PHP - Unexpected T_object_operator Error - Dom Parser
Hello all,
I have here some PHP code that was working fine under my installation of XAMPP (it has PHP 5). When I moved the following code to my web hosting site, 1&1, it threw up the error you see in the subject field. I attempted to create a new htaccess file in the same directory as my website files to force PHP 5, but I still get the same error. Any ideas on how else I can parse the XML? My code is as follows: //get ALL instances of wanted element(s) $titles = $item->getElementsByTagName('title'); $dates = $item->getElementsByTagName('pubDate'); $descriptions = $item ->getElementsByTagName('description'); //formatting $content = (' <ul class ="blog_entry"> <li class="title_entry"> '.$titles->item(0)->nodeValue. '</li> <li class="date_entry"> Posted on '.date("M d, Y H:i",strtotime($dates->item(0)->nodeValue)). '</li> <br> <li class="description_entry"> '.$descriptions->item(0)->nodeValue. '</li> </ul> '); echo $content; } Personally, I think it's a problem with the nodeValue, since apparently the PHP 5 push doesn't seem to work. Any other way I could reference the XML values I get? Similar Tutorialsi keep getting the above error.. help this is a class of the log entry <?php require_once "config.php"; abstract class DataObject { protected $data = array(); public function__construct( $data ) { foreach ( $data as $key => $value ) { if ( array_key_exists( $key, $this->data )) $this->data[$key] = $value; } } public function getValue( $field ) { if ( array_key_exists( $field, $this->data )) { return $this->data[$field]; } else { die( "field not found" ); } } public function getValueEncoded( $field ) { return htmlspecialchars( $this->getValue( $field )); } protected function connect() { try { $conn = new PDO(DB_DSN, DB_USERNAME, DB_PASSWORD ); $Conn->setAttribute( PDO::ATTR_PERSISTENT, true ); $conn->setAttribute( PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION ); } catch ( PDOException $e->getMessage() ); die( "connection failed: " . $e->getMessage() ); } return $conn; } protected function disconnect( $conn ) { $conn = ""; } } ?> sorry this was the actuall php code for this error... <?php require_once "DataObject.class.php"; class LogEntry extends DataObject { protected $data = array( "userid" => "", "pageUrl" => "", "numVisits" => "", "lastAcces" => "", ); public static function getLogEntries( $userid ) { $conn = parent::connect(); $sql = "SELECT * FROM " . TBL_accesslog . " WHERE userid = : userid ORDER BY lastAcces DESC"; try { $st = conn->prepare( $sql ); $st->bindValue( ":userid", $userid, PDO::PARAM_INT ); $st->execute(); $logEntries = array(); foreach ( $st->fetchAll() as $row ) { $logEntries[] = new logEntry( $row); } parent::disconnect( $conn ); return $logEntries; } catch ( PDOExeception $e ) { parent::disconnect( $conn ); die( "Query failed: " . $e->getMessage() ); } } } ?> Hey, Its something to do with the ' or \ I know that as Ive been trying alot. Code Code: [Select] if ($this->isAdmin && count ($func_players) > SettingsManager::GetSetting(Settings::BAN_LIMIT)) return $this->sendErrorBox('max', 'You can\'t ban that many Users at once!', 'Gosh', 'iBan'); foreach($func_players as $func_player) $func_player->ban(&this->playerName, $this->isAdmin); return $this->sendErrorBox('max', sprintf( '%s ha%s been banned.' $this->getPlayerString($func_players), count($func_players) == 1 ? 's' : 've'), 'SykoPwns:P', 'Sykos:iBan'); Thanks for your help! Ive tried alot of things I think I could just take out the \ or something!! Code: [Select] ->from('songlist', array('album', 'artist', 'date_added', 'picture', 'albumyear', 'cnt' => 'Count(*)')) Any ideas why I am getting the Parse Error? Thanks I need help with this old script I found. Parse Error on line 101. And Line 101 is ?> <?php $file = "music.xml"; $to_print = array("Name", "Artist", "Album", "Track ID", "Year", "Play Count", "Track Number", "Track Count", "Genre", "Rating", "Date Added"); $db_host = "localhost"; $db_name = "music_library"; $db_table = "table"; $db_username = "root"; $db_password = ""; function db_connect() { global $db_host, $db_name, $db_table, $db_username, $db_password; mysql_connect($db_host, $db_username, $db_password) or die("<p style='font-color:red'>Cannot connect to mySQL server</p>"); mysql_select_db($db_name) or die("<p style='font-color:red'>Cannot connect to mySQL database</p>"); } function alter_print_arr(&$input, $key) { $input = str_replace(' ', '_', strtolower($input)); } array_walk($to_print, 'alter_print_arr'); function array_to_table($array) { global $db_table, $to_print; db_connect(); mysql_query("DELETE FROM $db_table") or die("Could not remove old records."); mysql_query("OPTIMIZE TABLE $db_table"); foreach ($array as $elem_key => $element) { if (isset($element[track_id])) { $sql = ""; foreach ($element as $k => $v) { if (in_array($k, $to_print)) { $sql .= "$k='" . mysql_real_escape_string(str_replace('=amp=', '&', $v)) . "', "; } } $sql = rtrim(ltrim($sql, "track_id='$element[track_id]', "), ", "); $sql1 = "INSERT INTO $db_table (track_id) VALUES ('$element[track_id]');"; $sql2 = "UPDATE $db_table SET $sql WHERE track_id=$element[track_id];"; mysql_query($sql1) or die(mysql_error()); // echo"$sql1<br />$sql2<br /><br />"; // For debugging. Uncomment with caution! mysql_query($sql2) or die(mysql_error()); } } echo "Done! :)"; // print_r($array); // For debugging. Uncomment with caution! } $xml_parser = ""; //will hold each song in a 2-d array $songs = array(); //counter, number of 'dict' elements encountered $current_key=""; $number_dicts = 0; //key for each element in second dimension of array $current_element=""; //stores xml element name //value for second dimension array elements $current_data = ""; //boolean used to help let us know if we're done with the song list $end_of_songs = false; function start_element($parser, $name, $attribs) { global $current_element, $number_dicts; if ($name == "DICT") { $number_dicts++; } if ($number_dicts > 2) { $current_element = $name; } } function end_element($parser, $name) { global $songs, $current_element, $current_data, $number_dicts, $array_key, $end_of_songs; if ($end_of_songs) { return; } if ($current_element == "KEY") { $array_key = str_replace(' ', '_', strtolower($current_data)); } else { $songs[$number_dicts][$array_key] = $current_data; } } function character_data($parser, $data) { global $number_dicts, $current_data, $end_of_songs; if ($data == "Playlists") { $end_of_songs = true; } $current_data = trim($data); } $xml_parser = xml_parser_create(); xml_parser_set_option($xml_parser, XML_OPTION_CASE_FOLDING, 1); xml_set_element_handler($xml_parser, "start_element", "end_element"); xml_set_character_data_handler($xml_parser, "character_data"); if (!($fp = @fopen($file, "r"))) { return false; } while ($data = fread($fp, 4096)) { // xml_parser jumps over ampersands. Decode any entities then replace any ampersands. // Reverse this when building SQL statement. if (!xml_parse($xml_parser, str_replace('&', '=amp=', html_entity_decode($data)), feof($fp))) { die(sprintf("XML error: %s at line %d ", xml_error_string(xml_get_error_code($xml_parser)), xml_get_current_line_number($xml_parser))); } } xml_parser_free($xml_parser); array_to_table($songs); ?> In the following code, I am getting an error: Parse error: syntax error, unexpected T_CONSTANT_ENCAPSED_STRING, expecting T_STRING or T_VARIABLE or '{' or '$' in XXX on line 235 Line 235 is the second line in the code snippet Code: [Select] $result = mysql_query( $querystr, $this->linkid ); $this->"queryid".$id = $result; if ( defined( "SWIFTDEBUG" ) ) { Thanks Parse error: syntax error, unexpected T_STRING in C:\xampp\htdocs\mywork\unique.php on line 15 <html> <head> <title> </title> </head> <body bgproperties="fixed"> <?php $dbhost = 'localhost'; $dbuser = 'root'; $dbpass = ''; $con = mysql_connect($dbhost, $dbuser, $dbpass) or die ('Error connecting to mysql'); $dbname = 'mywork'; mysql_select_db($dbname, $con); $sql=mysql_query(insert into users (regno,name,gender,date,month,year,emailid,cell,paddress,caddress,incometype,incomeamt,dad,fyes,dadocup,mom,myes,momocup,password) VALUES ('$_POST[regno]','$_POST[name]','$_POST[gender]','$_POST[date]','$_POST[month]','$_POST[year]','$_POST[emailid]','$_POST[cell]','$_POST[paddress]','$_POST[caddress]','$_POST[incometype]','$_POST[incomeamt]','$_POST[dad]','$_POST[fyes]','$_POST[dadocup]','$_POST[mom]','$_POST[myes]','$_POST[momocup]','$_POST[password]')"); $sql1=mysql_fetch_array($sql); $result = @mysql_query($SQl1); $result="SELECT * FROM users WHERE regno='$regno'"; while($row = mysql_fetch_array($result)) { //echo $row['regno']."regno<br>"; //echo $row['name']."name<br>"; //echo $row['gender']."gender<br>"; //echo $row['date']."date<br>"; //echo $row['month']."month<br>"; //echo $row['year']."year<br>"; //echo $row['emailid']."emailid<br>"; //echo $row['cell']."cell<br>"; //echo $row['paddress']."paddress<br>"; //echo $row['caddress']."caddress<br>"; //echo $row['incometype']."incometype<br>"; //echo $row['incomeamt']."incomeamt<br>"; //echo $row['dad']."dad<br>"; //echo $row['fyes']."fyes<br>"; //echo $row['dadocup']."dadocup<br>"; //echo $row['mom']."mom<br>"; //echo $row['myes']."myes<br>"; //echo $row['momocup']."momocup<br>"; //echo $row['password']."password<br>"; } echo "Thanks for Register!"; if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } echo "1 record added"; mysql_close($con); ?> <form name="security" action="index.php" method="post"> <input type="submit" value="click here to login"> </form> </body> </html> I'm using PHP 5.2 Server and Simple HTML DOM 1.5. This script scrape or extract data from a football site, its fully working on PHP 5.9 Server but I need to know how I can fix it for PHP 5.2 server. Can someone give me a hint on how can I fix the error? Thanks in advance. My PHP 5.2 Server script output shows: ++++++++++++++++ Object id #599 Object id #604 Object id #609 Object id #614 Object id #619 Object id #627 Object id #632 Object id #637 Object id #642 Object id #647 Object id #655 Object id #660 Object id #665 Object id #670 Object id #675 Object id #683 Object id #688 Object id #693 Object id #698 Object id #703 Object id #711 Object id #716 Object id #721 Object id #726 Object id #731 ++++++++++++++++ while PHP 5.9 Server says ++++++++++++++++ Rk Player Team POS OPPONENT 1 Aaron Rodgers GB QB at CAR 2 Tom Brady NE QB vs. SD 3 Matt Schaub HOU QB at MIA 4 Michael Vick PHI QB at ATL ++++++++++++++++ I did applied the bug solution listed on https://sourceforge.net/tracker/index.php?func=detail&aid=3107230&group_id=218559&atid=1044037 but it is still not working. It says: ++++++++++++++++ Details: I get compiler errors in PHP 5.2 when using this as an object. The offending lines are 609 and 940, which both contain this construct: if ($this->size>0) $this->char = $this->doc[0]; This tries to get the first character of $this->doc, but PHP 5.2 sees it as trying to access it as an array. It's easily fixed by this: if ($this->size>0) $this->char = substr($this->doc, 0, 1); Or you could probably use chr(ord($this->doc)) as well. Either way solves the compile error without changing functionality. ++++++++++++++++ Here are my codes: Code: [Select] <?php # don't forget the library include('simple_html_dom.php'); # this is the global array we fill with article information $articles = array(); $source = 'http://www.athlonsports.com/columns/winning-game-plan/fantasy-football-qb-rankings'; # passing in the first page to parse, it will crawl to the end # on its own getArticles($source); function getArticles($page) { global $articles, $descriptions; $html = new simple_html_dom(); $html->load_file($page); //$items = $html->find('div[class=preview]'); $items = $html->find('tbody tr'); foreach($items as $post) { # remember comments count as nodes /*$articles[] = array($post->children(3)->outertext, $post->children(6)->first_child()->outertext);*/ $articles[] = array($post->children(0), $post->children(1), $post->children(2), $post->children(3), $post->children(4)); } # lets see if there's a next page if($next = $html->find('a[class=nextpostslink]', 0)) { $URL = $next->href; echo "going on to $URL <<<\n"; # memory leak clean up $html->clear(); unset($html); getArticles($URL); } } ?> <html> <head> </head> <body> <? echo "Source: " . $source; ?> <table cellpadding="5" cellspacing="0" border="0"> <?php foreach($articles as $item) { echo "<tr>"; echo "<td>" . $item[0] . "</td><td>" . $item[1] . "</td><td>" . $item[2] . "</td>"; echo "<td>" . $item[3] . "</td><td>" . $item[4] . "</td>"; echo "<tr>"; } ?> </table> </body> </html> Code: [Select] <?php mysql_connect ("-","-","-") or die ('Error'); mysql_select_db ("-"); $out = mysql_query("SELECT * FROM guestbook ORDER BY id DESC"); while($row = mysql_fetch_assoc($out); --and this one if that braces is deleted { ----this is where im getting the error $name = $row['name']; $email = $row['email']; $txt = $row['comment']; $msg = "Are you sure you want to delete"; /* @var $_REQUEST <type> */ if (isset($_REQUEST ["action"]) && $_REQUEST["action"] == "del") { $id = intval($_REQUEST['id']); mysql_query("DELETE FROM guestbook WHERE id=$id;"); echo "<action=index.php>"; } echo "<font face='verdana' size='1'>"; echo "<table border='0'> <tr><td>Name: ".$name."</td></tr>"." <tr><td>Email: ".$email."</td></tr> <tr><td colspan='2'>Comment:</td></tr> <tr><td colspan='2' width='500'><b>".$txt."</b></td></tr> <tr><td><a onclick=\"return confirm('.$msg.');\" href='index.php?action=del&id=".$row['id']."'><span class='red'>["."Delete"."]</span></a> </td></tr> </table><br />"; echo "<hr size='1' width='500' align='left'></font>"; } ?> Kindly help me please. When i delete ({) the error will become the ( i dont know what to do already. Thanks. I have been trying to get my files to upload onto a computer and I receive this message: Parse error: syntax error, unexpected T_STRING in /home/content/19/6550319/html/listing.php on line 27. Line 27 is how the php logs into my SQL. The problem is that I was able to log in before. I just made changes to the form by adding a dropdown menu and price and now it says it doesnt parse. Can anyone figure this out. I will include the code without the login information because the forum is public but I did put the words left out for you to see where I took out the passcodes. Code: [Select] <?php //This is the directory where images will be saved $target = "potofiles/"; $target = $target . basename( $_FILES['photo']['name']); //This gets all the other information from the form $price=$_POST['price']; $gig=$_POST['giga']; $yesg=$_POST['yesg']; $pic=($_FILES['photo']['name']); $pic2=($_FILES['phototwo']['name']); $pic3=($_FILES['photothree']['name']); $pic4=($_FILES['photofour']['name']); $description=$_POST['iPadDescription']; $condition=$_POST['condition']; $fname=$_POST['firstName']; $lname=$_POST['lastName']; $email=$_POST['email'] // Connects to your Database mysql_connect ("left out", "left out", "left out") or die(mysql_error()) ; mysql_select_db("left out") or die(mysql_error()) ; //Writes the information to the database mysql_query("INSERT INTO listing (price,giga,yesg,photo,phototwo,photothree,photofour,iPadDescription,condition,firstName,lastName,email) VALUES ('$price', '$gig', '$yesg', '$pic', '$pic2', '$pic3', '$pic4', '$description', '$condition', '$fname', '$lname', '$email')") ; //Writes the photo to the server if(move_uploaded_file($_FILES['photo']['tmp_name'], $target)) { //Tells you if its all ok echo "The file ". basename( $_FILES['uploadedfile']['name']). " has been uploaded, and your information has been added to the directory"; } else { //Gives and error if its not echo "Sorry, there was a problem uploading your file."; } echo date("m/d/y : H:i:s", time()) ?> I don`t get it, waht is wrong?! Code: [Select] <?php require_once 'auth.php'; if (!isset($_SESSION['SESS_VERIFY'])) { header("location: access-denied.php"); exit(); } if ($_SESSION['lang'] == 'Ro') { // setare data romania date_default_timezone_set('Europe/Bucharest'); $today = getdate(); $zi = $today['mday']; $luna = $today['mon']; $lunastring = $today['month']; $an = $today['year']; $data = $zi.$luna.$an; $data = (string)$data; $ora = date('H:i:s'); $msg = array(); $err = array(); $luni = array ( 1=>'Ianuarie', 2=>'Februarie', 3=>'Martie', 4=>'Aprilie', 5=>'Mai', 6=>'Iunie', 7=>'Iulie', 8=>'August', 9=>'Septembrie', 10=>'Octobrie', 11=>'Noiembrie', 12=>'Decembrie'); // comun const SQL_ERR = 'SQL statement failed with error: '; const ADD_MODEL = 'ADAUGA UN MODEL NOU'; . .many constants.. . } elseif ($_SESSION['lang'] == 'It') {... Thank you! Hi folks, I am a complete n00b at php and mysql. I am teaching myself from books and the WWW, but alas I am stuck... the error I get is: Parse error: syntax error, unexpected T_STRING in X:\xampp\htdocs\search.php on line 7 here is the code: <?php mysql_connect ("localhost", "user", "password") or die (mysql_error()); mysql_select_db ("it_homehelp_test") or die (mysql_error()); $term = $_POST['term']; $sql = $mysql_query(select * from it_homehelp_test where ClientName1 like '%term%'); <<<------this is line 7 while ($row = mysql_fetch_array($sql)){ echo 'Client Name:' .$row['ClientName1']; echo 'Address:' .$row['Address1']; echo 'Phone:' .$row['Tel1']; } ?> Any help you can offer would be great. I can also post the ".html" file that creates the search bar if it is needed. Thanks
Hello everyone,
1 <?php
7 // Create connection
10 // Check connection
14 $firstname = $conn->real_escape_string($_REQUEST['firstname']); 25 $sql2 = "INSERT INTO countries VALUES ('$country')"; 27 $sql3 = "INSERT INTO Contacts (firstname, lastname, address, city, country, phone, email) VALUES ('$firstname', '$lastname', '$address', $city, $country, '$phone_number','$email')";
29 SELECT * FROM cities;
if($conn->query($sql2) === true){
if($conn->query($sql3) === true){ I just enabled error reporting and I am not that familiar with it. I know I have an error some where around line 33. I know I am missing a bracket or a comma or some other syntax error I just cannot find where the error is. Below is my script. Thanks for any help. Code: [Select] <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title>Airline Survey</title> <meta http-equiv="content-type" content="text/html; charset=iso-8859-1" /> <meta name="author" content="Revised by abc1234"/> </head> <body> <?php $WaitTime = addslashes($_POST["wait_time"]); $Friendliness = addslashes($_POST["friendliness"]); $Space = addslashes($_POST["space"]); $Comfort = addslashes($_POST["comfort"]); $Cleanliness = addslashes($_POST["cleanliness"]); $Noise = addslashes($_POST["noise"]); if (empty($WaitTime) || empty($Friendliness) || empty($Space) || empty($Comfort) || empty($Cleanliness) || empty($Noise)) echo "<hr /><p>You must enter a value in each field. Click your browser's Back button to return to the form.</p><hr />"; else { $Entry = $WaitTime . "\n"; $Entry .= $Friendliness . "\n"; $Entry .= $Space . "\n"; $Entry .= $Comfort . "\n"; $Entry .= $Cleanliness . "\n"; $Entry .= $Noise . "\n"; $SurveyFile = fopen("survey.txt", "w") } if (flock($SurveyFile, LOCK_EX)) { if (fwrite($SurveyFile, $Entry) > 0) { echo "<p>The entry has been successfully added.</p>"; flock($SurveyFile, LOCK_UN; fclose($SurveyFile); else echo "<p>The entry could not be saved!</p>"; } else echo "<p>The entry could not be saved!</p>"; } ?d> <p><a href="AirlineSurvey.html">Return to Airline Survey</a></p> </body> </html> Code: [Select] <?php if (!isset($_POST['submit'])) { ?> <h2>Todays Special</h2> <p> <form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post"> <select name="day"> <option value="1">Monday/Wednesday <option value="2">Tuesday/Thursday <option value="3">Friday/Sunday <option value="4">Saturday </select> input type="submit" name="submit" value="Go"> </form> <?php // get form selection $day = $_POST['day']; // check value and select appropriate item switch ($day) { case 1: $special = 'Chicken in oyster sauce'; break; case 2: $special = 'French onion soup'; break; case 3: $special = 'Pork chops with mashed potatoes and green salad'; break; default: $special = 'Fish and chips'; break; } ?> Hey Everyone, I'm getting this error when I submit my contact form. Parse error: syntax error, unexpected $end in /home1/user/public_html/contact/process.php on line 22 I got this code from a video on youtube. http://www.youtube.com/watch?v=rdsz9Ie6h7I If I made a mistake or TYPO please let me know. Thanks! Here's my code: <?php $emailSubject = 'Contact Form Submission'; $sendto = 'info@mydomain.com'; $nameField = $_Post['name']; $emilField = $_Post['email']; $phoneField = $_Post['phone']; $SubjectField = $_Post['subject']; $messageField = $_Post['message']; $body = <<<EOD <br><hl><br>This Form was submitted from the Domain.com contact page.<br> Name: $name<br> E-Mail: $email<br> Phone: $phone<br> Subject: $subject<br> Message: $message<br> BOD; $headers = "FROM: $email\r\n"; $headers .="Content-Type: text/html\r\n"; $success = mail($sendto, $emailSubject, $body, $headers); ?> Hi all, Does anybody can help me with this error...? I am trying create a simple form which insert data into mysql table called 'sample' Here is my code... Code: [Select] <?php $connection = mysql_connect("localhost","root", "123"); if(!$connection) { die("db connection error" .mysql_error()); } $db_select = mysql_select_db("project", $connection); if(!$db_select) { die("db select error" .mysql_error()); } $sql = "INSERT INTO sample (id,firstname,lastname,bio,gender) VALUES ('$_POST['ID_']','$_POST['firstname']','$_POST['lastname']','$_POST['bio']','$_POST['gender']')"; if(!$sql) { die('Error: ' . mysql_error()); } echo "1 record added"; ?> And every time I am getting this annoying error Quote Parse error: syntax error, unexpected T_ENCAPSED_AND_WHITESPACE, expecting T_STRING or T_VARIABLE or T_NUM_STRING in C:\wamp\www\project\process.php on line 19 and Line 19 is Code: [Select] ('$_POST['ID_']','$_POST['firstname']','$_POST['lastname']','$_POST['bio']','$_POST['gender']')"; Thanks in advance..! :-) |