match($this->realNamePattern, $crtEntry->author->name, $matches); $name = $matches[1]; // get the time passed between now and the time of tweet, don't allow for negative // (future) values that may have occured if server time is wrong $time = 'just now'; $secondsPassed = time() - strtotime($crtEntry->published); if ($secondsPassed>0) { // see what interval are we in for($j = count($this->intervalSeconds)-1; ($j >= 0); $j--) { $crtIntervalName = $this->intervalNames[$j]; $crtInterval = $this->intervalSeconds[$j]; if ($secondsPassed >= $crtInterval) { $value = floor($secondsPassed / $crtInterval); if ($value > 1) $crtIntervalName .= 's'; $time = $value . ' ' . $crtIntervalName . ' ago'; break; } } } $output .= ' <div class="tweet"> <div class="avatar"> <a href="' . $account . '" target="_blank"><img src="' . $image .'"></a> </div> <div class="message"> <span class="author"><a href="' . $account . '" target="_blank">' . $name . '</a></span>: ' . $tweet . '<span class="time"> - ' . $time . '</span> </div> </div>'; } } else $output = '<div class="tweet"><span class="error">' . curl_error($ch) . '</span></div>'; curl_close($ch); return $output; } } ?> The HTML I have been using with this code is here Code: [Select] <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title>Twitter</title> </head> <body> <?php require('twitter.class.php'); $twitter = new twitter_class(); echo $twitter->getTweets('example search term', 10); ?> </body> </html> This is not my code. It is from a tutorial that can be accessed from here >> http://www.richnetapps.com/php-twitter-search-parser/ Hey Everyone, I want to start out by saying thanks in advance for reading this. Since I started working with the XAMPP package this community has been a great resource, though this is my first post. most of my work has been modifying existing stuff in our network, this is my first project from scratch. I am working on an access control project where I am storing site names and RFID tags in a table, and using PHP to check for existing records. Basically, I want to submit 2 credentials from a host (site and RFID), check if they exist together in the table, if so return TRUE or 1, if not return FALSE or 0. I am new to both PHP and MySQL (although I took a course years ago) so I am looking here for help. On this server I have XAMPP installed and everything I need running. I have a table and created a few records for testing. My current trouble is getting PHP to return the proper values for the SQL query. The SQL query works fine, I think - it returns the number of rows that match and that record. I'm not sure this is the result I need to be able to deal with the way I want. Using other resources my current PHP statement looks like this: Code: [Select] if(mysql_num_rows(mysql_query("SELECT * FROM `users` WHERE 'site_name' LIKE 'berland' AND 'card_id' LIKE '290093C84E' LIMIT 0 , 30"))>0){echo '1';} else {echo '0';} So, my table has the entry as noted in this query above. Final one will be dynamic where the host will be sending those values - I will likely need help with that as well, but small steps first.;-) Anyway, I was playing around with the end statement >0{echo '1';} but wasn't able to make it do what I want. Any help is appreciated. Thank you. Aaron First up quick thanks in advance, any and all help is greatfully recieved
I have this query:
SELECT Player.MembershipNo , Player.FirstName , Player.LastName , Venue.VenueName as Venue, Results.MemCard, Results.EarlyReg , Position.Points as Venue_Points, Results.Date FROM Position , Player , Results , Venue WHERE Player.MembershipNo =Results.MembershipNo AND Results.Position =Position.Position AND Venue.VenueID =Results.VenueID AND Results.Date BETWEEN '2014-07-01' AND '2014-09-30' ORDER BY MembershipNo, Venuewhich returns these results: +--------------+-----------+----------+-------------------+---------+----------+--------------+------------+ | MembershipNo | FirstName | LastName | Venue | MemCard | EarlyReg | Venue_Points | Date | +--------------+-----------+----------+-------------------+---------+----------+--------------+------------+ | 0 | Bob | Stevens | The Dolphin | 1 | 1 | 32 | 27/08/2014 | | 0 | Bob | Stevens | The Enigma Tavern | 1 | 1 | 40 | 08/07/2014 | | 0 | Bob | Stevens | The Enigma Tavern | 1 | 1 | 16 | 15/07/2014 | | 1 | Dave | Green | The Dolphin | 1 | 1 | 20 | 13/08/2014 | | 1 | Dave | Green | The Dolphin | 1 | 1 | 2 | 20/08/2014 | +--------------+-----------+----------+-------------------+---------+----------+--------------+------------+ Hello all, I'm writing a page with a simple database with a table called recipes in it with a series of recipes (go figure). I want to display a list of the recipe titles in ascending alphabetical order with each title linked to another page that displays all of the information about the recipe. I can't seem to get anything to display though (not even the titles) but I'm not getting any errors returned either. It seems as if there is nothing in the table to display (even though there are 40 records there). Any help would be greatly appreciated. Here is the code I have so far: Code: [Select] <?php $dbhost = 'localhost'; $dbuser = '*****'; $dbpass = '*****'; $dbname = '*******'; $conn = mysql_connect($dbhost, $dbuser, $dbpass) or die ('Error connecting to database'); mysql_select_db($dbname) or die('Error selecting the database'); // select data from db to use $result = mysql_query("SELECT * FROM recipes ORDER BY title ASC LIMIT 0,50") or die('mysql_error()'.'Error: ' .mysql_errno() ); //display the data while($row = mysql_fetch_array($result)); { echo"<b><center>Healthy Lifestyle Gourmet Recipes</center></b><br /><br />"; echo "<span class=\"recipelink\"><a href=\"reciperesults.php?id=".$row['id']."\" target=\"_blank\">".$row['title']."</a></span><br/>\n"; } mysql_close(); ?> I starred out the connection variables but, they are all correct in my code (I'm not getting the "or die" errors) Hello, I have been developing a website that needs to display products online, I was originally going to hand-write the PHP code but I thought it would be more beneficial to make it database orientated as new products can easily be added and a search function becomes possible. I have it working so far so good, but the last part I can't seem to get working. I have it so all the products that have the desired category are displayed, but I want a more detailed analysis of the product to appear when the image is clicked, which at the moment, displays a blank page. http://www.webwib.co...?p=floorpuzzles - this is the hand coded version that demonstrates how I want it to work. http://www.webwib.co...hp?floorpuzzles - this is the db version so far, it works how it is intended to apart from the last stage, which returns as a blank page rather than a dedicated page for the selected product. Here is my code, the third segment beginning with "if(isset($_GET['$ID'])){", is my attempt at the final stage.
<?php
$db=mysql_connect ("localhost", "webwibco_charlie", "Hello123") or die ('I cannot connect to the database because: ' . mysql_error());
$mydb=mysql_select_db("webwibco_products");
include("header.php");
if(isset($_GET['floorpuzzles'])){
echo "<h1>Our Floor Puzzles</h1>";
$sql="SELECT ID, Name, Tags, Description, Category FROM products WHERE Category LIKE '%" . FloorPuzzles . "%'";
$result=mysql_query($sql);
while($row=mysql_fetch_array($result)){
$Name =$row['Name'];
$ID =$row['ID'];
$Description =$row['Description'];
echo "<div class=\"box\">";
echo "<h1>$Name</h1>";
echo "<div class=\"floorbox\"><a href=\"?$ID#productspage\"><img src=\"images/products/catalogue/$ID.jpg\" class=\"small\"></a></div>";
echo "<h2>$Description</h2>";
echo "</div>";
}
}
if(isset($_GET['anothercategory'])){
$sql="SELECT ID, Name, Tags, Description, Category FROM products WHERE Category LIKE '%" . AnotherCategory . "%'";
$result=mysql_query($sql);
while($row=mysql_fetch_array($result)){
$Name =$row['Name'];
$ID =$row['ID'];
$Description =$row['Description'];
echo "<h1>Our Floor Puzzles</h1>";
echo "<div class=\"box\">";
echo "<h1>$Name</h1>";
echo "<div class=\"floorbox\"><a href=\"?$ID0#productspage\"><img src=\"images/products/catalogue//$ID.jpg\" class=\"small\"></a></div>";
echo "<h2>$Description</h2>";
echo "</div>";
}
}
if(isset($_GET['$ID'])){
$sql="SELECT ID, Name, Tags, Description, Peices, Size, Barcode, Category FROM products WHERE ID LIKE '%" . $ID . "%'";
$result=mysql_query($sql);
while($row=mysql_fetch_array($result)){
$Name =$row['Name'];
$ID =$row['ID'];
$Description =$row['Description'];
$Pieces =$row['Pieces'];
$Size =$row['Size'];
$Barcode =$row['Barcode'];
echo "<div class=\"1\">";
echo "<h1>$Name</h1>";
echo "<div class=\"bigbox\">";
echo "<div class=\"floorbox\"><img src=\"images/products/catalogue/$ID.jpg\" class=\"big\"></div>";
echo "</div>";
echo "</div>";
echo "<div class=\"2\">";
echo "<p>Puzzle Pieces: $Pieces</p>
<p>Puzzle Size: $Size</p>
<p>Barcode $Barcode</p>";
echo "</div>";
}
}
include("footer.php");
?>
Thank you in advance for any assistance given.
Hi all, Im really struggling to build an update multiple records form, Ive built my table which calls all data i need from the db in a looped region which works fine I just cant understand how to then input these back into the table in the correct rows, if this makes sense? Ive been reading this tutorial but Its not very informative its more of a copy and paste http://www.phpeasystep.com/mysql/10.html Hi I have a query where it returns a few fields based on the location. I created a class for the function and an index page. It does not return any values. Can someone please advise/ THE CLASS Code: [Select] <?php /**************************************** * * WIP Progress Class * * ****************************************/ class CHWIPProgress { var $conn; // Constructor, connect to the database public function __construct() { require_once "/var/www/reporting/settings.php"; define("DAY", 86400); if(!$this->conn = mysql_connect(DB_HOST, DB_USERNAME, DB_PASSWORD)) die(mysql_error()); if(!mysql_select_db(DB_DATABASE_NAME, $this->conn)) die(mysql_error()); } public function ListWIPOnLocation($location) { $sql = "SELECT `ProgressPoint.PPDescription` AS Description ,`Bundle.WorksOrder` AS WorksOrder, `Bundle.BundleNumber` AS Number, `Bundle.BundleReference` AS Reference,`TWOrder.DueDate` AS Duedate FROM `TWOrder`,`Bundle`,`ProgressPoint` WHERE `Bundle.CurrentProgressPoint`=`ProgressPoint.PPNumber` AND `TWOrder.Colour=Bundle.Colour` AND `TWOrder.Size=Bundle.Size` AND `TWOrder.WorksOrderNumber`=`Bundle.WorksOrder` AND `ProgressPoint.PPDescription` LIKE '" . $location . "%' ORDER BY TWOrder.DueDate DESC"; mysql_select_db(DB_DATABASE_NAME, $this->conn); $result = mysql_query($sql, $this->conn); echo $sql; while($row = mysql_fetch_array($result, MYSQL_ASSOC)) { $return[] = $row; } return $return; } } ?> The index page Code: [Select] <?php // First of all initialise the user and check for permissions require_once "/var/www/users/user.php"; $user = new CHUser(7); // Initialise the template require_once "/var/www/template/template.php"; $template = new CHTemplate(); // And create a cid object require_once "/var/www/WIPProgress/DisplayWIPOnLocation.php"; $WIPProgress= new CHWIPProgress(); $content = "Check WIP Status on Location <br>"; $content = "<form action='index.php' method='get' name ='location'> <select id='location' > <option>Skin Room</option> <option>Clicking</option> <option>Kettering</option> <option>Closing</option> <option>Rushden</option> <option>Assembly</option> <option>Lasting</option> <option>Making</option> <option>Finishing</option> <option>Shoe Room</option> </select> <input type='submit' /> </form>"; $wip = $WIPProgress->ListWIPOnLocation($_GET['location']); // Now show the details $content .= "<h2>Detail</h2> <table> <tr> <th>PPDescription</th> <th>Works Order</th> <th>Bundle Number</th> <th>Bundle Reference</th> <th>Due Date</th> </tr>"; foreach($wip as $x) { $content .= "<tr> <td>" . $x['Description'] . "</td> <td>" . $x['WorksOrder'] . "</td> <td>" . $x['Number'] . "</td> <td>" . $x['Reference'] . "</td> <td>" . $x['DueDate'] . "</td> </tr>"; } $template->SetTag("content", $content); echo $template->Display(); ?> thank you I'm working on this database that was built by somebody else, and I'm having issues with. I'm attaching a photo of the database. The problem I'm having is that even when I hard-code variables in the statement, it still brings back "Sorry, but we can not find an entry to match your query" Is there something that I'm not seeing, or something that I'm doing wrong here? You can clearly see in the photo that I'm trying to grab the info with the id_pk 300000. Code: [Select] <?php //$search = $_POST['search']; //$search = '300000'; $data = mysql_query("SELECT * FROM page_listings WHERE id_pk = '300000'"); while($result = mysql_fetch_array( $data )) { $name = $result['page_name']; $id = $result['id_pk']; $page = $result['html']; $cat = $result['category']; $dir = $result['directory']; echo "ID: " .$id ."<br>Page: ". $name ."<br>HTML: ". $page ."<br>Category: ". $cat ."<br>Directory: ". $dir ."<br />"; } $anymatches=mysql_num_rows($data); if ($anymatches == 0) { echo "Sorry, but we can not find an entry to match your query<br><br>"; } ?> Thanks in advance [attachment deleted by admin] I am using Dreamweaver CS4 to build a website. On my contact page, I made a form with spry validation. I used a tutvid tutorial to learn a simple form handler script (I'm a complete newb at PHP) and everything works great. The only problem I'm having is, in my Dreamweaver template, I have an editable region that has the form. When the user clicks to submit the form, a new html page opens up that looks nothing like my website. What I'm trying to accomplish is having the form disappear and be replaced in the same editable region with my "thank you" message. This way, the user just submits, the form disappears, and they get a thank you message on the same page, in the same place where the form was. Here is the form code: Code: [Select] <form id="frmContact" name="frmContact" method="post" action="contact_form.php"> <fieldset><legend>Submit a question or comment...</legend> <p> <label for="name">Name:</label> <span id="spryName"> <input type="text" name="name" id="name" /> <span class="textfieldRequiredMsg">Name is required.</span><span class="textfieldMinCharsMsg">Must have at least 3 characters.</span><span class="textfieldMaxCharsMsg">Must not exceed 20 characters.</span></span></p> <p> <label for="email">Email:</label> <span id="spryPassword"> <input type="text" name="email" id="email" tabindex="10" /> <span class="textfieldRequiredMsg">Email address is required.</span><span class="textfieldInvalidFormatMsg">Not a valid email address.</span><span class="textfieldMinCharsMsg">Not a valid email address.</span><span class="textfieldMaxCharsMsg">Not a valid email address.</span></span></p> <p> <label id="message" for="question">Please tell us how we can help you:</label><br /> <span id="spryText"> <textarea name="question" id="question" cols="45" rows="5" tabindex="20"></textarea><br /> <span class="textareaRequiredMsg">A question or comment is required.</span><span class="textareaMinCharsMsg">Must have 16 characters minimum</span><span class="textareaMaxCharsMsg">Must not exceed 500 characters.</span></span></p> <p> <input type="submit" name="submit" id="submit" value="Submit" tabindex="30" /> </p> </fieldset> </form> Here is the PHP script: <?php /* Subject and Email variables */ $emailSubject = 'Contact Form Response'; $webMaster = 'centerline.computers@gmail.com'; /* Gather Data variables */ $nameField = $_POST['name']; $emailField = $_POST['email']; $questionField = $_POST['question']; $body = <<<EOD <br><hr><br> Name: $nameField <br> Email: $emailField <br> Message: $questionField <br> EOD; $headers = "From: $emailField\r\n"; $headers .= "Content-type: text/html\r\n"; $success = mail($webMaster, $emailSubject, $body, $headers); /* Results rendered as HTML */ $theResults = <<<EOD <html><body> <h2>Thank you for submitting.</h2> <p>We will get back to you as soon as possible.</p> </body> </html> EOD; echo "$theResults"; ?> Thanks for any help you might have for me! Hi Everyone, Well I have a bit of a problem... I have created a search page that I would like to return results from my MySQL database. However for some reason I can not get my page to display the results. Instead I am getting an error page. Below is the code I am using: In addition to this, should I wish for a user to be able to edit the returned results by clicking a link, how would I do that? <?php session_start(); ?> <link rel="stylesheet" type="text/css" href="css/layout.css"/> <html> <?php $record = $_POST['record']; echo "<p>Search results for: $record<br><BR>"; $host = "localhost"; $login_name = "root"; $password = "P@ssword"; //Connecting to MYSQL MySQL_connect("$host","$login_name","$password"); //Select the database we want to use mysql_select_db("schedules_2010") or die("Could not find database"); $result = mysql_query("SELECT * FROM schedule_september_2010 WHERE champ LIKE '%$record%' ") or die(mysql_error()); // keeps getting the next row until there are no more to get while($row = mysql_fetch_array( $result )) { // Print out the contents of each row echo "<br><p>Your Schedule<BR></p><br>"; echo "<table border=1>\n"; echo "<tr> <td bgcolor=#444444 align=center><p><b>Champ</p></td> <td bgcolor=#444444 align=center><p><b>Date</p></td> <td bgcolor=#444444 align=center><p><b>Start Time</p></td> <td bgcolor=#444444 align=center><p><b>End Time</p></td> <td bgcolor=#444444 align=center><p><b>Department</p></td> <td bgcolor=#444444 align=center><p><b>First Break</p></td> <td bgcolor=#444444 align=center><p><b>Second Break</p></td> <td bgcolor=#444444 align=center><p><b>Login ID</p></td> </tr>\n"; do { printf("<tr> <td><p>%s</p></td> <td><p>%s</p></td> <td><p>%s</p></td> <td><p>%s</p></td> <td><p>%s</p></td> <td><p>%s</p></td> <td><p>%s</p></td> <td><p>%s</p></td> </tr>\n" , $row["champ"] , $row["date_time"] , $row["start_time"] , $row["end_time"] , $row["department"] , $row["first_break"] , $row["second_break"] , $row["login_id"] ); } while ($row = mysql_fetch_array($result)); echo "</table>\n"; } else { echo "$champ No Records Found"; } mysql_free_result($result); mysql_close($con); ?> </html> I created a function called converter. My code doesn't look like it processes anything after the first if . This is what is displayed in browser. Convert a String original string: roses Are red, violets are blue.... converted string: roses are red, violets are blue.... converted string: roses are red, violets are blue.... converted string: roses are red, violets are blue.... <html> <head> <title>Create a PHP Function to Convert a String</title> </head> <body bgcolor="pink"> <h2>Convert a String</h2> <?php $phrase = "roses Are red, violets are blue...."; function converter($arg1, $arg2){ if($arg1="lower"){ return strtolower($arg2); } elseif ($arg1="upper"){ return strtoupper($arg2); } else /* if($arg1="title")*/{ return ucwords($arg2); } } print "original string: ".$phrase."<br />"; print "converted string: ".converter("upper",$phrase)."<br />"; print "converted string: ".converter("lower",$phrase)."<br />"; print "converted string: ".converter("title",$phrase)."<br />"; ?> </body> </html> Hey guys I'm not amazing at PHP, but know just enough to be dangerous. Basically I'm trying to get these records from my database to display in rows of 4. For some reason every time, I'm missing a record (the first record returned in my query). It's probably something simple is my code. Would be grateful if anyone could lend a suggestion. Code: [Select] <?php $a=0; $b=3; while ($ArrayData = mysql_fetch_array($QueryData)) { //if a=0, start new row if ($a==0) { echo '<tr>'; } //create cell //if thumbnail exists, use it, otherwise throw in the unavailable image if ($ArrayData["PhotoThumb"]!="") { $ImageToUse = $ArrayData["PhotoThumb"]; } else { $ImageToUse = "image_unavailable_thumb.jpg"; } echo ' <td width="33%" align="center" valign="top"><p><a href="item.php?ItemID='.$ArrayData["ItemID"].'"><img src="images/'.$ImageToUse.'" border="0" /></a></p> <p><a href="item.php?ItemID='.$ArrayData["ItemID"].'" class="cart_body_text">'.$ArrayData["ItemName"].'</a><br /> <span class="style1"> <strong>$'.sprintf("%01.2f", $ArrayData["UnitPrice"]).'</strong></span><br /> </p> </td>'; //increment by 1 $a++; //if a = 3 then close the row using </tr>, ready to start a new one if ($a==$b) { echo ' </tr>'; //reset counter, ready to start new row $a=0; } } if ($a > 0 ) { echo '</tr>'; } ?> Thanks guys! Hello, First time posting here, my MYSQL version is 5.1.52 and I have a created a search function to find a user record and if the name is typed correctly the name and details are displayed on the search page, but if the name is typed incorrectly nothing is appearing. Basically I would like to be able to say if no record found and redirect back to the previous page. Code: Code: [Select] <?php add = $_POST['add']; // Database details $host=""; // Host name $username=""; // Mysql username $password=""; // Mysql password $db_name=""; // Database name $tbl_name="Rewards"; // Table name // Connect to server and select databse. mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot SELECT DB"); //Add query $sql = mysql_query("UPDATE Rewards SET Rewards = (Rewards + 10) WHERE Name '%$add%'"); // Database details $host=""; // Host name $username=""; // Mysql username $password=""; // Mysql password $db_name=""; // Database name $tbl_name="UserList"; // Table name // Connect to server and select databse. mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot SELECT DB"); //Update Total Points query $sql = mysql_query("UPDATE UserList SET TotalPoints = (TotalPoints + 10) WHERE Name '%$add%'"); // Database details $host=""; // Host name $username=""; // Mysql username $password=""; // Mysql password $db_name=""; // Database name $tbl_name="UserList"; // Table name // Connect to server and select databse. mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot SELECT DB"); //Search Query $sql = mysql_query("SELECT * FROM UserList WHERE Name '%$add%'"); while ($row = mysql_fetch_array($sql)){ echo '<br/><img src="images/line1.jpg" alt="" width="200" height="2" />'; echo '<br/> Username: '.$row['Username']; echo '<br/>'; echo '<br/><img src="images/line2.jpg" alt="" width="200" height="2" />'; echo '<br/> Name: '.$row['Name']; echo '<br/> Year Group: '.$row['YearGroup']; echo '<br/> Form Class: '.$row['FormClass']; echo '<br/>'; echo '<br/><img src="images/line3.jpg" alt="" width="200" height="2" />'; } // Database details $host=""; // Host name $username=""; // Mysql username $password=""; // Mysql password $db_name=""; // Database name $tbl_name="Rewards"; // Table name // Connect to server and select databse. mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot SELECT DB"); $sql = mysql_query("SELECT * FROM Rewards WHERE Name '%$add%'"); while ($row = mysql_fetch_array($sql)){ echo '<br/> Rewards: '.$row['Rewards']; } // Database details $host=""; // Host name $username=""; // Mysql username $password=""; // Mysql password $db_name=""; // Database name $tbl_name="Sanctions"; // Table name // Connect to server and select databse. mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot SELECT DB"); $sql = mysql_query("SELECT * FROM Sanctions WHERE Name '%$add%'"); while ($row = mysql_fetch_array($sql)){ echo '<br/> Sanctions: '.$row['Sanctions']; } // Database details $host=""; // Host name $username=""; // Mysql username $password=""; // Mysql password $db_name=""; // Database name $tbl_name="UserList"; // Table name // Connect to server and select databse. mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot SELECT DB"); $sql = mysql_query("SELECT * FROM UserList WHERE Name '%$add%'"); while ($row = mysql_fetch_array($sql)){ echo '<br/> Total Points: '.$row['TotalPoints']; echo '<br/>'; echo '<br/><img src="images/line4.jpg" alt="" width="200" height="2" />'; } Any help would be greatly appreciated. Many Thanks P Quinn MOD EDIT: [code] . . . [/code] tags added. |
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