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PHP - Option Selected
I have the following which fils a combo box with years from 1950 to 2100. This is the year box for the date of birth.
Year <select name="year_select"> <?php for( $i=1950; $i<=2100; $i++ ) { echo "<option value=\"{$i}\" class=\"year\">{$i}</option>"; } ?> </select> I want it to automatically display the year that is in the database so instead of automatically displaying 1950 i want their birth year displayed which is $tab_info->user_dob_year. How would i go about this? i dont know where to start since im using a for loop to populate it. Similar Tutorialsmysql.php <?php $con = mysql_connect("localhost","root",""); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("ckeditor",$con); ?> --------------------------------------------------------- add.php <?php include("mysql.php"); if(isset($_POST["button2"])) { $sql="INSERT INTO cktext (section) VALUES ('$_POST[select2]')"; if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } ?> ----------------------------------------------------------------- home.php <form id="form1" name="form1" method="post" action="add.php"> <tr> <td>Section:</td> <td><select name="select2" id="select2"> <option selected="selected" value="MALE">Male</option> <option selected="" value="FEMAIL">FEMAIL</option> </select></td> </tr> <input type="submit" name="button2" id="button2" value="Upload" /> </form> In DATABASE :- cktext table attribute "section" is varchar type. BUT IT RETURN ME BLANK OUTPUT. If I have a variable and a hard coded select dropdown, what is the easiest way to compare the variable with the value and set that particular option's selected attributed to selected? Hi, I wanted to make a dynamic php page. I want the user to choose an option you could select in an option box (html) and after that I wish that down the page some text would change. If I take option 1 -> text 1, option 2 -> text 2, ... But this doesn't work, do I need a button or something to made my code running, and how do I have to use it on the same page? Or is it possible to run it automaticly after a new choice? Thanx, Kevin My code: <?php /* Template Name: template voor Ieder1Trainer # */ get_header(); $Tacktiek = ""; $Tacktiek1 = "3-5-2"; $Tacktiek2 = "3-4-3"; $Tacktiek3 = "4-5-1"; $Tacktiek4 = "4-4-2"; $Tacktiek5 = "4-3-3"; $Tacktiek6 = "5-4-1"; $Tacktiek7 = "5-3-2"; $aantalDef; $aantalMid; $aantalAtt; ?> <div id="newsfeed"> <div class="banderol"> <div class="banderol_left"></div> <h1>Dynamic page</h1> </div> <?php if(is_user_logged_in()) { get_currentuserinfo(); //echo 'Username: ' . $current_user->user_login . "\n"; //echo 'User email: ' . $current_user->user_email . "\n"; ?> <!-- Here you choose a tactiek; 1,2,3, .. after that has been choosen I whise the next php-code would be run (the if-then-elseif-...) --> <tr> <td><p class="formulier">Kies je Tacktiek:</p></td> <td> <select size="1" name="$Tacktiek"> <option selected><?php echo $Tacktiek1;?></option> <option><?php echo $Tacktiek2;?></option> <option><?php echo $Tacktiek3;?></option> <option><?php echo $Tacktiek4;?></option> <option><?php echo $Tacktiek5;?></option> <option><?php echo $Tacktiek6;?></option> <option><?php echo $Tacktiek7;?></option> </select> </td> </tr> <!-- This must be run after choosen a tactiek. --> <?php if($Tacktiek == '3-5-2') { $aantalDef = 3; $aantalMid = 5; $aantalAtt = 2; } elseif($Tacktiek == '3-4-3') { $aantalDef = 3; $aantalMid = 4; $aantalAtt = 3; } elseif($Tacktiek == '4-5-1') { $aantalDef = 4; $aantalMid = 5; $aantalAtt = 1; } elseif($Tacktiek == '4-4-2') { $aantalDef = 4; $aantalMid = 4; $aantalAtt = 2; } elseif($Tacktiek == '4-3-3') { $aantalDef = 4; $aantalMid = 3; $aantalAtt = 3; } elseif($Tacktiek == '5-4-1') { $aantalDef = 5; $aantalMid = 4; $aantalAtt = 1; } elseif($Tacktiek == '5-3-2') { $aantalDef = 5; $aantalMid = 3; $aantalAtt = 2; } ?> <!-- After this run, the next code must be run and made a choose of text --> <tr> <td><p class="formulier"> <?php if($aantalDef == '3') { echo "3 defs"; //Choosen text if aantalDef == 3 } elseif($aantalDef == '4') { echo "4 defs"; //Choosen text if aantalDef == 4 } elseif($aantalDef == '5') { echo "5 defs"; //Choosen text if aantalDef == 5 } ?> </p></td> <!-- Other choose of options, but always the same options. --> <td> <select size="1" name="$Speler4"> <option selected><?php echo $NaamDef1;?></option> <option><?php echo $NaamDef2;?></option> <option><?php echo $NaamDefMid1;?></option> <option><?php echo $NaamDefMid2;?></option> <option><?php echo $NaamDefMid3;?></option> <option><?php echo $NaamDefMid4;?></option> <option><?php echo $NaamDefMid5;?></option> <option><?php echo $NaamDefMid6;?></option> <option><?php echo $NaamDefMid7;?></option> <option><?php echo $NaamDefMid8;?></option> <option><?php echo $NaamDefMidAtt1;?></option> <option><?php echo $NaamDefMidAtt2;?></option> <option><?php echo $NaamDefMidAtt3;?></option> </select> </td> </tr> <?php } else{ echo 'U dient in te loggen.'; } ?> </div> <?php get_footer(); ?> I'm just attempting to learn how PHP handles things and I can't quite wrap my head around how to apply Selected to the final Option and show the Traits for the Character based on the Selected Option. I understand this might need POST, if it does, I would appreciate a bit of help on how I would set this up as POST since I didn't think a drop down required a submit button. Code: [Select] $character= array (array(Name=>"Barry","Class"=>"Fighter",Level=>1,Str=>10,Dex=>10,"Int"=>10),array(Name=>"Lindehar","Class"=>"Ranger",Level=>1,Str=>10,Dex=>10,"Int"=>10),array(Name=>"Verelden","Class"=>"Mage",Level=>1,Str=>10,Dex=>10,"Int"=>10)); print "Select a Character:<br /><select>"; foreach($character as $array_num) { foreach($array_num as $char_trait=>$trait_value) { if($char_trait==Name) { $selected_value=""; $generated_chars="<option selected=".$selected_value." value='".$char_trait."'>".$char_trait.": ".$trait_value."</option>"; print $generated_chars; if($selected_value=/".$char_trait.": Barry"/") { foreach($char_trait=="Barry") { print "<h4>".$char_trait.": ".$trait_value."</h4>"; } } } } } print "</select><p />"; Not sure exactly where this problem is coming from, but php seems the most likely candidate to fix it. My php loads, from a MySQL database, a list of names (students in a class) and a drop-down for each student with attendance options. Based on the information in the database, the appropriate attendance option is selected (<option selected></option>). Everything works fine on the initial page load. Next, I want to update the status, so I select a new option from the drop-down list and click submit. The php code updates the database correctly, but the selected option (in HTML) is still the original one. If I change the option to something different and submit again, I get the previously selected option (that I selected the first time) - in essence, the HTML is always one step behind the database. I've attached the snippet of relevant code - again, I know that the code works when the page loads initially and that the database is getting updated correctly. Any help or comments are appreciated. I have a form that contains 3 text fields and 7 populated lists (that are dependent on the choice of the previous lists). When I post the information to MySQL and to my processing page, it posts the table "ids" instead of the selected option. Here's the php code for the form: <form action="gccsuccess_form.php" method="post" enctype="multipart/form-data" name="gcc" id="gcc"> <table width="700" border="0" align="center" cellpadding="3" cellspacing="3"> <tr> <td><label for="date">Today's Date:</label> <input type="text" name="date" id="date"></td> <td> </td> </tr> <tr> <td>Week Number: <select name="week" size="1" id="week"> <option value="0" selected>Week 0 - 3/26 - 4/1</option> <option value="1">Week 1 - 4/2 - 4/8</option> <option value="2">Week 2 - 4/9 - 4/15</option> <option value="3">Week 3 - 4/16 - 4/22</option> <option value="4">Week 4 - 4/23 - 4/29</option> <option value="5">Week 5 - 4/30 - 5/6</option> <option value="6">Week 6 - 5/7 - 5/13</option> </select></td> <td><label for="location"></label> </td> </tr> <tr> <td>Location: <select id='locations' name='location'> </select></td> <td> </td> </tr> <tr> <td><label for="label8">Team Name</label> <select id='team_names' name='team_name'> </select></td> <td> </td> </tr> <tr> <td><em>*Please enter each team member's first and last name:</em></td> <td> </td> </tr> <tr> <td><label for="mem_1"> Team <strong>Captain:</strong></label> <select id='team_members 1' name='capt'> </select></td> <td><label for="label4"><strong>Steps:</strong></label> <input type="text" name="steps_1" id="steps_1"></td> </tr> <tr> <td><label for="mem_2">Team Member #2 <strong>Name: <select id='team_members 2' name='mem_2'> </select> </strong></label></td> <td><label for="label5"><strong>Steps:</strong></label> <input type="text" name="steps_2" id="steps_2"></td> </tr> <tr> <td><label for="mem_3">Team Member #3 <strong>Name: <select id='team_members 3' name='mem_3'> </select> </strong></label></td> <td><label for="label6"><strong>Steps:</strong></label> <input type="text" name="steps_3" id="steps_3"></td> </tr> <tr> <td><label for="mem_4">Team Member #4<strong> Name</strong>: <select id='team_members 4' name='mem_4'> </select> </label></td> <td><label for="label7"><strong>Steps:</strong></label> <input type="text" name="steps_4" id="steps_4"></td> </tr> <tr> <td><label for="label">Team Member #5<strong> Name</strong>: <select id='team_members 5' name='mem_5'> </select> </label></td> <td><label for="label7"><strong>Steps:</strong></label> <input type="text" name="steps_5" id="steps_5"></td> </tr> <tr> <td> </td> <td> </td> </tr> <tr> <td> </td> <td><em>* Maximum steps for each team member per week is <strong>105,000. </strong></em></td> </tr> <tr> <td> </td> <td><input type="submit" name="Submit Form" id="Submit Form" value="Submit"></td> </tr> </table> <label></label> <div align="center"><br> If you have questions about the competition or reporting please contact KC WELLNESS, INC toll free at <SPAN id="lw_1237248942_0">877-634-1412.</SPAN><br> <br> </div> </form> And here's the code for the page it is posted in: <?php $date = $_POST['date']; $week = $_POST['week']; $location = $_POST['location']; $team_name = $_POST['team_name']; $capt = $_POST['capt']; $mem_2 = $_POST['mem_2']; $mem_3 = $_POST['mem_3']; $mem_4 = $_POST['mem_4']; $mem_5 = $_POST['mem_5']; $steps_1= $_POST['steps_1']; $steps_2= $_POST['steps_2']; $steps_3= $_POST['steps_3']; $steps_4 = $_POST['steps_4']; $steps_5 = $_POST['steps_5']; mysql_connect("mysql1.myregisteredsite.com", "49200_kandace", "Leonardo56") or die(mysql_error()); mysql_select_db("49200_GCC") or die(mysql_error()); mysql_query("INSERT INTO `walkathon` VALUES ('$date', '$week', '$location', '$team_name', '$capt','$mem_2','$mem_3', '$mem_4', '$mem_5', '$steps_1','$steps_2', '$steps_3','$steps_4', '$steps_5' )"); Print "Thank you for your entry. <br> Report summary: <br/><br/>"; echo "<strong> Date: </strong> {$date} <br/> <br/><strong> Week: </strong> {$week} <br/> <br/><strong> Location: </strong> {$location} <br/> <br/><strong> Team Name: </strong> {$team_name} <br/> <br/><strong> Team Captain: </strong> {$capt} / <strong> Steps: </strong> {$steps_1} <br /> <br/><strong> Team Member 2 Name: </strong> {$mem_2} / <strong> Steps: </strong> {$steps_2} <br /> <br/><strong> Team Member 3 Name: </strong> {$mem_3} / <strong> Steps: </strong> {$steps_3} <br /> <br/><strong> Team Member 4 Name: </strong> {$mem_4} / <strong> Steps: </strong> {$steps_4} <br /> <br/><strong> Team Member 5 Name: </strong> {$mem_5} / <strong> Steps: </strong> {$steps_5}" ?> How do I get the processing page to echo the selected option instead of the id? I'm trying to create a dynamic option menu with one alert selected based on the first query to the db. Any help would be greatly appreciated. Code: [Select] //function to get alerts and create select menu with current alerts pre-selected function getALERTS1($id){ require('db.php'); $alert = mysqli_query($conn, "SELECT alert1 FROM visit_data WEHERE patientid = $id AND discharged IS NULL"); $row = mysqli_fetch_array($alert); $selects=null; $query = mysqli_query($conn, "SELECT alertid, name FROM alerts"); while($row1 = mysqli_fetch_array($query)) { $selects .= "<option value=\"" . $row1['alertid'] . "\"> if($row1['alertid']==$row['alert1']) { echo ' selected'; } ".$row1['name']."</option>"; } return $selects; }
<?php Hi, I have an html form in "send.htm" that sends data to "retrieve.php" with the following structu send.htm: Code: [Select] <html> <body> <form method="post" action="retrieve.php" <select id='select' name='select' > <option>option1</option> <option>option2</option> <option>option3</option> <option>etc...</option> </select> <input type="submit"> </form> </body> </html> retrieve.php: Code: [Select] <?php $selectedoption = $_POST['select']; print" <html> <body> <select id='select' name='select' > <option>option1</option> <option>option2</option> <option>option3</option> <option>etc...</option> </select> </body> </html> "; ?> How do I specify that the select menu in retrieve.php should have the option selected that was chosen from the select menu in send.htm? I'm guessing this is probably quite straightforward, but I can't quite work it out. Please help! Thanks. Hi I have a list of states using the array method in a form. The drop down menu works fine. I want to save the user choice,if the form is re-displayed due to a blank field or pattern mismatch. I know I can use the selected=selected, but don't know wher to put the statement: My array is: state_province = array ("list of states", "provinces") Var in my labels array is "state"=>"state" Here is my code for the select/option statement: { if($field == "state") { echo "<div class='province_state'><label for='state' size='10'>* Province/State</label><select>"; foreach($state_province as $state) { echo "\n<option value='$state_province' /> "; echo $state ; echo "</option>"; } echo "</select></div>\n"; } ?Is this the correct code to add and where would I add it? if(@$_POST['state'] == $value) { echo "selected='selected' "; } Hi all, I have a html drop down menu and want to show the initially selected value as the one stored in the mysql database that a member selected. I have 180+ rows in mysql that a member could have selected and would like to basically do this: IF (value of option == $row['value'] ) { echo "selected=\"selected\"; } I could put this in every one of the rows it would be much better to have an if statement. As there are so many values I do not know where to begin. Can someone point me in the right direction? Thanks This topic has been moved to JavaScript Help. http://www.phpfreaks.com/forums/index.php?topic=307346.0 I have this loop on a shorturl website i own that selects domains from my website and lists them in a dropdown list where users can select one domain to use as url shortener. The problem is that when a users selects and entry from the dropdown list this created only the [[[main_url]]] entry from the database table bellow can be used. When someone selectes "coolartistname.site.com the submit button cannot be pressed. in other words it's not adding the SELECTED attribute other than the [[[main_url]]] domain. Can anyone see on the code bellow why this would happen?
**Index.php** // get base urls
$shortUrlDomains = getShortUrlDomains();
<?php
foreach ($shortUrlDomains AS $k => $shortUrlDomain)
{
// active domains only
if (($shortUrlDomain['premium_only'] !== '1') && ($shortUrlDomain['premium_only'] !== $Auth->id))
{
continue;
}
echo '<option value="' . (int)$k . '"';
if (isset($_REQUEST['shortUrlDomain']))
{
if ($k == (int)$_REQUEST['shortUrlDomain'])
{
echo 'SELECTED';
}
}
echo '>';
echo $shortUrlDomain['domain'];
if ($disabled == true)
{
echo ' (' . safeOutputToScreen(t('unavailable', 'unavailable')) . ')';
}
'</option>';
}
echo '</optgroup>';
?>
FUNCTIONS.PHP function getShortUrlDomains()
{
// if we already have it cached
if(defined('_SETTINGS_SHORT_URL_DOMAINS'))
{
return unserialize(_SETTINGS_SHORT_URL_DOMAINS);
}
// get connection
$db = Database::getDatabase(true);
// load from database
$domains = $db->getRows("SELECT id, domain, premium_only, status FROM url_domain ORDER BY premium_only ASC, id ASC");
// organise and replace site url
$rs = array();
foreach($domains AS $domain)
{
if($domain['domain'] == '[[[main_url]]]')
{
$domain['domain'] = _CONFIG_SITE_FULL_URL;
}
$rs[$domain{'id'}] = $domain;
}
**MYSQL DATABASE** url_domain (id, domain, premium_only, status, date_created, owner) VALUES (1, '[[[main_url]]]', 0, 'enabled', '2019-03-02 08:13:00', 1) (14, 'coolartistname.site.com', 6, 'enabled', '2020-04-18 19:21:59', 6);
How can I maintain selected='selected' when the page is reloaded? I don't want to just echo out what they have selected, but rather maintain which option has been selected. Here is my drop down. Code: [Select] <form method='POST' id='jumpbox' action='./entrepreneur.php' onsubmit='if(document.jumpbox.industry.value == -1){return false;}'> <fieldset class='jumpbox'> <select name='industry' id='industry' onchange='if(this.options[this.selectedIndex].value != -1){ document.forms['jumpbox'].submit() }'> <option value='-1' selected='selected'>Select an Industry</option> <option value='-1'>------------------</option> <option value='1'>Digital Media</option> <option value='2'>Software</option> <option value='3'>Telecommunication</option> </select> <input type='submit' value='Go' class='go'/> </fieldset> </form> how would i render this Code: [Select] <select name="state" value="<?php echo $state; ?>"> <option>Select a state</option> <option value="AL">Alabama</option> <option value="AK">Alaska</option> <option value="AZ">Arizona</option> <option value="AR">Arkansas</option> <option value="CA">California</option> <option value="CO">Colorado</option> <option value="CT">Connecticut</option> <option value="DE">Delaware</option> <option value="DC">District Of Columbia</option> <option value="FL">Florida</option> <option value="GA">Georgia</option> <option value="HI">Hawaii</option> <option value="ID">Idaho</option> <option value="IL">Illinois</option> <option value="IN">Indiana</option> <option value="IA">Iowa</option> <option value="KS">Kansas</option> <option value="KY">Kentucky</option> <option value="LA">Louisiana</option> <option value="ME">Maine</option> <option value="MD">Maryland</option> <option value="MA">Massachusetts</option> <option value="MI">Michigan</option> <option value="MN">Minnesota</option> <option value="MS">Mississippi</option> <option value="MO">Missouri</option> <option value="MT">Montana</option> <option value="NE">Nebraska</option> <option value="NV">Nevada</option> <option value="NH">New Hampshire</option> <option value="NJ">New Jersey</option> <option value="NM">New Mexico</option> <option value="NY">New York</option> <option value="NC">North Carolina</option> <option value="ND">North Dakota</option> <option value="OH">Ohio</option> <option value="OK">Oklahoma</option> <option value="OR">Oregon</option> <option value="PA">Pennsylvania</option> <option value="RI">Rhode Island</option> <option value="SC">South Carolina</option> <option value="SD">South Dakota</option> <option value="TN">Tennessee</option> <option value="TX">Texas</option> <option value="UT">Utah</option> <option value="VT">Vermont</option> <option value="VA">Virginia</option> <option value="WA">Washington</option> <option value="WV">West Virginia</option> <option value="WI">Wisconsin</option> <option value="WY">Wyoming</option> </select> I'm having the strangest thing happing. When posting a form i'm not getting the option value. Instead its posting my text field ie: <option name="1">text</option> Code: [Select] <?php $query = "SELECT id, name FROM locations ORDER BY name"; $res = mysql_query($query, $cid); while($a = mysql_fetch_array($res)) { echo "<option name=".$a["id"].">".$a["name"]."</option>"; } ?> Code: [Select] <?php The code thats grapping it: if($_POST['location']==""){ $location = ""; echo '<div class="message error">Please enter a <strong>Location</strong></div>'; }else{ $location = $_POST['location']; } ?> Can anyone see why? I have also tried it in html to see if its my php, but i get the same result Do I need to add value to this select statement? Code: [Select] <select id="expYear" name="expYear"> <option></option> <option>2011</option> <option>2012</option> <option>2013</option> <option>2014</option> <option>2015</option> <option>2016</option> <option>2017</option> <option>2018</option> <option>2019</option> <option>2020</option> </select> Debbie I am using PHP for CV Generator. I need to add an element for 'Add another' option, e.g. on employment section, if you have more than one job you may require to add another form. Would this work with PHP coding? If so, what is it called? If not so, maybe Javascript? I can google for it when I get a answer from you guys. By the way, you may be aware with this- I have a little experience with PHP coding. Dean I'm trying to create VIP zone, but I need to check if user has input correct username and password....I tried to make it work this way HTML Code: [Select] <form action="vipchat.php" method="post" /> Korisnicko ime: <input type="text" name="ime"/> Lozinka: <input type="password" name="lozinka"/> <input type="submit" value="Uloguj se"/> </form>php Code: [Select] <?php $imet = "komp"; $sifrat = "racun"; if ($_POST["ime"]==$imet)and($_POST["lozinka"]==$sifrat) echo "Tacno je"; else echo "Netacno je"; ?> But it gives me this error Code: [Select] Parse error: syntax error, unexpected T_LOGICAL_AND in C:\AppServ\www\adm\vipchat.php on line 16 |
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