PHP - Php Array Link To Page
Hello all,
I am working on a webpage which needs to be finished Friday so I am a bit stressing out, hence this post. I have made the following script: // Uitkomst van POST waardes echo"<pre>"; print_r($_POST); echo"</pre>"; // LET OP: De tabel "test_optie" is niet compleet gevuld en daarom werkt het script alleen als je start bij categorie 1. // Het is dus GEEN fout in de script, alleen de database is niet helemaal gevuld kostte me teveel tijd! echo" <html> <head> <style> select {float:left;width:250px;margin:0 5px 0 0;} </style> </head> <body> <form name='form' action='chainselect.php' method='post' /> <select name='veld1' onChange='document.form.submit()'> "; // Data opvragen $sql_categorie = mysql_query("SELECT * FROM plaatsnaam ORDER BY id") or die (mysql_error()); // Counter $a = 0; // Standaard geselecteerd echo"<option value='0' selected>Selecteer een plaats</option>"; while($row_categorie = mysql_fetch_array($sql_categorie)){ $a++; echo"<option value='$row_categorie[id]' ";if($_POST[veld1] == "$a"){echo"selected";}echo">$row_categorie[naam]</option>"; } echo" </select> <select name='veld2' onChange='document.form.submit()'> "; // Data opvragen $sql_rubriek = mysql_query("SELECT * FROM branche WHERE catid = '$_POST[veld1]'") or die (mysql_error()); $ant_rubriek = mysql_num_rows($sql_rubriek); // Huidige id veld2 om zodoende huidig veld te selecteren indien gewijzigd if(isset($_POST[veld2])){ $b = "$_POST[veld2]"; } // Als er geen data gevonden is dan de onderstaande option laten tonen. if($ant_rubriek <= 0){ echo"<option value='0'>-</option>"; } else{ // Standaard geselecteerd echo"<option value='0' selected>Selecteer een branche</option>"; while($row_rubriek = mysql_fetch_array($sql_rubriek)){ echo"<option value='$row_rubriek[id]' ";if($_POST[veld2] == "$row_rubriek[id]"){echo"selected";}echo">$row_rubriek[naam]</option>"; } } echo" </select> <select name='veld3' onChange='document.form.submit()'> "; // Data opvragen $sql_optie = mysql_query("SELECT * FROM filiaal WHERE catid = '$_POST[veld1]' AND rubid = '$_POST[veld2]'") or die (mysql_error()); $ant_optie = mysql_num_rows($sql_optie); // Huidige id veld3 om zodoende huidig veld te selecteren indien gewijzigd if(isset($_POST[veld3])){ $c = "$_POST[veld3]"; } // Als er geen data gevonden is dan de onderstaande option laten tonen. if($ant_optie <= 0){ echo"<option value='0'>-</option>"; } else{ // Standaard geselecteerd echo"<option value='0' selected>Selecteer een filiaal</option>"; while($row_optie = mysql_fetch_array($sql_optie)){ echo"<option value='$row_optie[id]' ";if($_POST[veld3] == "$row_optie[id]"){echo"selected";}echo">$row_optie[naam]</option>"; } } echo" </select> </form> </body> </html> "; ?> What I need now is the results shown linked to a page. U can see the dropdowns in action he www.inventar.nl/chainselect.php For example: In the first dropdown I select Groningen, in the 2nd drop I select Groningen, Restaurant and in the 3rd Groningen, Restaurant, Ni Hao Wok. This gives me the following: Quote Array ( [veld1] => 1 [veld2] => 2 [veld3] => 3 ) Now I have a page named nihao.php, this page needs to be linked to this array result. So if I do the above dropdowns it needs to open nihao.php Can anyone help me with this problem? I am really confused! Thanks in advance! Wheelie Similar TutorialsHello.
I have a bit of a problem. When I fetch the link field from the database.i don't see an actual link on the page.
One more thing, what type of field should I use to store the link in the database? Probably there is where I went wrong.
All help is
Hi, Is it possible to build a PHP Template page that selects and publishes a row of data from a MySQL Database when a linked is clicked? I would design: Template.php Text links (perhaps on homepage of navigation bar): ProductA, ProductB and ProductC If you click link ProductA Template.php would display data for ProductA and likewise for ProductB and ProductC. I would also like search engines for find ProductA, ProductB and ProductC PHP pages. (Not just my single Template.php) Any ideas as to how this could be done without designing individual PHP pages for each product? Kind regards, Matthew. Hey i'm having trouble figuring out how to do this. This is the code grabbing the users who are online and listing them one by one. Code: [Select] $qt=mysql_query("SELECT username FROM users WHERE lastvisit > '$tm' and online='ON'"); echo mysql_error(); while($nt=mysql_fetch_array($qt)){ echo "<tr><td> $nt[username] </td></tr>"; } ?> what i want to do is have each username be a hyperlink that links to their profile how would i go about this? cause i'm completely clueless on this. is there some way i can do it in the php or will i need to make a varchar column for each player that holds their profile link and grab that with the query too? Greetings all. I am building a website which will have a popup box. When a link is clicked on, the proper data will show in the box. I just need to know how I can detect which link was clicked. e.g. <a href="#">link one</a> <a href="#">link two</a> $a[1]="item1 | item2 | item3" $a[2]="item4 | item5 | item6" list($one, $two, $three)=explode("|",$a ) Where x is dependent on the link clicked. All the sites I have seen so far speak of basic array structures and how to set them up. If it makes any difference, the links are inside an unordered list setup. Thanks for any help. Can someone help me debug this code...this is a search page where it searches the keyword typed in the mysql db and it limits 10 results per page...and at the bottom if there are more than 10 results it says next 10 and its a link but when it is clicked it goes to the code and says please type a search, here is the code can someone please help me with this I would really appreciate it. Code: [Select] <?php $page = $PHP_SELF; // Get the search variable from URL $var = @$_GET['search'] ; $searchtype = @$_GET['searchtype']; $isbn = "ISBN"; $school = "School"; $title = "Title"; $subject = "Subject"; $trimmed = trim($var); //trim whitespace from the stored variable // rows to return $limit=10; // check for an empty string and display a message. if ($trimmed == "") { echo "<p>Please enter a search...</p>"; exit; } // check for a search parameter if (!isset($var)) { echo "<p>We dont seem to have a search parameter!</p>"; exit; } //connect to your database $connect = mysql_connect("","]",]") or die("Not connected"); //specify database mysql_select_db("collegebooxboox") or die("could not log in"); if ($searchtype == ($title)) { // Build SQL Query $query = "select * from boox where name like \"%$trimmed%\" order by name"; // EDIT HERE and specify your table and field names for the SQL query } elseif ($searchtype == ($school)) { // Build SQL Query $query = "select * from boox where school like \"%$trimmed%\" order by school"; // EDIT HERE and specify your table and field names for the SQL query } elseif ($searchtype == ($isbn)) { // Build SQL Query $query = "select * from boox where isbn like \"%$trimmed%\" order by isbn"; // EDIT HERE and specify your table and field names for the SQL query echo "isbn"; } elseif ($searchtype == ($subject)) { // Build SQL Query $query = "select * from boox where subject like \"%$trimmed%\" order by subject"; // EDIT HERE and specify your table and field names for the SQL query } $numresults=mysql_query($query); $numrows=mysql_num_rows($numresults); // If we have no results, offer a google search as an alternative if ($numrows == 0) { echo "<h4>Results</h4>"; echo "<p>Sorry, your search: "" . $trimmed . "" returned zero results</p>"; echo "<p><a href=\"http://www.google.com/search?q=" . $trimmed . "\" target=\"_blank\" title=\"Look up " . $trimmed . " on Google\">Click here</a> to try the search on google</p>"; } // next determine if s has been passed to script, if not use 0 if (empty($s)) { $s=0; } // get results $query .= " limit $s,$limit"; $result = mysql_query($query) or die("Couldn't execute query"); // display what the person searched for echo "<p>You searched for: "" . $var . "" in "" . $searchtype ."" </p>"; // begin to show results set echo "Results "; $count = 1 + $s ; if ($searchtype = $title) { // now you can display the results returned while ($row= mysql_fetch_array($result)) { $title = $row["name"]; echo "$count. $title   </br><table width='297' border='1' align='center'> <tr> <td width='152'>Book Title:</td> <td width='129'>$row[name]</td> </tr> <tr> <td>Author:</td> <td>$row[author]</td> </tr> <tr> <td>ISBN#</td> <td>$row[isbn]</td> </tr> <tr> <td>Date Posted:</td> <td>$row[date]</td> </tr> <tr> <td>Posted By:</td> <td><a href='backpack.php' onclick='document['packback'].submit()'>$row[username]</a></td> </tr> <tr> <td>School:</td> <td>$row[school]</td> </tr> </table></br>"; $count++ ; } } elseif ($searchtype = $school) { // now you can display the results returned while ($row= mysql_fetch_array($result)) { $title = $row["school"]; echo "$count. $title" ; $count++ ; } } elseif ($searchtype = $subject) { // now you can display the results returned while ($row= mysql_fetch_array($result)) { $title = $row["subject"]; echo "$count. $title" ; $count++ ; } } elseif ($searchtype = $isbn) { // now you can display the results returned while ($row= mysql_fetch_array($result)) { $title = $row["isbn"]; echo "$count. $title" ; $count++ ; } } $currPage = (($s/$limit) + 1); //break before paging echo "<br />"; // next we need to do the links to other results if ($s>=1) { // bypass PREV link if s is 0 $prevs=($s-$limit); print " <a href=\"$PHP_SELF?s=$prevs&q=$var\"><< Prev 10</a>  "; } // calculate number of pages needing links $pages=intval($numrows/$limit); // $pages now contains int of pages needed unless there is a remainder from division if ($numrows%$limit) { // has remainder so add one page $pages++; } // check to see if last page if (!((($s+$limit)/$limit)==$pages) && $pages!=1) { // not last page so give NEXT link $news=$s+$limit; echo " <a href=\"$PHP_SELF?s=$news&q=$var\">Next 10 >></a>"; } $a = $s + ($limit) ; if ($a > $numrows) { $a = $numrows ; } $b = $s + 1 ; echo "<p>Showing results $b to $a of $numrows</p>"; ?> ok so now all my logo link goes to the same page..i dont know how to fix it.i want all of them connect to a link(each of the company has their own company_link id) which i named company_link which is already in the database..so i need to call it.there are about 20 total logos.. except for the $company id=33..just remain that one.. Code: [Select] <? if(isset($_GET[ttid])) { $ttid = $_GET[ttid]; } $connection=mysql_connect("$server", "$username", "$password") or die("Could not establish connection"); mysql_select_db($database_name, $connection) or die ("Could not select database"); $query = "select master_event.* , (DATE_FORMAT(event_datefrom, '%d %M %Y')) as datefrom, (DATE_FORMAT(event_dateto, '%d %M %Y')) as dateto, ucase(event_name) as eventname from master_event where master_event.event_id = '$ttid '"; $result=mysql_query($query); while($row = mysql_fetch_array($result)){ $eventname = $row['eventname']; $eventdesc = $row['event_desc']; $companydescription = $row['company_description']; $eventvenue = $row['event_venue']; $eventfee = $row['event_fee']; $datefrom = $row['datefrom']; $dateto = $row['dateto']; echo "<font color='#000000' face='arial' ><b> $eventname </b> </font> <br>"; echo "<font color='#000000' face='arial' ><i>Date</i> : $datefrom - $dateto <br>"; echo "<i>Venue</i> : $eventvenue <br>"; $querypstype = "SELECT DISTINCT master_pstype.pstype_id, pstype_desc FROM master_pstype INNER JOIN master_psevent ON master_psevent.pstype_id= master_pstype.pstype_id where master_psevent.event_id = '$ttid' ORDER BY pstype_id"; $resultpstype=mysql_query($querypstype); while($rowpstype = mysql_fetch_array($resultpstype)){ $pstypeid = $rowpstype['pstype_id']; $pstypedesc = $rowpstype['pstype_desc']; echo "<br><font color='#8B3A3A' size='1' face='georgia' ><b><i>$pstypedesc</i></b></font> <br>"; $queryps = "SELECT master_psevent.*, pstype_desc, company_name, company_link, company_description, logo_filename FROM master_psevent LEFT JOIN master_pstype ON master_psevent.pstype_id = master_pstype.pstype_id LEFT JOIN master_ps ON master_ps.ps_id = master_psevent.ps_id WHERE master_psevent.event_id = '$ttid' and master_pstype.pstype_id= '$pstypeid' ORDER BY pstype_desc,company_name "; $resultps=mysql_query($queryps); while($rowps = mysql_fetch_array($resultps)){ $companyname = $rowps['company_name']; $companyid = $rowps['ps_id']; $companylinkori = $rowps['company_link']; $companydescription = $rowps['company_description']; if ($companyid==33){ $companylink = "http://(confidential)/index.php?view=describe"; } else { if ($companylinkori <> "") { //$companylink = "http://".$rowps['company_link']; $companylink = "http://(confidential)/index.php?view=".$companyid; } else { $companylink = ""; } } $logopath = $rowps['logo_filename']; if ($companylink <> ""){ echo "<font color='#4A708B' face='arial' ><a href=$companylink style=\"color:white;text-decoration: none; \" target='new'><img src=".$logo_dir."/".$logopath." width=\"15%\"></img></a>  </font>"; } else { echo "<font color='#4A708B' face='arial' ><img src=".$logo_dir."/".$logopath." width=\"15%\"></img>  </font>"; } ?> <br> <? } echo "<br>"; } } ?> Hello. Say i want to view another user profile. I click on user name and i see the profile page. So how can i link user name to his profile? I have tried linking it to $id (this is where user id is stored in the database), but no luck. Thank you. hi there alll newbie here lol just needed help with the code for the next page of results ? IE i have say 30 results returned from a sql query but only want to show ten at a time i no how to limit the result with the LIMIT 10 but how do i get it to put link show the other ten and so on. the code i have is here at the bottom of page http://www.phpfreaks.com/forums/index.php/topic,307971.0.html thanks in advance for any help kaine Hello i kinda new to programing mostly learning myself stuf there so i need some help to figure out. so i have lets say static link who always same and i write something in input field and press search button. so i get new link and immediately going to dat link, which means i leaving my site. in my case i working with image so my problem, is it somehow possible to display image in same page while writing someting in input field when presing button and image just change down below not going directly to link ? P.S. sory for my english
i have this code
<html> <body>
<center>
<form action="#" method="POST">
</form>
<?php require_once 'linkgenerator.php' ?>
PHP link generator code
<?php
Edited March 18, 2020 by eagle101 Hi, I know it is probely not a regex question but I don't know the right category. I have 2 variables like $variable1 and $ variable2 which are placed in a loop now I want the $variable to be echo't in a link like <a href="http://exampe.com/$variable1"/> On this dynamicly generated page I want to output the $varible1 of this link and $variable2 while($row = mysql_fetch_assoc($result)) { echo " <tr>"; echo " <td>" . $row["variable1"] . "</td>"; echo " <td>" . $row["variable2"] . "</td>"; echo " </tr>"; I have an 'I agree' button on this page https://www.setstuffrentals.com/credit-card-authorization/
I basically need the button to redirect to another web page after a customer hits 'I agree'. I don't know PHP much. Can someone help step by step, please? Every other time a user/users click on a link I want the link to change to a different url the next time a user clicks onto that link.
For example two links
url1.html
url2.html
url1.html shows up when a user clicks that link the link auto changes to then when a new user clicks the linke url2.html then back to url1.html and so on?
Don't know where to start on how I would do this let alone have the server remember to keep which ever link to be held for the next user?
I have a site, and there is an image with a link to another page, how can I make it so this is the only way to get to that page is by clicking on that image, and not by typing www.mywebsite.com/page.php into the address bar in a browser? Instead of breaking down and actually learning how to use ajax, I'm thinking about trying to do something so I don't need a page refresh every time, and the filtered data is nearly instant. I just use the session array var, and build a new array from the rows that meet the conditions. I'm thinking of loading a two dimensional array into a session var, then use some input buttons, and use the post vars to filter the array based on a set of predefined conditions. ie status = 0, status = 1. It's a fairly small number of conditions applied to two different fields. So, I need to access specific fields within a row, and essentially create a new array either including or excluding that row depending on whether it met the condition. I'm struggling on several parts. 1. not sure how to build the array so that I can access specific fields, then not sure how to access those fields. Do I do this..... to build the array? .... Code: [Select] while($row = mysql_fetch_assoc($result)){ $array[] = array($row['field1'], $row['field2']); } I was thinking about using a foreach and is_array() to get to each row... Code: [Select] foreach($array as $key => $value){ if(is_array){ foreach($value as $k => $v){ if($v[0] == 1){ //stuck here $v[0] is not a field, it's the first char of the string. not sure how to access a field $new_array[] = $value; //stuck here. I need to put the whole row back into the array if the condition was true. seems like I would have to use the field selectors and rebuild the array. } } } } What would you do? Open to any ideas. Hi people, I've been having trouble with this for a while now. Basically, i have this website: http://el07jpg.info . You can log in with username:doctor1 password:password1 Once you've logged on, u can click on "Patients". Then, if you click on a patient, it shows their info. Then at the bottom, I have links to glucose readings and heart rate readings... but when I click on either of those links, it goes back to the main page, showing all the patients.. The weird thing is that I got this to work for the first step, u click on the <a href> link of a patient, and it brings you to their page. Then I've done the EXACT same thing to link to the glucose or heart rate readings of that specific patient, but it doesn't work. I really can't see what i've done wrong. Although I noticed in the address bar, when I click on glucose readings for example, the url is http://el07jpg.info/index.php?op=patients&id=&reading=glucose (id should be equal to a number, like id=4, but there's no number... Any help would be much appreciated! Cheers! Code for op_patients.php page: <?php //Page if a set of records is selected from a single patient's page if ($_REQUEST[reading]+0) { $GLOBALS['html']['css'][]="default.css"; $reading_source=$_REQUEST[reading]+0; $sql="select * from {$reading_source}_readings where patientRFID='{$patient[patientRFID]}' "; $results=mysql_select_assoc($sql); if (!$results){ $GLOBALS[err][]="No records exist!"; exit; } $GLOBALS['html']['title']="Patient: {$patient[first_name]} {$patient[last_name]}'s {$reading_source} readings "; echo $reading_source; } //Page if a single patient is selected if ($_REQUEST[id]+0) { $GLOBALS['html']['css'][]="default.css"; $id=$_REQUEST[id]+0; $sql="select * from patients where doctorID='{$_SESSION[user][id]}' and patientID='$id' "; $patient=mysql_select_assoc($sql); if (!$patient){ $GLOBALS[err][]="The patient can't be found!"; exit; } $GLOBALS['html']['title']="Patient: {$patient[last_name]}, {$patient[first_name]} "; $output.=" <br> <table border='1' cellpadding='5' cellspacing='5' width='600'> <tr><td rowspan=6><img src=\"$patient[photo]\"> </td> <th>Name: </th><td>{$patient[first_name]} {$patient[last_name]} </td></tr> <tr><th>D.O.B: </th><td>{$patient[dob]} </td></tr> <tr><th>Email: </th><td>{$patient[email]} </td></tr> <tr><th>Phone Number: </th><td>{$patient[phone_no]}</td></tr> <tr><th>Address: </th><td>{$patient[address]}</td></tr> <tr><th><br> Comments:<br> </th> <td>{$patient[comments]} </td></tr> </table> <table border='1' cellpadding='5' cellspacing='5' width='600'> <tr><th colspan=3><br>Medical Readings<br><br></th></tr> <tr> <td align='center' width='300'> <a href='index.php?op=patients&id={$v[patientID]}&reading=glucose'>Glucose Readings</a> </td> <td colspan=2 align='center' width='300'> <a href='index.php?op=patients&id={$v[patientID]}&reading=heart'>Heart Rate Readings</a> </td> </tr> </table> "; echo $output; exit; } //Main Page showing all patients $GLOBALS['html']['title']="Patients"; $GLOBALS['html']['css'][]="default.css"; if(!$_SESSION[user][id]) { $er="Access Denied! Please Log in."; echo "<div style='color:red;'>$er</div>"; } else { $sql="select * from patients where doctorID='{$_SESSION[user][id]}' order by last_name"; $d=mysql_getarray_assoc($sql); $output=''; foreach ($d as $v){ $output.=" <tr><td> <a href='index.php?op=patients&id={$v[patientID]}'>{$v[last_name]}, {$v[first_name]}</a> </td></tr> "; } echo " <table width=80% align=left border='1' cellpadding='5' cellspacing='5' width='100%'> <tr><th class=popupheader align='left'> Patient Name<br><br> </th></tr> $output </table> "; } ?> Hi.. I have an issue on my project.I want to open a particular page of a PDF file by clicking a hyper link.How should I do it?any idea ? I used the following code <?php header("Content-Type: application/pdf"); $pdfFile="readme.pdf#page=10"; ?> <html> <head> <title>Untitled Document</title> </head> <body> <a href="http://<?php echo $pdfFile; ?>">Click Here</a> </body> </html> But it showing an alert like following File does not begin with '%PDF-' After clicking alert showing a black screen.. can u please send me the entire code? Thanks...
Hello everyone, This is the code I need to implement: https://developer.wordpress.org/reference/functions/wp_get_attachment_link/
and this is the file where it has to included: This is my script I want to display but it does not show in the page just blank. <td><object width="220" height="148"><param name="movie" value="http://www.youtube.com/user/THEWORLDOFTRAVEL#p/search/2/uX9nd3xM_MY=1&h1=enUS&color1=0x234900&color3=34900&"></param><param name="allowFullScreen" value="true"></param><param name="allowscriptaccess" value="always"></param><embed src="http://www.youtube.com/user/THEWORLDOFTRAVEL#p/search/2/uX9nd3xM_MY=1&h1=enUS&color1=0x234900&color3=34900&" type="application/x-shockwave-flash" allowscriptaccess="always" allowfullscreen="true" width="220" height="148"></embed></object></td> Ok, I've spent a good part of the day trying to figure out what is going wrong with a client site. I introduced a link within document to send readers from the blogs home page to the comments section of individual posts. It's straight forward right? HTML1, been doing these kind of links for more than ten years. #respond at the end of the normal URL in a normal anchor tag should bring the browser to id="respond" or name="respond" within the document. Right? But, a.) it doesn't. And b.) once it makes a jump everything above that point disappears. Space fills out to the same page height as if it existed but you can't scroll up. You can see it in action at http://www.thebouncingbead.com/blog/ by clicking "Add Your Comment (0)" under the title of any post. Can anyone see what might be causing this problem or experienced something similar before? |