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PHP - I Want To Display Imageid Along Wid Image In A Table Format
can anione help me to display imageid along wid each image in table format...here is my code which takes image from user....n d id can b anithing i mean its ur choice u can start wid first image by giving it imageid 1 n can continue til d image ends
<?php mysql_connect("localhost","root",""); @mysql_select_db(proj) or die( "Unable to select database"); $query="SELECT * FROM form"; $result=mysql_query($query); //define a maxim size for the uploaded images in Kb define ("MAX_SIZE","100"); //This function reads the extension of the file. It is used to determine if the file is an image by checking the extension. function getExtension($str) { $i = strrpos($str,"."); if (!$i) { return ""; } $l = strlen($str) - $i; $ext = substr($str,$i+1,$l); return $ext; } //This variable is used as a flag. The value is initialized with 0 (meaning no error found) //and it will be changed to 1 if an errro occures. //If the error occures the file will not be uploaded. $errors=0; //checks if the form has been submitted if(isset($_POST['Submit'])) { //reads the name of the file the user submitted for uploading $image=$_FILES['image']['name']; //if it is not empty if ($image) { //get the original name of the file from the clients machine $filename = stripslashes($_FILES['image']['name']); //get the extension of the file in a lower case format $extension = getExtension($filename); $extension = strtolower($extension); //if it is not a known extension, we will suppose it is an error and will not upload the file, //otherwise we will do more tests if (($extension != "jpg") && ($extension != "jpeg") && ($extension != "png") && ($extension != "gif")) { //print error message echo '<h1>Unknown extension!</h1>'; $errors=1; } else { //get the size of the image in bytes //$_FILES['image']['tmp_name'] is the temporary filename of the file //in which the uploaded file was stored on the server $size=filesize($_FILES['image']['tmp_name']); //compare the size with the maxim size we defined and print error if bigger if ($size > MAX_SIZE*1024) { echo '<h1>You have exceeded the size limit!</h1>'; $errors=1; } //we will give an unique name, for example the time in unix time format $image_name=time().'.'.$extension; //the new name will be containing the full path where will be stored (images folder) $newname="upload/".$image_name; //we verify if the image has been uploaded, and print error instead $copied = copy($_FILES['image']['tmp_name'], $newname); if (!$copied) { echo '<h1>Copy unsuccessfull!</h1>'; $errors=1; }}}} //If no errors registred, print the success message if(isset($_POST['Submit']) && !$errors) { $sql=mysql_query("INSERT INTO image (img) VALUES('$newname')"); if($sql) { echo "<h1>File Uploaded Successfully! Try again!</h1>"; } } ?> <!--next comes the form, you must set the enctype to "multipart/frm-data" and use an input type "file" --> <form name="newad" method="post" enctype="multipart/form-data" action=""> <table> <tr><td><input type="file" name="image"></td></tr> <tr><td><input name="Submit" type="submit" value="Upload image"></td></tr> </table> <p><a href="resizeimg.php">resize the images </a></p> </form> <p> </p> here is my code for displaying d images Similar TutorialsSorry for the beginner question, here I'm trying to retrieve data from the database and display it in the table format. But only table headers are printed, and not the actual values. The count variable is echoing 2 saying that data is present and correctly retrieved. Can anyone help?
<?php
include 'connect.php';
error_reporting(E_ALL ^ E_DEPRECATED);
error_reporting(E_ERROR | E_PARSE);
$sql="SELECT * FROM `resources` as r INNER JOIN `project_resources` as pr
ON r.res_id =pr.res_id WHERE project_id='$_POST[project_id]'";
$result=mysql_query($sql);
$count=mysql_num_rows($result);
if($result === FALSE) {
die(mysql_error());
}
echo "$count";
echo '<table>
<tr>
<th>Resource ID</th>
<th>Resource Name</th>
<th>Email</th>
<th>Phone Number</th>
<th>Reporting Manager</th>
<th>Role</th>
<th>Designation</th>
</tr>';
while ($row = mysql_fetch_array($result)) {
echo '
<tr>
<td>'.$row['res_id'].'</td>
<td>'.$row['res_name'].'</td>
<td>'.$row['email'].'</td>
<td>'.$row['phone_number'].'</td>
<td>'.$row['reporting_manager'].'</td>
<td>'.$row['role'].'</td>
<td>'.$row['designation'].'</td>
</tr>';
}
echo '
</table>';
?>
Edited by mac_gyver, 22 September 2014 - 07:25 AM. code tags please Hello,
I am trying to display the data from two tables with proper format. But Its not happening
Here is my 1st table - orders
2.PNG 10.12KB
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and my 2nd table - order_line_items
1.PNG 14.92KB
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I want to display like this
3.PNG 4.03KB
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Here is my code
$query = $mysqli->query("SELECT orders.order_id, orders.company_id, orders.order_for, order_line_items.order_id, order_line_items.item, order_line_items.unit,SUM(order_line_items.unit_cost * order_line_items.quantity) AS 'Total', order_line_items.tax from orders INNER JOIN order_line_items ON orders.order_id = order_line_items.order_id where orders.order_quote = 'Order' GROUP BY order_line_items.id"); ?>
<table id="dt_hScroll" class="table table-striped">
<thead><tr>
<th>Order ID</th>
<th>Company</th>
<th>Contact Person</th>
<th>Products</th>
<th>Total</th>
</tr>
</thead>
<tbody> <?php
while($row = $query->fetch_array())
{
?>
<tr>
<td><?php echo $row['order_id']; ?></td>
<td><?php echo $row['company_id']; ?></td>
<td><?php echo $row['contact_person'] ?></td>
<td><?php echo $row['item']; ?></td>
<td><?php echo $row['Total']; ?> %</td>
</tr>
<?php
}
But here order ID, Company ID, Contact Person are also repeating thrice with item in order_line_items table
Please suggest me how to do this
Alright, I looked though the read me's, went over the FAQ's... Think it is time to post...
So, this lump is what I got from going though google and piecing together the bits that looked good.
<?php
$db_host = "****";
$db_user = "****";
$db_pwd = "****";
$database = "****";
$table = "****";
$query = "SELECT * FROM {$table}";
$conn = mysqli_connect($db_host, $db_user, $db_pwd, $database);
$result = mysqli_query($conn,$query) or trigger_error($query . ' - has encountered an error at:<br />' . mysqli_error($conn));
$fields = mysqli_fetch_fields($conn);
$field_count = mysqli_num_fields($conn);
echo '<table border="1" style="width:100%">' . "\n" . '<tr>';
$i = 0;
foreach($fields as $field)
{
if(++$i == 1) {
echo '<th colspan="' . $field_count . '">' . $field->table . '</th></tr><tr>';
}
echo "\n" . '<th>' . $field->name . '</th>';
}
echo '</tr>';
while($row = mysqli_fetch_row($result)) {
echo '<tr><td>' . implode('</td><td>' , $row) . '</td></tr>';
}
echo '</table>';
?>
The goal is to display the table and conditionally format the contents.
Let's forget about the conditional part (thinking if/than but don't know how I'm going to do that yet) and focus on the key problem: displaying the table.
I have tested this code. It works...to a point. it displays the table and its contents but no headers. I know my issue is in line 20 and 22 but I can not for the life of me figure it out. If it is stupidly easy (for you) please remember that I am not a coder. At best I am a scripter when it comes to linux. I am over my head on this stuff.
Thank you all for any help you can give me
Edited by TheAlmightyOS, 18 November 2014 - 03:30 PM. I have a simple mysql database holding information about an image upload including its 'name' and 'date uploaded' [current_timestamp()] to a folder 'image' I then display it into a table using the php ‘foreach’ facility. I want the date to be displayed in the ‘dd/mm/yyyy’ format. not the default yyyy/mm/dd. Here is the relevant code
<?php
$conn = mysqli_connect("localhost", "root", "", "dbname");
$results = mysqli_query($conn, "SELECT * FROM tablename");
$image = mysqli_fetch_all($results, MYSQLI_ASSOC);
?>
<?php foreach ($image as $user): ?>
<td><p>NAME</p><?php echo $user['name']; ?></td>
<td><p>COMMENT</p><?php echo $user['comment']; ?></td>
<td><p>DATE</p><?php echo $user['date']; ?></td>
What do I need to do? THANKS- Warren OK, Here is the code $sql = "SELECT TrialListing.listingID AS Trial, TrialClass.classID AS Class, place.place_name AS Place, CONCAT_WS( ' ', pedigree.pretitle, pedigree.`Name`) AS Hound, CONCAT_WS( ' ', ped2.pretitle, ped2. NAME )AS Sire, CONCAT_WS( ' ', ped3.pretitle, ped3. NAME )AS Dam, pedigree.Breeder, pedigree.`Owner`, CASE WHEN placement.place_id < 5 THEN TRUNCATE(TrialClass.number_of_entrants / placement.place_id,2) WHEN placement.place_id = 5 THEN '' ELSE 0 END AS Score FROM TrialListing Left Join TrialClass ON TrialListing.listingID = TrialClass.listingID JOIN placement ON placement.event_id = TrialClass.trialClassID JOIN pedigree ON pedigree.PedigreeId = placement.hound_id LEFT OUTER JOIN pedigree AS ped2 ON pedigree.SireId = ped2.PedigreeId LEFT OUTER JOIN pedigree AS ped3 ON pedigree.DamId = ped3.PedigreeId LEFT JOIN place ON place.place_id = placement.place_id WHERE TrialListing.listingID = 11 ORDER BY Class, FIELD(place.place_id, '1', '2', '3', '4', '0') "; // Database Query $result = mysql_query("$sql"); // Database Query result $num_rows = mysql_num_rows($result); // Starts the table echo "<table class=\"clubList\">\n <tr> <th>trialID</th> <th>ClassID</th> <th>Place</th> <th>Hound</th> <th>Sire</th> <th>Dam</th> <th>Score</th> </tr>"; // Create the contents of the table. for( $i = 0; $i < $row = mysql_fetch_array($result); $i++){ echo "<tr>\n" ."<td>".$row["Trial"]."</td>\n" ."<td>".$row["Class"]."</td>\n" ."<td>".$row["Place"]."</td>\n" ."<td>".$row["Hound"]."</td>\n" ."<td>".$row["Sire"]."</td>\n" ."<td>".$row["Dam"]."</td>\n" ."<td>".$row["Score"]."</td>\n" ."</tr>";} echo "</TABLE>"; Here is the output, I added the TrialID & ClassID for informational purposes, they do not need to be displayed in the live table. trialID ClassID Place Hound Sire Dam Score 11 1 1st Eaton Brook Tug Hill Tatonka Eaton Brook Hickety Hawk Eaton Brook Gunner's Beulah 43.00 11 1 2nd FC North Bend Igloo FC DFJ Murphy White IFC Brad-Ju's Bella Donna 21.50 11 1 3rd FC North Bend Igloo FC DFJ Murphy White IFC Brad-Ju's Bella Donna 14.33 11 1 4th Rail Road Spike VI Elwell's Mike Elwell's Hannah 10.75 11 1 NBQ FC Fish Creek Spike Fish Creek Bull II Fish Creek Susie [H849395] 11 2 1st Enman Hill Sweet Poppy FTCH Straight Arrow Lucky of Coos 32.00 11 2 2nd Fishflakes Penny At Harehaven FTCH Jill's Fair-Isle Spud FTCH Millbridge Brownie 16.00 11 2 3rd Line Elm Flakers IFC Flakers Rex IFC Line Elm Ginger 10.66 11 2 4th FTCH Fareast Mookie FTCH Mellowrun Sly FTCH Cape Breton Maude 8.00 11 2 NBQ FTCH Mellowrun Sly Mellowrun Skylighter FTCH Mellowrun Becka 11 3 1st Bojangle V Lee Otworth Half Acre's Cocoa Candy 23.00 11 3 2nd Gay Doll Gay Roll II Gay Idol 11.50 11 3 3rd Bruce's Blue Lady FC Kilsock's Blue Creek Bart Bishopville's Zippy 7.66 11 3 4th FC Pearson Creek Barbin FC Pearson Creek Barbarian FC B-Line Stubby 5.75 11 3 NBQ Sims Creek Cricket Ronnie Joe Sims Creek Tiny 11 4 1st FTCH Fareast Mookie FTCH Mellowrun Sly FTCH Cape Breton Maude 26.00 11 4 2nd FTCH Mellowrun Sly Mellowrun Skylighter FTCH Mellowrun Becka 13.00 11 4 3rd Fishflakes Penny At Harehaven FTCH Jill's Fair-Isle Spud FTCH Millbridge Brownie 8.66 11 4 4th Enman Hill Sweet Poppy FTCH Straight Arrow Lucky of Coos 6.50 11 4 NBQ Line Elm Flakers IFC Flakers Rex IFC Line Elm Ginger Below is what I would like to generate. How do I word or nest the proper PHP code/loops to accomplish this? ClassID Place Hound Sire Dam Score 1st Eaton Brook Tug Hill Tatonka Eaton Brook Hickety Hawk Eaton Brook Gunner's Beulah 43.00 2nd FC North Bend Igloo FC DFJ Murphy White IFC Brad-Ju's Bella Donna 21.50 3rd FC North Bend Igloo FC DFJ Murphy White IFC Brad-Ju's Bella Donna 14.33 4th Rail Road Spike VI Elwell's Mike Elwell's Hannah 10.75 NBQ FC Fish Creek Spike Fish Creek Bull II Fish Creek Susie [H849395] ClassID Place Hound Sire Dam Score 1st Enman Hill Sweet Poppy FTCH Straight Arrow Lucky of Coos 32.00 2nd Fishflakes Penny At Harehaven FTCH Jill's Fair-Isle Spud FTCH Millbridge Brownie 16.00 3rd Line Elm Flakers IFC Flakers Rex IFC Line Elm Ginger 10.66 4th FTCH Fareast Mookie FTCH Mellowrun Sly FTCH Cape Breton Maude 8.00 NBQ FTCH Mellowrun Sly Mellowrun Skylighter FTCH Mellowrun Becka ClassID Place Hound Sire Dam Score 1st Bojangle V Lee Otworth Half Acre's Cocoa Candy 23.00 2nd Gay Doll Gay Roll II Gay Idol 11.50 3rd Bruce's Blue Lady FC Kilsock's Blue Creek Bart Bishopville's Zippy 7.66 4th FC Pearson Creek Barbin FC Pearson Creek Barbarian FC B-Line Stubby 5.75 NBQ Sims Creek Cricket Ronnie Joe Sims Creek Tiny ClassID Place Hound Sire Dam Score 1st FTCH Fareast Mookie FTCH Mellowrun Sly FTCH Cape Breton Maude 26.00 2nd FTCH Mellowrun Sly Mellowrun Skylighter FTCH Mellowrun Becka 13.00 3rd Fishflakes Penny At Harehaven FTCH Jill's Fair-Isle Spud FTCH Millbridge Brownie 8.66 4th Enman Hill Sweet Poppy FTCH Straight Arrow Lucky of Coos 6.50 NBQ Line Elm Flakers IFC Flakers Rex IFC Line Elm Ginger I have the code below displaying images and image names. I want these to display in a table 2 rows high by the needed number of columns to show all the images in the directory. I have no idea what to do. What I am getting now is a single column with each image in its own row. <?php $path = "./uploaded/"; $dir_handle = @opendir($path) or die("Unable to open folder"); while (false != ($file = readdir($dir_handle))) { if($file == "index.php") continue; if($file == ".") continue; if($file == "..") continue; //show in a table 2 rows by required/needed number of columns echo'<div>'; echo '<table border="1">'; echo "<img src='$path/$file' alt='$file'>"."<img src='$file' alt='$file'>"; echo'</table>'; echo '<div>'; } ?> Hello every one I need Ur Help... In mY site i have one page which name is invoice.php,but when i click a link in invoice.php,one page is generated which name is make invoice.php, but i want makeinvoice.php page should display as pdf..... Please Help me..... Thanks In Advance Hi,
I want to display my data in this format
format.JPG 54.52KB
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Expense data i am getting like this
<td><?php
$in = "SELECT sales_invoice.invoice_id as INID, DATE_FORMAT(sales_invoice.date_invoiced,'%M') AS month, sales_invoice_line_items.invoice_id, SUM(sales_invoice_line_items.sub_total) AS Total, SUM(sales_invoice_line_items.tax_amount) AS total_tax FROM sales_invoice INNER JOIN sales_invoice_line_items ON sales_invoice.invoice_id=sales_invoice_line_items.invoice_id GROUP BY sales_invoice.invoice_id, DATE_FORMAT(sales_invoice.date_invoiced, '%Y-%m')";
$in1 = mysql_query($in) or die (mysql_error());
$total=0;
$tax =0;
while($income = mysql_fetch_array($in1))
{
$total +=$income['Total'];
$tax +=$income['total_tax'];
echo $total - $tax; }
?>
</td>
And Profit i am getting like this
<td><?php
$in = "SELECT purchase_invoice.invoice_id as INID, DATE_FORMAT(purchase_invoice.date_invoiced,'%M') AS month, purchase_invoice_line_items.invoice_id, SUM(purchase_invoice_line_items.sub_total) AS Total, SUM(purchase_invoice_line_items.tax_amount) AS total_tax FROM purchase_invoice INNER JOIN purchase_invoice_line_items ON purchase_invoice.invoice_id=purchase_invoice_line_items.invoice_id GROUP BY purchase_invoice.invoice_id, DATE_FORMAT(purchase_invoice.date_invoiced, '%Y-%m')";
$in1 = mysql_query($in) or die (mysql_error());
$total=0;
$tax =0;
while($income = mysql_fetch_array($in1))
{
$total +=$income['Total'];
$tax +=$income['total_tax'];
echo $total - $tax; }
?>
</td>
I dont know how to display data like this. Do i need to change the the table structure in my database? Please suggest
Hi I have been trying to populate my data from 3 tables and display like this: DATE $acronym1 $acronym2 POSTS 1/9/2011 10 (this is no of posts) 3 POSTS 31/8/2011 20 10 and so on. the threads and user table will be similar as well. I am not able to populate the distinct dates since the dateline contains time as well. So when I try to print out the just dates(without time) , it prints with the dates repeated. it prints something like this: 1/9/2011 1 1/9/2011 1 and so on.. How can populate and print the the date and number of posts in the above format. Here is my complete code below: Code: [Select] <?php error_reporting(-1); //ini_set('display_errors',1); include("db.php"); //$thirty_days_ago = strtotime("-30 days"); $limit = strtotime("-1 month"); $sql=mysql_query(("SELECT * from new_site"),$con) or die(mysql_error()); while($row=mysql_fetch_assoc($sql)) { $include=$row['include']; $forumurl=$row['forumurl']; $url=$row['url']; $acronym=$row['acronym']; include("$include"); //echo $include."<br>"; $configdbname=$config['Database']['dbname']; $configdbconport=$config['MasterServer']['servername'].":".$config['MasterServer']['port']; $configusername=$config['MasterServer']['username']; $configpassword=$config['MasterServer']['password']; $configprefix=$config['Database']['tableprefix']; /* Connect to the required database */ $con2=mysql_connect($configdbconport, $configusername, $configpassword); if (!$con2) { die('Could not connect: ' . mysql_error()); } mysql_select_db($configdbname, $con2); $postdate=mysql_query("SELECT DISTINCT dateline,postid from post WHERE dateline >='$limit' ORDER by dateline DESC") or die(mysql_error()); while($postdate_results=mysql_fetch_assoc($postdate)) { $postdate_record=$postdate_results['dateline']; // echo $postdate."<br>"; $postdate_formatted=date('M dS Y ',$postdate_results['dateline']); $post_count=mysql_query("SELECT * from post WHERE dateline >='$postdate_record'"); while($post_count_results=mysql_fetch_assoc($post_count)) { //$postdate_formatted=date('M dS Y ',$post_dateline_results['dateline']); $posts=mysql_num_rows($post_count) or die(mysql_error()); //echo $acronym.":POSTS:".$posts."<br>"; echo '<table border="1">'; echo "<tr>"; echo "<th>Category</th>"; echo "<th>".$acronym."</th>"; echo "</tr>"; echo "<tr>"; echo "<td>POSTS:DATE:".$postdate_formatted."</td>"; echo "<td>".$posts."</td>"; echo "</tr>"; } $threaddate=mysql_query("SELECT * from thread WHERE dateline >='$limit' ORDER by dateline DESC") or die(mysql_error()); while($threaddate_results=mysql_fetch_assoc($threaddate)) { $threaddate_record=$threaddate_results['dateline']; $threaddate_formatted=date('M dS Y ',$threaddate_results['dateline']); $thread_count=mysql_query("SELECT * from thread WHERE dateline='$threaddate_record'"); while($thread_count_results=mysql_fetch_assoc($thread_count)) { $threads=mysql_num_rows($thread_count) or die(mysql_error()); //echo $acronym.":THREADS:".$threads."<br>"; echo "<tr>"; echo "<td>THREADS:DATE:".$threaddate_formatted."</td>"; echo "<td>".$threads."</td>"; echo "</tr>"; $userdate=mysql_query("SELECT * from user WHERE joindate >='$limit' ORDER by joindate DESC") or die(mysql_error()); while($userdate_results=mysql_fetch_assoc($userdate)) { $userdate_record=$userdate_results['joindate']; $userdate_formatted=date('M dS Y ',$userdate_results['joindate']); $user_count=mysql_query("SELECT * from user WHERE joindate='$userdate_record'"); while($user_count_results=mysql_fetch_assoc($user_count)) { $users=mysql_num_rows($user_count) or die(mysql_error()); //echo $acronym.":USERS REGISTERED:".$users."<br>"; echo "<tr>"; echo "<td>REGISTERED USERS::DATE:".$userdate_formatted."</td>"; echo "<td>".$users."</td>"; echo "</tr>"; } } } } } } echo "</table>"; ?> hello, lets say i want 3 of the following columns to only display on 1 line always, is there a way to do that? Code: [Select] <th align='center'>Date</th> <th align='center'>Supplier</th> <th align='center'>Requested By</th> <th align='center'>Address of Job</th> <th align='center'>Job Number</th> <th align='center'>P.O. Number</th> <th align='center'>Description</th> <th align='center'>Amount</th> <th align='center'>Notes</th> <th align='center'></th> Hey, I am grabbing a date from a row in my table which is currently formatted as: date("Y-m-d") 2010-09-29 So in my code I have something like this: $row['date']; How do I use this to rearrange the date to look like: 09-29-2010 I looked at the formatting tutorials, but they explain how to format it for the date you are currently setting into a variable. Coming from the world of Excel, I can easily format numbers as $1,500.00, or 27%. When I uploaded a large chunk of data into SQL to be read back through a table, the values all come out as exactly what they were uploaded as. For example, I have an SQL column set as Decimal(19,4) that I want formatted like currency, but which shows up as 1500.0000 in my table, or another column with type decimal(5,2) which shows up as 5500.0000, but which I want to show up as 55%. How do I do this?
Hi all - I am parsing info from mysql into a php table but the date being returned is in YYYY-MM-DD format and I want it DD-MM-YYYY. How would I do this? Code at the moment is: Code: [Select] $link = connect(); function get_user_posts(){ $getPosts = mysql_query('SELECT a.id as id,a.post as question, a.answer as answer, a.created as created, a.updated as updated, b.vclogin as admin FROM user_posts as a, admin as b WHERE a.admin_id=b.adminid',connect()); return $getPosts; } Code: [Select] <table class="list"> <tr> <th><?php echo getlocal("upost.post") ?></th> <th><?php echo getlocal("upost.answer") ?></th> <th><?php echo getlocal("upost.admin") ?></th> <th><?php echo getlocal("upost.created") ?></th> <th><?php echo getlocal("upost.updated") ?></th> <th></th> <th></th> </tr> <?php $all_questions = get_user_posts(); while ($question = mysql_fetch_assoc($all_posts)): ?> <tr> <td><?php echo $post['post']?></td> <td><?php echo $post['answer']?></td> <td><?php echo $post['admin']?></td> <td><?php echo $post['created']?></td> <td><?php echo $post['updated']?></td> <td><a href="javascript:user_post('<?php echo $post['id']?>')">edit</a></td> <td><a href="javascript:delete_post('<?php echo $post['id']?>')">delete</a></td> </tr> THANKS! Hi I have a table that populated by a recordset, and wondered whether is was possible to make a row background colour = red where a particular cell = some text? I have been searching around and not managed to find anything of use. Any help would be appreciated. Hi I have the following for an input form, I was under the impression that ucwords would format the text into Initial Characters, but this does not do that? What have I done wrong? $ven_name = trim(ucwords(mysql_prep($_POST['ven_name']))); I'm not sure if my problem is with the PHP, MySQL, HTML, or all of the above, but I've used a tutorial from ScriptPlayground (http://scriptplayground.com/tutorials/php/Printing-a-MySQL-table-to-a-dynamic-HTML-table-with-PHP/) to print a table to HTML. My problem isn't that I couldn't get it to work, as you can see from my site, http://dollapal.com/offerlist.php I've used the code on my site, trying to display a list of offers, with links to each, but I actually have two questions: Is there a way to EXCLUDE columns of the table? I would rather not show the 'id' or 'points' columns, since they don't offer any worth to the user. I would also need to hopefully add a dollar sign before the 'pay' quantities if possible. I would also like use the 'title' field as a hyperlink to the URL listed in the 'URL' field, instead of simply printing the URL. Are there any simple ways to do this and not have it look terrible? I have included a copy of the script that I'm working with so far. Thank you in advance! I am a developer in PHP but have run into an obstacle and was hoping for some insight. I am attempting to do something a little complicated I fear but perhaps there is a solution. A client of mine is offering CSV templates for customers to use to BATCH UPLOAD item's to their account. This is self explanatory in the fact that I know how to import a .CSV with PHP and I know how to properly insert it into the database. My question is this: What if we wanted to offer a way for the customer to insert an image into the .CSV template. By the time the .csv reached my PHP code would the image still be in a format where it could be uploaded to a directory on the server? I have not found anything on the web where anyone has tried this. Again, the customer will insert an image from their hard drive into a row within the .CSV template. My code will parse the .CSV row data and if the image is still in tact...will then upload the image to a director with more code. Thanks for any help. Joe Hi... I tried to use foreach in displaying my table header, but I encountered problem when I tried to display data on the first row , my query only display the last Sum for the last Comp. here is my code: <html> <head> <title>Half Shell</title> <link rel="stylesheet" type="text/css" href="kanban.css" /> <?php error_reporting(E_ALL ^ E_NOTICE); date_default_timezone_set("Asia/Singapore"); //set the time zone $con = mysql_connect('localhost', 'root',''); if (!$con) { echo 'failed'; die(); } mysql_select_db("mes", $con); ?> <body> <form name="param" action="" method="post" onSubmit="return false"> <div id="fieldset_PS"> <?php echo "<table>"; $sql = "SELECT DISTINCT s.Comp FROM sales_order s, param_settings p WHERE s.Comp = p.Compounds ORDER BY s.Comp"; $res_comp = mysql_query($sql, $con); while($row_comp = mysql_fetch_assoc($res_comp)){ $Comp[] = $row_comp['Comp']; } echo "<th> </th>"; foreach($Comp AS $Comp){ echo "<th>$Comp</th>"; } echo "<tr> <td>Total Kg/Compound</td>"; $sql_sec = "SELECT SUM(TotalKg) AS TotalKg FROM sales_order WHERE Comp = '$Comp' ORDER BY Comp"; $res_sec = mysql_query($sql_sec, $con); while($row_sec = mysql_fetch_assoc($res_sec)){ $TotalKg[] = $row_sec['TotalKg']; } foreach($TotalKg AS $TotalKg){ echo "<td>$TotalKg</td> </tr>"; } ?> I also attach the correct output that should be and the result from my code. Thank you Hi, I have a connection set up to an API using a PHP script - the API sends back data in JSON format, and if I capture it and echo it, it displays in extremely unfriendly format on the screen. I've tried to find a way to convert this data into readable format, ideally in a HTML table, but although there are articles on converting manually inputted JSON data into a HTML table using Javascript, I can't find a way to do it from a PHP variable. This is what I have so far:
if ($_POST['getcompany']) {
$companyname = $_POST['_Name'];
$ch = curl_init();
$data_array2 = array(
'token' => $token
);
$make_call2 = json_encode($data_array2);
//echo 'Token is '.$token;
$token2 = substr($token, 14);
$token3 = substr($token2, 0, -3);
//echo 'Token 2 is '.$token3;
//echo 'Company Name is '.$companyname;
//curl_setopt($ch, CURLOPT_GET, 1);
//curl_setopt($ch, CURLOPT_POSTFIELDS, $make_call2);
curl_setopt($ch, CURLOPT_HTTPHEADER, array('Content-Type: application/json','Authorization: '.$token3.''));
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_URL, 'https://connectionurl?countries=GB&name='.$companyname);
//Execute the request
$result = curl_exec($ch);
echo 'Companies: '.$result; //This displays the data provided by the search, but is in JSON format
So I need a way to get the data held in $result, into a HTML table. Any idea how I can do this?
Hello All,
function convertTimeFormat($time12Hour) {
// Initialized required variable to an empty string.
$time24Hour = "";
// Used explode() function to break the string into an array and stored its value in $Split variable.
$Split = explode(":",$time12Hour); // print_r(explode (":", $time12Hour)); => Array ( [0] => 09 [1] => 50 [2] => 08AM )
// Retrieved only "hour" from the array and stored in $Hour variable.
$Hour = $Split[0];
$Split[2] = substr($Split[2],0,2);
// Used stripos() function to find the position of the first occurrence of a string inside another string.
if($Hour == '12' && strpos($time12Hour,"AM")!== FALSE) {
// Code here
} elseif(strpos($time12Hour,"PM")!== FALSE && $Hour != "12") {
// code here
}
return $time24Hour;
}
$time12Hour = "09:50:08AM";
$result = convertTimeFormat($time12Hour);
print_r($result);
/*
Input : "09:50:08AM";
Output : "21:50:08PM";
*/
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