PHP - Help With Escaping Quotes

Hello everyone!  This is my first post.  I am very new to php and mysql and coding in general.  It has not been made 100% clear to me as to when I should use single quotes, double quotes, and {}.  From what I gather you use single quotes for literal interpretation...  so if you put something like a variable in single quotes and echoed it, it would literally echo it as it is written and not the value of the variable.  in double quotes, I gather that it will echo the value of the variable.  as for {} I am unclear as to when to use the curly brackets for a variable.  I am assuming if you had a statement in single quotes and you put a variable in curly brackets you would get the value of the variable?
Edited by LazerOrca, 25 November 2014 - 11:20 PM.

The fancy-looking quotes won't insert into my DB, so I'm trying to convert them to %93 & %94 or normal quotes.    Nothing I've tried works.   Code:   $fancy=" “test” ";
$fixed=htmlentities($old, ENT_QUOTES);   echo "fancy: $fancy<br>"; echo "fixed: $fixed";

Results:

fancy: “test”
fixed:   I want $fixed to be %93test%94, or even "test" would work. 
Edited by rwmaho, 18 October 2014 - 01:28 PM.

I don't think I've asked this before have I??  can someone give me an internet KB that gives me all scenarios that warrant using singles or doubles?  as in, wrapping values, variables, and why I need to do either, and when, etc, etc....?

thanks

Edited March 29 by ajetrumpet

A problem has arisen which puzzles me. I have forms which save data to MySql and retrieve it, showing it as the default data in the form. Naturally I escape any quotes before sending it to the database and remove the slashes when I retrieve it. But the form HTML code shows the data like this value="$variable" which is fine when only single quotes are used in the data but causes a problem when the user uses double quotes. So data of John \"Jack\" Smith would be output as value="John "Jack" Smith" with obvious problems. If I use value='...' then that would cause problems with single quotes.

I haven't seen the answer in any of my books. The only things I can think of is changing all double quotes to single before saving to DB or converting them with htmlspecialcharacters so they are no longer actual quotes.

Hi Php Freaks

I am trying to escape variable but I am lost. I am sure that it is easy. can anyone help ta

Code: [Select]
$y="\\$GLOBALARRAY = array(   \n";
echo $y;

Hello!

I'm very new to PHP, and I'm sure this is a noob question - still, its got me stuck!

How would I best escape this properly?

$resizeObj = new resize('C:\xampp\htdocs\images_test\$file');

so that $file is parsed?

the whole script is as follows:

Code: [Select]
<?php
// *** Include Nathan's class
include("resize-class.php");

// Define the full path to your folder from root 
$path = 'C:\xampp\htdocs\images_test'; 

// Open the folder 
$dir_handle = @opendir($path) or die("Unable to open $path"); 

    // Loop through the files 
    while ($file = readdir($dir_handle)) { 

    if($file == "." || $file == ".." || $file == "index.php" ) 

        continue; 

// *** 1) Initialise / load image
$resizeObj = new resize('C:\xampp\htdocs\images_test\$file');
// *** 2) Resize image 
$resizeObj -> resizeImage(100, 100, 'auto');
// *** 3) Save image
$resizeObj -> saveImage('C:\xampp\htdocs\images_test\$file', 90);

        echo "<a href=\"$file\">$file</a><br />"; 
echo $path;

    } 
    // Close 
    closedir($dir_handle); 



?>

Hi,

I have set up a simple function so that when a user enters a title in a php form, php gives the first letter of each word a capital letter. As follows:

function caps($text){
$search_text=$text;
$search_text=ucwords(strtolower($search_text));
$look_for = "(a";
$change_to = "(A";
$changed_text = str_replace($look_for, $change_to, $search_text);
$search_text=$changed_text;
$look_for = "(b";
$change_to = "(B";
$changed_text = str_replace($look_for, $change_to, $search_text);
$search_text=$changed_text;
$look_for = "(c";
$change_to = "(C";

//...etc...etc.. up to

$look_for = "(z";
$change_to = "(Z";
$changed_text = str_replace($look_for, $change_to, $search_text);
$search_text=$changed_text;
return $search_text;

}

The trouble is, if I were to enter the following "The secret of DNA", my function would return "The Secret Of Dna" (removes the caps). Any ideas how to get around this would be most useful. Thanks in advance.

Russ

Do I need to escape variables passed via link? Is it possible that someone does an SQL Injection via unescaped $_GET variable? (Yes I am using it in an SQL query, not inserting it into a DB tho)

Im getting a syntax error caused by the first line. How do I properly escape the code? echo "<tr class="'.$colors[$i++ % 2].'">
<td align=center  nowrap>($phone1) XXX-$phone2</td>
<td align=center  nowrap>$overall</td>
<td align=center  nowrap>$hygiene</td>
<td align=center  nowrap>$attitude</td>
<td align=center  nowrap>$ethnicity</td>
<td align=center  nowrap>$body</td>
<td align=center  nowrap>$city</td>
<td align=center  nowrap>$user</td>
<td align=center  nowrap>$date</td>
<td align=center  nowrap>$comment</td>
</tr>";

I have a table with two columns A and B.  I'm submitting a form where the user selects different checkboxes.   Column A contains the values of all the checkboxes.  I want to, after the form is submitted, using the array of values of randomly checked checkboxes, search the table for the corresponding values in column B.  Then display the values of selected checkboxes and their cosesponding values from column B. 
First I did an implode() on the array of submitted checkbox values,
Code: [Select]
$list = "'".implode("','", $_POST['Ref'])."'"; then did a mysql_real_escape_string on that.
Code: [Select]
for($i=0;$i<$count;$i++)
     {
$list = mysql_real_escape_string($list[$i]);
} I got a
Warning: mysql_real_escape_string() [function.mysql-real-escape-string]: Access denied for user 'SYSTEM'@'localhost' (using password: NO)
Warning: mysql_real_escape_string() [function.mysql-real-escape-string]: A link to the server could not be established
for each row of $list.
What am I doing wrong? 

Hi guys I am encoding JSON in PHP but want to know how to escape ' and " thats in the content?

Thanks

I've got this code and it works fine.  All I want to do is, when people click on the x to delete something they submitted erroneously, I want a confirmation...really want to delete this?  (sometimes that x is too tempting you know)

But I *think* I'm having trouble escaping the line (near bottom):  onsubmit='".return confirm('Really Delete');."'

I'm not sure if it will work anyhow...but right now it doesn't.

Thanks for any suggestions.

<code>
<?php

include '../php/config_conn.php';

$querysum = "SELECT SUM(total_time) FROM `coop_hours` where user = '".$_SESSION['user_name']."'";
$resultsum = mysql_query($querysum);
$arr = mysql_fetch_row($resultsum);
$resulthours = $arr[0];

$querytime = "SELECT * FROM `coop_hours` WHERE user = '".$_SESSION['user_name']."' ORDER BY `date_completed`";
$result = mysql_query($querytime);

$num = mysql_num_rows($result);

mysql_close();


echo "<table width='1000' cellpadding='0' cellspacing='0' border='0'><tr>
      <td width='200'><strong>Coop Job</strong></td>
      <td align=center width='200'><strong>Date Completed</strong></td>
      <td align=center width='120'><strong>Total Time</strong></td>
      <td width='380'><strong>Comments</strong></td>
      <td width='100'>Delete Entry</td></tr>";

$i=0;
while ($i < $num) {
   
$hours_id = mysql_result($result, $i, "hours_id");
$user = mysql_result($result, $i, "user");
$coop_job = mysql_result($result, $i, "coop_job");
$date_completed = mysql_result($result, $i, "date_completed");
$start_time = mysql_result($result, $i, "start_time");
$end_time = mysql_result($result, $i, "end_time");
$total_time = mysql_result($result, $i, "total_time");
$comments = mysql_result($result, $i, "comments");


echo "<tr><td>$coop_job</td>
   <td align=center>$date_completed</td>
   <td align=center>$total_time</td>
   <td>$comments</td>
   <td align=center valign='middle'>
   <form action='".php/del.php."' method='".post."' onsubmit='".return confirm('Really Delete');."'>
   <input type='".hidden."' name='".hours_id."' value='".$hours_id."'>
   <input TYPE='image' SRC='images/del.png' width='11' height='11' border='0' alt='Delete'>
   </form>
   </td>
   </tr>";

$i++;
}
echo "<tr><td colspan=5><hr></td></tr>";
echo "<tr><td></td><td align=right>Total hours:</td><td align=center>$resulthours</td><td></td></tr>";
echo "<table>";

?>
</code>

Quote from: Mike Solstice on April 14, 2011, 12:24:45 AM

Ok, that works if I run it CLI or though phpMyAdmin, but won't if I try it in php

Code: [Select]
$remcomma = "UPDATE top_train SET deaths = replace( replace(field_name, ',', ''), '"', '' )";
mysql_query($remcomma);

I assume because of the quotes used in the regex. I tried escaping the "

Code: [Select]
$remcomma = "UPDATE top_train SET deaths = replace( replace(field_name, ',', ''), '\"', '' )";
mysql_query($remcomma);

Which broke it altogether. Anyone have any ideas?

Thanks!



Moved here since that thread was marked as solved & it's more of a PHP issue at this point anyway. Any & all help is greatly appreciated!

This should be really simple but I can't get my head round it.

Please see the PHP/HTML below.


<?php
$a = array(

'test' =>

"'data'"
);
$json = json_encode($a);
?>

<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="utf-8">
<title>Unknown Page</title>
<script type="text/javascript" src="http://ajax.microsoft.com/ajax/jquery/jquery-1.5.min.js"></script>
<script type="text/javascript">
var j = jQuery.parseJSON('<?php echo $json; ?>');
</script>
</head>
<body>
</body>
</html>


You will notice that data is stored by " then '
I have tried how it is and also with add slashes


$a = array(

'test' =>

addslashes("'data'")
);

It either outputs without slashes (which is clearly wrong)
Code: [Select]
var j = jQuery.parseJSON('{"test":"'data'"}');Or which I cant work out why dosent work
Code: [Select]
var j = jQuery.parseJSON('{"test":"\\'data\\'"}');
Now firebog throws the following error
Code: [Select]
missing ) after argument list
How should I be escaping this variable?