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PHP - Could Anyone Check This Code

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Could Anyone Check This Code	View Content

basically this is a search function

<form method="post" action="test1.php">
<input type = "hidden" name="submitted" value ="true" />
<label>TYPE:
<select name="field">
<option value = "sid">StudentID</option>
<option value = "sname">StudentName</option>
</select>
</label>
<label>WORD:
<input type="text" name="searchword" />
</label>
<input type="submit" />
</form>

-------------
<?php
if (isset($_POST['submitted'])){

$con = mysql_connect("localhost","root","");

mysql_select_db("uni", $con);

$field= $_POST['field'];
$searchword = $_POST['searchword'];
$query = "SELECT* FROM student WHERE $field = '$searchword'";
$result = mysqli_query($con,$query) or die ('error data'); //-----------> error line

echo"<table>";
echo "<tr><th>StudentID</th><th>StudentName</th></tr>";
while($row = mysqli_fetch_array($result)){

echo "<tr><td>";
echo "$row ['sid']";
echo "</td><td>";
echo "$row ['sname']";
echo "</td></tr>";
}

echo"</table>";

}

mysql_close($con);

?>

NB: the error message "Warning: mysqli_query() expects parameter 1 to be mysqli, resource given in C:\wamp\www\test1.php on line 21
error data"

Full Excel VBA Course - Beginner to Expert

Need Help In Where To Insert Username Check Code Into Current Form Code

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Hi, I need to insert some code into my current form code which will check to see if a username exist and if so will display an echo message. If it does not exist will post the form (assuming everything else is filled in correctly). I have tried some code in a few places but it doesn't work correctly as I get the username message exist no matter what. I think I am inserting the code into the wrong area, so need assistance as to how to incorporate the username check code.

$sql="select * from Profile where username = '$username';
$result = mysql_query( $sql, $conn )
      or die( "ERR: SQL 1" );
if(mysql_num_rows($result)!=0)
{
process form
}
else
{
echo "That username already exist!";
}

the current code of the form

<?PHP
//session_start();
require_once "formvalidator.php";
$show_form=true;

if (!isset($_POST['Submit'])) {

$human_number1 = rand(1, 12);

$human_number2 = rand(1, 38);

$human_answer = $human_number1 + $human_number2;

$_SESSION['check_answer'] = $human_answer;
}

if(isset($_POST['Submit']))
{

if (!isset($_SESSION['check_answer'])) {
echo "<p>Error: Answer session not set</p>";
}

if($_POST['math'] != $_SESSION['check_answer']) {
echo "<p>You did not pass the human check.</p>";
exit();
}

   $validator = new FormValidator();
    $validator->addValidation("FirstName","req","Please fill in FirstName");

$validator->addValidation("LastName","req","Please fill in LastName");
$validator->addValidation("UserName","req","Please fill in UserName");
$validator->addValidation("Password","req","Please fill in a Password");
$validator->addValidation("Password2","req","Please re-enter your password");
$validator->addValidation("Password2","eqelmnt=Password","Your passwords do not match!");
$validator->addValidation("email","email","The input for Email should be a valid email value");
$validator->addValidation("email","req","Please fill in Email");
$validator->addValidation("Zip","req","Please fill in your Zip Code");
$validator->addValidation("Security","req","Please fill in your Security Question");
$validator->addValidation("Security2","req","Please fill in your Security Answer");
    if($validator->ValidateForm())
    {
        $con = mysql_connect("localhost","uname","pw") or die('Could not connect: ' . mysql_error());
        mysql_select_db("beatthis_beatthis") or die(mysql_error());
$FirstName=mysql_real_escape_string($_POST['FirstName']); //This value has to be the same as in the HTML form file
$LastName=mysql_real_escape_string($_POST['LastName']); //This value has to be the same as in the HTML form file
$UserName=mysql_real_escape_string($_POST['UserName']); //This value has to be the same as in the HTML form file
$Password= md5($_POST['Password']); //This value has to be the same as in the HTML form file
$Password2= md5($_POST['Password2']); //This value has to be the same as in the HTML form file
$email=mysql_real_escape_string($_POST['email']); //This value has to be the same as in the HTML form file
$Zip=mysql_real_escape_string($_POST['Zip']); //This value has to be the same as in the HTML form file
$Birthday=mysql_real_escape_string($_POST['Birthday']); //This value has to be the same as in the HTML form file
$Security=mysql_real_escape_string($_POST['Security']); //This value has to be the same as in the HTML form file
$Security2=mysql_real_escape_string($_POST['Security2']); //This value has to be the same as in the HTML form file

$sql="INSERT INTO Profile (`FirstName`,`LastName`,`Username`,`Password`,`Password2`,`email`,`Zip`,`Birthday`,`Security`,`Security2`) VALUES ('$FirstName','$LastName','$UserName','$Password','$Password2','$email','$Zip','$Birthday','$Security','$Security2')";
//echo $sql;
if (!mysql_query($sql,$con)) {

die('Error: ' . mysql_error());

} else{

mail('email@gmail.com','A profile has been submitted!',$FirstName.' has submitted their profile',$body);

echo "<h3>Your profile information has been submitted successfully.</h3>";
}

mysql_close($con);
        $show_form=false;
    }
    else
    {
        echo "<h3 class='ErrorTitle'>Validation Errors:</h3>";

        $error_hash = $validator->GetErrors();
        foreach($error_hash as $inpname => $inp_err)
        {
            echo "<p class='errors'>$inpname : $inp_err</p>\n";
        }
    }
}

if(true == $show_form)
{
?>

Check My Code

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I am new to PHP.

I developed this class, I wonder if there's anything wrong or that I can improve. I could not test it because I'm in school.

Thanks in advance.

Code: [Select]
<?

class user {

var $userID,

$schoolID,

$userName,

$userPass,

$dbHost,

$dbUser,

$dbName,

$dbPass,

$dbUserTable;

$dbSchoolTable;

function dbInfo() {

$this->dbHost = 'localhost';

$this->dbUser = '';

$this->dbName = '';

$this->dbPass = '';

$this->dbUserTable = '';

$this->dbSchoolTable = '';

}

function registerUser($userName, $userPass) {

$dbLink = mysql_connect($this->dbHost, $this->dbUser, $this->dbPass);

if(!$dbLink) die("Could not connect to database: " . mysql_error());

mysql_select_db($this->dbName);

$query = "INSERT INTO $this->dbUserTable VALUES (NULL, \"$userName\", \"$userPass\")";

$result = mysql_query($query);

if(!$result) {
echo "Fail.";
} else {
$this->userID = mysql_insert_id();
}

mysql_close($dbLink);

$this->userName = $userName;

$this->userPass = $userPass;

}

function registerSchool($schoolName) {

$dbLink = mysql_connect($this->dbHost, $this->dbUser, $this->dbPass);

if(!$dbLink) die("Could not connect to database: " . mysql_error());

mysql_select_db($this->dbName);

$query = "INSERT INTO $this->dbSchoolTable VALUES (NULL, \"$schoolName\")";

$result = mysql_query($query);

if(!$result) {
echo "Fail.";
} else {
$this->schoolID = mysql_insert_id();
}

mysql_close($dbLink);

$this->schoolName = $schoolName;

}

function userLogin() {

$dbLink = mysql_connect($this->dbHost, $this->dbUser, $this->dbPass);

if(!$dbLink) die("Could not connect to database: " . mysql_error());

mysql_select_db($this->dbName);

$query = "SELECT * FROM $this->dbUserTable WHERE userName = \"$this->userName\" AND userPass = \"$this->userPass\" LIMIT 1";

$result = mysql_query($query);

if(!$result) {
echo "Fail.";
} else {
while($row = mysql_fetch_array($result)) {
session_start();
$_SESSION['userID'] = $row['userID'];
session_write_close();
}
}

mysql_close($dbLink);

}

function changePass($newPass) {

$dbLink = mysql_connect($this->dbHost, $this->dbUser, $this->dbPass);

if(!$dbLink) die("Could not connect to database: " . mysql_error());

mysql_select_db($this->dbName);

$query = "SELECT * FROM $this->dbUserTable WHERE userName = \"$this->userName\" LIMIT 1";

$result = mysql_query($query);

if(!$result) {
echo "Fail.";
} else {

$query = "UPDATE $this->dbUserTable SET userPass = \"$newPass\" WHERE userName = \"$this->userName\"";

$result = mysql_query($query);

if(!$result) {
echo "Fail";
} else {
$this->userPass = $newPass;
}
}

mysql_close($dbLink);

}

}

?>

Code Check

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Anyone Check This Code Plss!

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try
   {
$sql   = "SELECT StudentID,CourseID FROM student,course WHERE StudentID =" . $_POST['sid']  AND CourseID =".$_POST['cid'] ; //-----> error line

    $query = mysql_query($sql) or trigger_error('MySQL error: ' . mysql_error());

    if (mysql_num_rows($query) > 0)
    {
        throw new Exception('StudentID already taken');
    }
}

NB: basicaly im inserting data into a table from another two table field.

How To Check For Malicious Php Code

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Can someone advise me how to check for malicious PHP code?

If I download a script from somewhere, how can I make sure it's not malicious?
If bad, maybe it could delete files?? Or send spam?
Or EVEN 'send home' code - so that they can track your usage - OK if I consent - not OK if haven't consented and they're doing it sneakily!

Sending spam has been a problem when installing Joomla plugins

Are there specific commands I should watch out for in PHP scripts?
Like send mail or something?

I'm sure the baddies would be clever and maybe use IP numbers to send out to instead of domain names?

Is there a PHP code checker online? Something that tells you what your PHP script does? Simple things: like tell you if it sends out mail or makes contact outside or deletes files

This would be great - it would save a lot of time going through hundreds/thousands of lines of code

Thanks

OM

Will This Code Check If Value Is Null

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will this code check if value is null

Code: [Select]
if($_SESSION["cart"] != null)

Can Some Please Check My Code If What Is Wrong

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can someone check if what the problem with my code
Code: [Select]
$avatar2 = mysql_query("SELECT `users`.`imagelocation' FROM `users` `forum_replies` WHERE `users`.`id`= `forum_replies`.`uid`")or die(mysql_error());

Please Check N Suggest My Update Code

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how to update the record of one table in which condition is that the it should similar to the other table feild only. e.g field of table1 will update only when the feild1 of table1 is equal to field2 of table2 in php??
while im using following command

mysql_select_db("db1",$con);
$query = "SELECT table2.feild1 , table2.feild1 " .
"FROM table2, table1 " .
"WHERE table1.feild2 = table2.feild1 ";

$data = mysql_query($query)
or die(mysql_error());

$sql="UPDATE table2 SET feild2='$_POST[value2]', feild3='$_POST[value3]' WHERE table1.feild2 = $data ";

Getting Error In This Useravailability Check Code

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I am writing a code using jquery in a php page to check the username availabiltiy,but getting error ie every time username is available is the message i am getting.

the code is

$(document).ready(function()
{
   $("#username").blur(function()
   {
      //remove all the class add the messagebox classes and start fading
      $("#msgbox").removeClass().addClass('messagebox').text('Checking...').fadeIn("slow");
      //check the username exists or not from ajax
      //$.post("themes/user_availability.php",{ username:$(this).val() } ,function(data)
$.post("themes/user_availability.php",{username:$(this).val() } ,function(data)
       {
        if(data=="no") //if username not avaiable
        {
       $("#msgbox").fadeTo(200,0.1,function() //start fading the messagebox
         {
           //add message and change the class of the box and start fading
           $(this).html('This User name Already exists').addClass('messageboxerror').fadeTo(900,1);
         });
}
        if(data=="yes")
        {
            $("#msgbox").fadeTo(200,0.1,function() //start fading the messagebox
         {
           //add message and change the class of the box and start fading
           $(this).html('Username available to register').addClass('messageboxok').fadeTo(900,1);
         });

        }

});

   });
});

php file user_availability.php
<?php
$login=$_POST['username'];
$sql="select username from web_payregister where username='$login'";
$result=mysql_query($sql);
if(mysql_num_rows($result)>0){

echo "no";
}else{
echo "yes";
}

?>

Mistake In Code To Check For Animated Gif?

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I wish to use the code from the following page that can be used to check if an uploaded image is an animated GIF:
http://stackoverflow.com/questions/280658/can-i-detect-animated-gifs-using-php-and-gd

Here is the function:
function is_ani($filename) {
    if(!($fh = @fopen($filename, 'rb')))
        return false;
    $count = 0;
    //an animated gif contains multiple "frames", with each frame having a
    //header made up of:
    // * a static 4-byte sequence (\x00\x21\xF9\x04)
    // * 4 variable bytes
    // * a static 2-byte sequence (\x00\x2C)

    // We read through the file til we reach the end of the file, or we've found
    // at least 2 frame headers
    while(!feof($fh) && $count < 2)
        $chunk = fread($fh, 1024 * 100); //read 100kb at a time
        $count += preg_match_all('#\x00\x21\xF9\x04.{4}\x00\x2C#s', $chunk, $matches);

    fclose($fh);
    return $count > 1;
}

Am I right in saying that there are curly brackets missing after the while line? The indenting indicates that both of the 2 following lines should be included in the while loop, but the lack of curly brackets mean that only the line beginning with $chunk is included in the loop.

The code actually seems to work with and without the curly brackets. Does anyone understand this code well enough to know whether or not the curly brackets should be included?

Thanks in advance.

Please Check Form Code - Something Is Screwed Up (probably Me!)

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This is what I have for the form (in short version) along with the text area and submit button.
The form shows up OK on the Internet http://www.lakegenevapieco.com/test_product_list.php

The problem is when I fill it out & submit it doesn't do two things:
1) It doesn't E-Mail me the information
2) It doesn't say, Thank you for using our mail form. It actually says page not available.

Here is the code:
<html>

<head>
<meta http-equiv="Content-Language" content="en-us">
<title>Products to be listed on the web site for the month of</title>
</head>

<body>
  Products to be listed on the web site for the month of 
  <select size="1" name="MONTH">
  <option selected>PICK MONTH</option>
  <option>1-JANUARY</option>
  <option>2-FEBUARY</option>
  <option>3-MARCH</option>
  <option>4-APRIL</option>
  <option>5-MAY</option>
  <option>6-JUNE</option>
  <option>7-JULY</option>
  <option>8-AUGUST</option>
  <option>9-SEPTEMBER</option>
  <option>10-OCTOBER</option>
  <option>11-NOVEMBER</option>
  <option>12-DECEMBER</option>
  </select> <select size="1" name="YEAR">
  <option selected>PICK YEAR</option>
  <option>2010</option>
  <option>2011</option>
  <option>2012</option>
  <option>2013</option>
  <option>2014</option>
  <option>2015</option>
  </select></p>
  <p><input type="checkbox" name="PumpkinSB" value="ON"> Pumpkin  
  Price increase to
  <input type="text" name="PriceIncreaseTo151" size="20" value="$"></p>
  <p><input type="checkbox" name="PumpkinWalnutSB" value="ON"> Pumpkin Walnut  
  Price increase to
  <input type="text" name="PriceIncreaseTo152" size="20" value="$"></p>
  <p><input type="checkbox" name="RaspberrySB" value="ON"> Raspberry  
  Price increase to
  <input type="text" name="PriceIncreaseTo153" size="20" value="$"></p>
  <p> </p>
  <p> </p>
  <p>
<?php
function spamcheck($field)
  {
  //filter_var() sanitizes the e-mail
  //address using FILTER_SANITIZE_EMAIL
  $field=filter_var($field, FILTER_SANITIZE_EMAIL);

  //filter_var() validates the e-mail
  //address using FILTER_VALIDATE_EMAIL
  if(filter_var($field, FILTER_VALIDATE_EMAIL))
    {
    return TRUE;
    }
  else
    {
    return FALSE;
    }
  }

if (isset($_REQUEST['email']))
  {//if "email" is filled out, proceed

  //check if the email address is invalid
  $mailcheck = spamcheck($_REQUEST['email']);
  if ($mailcheck==FALSE)
    {
    echo "Invalid input";
    }
  else
    {//send email
    $email = $_REQUEST['email'] ;
    $subject = $_REQUEST['subject'] ;
    $message = $_REQUEST['message'] ;
    mail("myemail@mia.net", "Subject: $subject",
    $message, "From: $email" );
    echo "Thank you for using our mail form";
    }
  }
else
  {//if "email" is not filled out, display the form
  echo "<form method='post' action='mailform.php'>
  Email: <input name='email' type='text' /><br />
  Subject: <input name='subject' type='text' /><br />
  Message:<br />
  <textarea name='message' rows='15' cols='40'>
  </textarea><br />
  <input type='submit' />
  </form>";
  }
?>

</p>
</form>

</body>

</html>

Error Code On Login-check

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When I log in on my web-site it takes me to a php login-check page

This is the error code that I am getting;

Quote

Warning: mysql_num_rows() expects parameter 1 to be resource, boolean given in D:\xampp\htdocs\login-check.php on line 26

This is the php code that i am using;

Code: [Select]
<?php
$host="localhost"; // Host name
$username="root"; // Mysql username
$password=""; // Mysql password
$db_name="deliverpizza"; // Database name
$tbl_name="customer, admin, staff"; // Table name

// Connect to server and select databse.
mysql_connect("$host", "$username", "$password")or die("cannot connect");
mysql_select_db("$db_name")or die("cannot select DB");

// username and password sent from form
$myusername=$_POST['myusername'];
$mypassword=$_POST['mypassword'];

// To protect MySQL injection (more detail about MySQL injection)
$myusername = stripslashes($myusername);
$mypassword = stripslashes($mypassword);
$myusername = mysql_real_escape_string($myusername);
$mypassword = mysql_real_escape_string($mypassword);

$sql="SELECT * FROM $tbl_name WHERE username='$myusername' and password='$mypassword'";
$result=mysql_query($sql);

// Mysql_num_row is counting table row
$count=mysql_num_rows($result);
// If result matched $myusername and $mypassword, table row must be 1 row

if($count==1){
// Register $myusername, $mypassword and redirect to file "login_success.php"
session_register("myusername");
session_register("mypassword");
header("location:login_privelage.php");
}
else {

}
?>

Moved: Spell Check My Php Code

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This topic has been moved to Miscellaneous.

http://www.phpfreaks.com/forums/index.php?topic=306339.0

Please Help Me Check This Code If It Safe From Hackers Or Spammers

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Good day friends, please i am still an upcoming developer please could you help me check if this contact form code is secured from hackers. Thanks

<?php
require "define.php";
$seotitlemeta = "Contact $sitename";
include './themes/header.php';
function filter_spam(&$string){ $url = str_replace(array("'", '', '%20'), ' ', $string); $url = preg_replace('~[\pL0-9]+u', ' ', $url); $url= strtolower($url); $url = trim($url, ""); return $url;}
function test_input($data) {
$data = trim($data);
$data = stripslashes($data);
$data = htmlspecialchars($data);
$data = strip_tags($data);
return $data; } ?>
<h1 title="Contact <?php echo $sitename;?>">Contact <?php echo $sitename;?></h1>
<?php
if ($SERVER["REQUEST_METHOD"] == "POST") {
$code1= trim(preg_replace(array("'", "[^a-z0-9]+"), array("", ""), strtolower(test_input($POST['code']))), "-");
$code1 = substr($code1, 0, 10);
$code= trim(preg_replace(array("'", "[^0-9]+"), array("", ""), strtolower(bin2hex(test_input($POST['code1'])))), "-");
$code = substr($code, 0, 10);
if (filter_var(test_input($POST['mail']), FILTER_VALIDATE_EMAIL)) {
if(strlen(test_input($POST["message"])) > 5){
$email_sumbit = test_input($POST['mail']);
$contact_name = test_input(filter_spam($POST['name']));
$subject_submit = test_input($POST['head']);
$message_submit= test_input($POST["message"]);
if($code1!== $code)
{ } else {
$from = "$email_sumbit";
$to_email = "mail@example.com";
$subject = $subject_submit;
$message = $message_submit;
$headers = "From: $contact_name $from";
mail($to_email,$subject,$message,$headers);
$sent_show_response = '<div class="contact-done">Your message has been sent successfully</div>';
$message_sent_remove_form = "1";
}
}}
if ($SERVER["REQUEST_METHOD"] == "POST") {
if($sent_show_response){
$sent_show_response = $sent_show_response; } else {
if(strlen(test_input($POST["message"])) < 5){
$sent_show_response = '<div class="contact-fail">Your message is too short</div>'; } else{
$sent_show_response = '<div class="contact-fail">Please provide valid information</div><br>';
}}}}
?><p><?php echo $sent_show_response; ?></p><?php if ($message_sent_remove_form == '1'){ } else{ ?><?php $Random_code=mt_rand(); $Random_code = substr($Random_code, 0, 5); $Random_codehex = substr(bin2hex($Random_code), 0, 10); ?><div class="contact"><form method="post" action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]);?>"><label> Full name: <input type="text" name="name" placeholder="Enter your full name" value="<?php echo $contact_name;?>" class="" required></label><label> E-mail address: <input type="email" name="mail" placeholder="Enter your valid e-mail address" value="<?php echo $email_sumbit;?>" class="" required></label><label> Subject: <input type="text" name="head" placeholder="Enter subject of your message" value="<?php echo $subject_submit;?>" class="" required></label><label> Message: <textarea name="message" placeholder="Write your complete message here..." class="" required><?php echo $message_submit;?></textarea></label><label> Human verification: <input type="text" name="code1" autocomplete="off" spellcheck="false" placeholder="Enter text shown on below image" class="captcha-in " required /><input type="hidden" name="code" value="<?php echo $Random_codehex; ?>" /></label><div class="captcha"><div class="image"><h3><b><?php $random_spilit = str_split($Random_code);foreach($random_spilit as $code_one_one){ echo "$code_one_one "; }?></b></h3><span class="overlay"></span></div><div class="reload"><font color="white" style="font-weight: bold;">CODE</font></div></div><button type="submit" name="submit"><span class="fas fa-paper-plane"></span> Send Message </button></form></div><?php }?></div></div><?php include './themes/footer.php'; ?>

I Want A Code In Php To Check If User Open This Page

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i want a code in php to check if user open this page

Not Able To Login - Help Me Disable Admin Check In The Code Below

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<?php
session_start( );
include_once( dirname( __FILE__ )."/../inc/func/get_sth.php" );
include_once( _ABSPATH_."/inc/func/header.php" );
if ( $_GET["f"] == "login" )
{
$adminuser = strtolower( strip_tags( trim( $_POST["adminuser"] ) ) );
$r_0 = strtolower( strip_tags( trim( $_SESSION["r"] ) ) );
$r_1 = strtolower( strip_tags( trim( $_POST["r"] ) ) );
if ( $r_0 == $r_1 )
{
$result = mysql_query( "SELECT password FROM admin where adminuser='".$adminuser."'" );
$val = mysql_fetch_array( $result );
if ( !$val["password"] )
{
$loginfail = 1;
}
else
{
if ( $val[password] === md5( $_POST["password"] ) )
{
$_SESSION['admin'] = $adminuser;
header( "Location: ./" );
exit( );
}
$loginfail = 1;
}
}
else
{
$loginfail = 2;
}
}
$page_title = l( "Administration Login" )." | ".get_sitename( );
$smarty->assign( "page_title", $page_title );
$smarty->assign( "loginfail", $loginfail );
$smarty->display( "mgt/login.tpl" );
?>

Altering Regex Code To Check For Image Instead Of Just Checking For Url

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I found the code below which checks to make sure something the user entered into a text field is an actual URL. I am looking to confirm that something a user enters is an actual link to an IMAGE, so does anyone know how I could adjust this code below to do that?

Basically, this code below would accept http://monkeys.com AND http://monkeys.com/images/monkey.jpg.

I want to alter the code so that http://monkeys.com would NOT be accepted since it's not an image. Essentially, I want to make sure whatever the user enters ends with .jpg, .gif or .png.

Anyone know how to do this?

Code: [Select]
url": {
"regex": /^(https?|ftp):\/\/(((([a-z]|\d|-|\.|_|~|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])|(%[\da-f]{2})|[!\$&'\*\+,;=]|:)*@)?(((\d|[1-9]\d|1\d\d|2[0-4]\d|25[0-5])\.(\d|[1-9]\d|1\d\d|2[0-4]\d|25[0-5])\.(\d|[1-9]\d|1\d\d|2[0-4]\d|25[0-5])\.(\d|[1-9]\d|1\d\d|2[0-4]\d|25[0-5]))|((([a-z]|\d|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])|(([a-z]|\d|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])([a-z]|\d|-|\.|_|~|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])*([a-z]|\d|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])))\.)+(([a-z]|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])|(([a-z]|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])([a-z]|\d|-|\.|_|~|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])*([a-z]|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])))\.?)(:\d*)?)(\/((([a-z]|\d|-|\.|_|~|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])|(%[\da-f]{2})|[!\$&'\*\+,;=]|:|@)+(\/(([a-z]|\d|-|\.|_|~|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])|(%[\da-f]{2})|[!\$&'\*\+,;=]|:|@)*)*)?)?(\?((([a-z]|\d|-|\.|_|~|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])|(%[\da-f]{2})|[!\$&'\*\+,;=]|:|@)|[\uE000-\uF8FF]|\/|\?)*)?(\#((([a-z]|\d|-|\.|_|~|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])|(%[\da-f]{2})|[!\$&'\*\+,;=]|:|@)|\/|\?)*)?$/,
"alertText": "* Invalid URL"
}

Code To Check Form Field Does Not Exceed 100 Characters

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Hi Guys

What code would you use to check that a form field does not exceed 100 characters?

Thanks for any help.

Php Code To Change Automatically Checked Check Boxes

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I am new to PHP and learning as I go I am stuck with a piece of code that I am trying to change. I have a php application that has tickboxes in and some are checked as standard. I want to change the tick box setting to be unchecked as standard. Here is the code. <label><input type="checkbox" name="notify" value="1" <?php echo (!isset($_SESSION['as_notify']) || !empty($_SESSION['as_notify'])) ? 'checked="checked"' : ''; ?> /> <?php echo $hesklang['seno']; ?></label><br /> I have tried everything I know but since I do not know that much I have been unable to change the standard. I am sure it is something small that I am overlooking. Anyone out there know what I am doing wrong?

Curl - Check Db On Remote Server For Authentication? (code Included)

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Hey All,

I will be marketing a simple php script shortly and would like to Obfuscate my code and have it check to see if the person is running the script on the proper domain, much like other Purchased Scripts, you have to buy licenses and some are limited to a Per Domain basis.

Could I use cURL to run a script on another server (mine) that takes the URL it came from, and a variable "the auth key" and check if the person is using the script on the proper domain? If the domain and auth key don't match in the DB i would return a message saying invalid key or something, else continue to execute the script.

<?php
//authkey would be defined in config file
$authkey = "769870afhljkzxf90436";

$curl_handle=curl_init();
curl_setopt($curl_handle,CURLOPT_URL,"http://example.com/page.php?authkey=$authkey");
curl_setopt($curl_handle,CURLOPT_CONNECTTIMEOUT,2);
curl_setopt($curl_handle,CURLOPT_RETURNTRANSFER,1);
$buffer = curl_exec($curl_handle);
curl_close($curl_handle);

if (empty($buffer))
{
print "Sorry, AuthServ is performing maintenance.....<p>";
}
else
{
print $buffer;
}
?>

Is there a smarter way to do this? I don't have an extra 300 bucks to use something like ioncube, just looking for a general proper direction on going about this as I am totally clueless.

thanks