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PHP - Simple Coding Problem With "echo"
Hi all - I am a novice when it comes to PHP, but I have managed to use it successfully many times. I have an issue where I can not get a variable to echo when I am calling it from within a file that is using SSI. Here is a basic example that should explain it better.
In the /index.php file: Code: [Select] <?php $photo1="photo1.jpg"; $photo2="photo2.jpg"; ?> <?php include('http://www.DOMAIN.com/includes/header.php'); ?> In the /header.php file: <img src="http://www.DOMAIN.com/photos/<?php echo $photo1; ?>"> When I try to echo $photo1 from within the /header.php file it simply does nothing, even though the variable is declared before the call for the include file. If I try to do the echo with the IMG tag from within the /index.php file, it works no problem -but that wont work without a MAJOR site redesign with how things are configured. Question is, why does this not work, and how can I fix it? Huge thanks from this Newb! Similar Tutorialshello, I was wondering what is the point of writing for a dropdown: <?php if ($_POST[inputfieldID] == "value") { echo "selected"; } ?> or for a checkbox/ radio button: <?php if ($_POST['cb/radioID'] == "value") { echo "checked"; } ?> I guess it's for after submit, if there is any error, the values filled will still be echoed in the inputfield, or am i wrong? But then if that is true, i have a php search box where i use AJAX object to to send all the input they filled in after submit. But after pushing submit the inputted values remain. I guess when using AJAX to send the information i don't need <?php if ($_POST[inputfieldID] == "value") { echo "selected"; } ?> in my html forms? Little confused Can maybe somebody bring clearness Can someone please help me with an array problem i can not figure out. I need the array to be numbered from 1 to how ever many fields that are needed in the form and have a mysql field name and the title of the field also in the array. 1, "mysql_field_name", "Title of form field" 2, "", "" and so on then the form will be shown based on the array. I have the following draft code which I am working with. any suggestions on how i may do this array ? Code: [Select] <?php $options = array( '1'=> array('fieldtext'=>'option1', 'mysqlfield'=>'option1'), '2'=> array('fieldtext'=>'option2', 'mysqlfield'=>'option2'), '3'=> array('fieldtext'=>'option3', 'mysqlfield'=>'option3'), '4'=> array('fieldtext'=>'option4', 'mysqlfield'=>'option4'), ); // $options = array(1 => "option1", "option2", "option3", "option4"); // the line above works but i want to include the name of the mysql field as well. $userid = 1; ?> <div style="align: center; margin: 12px; font-family:Tahoma;"> <br><br><?php if ($_POST['Update'] != "Update") { // check if form submitted yet, if not get data from mysql. $res = db_query("SELECT * FROM `users` WHERE `userid` = '" . $userid . "'"); foreach($options as $key => $value) { $_POST[$key] = mysql_result($res, 0, $value); } $ok_to_update = "no"; } elseif ($_POST['Update'] == "Update") { // check if form submitted yet, if so get POST data. // error checking // foreach($options as $key => $value) { // $_POST[$i] = ""; // } $ok_to_update = "yes"; } if ($_POST['Update'] == "Update" && $ok_to_update == "yes") { // $res = db_query("INSERT INTO `users` () VALUES ()"); // add user details to database. ?><p><br><br><br>Thank you for updating</p><?php } else { ?><form name="form1" method="post" action=""> <?php foreach($options as $key => $value) { ?><p><?php echo($value); ?>: <input type="text" name="<?php echo($key); ?>" value="<?php echo($_POST[$key]);?>"></p> <?php } ?> <input name="Update" type="submit" value="Update"> </form> <?php } ?> </div> Hi, I currently have an if, elseif, else program that starts off with Code: [Select] if( $v_name == "" || $v_msg == "" ) echo "something" how do I turn this into a switch? but the very next elseif I have Code: [Select] elseif( strcspn( $_REQUEST['msg'], '0123456789' ) == strlen( $_REQUEST['msg'] ) ) echo "something" is it possible to turn this into a switch with 2 different strings like that to evaluate? How can i make echo "<b>Site:</b> ".$req_user_info['site']."<br>"; linkable The site raw fron the db contains an site url. Regards I have a registration form on my website and after Registration I want the user to activate first his account. I don't have problem on sending this email to the user. What I want to appear is like this.. GoodDay "username", Blah Blah! how can you actually do that? I know that you can do that through session variables but the thing is email's can't accept scripts on sending emails. how can I get the value from a session variable for example and convert it to plain html text so that i can OUTPUT it to the email.. HELP PLEASE! Hi, bit stuck on how to find and replace "<" and ">" with "<" and ">". I basically have a database record that outputs to screen and I need the code in the <code> tags to be rendered to the screen. I therefore need it to go through the whole array variable from the db and change the symbols just inside the code tags. Please be aware that the code tags might happen more than once here's an example below Code: [Select] <p>blah blah blah</p> <p>blah blah blah</p> <p>blah blah blah</p> <code> <h1>hello</h1> </code> <p>blah blah blah</p> <p>blah blah blah</p> <p>blah blah blah</p> <code> <h1>hello</h1> </code> the desired output would be: <p>blah blah blah</p> <p>blah blah blah</p> <p>blah blah blah</p> <code> <h1>hello</h1 </code> <p>blah blah blah</p> <p>blah blah blah</p> <p>blah blah blah</p> <code> <h1>hello</h1 </code> help on this would be great Cheers Rob Hi guys I am a newbie with PHP and I have been trying to solve this problem for 3 days.. Ive set up a booking form on my website to be sent directly to my email once the client clicked on the send button.. The problem I am having while checking these pages on wamp is that the booking form is ok but when I click on the send button the following message error appears "Warning: mail() [function.mail]: Failed to connect to mailserver at "localhost" port 25, verify your "SMTP" and "smtp_port" setting in php.ini or use ini_set() in C:\wamp\www\fluffy_paws\booking_form2.php on line 27" When I check online I have this message "500 - Internal server error. There is a problem with the resource you are looking for, and it cannot be displayed." Are my codes wrong??? My webhosting is Blacknight.com , Im on Windows Vista, my internet is a dongle with O2 ireland Thanks for your help! Hello I have a from that updates a few things in the db, and uses "<?php echo $PHP_SELF;?>". The form does update everything fine, however that page does not reflect it. If I refresh the page manually I can see the new values. Is this a common thing, and can anything be done to fix this? Hi guys I'm struggling a bit, I need to replace a word that occurs multiple times in text with an array("up","down","forward","backwards") of words. $find = "left"; $replace = array("up","down","forward","backwards"); $text = "left left left left"; echo str_replace($find,$replace,$text); The Output is: array array array array Did try this with a foreach statement as well, but no luck. Is there a better way of doing this? Thanks Good evening -- My script takes a while to execute as it processes records from the db. I'd like to have it print out to the screen the record id # as it processess each record, just to let me know where it is. Currently, the program waits till the end and then prints out the record numbers, which is no help. How can I enable PHP to print out each record number as it goes along? Thanks! Hello, all... I seem to remember, like if I have a problem with a mysql_query() statement, and want find out why it keeps giving me an error, I'm often told to echo out the statement for debugging purposes. Can somebody remind me again how that's done... thanks! cant work out this mysql syntax error "operation":"medupdate","medid":"","name":"ibo","medyear":"5","medmonth":"21","medday":"1","recuser":1,"SuccFail":"fail","SuccFailMessage":"error occured You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '''WHERE med_id=' at line 2","ResultData":""} Code: [Select] $sql="update metodology set med_description='".$req['name']."', med_year='".$req['medyear']."', med_month='".$req['medmonth']."', med_day='".$req['medday']."', med_recorddate= now(), med_recorduserid= 1'"; $sql.= " WHERE med_id=".$req['medid']; I have written code so that when something from a MySQL field equals 0, then PHP will take no action, and if the field equals anything else, then 'echo "foo"'. The problem I am having is that when PHP echo's nothing (echo ""), its still creating the effect of a HTML <BR>. Screen shots: 1. When the MySQL table contains something else than 0 (echo "foo"). http://i51.tinypic.com/2n7oxo1.png 2. When the table contains 0 (echo ""). http://i53.tinypic.com/2h5jg4k.png 3. What it should look like if the table were to contain 0 (echo ""). Note that their is no <BR> effect. http://i51.tinypic.com/2jdtaf.png Code: $query = "select sizes from products where id='$id'"; $result = mysql_query($query); $data = mysql_fetch_array($result); if ($data['sizes'] == 0) {echo "";} else {echo "Small - ".$data['sizes'];} Is it possible to make it so if a MySQL field result equals 0, then PHP will not produce the HTML <BR> effect when it echo's nothing (echo "")? I am running through a tutorial and I am getting an error based on a the concatication operator on my output. Below is my code. As you can see I am echoing $display_block .= "<p>$title<br>$rec_label<br>.... If I send this as-is I get this error: Notice: Undefined variable: display_block in C:\wamp\www\php\php_mysql\sel_byid.php on line 36 I can resolve the error by placing this before the while loop: $display_block = ""; Is there a better way to output the concatenation.= so I don't need to do this weird fix? while ($row = mysql_fetch_array($result)) { $id = $row['id']; $format = $row['format']; $title = stripslashes($row['title']); $artist_fn = stripslashes($row['artist_fn']); $artist_ln = stripslashes($row['artist_ln']); $rec_label = stripslashes($row['rec_label']); $my_notes = stripslashes($row['my_notes']); $date_acq = $row['date_acq']; if ($artist_fn != "") { $artist_fullname = trim("$artist_fn $artist_ln"); } else { $artist_fullname = trim("$artist_ln"); } if ($date_acq == "0000-00-00") { $date_acq = "[unknown]"; } $display_block .= "<p>$title<br>$rec_label<br>$artist_fullname<br>$my_notes<br>$date_acq<br>$format</p>"; I am getting the following error when using composer: "continue" targeting switch is equivalent to "break". Did you mean to use "continue 2"? Just started. I am pretty sure composer.json wasn't changed. journalctl doesn't show anything. Maybe Doctrine related, however, nothing seems to help.
Any ideas? [michael@devserver www]$ php -v PHP 7.3.4 (cli) (built: Apr 2 2019 13:48:50) ( NTS ) Copyright (c) 1997-2018 The PHP Group Zend Engine v3.3.4, Copyright (c) 1998-2018 Zend Technologies with DBG v9.1.9, (C) 2000,2018, by Dmitri Dmitrienko [michael@devserver www]$ composer -V Composer version 1.4.2 2017-05-17 08:17:52 [michael@devserver www]$ yum info composer Loaded plugins: fastestmirror Loading mirror speeds from cached hostfile * base: mirror.us.oneandone.net * epel: mirror.rnet.missouri.edu * extras: mirror.us.oneandone.net * remi-php73: mirror.bebout.net * remi-safe: mirror.bebout.net * updates: mirror.us.oneandone.net Installed Packages Name : composer Arch : noarch Version : 1.8.4 Release : 1.el7 Size : 1.8 M Repo : installed From repo : epel Summary : Dependency Manager for PHP URL : https://getcomposer.org/ License : MIT Description : Composer helps you declare, manage and install dependencies of PHP projects, : ensuring you have the right stack everywhere. : : Documentation: https://getcomposer.org/doc/ [michael@devserver www]$ composer update Loading composer repositories with package information Updating dependencies (including require-dev) [ErrorException] "continue" targeting switch is equivalent to "break". Did you mean to use "continue 2"? update [--prefer-source] [--prefer-dist] [--dry-run] [--dev] [--no-dev] [--lock] [--no-custom-installers] [--no-autoloader] [--no-scripts] [--no-progress] [--no-suggest] [--with-dependencies] [-v|vv|vvv|--verbose] [-o|--optimize-autoloader] [-a|--classmap-authoritative] [--apcu-autoloader] [--ignore-platform-reqs] [--prefer-stable] [--prefer-lowest] [-i|--interactive] [--root-reqs] [--] [<packages>]... [michael@devserver www]$
This topic has been moved to Linux. http://www.phpfreaks.com/forums/index.php?topic=318175.0 I have a simple form to add details to the database. I want to use the same form layout to call back details for editting and updating. The main page is showroomedit.php which lists (in an array) the records in the database. I have added an edit.php but cant seem to work the code out. Can some one point me in the right direction. here is edit.php: <?PHP include('dbconnect.php') ?> <HTML> <HEAD> <TITLE>Barry Ottley Motor Co - Quality Used Motors - Stanford-Le-Hope, Essex</TITLE> </HEAD> <BODY LINK="#000000" ALINK="#000000" VLINK="#000000"> <CENTER><IMG SRC="logo.jpg"></CENTER> <CENTER> <TABLE WIDTH="840" CELLPADDING="0" CELLSPACING="0" BORDER="0"> <TR> <TD WIDTH="186" valign="top"> <BR> <CENTER><A HREF="index.html"><IMG SRC="homepage.jpg" alt="Homepage" border="0"></A></CENTER> <CENTER><A HREF="showroom.php"><IMG SRC="showroom.jpg" alt="Our Online Showroom" border="0"></A></CENTER> <CENTER><A HREF="location.html"><IMG SRC="ourlocation.jpg" alt="Our location" border="0"></A></CENTER> <CENTER><A HREF="aboutus.html"><IMG SRC="aboutus.jpg" alt="About Us" border="0"></A></CENTER> <CENTER><A HREF="contactus.php"><IMG SRC="contactus.jpg" alt="Contact Us" border="0"></A></CENTER> </TD> <TD WIDTH="30" valign="top"> </TD> <TD valign="top"> <FONT SIZE="2" FACE="ARIAL"> <CENTER><A HREF="addcar.html"><IMG SRC="vehicleadd.jpg" border="0"></A><A HREF="showroomconfig.php"><IMG SRC="vehicleedit.jpg" border="0"></A><A HREF="showroomconfig.php"><IMG SRC="vehicledelete.jpg" border="0"></A></CENTER> <CENTER><B>Update a Vehicle</B></CENTER> <BR> <?php $query1="SELECT cars FROM CarName='$carname', CarTitle='$CarTitle', CarPrice='$carprice', CarMiles='$carmiles', CarDescription='$cardesc'"; mysql_query($query1); mysql_close(); ?> <form action="editvehicle.php" method="post"> <CENTER>Vehicle Name:</CENTER> <CENTER><input type="text" name="CarName" value="<?php echo $carname; ?>"></CENTER> <br> <CENTER>Vehicle Type:</CENTER> <CENTER><input type="text" name="CarTitle" value="<?php echo $cartitle; ?>"></CENTER> <br> <CENTER>Vehicle Price:</CENTER> <CENTER><input type="text" name="CarPrice" value="<?php echo $carprice; ?>"></CENTER> <br> <CENTER>Vehicle Mileage:</CENTER> <CENTER><input type="text" name="CarMiles" value="<?php echo $carprice; ?>"></CENTER> <br> <CENTER>Vehicle Description:</CENTER> <CENTER><textarea name="CarDescription" rows="10" cols="30" value="<?php echo $cardesc; ?>"></textarea></CENTER> <br> <CENTER><input type="Submit"></CENTER> </form> </TD> </TR> </TABLE> <BR><BR><BR><BR> <CENTER><FONT FACE="VERDANA" SIZE="1"> This website was designed and is hosted by <A HREF="http://www.IRCDirect.co.uk">IRC Direct Website Design™</A> 2010 </CENTER> <BR> <CENTER><A HREF="admin.php">Employee Area</A> </BODY> </HTML> That is not even showing me the table details at all. Im lost . There is an "Update" link in each array in showroom.php in which when the user clicks it opens edit.php . They update the form as they wish... then click update and it updates the database and sends them back to showroomedit.php Much help would be appreciated ! Cheers paul if your out there still Hello I code by hand (HTML & CF -14 years now), and some of my customers want the ability to do updates to their sites themselves using Adobe Contribute, and I can build any app they need that Contribute can't handle in CF if they host on my server - however, in this particular case, the site is hosted by GoDaddy which is no longer supporting CF. The site is PHP-enabled, and the client was using WordPress to update his entire site. Because of the blogging-centric features of Wordpress, a user can enter a "headline" then an associated story (commentary) - publish, and the headline ends up on one page linked to the page where the headline and story live. So, I need a simple form handler written in PHP that allows the client to enter his "headline" (which is a hard-coded link to the "rest of the story" page), the headline showing up above the story content (using a second form field) - not necessarily targeting <a href="#end-up-here"> - just simply land on the page where the content gets dynamically displayed. Thanks in advance for your patience and be kind---- I have never written a line of PHP- just thousands of lines of CF..... Norman I have a field in my database called `intro` In this field the user has entered spaces, different paragraphs and "" When it was entered into the field it was run through trim and mysql_real_escape_string. when its echoed I am just using echo "member['intro']; How do I make it display like it was entered? Is there a function for this? Hello, I am guessing that this is a totally noob question and I am sorry about it. I am not someone who is familiar with php. I just can see what code says sometimes. I have a wordpress file which I wanted to edit. I was successful until I hit this line of code. <?php echo "\n" . installedtheme::frontSections( ); ?> This code is responsible for entire front page structure. When I delete this line my front page gets empty. In html side I can see </section> parts which I want to exclude but select what to exclude from code. I am guessing this echo calling a file that is told as front sections. I am lost. Is there any way to find and edit this file?
Thanks for help. |
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