PHP - Parse A Url Parameter Hyperlink In An Echo
Hi there im trying to parse a url parameter in a hyperlink, i cant seem to get it to work, im sure its a problem with the braces.
This is the original code: Code: [Select] echo '<a href="http://localhost/swb/planet.php/"> <p class="rmoncalamari tmoncalamari">' . $moncalamari. "1-1-2-6".'</p></a>'; and i tried to modify it to parse the record id... Code: [Select] echo '<a href="http://localhost/swb/planet.php?recordID= '$row_cats['CatName'];/"> <p class="rmoncalamari tmoncalamari">' . $moncalamari. "1-1-2-6".'</p></a>'; If you could help me that would be ace. Thank you Similar TutorialsHi there, im trying to echo a hyperlink and parse a url parameter. Its not quite working as iam getting T-string error. If someone with fresh eyes could quickly glance for me that would be ace. Code: [Select] <?php if ($row_ship['PlayerName'] == '$_SESSION['MM_Username']'){ echo '<a href="ship_edit.php?recordID='.$row_Ship['ShipID'].'">Edit</a>';} ?> Thank You Hi there im using dream weaver and ive created a form that can be updated: Code: [Select] if ((isset($_POST["MM_update"])) && ($_POST["MM_update"] == "form1")) { $updateSQL = sprintf("UPDATE ships SET FleetName=%s, HealthA=%s, HealthB=%s WHERE ShipID=%s", GetSQLValueString($_POST['select'], "text"), GetSQLValueString($_POST['textfield'], "int"), GetSQLValueString($_POST['textfield2'], "int"), GetSQLValueString($_POST['hiddenField'], "int")); mysql_select_db($database_swb, $swb); $Result1 = mysql_query($updateSQL, $swb) or die(mysql_error()); $updateGoTo = "fleet.php"; if (isset($_SERVER['QUERY_STRING'])) { $updateGoTo .= (strpos($updateGoTo, '?')) ? "&" : "?"; $updateGoTo .= $_SERVER['QUERY_STRING']; } header(sprintf("Location: %s", $updateGoTo)); } I want to parse a parameter after its updated and directed to another page but i cant seem to get it to work: Code: [Select] $updateGoTo = "fleet.php?recordID=$row_Ship['FleetName']"; Please help Thanks What I have been attempting to do with no luck is utilize <?php echo $row_DetailRS1['NSN']; ?> as a hyperlink. The Hyperlink will point to another website http://www.logisticsinformationservice.dla.mil/webflis/pub/pub_search.aspx?niin=+++++++++++++ The 13 + signs would be populated with the 13 digit that is returned from <?php $info=$row_DetailRS1['NSN']; ?> Below is the complete code as it stands how. Any assistance with making this work is greatly appreciated. <A HERF="http://www.logisticsinformationservice.dla.mil/webflis/pub/pub_search.aspx?niin=<?php $info=$row_DetailRS1['NSN']; ?>"><?php echo $row_DetailRS1['NSN']; ?></A> One additional question. If I want a new page to open when the hyperlink is clicked would I add &newpage=1 to the end of the URL? Hello,
I recently posted here about an issue I was having with my database orientated products page.
I have now run into another problem where say if, /db.php was typed or /db.php?p=IDoNotExist was typed, it returns blank.
I have in my code the desired content to be displayed, but it just doesn't seem to want to make a show.
I was also wondering if it is possible to show different content for whatever the URL is, so for no parameter, the content about the products, and a non existent one, maybe "Product not found"?
Here is my code:
<?php $db=mysql_connect ("localhost", "webwibco_charlie", "Hello123") or die ('I cannot connect to the database because: ' . mysql_error()); $mydb=mysql_select_db("webwibco_products"); include("header.php"); $status = htmlspecialchars( @$_GET ['p'] ); if ($status == "floorpuzzles") { echo "<h1>Our Floor Puzzles</h1>"; $sql="SELECT ID, Name, Tags, Description, Category FROM products WHERE Category LIKE '%" . FloorPuzzles . "%'"; $result=mysql_query($sql); while($row=mysql_fetch_array($result)){ $Name =$row['Name']; $ID =$row['ID']; $Description =$row['Description']; echo "<div class=\"box\">"; echo "<h1>$Name</h1>"; echo "<div class=\"floorbox\"><a href=\"?p=$ID\"><img src=\"images/products/catalogue/big/floorpuzzles/$ID.jpg\" class=\"small\"></a></div>"; echo "<h2>$Description</h2>"; echo "</div>"; } ?> <? }else{ if ($status == $_GET["p"]) { $sql="SELECT ID, Name, Tags, Description, Pieces, Size, Barcode, Category FROM products WHERE ID = '" . $_GET['p'] . "'"; $result=mysql_query($sql); while($row=mysql_fetch_array($result)){ $Name =$row['Name']; $ID =$row['ID']; $Description =$row['Description']; $Pieces =$row['Pieces']; $Size =$row['Size']; $Barcode =$row['Barcode']; echo "<div class=\"1\">"; echo "<h1>$Name</h1>"; echo "<div class=\"bigbox\">"; echo "<div class=\"floorbox\"><img src=\"images/products/catalogue/big/floorpuzzles/$ID.jpg\" class=\"big\"></div>"; echo "</div>"; echo "</div>"; echo "<div class=\"2\">"; echo "<p>Puzzle Pieces: $Pieces</p> <p>Puzzle Size: $Size</p> <p>Barcode: $Barcode</p>"; echo "</div>"; } }else{ ?> <? echo"<h1>Our Products</h1> <p>Our jigsaw puzzles are hand cut by skilled craftsmen and therefore each one is unique with self-correcting pieces. There is a strict quality control process at all stages by our highly experienced staff. The puzzles are durable and provide fun and excitement, enhancing learning and a child’s development.<p> <p>All of our jigsaws are made using materials from sustainable resources grown in managed forests. Where possible we support companies in the UK and source our components locally, most of our suppliers are in the East Midlands, many in Derbyshire and Nottinghamshire. We keep packaging to a minimum and take our environmental and ethical responsibilities very seriously.</p> <p>Reducing waste and recycling was a way of life for us before it became fashionable. We are constantly searching for new ideas and consult teachers when developing our jigsaws, which are often used within the national curriculum.</p> <p>As well as making our own range, we manufacture for leading suppliers to the education market. Check for \"Made in Britain\" and it is probably made by us.</p> <p>We have a wide variety of products available for viewing, from classic floor puzzles to innovative inset trays. You can take a look at all our products on this page, simply use the navigation buttons to your left.</p>"; }} include("footer.php"); ?>The final echo is what I wish to be displayed on the URL without or with an invalid parameter. Here is my site URL: http://www.webwib.co...saws/search.php (note that only the "Floor Puzzles" category has content within it). Thank you in advance for assistance. I have the following code just to insert a username and hashed password into the database but somehow I am getting this error and I couldn't find out where I am doing it wrong...can someone please give me a hand?
I tried it in two ways and both errors...
the first few lines are just connecting database which worked fine and a password.php so I can use password_hash() with my php version
$hash = password_hash('xx', PASSWORD_BCRYPT, array('cost' => 10)); $username = 'xx'; $insertQuery = $db->prepare(" INSERT INTO et_todo (username, password) VALUES (:username, :hash) "); $insertQuery->execute(array( 'username' => $username, 'password' => $hash ));also tried $hash = password_hash('xx', PASSWORD_BCRYPT, array('cost' => 10)); $insertQuery = $db->prepare(" INSERT INTO et_todo (username, password) VALUES ('xx', :hash) "); $insertQuery->execute(array( 'username' => 'xx', 'password' => $hash )); OK, have no idea what's going on... I've done this a million times... why wont this output!?? I must have a major brain meltdown and dont know it yet!!! Code: [Select] <?php // this echoes just fine: echo $_POST['testfield']; // but this wont echo: echo if (isset($_POST['testfield'])) { $_POST['testfield'] = $test; } echo $test; /// or even this DOESNT echo either!: $_POST['testfield'] = $test; echo $test; ?> Hello I have one problem with fwrite() I have one script to get width and height from javascript and echo it with PHP. echo "Screen width is: ". $_GET['width'] ."<br />\n"; echo "Screen height is: ". $_GET['height'] ."<br />\n"; It works but i want to store the result in a file fwrite($info,"Height: $_GET['height'] <br />"); But then I get error Parse error: parse error, expecting `T_STRING' or `T_VARIABLE' or `T_NUM_STRING //////////////////////// it would be even better if I don't have to print the values but directly store them in $iinfo sorry if something similar was soved but those examples were different or i was unable to transform it to solve my problem hi all am new to this forum help me to overcome from this error Parse error: parse error, expecting `T_STRING' or `T_VARIABLE' or `T_NUM_STRING' in D:\wamp\www\quiz1\quiz1.php on line 12 Code: [Select] <?php include("contentdb.php"); $display = mysql_query("SELECT * FROM $table ORDER BY id",$db); if (!$submit) { echo "<form method=post action=$_SERVER['PHP_SELF']>"; echo "<table border=0>"; while ($row = mysql_fetch_array($display)) { $id = $row["id"]; $question = $row["question"]; $opt1 = $row["opt1"]; $opt2 = $row["opt2"]; $opt3 = $row["opt3"]; $answer = $row["answer"]; echo "<tr><td colspan=3><br><b>$question</b></td></tr>"; echo "<tr><td>$opt1 <input type=radio name=q$id value=\"$opt1\"></td><td>$opt2 <input type=radio name=q$id value=\"$opt2\"></td><td>$opt3 <input type=radio name=q$id value=\"$opt3\"></td></tr>"; } echo "</table>"; echo "<input type='submit' value='See how you did' name='submit'>"; echo "</form>"; } elseif ($submit) { $score = 0; $total = mysql_num_rows($display); while ($result = mysql_fetch_array($display)) { $answer = $result["answer"]; $q = $result["q"]; if ($$q == $answer) { $score++; } } echo "<p align=center><b>You scored $score out of $total</b></p>"; echo "<p>"; if ($score == $total) { echo "Congratulations! You got every question right!"; } elseif ($score/$total < 0.34) { echo "Oh dear. Not the best score, but don't worry, it's only a quiz."; } elseif ($score/$total > 0.67) { echo "Well done! You certainly know your stuff."; } else { echo "Not bad - but there were a few that caught you out!"; } echo "</p>"; echo "<p>Here are the answers:"; echo "<table border=0>"; $display = mysql_query("SELECT * FROM $table ORDER BY id",$db); while ($row = mysql_fetch_array($display)) { $question = $row["question"]; $answer = $row["answer"]; $q = $row["q"]; echo "<tr><td><br>$question</td></tr>"; if ($$q == $answer) { echo "<tr><td>»you answered ${$q}, which is correct</td></tr>"; } elseif ($$q == "") { echo "<tr><td>»you didn't select an answer. The answer is $answer</td></tr>"; } else { echo "<tr><td>»you answered ${$q}. The answer is $answer</td></tr>"; } } echo "</table></p>"; } ?> thanks in adavance Hi All, I'm trying to echo the response from an SLA query, the query works and returns the data when I test it on an SQL application.. but when I run it on my webpage it won't echo the result. Please help? <?php $mysqli = mysqli_connect("removed", "removed", "removed", "removed"); $sql = "SELECT posts.message FROM posts INNER JOIN threads ON posts.pid=threads.firstpost WHERE threads.firstpost='1'"; $result = mysqli_query($mysqli, $sql); echo {$result['message']}; ?> I am trying to put a href on a line to link me to another php module, but get an error: Parse error: parse error in C:\wamp\www\editpolicy.php on line 47 My code: while ($row2 = mysql_fetch_array($result2) ) { print "<tr><td>"; <a href='editpayment.php?payid=$row2[PaymentID]'>$row2[PaymentID]</a> .........THIS IS LINE 47 ??? print "</td><td>"; print $row2['Actioned']; print "</td><td align='right'>"; print $row2['PremiumPaidAmount']; print "</td><td align='right'>"; print $row2['Risk']; print "</td></tr>"; } echo "</select></td>\r\n </tr>\r\n \r\n <tr>\r\n <td align=\"right\">Total Views Allowed:</td>\r\n <td><input type=\"text\" id=\"ad_total_views\" style=\"width:50px;\" value=\"\" disabled=\"disabled\" /> <label><input type=\"checkbox\" checked=\"checked\" onclick=\"if(this.checked==true){$('#ad_total_views').val('');$('#ad_total_views').attr('disabled','disabled');}else{$('#ad_total_views').val('');$('#ad_total_views').removeAttr('disabled');$('#ad_total_views').focus()}\" />Unlimited</label></td>\r\n </tr>\r\n \r\n <tr>\r\n <td align=\"right\">Total Clicks Allowed:</td>\r\n <td><input type=\"text\" id=\"ad_total_clicks\" style=\"width:50px;\" value=\"\" disabled=\"disabled\" /> <label><input type=\"checkbox\" checked=\"checked\" onclick=\"if(this.checked==true){$('#ad_total_clicks').val('');$('#ad_total_clicks').attr('disabled','disabled');}else{$('#ad_total_clicks').val('');$('#ad_total_clicks').removeAttr('disabled');$('#ad_total_clicks').focus()}\" />Unlimited</label></td>\r\n </tr>\r\n </table></td>\r\n </tr>\r\n <tr bgcolor=\"#FFFFFF\">\r\n <td class=\"td_th\" align=\"center\">Smarty Code (Developer)</td>\r\n <td>{\$ads->getAdCode(<span id=\"smartycode\">1</span>)}</td>\r\n </tr>\r\n <tr bgcolor=\"#FFFFFF\">\r\n <td class=\"td_th\" align=\"center\"> </td>\r\n <td><input type=\"button\" value=\"Create New Campaign\" onclick=\"new_ad()\" /></td>\r\n </tr>\r\n </TBODY></TABLE>\r\n<br />\r\n\r\n<TABLE cellSpacing=1 cellPadding=4 width=\"100%\" border=0>\r\n <TBODY>\r\n <TR class=\"td_title\">\r\n <TD colSpan=7>Ad Campaigns</TD></TR>\r\n <TR bgColor=#ffffff>\r\n \r\n <TD width=\"10%\" align=\"center\" class=\"td_th\"> </TD>\r\n <TD width=\"4%\" align=\"center\" class=\"td_th\">ID</TD>\r\n <TD width=\"29%\" align=\"center\" class=\"td_th\">Campaign Name</TD>\r\n <TD width=\"12%\" align=\"center\" class=\"td_th\">Start Date</TD>\r\n <TD width=\"11%\" align=\"center\" class=\"td_th\">End Date</TD>\r\n <TD width=\"17%\" align=\"center\" class=\"td_th\">Viewed / Views Allowed</TD>\r\n <TD width=\"17%\" align=\"center\" class=\"td_th\">Clicked / Clicks Allowed</TD>\r\n </TR>\r\n "; $BoxSize = array("smallbox" = array("length" => 12, "width" => 10, "depth" => 2.5), "mediumbox" = array("length" => 30, "width" => 20, "depth" => 4), "largebox" = array("length" => 60, "width" => 40, "depth" => 11.5)); I have a log system that allows 10 logs on each side(Left and right). I am trying to make it so that the left side has the 10 most recent logs, then the right as the next 10. Any ideas? So I need to echo a row from my database with php, but where i need to echo is already inside an echo. This is my part of my code: $con = mysql_connect("$host","$username","$password"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("main", $con); $result = mysql_query("SELECT * FROM Vendor"); while($row = mysql_fetch_array($result)) { //I need to echo right here .................. but I get a blank page when I try this. Please Help. echo '<option value=$row['vendor_id']>'; echo $row['vendor_id']; echo '</option>'; } mysql_close($con); Result: A Blank page. Thanks in advance! Hi
I try to echo out random lines of a html file and want after submit password to whole content of the same html file. I have two Problems.
1st Problem When I echo out the random lines of the html file I don't get just the text but the code of the html file as well. I don't want that. I just want the text. How to do that?
for($x = 1;$x<=40;$x++) { $lines = file("$filename.html"); echo $lines[rand(0, count($lines)-1)]."<br>"; }I tried instead of "file("$filename.html");" "readfile("$filename.html");" But then I get the random lines plus the whole content. Is there anything else I can use instead of file so that I get the random lines of text without the html code?P.S file_get_contents doesn't work either have tried that one. 2nd Problem: As you could see in my first problem I have a file called $filename.html. After I submit the value of a password I want the whole content. But it is like the program did forget what $filename.html is. How can I make the program remember what $filename.html is? Or with other words how to get the whole content of the html file? My code: if($_POST['submitPasswordIT']){ if ($_POST['passIT']== $password ){ $my_file = file_get_contents("$filename.html"); echo $my_file; } else{ echo "You entered wrong password"; } }If the password isn't correct I get: You entered wrong password. If the password is correct I get nothing. I probably need to create a path to the file "$filename.html", but I don't know exactly how to do that. Code: [Select] This is a clip of my PHP file: <?php $con = mysql_connect($host,$username,$password); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db($database, $con); $result = mysql_query("SELECT * FROM purchase_order WHERE purchase_order_number=='$purchase_order_number'"); while($row = mysql_fetch_array($result)) { $vendor=$row['vendor']; $purchase_order_date=$row['purchase_order_date']; $ship=$row['ship']; $state=$row['state']; $fob=$row['fob']; $terms=$row['terms']; $buyer=$row['buyer']; $freight=$row['freight']; $req_date=$row['req_date']; $confirming_to=$row['confirming_to']; $remarks=$row['remarks']; $tax=$row['tax'] } // [i][u][b]<-- This is line 88 (The one with the error)[/b][/u][/i] ?>Thanks in advance! Hey guys Just a quick question: How to embed hyperlink into a database cell? Basically I echo out a table on the user interface of my site and there's an URL in one of the cells I want the user to access it by clicking on it, without copying and pasting the URL into the URL bar of the browser I tried updating the cell in phpmyadmin using <a href = http://www.example.com>http://www.example.com</a> but didn't work out, the resulting cell only had the text format Any help would be appreciated Thanks. Hello im wondering how i can make a hyperlinks adress be a set after a variable. this is my php: $result1 = mysql_query("SELECT id, namn, url FROM stuff ORDER BY id desc limit 1;"); $result2 = mysql_query("SELECT id, namn, url FROM stuff ORDER BY id desc limit 1,1;"); <html> <a href="???"> <p class="note-general"> The first link </p> <a href="???"> <p class="note-general"> The the second link </p> </html> The important thing is that the url from $result1 will link under "the first link" and url from $result2 link under "the second link". I am having problems with a line of code. This is what I have so far. I am missing a "," according to my error message. Im trading in deep water with this line of code. I am trying to use the data from my echo state to be a hyperlink... If that makes sense. Code: [Select] echo "\t" . '<td><a href="' . APP_ROOT . 'onlinebanking/viewtransactions.php">. $account['BankAccountID'] . </a>' '</td>' . "\n"; Hello Everyone. Im new here, but hopefully you can help me I have designed a CMS using PHP and MySQL. Its fairly basic, I'll talk you thorugh the stages: 1.) The user inputs their product information into a form and the script uploads it to the database giving it a unique ID. 2.) The user is then asked to upload a big image for that product, the image is added to a folder on the server. 3.) Now the user must choose a thumbnail and it uploads in the same manner. My problem is linking the two together... So far I have this: <?php $images = "products/"; $big = "big/"; $cols = 2; if ($handle = opendir($images)) { while (false !== ($file = readdir($handle))) { if ($file != "." && $file != ".." && $file != rtrim($big,"/")) { $files[] = $file; } } closedir($handle); } $colCtr = 0; echo '<table width="212" cellpadding="2"><tr>'; foreach($files as $file) { if($colCtr %$cols == 0) echo '</tr><tr><td colspan="2"></td></tr><tr>'; echo '<td wdith=50% align="center"><a href="' . $images . $big . $file . '"><img border="0" class="gradualfader" src="' . $images . $file . '" /></a></td>'; $colCtr++; } echo '</table>' . "\r\n"; ?> This displays a lovely list of thumbnails, which when clicked opens the larger image. What i would like to do is insert a "ID" for each image so the product data can be grabbed from the database ? I think i've explained this well enough? reply if not and illl try and add more detail. To see it in action you can go to http://design.surreylabs.co.uk/parliament/2/products.php Thanks in Advance! |