PHP - Receive Http Upload
Hi,
Anyone can help me on how to receive a file as a http upload? I have an application that sends an xml file with http (post method) to our server and I need to make a script that receives that, writes it to database and archives the file away. Tried to google something but no luck so far. If anyone have done something like this I appreciate any help you can give. Thanks. Similar TutorialsHello I am a total beginner and don't know first thing about php, but still trying to figure this out. So what I am trying to achieve is, send a http request from a software to my website with a ticket number, is it possible in php to receive that request and show it on a different webpage of the same site? It would be helpful if you can point me to some related articles. Trying to run a simple program that, when submitted, stores the username and password as cookies. When clicking Submit, I get the error "HTTP Error 405 - The HTTP verb used to access this page is not allowed". If the username and password fields are left blank when submitting it's suppose to give a message to enter a username and password, but, I still get that error message. HTML form: Code: [Select] <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en"> <head> <title>Week 1 Project--Cookies</title> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> </head> <body> <form action="cookie1.php" method="post"> <h2 align="center">Cookies</h2> <br /> <div> <p>Enter your username and password and click "Submit":</p><br /> <p>Username:<input type="text" name="username" size="20"></p> <p>Password:<input type="text" name="password" size="20"></p> </div> <br /> <div><input type="submit" name="submit" value="Submit" /></div> <br /> <div> <input type="reset" name="Reset" value="Start Over" /> </div> </form> </body> </html> PHP file: Code: [Select] <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en"> <head> <title>Cookie File</title> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> </head> <body> <div> <?php if ($_SERVER['REQUEST_METHOD'] == 'POST') { setcookie('username', $_POST['username'], time() + 2592000); setcookie('password', $_POST['password'], time() + 2592000); } if(($_POST['username'] == "") || ($_POST['password'] == "")) { print "You must enter both a username and password. Press the Back button on your browser and try again."; } else if (isset($_COOKIE['username'])) { print "Welcome, " .$_COOKIE['username']; } ?> </div> </body> </html> An automated API is sending an XML message to a PHP file on my site. How do I deal with this? Hey folks, I made a small shopping cart but I struggle with receiving an email with the orders; thanks in advance this is the mail.php <?php session_start(); if($_POST['sendemail'] == 'Email') { $headers = 'From: Sender <andrej13@gmail.com>'; mail('andrej13@gmail.com', 'Subject', $_SESSION["cart"], $headers); echo "DEBdsUG".$_POST["cart"]; echo 'Your mail has been sent'; } else { echo 'Your mail was not sent'; } ?> this is the cart.php <?php // Include MySQL class require_once('inc/mysql.class.php'); // Include database connection require_once('inc/global.inc.php'); // Include functions require_once('inc/functions.inc.php'); // Start the session session_start(); // Process actions $cart = $_SESSION['cart']; $action = $_GET['action']; switch ($action) { case 'add': if ($cart) { $cart .= ','.$_GET['id']; } else { $cart = $_GET['id']; } break; case 'delete': if ($cart) { $items = explode(',',$cart); $newcart = ''; foreach ($items as $item) { if ($_GET['id'] != $item) { if ($newcart != '') { $newcart .= ','.$item; } else { $newcart = $item; } } } $cart = $newcart; } break; case 'update': if ($cart) { $newcart = ''; foreach ($_POST as $key=>$value) { if (stristr($key,'qty')) { $id = str_replace('qty','',$key); $items = ($newcart != '') ? explode(',',$newcart) : explode(',',$cart); $newcart = ''; foreach ($items as $item) { if ($id != $item) { if ($newcart != '') { $newcart .= ','.$item; } else { $newcart = $item; } } } for ($i=1;$i<=$value;$i++) { if ($newcart != '') { $newcart .= ','.$id; } else { $newcart = $id; } } } } } $cart = $newcart; break; } $_SESSION['cart'] = $cart; ?><!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en"> <head> <title>PHP Shopping Cart Demo &#0183; Cart</title> <link rel="stylesheet" href="css/styles.css" /> </head> <body> <div id="shoppingcart"> <h1>Your Shopping Cart</h1> <?php echo writeShoppingCart(); ?> </div> <div id="contents"> <h1>Please check quantities...</h1> <?php echo showCart(); ?> <p><a href="index.php">Back to bookshop...</a></p> <form action="mail.php" method="post"> <input type="submit" name="sendemail" value="Email" /> <input type="hidden" name="cart" value="<?= $cart; ?>" /> </form> </div> </body> </html> Hey, I'm trying to send a form input to a page, and then get the response (as in, the body) from that page without leaving my PHP script. So instead of when you normally submit a form and it will take you to the 'action="/somepage"'. I want it to get that information and bring it back to the original page. No navigation should happen. I'm almost certain this is possible, but the only thing I've found at the moment requires a custom addon - which, isn't on most hosting sites. Sorry if I haven't described this very well, but any help would be appreciated Thanks tree Hi guys, I am having a problem of deleting the rows in the database. I just receive two warnings of mysql_real_escape_string which they a Code: [Select] Warning: mysql_real_escape_string() [function.mysql-real-escape-string]: Access denied for user 'myusername'@'localhost' (using password: NO) in /home/username/public_html/mysite.com/delete.php on line 11 Warning: mysql_real_escape_string() [function.mysql-real-escape-string]: A link to the server could not be established in /home/username/public_html/mysite.com/delete.php on line 11 failed The error are jumping on this line: Code: [Select] return mysql_real_escape_string($value); Here it the full code: <?php session_start(); define('DB_HOST', 'localhost'); define('DB_USER', 'username'); define('DB_PASSWORD', 'password'); define('DB_DATABASE', 'databasename'); function clean($value) { return mysql_real_escape_string($value); } $id = clean($_GET['id']); if ($id != NULL) { $query = @mysql_db_query(_DB,"DELETE FROM table1 WHERE $id = 'id"); $deleted = @mysql_affected_rows(); if($deleted > 0) { echo("worked"); } else { echo("failed"); } }else{ echo("failed"); } @mysql_close($link); ?> I have input the correct password, so what's wrong?? Not sure if my title line was worded correctly, but here is what I am trying to understand... I need to hook my website up to a payment gateway to accept credit cards. After I package up the customer's payment details and send the payment gateway an XML string, their server supposedly sends back a request for more information OR it indicates a Pass/Fail message. This is where I am getting lost. If I send data over HTTPS using POST, then how am I supposed to receive a message back from them? It's not like we are on the telephone and there is a "live" link between my web server and theirs?! Can someone please explain how this works? Thanks, Debbie $msg = "testing message"; $to = "$email"; $subjects = "testing"; $mailheaders = "From : singapore \n"; mail($to, $subjects, $msg, $mailheaders); Received in the email From : server name Question is I need it to receive as my domain name (FROM). Not the server name (FROM). How do I only redirect the page when index.php is present? Hello, i want to send and receive data from https url. how it can be done in php? Thanks Hi, I have been exploring twilio for an app that should be able to receive and store a text message. Do I need a SMS gateway to accomplish this? Thank you V. i want receive this API JSON : "https://api.cryptowat.ch/markets/binance/btcusdt/ohlc" in PHP And put it in a variable . so i did this :
<?php $json= file_get_contents('https://api.cryptowat.ch/markets/binance/btcusdt/ohlc'); $json= json_decode($json , true); foreach ($json as $row){ $price = $row['86400'] ?? ""; print_r($price) ; } and its worked ! but i want to show a specific price like : 86400 / 1122 / 0 and i don't know how ? I have created a simple form that collects a comment or question from a visitor to my website. The problem is that if the visitor types: Your site looks Ok. I will get that message. But if the type: Your site needs "Work". I will get: Your site needs The script will not send the double quotes or anything after the double quotes What am I missing??? I have tried: addslashes() str_replace() preg_replace() with on change to the message. This is the script Code: [Select] <?php $recipient = $_POST['recipient']; $subject = $_POST['subject']; $first_name = $_POST['first_name']; $last_name = $_POST['last_name']; $senders_email_address = $_POST['senders_email_address']; $comments = $_POST['comments']; $mailheaders .= "To: Thin Dime Web. <$recipient>\n"; $mailheaders .= "From: $first_name $last_name <$senders_email_address>\n"; $body .= "Subject: $subject\n\n"; $body .= "Senders Name: $first_name $last_name\n"; $body .= "E-mail Address: $senders_email_address\n\n"; $body .= "The following Comments or Question came from a visitor to your website\n"; $body .= "\n"; $body .= "$comments\n"; mail("$recipient", "$subject", "$body", "$mailheaders"); ?> Hi, didnt know how to add this to the repository so can an admin move this please. this updated version will tell you still when you recieve a visitor but to identify who i have included so that it tracks the ip and tells you when its you!!! <?php // Script to email you when Google refers traffic to your site. $name=""; // add your name here $email_address=""; // add your email address here $keywords=""; $referrer=$_SERVER['HTTP_REFERER']; $known_ips = array( '01.01.01.01' => 'from the computer your are at now!', // etc. ); $ip = $_SERVER['REMOTE_ADDR']; if (array_key_exists($ip, $known_ips)) { $ip = $known_ips[$ip]; // you may want to use a different var name here now? } if( (stristr($referrer, "google")) && (stristr($referrer, "search")) ) { parse_str($referrer, $output); $keywords=$output['q']; $email_message="A visitor just arrived to the website after searching for '$keywords', Their IP address is '$ip'. ($referrer)"; mail ("$email_address","Google referred a visitor","$email_message"); } ?> hope it all works... give it a try and let me know. Hi, I'm working on a web application that will interact with an existing website from another company. On the other company's site, there will be a form (using POST) that has my web application as the action element. The user who clicked the submit button will be redirected to my site, where I need to receive the $_POST data from this form to process before redirecting into the web application. I have done work on the other side, using standard form posts to send data to another site, but I've never had to write the code for the receiving end. How do I receive the form data posted from the other website? Can I access the $_POST[''] array as I would with any normal same-site POST transaction? Please let me know if you need additional detail or if my question wasn't clear! I'm fast approaching deadlines and really appreciate your help! Thanks! I have code written for image uploading, but it doesn't allow multiple images on a single upload, and doesn't re-size. Anyone willing to share a good upload script that will do the following?: -Allow multiple image uploads (10+ per submission), -Re-size images on upload, and -Rename images. Thanks Brett Hi everyone, I have a page that i use to upload images to my website, i got a bit fed up of uploading one at a time so i decided to add multiple file fields to the form to upload multiple images at the same time. Im having a few problems, iv read up he http://www.php.net/manual/en/features.file-upload.multiple.php and it seems all i have to do is add [] to the form names to turn them into arrays. However when i come to upload the images, i keep getting the "$error[] = "Incorrect format!...." error from the code below. I cant seem to figure out what the problem is. Could anybody please point me in the right direction? <?php session_start(); $id = $_SESSION['id']; $connect = mysql_connect("localhost","leemp5_admin","p7031521"); mysql_select_db("leemp5_database"); $query = mysql_query("SELECT * FROM users WHERE id='$id'"); $row = mysql_fetch_assoc($query); $username = $row['username']; $submit = $_POST['submit']; $type = $_FILES['image']['type']; $size = $_FILES['image']['size']; $max_size = "1000"; $width = "100"; $height = "100"; $error = array(); function make_thumb($image_name,$filename,$new_width,$new_height) { $ext=getExtension($image_name); if(!strcmp("jpg",$ext) || !strcmp("jpeg",$ext)) $source_image=imagecreatefromjpeg($image_name); if(!strcmp("png",$ext)) $source_image=imagecreatefrompng($image_name); if(!strcmp("gif",$ext)) $source_image=imagecreatefromgif($image_name); $old_x=imageSX($source_image); $old_y=imageSY($source_image); $ratio1=$old_x/$new_width; $ratio2=$old_y/$new_height; if($ratio1>$ratio2) { $thumb_width=$new_width; $thumb_height=$old_y/$ratio1; } else { $thumb_height=$new_height; $thumb_width=$old_x/$ratio2; } $destination_image=ImageCreateTrueColor($thumb_width,$thumb_height); imagecopyresampled($destination_image,$source_image,0,0,0,0,$thumb_width,$thumb_height,$old_x,$old_y); if(!strcmp("jpg",$ext) || !strcmp("jpeg",$ext)) { imagejpeg($destination_image,$filename); } if(!strcmp("png",$ext)) { imagepng($destination_image,$filename); } if(!strcmp("gif",$ext)) { imagegif($destination_image,$filename); } imagedestroy($destination_image); imagedestroy($source_image); } function getExtension($str) { $i = strrpos($str,"."); if (!$i) { return ""; } $l = strlen($str) - $i; $ext = substr($str,$i+1,$l); return $ext; } if($submit) { $image=$_FILES['image']['name']; if ($image) { $filename = stripslashes($_FILES['image']['name']); $extension = getExtension($filename); $extension = strtolower($extension); if (($extension != "jpg") && ($extension != "jpeg") && ($extension != "png") && ($extension != "gif")) { $error[] = "Incorrect format! Please make sure your image is a .jpg, .jpeg, .png or .gif file."; } else { $size=getimagesize($_FILES['image']['tmp_name']); $sizekb=filesize($_FILES['image']['tmp_name']); if ($sizekb > $max_size*1024) { $error[] = "Your image is too big! The maximum upload size is 1MB."; } else { $image_name=time().'.'.$extension; $newname="uploads/" . $username . "/images/".$image_name; $copied = copy($_FILES['image']['tmp_name'], $newname); if (!$copied) { $error[] = "There was an error uploading your image. Please try again!"; } else { $thumb_name='uploads/' . $username . '/images/thumbs/thumb_'.$image_name; $thumb=make_thumb($newname,$thumb_name,$width,$height); } } } } else { $error[] = "Please select an image to upload!"; } if(empty($error)) { echo "Upload Successfully!<br />"; echo '<img src="'.$thumb_name.'">'; mysql_query("INSERT INTO images VALUES ('','$username','$image_name','','','','','uploads/$username/images/$image_name','uploads/$username/images/thumbs/thumb_$image_name','$type','$size')"); } else { echo implode($error); } } ?> <form method="post" enctype="multipart/form-data" action="upload_images.php"> <input type="file" name="image[]" /><br /> <input type="file" name="image[]" /><br /> <input type="file" name="image[]" /><br /> <input type="file" name="image[]" /><br /> <input type="file" name="image[]" /><br /> <input type="file" name="image[]" /><br /> <input type="submit" name="submit" value="Upload"> </form> Thanks files that upload during insert/submit form was gone , only files upload during the update remain , is the way query for update multiple files is wrong ? $targetDir1= "folder/pda-semakan/ic/"; if(isset($_FILES['ic'])){ $fileName1 = $_FILES['ic']['name']; $targetFilePath1 = $targetDir1 . $fileName1; //$main_tmp2 = $_FILES['ic']['tmp_name']; $move2 =move_uploaded_file($_FILES["ic"]["tmp_name"], $targetFilePath1); } $targetDir2= "folder/pda-semakan/sijil_lahir/"; if(isset($_FILES['sijilkelahiran'])){ $fileName2 = $_FILES['sijilkelahiran']['name']; $targetFilePath2 = $targetDir2 . $fileName2; $move3 =move_uploaded_file($_FILES["sijilkelahiran"]["tmp_name"], $targetFilePath2); } $targetDir3= "folder/pda-semakan/sijil_spm/"; if(isset($_FILES['sijilspm'])){ $fileName3 = $_FILES['sijilspm']['name']; $targetFilePath3 = $targetDir3 . $fileName3; $move4 =move_uploaded_file($_FILES["sijilspm"]["tmp_name"], $targetFilePath3); } $query1=("UPDATE semakan_dokumen set student_id='$noMatrik', email= '$stdEmail', surat_tawaran='$fileName', ic='$fileName1',sijil_lahir='$fileName2',sijil_spm= '$fileName3' where email= '$stdEmail'");
Just a quick question. I'm using the Live HTTP Headers add-on for Firefox that display all the HTTP headers etc. I'm writing an article on it and want to include a screenshot of it in action. Are there any headers that I should hide from the reader for security reasons? Thanks for any help. |