PHP - Folder Does / Does Not Exist?

Hi everyone, I'm still learning, but getting intermediate in PHP now, but it is still challenge to learn. I'm trying to have php check to see if one file inside folder in server, seem I could not get it right, but I tested it on other site, it works, but not this script, I don't understand why it won't work...maybe logical is wrong?

here my code:

	if ($_POST['video']) {
	        $path1 = "UPLOADS/Home/";
        $path2 = "UPLOADS/Breakfast/";
        $path3 = "UPLOADS/Spider/";
	        $scan1 = scandir($path1);
        $scan2 = scandir($path2);
        $scan3 = scandir($path3);
	        $count1 = count($scan1) - 3;
        $count2 = count($scan2) - 3;
        $count3 = count($scan3) - 3;
	        if($count1 > 0) {
            header('location:exist.html');
        }elseif ($count2 > 0) {
            header('location:exist.html');
        }elseif ($count3 > 0) {
            header('location:exist.html');
        }
	

But other site, it works:

	$scan = scandir($path);
$count = count($scan) - 3;
	echo $count;
	if($count > 1){
    echo "Hello yourself!<br />";
}
	

Anyone will help will be appreciate! Thank you!

Gary

Edited April 3, 2019 by sigmahokies

i have error where my code should update existing data where id exist, it get updated ..but the others data is disappeared .only the data updated is remained 

$sql1 ="select*from semakan_dokumen where email='$stdEmail'";
$sqlsearch1 = mysqli_query($dbconfig,$sql1);
$resultcount1 = mysqli_num_rows($sqlsearch1);

if($resultcount1 > 0){
$query1=("UPDATE  semakan_dokumen set student_id='$noMatrik', email= '$stdEmail', surat_tawaran='$fileName', ic='$fileName1',sijil_lahir='$fileName2',sijil_spm= '$fileName3',sijil_sekolah= '$fileName4', sijil_dip= '$fileName5',sej_julai='$fileName6',bm_julai='$fileName7',muet='$fileName8', mid1='$fileName9',yuran= '$fileName10',umpa_bend1= '$fileName11',umpa_bend2='$fileName12',bpkp='$fileName13', penaja='$fileName14',kesihatan= '$fileName15', jhepa='$fileName16' where email= '$stdEmail' ");

}else{


//filezip
$query1 = "INSERT INTO semakan_dokumen (email,surat_tawaran,ic,sijil_lahir,sijil_spm,sijil_sekolah,sijil_dip,sej_julai,bm_julai,muet,mid1,yuran,umpa_bend1,umpa_bend2,bpkp,penaja,kesihatan,jhepa) VALUES ('$stdEmail','$fileName','$fileName1','$fileName2','$fileName3','$fileName4','$fileName5','$fileName6','$fileName7','$fileName8','$fileName9','$fileName10','$fileName11','$fileName12','$fileName13','$fileName14','$fileName15','$fileName16')";
}

 

I got this script:

But it give me error, file_get_contents cannot open stream.

I need to add the FTP connection with user/pass paramaters.

then look in set http url, to get the file contents(images) and transfer to ftp server location.

Can Anyone take alook and tell me if I am going down the right path and how to get there. Please

Code: [Select]
function postToHost($host, $port, $path, $postdata = array(), $filedata = array()) {
$data = "";
$boundary = "---------------------".substr(md5(rand(0,32000)),0,10);
$fp = fsockopen($host, $port);

fputs($fp, "POST $path HTTP/1.0\n");
fputs($fp, "Host: $host\n");
fputs($fp, "Content-type: multipart/form-data; boundary=".$boundary."\n");

// Ab dieser Stelle sammeln wir erstmal alle Daten in einem String
// Sammeln der POST Daten
foreach($postdata as $key => $val){
$data .= "--$boundary\n";
$data .= "Content-Disposition: form-data; name=\"".$key."\"\n\n".$val."\n";
}

// Sammeln der FILE Daten
if($filedata) {
$data .= "--$boundary\n";
$data .= "Content-Disposition: form-data; name=\"".$filedata['name']."\"; filename=\"".$filedata['name']."\"\n";
$data .= "Content-Type: ".$filedata['type']."\n";
$data .= "Content-Transfer-Encoding: binary\n\n";
$data .= $filedata['data']."\n";
$data .= "--$boundary--\n";
}

// Senden aller Informationen
fputs($fp, "Content-length: ".strlen($data)."\n\n");
fputs($fp, $data);

// Auslesen der Antwort
while(!feof($fp)) {
$res .= fread($fp, 1);
}
fclose($fp);

return $res;
}

$postdata = array('var1'=>'today', 'var2'=>'yesterday');
$filedata = array(
'type' => 'image/png',
'data' => file_get_contents('http://xxx/tdr-images/images/mapping/dynamic/deals/spot_map')
);

echo '<pre>'.postToHost ("localhost", 80, "/test3.php", $postdata, $filedata).'</pre>';

I want to copy everything in templates/blue to the folder code/

However:

shell_exec("cp -r 'templates/blue' 'code'");

Creates a folder called blue inside code. I tried cp -r 'templates/blue/*' 'code', but that didn't do anything.

Any ideas?

if so how would they be used in a mysql query?