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PHP - Jquery And Php To Update A Table In Mysql
Hi,
I am trying to build a jQuery and PHP love it button where the user clicks it and the number increments and saves to a DB. I have it all working apart from the Saving to the DB part : ) I have this currently to save but it doesnt seem to work. Code: [Select] <?php mysql_connect("localhost", "web183-loveit", "password") or die ("Error."); mysql_select_db("web183-loveit") or die ("error"); $increase = "UPDATE results SET value=value+1 WHERE id=1;"; $active_rate = mysql_query("SELECT * FROM results WHERE id=1;"); $val = 0; if($rt = mysql_fetch_assoc($active_rate)) { $val = $rt['value']; } if($_POST['action'] == 'add') { mysql_query($increase); print $val++; } ?> Please see it here http://bit.ly/dKx15z Any ideas?? cheers Craig Similar TutorialsCan anyone post a generic update function to update mysql table. The manual approach: update $tablename set $column1='a', $column2='b' where $id=$value; Hi, what I am trying to do is "update" a mysql table via a form post, instead of "insert into" a table. I have a selected ID field or RID in the case of my code below... Code: [Select] <?php $q=$_GET["q"]; $con = mysql_connect('my-host', 'my_user', 'my_pwd'); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("my_db", $con); $sql="SELECT * FROM daterange WHERE DEND > DATE(NOW()) AND STATUS='A' AND MONTH = '".$q."' ORDER BY RID, DATE, SITE"; $result = mysql_query($sql); // Determine the number of reservation dates $number = mysql_numrows($result); // Create drop-down menu of reservation dates print "<font size=\"3\" face=\"Arial\"><b>Select Your Reservation:</b><br> <form action=\"resersend.php\" method=\"post\"> <select name=\"RID\"> <option value=\"\">Choose One</option>"; for ($i=0; $i<$number; $i++) { $RID = mysql_result($result,$i,"RID"); $DATE = mysql_result($result,$i,"DATE"); $SITE = mysql_result($result,$i, "SITE"); $PRICE = mysql_result($result,$i, "PRICE"); print "<option value=\"$RID\">$DATE, $SITE, $PRICE</option>"; } print "</select><p align=left><label><font size=\"3\" face=\"Arial\">First Name: <input type=\"text\" name=\"FNAME\" size=\"50\" maxlength=\"50\" tabindex=\"1\"<br>"; print "<p align=left><label>Last Name: <input type=\"text\" name=\"LNAME\" size=\"50\" maxlength=\"50\" tabindex=\"2\"<br>"; print "<p align=left><label>Address Line 1: <input type=\"text\" name=\"ADDR1\" size=\"50\" maxlength=\"50\" tabindex=\"3\"<br>"; print "<p align=left><label>Address Line 2: <input type=\"text\" name=\"ADDR2\" size=\"50\" maxlength=\"50\" tabindex=\"4\"<br>"; print "<p align=left><label>City: <input type=\"text\" name=\"CITY\" size=\"50\" maxlength=\"50\" tabindex=\"5\"<br>"; print "<p align=left><label>State (abbrev.): <input type=\"text\" name=\"STATE\" size=\"2\" maxlength=\"2\" tabindex=\"6\"<br>"; print "<p align=left><label>Zip Code: <input type=\"text\" name=\"ZIP\" size=\"5\" maxlength=\"5\" tabindex=\"7\"<br>"; print "<p align=left><label>Contact Phone Number: (<input type=\"text\" name=\"PHONE1\" size=\"3\" maxlength=\"3\" tabindex=\"8\""; print "<label>)<input type=\"text\" name=\"PHONE2\" size=\"3\" maxlength=\"3\" tabindex=\"9\""; print "<label>-<input type=\"text\" name=\"PHONE3\" size=\"4\" maxlength=\"4\" tabindex=\"10\"<br>"; print "<p align=left><label>Email: <input type=\"text\" name=\"EMAIL\" size=\"50\" maxlength=\"50\" tabindex=\"11\"<br>"; print "<p align=left><input type=\"submit\" value=\"Book Now!\" name=\"submit\">"; print "<input type=\"reset\" value=\"reset\" name=\"reset\"></form>"; // Close the database connection mysql_close($con); ?> Can someone help me update the selected RID field with the remainder of the fields from the form above, point me in the right direction? Thanks. MOD: Thanks for moving to the correct forum - much appreciated! OK, I've taken a look around and cannot find a complete tutorial on how to do this. I have created a database with a table and the following fields; id, day, month, year, event, type What I am trying to do is read the data held in the table by referencing the type field (unique data), have it populate data firleds which are user editable and then once all changes are made have it update into the table. I can't imagine that this is that hard at all, but I cannot for the life of me figure it out! Anybody got a tutorial or some code which will do this? Hi, when I submit a form I want to update a field in the "daterange" table. In the form the id field (RID) from "daterange" is selected prior to submit. Basically, I want to change the STATUS field to B (from A). The structure of daterange table is as follows: RID (key field) DEND MONTH DATE SITE PRICE STATUS What is the easiest way to accomplish this? Here is the code from the form (if it will help)... Code: [Select] <?php //************************************** // Page load dropdown results // //************************************** function getTierOne() { $result = mysql_query("SELECT DISTINCT MONTH FROM daterange") or die(mysql_error()); while($tier = mysql_fetch_array( $result )) { echo '<option value="'.$tier['MONTH'].'">'.$tier['MONTH'].'</option>'; } } //************************************** // First selection results // //************************************** if($_GET['func'] == "drop_1" && isset($_GET['func'])) { drop_1($_GET['drop_var']); } function drop_1($drop_var) { include_once('db.php'); $result = mysql_query("SELECT * FROM daterange WHERE DEND > DATE(NOW()) AND STATUS='A' AND MONTH='$drop_var' ORDER BY DATE, SITE") or die(mysql_error()); echo '<select name="RID"> <option value=" " disabled="disabled" selected="selected">Choose a Reservation</option>'; while($drop_2 = mysql_fetch_array( $result )) { echo '<option value="'.$drop_2['RID'].'">'.$drop_2 ['DATE']. ', '.$drop_2 ['SITE']. ', '.$drop_2 ['PRICE'].'</option>'; } echo '</select> '; echo "<br />"; echo "</select><p align=left><label><font size=\"2\" face=\"Arial\">First Name: <input type=\"text\" name=\"FNAME\" size=\"50\" maxlength=\"50\" tabindex=\"1\"<br />"; echo "<p align=left><label>Last Name: <input type=\"text\" name=\"LNAME\" size=\"50\" maxlength=\"50\" tabindex=\"2\"<br />"; echo "<p align=left><label>Address Line 1: <input type=\"text\" name=\"ADDR1\" size=\"50\" maxlength=\"50\" tabindex=\"3\"<br />"; echo "<p align=left><label>Address Line 2: <input type=\"text\" name=\"ADDR2\" size=\"50\" maxlength=\"50\" tabindex=\"4\"<br />"; echo "<p align=left><label>City: <input type=\"text\" name=\"CITY\" size=\"50\" maxlength=\"50\" tabindex=\"5\"<br />"; echo "<p align=left><label>State (abbrev.): <input type=\"text\" name=\"STATE\" size=\"2\" maxlength=\"2\" tabindex=\"6\"<br />"; echo "<p align=left><label>Zip Code: <input type=\"text\" name=\"ZIP\" size=\"5\" maxlength=\"5\" tabindex=\"7\"<br />"; echo "<p align=left><label>Contact Phone Number: (<input type=\"text\" name=\"PHONE1\" size=\"3\" maxlength=\"3\" tabindex=\"8\""; echo "<label>)<input type=\"text\" name=\"PHONE2\" size=\"3\" maxlength=\"3\" tabindex=\"9\""; echo "<label>-<input type=\"text\" name=\"PHONE3\" size=\"4\" maxlength=\"4\" tabindex=\"10\"<br />"; echo "<p align=left><label>Email: <input type=\"text\" name=\"EMAIL\" size=\"50\" maxlength=\"50\" tabindex=\"11\"<br />"; echo '<input type="submit" name="submit" value="Book Now!" /><br />'; echo '<input type="reset" name="submit" value="Reset" /><br />'; } ?> Hi all I have 2 tables: 1. is a tables full of images that have an id, a src and a title (images_table). 2. table is a list of records with an id, a description and an images_id (records_table) What I'm looking to do is: Loop through the records in the records_table and find the description, the description is something like this 'Welcome to Kansas'. Then, I want to loop through the images_table and find the associated image of Kansas, based on a MySQL LIKE statement. This is because the images_table has a title of 'Kansas', for example. Once this has been done, I then need to insert the id of Kansas into the images_id in the records_table a possible MySQL UPDATE. Has anyone got an idea how I could do this? Thanks This way seems not good. <?php $username ="MANCENT"; $user_input_x = _xmouse.movement ;//FLASH $user_input_y = _ymouse.movement ;//FLASH while(true) { $updatepos = mysql_query("UPDATE users_float SET user_input_x = '$user_input_x' , user_input_y = '$user_input_y' WHERE username = '$username'"); } This way works but whats a better way? ?> I am pulling 5 addresses and I am wanting to store these 5 addresses in columns in a separate table. On the query string I put LIMIT 5. How can I store the results of each of the 5 loops into columns in a separate table? The columns are A1(for name), A2(for address), A3 (for city), A4 (for state), A5 (for zip), A6 (for phone), A7 (for miles), .... then I also have B1-B7, C1-C7, D1-D7, and E1-E7. I am basically wanting to store up to 5 addresses in an array and then update them into a mysql table. Code: [Select] foreach ($zips as $key => $value) { $result = mysql_query("SELECT State FROM extreme WHERE Zip = '$key' AND Type='store' AND `InStore` <> 'NO' LIMIT 5", $db); $num_rows = mysql_num_rows($result); while($myrow = mysql_fetch_array ($result)) { $Dealer=$myrow['Dealer']; $Address=$myrow['Address']; $City=$myrow['City']; $State=$myrow['State']; $Zip=$myrow['Zip']; $Phone=$myrow['Phone']; $Miles = $value; } } Hi,
I've seen this done, and I thought it would be simple now that I am starting to understand ajax but I can't figure it out.
I am using jQuery ajax via wordpress. I can click a button, call a php function and use the value returned from php to populate the textbox.
Ok, great!
but I want to run a rather lengthy procedure, and while it's running I would like it to record it's status in a multi-line text box as sort of a debugger ( and to pass the time while waiting )
How can I accomplish this?
I've googled but I must not be using the correct words to search.
I'm new to PHP and I was able to figure out how to populate data from my database into my text fields. I am trying to add the update information to the same php file; however, I am now receiving errors within the data I was able to populate,
Notice: Undefined variable: stmt in C:\xampp\htdocs\Cust_App\update.php on line 47 and errors with the Update statement
Notice: Undefined variable: stmtupdate in C:\xampp\htdocs\Cust_App\update.php on line 96 I had defined the customerID variable above in the code, but it isn't being captured from here. I tried setting up this query like the one which gathered the data, but I'm off by a little bit. I would like the option to be able to update all fields. Any help is appreciated. I'm trying to learn as I may get asked to update other forms in the future. (new boss asks a lot)
<?php
require_once('database.php');
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"
"http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<!-- the head section -->
<head>
<title>My Guitar Shop</title>
<link rel="stylesheet" type="text/css" href="main.css" />
</head>
<!-- the body section -->
<body>
<div id="page">
<div id="header">
<h1>SportsPro Technical Support</h1>
<p>Sports management software for the sports enthusiast.</p></h1>
</div>
<div id="main">
<h1>View/Update Customer</h1>
<form action="update.php" method="get" >
<?php
if(isset($_GET['customerID'])) {
$customerID = filter_input(INPUT_GET, 'customerID', FILTER_SANITIZE_NUMBER_INT);
$sql = "SELECT * FROM customers WHERE customerID =$customerID ";
$stmt = $db->query($sql);
}
?>
<div id="content">
<!-- display a table of products -->
<h2>Customers</h2>
<form method = "edit">
<?php foreach ($stmt as $cust) { ?>
<div>
<label>First Name</label>
<input type="text" name="name" class ="form-control" value ="<?php echo $cust['firstName']; ?>">
</div><br>
<div>
<label>Last Name</label>
<input type="text" name="name" class ="form-control" value ="<?php echo $cust['lastName']; ?>">
</div><br>
<div>
<label>Address</label>
<input type="text" name="address" class ="form-control" value ="<?php echo $cust['address']; ?>">
</div><br>
<div>
<label>City</label>
<input type="text" name="city" class ="form-control" value ="<?php echo $cust['city']; ?>">
</div><br>
<div>
<label>State</label>
<input type="text" name="state" class ="form-control" value ="<?php echo $cust['state']; ?>">
</div><br>
<div>
<label>Country</label>
<input type="text" name="countryCode" class ="form-control" value ="<?php echo $cust['countryCode']; ?>">
</div><br>
<div>
<label>Zip Code</label>
<input type="text" name="postalCode" class ="form-control" value ="<?php echo $cust['postalCode']; ?>">
</div><br>
<div>
<label>Email </label>
<input type="text" name="email" class ="form-control" value ="<?php echo $cust['email']; ?>">
</div><br>
<div>
<label>Phone Number </label>
<input type="text" name="phone" class ="form-control" value ="<?php echo $cust['phone']; ?>">
</div><br>
<div>
<label>Password </label>
<input type="text" name="password" class ="form-control" value ="<?php echo $cust['password']; ?>">
</div><br>
<div>
<?php }
?>
<input type="Submit" name="Update_Data" value="Update Data"></input>
<?php
$sql2 = "UPDATE customers SET firstName = ". $stmtupdate['firstName']." WHERE customerID =$customerID ";
$stmtupdate = $db->query($sql2);
?>
</div>
</div>
<div id="footer">
<p>
© <?php echo date("Y"); ?> SportsPro, Inc.
</p>
</div>
</div><!-- end page -->
</body>
</html>
Please help me with this: been doing this for 2 days and still cannot solve it. it won't update... I have attached my file: <?php include('connect-database.php'); if (isset($_POST['submit']) AND $_POST['submit'] == 'update') { $error = false; extract($_POST); if (empty($full_name)) $error = true; if (!$error) { $update = "UPDATE users SET full_name = '$full_name', WHERE id=$id "; mysql_query($update) or die(mysql_error() . "<br><br>" . $update); $full_name = ''; $message = "Record successfully updated."; } else { $message = "There is an error in your entry"; } } else { $id = intval(isset($_GET['id']) ? $_GET['id'] : 0); } if ($id == 0) { echo "<div style='margin-bottom:10px'>Invalid ID.</div>"; exit; } $query = "SELECT * FROM users WHERE id=$id"; $result = mysql_query($query) or die(mysql_error() . "<br><br>" . $query); if (mysql_num_rows($result) == 0) { echo "<div style='margin-bottom:10px'>Record Not Found in Database!</div>"; exit; } $row = mysql_fetch_array($result); extract($row); ?> <div id="mainContent" class="tab_container"> <div id="tab1" class="tab_content"> <h1>Edit Personal Data</h1> <div style="color:red;font-weight:bold"><? echo $message; ?></div> <form name="submit" action="" method="post"> <ul> <li><b>ID # :</b> <?php echo $id?></li> <li><b>Name :</b> <input type="text" name="full_name" id="" size="30" value="<?php echo $full_name ?>" /></li> <li><b>Address :</b> <input type="text" name="address" id="" size="55" maxlength="100" value="<?php echo $address ?>" /></li> <li><b>Contact Number :</b> <input type="text" name="contact_number" id="" size="11" value="<?php echo $contact_number ?>" /></li> <li><b>Email Address :</b> <input type="text" name="user_email" id="" size="30" value="<?php echo $user_email ?>" /></li> <li><b>Status :</b> <input type="text" name="status" id="" size="10" value="<?php echo $status ?>" /></li> <li><b>Nationality :</b> <input type="text" name="nationality" id="" size="20" value="<?php echo $nationality ?>" /></li> <li><b>Religion :</b> <input type="text" name="religion" id="" size="20" value="<?php echo $religion ?>" /></li> </ul> <h2>Self Description</h2> <p><textarea rows="9" cols="40" name="self_description" ><?php echo $self_description ?></textarea></p> <input type="hidden" name="id" value="<?php echo $id; ?>" /> <input type="submit" name="submit" value="update" /> </form> </div> Hello I have three tables User diysmps usergroup usergroupid is common in the three tables. diysmps is joined on usergroup, so running this sql SELECT diysmps.name, diysmps.email, diysmps.sumbit, diysmps.message, diysmps.ID, usergroup.title FROM diysmps INNER JOIN usergroup ON diysmps.usergroupid = usergroup.usergroupid ORDER BY diysmps.ID DESC see results i get in picture attached. the result (PENDIN REGISTRATION) is what i need to be updated WHEN the user register to the forums. when the user register to the forums, an account with his EMAIL will be created into the (USER) table. So, I need to look out for the email FROM (diysmps TABLE) into the user table _search user table for email from diysmps table_ and if found to update the USERGROUPID in (diysmps TABLE) withe the USERGROUPID from (USER) table (related to the email searched) so, when user registers, status from PENDING REGISTRATION to REGISTERED will be shown I know it looks complex for me, but thats how i can describe Thanks all Hello, i want when click next button to show the 4 content ... ive try everything Code: [Select] <div id="MoreBoxBorder"><div id="MoreBoxBorderLine"></div></div> <div id="ArrowMoreBox"><a class="next browse right"><div id="ArrowMoreImage"></div></a></div> <?php $query = "SELECT *, date_FORMAT(Date, '%H:%i') as Date_Time FROM tblnews WHERE LatestNews = 1 AND Category != 10 ORDER BY `Date` DESC LIMIT 4"; $result = mysql_query($query); while($row = mysql_fetch_assoc($result)) { ?> <div id="MoreBox" id="comments"> <div class="box"> <a href="<?php echo BASE_URL;?>index.php?pid=article&artidread=<?php echo $row['Id'];?>"><img src="<?php echo html_entity_decode($row['Thumb']);?>" border="0" width="110" height="64" /></a> <strong><a href="<?php echo BASE_URL;?>index.php?pid=article&artidread=<?php echo $row['Id'];?>"><strong><?php echo html_entity_decode(substr($row['Title'],0,437));?></strong></a></strong> <p><?php echo html_entity_decode($row['SubTitle']);?></strong> <div id="MoreIcoBox"> <a href="<?php echo BASE_URL;?>index.php?pid=article&artidread=<?php echo $row['Id'];?>"><img id="MoreIco" src="<?php echo BASE_URL;?>images/news/more.png" border="0" /></a> </div> </div> </div> <?php } ?> Like the image.. when i click next image will display another 4 (& auto scroll every 10seconds) Any help please Thank you Hey, I have this code, and it's ment to change the name / content of a page that is being put onto a page. Both of the include files are fine as it works for other actions, but this one just returns the error. <?php include "../includes/mysql_connect.php"; include "../includes/info_files.php"; if(isset($_POST['submitted'])) { mysql_query("UPDATE `pages` SET name='$_POST[name]' AND SET content='$_POST[content]' AND SET catt='$_POST[catt]' AND SET page='$_POST[page]' WHERE id='$_POST[id]'") or die('Edit failed'); echo "Page made.<br /><br />"; }else{ $result = mysql_query("SELECT * FROM pages WHERE id='$_GET[page]'"); while($row = mysql_fetch_array($result)) { echo '<form action="" method="post">'; echo '<input type="hidden" name="id" value="' . $row['id'] . '" /><br />'; echo '<strong>Edit: ' . $row['name'] . '</strong><br />'; echo 'Name: <input type="text" name="name" value="' . $row['name'] . '" /><br />'; echo 'Category: <input type="text" name="catt" value="' . $row['catt'] . '" /><br />'; echo 'Page: <input type="text" name="page" value="' . $row['page'] . '" /><br />'; echo '<textarea rows="25" cols="60" name="content">' . $row['content'] . '</textarea><br />'; echo '<input type="submit" name="submitted" value="Edit" />'; echo '</form>'; } } ?> Any help would be great. Code: [Select] if(isset($_POST['npassword']) and ($_POST['cpassword'])){ $npassword = $_POST['npassword']; $cpassword = $_POST['cpassword']; $username = $_SESSION['SESS_login']; if($npassword==$cpassword){ $password = md5($npassword); $lol = mysql_query("UPDATE `members` SET `passwd` = '$password' WHERE `login`= '$username';"); echo"Password Changed!"; } } It echos password changed, but its not updating the password. If I run it in phpmyadmin it works fine... So i'm really stuck. I have the following code that when used seperately work. How would I write an if..else statement that will make them work together? The following code give me an Parse Error, syntax error unexpected T_string. The following if my code I have tried, Code: [Select] if (SELECT tournament FROM weekly_picks WHERE tournament = '$tournament') mysql_query("UPDATE weekly_picks SET player = '$golfer' WHERE tournament = '$tournament' AND user = '$usr'"); else mysql_query("INSERT INTO weekly_picks (t_id, tournament, user, player, backup, timestamp) VALUES ('$t_id', '$tournament', '$usr', '$golfer', '$backup', '$time')",$link) or die('Error, insert query failed'); I also know that values are being stored in the variables. this is what i have so far but i cant get it to update the data update page <?php $host="localhost"; // Host name $username="**"; // Mysql username $password="*****"; // Mysql password $db_name="manews"; // Database name $tbl_name="Shows"; // Table name // Connect to server and select database. mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); // get value of id that sent from address bar $id=$_GET['id']; // Retrieve data from database $sql="SELECT * FROM $tbl_name WHERE id='$id'"; $result=mysql_query($sql); $rows=mysql_fetch_array($result); ?> <table width="400" border="0" cellspacing="1" cellpadding="0"> <tr> <form name="form1" method="post" action="update_ac.php"> <td> <table width="100%" border="0" cellspacing="1" cellpadding="0"> <tr> <td> </td> <td colspan="3"><strong>Update data in mysql</strong> </td> </tr> <tr> <td align="center"> </td> <td align="center"> </td> <td align="center"> </td> <td align="center"> </td> </tr> <tr> <td align="center"> </td> <td align="center"><strong>Day</strong></td> <td align="center"><strong>Month</strong></td> <td align="center"><strong>Year</strong></td> <td align="center"><strong>Song</strong></td> <td align="center"><strong>Data</strong></td> </tr> <tr> <td> </td> <td align="center"><input name="Day" type="text" id="Day" value="<? echo $rows['Day']; ?>"></td> <td align="center"><input name="Month" type="text" id="Month" value="<? echo $rows['Month']; ?>"></td> <td align="center"><input name="Year" type="text" id="Year" value="<? echo $rows['Year']; ?>" size="15"></td> <td align="center"><input name="Song" type="text" id="Song" value="<? echo $rows['Song']; ?>"></td> <td align="center"><input name="Data" type="text" id="Data" value="<? echo $rows['Data']; ?>" size="15"></td> </tr> <tr> <td> </td> <td><input name="id" type="hidden" id="id" value="<? echo $rows['id']; ?>"></td> <td align="center"><input type="submit" name="Submit" value="Submit"></td> <td> </td> </tr> </table> </td> </form> </tr> </table> <? // close connection mysql_close(); ?> update script <?php $host="localhost"; // Host name $username="**"; // Mysql username $password="**"; // Mysql password $db_name="manews"; // Database name $tbl_name="Shows"; // Table name // Connect to server and select database. mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); // update data in mysql database $sql="UPDATE $tbl_name SET Day='$Day', Month='$Month', Year='$Year', Year='$Song', Year='$Data' WHERE id='$id'"; $result=mysql_query($sql); // if successfully updated. if($result){ echo "Successful"; echo "<BR>"; echo "<a href='list_records.php'>View result</a>"; } else { echo "ERROR"; } ?> So there is this code I have here : http://pastebin.com/rwcN7FeJ and I need to find a way to incorporate this code that user Barand gave me Code: [Select] $referName = mysql_real_escape_string($gateway_data['refer']); $query = "UPDATE users a INNER JOIN users b ON a.refer = b.nick SET a.refer = '', b.balance = b.balance + 5 WHERE b.refer = '$referName'"; mysql_query($query); But I havent the damnedest how to do that. If anyone could help me at all, it would be appreciated. I have lost my record when I run the code below, all fields are empty... Code: [Select] <a href='edit.php?id={$info['person_id']}'><font color='#00AE0A'>Edit User</font> </a> Code: [Select] $sql = "SELECT * FROM person WHERE person_id='{$_REQUEST['id']}' "; $result = mysql_query($sql); if (!$result) { echo("<p>Error performing query: " . mysql_error() . "</p>"); exit(); } if ($row = @mysql_fetch_array($result, MYSQL_ASSOC)) { print " <form action='<?php echo $PHP_SELF;?>' method=\"post\"> <table> <tr> <td><strong>Name</strong></td> <td><input type=\"text\" name=\"fname\" size=\"60\" value=\"$row[fname]\"></td> </tr> <tr> <td><strong>Surname</strong></td> <td><input type=\"text\" name=\"lname\" size=\"60\" value=\"$row[lname]\"></td> </tr> <tr> <td><strong>Email</strong></td> <td><input type=\"text\" name=\"email\" size=\"60\" value=\"$row[email]\"></td> </tr> <tr> <td><strong>Committee</strong></td> <td><input type=\"text\" name=\"committee_no\" size=\"60\" value=\"$row[committee_no]\"></td> </tr> <tr> <td><INPUT type=\"submit\" value=\"Send\"> </td> </tr> </table></form> "; } else { echo("There has been an error" . mysql_error()); } /* closes connection */ ?> <?php $control = mysql_query(" UPDATE person SET fname='{$_REQUEST['fname']}' , lname='{$_REQUEST['lname']}' , email='{$_REQUEST['email']}', committee_no='{$_REQUEST['committee_no']}' WHERE person_id='{$_REQUEST['id']}'"); if($control) { header("Location:".$_SERVER["HTTP_REFERER"].""); } ?> I have this query: Code: [Select] $sql3 = "UPDATE users SET hours = '$newHours', pay = '$newPay', virtualLocation = '$arrival', expDate = '$expDate' WHERE pilotID = '$pilotid'"; I've echoed it out and all the variables put out the correct values. The query works except for the pay section of it. It will update the hours, virtual location, and expiration date but it will not update the pay. It inputs 1.00 when the value echoed in the query is not 1.00. I'm not sure if, because it is a decimal, it changes how the query works. Any help? Thanks. I have made this, although i can not seem to the status... changeapp.php Code: [Select] <form method="post" name="memberadd" action="change_app_complete.php"> <label>Name:</label> <select name="member"> <?php $con = mysql_connect("host","user","password"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("database",$con); $sqlquery="SELECT * FROM `application` Order By Name"; $result=mysql_query($sqlquery,$con); while($row=mysql_fetch_array($result)) { echo "<option value='".$row['ID']."'>".$row['Name']." (".$row['Status'].")</option>"; } ?> </select> <br> <label>Status:</label> <select name="Status"> <option value="PENDING">PENDING</option> <option value="ACCEPTED">ACCEPTED</option> <option value="DENIED">DENIED</option> <br> <input type="submit" value="submit" /> </form> change_app_complete.php Code: [Select] <?php $status=$_POST['Status']; $con = mysql_connect("host","user","password"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("database",$con); $sql="UPDATE application SET Status = '$status' WHERE Name= '$member'"; if(mysql_query($sql,$con)) { echo 'Status Changed.<br /><a href="../applications.php">Return To Members List</a>'; } else { die('Could not submit: ' . mysql_error()); } mysql_close($con); ?> What is wrong? |
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