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PHP - Php Variable In Html Table
<?php function money($amount,$separator=true,$simple=false){ return (true===$separator? (false===$simple? number_format($amount,2,'.',','): str_replace('.00','',money($amount)) ): (false===$simple? number_format($amount,2,'.',''): str_replace('.00','',money($amount,false)) ) ); } $income = 5000000000; $daily = money($income*24,true,true); $weekly = money(($income*24)*7,true,true); $monthly = money((($income*24)*7)*30,true,true); ?> </center> <center> <table border="1"> <tr> <td>Daily</td> <td><?php echo $daily ?></td> </tr> <tr> <td>Weekly</td> <td><?php echo $weekly ?></td> </tr> <tr> <td>Monthly</td> <td><?php echo $monthly ?></td> </tr> </table> </form> </center> What am I doing wrong? Im fairly new to this Similar TutorialsI have a form that users input user name, password, and email... all writes to csv fine. My problem is I need to concatenate a a string with a variable and some html code will preserving the html when written to the csv.. I need the csv to be this username,password,email,user,category,text with http://sub.domain..com/splash/,something,something here's what i have Code: [Select] <?php if($_POST['formSubmit'] == "Submit") $varUserName = $_POST['username']; $varPW = $_POST['PW']; $varEmail = $_POST['email']; { $fs = fopen("testcsv.csv","a"); fputcsv($fs, array($varUserName,$varPW,$varEmail,"user","title",",category","some text '<a href="http://$varUserName.url.com/splash/>site.com</a>',)); fclose($fs); exit; } ?> and of course I'm getting Parse error: syntax error, unexpected T_STRING, expecting ')' on line 9 Hello, I need some help. Say that I have a list in my MySQL database that contains elements "A", "S", "C", "D" etc... Now, I want to generate an html table where these elements should be distributed in a random and unique way while leaving some entries of the table empty, see the picture below. But, I have no clue how to do this... Any hints? Thanks in advance, Vero Hey, I have a mysql table for my setups, it contains basically three fields: 'id','variable','value'. i want to create/name a variable from a result from the database and then from another field it should give the newly created variable its value The table is already filled with the variables i want to use, now i just want my index page to get the different variable out of the table with the value as its value. Is that even possible? so lets say i have a variable in my table called 'header_color' the value in that table row is 'FFF' i want my index to get all variable from the database (through a while??) with again its value as a value. This is my thought: $sql = mysql_query("SELECT * FROM setup"); while ($res = mysql_fetch_array($sql)){ $res[variable]; = $??my_variable??; $myvariable = $res[value]; } and so when i have my div for my header i want it to be <div style="background-color:#<?=$header_color?>"> resulting in <div style="background-color:#FFF> in my table under variable it has the name "header_color" and under value "FFF" maybe i need to create an array or something i have no idea. Hope you guys can help me. Hi, I'm trying to drop a table form a database using the table name as a variable. This variable is set within a session. I am using a form where you input the table name, then the DROP TABLE procedure is executed in the next page. I know that the variable gets passed because it prints the table name variable out when I "echo". The execution is simple (code found in deletetable.php) $temp = $_POST['temp']; $query = "DROP TABLE $temp"; if(mysql_query($query)){ echo "<h1 style='color:green;'>Table $temp deleted</h1>";} else{ echo "<h1 style='color:red;'>Deletion of table '$temp' failed!</h1>";} Here's my code for the two pages: delete_table.php <?php include("includes/header.html"); session_start(); $hostname = $_SESSION['hostname']; $user = $_SESSION['user']; $passwd = $_SESSION['passwd']; $database = $_SESSION['database']; $tblname = $_SESSION['table']; $conn = mysql_connect($hostname, $user, $passwd, $database); /*if(! $conn ) { die('Could not connect: ' . mysql_error()); }*/ ?> <div id="container"> <div id="header">Create DB</div> <div id="breadcrumbs"> <?php function check_port($port) { $conn = @fsockopen("127.0.0.1", $port, $errno, $errstr, 0.2); if ($conn) { fclose($conn); return true; } } function server_report() { $report = array(); $svcs = array('3306'=>'MySQL'); foreach ($svcs as $port=>$service) { $report[$service] = check_port($port); } return $report; } $report = server_report(); ?> <div id="server"><p>Server is <?php echo $report['MySQL'] ? "running" : "offline"; ?></p></div> <?php if(!$_SESSION['hostname']){ echo "<font color='red'>Not connected to server!</font>"; } else { echo "<font color='green'>Server: ".$_SESSION['hostname']."</font>"; } if(!$_SESSION['database']){ echo ""; }else{ echo "<br><font color='green'>Database: ".$_SESSION['database']."</font>"; } ?> </div> <div id="nav"> <p><a href="#" onclick="javascript:window.open('connect_db.php','_self');"><img src="server_conn_ico.png" align="left" />Server Connection</a></p> <p><a href="databases.php"><img src="databases_ico.png" align="left" />View Database</a></p> <p><a href="create_db.php"><img src="server_folder_ico.png" align="left" />Create Database</a></p> <p><a href="drop_db.php"><img src="drop_ico.png" align="left" />Drop Database</a></p> <p><a href="create_table.php"><img src="status_ico.png" align="left" />Add Table</a></p> <p><a href="add_fields.php"><img src="server_ico.png" align="left" />Add Fields</a></p> <p class="active"><a href="delete_table.php"><img src="status_delete_ico.png" align="left" />Delete Table</a></p> <p><a href="view_tables.php"><img src="user_admin_ico.png" align="left" />View Tables</a></p> <p><a href="view_data.php"><img src="user_admin_ico.png" align="left" />View Table Data</a></p> <p><a href="http://localhost/phpmyadmin/" target="_blank"><img src="phpmyadmin_ico.png" align="left" />phpMyAdmin</a></p> <p><a href="connect_info.php"><img src="health_ico.png" align="left" />System Info</a></p> <p><a href="error_log.php"><img src="logs_ico.png" align="left" />Server Log</a></p> <p><a href="bug_report.php"><img src="bugs-icon.png" align="left" />Bug Reports</a></p> </div> <div id="controls"><a href="javascript:self.close()"><img src="controls.png" /></a></div> <div id="main"> <div id="content"> <!--<h1>Delete Database Table</h1>--> <?php if(empty($database)) { echo "<p>You must be connected to a database in order to delete a table.</p>"; }else{ //echo 'Connected successfully to \''.$database.'\''; // Check tables $sql = "SHOW TABLES FROM $database"; $result = mysql_query($sql); if (mysql_num_rows($result) > 0) { echo "<p style='text-align:left;padding-left:24px;'>Available tables:</p>\n"; echo "<pre style='text-align:left;padding-left:24px;font-size:1.2em;'>\n"; while ($row = mysql_fetch_row($result)) { echo "{$row[0]}\n"; } echo "</pre>\n"; } ?> <form action="deletetable.php" method="post"> Enter table you'd like to delete from '<?php echo $database; ?>' database: <input name="temp" type="text" /><br/> <input name="Submit" type="submit" value=" Delete Table " /> <input type='button' value=' Cancel ' onclick="javascript:window.location='connect_db.php';"></p> </form> <?php } include("includes/footer.html"); ?> Executing file deletetable.php: <?php include("includes/header.html"); session_start(); $hostname = $_SESSION['hostname']; $user = $_SESSION['user']; $passwd = $_SESSION['passwd']; $database = $_SESSION['database']; //$tblname = $_SESSION['table']; $conn = mysql_connect($hostname, $user, $passwd, $database); ?> <div id="container"> <div id="header">Create DB</div> <div id="breadcrumbs"> <?php function check_port($port) { $conn = @fsockopen("127.0.0.1", $port, $errno, $errstr, 0.2); if ($conn) { fclose($conn); return true; } } function server_report() { $report = array(); $svcs = array('3306'=>'MySQL'); foreach ($svcs as $port=>$service) { $report[$service] = check_port($port); } return $report; } $report = server_report(); ?> <div id="server"><p>Server is <?php echo $report['MySQL'] ? "running" : "offline"; ?></p></div> <?php if(!$_SESSION['hostname']){ echo "<font color='red'>Not connected to server!</font>"; } else { echo "<font color='green'>Server: ".$_SESSION['hostname']."</font>"; } if(!$_SESSION['database']){ echo ""; }else{ echo "<br><font color='green'>Database: ".$_SESSION['database']."</font>"; } ?> </div> <div id="nav"> <p><a href="#" onclick="javascript:window.open('connect_db.php','_self');"><img src="server_conn_ico.png" align="left" />Server Connection</a></p> <p><a href="databases.php"><img src="databases_ico.png" align="left" />View Database</a></p> <p><a href="create_db.php"><img src="server_folder_ico.png" align="left" />Create Database</a></p> <p><a href="drop_db.php"><img src="drop_ico.png" align="left" />Drop Database</a></p> <p><a href="create_table.php"><img src="status_ico.png" align="left" />Add Table</a></p> <p><a href="add_fields.php"><img src="server_ico.png" align="left" />Add Fields</a></p> <p class="active"><a href="delete_table.php"><img src="status_delete_ico.png" align="left" />Delete Table</a></p> <p><a href="view_tables.php"><img src="user_admin_ico.png" align="left" />View Tables</a></p> <p><a href="view_data.php"><img src="user_admin_ico.png" align="left" />View Table Data</a></p> <p><a href="http://localhost/phpmyadmin/" target="_blank"><img src="phpmyadmin_ico.png" align="left" />phpMyAdmin</a></p> <p><a href="connect_info.php"><img src="health_ico.png" align="left" />System Info</a></p> <p><a href="error_log.php"><img src="logs_ico.png" align="left" />Server Log</a></p> <p><a href="bug_report.php"><img src="bugs-icon.png" align="left" />Bug Reports</a></p> </div> <div id="controls"><a href="javascript:self.close()"><img src="controls.png" /></a></div> <div id="main"> <div id="content"> <?php $temp = $_POST['temp']; $query = "DROP TABLE $temp"; if(mysql_query($query)){ echo "<h1 style='color:green;'>Table $temp deleted</h1>";} else{ echo "<h1 style='color:red;'>Deletion of table '$temp' failed!</h1>";} include("includes/footer.html"); ?> Your help is greatly appreciated!! I have a dropdown menu <td width="148" height="35" valign="top"><b>Type: </b> </td> <td><select name ="tabledrop"> <option value="goggles">goggles</option> <option value="headbands">headbands</option> <input type='hidden' id='tabledrop' name='tabledrop' value = ''/> </select> </td> those 2 options are actually names of my tables. I tried this and got some syntax error. $type = $_POST['tabledrop']; $item = $_POST['goggles_name']; $price = $_POST['goggles_price']; $file = $_FILES['goggles_image']['name']; $query = "INSERT into $type SET [$type]_name = '$item' , [$type]_price = '$price' , [$type]_image = '$file'"; Hi, i cant seem to get something working, should be simple but its not working for me. I just need to only display a table if a variable in my table = a certain value. The column in the table is called 'option1_available' and if its value is set to 'Y' i want it to display a table. Appreciate any help, Thanks Hello, I'm working on a PHP register form, all I want to do, is to be able to insert an extra variable into the database: Code: [Select] // now we insert it into the database $insert = " INSERT INTO users (username, password) VALUES ('".$_POST['username']."', '".$_POST['pass']."') "; $add_member = mysql_query($insert); right, so I have the username and password variable being passed. But I also want to pass a variable into a column called 'weaponAttachments', all I want for this variable to be is 5000. So, in other words, something like this: 5000['weaponAttachments'] Thanks I know I'm doing it something right, but can someone tell me why only one table is showing up? Can you help me fix the issue? Heres my code: function showcoords() { echo"J3st3r's CoordVision"; $result=dbquery("SELECT alliance, region, coordx, coordy FROM ".DB_COORDFUSION.""); dbarray($result); $fields_num = mysql_num_fields($result); echo "<table border='1'>"; // printing table headers echo "<td>Alliance</td>"; echo "<td>Region</td>"; echo "<td>Coord</td>"; // printing table rows while($row = mysql_fetch_array($result)) { // $row is array... foreach( .. ) puts every element // of $row to $cell variable foreach($row AS $Cell) echo "<tr>"; echo "<td>".$row['alliance']."</td>\n"; echo "<td>".$row['region']."</td>\n"; echo "<td>".$row['coordx'].",".$row['coordy']."</td>\n"; echo "</tr>\n"; } echo "</table>"; mysql_free_result($result); } I have 2 rows inserted into my coords table. Just frustrated and ignorant to php. Hello guys, I do not know if anyone work or have worked with the "elFinder (file manager)" .. I incorporate "elFinder" to my platform .. and have the following question .. Have its connector: Code: ------------------------------------- //za screen imeto function clean($string) { $string = str_replace(' ', '-', $string); // Replaces all spaces with hyphens. $string = preg_replace('/[^A-Za-z0-9\-]/', '', $string); // Removes special chars. return preg_replace('/-+/', '-', $string); // Replaces multiple hyphens with single one. } //end $srvname = mysql_real_escape_string(trim($_POST['servername'])); //ime na servera $port = (int)$_POST['ports']; //port na servera $ip = mysql_real_escape_string(trim($_POST['serverip'])); //serverip $screen = clean($srvname).$port.'_'.uniqid(); //screen imeto mysql_query("INSERT INTO server (screen) VALUES('$screen')") or die(mysql_error()); $opts = array( 'locale' => 'en_US.UTF-8', 'bind' => array( // '*' => 'logger', 'mkdir mkfile rename duplicate upload rm paste' => 'logger' ), 'debug' => true, 'roots' => array( array( 'driver' => 'LocalFileSystem', 'path' => ''.$screen.'', 'startPath' => ''.$screen.'', 'URL' => dirname($_SERVER['PHP_SELF']) . ''.$screen.'', // 'treeDeep' => 3, // 'alias' => 'File system', 'mimeDetect' => 'internal', 'tmbPath' => '.tmb', 'utf8fix' => true, 'tmbCrop' => false, 'tmbBgColor' => 'transparent', 'accessControl' => 'access', 'acceptedName' => '/^[^\.].*$/', // 'disabled' => array('extract', 'archive'), // 'tmbSize' => 128, 'attributes' => array( array( 'pattern' => '/\.js$/', 'read' => true, 'write' => false ), array( 'pattern' => '/^\/icons$/', 'read' => true, 'write' => false ) ) // 'uploadDeny' => array('application', 'text/xml') ), -------------------------------------- It doesn't work.. I need help for connect to the variable "$screen".. How can call the "table $screen" ? "table $screen": folders are automatically created by users Regards, Joob Hello, I am working on a project and I cant seem to get this to work. I have a database (Kingsbury) that stores a contact list. I am trying to make an page were a user can search the database by state. The code from the HTML site is: Code: [Select] <form action = "sqlllist.php" method="post"><br /> Please enter the state you would like to search: <input type="text" name="state" /><br /> <p><input type="submit" value="Enter" /></p> </form> And then from the .php file Code: [Select] <?php $DBConnect = mysql_connect("*****", "*****", "********"); if ($DBConnect===FALSE) echo "<p>Connection Failed!.</p>\n"; else { $State == $_POST['state']; $Result = mysql_select_db("Kingsbury", $DBConnect); $queryresult = @mysql_query("SELECT * FROM contacts WHERE State = $State'", $DBConnect); echo "<table width='100%' border='1'>\n"; echo "<tr><th>User ID</th> <th>First Name</th> <th>Last Name</th> <th>Address</th> <th>State</th> <th>City</th> <th>Zip Code</th> <th>Area Code</th> <th>Phone Number</th>\n"; While (($Row = mysql_fetch_row($queryresult)) !== FALSE) { echo "<tr><td>{$Row[0]}</td>"; echo "<td>{$Row[1]}</td>"; echo "<td>{$Row[2]}</td>"; echo "<td>{$Row[3]}</td>"; echo "<td>{$Row[4]}</td>"; echo "<td>{$Row[5]}</td>"; echo "<td>{$Row[6]}</td>"; echo "<td>{$Row[7]}</td>"; echo "<td>{$Row[8]}</td>"; } echo "</table>\n"; mysql_free_result($queryresult); mysql_close($DBConnect); } ?> This, to me seems like it should be working, but it outputs the entire database. Good evening,
I am working on a program that takes images, and casts them into an associated array, I then want to display thumbnails of those images into a 3 column by 4 row table...
[image][image][image]
[image][image][image]
[image][image][image]
[image][image][image]
(For my visual friends)
here is my current, pardon for the mess, but right now, functionality is more important.
<!DOCTYPE html>
<html>
<head>
<title>Zodiac Gallery</title>
</head>
<body>
<h2 style="text-align:center">Zodiac Gallery</h2>
<p>Click a thumbnail image to see enlarged view.</p>
<?php
$ZodiacArray = array (
"Images/rat.jpg" => "Rat",
"Images/ox.jpg" => "Ox",
"Images/tiger.jpg" => "Tiger",
"Images/rabbit.jpg" => "Rabbit",
"Images/dragon.jpg" => "Dragon",
"Images/snake.jpg" => "Snake",
"Images/horse.jpg" => "Horse",
"Images/goat.jpg" => "Goat",
"Images/monkey.jpg" => "Monkey",
"Images/rooster.jpg" => "Rooster",
"Images/dog.jpg" => "Dog",
"Images/pig.jpg" => "Pig");
foreach ($ZodiacArray as $image => $zodiac)
{
echo "<table>
<tr>
<td><img src="$image" alt="$zodiac" style="width:68px;height:65px"></td
<td><img src="$image" alt="$zodiac" style="width:68px;height:65px"></td>
<td><img src="$image" alt="$zodiac" style="width:68px;height:65px"></td>
</tr>
<tr>
<td><img src="$image" alt="$zodiac" style="width:68px;height:65px"></td>
<td><img src="$image" alt="$zodiac" style="width:68px;height:65px"></td>
<td><img src="$image" alt="$zodiac" style="width:68px;height:65px"></td>
</tr>
<tr>
<td><img src="$image" alt="$zodiac" style="width:68px;height:65px"></td>
<td><img src="$image" alt="$zodiac" style="width:68px;height:65px"></td>
<td><img src="$image" alt="$zodiac" style="width:68px;height:65px"></td>
</tr>
<tr>
<td><img src="$image" alt="$zodiac" style="width:68px;height:65px"></td>
<td><img src="$image" alt="$zodiac" style="width:68px;height:65px"></td>
<td><img src="$image" alt="$zodiac" style="width:68px;height:65px"></td>
</tr>
</table>";
?>
Help is welcome, thank you.
I actually asked a question here yesterday and decided to try a different route with it. What I am doing is passing an email variable entered from my home page on to www.dollapal.com/offerlist.php. I'm wanting this page to be a complete list of all of my entries in my surveys table. The email variable needs to be appended to the end of every link. I got that to work, but what I want to do now is display that information for every record in my 'surveys' table. Right now I am using the random function, which I'm sure is wrong, but I'm not sure what function to be looking for. Is it possible to use a foreach function here to echo each record? If so, I'm not sure how exactly to call the foreach() function in this case. I believe my two problems lie in the random and foreach functions, but I'm not sure how to correct them. I've attached a little chunk of code that I'm working with. I'm not sure if I'm completely off base here, or if I'm close to achieving my desired result. Please let me know if you require more information. This forum has been amazing to me so far. Thank you all for your help! This topic has used a waypoint to get to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=359489.0 How do I like it, you ask? Quite well. Besides the downtime Tuesday I haven't had any server problems, and the game itself is great. Very D2-esque but with very noticeable enhancements. hi ..
hit little snag Ive got html <form name="formx" method="POST" action="connect.php" class='ajaxform'> and about 4 varibles in that form .. now how to properly
query table users so i can find out which prefix correspond with that user
Insert into table "upis" in this case that prefix with 3 variables..
everything in single,.. in this case connect.php file
I know how to do QUERY and INSERT INTO but i don't know how to connect with 2 different tbl or db and do the query and input of data.. every time I put 2 of them together .. never works out..
this is example.. i dont know is this right way to do it .. Hi - I know this is a #101 question but here goes! I simply want to select a single row from a table and use the columns fields as variables that can then be posted in a form. $result = mysql_query("SELECT * from tblquestions WHERE qid='1'"); if (!$result) { echo 'Could not run query: ' . mysql_error(); exit; } $row = mysql_fetch_row($result); $oid=$result['oid']; $qid=$result['qid']; $question=$result['question']; The code above isn't working - as when I try to echo each variable <?php echo $question;?> nothing is being shown on screen. I'm obviously barking up the wrong tree in the way I'm trying to create the variable - but don't really have any idea where to look next.
When I echo out my variable in the php file it works fine but when I put the variable in a table cell it doesn't echo out. Quote <?php $var = "http://www.google.com" ; ?> <iframe id="I1" name="I1" src= http://www.google.com style="width: 1186px; height: 1346px; float: middle"> Your browser does not support inline frames or is currently configured not to display inline frames. </iframe></div> Instead of the bold parts, I want the frame to show what $var links to, but as I have closed ?PHP, it will not return the link. Any help on how to make it go to $var? First page adds a new job number, then the order page loaded with the job number id as a get id. Basically there is a while loop in the order page which shows products/services client can order and he chooses what he requires 'one or eight services' (8 in total) and some other variables like date of order and client name etc. Here is the order item code The first sql statement executes fine, but in the second sql query nothing happens $sql="insert into job_order(order_num,order_date,order_customer_id, order_remarks) values(".$_GET['id'].",NOW(),".$_POST['companyBox'].",'".$_POST['remarkBox']."');"; $res=mysql_query($sql); $id=mysql_insert_id(); foreach($_POST as $key => $value) { if(!empty($value)) { $key.' => '.trim(strip_tags($value)); $order="INSERT INTO orderprod (order_num,prod_id,order_amount,teeth_amount) VALUES ('$_GET[id]','$value','$value','$value');"; $orderres=mysql_query($order) or die(mysql_error()); } }?>$sql="insert into job_order(order_num,order_date,order_customer_id, order_remarks) values(".$_GET['id'].",NOW(),".$_POST['companyBox'].",'".$_POST['remarkBox']."');"; $res=mysql_query($sql); $id=mysql_insert_id(); foreach($_POST as $key => $value) { if(!empty($value)) { $key.' => '.trim(strip_tags($value)); $order="INSERT INTO orderprod (order_num,prod_id,order_amount,teeth_amount) VALUES ('$_GET[id]','$value','$value','$value');"; $orderres=mysql_query($order) or die(mysql_error()); } } ?> ============= This is the formI have removed parts which are irrelevant. Please note that dateBox and companyBox are not required to be looping as they are only for first table, echo "<form action=".$config_basedir."./vieworder.php?id=".$_GET['id']." name=form1 method=post>";?><table><tr><td><h4>JOB ORDER</H4></TD><TD></TD></TR><TR><TD>ORDER NUMBER</TD><TD><?PHP ECHO $_GET['id'] ?></td></tr><tr><td>ORDER DATE</td><td><input type=text name=dateBox></td></tr> <tr><td>COMPANY NAME</td><td><?PHP$sql="select * from customers";$res=mysql_query($sql);echo "<select name=companyBox><option value=''>Please select</option>";WHILE($fetch=mysql_fetch_assoc($res)){ echo "<option value='".$fetch['id']."'>".$fetch['cust_name']."</option>";} echo "</select>"; echo "</td></tr>"; ?> </table> <table><tr><th>ITEM</th><th>QUANTITY</th><th>N0. of Teeths</th></tr><tr><?PHP$sql="select * from products";$res=mysql_query($sql); WHILE($fetch=mysql_fetch_assoc($res)){ echo "<td><input type=text name=desBox value='".$fetch['prod_id']."'>".$fetch['prod_name']."</td><td><input type=text name=quantBox></td><td><input type=text name=teethBox></td>";echo "</tr>";}echo "</table>";?>echo "<form action=".$config_basedir."./vieworder.php?id=".$_GET['id']." name=form1 method=post>"; ?> <table> <tr> <td><h4>JOB ORDER</H4></TD><TD></TD> </TR> <TR> <TD>ORDER NUMBER</TD><TD><?PHP ECHO $_GET['id'] ?></td> </tr> <tr> <td>ORDER DATE</td><td><input type=text name=dateBox></td> </tr> <tr> <td>COMPANY NAME</td><td> <?PHP $sql="select * from customers"; $res=mysql_query($sql); echo "<select name=companyBox><option value=''>Please select</option>"; WHILE($fetch=mysql_fetch_assoc($res)){ echo "<option value='".$fetch['id']."'>".$fetch['cust_name']."</option>";} echo "</select>"; echo "</td></tr>"; ?> </table> <table> <tr> <th>ITEM</th><th>QUANTITY</th><th>N0. of Teeths</th> </tr> <tr> <?PHP $sql="select * from products"; $res=mysql_query($sql); WHILE($fetch=mysql_fetch_assoc($res)){ echo "<td><input type=text name=desBox value='".$fetch['prod_id']."'>".$fetch['prod_name']."</td> <td><input type=text name=quantBox></td> <td><input type=text name=teethBox></td>"; echo "</tr>";} echo "</table>"; ?> HERE IS THE IMAGE showing the populated services. http://dubads.com/images/order.jpg Hi all. I have this code. <?php $ext = ' <form action="/members/clubs/view-activity.php" method="post" name="venuefrm"> <button type="submit" id="close" class="link"><span>View Activity</span></button> <input name="activity" type="hidden" value="<?php echo $activites['activityID']; ?>" /> </form>'; ?> The code falls down at the value="<?php echo $activites['activityID']; ?>" part. Can someone please show me how I break into php to write this part properly as I dont understand an it is obviously wrong. Thanks Danny |
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