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PHP - Insert In Mysql Array Value From Drop Select Box Value - Cannot Pass The Var
I am simply trying to insert a value generated from an array in a while loop, but it seems the value is not global and I can't pass it as I like. I did some research on this, but could not find an answer that solved my issue...
Here is my select box code which is working perfect: <select name="city"> <?php $sql = "SELECT id, city_name FROM cities ". "ORDER BY city_name"; $results_set = (mysqli_query($cxn, $sql)) or die("Was not able to produce the result set!"); while($row = mysqli_fetch_array($results_set)) { echo "<option value=$row[id]>$row[city_name]</option>"; } ?> </select> Are any variables defined in a while loop global to the while loop only? Here is my SQL which you can see my $row[id] being passed thru field city_id... The value is being generated as supposed to based on value like: value="1", value="2" etc.. for the select options for each city name. So the values are there... But I CANNOT get that numerical id to pass to the database when submitting my form. Any ideas for a workaround to get this value passing as normal? if (isset($_POST['addPosting'])) { $query = "INSERT INTO Postings (id, city_id, title, description) VALUES ('','$row[id]','$_POST[title]','$_POST[description]')"; Similar TutorialsI have a simple ajax that passes data to a php script using jquery serialize. This is working good but where I am getting stuck is trying to pass json array into mysql. The json is outputting the correct data, but when I insert into db, it just says Array in the field. How can I convert(if that is the right term) json array to use in mysql. In the code I have posted, $box is an array from jquery which I normally use foreach to loop through array. What I need to do is convert $box after is has been encoded. Thanks Code: [Select] $box = $_POST['BRVbrtrv_boxnumber']; $list = array("activity" => $activity, "mobile" => $mobile, "company" => $company, "authorised" => $authorised, "service" => $service, "department" => $department, "address" => $address, "boxcount" => $boxcount, "box" => $box); $c = json_encode($list); echo $c; I'm a newbie on php. I'm really a system administrator and I was just task to do this simple task. For me its hard but I'm sure for a programmer this is very simple. My agenda is to pull out data on one of my column in mysql, select it and dump it on mysql. Here is the php for retrieving mysql data Code: [Select] <?php function database_connect($users) { $resource_link = mysql_connect("localhost", "root", "root"); if (mysql_select_db($users, $resource_link)) { return $resource_link; } else { echo "Cannot connect to DB"; return false; } } function print_dropdown($query, $link){ $queried = mysql_query($query, $link); $menu = '<select username="username">'; while ($result = mysql_fetch_array($queried)) { $menu .= ' <option value="' . $result['id'] . '">' . $result['username'] . '</option>'; } $menu .= '</select>'; return $menu; } //Some other form elements, or just start a form. echo '<form method="post" action="create2.php">'; //The important bit echo print_dropdown("SELECT username FROM mailbox;", database_connect("users")); //Some other form elements, or just end the form. echo '<input type="submit" name="submit" value="submit"/></form>'; Here is the content of my create2.php. This is the php page who do the insert on my mysql. Code: [Select] <?php // open the connection $conn = mysql_connect("localhost", "root", "root"); // pick the database to use mysql_select_db("users",$conn); // create the SQL statement $sql2 = "INSERT INTO mailbox values ('','locked','','$_POST[username]','',NOW(),'','locked','')"; // for troubleshooting $result = mysql_query($sql2, $conn) or die(mysql_error()); // execute the SQL statement //if (mysql_query($sql2, $conn)) { // echo "Success"; //} else { // echo "Fail"; //} } ?> When I click the submit button, I don't see any record being inserted on my table. I'm using the create2.php on my other page though it is only an insert/fill up form not like this one that I need to pull up the date, select and insert to mysql. I am trying to insert a date into a mySQL table from html drop downs with php. Right now when I enter the date it goes into the database as 0000-00-00. Can anybody see why it might be doing this? My html: Code: [Select] <label for='birthdate' >Birthdate (Optional):</label><br/> <select name='month' id='month' value='<?php echo $fgmembersite->SafeDisplay('month') ?>'> <option value="01" selected="January">January</option> <option value="02">February</option> <option value="03">March</option> etc... </select> <select name='day' id='day' value='<?php echo $fgmembersite->SafeDisplay('day') ?>'> <option value="01" selected="1">1</option> <option value="02">2</option> <option value="03">3</option> etc... </select> <select name='year' id='year' value='<?php echo $fgmembersite->SafeDisplay('year') ?>'> <option value="2010" selected="2010">2010</option> <option value="2009">2009</option> <option value="2008">2008</option> etc... </select> And my php to collect info: Code: [Select] $formvars['birthdate'] = $this->Sanitize($_POST['year'], $_POST['month'], $_POST['day']); php where I make table: Code: [Select] "birthdate DATE NOT NULL ,". php to insert into mysql: Code: [Select] $insert_query = 'insert into '.$this->tablename.'( name, address, birthdate, sex, program, guide, email, username, password, confirmcode ) values ( "' . $this->SanitizeForSQL($formvars['name']) . '", "' . $this->SanitizeForSQL($formvars['address']) . '", "' . $this->SanitizeForSQL($formvars['birthdate']) . '", "' . $this->SanitizeForSQL($formvars['sex']) . '", "' . $this->SanitizeForSQL($formvars['program']) . '", "' . $this->SanitizeForSQL($formvars['guide']) . '", "' . $this->SanitizeForSQL($formvars['email']) . '", "' . $this->SanitizeForSQL($formvars['username']) . '", "' . md5($formvars['password']) . '", "' . $confirmcode . '" )'; Thank you! I am trying to update a mysql table called AvItems with the value 'Torso' in the Equip "section?" I have been through the forums and cannot see anything to match. I dont mind if the page looses the onsubmit() and has a button instead. Though I would like to update the database and link back to the same page: There is a display that shows the item that is currently equiped, I have put this in to show it works, or doesn't as the case may be. Hope I got the code /code right this time. many thanks in advance Andy Curtis Code: [Select] create table Items( ItemID integer unsigned auto_increment primary key, ItemName varchar(20) not null, Type varchar(10), UsedOn varchar(10), ); create table AvItems( AvItemID integer unsigned auto_increment primary key, AvID integer unsigned, ItemID integer unsigned, Equip varchar(8)); <?php $username="root"; $password="MyPassword"; $database="MyDataBase"; $AvName = "AndyJCurtis"; mysql_connect(localhost,$username,$password); @mysql_select_db($database) or die( "Unable to select database"); $AvAccR = mysql_query( " SELECT AvID FROM AvAcc WHERE AvName = '$AvName' " ); $AvID = mysql_result($AvAccR, 0, 'AvID'); /////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////// $Torso = mysql_query(" select ItemName from AvItems, Items where AvItems.itemID = Items.itemID AND AvItems.AvID = '$AvID' AND UsedON = 'Body' "); $TorsoE = mysql_query(" select ItemName from AvItems, Items where AvItems.itemID = Items.itemID AND AvItems.AvID = '$AvID' And UsedON = 'Body' AND Equip = 'Body' "); if(mysql_num_rows($TorsoE) != 0) { $TorsoItem = mysql_result($TorsoE ,0,"ItemName"); //mysql_close(); ?> <title></title> <head></head> <body> <form action="http://localhost/CI/Equip2.php" method="post"> <table border=1> <tbody> <tr> <td>Torso<BR> <?PHP echo "$TorsoItem <BR>"; ?> <select name="Torso" onchange="submit();" value =" Update"> <?PHP while($TorsoRow = mysql_fetch_array($Torso)) { echo "<option value=\"".$TorsoRow['ItemName']."\">".$TorsoRow['ItemName']."\n </option>"; } ?> </select> </td> </tr> //////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////// <?php if($_POST['Torso'] == 'Update') { mysql_query("update AvItems set Equip = '' where Equip='Torso'") or die("cant update unequip"); mysql_query("update AvItems set Equip = 'Torso' where ItemID='{$_POST['ItemName']}'") or die("cant update equip"); } ?> /////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////////// </tbody> </table> </.form> </body> </html> I'm trying to insert array of posts categories into MySQL. I'm getting category IDs from drop down list.. ERR: Notice: Notice: Array to string conversion in C:\laragon\*********\includes\functions.php on line 477
Array
Array
(
[0] => Array
(
[0] => 4
[1] => 5
)
)
PHP
try {
$sql = "INSERT INTO posts_category_ids (post_id, category_id) VALUES";
$insertQuery = array();
$insertData = array();
foreach ($filter_category as $row) {
$insertQuery[] = '(?, ?)';
$insertData[] = $id;
$insertData[] = $row;
}
if (!empty($insertQuery)) {
$stmt = $this->conn->prepare($sql);
$stmt->execute($insertData); //477
}
}catch (Exception $e){
echo $e->getMessage();
}
}
Hello, I have been at this for awhile now and cant seem to figure it out. I have 2 separate arrays like shown below and I am trying to insert each value into my database using one update query. I have tried a for loop inside each array, but only one column populates. I have tried breaking the values outside their for loop, etc, etc. Does anyone know a way this can be done? Code: [Select] //Cars $cars = array('ford', 'toyota', 'bmw'); //Places $places =arrray('Orlando','California','Texas'); foreach ($cars as $car){ foreach ($places as $place){ $place .=$place; } mysql_query("INSERT INTO vehicles (cars, places) VALUES ('" . $car. "', '" . $place . "'')"); } I have tried many ways of storing an array of data that comes from a multiple selection form into a mysql table, including serialization. I am currently trying to do it by forming a string, and using the string in the insert query, but keep getting errors, or just nothing happening. I am not sure what I am doing wrong. Code: [Select] $categoryString = array(); if ($categoryArray){ foreach ($categoryArray as $category){ $categoryString[] = $category.'<br />';} } $categoryquery= "INSERT INTO categoryname VALUES('$categoryString')"; mysql_query($categoryquery); Thank you for your time as always. hi guys so i have this add contacts page and the form is divided into 3 different froms 1) primary contact 2)spouse 3)child and the child form data is inserted as array into database because in the primary contact part of the form there is a "Children ?" with yes and no radio button and if yes a drop down list is enabled where if user chooses say 2 then there would be 2 child form that appears. and since theres 2 children then in the database a new row and data will be added accordingly.
image attached to be clearer.
from2.jpg 24.15KB
0 downloads
i got it inserted into database but in the specified field it says array: |child_name|dob|house_add1|mobile|office|email| inserted: |array|array-array-array|array|array|array|array| query:
"INSERT INTO child VALUES('','".$childsalutations." $childfname $childlname',' ".$cday."-".$cmonth."-$cyear ','$childline1','$childline2','$childm','$childoff','$childemail')"
in a stackoverflow question(not my own question) someone says: information stating arrays need to be split, before inserting into the table. does that mean something like this?:
$cday = ($_POST['cday']);
$cmonth = ($_POST['cmonth']);
$cyear = ($_POST['cyear']);
$childsalutations = ($_POST['child-salutations']);
$childfname = ($_POST['child-fname']);
$childlname = ($_POST['child-lname']);
$childline1 = ($_POST['child-line1']);
$childemail = ($_POST['child-email']);
$childm = ($_POST['child-mobile']);
$childoff = ($_POST['child-office']);
$info = array('c_name' => $childsalutation $childfname $childlname, 'c_dob' => $cday-$cmonth-$cyear, 'c_line1' => $childline1, 'c_mobile' => $childm, 'c_office' => $childoff, 'c_email' => $childemail)
just in case u wanted to c the html child form(warning its abit long,very!):
<table class="prime"> <tbody> <br> <tr><td style="font-size:20px;font-weight:bold">Child <span id="number"></span></td></tr> <tr> <td>Salutation :</td> <td><select name="child-salutations[]" id="child-salutations"> <option value="" disabled selected>Salutations</option> <option value="Datin">Datin</option> <option value="Datin Paduka">Datin Paduka</option> <option value="Dato Paduka">Dato Paduka</option> <option value="Dato'">Dato'</option> <option value="Dato' Seri">Dato' Seri</option> <option value="Datuk">Datuk</option> <option value="Datuk Seri">Datuk Seri</option> <option value="Dr.">Dr.</option> <option value="Haji">Haji</option> <option value="Hajjah">Hajjah</option> <option value="HM">HM</option> <option value="HRH">HRH</option> <option value="Miss">Miss</option> <option value="Mrs.">Mrs.</option> <option value="Mr.">Mr.</option> <option value="Pehin">Pehin</option> <option value="Professor">Professor</option> <option value="Raja">Raja</option> <option value="Tan Sri">Tan Sri</option> <option value="Tengku">Tengku</option> <option value="Tuanku">Tuanku</option> <option value="Tun">Tun</option> <option value="Tunku">Tunku</option> <option value="Ungku">Ungku</option> </select> </td> </tr> <tr><td colspan="2"><label class="label" style="color:Red">*If a person has many salutations, choose the highest form of salutation</label></td></tr> <tr><td>First Name :</td><td><input type="text" name="child-fname[]" id="child-fname" class="style" /></td> <td>Last Name :</td><td><input type="text" name="child-lname[]" id="child-lname" class="style" /></td></tr> <tr> <td>Date of Birth : </td> <td> <select name="cday[]"> <option value=""selected disabled>Day</option> <option value="1">1</option> <option value="2">2</option> <option value="3">3</option> <option value="4">4</option> <option value="5">5</option> <option value="6">6</option> <option value="7">7</option> <option value="8">8</option> <option value="9">9</option> <option value="10">10</option> <option value="11">11</option> <option value="12">12</option> <option value="13">13</option> <option value="14">14</option> <option value="15">15</option> <option value="16">16</option> <option value="17">17</option> <option value="18">18</option> <option value="19">19</option> <option value="20">20</option> <option value="21">21</option> <option value="22">22</option> <option value="23">23</option> <option value="24">24</option> <option value="25">25</option> <option value="26">26</option> <option value="27">27</option> <option value="28">28</option> <option value="29">29</option> <option value="30">30</option> <option value="31">31</option> </select> <select name="cmonth[]"> <option value="" selected disabled>Month</option> <option value="1">January</option> <option value="2">February</option> <option value="3">March</option> <option value="4">April</option> <option value="5">May</option> <option value="6">June</option> <option value="7">July</option> <option value="8">August</option> <option value="9">September</option> <option value="10">October</option> <option value="11">November</option> <option value="12">December</option> </select> Year : <input type="text" name="cyear[]" maxlength="4" size="4" class="year"> </td> </tr> <tr><td>Where do they live ?</td><td colspan="3"><input type="radio" name="living[]" id="living-me" class="living-me"/>With Me<input type="radio" name="living[]" id="living-other" class="living-other"/>With Other Parent<input type="radio" name="living[]" id="living-own" class="living-own"/>Own</td></tr> <tr><td>House Address</td></tr> <tr><td>Line 1 :</td><td><input type="text" name="child-line1[]" id="child-line1" size="20" class="style" /></td> <td>Mobile No :</td><td><input type="text" name="child-mobile[]" id="child-mobile" class="style" /></td></tr> <tr><td>Office No :</td><td><input type="text" name="child-office[]" id="child-office" class="style" /></td> <td>Email Address : </td><td><input type="email" name="child-email[]" id="email" class="style" /></td></tr> </tbody> </table> Hi, I have an 2 arrays ( $match[1] and $match[2] ) with 50+ fields that i need to insert into a database, but im not getting how i could do it. Until now im trying with with the following code: Code: [Select] $sql="INSERT INTO is_trigger_reference (triggerName) VALUES ('$match[2][0]')"; mysql_query($sql) or die(mysql_error()); But when i check into the db table i only got: Code: [Select] triggername ( field name ) Array[0] ( data inserted) I know i can set a var to each array ( 40+ ) but i belive there's something more clean than that Thanks! Hi I have tried the mysql forum but have had no joy with an answer to my problem so wondered if php would be better. I want my users to be able to select from 5 different drop down lists where they can chose any combination from 1 up to all 5, I have attached the front end. These lists are being populated from mysql tables. Code for the drop down lists is as follows Code: [Select] <form action="horse-events-devon.php?url_countyid=<?php echo urlencode ($url_countyid ['url_countyid']) ; ?>&go" method="POST"> <table id="searchtable"> <tr> <th>Find By Discipline</th> <th>Find By Venue</th> <th>Find By Championship</th> <th>Find By Organiser</th> <th>Equine Association</th> <th>Submit Your Selections</th> </tr> <tr> <td><select name="dis_id"> <?php $upcomingdis = upcomingdis($url_countyid); $upcoming_dis_bycounty = mysql_fetch_assoc ($upcomingdis); ?> <?php do { ?> <option value="<?php echo $upcoming_dis_bycounty ['dis_id']; ?>" > <?php echo $upcoming_dis_bycounty ['dis_description']; ?></option> <?php } while ($upcoming_dis_bycounty = mysql_fetch_assoc ($upcomingdis)); ?></select></td> <td><select name="ven_id"> <?php $upvenbycounty_set = upcoming_venevents_bycounty($url_countyid); $upcoming_ven_bycounty = mysql_fetch_assoc ($upvenbycounty_set); ?> <?php do { ?> <option value="<?php echo $upcoming_ven_bycounty ['ven_id']; ?>" > <?php echo $upcoming_ven_bycounty ['ven_name']; ?></option> <?php } while ($upcoming_ven_bycounty = mysql_fetch_assoc ($upvenbycounty_set)); ?></select></td> <td><select name="champ_id"> <?php $championship_set = findchampionships(); $champlist = mysql_fetch_assoc ($championship_set); ?> <?php do { ?> <option value="<?php echo $champlist ['champ_id']; ?>" > <?php echo $champlist ['champ_description']; ?></option> <?php } while ($champlist = mysql_fetch_assoc ($championship_set)); ?></select></td> <td> <select name="org_id"> <?php $uporgbycounty_set = upcoming_organevents_bycounty($url_countyid); $upcoming_org_bycounty = mysql_fetch_assoc ($uporgbycounty_set); ?> <?php do { ?> <option value="<?php echo $upcoming_org_bycounty ['org_id']; ?>" ><?php echo $upcoming_org_bycounty ['org_name']; ?></option> <?php } while ($upcoming_org_bycounty = mysql_fetch_assoc ($uporgbycounty_set)); ?></select> </td> <td><select name="ass_id"> <?php $upassbycounty_set = upcoming_assevents_bycounty($url_countyid); $upcoming_assbycounty = mysql_fetch_assoc ($upassbycounty_set); ?> <?php do { ?> <option value="<?php echo $upcoming_assbycounty ['ass_id']; ?>" > <?php echo $upcoming_assbycounty ['ass_description']; ?></option> <?php } while ($upcoming_assbycounty = mysql_fetch_assoc ($upassbycounty_set)); ?></select></td> <td><input name="submit" type="submit" /><input name="countyid" type="hidden" value="<?php echo $url_countyid ['url_countyid']; ?>" /></td> </tr> </table> </form> My search processing is as follows Code: [Select] <?php if (isset($_POST['submit'])){ if (isset($_GET['go'])){ $countyid = $_POST['countyid']; $ven_id = $_POST['ven_id']; $dis_id = $_POST['dis_id']; $champ_id = $_POST['champ_id']; $org_id = $_POST['org_id']; $event_id = $row['event_id']; $sql = "SELECT DATE_FORMAT (events.startdate, '%a, %d, %b') AS stdate, events.event_id, events.title, events.ven_id, events.org_id, venue.county_id, venue.ven_id, eventdisciplines.event_id, eventdisciplines.dis_id, county.county_id, discipline.dis_id \n" . "FROM events \n" . "LEFT OUTER JOIN eventdisciplines \n" . "ON events.event_id = eventdisciplines.event_id \n" . "LEFT OUTER JOIN discipline \n" . "ON eventdisciplines.dis_id = discipline.dis_id \n" . "LEFT OUTER JOIN venue \n" . "ON events.ven_id = venue.ven_id \n" . "LEFT OUTER JOIN county \n" . "ON venue.county_id = county.county_id \n" . "WHERE events.ven_id = ({$ven_id} OR events.org_id = {$org_id})\n" . "AND events.startdate > NOW()\n" . "AND venue.county_id = {$countyid} \n" . "ORDER BY startdate ASC"; $result = mysql_query ($sql, $connection); ?> How am I best to do this please? my OR within the mysql does not work, should I not be doing this with php in the search processing? someones help would really be appreciated, just to point me in the right direction. [attachment deleted by admin]
An affiliate marketer refers some products which are stored in a simple array. $all_items_sold = '{"7777":{"item":"hammer","price":"4.99"},"8888":{"item":"nail","price":"1.99"},"9999":{"item":"apple","price":"2.00"}}';
$referred_by_Affiliate = array('1234','8888','7777');
So, out of all the 3 items that sold, only 2 of them were referred by the affiliate marketer.
Currently I do this:
Is there a "best practices" way to accomplish this?
Thank you. Hi again all, Why does the foreach loop im doing, put the array values from collection, into seperate table rows rather than 1 row per whole array? <?php class registration{ public $fields = array("username", "email", "password"); public $data = array(); public $table = "users"; public $dateTime = ""; public $datePos = 0; public $dateEntryName = "date"; public $connection; function timeStamp(){ return($this->dateTime = date("Y-m-d H:i:s")); } function insertRow($collection){ //HERE foreach($this->fields as $row => $value){ mysql_query("INSERT INTO $this->table ($value) VALUES ('$collection[$row]')"); } mysql_close($this->connection->connectData); } function validateFields(){ $this->connection = new connection(); $this->connection->connect(); foreach($this->fields as $key => $value){ array_push($this->data, $_POST[$this->fields[$key]]); } $this->dateTime = $this->timeStamp(); array_unshift($this->data, $this->dateTime); array_unshift($this->fields, $this->dateEntryName); foreach($this->data as $value){ echo "$value"; } $this->insertRow($this->data); } } $registration = new registration(); $registration->validateFields(); ?> I end up with 3 rows row 1: username row 2: email row 3 : password rather than row 1:username email password. Here is my query: Code: [Select] $db->query("SELECT cache.*,u.username from search_cache cache LEFT Join users as u ON u.id = 'NEED HELP HERE' where ident = '{$username}' ORDER BY DATE DESC") or error('Unable to send the message.', __FILE__, __LINE__, $db->error()); Here is my data inside my search_cache Here is my while loop: Code: [Select] while($recent = $db->fetch_assoc($rec)){ $data = unserialize($recent['search_data']); } Now I can use $data['search_type'] as a array and If I use echo $data['search_type']['2'] it echo's out the user_id 32 as seen in the screenshot at the very end. Problem is, I want to use that 'NEED HELP HERE' to join with that id 32 dynamically, how the hell is that possible with mysql or is it? Or would it be easier to just add a new row/column named user_id and just join of that instead of trying to do all this? would that be faster? Hi, I have come up with the following code, I need it to get the details of several scattered products and echo the results, the trick is I don't want it to echo the results one after the other... I want to have the products scattered between unique text on the page but don't want to run the query several times for performance reasons. E.g.- PAGE to look like this: $Product_1 unique text/images $Product_2 $Product_3 unique text/images $Product_4 Current Code: Code: [Select] <? $result = mysql_query("SELECT * FROM products where Product_ID IN (475, 465, 234, 567, 845)"); while($row = mysql_fetch_array($result)) { $x = "1"; while ($x<=3) { echo $x; $Product = "Product_"; $Product = $Product.$x; echo $Product; $Product = $row['Product_ID']; echo $Product; $x++; echo $x; } } At the moment it returns the following results: Quote 1 Product_1 465 2 2 Product_2 465 3 3 Product_3 465 4 1 Product_1 475 2 2 Product_2 475 3 3 Product_3 475 4 A few problems... In Blue... it duplicates for product 465 In Red... It repeats again for 475 Also.... it starts with 465, but I want it to go in order as how it appears - $result = mysql_query("SELECT * FROM products where Product_ID IN (475, 465, 234, 567, 845)"); so should start with 475 I want to get the following result: Quote 1 Product_1 475 2 2 Product_2 465 3 3 Product_3 234 4 4 Product_4 567 4 (and so on.....) If anyone could provide me assistance with my troubled 'while loop' statement that would be much appreciated! I'm trying to pass php select option value to another page through url.but it's not working.please help me.
member.php
<?php
mysql_connect("localhost","root","") or die(mysql_error());
mysql_select_db("nordfxlk_member")or die(mysql_error());
$result = mysql_query("SELECT id,ugroup FROM ugroups");
?>
<select name='group' id='group' >
<?php
while ($line = mysql_fetch_array($result)) {
echo '<option value=' . $line['ugroup'] . '>' . $line['ugroup'] . '</option>';
}?>
</select>
<a href="db_sql/add_group.php?ugroup=<?php echo $line['ugroup'] ;?>"> click</a>
add_group.php
include('../limoconfig.php');
if(!isset($_SESSION['adminuserid']) )
{
header('Location:../index.php');
}
else
{
$ugroup = $_GET['ugroup'];
/*$id = $_GET['id'];*/
$acc_status = "update users set ugroup='".$ugroup."' where id=1931";
echo $acc_status;
$rate = db::getInstance()->exec($acc_status);
header('Location:../test.php');
}
}
Can anyone tell me why this is not INSERTing? My array data is coming out just fine.. I've tried everything I can think of and cannot get anything to insert.. Ahhhh! <?php $query = "SELECT RegionID, City FROM geo_cities WHERE RegionID='135'"; $results = mysqli_query($cxn, $query); $row_cnt = mysqli_num_rows($results); echo $row_cnt . " Total Records in Query.<br /><br />"; if (mysqli_num_rows($results)) { while ($row = mysqli_fetch_array($results)) { $insert_city_query = "INSERT INTO all_illinois SET state_id=$row[RegionID], city_name=$row[City] WHERE id = null" or mysqli_error(); $insert = mysqli_query($cxn, $insert_city_query); if (!$insert) { echo "INSERT is NOT working!"; exit(); } echo $row['City'] . "<br />"; echo "<pre>"; echo print_r($row); echo "</pre>"; } //while ($rows = mysqli_fetch_array($results)) } //if (mysqli_num_rows($results)) else { echo "No results to get!"; } ?> Here is my all_illinois INSERT table structu CREATE TABLE IF NOT EXISTS `all_illinois` ( `state_id` varchar(255) NOT NULL, `city_name` varchar(255) NOT NULL ) ENGINE=MyISAM DEFAULT CHARSET=latin1; Here is my source table geo_cities structu CREATE TABLE IF NOT EXISTS `1` ( `CityId` varchar(255) NOT NULL, `CountryID` varchar(255) NOT NULL, `RegionID` varchar(255) NOT NULL, `City` varchar(255) NOT NULL, `Latitude` varchar(255) NOT NULL, `Longitude` varchar(255) NOT NULL, `TimeZone` varchar(255) NOT NULL, `DmaId` varchar(255) NOT NULL, `Code` varchar(255) NOT NULL ) ENGINE=MyISAM DEFAULT CHARSET=latin1; Hi I am looking to be able to pass an array to mysql_fetch_row() not sure where i am going wrong. works fine like this. Code: [Select] mysql_select_db($DB_NAME); $new = mysql_query("SELECT * FROM {$DB_TABLE}"); if (!$new) { echo 'MySQL Error: ' . mysql_error(); exit; } $row = mysql_fetch_array($new); while ($row = mysql_fetch_array($new)) { echo $row['username'] . $DELIMITER . $row['firstname'] . $DELIMITER . $row['lastname'] . $DELIMITER . $row['password'] . $DELIMITER. "example@gmail.com" . $DELIMITER . "author"; echo "<br />"; } But really need too be able to do it this way. Code: [Select] mysql_select_db($DB_NAME); $new = mysql_query("SELECT * FROM {$DB_TABLE}"); if (!$new) { echo 'MySQL Error: ' . mysql_error(); exit; } $row = mysql_fetch_array($new); echo "<pre>"; //print_r($row); echo "</pre>"; $sam = array('username','firstname','lastname'); while ($row = mysql_fetch_row($new)) { echo $row[$sam] . $DELIMITER; echo "<br />"; } So it will just loop through the array so i can keep adding to it by just adding an extra parameter to the array. Any Help Stuck???? You guys are great, thanks again for the help last week. Now I almost got this working but a small hiccup. here is my code: Code: [Select] <?php include("config.php"); $my_t=getdate(date("U")); $my_t1=$my_t[weekday]; $result = mysql_query("SELECT * FROM tourney where day_of_week = '$my_t1'") or die(mysql_error()); if ($result == '') echo "<br>Empty Set\n"; print_r ($my_t1); This prints correctly Code: [Select] while ($result = mysql_fetch_array($result,MYSQL_ASSOC)) { This is my error. "Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in /hermes/bosweb/web017/b172/ipg.dswdesignsnet/pp4c/charity1.php on line 8" Code: [Select] print "<b>Starting Time: <br></b>".$row{'start_time'}."<br><b>Tournament: </b><br>".$row{'tourney'}."<br><b>Buy-in: <br>".$row{'buy_in'}."<br><b>Starting Chips: <br>".$row{'start_chips'}."</font><p>"; This prints headers correctly, but no variables. Code: [Select] } mysql_close($dbh); ?> What did I forget to do or what did I do wrong. I'm still learning mysql and php. I need a help in the following : I have an admin page from where the admin attaches an gif image.This attached image should be shown to the user as a scrolling image. The code for the scrolling image is done through javascript. So my actual problem is getting the name of the attached gif image to the javascript array which is used for scrolling horizontally. |
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