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PHP - Mysql_num_rows() Expects Parameter 1 To Be Resource,
Hi
I'm having a bit of bother with my login. I created a login using this tutorial http://www.phpeasystep.com/phptu/6.html and it works perfectly. So i have attempted to change it to meet my own database. So basically i've changed the database, table names etc to meet my own. I haven't changed any other lines. When i run it i get an error message: Warning: mysql_num_rows() expects parameter 1 to be resource, boolean given in C:\xampp\htdocs\checklogin.php on line 26 The code is below: Code: [Select] <?php $host="localhost"; // Host name $username="root"; // Mysql username $password=""; // Mysql password $db_name="final year project"; // Database name $tbl_name="tbl_user"; // Table name // Connect to server and select databse. mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); // username and password sent from form $mem_username=$_POST['mem_username']; $mem_password=$_POST['mem_password']; // To protect MySQL injection (more detail about MySQL injection) $mem_username = stripslashes($mem_username); $mem_password = stripslashes($mem_password); $mem_username = mysql_real_escape_string($mem_username); $mem_password = mysql_real_escape_string($mem_password); $sql="SELECT * FROM $tbl_name WHERE username='$mem_username' and password='$mem_password'"; $result=mysql_query($sql); // Mysql_num_row is counting table row $count=mysql_num_rows($result); // If result matched $mem_username and $mem_password, table row must be 1 row if($count==1){ // Register $mem_username, $mem_password and redirect to file "login_success.php" session_register("mem_username"); session_register("mem_password"); header("location:login_success.php"); } else { echo "Wrong Username or Password"; } ?> Line 26 is $count=mysql_num_rows($result); I'm baffled as to why the test database worked. I tried another test database but got the same error. baffled.com Hope someone can help MOD EDIT: [code] . . . [/code] tags added. Similar TutorialsI have tired to search this up but get nothing back.. :@ This error is on line 18 on line 18 is Code: [Select] if (mysql_num_rows($result) == 1) { Quote Notice: Undefined variable: result in C:\xampp\htdocs\Exam_Online\Staff_login\Staff_login_process.php on line 18 Warning: mysql_num_rows() expects parameter 1 to be resource, null given in C:\xampp\htdocs\Exam_Online\Staff_login\Staff_login_process.php on line 18 Wrong Username or Password This is the error message. Code: [Select] if (mysql_num_rows($result) == 1) { // Set username session variable $_SESSION['ID'] = $_POST['ID']; header("location:Staff_Menu.php"); } else { echo"Wrong Username or Password"; } Hi guys, I'm new to forums so hopefully someone can help me. I keep getting the following error: Warning: mysql_num_rows() expects parameter 1 to be resource, boolean given in C:\wamp\www\Blog2\checklogin.php on line 27 My code is: Code: [Select] // Define $blog_user_name and $blog_user_password $blog_user_name=$_POST['blog_user_name']; $blog_user_password=$_POST['blog_user_password']; // To protect MySQL injection (more detail about MySQL injection) $blog_user_name = stripslashes($blog_user_name); $blog_user_password = stripslashes($blog_user_password); $blog_user_name = mysql_real_escape_string($blog_user_name); $blog_user_password = mysql_real_escape_string($blog_user_password); $sql="SELECT * FROM $tbl_name WHERE username='$blog_user_name' and password='$blog_user_password'"; $result=mysql_query($sql); // Mysql_num_row is counting table row $count=mysql_num_rows($result); //THIS IS LINE 27 // If result matched $blog_user_name and $blog_user_password, table row must be 1 row if($count==1){ // Register $blog_user_name, $blog_user_password and redirect to file "index.php" session_register("blog_user_name"); session_register("blog_user_password"); header("location:index.php"); } else { echo "Wrong Username or Password"; } ob_end_flush(); Please can someone help I have know idea what the problem could be. Thanks. Hey, this is my first post here, so bear with me: I'm new to PHP, and am trying to make an online store, right now I'm just making an admin inventory management, and so I'm using PHP to link to the database. Before any of this script, I link to the database and all that, so it's not an issue of connection. My issue is I keep getting the following message: Warning: mysql_num_rows() expects parameter 1 to be resource, boolean given in "inventory_list.php" on line 38 Column count doesn't match value count at row 1 There used to be three or four other error messages, but I've been able to work out my mistakes and fix them. Here is my code, starting at Line 27: Code: [Select] <?php // Parse the form data and add inventory item to the system if (isset($_POST['product_name'])) { $product_name = mysql_real_escape_string($_POST['product_name']); $price = mysql_real_escape_string($_POST['price']); $category = mysql_real_escape_string($_POST['category']); $subcategory = mysql_real_escape_string($_POST['subcategory']); $details = mysql_real_escape_string($_POST['details']); // See if that product name is an identicle match to another in the system $sql = mysql_query("SELECT product_id FROM products WHERE product_name='$product_name' LIMIT 1"); $productMatch = mysql_num_rows($sql); // count the output amount if ($productMatch > 0){ echo 'Sorry, you tried to place a duplicate "Product Name" into the system, <a href="inventory_list.php">click here</a>'; exit(); } // Add this product into the database now $sql = mysql_query("INSERT INTO product (product_name, price, category, subcategory, date_added) VALUES('$product_name','$price','$details','$category','$subcategory',now())") or die (mysql_error()); $pid = mysql_insert_id(); // Place image in the folder $newname = "$pid.jpg"; move_uploaded_file($_FILES['fileField']['tmp_name'], "../inventory_images/$newname"); } ?> The line causing this issue is thus: Code: [Select] $productMatch = mysql_num_rows($sql); // count the output amount Does anyone know how to fix this for me? Thanks This has been really annoying me for 2 hours now . I know its something silly Database Structure QuestionID int Question VarChar HelpDocument VarChar (Link) Posting Code: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.2.6/jquery.min.js"></script> <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jqueryui/1.5.3/jquery-ui.min.js"></script> <script type="text/javascript" src="jquery.simpledialog/jquery.simpledialog.0.1.js"></script> <link rel="stylesheet" type="text/css" href="style.css" /> <link rel="stylesheet" href="ui.datepicker.css" type="text/css" media="screen" /> <link rel="stylesheet" href="jquery.simpledialog/simpledialog.css" type="text/css" media="screen" /> <script type="text/javascript" src="http://ajax.googleapis.com/ajax/ libs/jquery/1.3.0/jquery.min.js"></script> <script type="text/javascript"> $(function() { $(".search_button").click(function() { var search_word = $("#search_box").val(); var dataString = 'search_word='+ search_word; if(search_word=='') { } else { $.ajax({ type: "GET", url: "getHelpDocuments.php", data: dataString, cache: false, beforeSend: function(html) { document.getElementById("insert_search").innerHTML = ''; $("#flash").show(); $("#searchword").show(); $(".searchword").html(search_word); $("#flash").html('<img src="ajax-loader.gif" /> Loading Results...'); }, success: function(html){ $("#insert_search").show(); $("#insert_search").append(html); $("#flash").hide(); } }); } return false; }); }); </script> <style> *{margin:0;padding:0;} ol.update { list-style:none; font-size:1.1em; margin-top:20px } ol.update li { height:70px; border-bottom:#dedede dashed 1px; text-align:left; } ol.update li:first-child { border-top:#dedede dashed 1px; height:70px; text-align:left } </style> </head> <body> <div id="AllContent"> <div id="header"> <br></br> <br></br> </div> <br></br> <div id="login"> </div> <br></br> <br></br> <br></br> <br></br> <br></br> <br></br> <br></br> <div id="RequestAccess"> <form method="get" action=""> <input type="text" name="search" id="search_box" class='search_box'/> <input type="submit" value="Search" class="search_button" /> </form> <div id="searchword"> Search results for <span class="searchword"></span></div> <div id="flash"></div> <ol id="insert_search" class="update"> </ol> </ul> </div> </div> </div> </div> </body> </html> PHP SCRIPT <?php if(isset($_GET['search_word'])) { $search_word=$_GET['search_word']; $search_word_new=mysql_escape_string($search_word); $search_word_fix=str_replace(" ","%",$search_word_new); $link = mysql_connect("localhost", "root", ""); mysql_select_db("blank", $link); $sql=mysql_query("SELECT HelpDocument FROM Questions WHERE Question LIKE '%$search_word_fix%' ORDER BY Question DESC LIMIT 20", $link); $count=mysql_num_rows($sql); if($count > 0) { while($row=mysql_fetch_array($sql)) { $msg=$row['Question']; $bold_word='<b>'.$search_word.'</b>'; $final_msg = str_ireplace($search_word, $bold_word, $msg); ?> <li><?php echo $final_msg; ?></li> <?php } } else { echo "<li>No Results</li>"; } } ?> getting this error Warning: mysql_num_rows() expects parameter 1 to be resource and it wont display the database fields after search Any help is deeply appreciated thanks The 2 errors I am getting a Warning: mysql_fetch_assoc() expects parameter 1 to be resource, boolean given in C:\wamp\www\searchstock2.php on line 36 Warning: mysql_num_rows() expects parameter 1 to be resource, boolean given in C:\wamp\www\searchstock2.php on line 38 I am trying to search a table and return results, all fields are VARCHAR except ID (integer), here is part of my code; $link = mysql_connect("localhxxxxx","xxx",""); //(host, username, password) mysql_select_db("wadkin", $link) or die("Unable to select database"); //select which database we're using // Build SQL Query $query = "select * from stocklist where Stock Number like \'%$trimmed%\'OR Name like \'%$trimmed%\' OR Category like \'%$trimmed%\'"; if ($numresults=mysql_query($query)); $row = mysql_fetch_assoc($numresults); if ($row['COUNT(*)'] == 0); $numrows=mysql_num_rows($numresults); if ($numrows == 0) { echo "<h4>Results</h4>"; echo "<p>Sorry, your search: "" . $trimmed . "" returned zero results</p>"; } // Determine if s has been passed to script, if not use 0 if (empty($s)) { $s=0; } // get results $query .= " limit $s,$limit"; $result = mysql_query($query) or die("Couldn't execute query"); // display what the person searched for echo "<p>You searched for: "" . $var . ""</p>"; // begin to show results set echo "Results"; $count = 1 + $s ; // display the results returned while ($row= mysql_fetch_array($result)) { $title = $row["Name"]; echo "$count.) $title" ; $count++ ; } $row = mysql_fetch_assoc($numresults); = line 36 $numrows=mysql_num_rows($numresults); = line 38 i give it up after 4 h. please help me, what i do wrong i am try to make a name, address search system into my website from my database. but i got this msg [Warning: mysql_num_rows() expects parameter 1 to be resource, boolean given in C:\xampplite\htdocs\3\searchresult.php on line 54] my full php code i.e. searchresult.php is under...... what i have mistake..... searchresult.php <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> <title>Untitled Document</title> </head> <body> <?php // TAKE THE INFORMATION FROM FORM. $search = $_GET['search']; // IF THERE IS NOT A KEYWORD GIVE A MISTAKE. if (!$search) echo "You didn't enter a keyword"; else { echo "<td>You searched for: <strong>$search </strong></td>"; mysql_connect('localhost','root',''); mysql_select_db('search'); $id=@$_GET['id']; //QUERY IS THE CODE WHICH WILL MAKE THE SEARCH IN YOUR DATABASE. //I WROTE AN EXPLANATION ABOUT IT AFTER THE CODE. $sql = "CREATE TABLE searchform \n" ."(\n" ."ID int NOT NULL AUTO_INCREMENT ,\n" ."FirstName varchar( 255 ) NOT NULL ,\n" ."LastName varchar( 255 ) NOT NULL ,\n" ."Email varchar( 255 ) NOT NULL ,\n" ."PhoneNumber varchar( 255 ) NOT NULL ,\n" ."PRIMARY KEY ( ID ) )";; $result1 = MySQL_query($query); if(!$result1) { echo MySQL_error()."<br>$query<br>"; } if(MySQL_num_rows($result1) > 5) { echo "<table width='750' align='center' border='0' cellspacing='0' cellpadding='0'>"; while($result2 = MySQL_fetch_array($result1)) { //A short description from category. $description = $result2['category']; $searchPosition = strpos($description, $search); $shortDescription = substr($description, $searchPosition, 150); // I added a link to results which will send the user to your display page. echo '<tr><td><p><strong><a href="displayresults.php?id='.$result2['id'].'">'.$result2['title'].'</strong></p></td></tr>'; echo "<tr><td>$shortDescription ...</td></tr>"; echo "<td>{$result2['name']} {$result2['surname']}</td><tr/>"; } echo "</table>"; }else { echo "No Results were found in this category.<br>"; }echo "<br>"; } ?> </body> </html> and searchform.php <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> <title>Untitled Document</title> </head> <body> <form action="searchresult.php" method="get"> <div align="center"> <p> <input name="search" type="text" size="60"/> <input name="submit" type="submit" value="Search" /> </p> </div> </form> </body> </html> Warning: mysql_num_rows() expects parameter 1 to be resource, boolean given in C:\xampp\htdocs\ipod\lib\connection.php on line 131 :S 129. function RecordCount ( $query ) 130. { 131. return mysql_num_rows( mysql_query( $query ) ); 132. } I've just started to learn PHP and I'm having a little trouble. I'm trying to stick with OOP but I'm having trouble with it. I've coded a database connection and I'm trying to take data from a form and insert it into a database. I've managed to do it without OOP but I can't get it to work with. The code is below. Any help would be great. I have a file for the form, which should take the data and the php should insert it into the table - <?php // Get the PHP file containing the dbConnect class require('../../configuration.php'); // Get the PHP file containing the dbConnect class require('../../lib/db.class.php'); // Checks whether a form has been submitted. If so, carry on if ($_POST) { // Creates an instance of dbConnect $link = new dbConnect(); // Creates a SQL query $insertQuery = 'INSERT INTO content SET title = "' . $_POST['title'] . '", alias = "' . $_POST['alias'] . '", category = "' . $_POST['category'] . '", summary = "' . $_POST['summary'] . '", content = "' . $_POST['content'] . '"'; $result = $link->query($insertQuery, $link); } ?> <body> <form action="" method="post"> <div> <label for="title">Title:</label> <textarea id="title" name="title" rows="1" cols="30"> </textarea> </div> <div> <label for="alias">Alias:</label> <textarea id="alias" name="alias" rows="1" cols="30"> </textarea> <div> <label for="category">Category:</label> <textarea id="category" name="category" rows="1" cols="30"> </textarea> </div> <div> <label for="summary">Summary:</label> <textarea id="summary" name="summary" rows="6" cols="40"> </textarea> </div> <div> <label for="content">Content:</label> <textarea id="content" name="content" rows="12" cols="40"> </textarea> </div> <div> <input type="submit" value="Add Article" /> </div> </form> This is my class to connect to the db - class dbConnect extends siteConfig { var $theQuery; var $link; // Function to connect to the database public function dbConnect() { // Load configuration from parent class $config = siteConfig::getConfig(); // Get main config settings from the array that we just loaded $host = $config['hostname']; $user = $config['username']; $pass = $config['password']; $db = $config['database']; // Connect to the DB $link = mysql_connect('localhost', 'user', 'pass'); if (!$link) { $error = 'Unable to connect to the database server.'; echo $error; exit(); } } // Function to execute a database query public function query($link, $query) { $this->theQuery = $query; mysql_query($this->link, $query); } // Function to get array of query results public function getArray($result) { return mysql_fetch_array($result); } // Function to close the connection public function closeConnection() { mysql_close($this->link); } } I also have a config file. I'm not using it atm but I thought I'd show it anyway as it may help - class siteConfig { var $config; function getConfig() { $config['site_url'] = 'localhost/edencms'; $config['hostname'] = 'localhost'; $config['username'] = 'user'; $config['password'] = 'pass'; $config['database'] = 'edencms'; } } After filling out the form and sending it, I get the following error: Quote Warning: mysql_query() expects parameter 2 to be resource, object given in C:\xampp\htdocs\EdenCMS\lib\db.class.php on line 39 It seems like $link isn't staying as a resource once the dbConnect is called. If I print it in the dbConnect function, it shows it's a resource but if I try to print it after, it shows as an object. I'm not sure why. As I said, I'm new, so go easy I keep getting this error when I run the following code: Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in C:\wamp\www\vitamin-k-tracker\my-meal-planner.php on line 29 Code: [Select] <?php include 'top.php'; ?> <?php if (!loggedin()) {//1 if start header('Location: need-to-log-in-mmp.php'); }//1 if end ?> <title>My Meal Planner - Vitamin K Tracker</title> </head> <div id="container"> <?php include 'header.php'; ?> <?php include 'nav.php'; ?> <?php //do sql query to return the foods and nutrients that a person added to their que // // we're doing a left join between the foods and user foods table connected by the id $queryc = "SELECT `foods.id`, `foods.name`, `foods.source`, `users_foods.food_id` FROM `foods` LEFT JOIN users_foods ON foods.id=users_foods.food_id"; $query_runc = mysql_query($queryc); //error on the line below: while ($rowc = mysql_fetch_array($query_runc)){ echo 'ok'; } ?> <div id="content-container"> <div id="content_for_site"> <h2>My Meal Planner</h2> <br /> My Meal Que: <br /> <ul> <form> <li><input type="checkbox" name="meal_one" value="meal_one" /> Meal One</li> How many servings will you have? <input type="text" name="meal_one_servings"><br /><br /> <li><input type="checkbox" name="food_one" value="food_one" /> Food One</li> How many servings will you have? <input type="text" name="meal_one_servings"> </form> </ul> <input type="submit" value="delete" name="delete"><br /> <input type="submit" value="add to calendar" name="add_to_calendar"> <br /><br /> <a href="create-a-meal.php">Create A Meal & add to your Meal Que</a><br /> <a href="find-a-meal.php">Find a Meal or Food to Add to your Meal Que</a> </div> <div id="clear"></div> <?php include 'footer.php'; ?> </div> </div> Please help, This code is giving me the warning stated in the above given Subject line. And combo box is also not populating. Code: [Select] function populatecombo() { $dropdown = ""; $sqlcmb = "select wardno from wards"; mysql_query($sqlcmb) or die(mysql_error('Unable to query the table')); while($row = mysql_fetch_assoc($sqlcmb)) { $dropdown .= "\r\n<option value='{$row['wardno']}>'{$row['wardno']}</option>"; } echo $dropdown; } Hello, Im developing simple user registration system with my knowledge.but got this error with this file Code: [Select] <?php //database connection require_once("dbconnection/connect.php"); $success_massage =""; if (isset($_POST['hiddenstudentid'])) $passstudent_id=$_POST['hiddenstudentid']; else $passstudent_id=$_POST['student_id_hidden']; $sql=mysql_query("SELECT * FROM student WHERE StudentID=$passstudent_id"); echo $sql; while ($row=mysql_fetch_assoc($sql)) { $update_nic=$row['NIC']; $update_name=$row['Student_Name']; $update_addr=$row['Address']; $take_bday=$row['Birthday']; echo $take_bday; $update_bday=date('d',strtotime($take_bday)); $update_month=date('m',strtotime($take_bday)); $update_year=date('y',strtotime($take_bday)); $update_tele=$row['Telephone']; $update_email=$row['Email']; } if (isset($_POST['btnupdate'])) { $insert_nic=$_POST['nic_txt']; $insert_name=$_POST['name_txt']; $insert_addr=$_POST['address_txt']; $insert_bday=$_POST['bdate']; $insert_month=$_POST['bmonth']; $insert_year=$_POST['byear']; $insert_tele=$_POST['telephone_txt']; $insert_email=$_POST['email_txt']; $Birthday =date("$insert_year-$insert_month-$insert_bday");//Bday eka $Birthday ta set kereema. $sql="update student set NIC='$insert_nic',Student_Name='$insert_name',Address='$insert_addr',Birthday='$Birthday',Telephone='$insert_tele',Email='$insert_email' where StudentID=$passstudent_id" ; /*(Student_ID,NIC,Student_Name,Address,Birthday,Telephone,Email)values('$student_id','$insert_nic','$insert_name','$insert_addr','$Birthday','$insert_tele','$insert_email')";*/ //echo $sql; $result=mysql_query($sql) or die ("database error"); $success ="Records updated successfully"; $success_massage =$success; header('Location:editdisplay.php'); } if ($_POST['btndelete']=='DELETER') { $delete = "delete from student where StudentID=$passstudent_id"; $result =mysql_query($delete) or die ("data deleting error"); $delete_massage="Record deleted"; //$success_massage = $delete_massage; } if (isset($_POST['btncancel'])) { header ('Location:registration.php'); } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> <script type="text/javascript"> function GetConfirmation() { var res=confirm("Are you sure to delete this Student?"); if(res==true) { var btn=document.getElementById("btndelete"); btn.value="DELETER"; // alert ("YES"); document.editForm.submit(); } } </script> </head> <body> <form id="form1" name="form1" method="post" action=""> <table width="406" border="1"> <tr> <td width="149"> </td> <td width="241">Student Registration</td> </tr> <tr> <td>NIC</td> <td><label for="nic_txt"></label> <input type="text" name="nic_txt" id="nic_txt" value="<?php echo $update_nic ?>" /><input type="hidden" name="student_id_hidden" id="student_id_hidden" value="<?php echo $passstudent_id ?>" /> </td> </tr> <tr> <td>Name</td> <td><label for="name_txt"></label> <input type="text" name="name_txt" id="name_txt" value="<?php echo $update_name ?>" /><span style="color:#F00"><?php echo $massage_name?></span></td> </tr> <tr> <td>Address</td> <td><label for="address_txt"></label> <input type="text" name="address_txt" id="address_txt" value="<?php echo $update_addr ?>" /><span style="color:#F00"><?php echo $massage_address?></span></td> </tr> <tr> <td>Birthday</td> <td><label for="bdate"></label> <select name="bdate" id="bdate"> <option selected="selected"><?php echo $update_bday ?></option> <?php for ( $i=1;$i<=31;$i++) {echo '<option>'.$i.'</option>'; } ?> </select> <label for="bmonth"></label> <select name="bmonth" id="bmonth"> <option selected="selected"><?php echo $update_month ?></option> <?php echo '<option>'.'-month-'.'</option>'; for ($b=1;$b<=12;$b++) {echo '<option>'.$b.'</option>'; } ?> </select> <label for="byear"></label> <select name="byear" id="byear" /> <option selected="selected"><?php echo $update_year ?></option> <?php echo '<option>'.'-year-'.'</option>'; for ($b=1960;$b<=2000;$b++) {echo '<option>'.$b.'</option>'; } ?> </select><span style="color:#F00"><?php echo $massage_bday?></span></td> </tr> <tr> <td>Email</td> <td><label for="email_txt"></label> <input type="text" name="email_txt" id="email_txt" value="<?php echo $update_email?>" /></td> </tr> <tr> <td>Telephone</td> <td><label for="telephone_txt"></label> <input type="text" name="telephone_txt" id="telephone_txt" value="<?php echo $update_tele?>"/></td> </tr> <tr> <td> </td> <td><input type="submit" name="btnupdate" id="btnupdate" value="Update" /> <input type="submit" name="btndelete" id="btndelete" value="Delete" onclick="GetConfirmation()" /> <input type="submit" name="btncancel" id="btncancel" value="Cancel" /></td> </tr> </table> <?php echo $success_massage?> </form> </body> </html> got error from these codes in this file Code: [Select] if (isset($_POST['hiddenstudentid'])) $passstudent_id=$_POST['hiddenstudentid']; else $passstudent_id=$_POST['student_id_hidden']; $sql=mysql_query("SELECT * FROM student WHERE StudentID=$passstudent_id"); echo $sql; it is showing this error this this warning error.in here that details from DB will show in form.and im going to edit them from this file. please help me to find the error. I have created a script to insert data into a database, but it returns this. Code: [Select] Warning: mysql_select_db() expects parameter 2 to be resource, null given in /RJFWS198/testing/elemata_project/admin/elements/create_page.php on line 51 Here is the code Code: [Select] <?PHP //Protect Against Attacks if (empty($_SESSION['E_User'])) { die("Access Denied"); } ?> <?php if (!empty($_REQUEST['title']) && (!empty($_SESSION['E_User']))) { require_once('../Connections/default.php'); if (empty($_REQUEST['password'])) { $password = "0"; }else{ $password = $_REQUEST['password']; } if (empty($_REQUEST['menu_order'])) { $mo = "0"; }else{ $mo = $_REQUEST['menu_order']; } if (empty($_REQUEST['meta_keywords'])) { $meta_keywords = "0"; }else{ $meta_keywords = $_REQUEST['meta_keywords']; } if (empty($_REQUEST['meta_desc'])) { $meta_desc = "0"; }else{ $meta_desc = $_REQUEST['meta_desc']; } if (empty($_REQUEST['meta_copyright'])) { $meta_copyright = "0"; }else{ $meta_copyright = $_REQUEST['meta_copyright']; } $author = $_SESSION['E_User']; $date = date("m.d.y"); $day = date("d"); $month = date("n"); $year = date("Y"); $time = ''.date("g").''.date("i").''.date("a").''; $ptitle = $_REQUEST['title']; $post_content = $_REQUEST['postContent']; $searchable = $_REQUEST['seachable']; $locked = $_REQUEST['privacy']; $tags = $_REQUEST['tags']; $meta_robots = $_REQUEST['robots']; mysql_select_db($database_default, $default); mysql_query("INSERT INTO posts (`time`, `year`, `month`, `day`, `date`, `author`, `title`, `content`, `searchable`, `locked`, `password`, `menu_order`, `tags`, `meta_keywords`, `meta_desc`, `meta_robots`, `meta_copyright`) VALUES ('$time', '$year', '$month', '$day', '$date', '$author', '$ptitle', '$post_content', '$searchable', '$locked', '$password', '$mo', '$tags', '$meta_keywords', '$meta_desc', '$meta_robots', '$meta_copyright')"); } ?> i am having problem with this error, could you please help me Code: [Select] function cart () { foreach($_SESSION as $name => $value) { if ($value>0) { if (substr($name, 0, 5) == "cart_") { $productid = substr($name, 5, (strlen($name)-5)); $query = mysql_query("SELECT ProductID, Name, Price FROM product WHERE ProductID = '".mysql_real_escape_string((int)$productid."'")); while ($query_row = mysql_fetch_assoc($query)) { $sub = $query["Price"]*$Value; echo $query["Name"]. ' x ' .$value. ' @ '.$query["Price"]. ' = '.$sub.'<br />'; } } } else { echo "<p>Your Shopping Basket is empty</p>"; } } } we did an exercise in IT class it was about how to inject php code in css code we took a template as an example to work on. i injected php code in the page "services.php"as instructed but it didn't work and i keep getting this error : this Nofications appear.. Notice: Undefined index: id in C:\wamp\www\WAR\up3\view.php on line 4 Warning: mysql_fetch_row() expects parameter 1 to be resource, boolean given in C:\wamp\www\WAR\up3\view.php on line 9 invalid id this is my code. <?php require ('dbconnect.php'); // Connect to database $id = $_GET['id']; // ID of entry you wish to view. To use this enter "view.php?id=x" where x is the entry you wish to view. $query = "SELECT data, filetype FROM uploads where uploadid=$id"; //Find the file, pull the filecontents and the filetype $result = MYSQL_QUERY($query); // run the query if($row=mysql_fetch_row($result)) // pull the first row of the result into an array(there will only be one) { $data = $row[0]; // First bit is the data $type = $row[1]; // second is the filename Header( "Content-type: $type"); // Send the header of the approptiate file type, if it's' a image you want it to show as one print $data; // Send the data. } else // the id was invalid { echo "invalid id"; } ?> This is my code $file = "E:/wamp/www/Project/Changes/".$LineNo.".txt"; if(file_exists($file)) { fopen($file,'a') or die("can't open file"); fwrite($file,$Username); } else { fopen($file,'w'); fwrite($file,$Username); } |
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