PHP - Show Value From A Mysql Table Selected
Hi all,
I am trying to make a members details section that can be updated. I want to be able to "SELECT * FROM users WHERE email='$email'" and then show the values that can be changed in a html drop down box with the selection that was made when the user registered already selected="selected"; You will be able to see what I am attempting to do below. <?php $sql = "SELECT manufacturer FROM table1 WHERE email=$'email'"; $result = mysqli_query($cxn,$sql); $row = mysqli_fetch_assoc($result); foreach manufacturer in table1 { if table1.manufacturer = table2.manufacturer { echo '<option name="manufacturer" selected="selected" value"$row['manufacturer']"</option>'; } else { echo '<option name="manufacturer" value"$row['manufacturer']"</option>'; } } ?> Similar Tutorialshi, i'm new to php. i've got a problem. I've 3 tables and table has following content table 1 id name email address phone execution_date executor_name web_address table 2 id name email address phone execution_date executor_name project_title table 3 id name email address phone execution_date executor_name reviewer I want to export these table to and spreadsheet (.xls) with some criteria a form will assign which data will published at the spreadsheet with these criteria #all data can be exported from three tables #some column can be selected from three tables #some or all data can be selected from individual table i've implement a script for this but it didn't meet my requirements. Can anyone help? here is my script <?php $DB_Server = "localhost"; //your MySQL Server $DB_Username = "root"; //your MySQL User Name $DB_Password = "pass"; //your MySQL Password $DB_DBName = "mydb"; //your MySQL Database Name $search_from_date = $_POST['start_date']; $search_to_date = $_POST['end_date']; $Connect = @mysql_connect($DB_Server, $DB_Username, $DB_Password) or die("Couldn't connect to MySQL:<br>" . mysql_error() . "<br>" . mysql_errno()); $Db = @mysql_select_db($DB_DBName, $Connect) or die("Couldn't select database:<br>" . mysql_error(). "<br>" . mysql_errno()); $now_date = date('m-d-Y H:i'); if(($_POST['typer_of_report'] == 'rrc_report') || ($_POST['typer_of_report'] == 'all_report')) { $DB_TBLName = 'rrc_record'; } if(($_POST['typer_of_report'] == 'erc_report') || ($_POST['typer_of_report'] == 'all_report')) { $DB_TBLName2 = 'erc_record'; } if(($_POST['typer_of_report'] == 'aeec_report') || ($_POST['typer_of_report'] == 'all_report')) { $DB_TBLName3 = 'aeec_record'; } $file_type = "vnd.ms-excel"; $file_ending = "xls"; //} header("Content-Type: application/$file_type"); header("Content-Disposition: attachment; filename=protocol_report.$file_ending"); header("Pragma: no-cache"); header("Expires: 0"); if($DB_TBLName) { $sql = "Select * from ".$DB_TBLName." where execution_date >= '".$search_from_date."' and execution_date <= '".$search_to_date."' order by execution_date desc"; $Use_Title = 1; $title = "Report for $DB_TBLName on $now_date"; $result = @mysql_query($sql,$Connect) or die("Couldn't execute query:<br>" . mysql_error(). "<br>" . mysql_errno()); if ($Use_Title == 1) { echo("$title\n"); } $sep = "\t"; //tabbed character for ($i = 0; $i < mysql_num_fields($result); $i++) { echo mysql_field_name($result,$i) . "\t"; } print("\n"); while($row = mysql_fetch_row($result)) { $schema_insert = ""; for($j=0; $j<mysql_num_fields($result);$j++) { if(!isset($row[$j])) $schema_insert .= "NULL".$sep; elseif ($row[$j] != "") $schema_insert .= "$row[$j]".$sep; else $schema_insert .= "".$sep; } $schema_insert = str_replace($sep."$", "", $schema_insert); $schema_insert = preg_replace("/\r\n|\n\r|\n|\r/", " ", $schema_insert); $schema_insert .= "\t"; print(trim($schema_insert)); print "\n"; } //} echo "\n...\n"; } if($DB_TBLName2) { $sql = "Select * from ".$DB_TBLName2." where execution_date >= '".$search_from_date."' and execution_date <= '".$search_to_date."' order by execution_date desc"; $result = @mysql_query($sql,$Connect) or die("Couldn't execute query:<br>" . mysql_error(). "<br>" . mysql_errno()); $Use_Title = 1; $title = "Report for $DB_TBLName2 on $now_date"; if ($Use_Title == 1) { echo("$title\n"); } $sep = "\t"; //tabbed character for ($i = 0; $i < mysql_num_fields($result); $i++) { echo mysql_field_name($result,$i) . "\t"; } print("\n"); while($row = mysql_fetch_row($result)) { $schema_insert = ""; for($j=0; $j<mysql_num_fields($result);$j++) { if(!isset($row[$j])) $schema_insert .= "NULL".$sep; elseif ($row[$j] != "") $schema_insert .= "$row[$j]".$sep; else $schema_insert .= "".$sep; } $schema_insert = str_replace($sep."$", "", $schema_insert); $schema_insert = preg_replace("/\r\n|\n\r|\n|\r/", " ", $schema_insert); $schema_insert .= "\t"; print(trim($schema_insert)); print "\n"; } echo "\n...\n"; } if($DB_TBLName3) { $sql = "Select * from ".$DB_TBLName3." where execution_date >= '".$search_from_date."' and execution_date <= '".$search_to_date."' order by execution_date desc"; $result = @mysql_query($sql,$Connect) or die("Couldn't execute query:<br>" . mysql_error(). "<br>" . mysql_errno()); $Use_Title = 1; $title = "Report for $DB_TBLName3 on $now_date"; if ($Use_Title == 1) { echo("$title\n"); } $sep = "\t"; //tabbed character for ($i = 0; $i < mysql_num_fields($result); $i++) { echo mysql_field_name($result,$i) . "\t"; } print("\n"); while($row = mysql_fetch_row($result)) { $schema_insert = ""; for($j=0; $j<mysql_num_fields($result);$j++) { if(!isset($row[$j])) $schema_insert .= "NULL".$sep; elseif ($row[$j] != "") $schema_insert .= "$row[$j]".$sep; else $schema_insert .= "".$sep; } $schema_insert = str_replace($sep."$", "", $schema_insert); $schema_insert = preg_replace("/\r\n|\n\r|\n|\r/", " ", $schema_insert); $schema_insert .= "\t"; print(trim($schema_insert)); print "\n"; } } ?> have anyone any idea? create table mimi (mimiId int(11) not null, mimiBody varchar(255) ); <?php //connecting to database include_once ('conn.php'); $sql ="SELECT mimiId, mimiBody FROM mimi"; $result = mysqli_query($conn, $sql ); $mimi = mysqli_fetch_assoc($result); $mimiId ='<span>No: '.$mimi['mimiId'].'</span>'; $mimiBody ='<p class="leading text-justify">'.$mimi['mimiBody'].'</p>'; ?> //what is next? i want to download pdf or text document after clicking button or link how to do that Hi, How can I get others informations on another page by clicking on one row's value I have this code, but it doesn't work: while($row = mysql_fetch_array($result)) { echo "<tr><p>"; echo "<th><p>" . $row['fname'] . " " . $row['lname'] . "</p></th>"; echo"<th><p><a href='student.php?id='".$row['topic']."'\'>".$row['topic']."</p></a></th>"; echo "</tr>"; } echo "</table>"; Student.php <?php $con = mysql_connect("localhost","root",""); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("college", $con); $result = mysql_query("SELECT * FROM students"); $topic = $_Get['topic']; while($row = mysql_fetch_array($result)) { echo "<tr><p>"; echo "<th><p>" . $row['month']." " .$row['datetime']."</p></th>"; echo"<th><p>". $row['topic'] ."</p></th>"; echo "<th><p>" . $row['gender'] . "</p></th>"; echo "<th><p>" . $row['fname'] . " " . $row['lname'] . "</p></th>"; echo "<th ><p>" . $row['id'] . "</p></th>"; echo "</tr>"; echo "</table>"; mysql_close($con); } ?> friend the code display all the managers name
<?phpand the variable below displays the result $Manager= $row['Manager'] ; but how do i do it on the above dropdown list the it shows which result is in the $Manager variable? I have a form gathering data from the database. There is one field 'country' which is a combo box. The combo box is populated from the countries table which joins the customers table to provide the country specific to the customer. I'm trying to have the combo box display the country associated with the customer. I think I'm close in my code, but unsure. This is a playground to so I can implement on our other site. <?php require_once('database.php'); $sql2 = "SELECT * From countries "; $countries = $db->query($sql2); if(isset($_GET['customerID'])) { $customerID = filter_input(INPUT_GET, 'customerID', FILTER_SANITIZE_NUMBER_INT); $sql = "SELECT * FROM customers WHERE customerID =$customerID "; //$sql2 = "SELECT * From countries //INNER JOIN customers ON countries.countryCode=customers.countryCode //WHERE customers.customerID = $customerID"; $stmt = $db->query($sql); } if(isset($_GET['customerID'])){ $customerID = filter_input(INPUT_GET, 'customerID', FILTER_SANITIZE_NUMBER_INT); $countryQuery = " {$sql2} INNER JOIN customers ON countries.countryCode = customers.countryCode WHERE customers.customerID = $customerID"; $countriesQuery = $db->prepare($countryQuery); $countriesQuery->execute(['customerID' => $_GET['customerID']]); $selectedCountry = $countriesQuery->fetch(PDO::FETCH_ASSOC); var_dump($selectedCountry); } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <!-- the head section --> <head> <title>My Guitar Shop</title> <link rel="stylesheet" type="text/css" href="main.css" /> </head> <!-- the body section --> <body> <div id="page"> <div id="header"> <h1>SportsPro Technical Support</h1> <p>Sports management software for the sports enthusiast.</p></h1> </div> <div id="main"> <h1>View/Update Customer</h1> <form action="update.php" method="get" > <?php ?> <div id="content"> <!-- display a table of products --> <h2>Customers</h2> <form name="customerInfo"> <?php foreach ($stmt as $cust) { ?> <div> <label>First Name</label> <input type="text" name="name" class ="form-control" value ="<?php echo $cust['firstName']; ?>"> </div><br> <div> <label>Last Name</label> <input type="text" name="name" class ="form-control" value ="<?php echo $cust['lastName']; ?>"> </div><br> <div> <label>Address</label> <input type="text" name="address" class ="form-control" value ="<?php echo $cust['address']; ?>"> </div><br> <div> <label>City</label> <input type="text" name="city" class ="form-control" value ="<?php echo $cust['city']; ?>"> </div><br> <div> <label>State</label> <input type="text" name="state" class ="form-control" value ="<?php echo $cust['state']; ?>"> </div><br> <form action="update.php" method="get"> <select name="country"> <option value=""></option> <?php foreach ($countries->fetchAll() as $country): ?> <option value="<?php echo $country['customerID']; ?> <?php echo isset($customerID) == $selectedCountry['customerID'] ? ' selected':''?> "><?php echo $country['countryName']; ?></option> <?php endforeach;?> </select> </form> </div> <br> <div> <label>Country Code</label> <input type="text" name="countryCode" class ="form-control" value ="<?php echo $cust['countryCode']; ?>"> </div><br> <div> <label>Zip Code</label> <input type="text" name="postalCode" class ="form-control" value ="<?php echo $cust['postalCode']; ?>"> </div><br> <div> <label>Email </label> <input type="text" name="email" class ="form-control" value ="<?php echo $cust['email']; ?>"> </div><br> <div> <label>Phone Number </label> <input type="text" name="phone" class ="form-control" value ="<?php echo $cust['phone']; ?>"> </div><br> <div> <label>Password </label> <input type="text" name="password" class ="form-control" value ="<?php echo $cust['password']; ?>"> </div><br> <div> <?php } ?> </div> </div> <form action="UpdateCustomer.php" method="get"> <input type="submit" name="data" value="Update_Data"></input> </form> <div id="footer"> <p> © <?php echo date("Y"); ?> SportsPro, Inc. </p> </div> </div><!-- end page --> </body> </html>
if the session is true $_SESSION['frommonth'] i want it to show the selected session Code: [Select] <select name="from_month" id="from_month"> <option value="<?php echo $_SESSION['frommonth'];?>" selected="selected">mm</dd> <?for ($i=1;$i<=12;$i++):?> <option value="<?=$i?>"><?=$months[$i]?></dd> <?endfor;?> </select> how could i do this? I've got a HTML drop down box as similar to this: <select name="dropdown"> <option>Option 1</option> <option>Option 2</option> <option>Option 3</option> </select> If I run a mysql query and get a result of "Option 3", is there anyway using PHP to give Option 3 the selected value? Hi, My output in html is : Code: [Select] <uL><li id="B1"></li> <li id="B2"></li> <li id="B3"></li> <li id="B4"></li> <li id="B5"></li> <li id="B6"></li> <li id="B7"></li> <li id="B8"></li> <li id="B9"></li> <li id="B10"></li> <li id="B11"></li> <li id="B12" class="active"></li> <li id="B13" class="no"></li> <li id="B14" class="no"></li> <li id="B15" class="no"></li> <li id="B16" class="no"></li> <li id="B17" class="no"></li> <li id="B18" class="no"></li> <li id="B19" class="no"></li> <li id="B20" class="no"></li> </ul> If MySQL query result is equal to `6`, then `<li>` tag with `id` equal to "`B12`" should have class "`active`". All the `<li>` elements occuring after this active element should have class "`no`". This shows images of horizontal rating between `0` and `10` and between 0.5 Example : 0 .5 1 1.5 2 2.5 3 3.5 4 4.5 5 5.5 6 6.5 7 7.5 8 8.5 9 9.5 10 In the example above elements from `0` to `5` will be blue, element `6` will be white and elements from `7` to `10` are black. How could I generate this using PHP and/or MySQL? Thanks, XXXX chirstmas XXXX Hey in my edit page i have 2 radio buttons in my form and i need to make sure the same value is still selected how can i do that? thanks Hi all I need to combine these two scripts: Firstly, the following decides which out of the following list is selected based on its value in the mySQL table: <select name="pack_choice"> <option value="Meters / Pack"<?php echo (($result['pack_choice']=="Meters / Pack") ? ' selected="selected"':'') ?>>Meters / Pack (m2)</option> <option value="m3"<?php echo (($result['pack_choice']=="m3") ? ' selected="selected"':'') ?>>Meters / Pack (m3)</option> <option value="Quantity"<?php echo (($result['pack_choice']=="Quantity") ? ' selected="selected"':'') ?>>Quantity</option> </select> Although this works OK, I need it also to show dynamic values like this: select name="category"> <?php $listCategories=mysql_query("SELECT * FROM `product_categories` ORDER BY id ASC"); while($categoryReturned=mysql_fetch_array($listCategories)) { echo "<option value=\"".$categoryReturned['name']."\">".$categoryReturned['name']."</option>"; } ?> </select> I'm not sure if this is possible? Many thanks for your help. Pete The Script:
<form method="post" action="<?php echo $_SERVER['PHP_SELF'] ?>"> <input type="text" name="hashtags" /> <input type="submit" name="submit" /> </form> <?php include("connect.php"); ?> <?php if(isset($_POST['submit'])){ $hashtags = explode(", ", $_POST['hashtags']); for($i= 0; $i < count($hashtags); $i++){ $tqs = "SELECT `id` FROM `hashtags_two` WHERE `hashtags` = '" . $hashtags[$i] . "'"; $tqr = mysqli_query($dbc, $tqs) or die(mysqli_error($dbc)); } $fetch_array = array(); while($row = mysqli_fetch_array($tqr)){ $fetch_array[] = $row['id']; } }Hey, sorry for these fundamental array questions lately, I am not going to ask much more when it comes to this. The hashtags come from the submit form (separated by commas) and get stored inside an array with the "explode()" function. The script should select the ID numbers of the hashtags from the table. With the script above only the last row gets inserted into $fetch_array inside the while loop. When the $fetch_array variable is printed on screen then only one ID number can be seen inside the array: Array ( [0] => 24 )How can I have the other ID numbers too? I am very new to PHP and haven't wriiten an update program except in the class I took about 4 years ago using MYSQL.
The company I work for is using PDO so I am having a little bit of a learning curve.
I have a table with a checkbox at the end and I want to insert the records from the table into a new file I created called
OPPSHEDT
SHEDORD Order Number 14 Char
SHEDBORD BackOrder Number 2 Char
SHEDPKD Picked Cases 9,0 Decimal
SHEDSHP Shipped Cases 9,0 Decimal
I'm just not sure how to write the update program to read the array of records and run through the loop and insert the items checked. I saw some other examples on here and all over the internet but they were using mysql. I have a copy of the code to create my table below.
I'd appreciate the help if you can.
Thanks.
ShipEstimate.php 6.41KB
4 downloads
Hi Good day Can someone pls help me regarding with this matter. I have a page for inserting records. And I have a combobox that is fetched through the specific field in database. I also have a table of records, for each row i have an href edit which throws the values to its respective texbox and combobox. THE PROBLEM is that when i click the href edit, the value from a selected row was not displayed from the combobox Hi all I have created a mySQL query and assigned it to a string: Code: [Select] $getjobs = mysql_query (" SELECT * FROM jobs WHERE from_date >= '".substr($newdate, 0, 10)."' $keyword_search $sector_search $salary_search $location_search $type_search ORDER BY job_refno DESC ") or die (mysql_error()); Is there any way to output the actual query to the browser to check it? Hi guys, I have page where it echos out the image url from mysql in a MAMP Server, however when i echo the image url out it seems to be fine but as soon as i put in a img scr it wont show the image but it shows the container. I have the code here Code: [Select] <div id="maincontentholderbottom"> <div id="maincontentholderbottom-index-left"> <div id="news-container"><ul> <?php $select=mysql_query("SELECT * FROM news"); while($get_news=mysql_fetch_array($select)){ $newsid=$get_news['id']; $title=$get_news['title']; $text=$get_news['text']; $newsdate=$get_news['date']; $newstime=$get_news['time']; $imagelink=$get_news['newsimagelink']; $newstext=substr($text, 0, 420); echo"<li><div id='title'>$title</div><div id='newsblock'>$newstext... <a href='http://localhost/mycomputer/create/news/index.php?id=$newsid'>Read More</a></div> <div id='newsimage'><img src='$imagelink' width='150' height='70'/></div> </li>"; } ?> </ul> </div> </div> </div> Do u know why is it like this? I appreciate your help in advance. Thanks! Hello, I need some help. Say that I have a list in my MySQL database that contains elements "A", "S", "C", "D" etc... Now, I want to generate an html table where these elements should be distributed in a random and unique way while leaving some entries of the table empty, see the picture below. But, I have no clue how to do this... Any hints? Thanks in advance, Vero Hi all expert. I am a newbie in this PHP programming. I need your help or advise on the PHP. And question is, I have a list of data and the details are as below:
ID BILLNO DATE AMOUNT ITEM DESCRIPTION QTY UPRICE 1 IV001 01/01/2015 100.00 A1 Balloon 1 30.00 2 IV001 01/01/2015 100.00 A2 Bag 2 20.00 3 IV001 01/01/2015 100.00 A3 Pen 3 10.00 4 IV002 02/01/2015 20.00 A3 Pen 2 10.00 5 IV003 02/01/2015 50.00 A1 Balloon 1 30.00 6 IV003 02/01/2015 50.00 A2 Bag 1 20.00 How can I make the output in xml by using PHP to output as below: <RECORD> <HEADER BILLNO="IV001" DATE="01/01/2015" AMOUNT="100.00> <DETAIL ITEM="A1" DESCRIPTION="Balloon" QTY="1" UPRICE="30.00"> </DETAIL> <DETAIL ITEM="A2" DESCRIPTION="Bag" QTY="2" UPRICE="20.00"> </DETAIL> <DETAIL ITEM="A3" DESCRIPTION="Pen" QTY="3" UPRICE="10.00"> </DETAIL> </HEADER> <HEADER BILLNO="IV002" DATE="02/01/2015" AMOUNT="20.00> <DETAIL ITEM="A3" DESCRIPTION="Balloon" QTY="2" UPRICE="10.00"> </DETAIL> </HEADER> </RECORD> Your feedback is highly appreciated. Thank you. HI All, I have noticed that when people show database structure on forums like this one, they have it as a table, like the following:
How do you create this? Can someone please tell me how to use the "SHOW FIELDS FROM $mytable" in php? I understand how the MySql works but need to get these fields back into an array in php. That is the part I am strruggling with.. I normally return rows of data from my table and use a while loop. |