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PHP - Moved: Cross Tab Query In Mysql
This topic has been moved to MySQL Help.
http://www.phpfreaks.com/forums/index.php?topic=315161.0 Similar TutorialsThis topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=325846.0 This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=348309.0 This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=328677.0 This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=358872.0 This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=313679.0 This topic has been moved to Ajax Help. http://www.phpfreaks.com/forums/index.php?topic=347585.0 This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=312690.0 This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=308528.0 This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=322237.0 This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=328883.0 This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=342695.0 Here is my code: // Start MySQL Query for Records $query = "SELECT codes_update_no_join_1b" . "SET orig_code_1 = new_code_1, orig_code_2 = new_code_2" . "WHERE concat(orig_code_1, orig_code_2) = concat(old_code_1, old_code_2)"; $results = mysql_query($query) or die(mysql_error()); // End MySQL Query for Records This query runs perfectly fine when run direct as SQL in phpMyAdmin, but throws this error when running in my script??? Why is this??? Code: [Select] You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '= new_code_1, orig_code_2 = new_code_2WHERE concat(orig_code_1, orig_c' at line 1 how to cross reference $_POST array 'checkboxes[]' with mysql field I have a form that is submitted so the user can select which results to print. but I am having problems getting the results to show correctly. how do I correctly cross reference the form data with the mysql Code: [Select] $getRequests = mysql_query("SELECT * FROM requests WHERE `customer_email`='{$_SESSION['FM_user']}'"); while($request = mysql_fetch_assoc($getRequests)) { if (!in_array($request['request_id'],array($_POST[request]))) { echo '<li style="font-size:10px; border-bottom: 0.1em solid #D0D0D0"> <div class="leftfloat"> <input type="checkbox" name="request[]" value="',$request['request_id'],'"> </div> <div class="leftfloat"> <em>',$request['request_id'],'</em> </div><div class="leftfloat"> | </div> <div class="leftfloat"> <em>',$request['customer_name'],'</em> </div><div class="leftfloat"> | </div> <br style="clear:both"> </li>'; } } If you also have any feedback on my code, please do tell me. I wish to improve my coding base. Basically when you fill out the register form, it will check for data, then execute the insert query. But for some reason, the query will NOT insert into the database. In the following code below, I left out the field ID. Doesn't work with it anyways, and I'm not sure it makes a difference. Code: Code: [Select] mysql_query("INSERT INTO servers (username, password, name, type, description, ip, votes, beta) VALUES ($username, $password, $name, $server_type, $description, $ip, 0, 1)"); Full code: Code: [Select] <?php include_once("includes/config.php"); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title><? $title; ?></title> <meta http-equiv="Content-Language" content="English" /> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8" /> <link rel="stylesheet" type="text/css" href="style.css" media="screen" /> </head> <body> <div id="wrap"> <div id="header"> <h1><? $title; ?></h1> <h2><? $description; ?></h2> </div> <? include_once("includes/navigation.php"); ?> <div id="content"> <div id="right"> <h2>Create</h2> <div id="artlicles"> <?php if(!$_SESSION['user']) { $username = mysql_real_escape_string($_POST['username']); $password = mysql_real_escape_string($_POST['password']); $name = mysql_real_escape_string($_POST['name']); $server_type = mysql_real_escape_string($_POST['type']); $description = mysql_real_escape_string($_POST['description']); if(!$username || !$password || !$server_type || !$description || !$name) { echo "Note: Descriptions allow HTML. Any abuse of this will result in an IP and account ban. No warnings!<br/>All forms are required to be filled out.<br><form action='create.php' method='POST'><table><tr><td>Username</td><td><input type='text' name='username'></td></tr><tr><td>Password</td><td><input type='password' name='password'></td></tr>"; echo "<tr><td>Sever Name</td><td><input type='text' name='name' maxlength='35'></td></tr><tr><td>Type of Server</td><td><select name='type'> <option value='Any'>Any</option> <option value='PvP'>PvP</option> <option value='Creative'>Creative</option> <option value='Survival'>Survival</option> <option value='Roleplay'>RolePlay</option> </select></td></tr> <tr><td>Description</td><td><textarea maxlength='1500' rows='18' cols='40' name='description'></textarea></td></tr>"; echo "<tr><td>Submit</td><td><input type='submit'></td></tr></table></form>"; } elseif(strlen($password) < 8) { echo "Password needs to be higher than 8 characters!"; } elseif(strlen($username) > 13) { echo "Username can't be greater than 13 characters!"; } else { $check1 = mysql_query("SELECT username,name FROM servers WHERE username = '$username' OR name = '$name' LIMIT 1"); if(mysql_num_rows($check1) < 0) { echo "Sorry, there is already an account with this username and/or server name!"; } else { $ip = $_SERVER['REMOTE_ADDR']; mysql_query("INSERT INTO servers (username, password, name, type, description, ip, votes, beta) VALUES ($username, $password, $name, $server_type, $description, $ip, 0, 1)"); echo "Server has been succesfully created!"; } } } else { echo "You are currently logged in!"; } ?> </div> </div> <div style="clear: both;"> </div> </div> <div id="footer"> <a href="http://www.templatesold.com/" target="_blank">Website Templates</a> by <a href="http://www.free-css-templates.com/" target="_blank">Free CSS Templates</a> - Site Copyright MCTop </div> </div> </body> </html> I'm restarting this under a new subject b/c I learned some things after I initially posted and the subject heading is no longer accurate. What would cause this behavior - when I populate session vars from a MYSQL query, they stick, if I populate them from an MSSQL query, they drop. It doesn't matter if I get to the next page using a header redirect or a form submit. I have two session vars I'm loading from a MYSQL query and they remain, the two loaded from MSSQL disappear. I have confirmed that all four session vars are loading ok initially and I can echo them out to the page, but when the application moves to next page via redirect or form submit, the two vars loaded from MSSQL are empty. Any ideas? This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=311010.0 This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=329559.0 This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=344191.0 This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=311619.0 This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=321853.0 |
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