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PHP - What Would Be The $_post Variable Name For A Radio Button Option?
what would be the $_POST variable name for a radio button option?
Similar TutorialsWhenever I try and post a form with radio buttons like this
<input type="radio" name"whatever" value="0">and I do a var_dump($_POST)it always shows
array(11) {["whatever"]=> string(2) "on" }
but this works and will display 1 in the var_dump
<input type="radio" name"whatever" value="1">Why is this. I need the value set to 0 because that's the value going into the database. I don't really want to do a str_replace just to replace "on" with "0" I am trying to allow the user to update a variable he chooses by radio buttons, which they will then input text into a box, and submit, to change some attributes. I really need some help here. It works just fine until I add the second layer of variables on top of it, and I can't find the answer to this question anywhere. <?PHP require('connect.php'); ?> <form action ='' method='post'> <select name="id"> <?php $extract = mysql_query("SELECT * FROM cars"); while($row=mysql_fetch_assoc($extract)){ $id = $row['id']; $make= $row['make']; $model= $row['model']; $year= $row['year']; $color= $row['color']; echo "<option value=$id>$color $year $make $model</option> ";}?> </select> Which attribute would you like to change?<br /> <input type="radio" name="getchanged" value="make"/>Make<br /> <input type="radio" name="getchanged" value="model"/>Model<br /> <input type="radio" name="getchanged" value="year" />Year<br /> <input type="radio" name="getchanged" value="color" />Color<br /><br /> <br /><input type='text' value='' name='tochange'> <input type='submit' value='Change' name='submit'> </form> //This is where I need help... <?PHP if(isset($_POST['submit'])&&($_POST['tochange'])){ mysql_query(" UPDATE cars SET '$_POST[getchanged]'='$_POST[tochange]' where id = '$_POST[id]' ");}?> Hi Everyone, I'm trying to make an userlist where I have a button (or better a picture with a hyperlink) which if I click it I will be forwarded to a new page where the user name is send as a $_Post variable. The code below is what I have this far. In some way when I click the send button it always gives the last username in the table in the $_Post variable. Can anyone help me please. Thnx Ryflex <?php require_once('auth.php'); require_once('config.php'); $global_dbh = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD) or die("Could not connect to database"); mysql_select_db(DB_DATABASE, $global_dbh) or die("Could not select database"); $user_query = "SELECT * FROM members"; $user_result = mysql_query($user_query); ?> <form ID="gotoresource" NAME="gotoresource" METHOD="POST" ACTION="resource_compose.php"> <table width="500" border="1" align="center" cellpadding="2" cellspacing="0"> <tr> <td><b>User</b></td> <td><b>Resource</b></td> </tr> <?php while($row = mysql_fetch_assoc($user_result)) { echo "<tr>"; echo "<td>"; echo $row['login']; $user = $row['login']; ?> <input name="User" type="hidden" maxlength="15" id="user" value="<?php echo $user; ?>"/> </td> <td> <input type="submit" name="Submit" value="Send" /> </td> <?php echo "</tr>"; } ?> <html> <head> <title>Userlist</title> <link href="loginmodule.css" rel="stylesheet" type="text/css" /> </head> <body> </body> </html> Hey all, I'm almost too embarrased to post this as I'm sure it is very simple - but for the life of me I can't get this to work. I am a complete newbie to PHP so please bear with me.. What I'm trying to do is to write a program that will go on to calculate a user's Body Mass Index (BMI) based on user inputted data of height and weight. However, I want to be able to accept heights and weights in a number of different units for maximum ease of use. I am trying to write some PHP code that will handle this , the main goal is to convert everything into 'cm' and 'kg' before going on and doing the simple BMI calculation later on. However I am stuck at this point: I have a text field for users to input their weight into. This is immediately followed by two radio buttons for the user to select which units they are inputting their weight in (kilograms or pounds). A third option to input their weight is given after this for those wishing to input their weight in 'stones and pounds'. My problem is as follows: I can't get my code to recognise which radio button (either 'kg' or 'lbs') has been pressed. What should happen is that my code can tell something has been inputted in the text box AND which of the radio buttons has been selected. From this it does one of the two; for the kilogram option it leaves the value as it is, but if the weight has been inputted in pounds (and the 'lbs' radio button selected) then I want the code to convert this into kilos by multiplying by 0.4535. Here is what I have so far (sorry its a bit messy - like i say I am a newbie): <?php //convert.php $ft = $cm = $inches = $weight = $stones =$pounds = $kilos = $units = ""; if(isset($_POST['cm'])) $cm = sanitizeString($_POST['cm']); if(isset($_POST['ft'])) $ft = sanitizeString($_POST['ft']); if(isset($_POST['inches'])) $inches = sanitizeString($_POST['inches']); if(isset($_POST['weight'])) $weight = sanitizeString($_POST['weight']); if(isset($_POST['stones'])) $stones = sanitizeString($_POST['stones']); if(isset($_POST['pounds'])) $pounds = sanitizeString($_POST['pounds']); if(isset($_POST['kilos'])) $kilos = sanitizeString($_POST['kilos']); if(isset($_POST['units'])) $units = sanitizeString($_POST['units']); if ($ft != '') { $height = intval(($ft * 30.48) + ($inches * 2.54)); $out = "you are $height cm tall"; } elseif($cm != '') { $height = intval($cm); $out = "you are $height cm tall"; } else $out = ""; if ($stones != '') { $kilos = intval((($stones * 14) + $pounds) * 0.45359237); $out2 = "you weigh $kilos Kg"; } elseif($weight != '' AND $units = "kg") { $kilos = $weight; $out2 = "you weigh $kilos Kg"; } elseif($weight != '' AND $units = "lbs") { $kilos = ($weight * 0.45359237); $out2 = "you weigh $kilos Kg"; } else $out2 = ""; echo <<<_END <html><head><title>Height & Weight Converter</title> </head><body><pre> Please enter your details below <b>$out$out2</b> <form method="post" action="convert.php"> Height: <input type="text" name="cm" size="3"> cm OR <input type="text" name="ft" size="1">ft <input type="text" name="inches" size="2">inches Weight: <input type="text" name="weight" size="4" /> Kg<input type="radio" name="units" value="kg" /> lbs<input type="radio" name="units" value="lbs" /> OR <input type="text" name="stones" size="2">stone <input type="text" name="pounds" size="2">pounds <input type="submit" value="Submit" /> </form></pre></body></html> _END; function sanitizeString($var) { $var = stripslashes($var); $var = htmlentities($var); $var = strip_tags($var); return $var; } ?> I have a form that creates rows of data input textboxes depending on a user input number of things. I have a naming convention for all these textboxes that basically just keeps incrementing a number suffix for each row. All this is working fine. My problem is I need to get the data inserted into this table of textboxes into an array. Here's my code where I attempt to to this (it does not work): Code: [Select] $temp = $_SESSION['Num_Part']; $count = 1; while ($count <= $temp){ $temp2[$count] = "'Participant_P".$count."'"; //echo $temp2[$count]."<br/>"; $temp3[$count]=$_POST[$temp2[$count]]; //here's the problem $temp4[$count] = "'Result_P".$count."'"; $temp5[$count]=$_POST[$temp4[$count]]; //here's the problem //echo $temp4[$count]."<br/>"; $count++; } The problem is that the $_POST does not work with the variable in the argument position - even though the argument is formatted with single quotes. Can a variable be used in a POST argument and if so what is the correct syntax? If not, is there some other simple solution to harvest the data into an array. I understand I can harvest by explicitly accessing each key in the post assoc array. But this could be dozens of rows of input fields. Thanks in advance for your help here. I couldn't find anything online re this topic. Code: [Select] $amountBoxName = "amount".$id; // Constructs the name of the input field $amountToPay = strip_tags($_POST["$amountBoxName"]); $amountBoxName then goes to 'amount22' says, however $amountToPay is then showing also as 'amount22', not getting the value of the text field whose name/id is amount22 on the previous page. How do I do this? I tried having " around the $amountBoxName, ' and no quotes although still can't get it working. Code: [Select] <?php if (isset($_POST['submit'])) { // Grab the selected value $optionValue = $_POST['subscriptionLevel']; // Grab the id of the selected value ** HOW DO I DO THIS? ** $optionID = ?????????????????????????; } ?> <html> <body> <form name="form" method="post" action=""> <table> <tr> <td> <label for="subscriptionLevel"></label> <select name="subscriptionLevel" id="subscriptionLevel"> <?php do { ?> <option id="<?php echo $dbRowResult['sub_level']; ?>" value="<?php echo $dbRowResult['sub_price']; ?>"><?php echo $dbRowResult['sub_desc']; ?></option> <?php } while ($dbRowResult = $db->dbGetRow($dbQueryResult)); ?> </select> </td> <td> <label> <input type="submit" name="submit" id="submit" value="submit"> </label> </td> </tr> </table> </form> </body> </html> How do I grab the id of the selected value? Thank you. Hi, I need to pass value of variable to another php file. I thought it is possible to do it as following: <form action="products.php"> <INPUT TYPE=hidden NAME='id' . VALUE='$id'> </form> But the problem is like that. The php file inside which I want to write above html code has not using <form> tag and it has no buttons. So how to initiate the transfer of variable into another php file? Is the above idea is not the good idea? Are there any another ways? Why doesn't this code work... Code: [Select] // Initialize variables. $form_value = ''; $form_value = $_POST['form_value']; I get this error... Quote Notice: Undefined index: form_value Thanks, Debbie So, i need this. User clicks on a url, ie: example.com/AEQ438J When I perform this in the code below: Code: [Select] $referrer = $_GET['_url']; // echo $referrer displays the referrer ID contents correctly as "AEQ438J" if ( ! empty($referrer)) { $mysqli->query("UPDATE coming_soon_emails SET clicks = clicks + 1 WHERE code='" . $referrer ."'"); } // this also updates the database correctly as it should if (!empty($_POST['email'])){ // echo $referrer displays the referrer ID contents as BLANK. It should display "AEQ438J"! ..... $referrer displays correctly BEFORE if($_POST['form']), however during the if($_POST['form']) $referrer is empty. How can I fix my code so that $referrer is not empty during the time the user posts their email address in the form? Thank you! Complete PHP and HTML Code: [Select] <?php require "includes/connect.php"; //var_dump($_GET);die; function gen_code($codeLen = 7) { $code = ''; for ($i=0; $i<$codeLen; $i++) { $d=rand(1,30)%2; $code .= $d ? chr(rand(65,90)) : chr(rand(48,57)); } return $code; } function add_code($email_id) { global $mysqli; $code = gen_code(7); $mysqli->query("UPDATE coming_soon_emails SET code='" . $code ."' WHERE email_id='" . $email_id . "'"); if($mysqli->affected_rows != 1) { add_code($email_id); } else return $code; } $msg = ''; $referrer = $_GET['_url']; // echo $referrer displays the referrer ID contents correctly if ( ! empty($referrer)) { $mysqli->query("UPDATE coming_soon_emails SET clicks = clicks + 1 WHERE code='" . $referrer ."'"); } if (!empty($_POST['email'])){ // echo $referrer displays the referrer ID contents as BLANK // Requested with AJAX: $ajax = ($_SERVER['HTTP_X_REQUESTED_WITH'] == 'XMLHttpRequest'); try{ if(!filter_input(INPUT_POST,'email',FILTER_VALIDATE_EMAIL)){ throw new Exception('Invalid Email!'); } $mysqli->query("INSERT INTO coming_soon_emails SET email='".$mysqli->real_escape_string($_POST['email'])."'"); if($mysqli->affected_rows != 1){ throw new Exception('This email already exists in the database.'); } else { $email_code = add_code($mysqli->insert_id); } $msg = "http://www.example.com/" . $email_code; //the following doesn't work as referrer is now empty :( if ( ! empty($referrer)) { $mysqli->query("UPDATE coming_soon_emails SET signup = signup + 1 WHERE code='" . $referrer ."'"); } if($ajax){ die(json_encode(array('msg' => $msg))); } } catch (Exception $e){ if($ajax){ die(json_encode(array('error'=>$e->getMessage()))); } $msg = $e->getMessage(); } } ?> <!DOCTYPE html> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title></title> <link rel="stylesheet" type="text/css" href="css/styles.css" /> </head> <body> <div id="launch"> <form id="form" method="post" action=""> <input type="text" id="email" name="email" value="<?php echo $msg;?>" /> <input type="submit" value="Submit" id="submitButton" /> </form> <div id="invite"> <p style="margin-top:20px;">The ID of who referred you: <?php echo $referrer; //this displays correctly?>)</p> <p style="margin-top:20px;"><span id="code" style="font-weight:bold;"> </span></p> </div> </div> <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.3/jquery.min.js"></script> <script src="js/script.js"></script> </body> </html> script.js Code: [Select] $(document).ready(function(){ // Binding event listeners for the form on document ready $('#email').defaultText('Your Email Address'); // 'working' prevents multiple submissions var working = false; $('#form').submit(function(){ if(working){ return false; } working = true; $.post("./index.php",{email:$('#email').val()},function(r){ if(r.error){ $('#email').val(r.error); } else { $('#email').val(r.msg); // not needed but gets hidden anyways... $('#launch form').hide(); $("#code").html(r.msg); $("#invite").fadeIn('slow'); } working = false; },'json'); return false; }); }); // A custom jQuery method for placeholder text: $.fn.defaultText = function(value){ var element = this.eq(0); element.data('defaultText',value); element.focus(function(){ if(element.val() == value){ element.val('').removeClass('defaultText'); } }).blur(function(){ if(element.val() == '' || element.val() == value){ element.addClass('defaultText').val(value); } }); return element.blur(); } htaccess Code: [Select] RewriteEngine on RewriteCond %{HTTP_HOST} ^my-url.com RewriteRule (.*) http://www.my-url.com/$1 [R=301,L] RewriteCond %{REQUEST_FILENAME} !-f RewriteCond %{REQUEST_FILENAME} !-d RewriteRule ^([a-z0-9]+)$ /index.php?_url=$1 [NC,L,QSA] table.sql Code: [Select] CREATE TABLE IF NOT EXISTS `coming_soon_emails` ( `email_id` int(11) NOT NULL auto_increment, `email` varchar(64) collate utf8_unicode_ci NOT NULL, `code` char(7) collate utf8_unicode_ci DEFAULT NULL, `clicks` int(64) collate utf8_unicode_ci DEFAULT 0, `signup` int(64) collate utf8_unicode_ci DEFAULT 0, `ts` timestamp NOT NULL default CURRENT_TIMESTAMP, PRIMARY KEY (`email_id`), UNIQUE KEY `email` (`email`), UNIQUE KEY `code` (`code`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci; Hopefully someone can help, firstly i am a newbie at php coding but keen to learn more.
Here is my problem
The database is built correctly with all the information i need, the first part is the dropdown menu which you select a car, next you choose a month and mileage - from there it shall show you the correct price for each one. There is columns for each price, mileage and months i just need to figure out how best to start this thing.
I first started by this
$query = "SELECT DISTINCT Full_Description FROM import"; Hello, I had 3 radio buttons with the same name, well, I had created 3 text box that are next to those 3 radio buttons. When I click save to the form, I need to know which radio button had been pressed, so that I can detect & retrieve its value. Any help? Thanks What am I doing wrong with this selected radio button? <form action="Process/privacy.php" method="post" enctype="multipart/form-data" id="privacy"> <div id="privacy_vis">Your profile is visible to:</div> <div id="privacy_select"> <label> <input name="RadioGroup1" type="radio" id="RadioGroup1_0" value="1" <?if($visible=="1")echo 'checked="checked"';?> /> Everyone</label> <label> <input name="RadioGroup1" type="radio" id="RadioGroup1_1" value="0"/> Members Only</label> </div> <br /> <div id="privacy_vis">Your Password to view your private pictures is:</div> <div> <input name="pictures_pw" type="text" id="pictures_pw" value="<? echo "$xxx_pw" ?>" size="50" maxlength="20" /> </div> <br /> <div> <input name="submit" type="submit" class="button" id="submit" value="Save Changes" /> </div> </form> </div> I am trying to have the text alongside the radio button trigger the radio button (cannot use < a href ) e.g. () Trigger with this text The closest I have found is <label for="r1"><input type="radio" name="group1" id="r1" value="1" /> button one</label> But it does not seem to work? Any help greatly appreciated I have a function to display some images and allow a user to select a choice via a radio button.The value is then passed to another function. I have 2 problems My selection is not being passed back and I cant assign the value to a query sring in a link to another page. On the form do i need to add checked? Any help appreciated. Code: [Select] function cover() { echo'<h2>Please upload your book cover or choose one from the selection</h2> <p>All book ideas require a cover. Your choice can be changed at a later date.</p>'; //process selection of cover if (isset($_POST['submit'])) { $coverID=$_POST['cover']; echo $coverID; ?>   <ul><li class="demo-menu-link"><a href="?page=submenu7&coverID=$coverID">Finnished Cover</a></li></ul><?php exit(); } else{ echo "not Submitted"; } global $wpdb; $query = "select * from wp_cover"; $result = mysql_query($query) or trigger_error("Query: $query\n<br />MySQL Error: " . mysql_error()); echo mysql_error(); if (!$result){ return false; } echo'<div class="wrap"><p>choose from one of the covers below</p></div>'; ?><form action="<?php $_SERVER['PHP_SELF'] ?>" method="POST" id="cover" enctype="multipart/form-data"> <table><tr><?php /* display picture and radio button */ while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) { $coverID=$row['coverID']; echo"<img src=\"/wordpress_3/wp-content/plugins/Authors2/jackets/{$row['pix']}\" />"; echo"<td>"; echo $coverID; echo "<Input type = 'Radio' Name ='cover' value= '$coverID'/>"; ?> </tr></table> <input type=submit value=submit> </form><?php } } I am trying to make a set of radio buttons that when you make a selection, it displays a sorted database from MYSQL. I have the MYSQL part figured out but I cannot figure out how to properly display it. I have the following code and I made a select screen just to test: index.html <html> <body> <form action="select.php" method="post"> <input type="radio" name="table" value="table1"> Table 1 <br> <br> <input type="radio" name="table" value="table2">Table 2 <br> <br> <input type="radio" name="table" value="table3">Table 3 <br> <br> <input type="radio" name="table" value="table4">Table 4 <br> <br> <input type="radio" name="table" value="table5">Table 5 <br> <br> <input type="Submit" Name = "submit" value="Submit"> <input type="Reset" value="Reset"> </form> </body></html> select.php <?PHP $selected_radio = $_POST["table"]; if ($selected_radio = = 'table1) { echo "Table 1 Here."; } else if ($selected_radio = = 'table2') { echo "Table 2 Here."; } else if ($selected_radio = = 'table3') { echo "Table 3 Here."; } else if ($selected_radio = = 'table4') { echo "Table 4 Here."; } else if ($selected_radio = = 'table5') { echo "Table 5 Here."; } ?> These are two separate files. When I go to run the code, no matter what I pick, the next page is always blank. Again, the select.php is just suppose to be a check, the real code will display the table instead of echoing a message. how do you make it so that a radio button is either checked or unchecked based on database? This topic has been moved to HTML Help. http://www.phpfreaks.com/forums/index.php?topic=317717.0 Hi, I have 2 radio button's within a table and need to pass this array. All other rows within my table can be sent as array's and captured using $_POST['field_name'][$ROW 1 value etc]. However for radio buttons this doesn't work. As an example, a standard textbox I can send an array using the following: echo "<td width='33%'><input type='Textbox' width='100%' id='test' name='test[]' value='" .$row['test']. "'></td>"; I can then capture it using: $test = $_POST['test'][$iLine]; This works, no problem, however for radio buttons, I can't use a static array name, as presumably it dumps all rows into the array, if I do this, only the last row has a checked button, hence I need to use the following (where $checked includes the logic to decide whether the button should be checked or not, this works correctly): echo "<input type='radio' name='".$row['venue_id']."[]' value='1'".$checked."/>P1" echo "<input type='radio' name='".$row['venue_id']."[]' value='0'".$checked2." />P2"; I tried using the following: var_dump($_POST[$row]['game_id'][$iLine]); But this just returns a null value. Any ideas? |
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