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PHP - Simple Search Form Help
hi iam trying to make a simple search form to search the members tables based on there input. iam new php so most of my code is guess work
Code: [Select] <form method="GET" action="<?php echo $_SERVER['PHP_SELF'];?>" name="searchForm"> <label for="country">Country:</label> <input type="text" name="country" /> <label for="state">State:</label> <input type="text" name="state" /> <label for="city">City:</label> <input type="text" name="city" /> <input type="submit" value="submit" /> </form> <? if ($_GET == array ()) { //Define a variable that will be used to query the members; in this case, it would select all members $query = "SELECT * FROM users"; } else { //If the user typed at least one thing (in the form OR the url) if (count ($_GET) == 1) { //If what they typed is only for one criteria, define a variable that creates a query for only ONE criteria to search for $query = "SELECT * FROM users WHERE 1"; foreach ($_GET as $field => $value) { $query .= " AND $field = '$value'"; } //If the user has typed in more than one field and hits search } else { //Define a variable for a query that selects members based off each criteria $query = "SELECT * FROM users WHERE 1"; foreach ($_GET as $field => $value) { $query .= " AND $field LIKE '%$value%'"; } } while($info = mysql_fetch_array( $data )) { Echo "<img src='http://datenight.netne.net/images/".$info['img'] ."' width='150' height='250''> <br>"; Echo "<b>Name:</b> ".$info['username'] . "<br> <hr>"; Echo "<b>Sex:</b> ".$info['sex'] . " <br><hr>"; Echo "<b>Intrested in</b>" . "<br><hr>"; Echo "".$info['rel'] . " "; Echo "".$info['frwb'] . " "; Echo "".$info['ons'] . " "; Echo "".$info['fr'] . "<br><hr>"; Echo "<b>About me:</b> ".$info['aboutme'] . "<br><hr> "; Echo "<b>Looking for:</b> ".$info['looking'] . " <br><hr>"; Echo "<a href='login_success.php'>'Back'</a>"; } ?> </body> </html> while($info = mysql_fetch_array( $data )) { is not vaild error Similar TutorialsI am currently looking to have two pages, one with a search form (textbox and button) and output the results (from database table) based on the strings input to another page. how do i achieve this? i just want something very simple nothing too complex and advanced please OK, I am new to PHP I am wanting to create a property search using drop down boxes. I have a database with 4 main fields to search: Bedrooms (beds), Area (area), Price Range (price) and Type (type) Here is the code so far, can someone please correct it. Thanks... +++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++ <?php // Get the search variable from URL $var1 = @$_GET['beds'] ; $var2 = @$_GET['area'] ; $var3 = @$_GET['price'] ; $var4 = @$_GET['type'] ; $trimmed = trim($var1, $var2, $var3, $var4); // rows to return $limit=10; // check for an empty string and display a message. if ($var1 == "") { echo "<p>Please enter a search...</p>"; exit; } // check for a search parameter if (!isset($var1)) { echo "<p>We dont seem to have a search parameter!</p>"; exit; } $host = "localhost"; $username = "root"; $password = ""; //connect to your database ** EDIT REQUIRED HERE ** $link = mysql_connect($host, $username, $password) or die("Unable to connect to SQL Server"); //(host, username, password) $db = "property_db"; //specify database ** EDIT REQUIRED HERE ** mysql_select_db($db, $link) or die("Unable to select database"); //select which database we're using // Build SQL Query $results = mysql_query("SELECT * FROM house_src", $link); $numresults = mysql_num_rows($results); // get results $result = mysql_query($results) or die("Couldn't execute query"); // display what the person searched for echo "<p>You searched for: ". $var4 . "property, with ". $var1 . " bedrooms, in the " . $var2 . "area, with a price range of " . $var3 .""; // begin to show results set echo "Results"; $count = 1 + $s ; // now you can display the results returned while ($row= mysql_fetch_array($result)) { $title = $row["1st_field"]; echo "$count.) $title" ; $count++ ; } $currPage = (($s/$limit) + 1); //break before paging echo "<br />"; // next we need to do the links to other results if ($s>=1) { // bypass PREV link if s is 0 $prevs=($s-$limit); print " <a href=\"$PHP_SELF?s=$prevs&q=$var\"><< Prev 10</a>  "; } // calculate number of pages needing links $pages=intval($numrows/$limit); // $pages now contains int of pages needed unless there is a remainder from division if ($numrows%$limit) { // has remainder so add one page $pages++; } // check to see if last page if (!((($s+$limit)/$limit)==$pages) && $pages!=1) { // not last page so give NEXT link $news=$s+$limit; echo " <a href=\"$PHP_SELF?s=$news&q=$var\">Next 10 >></a>"; } $a = $s + ($limit) ; if ($a > $numrows) { $a = $numrows ; } $b = $s + 1 ; echo "<p>Showing results $b to $a of $numrows</p>"; ?> OK, I am new to PHP I am wanting to create a property search using drop down boxes. I have a database with 4 main fields to search: Bedrooms (beds), Area (area), Price Range (price) and Type (type) Here is the code so far, can someone please correct it. Thanks... ****************************** When I run it it says: Warning: trim() expects at most 2 parameters, 4 given in C:\wamp\www\search222.php on line 8 Warning: mysql_query() expects parameter 1 to be string, resource given in C:\wamp\www\search222.php on line 45 Couldn't execute query +++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++ <?php // Get the search variable from URL $var1 = @$_GET['beds'] ; $var2 = @$_GET['area'] ; $var3 = @$_GET['price'] ; $var4 = @$_GET['type'] ; $trimmed = trim($var1, $var2, $var3, $var4); // rows to return $limit=10; // check for an empty string and display a message. if ($var1 == "") { echo "<p>Please enter a search...</p>"; exit; } // check for a search parameter if (!isset($var1)) { echo "<p>We dont seem to have a search parameter!</p>"; exit; } $host = "localhost"; $username = "root"; $password = ""; //connect to your database ** EDIT REQUIRED HERE ** $link = mysql_connect($host, $username, $password) or die("Unable to connect to SQL Server"); //(host, username, password) $db = "property_db"; //specify database ** EDIT REQUIRED HERE ** mysql_select_db($db, $link) or die("Unable to select database"); //select which database we're using // Build SQL Query $results = mysql_query("SELECT * FROM house_src", $link); $numresults = mysql_num_rows($results); // get results $result = mysql_query($results) or die("Couldn't execute query"); // display what the person searched for echo "<p>You searched for: ". $var4 . "property, with ". $var1 . " bedrooms, in the " . $var2 . "area, with a price range of " . $var3 .""; // begin to show results set echo "Results"; $count = 1 + $s ; // now you can display the results returned while ($row= mysql_fetch_array($result)) { $title = $row["1st_field"]; echo "$count.) $title" ; $count++ ; } $currPage = (($s/$limit) + 1); //break before paging echo "<br />"; // next we need to do the links to other results if ($s>=1) { // bypass PREV link if s is 0 $prevs=($s-$limit); print " <a href=\"$PHP_SELF?s=$prevs&q=$var\"><< Prev 10</a>  "; } // calculate number of pages needing links $pages=intval($numrows/$limit); // $pages now contains int of pages needed unless there is a remainder from division if ($numrows%$limit) { // has remainder so add one page $pages++; } // check to see if last page if (!((($s+$limit)/$limit)==$pages) && $pages!=1) { // not last page so give NEXT link $news=$s+$limit; echo " <a href=\"$PHP_SELF?s=$news&q=$var\">Next 10 >></a>"; } $a = $s + ($limit) ; if ($a > $numrows) { $a = $numrows ; } $b = $s + 1 ; echo "<p>Showing results $b to $a of $numrows</p>"; ?> i have enters some data using form which submit data in sql table1 like this, Fields name in table -->> id First name Lastname Date data saved -->> 1 user 1 2011-05-10 2 user 2 2011-05-11 3 user 3 2011-05-12 now i dont want to duplicate date in database let say while inserting data using form, Firstname : ____________ Lasename : ____________ Date : ____________ (i dont want this date to b save if the date alredy exist in database, it should prompt user "Date already exist and to edit click here (this will be the link to that date which is already exist so that we can edit) " ) SAVE i user files , form.php , insert.php(so insert values in database) , so tell me what function should i use to solve my problem.... Hey all, I need your help! So, I am the web designer for a small company, but I use that term loosely as I for the most part am limited to design through Dreamweaver and Muse. I know a decent amount of HTML off the top of mey head, but when it comes to PHP, yikes... My company asked me to make a simple searchable web page based on their price guide/catalog, built into their website. I have MySQL set up within their godaddy. I can use the SQL search functions to get the exact results back that I need, and the SQL cPanel gives me the following code: SELECT * FROM `SMQSQL` WHERE `Scott` = '(Whatever I search for)' ORDER BY `LINEID` ASC This makes sense to me up to here; this is very simple language, However, I have been pulling my hair out for days trying to get a simple search function as an actual PHP *PAGE* going. Basically, I need to set up a PHP form search (not hard) that will go back and log in to my SQL database named SMQ (not too bad yet), perform a search out of a specific column named Scott (getting a little harder, and somewhat lost), take the search results from specific columns (getting harder), and display them in a neat little table (now I'm lost). My SQL database is set up with the following columns: LINEID, Scott, Den, Color, Cond, 70, 70J, 75, 75J, 80, 80J, 85, 85J, 90, 90J, 95, 95J, 98, 98J, 100 Where LINEID is the index. LINEID is set to INT (5 char), the next 4 are TEXT (255 char, item descriptors), and the rest INT (9 char; prices). When the results are displayed, I would like all but the LINEID visible. I have tried and tried and tried playing with my PHP coding but am ready to shoot my computer. Here it is:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
<title>Online Search</title>
</head>
<body>
<h3>Search Online</h3>
<p>You may search by Catalog number. Please use the exact Catalog number or you may receive an error. Please note that if searching for more than a basic item, include the full Catalog number WITHOUT spaces.</p>
<form method="post" action="search.php?go" id="searchform">
<input type="text" name="Scott">
<input type="submit" name="submit" value="Search">
</form>
<?php
if(isset($_POST['submit'])){
if(isset($_GET['go'])){
$Scott=$_POST['Scott'];;
$db=mysql_connect ("localhost", "guestuser", "guestuser") or die ('Error connecting to the database. Error: ' . mysql_error());
$mydb=mysql_select_db("SMQ");
$sql="SELECT Scott, Den, Color, Cond, 70, 70J, 75, 75J, 80, 80J, 85, 85J, 90, 90J, 95, 95J, P98, 98J, 100 FROM SMQ WHERE Scott LIKE '%" . $Scott . "%';
$result=mysql_query($sql);
while($row=mysql_fetch_array($result)){
$Scott=$row['Scott'];
$Den=$row['Den'];
$Color=$row['Color'];
$Cond=$row['Cond'];
$70=$row['70'];
$70J=$row['70J'];
$75=$row['75'];
$75J=$row['75J'];
$80=$row['80'];
$80J=$row['80J'];
$85=$row['85'];
$85J=$row['85J'];
$90=$row['90'];
$90J=$row['90J'];
$95=$row['95'];
$95J=$row['95J'];
$98=$row['98'];
$98J=$row['98J'];
$100=$row['100'];
echo "<ul>\n";
echo "<li>" . "<a href=\"SMQ.php?id=$Scott\">" .$Scott . " " . $Den . " " . $Color . " " . $Cond . " " . $70 . " " . $70J . " " . $75 . " " . $75J . " " . $80 . " " . $80J . " " . $85 . " " . $85J . " " . $90 . " " . $90J . " " . $95 . " " . $95J . " " . $98 . " " . $98J . " " . $100 . "</a></li>\n";
echo "</ul>";
}
}
else{
echo "<p>Please enter a search query</p>";
}
?>
I know it's probably pretty bad, but hopefully at least you can get an idea of what I'm trying to accomplish. Please dear God tell me what I am doing wrong! I'm sure it will take a knowledgeable user 5 minutes to fix this, but you would be saving my skin!THANKS!!! Edited by mac_gyver, 14 August 2014 - 11:04 AM. removed link to op's cp and code tags please when posting code I found this amazing tutorial and i try to change it for a different database, but when i do a search it never finds anything. <?php $dbHost = 'localhost'; // localhost will be used in most cases // set these to your mysql database username and password. $dbUser = 'root'; $dbPass = '123'; $dbDatabase = 'ergasia2'; // the database you put the table into. $con = mysql_connect($dbHost, $dbUser, $dbPass) or trigger_error("Failed to connect to MySQL Server. Error: " . mysql_error()); mysql_select_db($dbDatabase) or trigger_error("Failed to connect to database {$dbDatabase}. Error: " . mysql_error()); // Set up our error check and result check array $error = array(); $results = array(); // First check if a form was submitted. // Since this is a search we will use $_GET if (isset($_GET['search'])) { $searchTerms = trim($_GET['search']); $searchTerms = strip_tags($searchTerms); // remove any html/javascript. if (strlen($searchTerms) < 3) { $error[] = "Ο όρος αναζήτησις πρέπει να είναι έχει περισσότερους από 3 χαρακτήρες."; }else { $searchTermDB = mysql_real_escape_string($searchTerms); // prevent sql injection. } // If there are no errors, lets get the search going. if (count($error) < 1) { $searchSQL = "SELECT Fname, Surname, StreetName, status FROM EMPLOYEES WHERE "; // grab the search types. $types = array(); $types[] = isset($_GET['Fname'])?"`Fname` LIKE '%{$searchTermDB}%'":''; $types[] = isset($_GET['Surname'])?"`Surname` LIKE '%{$searchTermDB}%'":''; $types[] = isset($_GET['StreetName'])?"`StreetName` LIKE '%{$searchTermDB}%'":''; $types = array_filter($types, "removeEmpty"); // removes any item that was empty (not checked) if (count($types) < 1) $types[] = "`sbody` LIKE '%{$searchTermDB}%'"; // use the body as a default search if none are checked $andOr = isset($_GET['matchall'])?'AND':'OR'; $searchSQL .= implode(" {$andOr} ", $types) . " ORDER BY `stitle`"; // order by title. $searchResult = mysql_query($searchSQL) or trigger_error("There was an error.<br/>" . mysql_error() . "<br />SQL Was: {$searchSQL}"); if (mysql_num_rows($searchResult) < 1) { $error[] = "The search term provided {$searchTerms} yielded no results."; }else { $results = array(); // the result array $i = 1; while ($row = mysql_fetch_assoc($searchResult)) { $results[] = "{$i}: {$row['stitle']}<br />{$row['sdescription']}<br />{$row['sbody']}<br /><br />"; $i++; } } } } function removeEmpty($var) { return (!empty($var)); } ?> <html> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"> <title>My Simple Search Form</title> <style type="text/css"> #error { color: red; } </style> <body> <?php echo (count($error) > 0)?"The following had errors:<br /><span id=\"error\">" . implode("<br />", $error) . "</span><br /><br />":""; ?> <form method="GET" action="<?php echo $_SERVER['PHP_SELF'];?>" name="searchForm"> Search For: <input type="text" name="search" value="<?php echo isset($searchTerms)?htmlspecialchars($searchTerms):''; ?>" /><br /> Search In:<br /> Body: <input type="checkbox" name="body" value="on" <?php echo isset($_GET['body'])?"checked":''; ?> /> | Title: <input type="checkbox" name="title" value="on" <?php echo isset($_GET['title'])?"checked":''; ?> /> | Description: <input type="checkbox" name="desc" value="on" <?php echo isset($_GET['desc'])?"checked":''; ?> /><br /> Match All Selected Fields? <input type="checkbox" name="matchall" value="on" <?php echo isset($_GET['matchall'])?"checked":''; ?><br /><br /> <input type="submit" name="submit" value="Search!" /> </form> <?php echo (count($results) > 0)?"Your search term: {$searchTerms} returned:<br /><br />" . implode("", $results):""; ?> </body> </html> The table which i use is the following ---------------- |EMPLOYEES| ---------------- |ssn | ---------------- |Fname ---------------- |postal code | ---------------- |salary | ---------------- |street name| ---------------- |street number | ------------------- |surname | ----------------- |UnionMembershipNumber| --------------------------------- |password | ----------------- |status | ---------------- Thank you for writing this script. It has been most helpful in doing a search for a website I manage. Everything is working fine but I would like some help in modifying the "$results[] = " line. For instance, I would like to show or hide the address of a business if a data value is set to 1 if set to 0 then hide. Same for the business web address. if ( $row_memberrs['WebAddress'] != NULL ) { echo <a href=\"{$row['WebAddress']}\" target=_blank>Visit our website</a>; } I am a newbie to php and would appreciate any help you can give me. Here is a link to the search page http://www.wildwoodba.org/searchsite.php If it is not too much trouble I would like to hide the check boxes and make it search the body, title or disc for the words entered. Thank you for your help. ugh... I'm a total PHP nub and I'm having trouble with: Code: [Select] $search_by = $_POST['search_by']; $search = $_post['search']; $dbc = mysqli_connect('xx', 'artofwarsomerset', 'xx', 'artofwarsomerset') or die ('Error connecting to MySQL server'); $query = "SELECT * FROM players WHERE '$search_by' = '$search' "; $result = mysqli_query($dbc,$query) or die("Error: ".mysqli_error($dbc)); echo "<table><tr><td>Player</td><td>city</td><td>alliance</td><td>x</td><td>y</td><td>other</td><td>porters</td><td>conscripts</td><td>Spies</td><td>HBD</td><td>Minos</td><td>LBM</td><td>SSD</td><td>BD</td><td>AT</td><td>Giants</td><td>Mirrors</td><td>Fangs</td><td>ogres</td><td>banshee</td></tr>" ; while ($row = mysqli_fetch_array ($result)) { echo '<tr><td> $row['player'] </td>'; echo '<td> . $row['city']</td>'; echo '<td> . $row['alliance']</td>'; echo '<td> . $row['x']</td>'; echo '<td> . $row['y']</td>'; echo '<td> . $row['other']</td>'; echo '<td> . $row['porter']</td>'; echo '<td> . $row['cons']</td>'; echo '<td> . $row['spy']</td>'; echo '<td> . $row['hbd']</td>'; echo '<td> . $row['mino']</td>'; echo '<td> . $row['lbm']</td>'; echo '<td> . $row['ssd']</td>'; echo '<td> . $row['bd']</td>'; echo '<td> . $row['at']</td>'; echo '<td> . $row['giant']</td>'; echo '<td> . $row['fm']</td>'; echo '<td> . $row['ft']</td>'; echo '<td> . $row['ogre']</td>'; echo '<td> . $row['banshee']</td></tr></table>'; } ?> Error shows up on line 35 but I'm not sure what I've done... Also, the xx's on my dbc statement were on purpose. Current error is: Parse error: syntax error, unexpected T_STRING, expecting ',' or ';' in /home/content/64/4940664/html/artofwar/browse.php on line 35, I can't figure out where the hell it wants a ;... I am wanting to write a script that will allow a user to search youtube videos! What I have so far is not working yet, but I know it can be done! I found this code and it works and its not a million api files to get one thing working! Code: [Select] <?php # YouTube Video Collector - YouTube.class.php ##################################################### # # # YouTube Video Collector 2010 # # # # Author: CMBSystems (Chris Bearcroft) # # Copyright: CMBSystems 2010, All Rights Reserved # # Last Modded: 29-09-2010, 1:26 AM (GMT) # # # ##################################################### class YouTube { public function getURL($Search){ if(!empty($Search)){ $Search=split("\n",$Search); for($i=0;$i<count($Search);$i++){ $SearchURL=urlencode($Search[$i]); $SearchURL="http://www.youtube.com/results?search_category=10&search_type=videos&search_query={$SearchURL}"; preg_match('/\/watch\?v=(.*?)\"/',file_get_contents($SearchURL),$URL); if(strpos($URL[1],'&')){$URL=split('&',$URL[1]);$URL=$URL[0];}else{$URL=$URL[1];} $array[]="http://www.youtube.com/watch?v={$URL}"; } return $array; } } public function printForm($Search){ $Search=htmlspecialchars(stripslashes($Search)); return "<form method=\"get\" action=\"\">\n <table>\n <tr>\n". " <td><textarea cols=\"60\" rows=\"15\" name=\"search_query\">{$Search}</textarea></td>\n". " </tr>\n <tr>\n <td align=\"right\"><input type=\"submit\" value=\"Search YouTube\" /></td>\n". " </tr>\n </table>\n</form>\n"; } } ?> Code: [Select] <?php # YouTube Video Collector - YouTube.php ##################################################### # # # YouTube Video Collector 2010 # # # # Author: CMBSystems (Chris Bearcroft) # # Copyright: CMBSystems 2010, All Rights Reserved # # Last Modded: 29-09-2010, 1:26 AM (GMT) # # # ##################################################### # Require the YouTube class require 'YouTube.class.php'; # Set the PHP vars $Form = YouTube::printForm($_GET['search_query']); $Result = YouTube::getURL($_GET['search_query']); print <<<YTVSC <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title>YouTube Collector</title> </head> <body> {$Form} YTVSC; print_r($Result); print <<<YTVSC </body> </html> YTVSC; ?> It allows me to have a feed link on my site to get the data http://claritydreams.com/youtube/YouTube.php?YT_Search=Staind I can push that ?YT_Search as a search from with in my client but I want to convert the file in to xml to read the data back into the client. im a complete novice. im using one of the tutorials on here to make a simple search form. the bit of script that i think outputs the results is $results = array(); // the result array $i = 1; while ($row = mysql_fetch_assoc($searchResult)) { $results[] = "{$i}: {$row['placing']},   {$row['racedate']},   {$row['horseid']}<br /><br />"; $i++; how do i make these results appear in a table, and how would i make it so there was a link on the date that clicked would show all the races on that day? sorry i advance as this is probably the most dumb of questions! I'm not sure why, but once I added a search form in my nav menu, it made my other forms on the website such as login and signup form take them to where the search button would take them. any ideas??? I want to know how to display results from mysql database by filling in a form. but i have found a tutorial which shows typing in a text box which displays results. if i follow this tutorial will it help me to understand and create php coding to display results for my form? Hi, I was wondering could anyone help me here please, I'm pretty stuck and not sure what's wrong. I have also posted this topic on Daniweb if that is OK as I'm kind of stuck for time on this (If I'm not allowed post on multiple forums this can be deleted). I have a database that contains files and I want to be able to search those files by putting in a ID number into a textbox on my homepage of a website I'm working on. In my databse my doc_id is the primary key, and I want the user to be able to enter a document ID and have all the information returned to them. Can anyone help me here as I don't understand why it isn't working? Here is the code as it is at the moment - Code: [Select] <?php include 'connect_db.php'; include 'newheader.php'; function sanitize_data($data) { $data = array_map('trim',$data); $data = array_map('strip_tags',$data); $data = array_map('htmlspecialchars',$data); $data = array_map('mysql_real_escape_string',$data); return $data; } $post = sanitize_data($_POST); if (isset($_POST['searchID'])) { $find = $_POST['find']; $find = strtoupper($find); $find = strip_tags($find); $find = trim ($find); $field = $_POST['field']; $data = mysql_query("SELECT * FROM tc_tool.forms WHERE upper(".$field.") LIKE'%$find%'") or die(mysql_error()); while ($result = mysql_fetch_array( $data )) { echo $result['doc_number']; echo " "; echo $result['doc_title']; echo " "; echo "<br>"; echo "<br>"; } ?> The error returned to me is this - Incorrect parameter count in the call to native function 'upper' Here is the code to my button too if it is any use - Code: [Select] <body onLoad = "documentNumber.focus()"> <input type= "text" id= "documentNumber" name= "searchbyequipmenttype" class= "eSearchFormInput"/> <input type= "submit" name= "searchID" value="Search By Doc ID" /><br /> And I have no idea why it is, can anyone help if possible? I have tried it a few ways so if needed I'll post the other ways I've tried it. Thanks if anyone can help Hello!To search in a table from my database i use this: mysql_connect ("localhost", "","") or die (mysql_error()); mysql_select_db (""); $key = $_POST['key']; $sql = mysql_query("select * from internet_securitate where nume_produs like '%$key%'"); while ($row = mysql_fetch_array($sql)){ echo 'Produs ID: '.$row['internet_securitateID']; echo '<br/> Denumire Produs: '.$row['nume_produs']; echo '<br/> Descrie '.$row['descriere']; echo '<br/> Disponibilitate: '.$row['disponibilitate_produs']; echo '<br/><br/>'; } can i expand this to searh in 3 tables? :-? I have a search form and have set up php, but at the moment its not making the correct searches, what am i doing wrong. Help is appreciated. heres my php code: Code: [Select] <?php $server = ""; // Enter your MYSQL server name/address between quotes $username = ""; // Your MYSQL username between quotes $password = ""; // Your MYSQL password between quotes $database = ""; // Your MYSQL database between quotes $con = mysql_connect($server, $username, $password); // Connect to the database if(!$con) { die('Could not connect: ' . mysql_error()); } // If connection failed, stop and display error mysql_select_db($database, $con); // Select database to use // Query database $result = mysql_query("SELECT * FROM Properties"); // Set up our error check and result check array $error = array(); $results = array(); // First check if a form was submitted. // Since this is a search we will use $_GET if (isset($_GET['search'])) { $searchTerms = trim($_GET['search']); $searchTerms = strip_tags($searchTerms); // remove any html/javascript. if (strlen($searchTerms) < 10) { $error[] = "Search terms must be longer than 10 characters."; }else { $searchTermDB = mysql_real_escape_string($searchTerms); // prevent sql injection. } // If there are no errors, lets get the search going. if (count($error) < 1) { $searchSQL = "SELECT sid, sbody, stitle, sdescription FROM simple_search WHERE "; // grab the search types. $types = array(); $types[] = isset($_GET['images'])?"`simages` LIKE '%{$searchTermDB}%'":''; $types[] = isset($_GET['Location'])?"`sLocation` LIKE '%{$searchTermDB}%'":''; $types[] = isset($_GET['Number of bedrooms'])?"`snumberofbedrooms` LIKE '%{$searchTermDB}%'":''; $types = array_filter($types, "removeEmpty"); // removes any item that was empty (not checked) if (count($types) < 1) $types[] = "`simages` LIKE '%{$searchTermDB}%'"; // use the body as a default search if none are checked $andOr = isset($_GET['matchall'])?'AND':'OR'; $searchSQL .= implode(" {$andOr} ", $types) . " ORDER BY `sLocation`"; // order by title. $searchResult = mysql_query($searchSQL) or trigger_error("There was an error.<br/>" . mysql_error() . "<br />SQL Was: {$searchSQL}"); if (mysql_num_rows($searchResult) < 1) { $error[] = "The search term provided {$searchTerms} yielded no results."; }else { $results = array(); // the result array $i = 1; while ($row = mysql_fetch_assoc($searchResult)) { $results[] = "{$i}: {$row['sLocation']}<br />{$row['sNumberofbedrooms']}<br />{$row['sbody']}<br /><br />"; $i++; } } } } function removeEmpty($var) { return (!empty($var)); } if (!$result) { echo "Error running query:<br>"; trigger_error(mysql_error()); } elseif(!mysql_num_rows($result)) { // no records found by query. echo "No records found"; } else { $i = 0; echo '<div class="container" style="float:left;">'; while($row = mysql_fetch_array($result)) { // Loop through results $i++; echo '<div class="imageholder" style="float:left;">'; echo '<img class="image1" src="'. $row['images'] .'" />'; //image echo '</div>'; echo '<div class="textholder" style="font-family:helvetica; font-size:13px; float:left; padding-top:10px;">'; echo "<span style=\"color:green;\"><b>Displaying record $i<br>\n</b><br></span>"; echo "<b>" . $row['id'] . "</b><br>\n"; // Where 'id' is the column/field title in the database echo "Location: ". $row['Location'] . "<br>\n"; // Where 'location' is the column/field title in the database echo "Property Type: ". $row['Property_type'] . "<br>\n"; // as above echo "Bedrooms: ". $row['Number_of_bedrooms'] . "<br>\n"; // .. echo "Purchase Type: ". $row['Purchase_type'] . "<br>\n"; // .. echo "Price: ". $row['Price_range'] . "<br>\n"; // .. echo '</div>'; echo '<div style="clear:both"></div>'; } echo '</div>'; } mysql_close($con); // Close the connection to the database after results, not before. ?> I just changed around my database and as such I need to update my search form. The way it used to work was a user could use the search bar to look for actors. In changing my database there in no longer a actor column, there are how ever actor_1, actor_2 ... until actor_7. What I am trying to do it set it up so my form looks the same but the back end will look in all the actor columns for the name. So when a user selects actor from the drop down menu it will look in all 7 actor columns. Here is what i had before that worked. for the search bar Code: [Select] <form action="/search.php" method="post"> <span class="rulesub">Search: </span><input type="text" name="search"> <select size="1" name="dropdown"> <option value="" selected>Search by...</option> <option value="title">Title</option> <option value="actors">Actors</option> <option value="difficulty">Difficulty 1-5</option> </select> <input type="Submit" value="Search" name="Submit"> </form> for the search page Code: [Select] $connect = mysql_connect('localhost', $username, $password) or die ("Unable to connect to host"); mysql_select_db($database) or die ("Unable to connect to database"); $search = empty($_POST['search'])? die ("Please enter search criteria.") : mysql_escape_string($_POST['search']); $dropdown = empty($_POST['dropdown'])? die ("Please select from search criteria.") : mysql_escape_string($_POST['dropdown']); $query = mysql_query("SELECT * FROM movie WHERE $dropdown Like '%$search%'") or die (mysql_error()); if(mysql_num_rows($query) == 0) { printf("Could not find $search while looking in $dropdown, please try again."); //exit; } else{ $num=mysql_numrows($query); mysql_close($connect); ?> Output thanks I Have been working on this search for for a while which is working but lacks a few feature i wanna add. 1st is if the make/model/price is empty i want to search the whole db I have attached the php file Also each card has a image and need help adding these to the search. the images are located in a uploads folder Iv grafted hard on this and need some help Also is this the correct way to process a form search? hi im new to these stuff and appreciate any help.
im creating a simple form with 1 textbox and a search button. when the button is pressed a select query should run and check the mysql database and list that result on that same page. For example, lets say there is a textbox named Lastname, then the search button should search mysql and list down the last name matching that name.
Form code :
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title>Search</title> </head> <body> <form action="post.php" method="GET"> <input type="text" name="query" /> <input type="submit" value="Search" /> </form> </body> </html>Any help? I need to show the result right bellow the button, and if no match found it should display an error : no match found thanks How would i begin to start php coding to work for this form shown in the image? could anyone point me to useful tutorials, i would appreciate it, thanx I'm very new to php, and so I haven't really mastered all the coding. But what I want to do is make a search form, which will search 15 different columns in a MySQL database. I've gone to a few different online walkthroughs, but I haven't managed to succeed as of yet. Can someone please show me the HTML and PHP coding required in order to make a search setup (the server is "localhost", the username is "root", the password is [blank], the database is "anzac war trophys" and the table is "anzac". And also assume that the collumns are called "a", "b", "c" and so on. Any help greatly appreciated! |
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