PHP - Moved: Need Help With Colums

What I am trying to do is create a search box to search for a specific piece of information in my client database, say last name, or account number, invoice number, etc. is there a way i can use the keyword to match the query to multiple columns?

here is my code, the script works if i use the $query to select just 1 column. but how do i add other columns to match it to?

I know its  where "different columns" LIKE search  my problem is this line basically.

Code: [Select]
mysql_select_db("terra_elegante_operations", $con);



$searchfor = $_GET['search_term'];


$query = "select * from client_information where name_last like \"%$searchfor%\"";

$result = mysql_query($query) or die("Couldn't execute query");

$row = mysql_fetch_array($result);

echo $row['0'];

I hope this entry finds everyone safe and healthy.

I am trying to extract table data and schema info from a database WITHOUT knowing the field names.

Essentially, I want to connect to the database and have the information for each table deposited into an HTML format (just like I'd see if I accessed the db directly).

I've found several methods online, but all use DEPRICATED coding that will no longer function.

Any code or links to assist in resolution would be appreciated. 

Stay safe, and thank you.

I am pulling some info from a mysql table, checking some logic, and displaying in on a page. The way this is written now it shows all of the items in a one column table, I simply want to break it up into multiple columns (ideally by specifying say 20 items per column). I know I need a counter and a loop but I'm just not sure how it all fits in with my existing program. Any help would be greatly appreciated.

Here is my code
Code: [Select]
$result2 = mysql_query("SELECT * FROM propertyids ORDER BY propertyname ASC");
while($row2 = mysql_fetch_array($result2)){
${'resp'.$row2['id']} = curl_multi_getcontent(${'ch'.$row2['id']});
${'status'.$row2['id']} = strpos(${'resp'.$row2['id']},$httpvar);
if(${'status'.$row2['id']} === false) {
echo "<tr><td>";
echo "<img src='images/down.png'> <a href='" . $row2['primaryurl'] . "' target='_blank'>" . $row2['propertyname'] . "</a>";
echo "</td></tr>";
}
else {
echo "<tr><td>";
echo "<img src='images/up.png'> <a href='" . $row2['primaryurl'] . "' target='_blank'>" . $row2['propertyname'] . "</a>";
echo "</td></tr>";
}
}
echo "</td></table>";

I am using the following code to generate a dynamic drop down menu from a column in table1(name) - and then inserting the selected option into table2.
What I am trying to do is, select data from 2 columns from table1(name,age) and then store and insert both of those values into table2

I am hoping someone can help me out or at least point me in the rigth direction. ..I would like to insert into table 2 the age that matches the person selected by the drop down menu from table1.

For example - if from the drop down menu I choose John - when the form is sumbitted i want to insert into table2 John's name and age (based on what is stored in table1, in this case John,22)

...Any ideas???

table1
id|name|age|score
01-john-22-1547
02-jane-22-1245

table2
id|county|name|age


the dynamic drop down is generated from table1 (name) with following code

Code: [Select]
<form method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>">

<table width="100%" border="0" cellpadding="5" cellspacing="0">

 

<?php

require_once('sql.php');

$dbc = mysqli_connect(DB_HOST, DB_USER, DB_PASSWORD, DB_NAME);



$query="SELECT name FROM table1  ORDER BY name ASC";

$result = mysqli_query ($dbc,$query) or die(mysqli_error());



$dropdown = "<select name='name'>";

while($row = mysqli_fetch_array($result)) {

$dropdown .= "\r\n<option value='{$row['name']}'>{$row['name']}</option>";

}

$dropdown .= "\r\n</select>";

echo $dropdown;

?>



      <tr>

          <td height="50" align="right">

                <label for="scheduled_time">Country</label><br/>

</td>

          <td align="left">

<input type="text" id="country" name="country" class="input" maxlength="30"" />

                </td>

      </table>

      <p></p>

    <input type="submit" value="Add Info" name="submit" />

</form>

I am inserting into table2 with the following code

Code: [Select]
<?php
$dbc = mysqli_connect(DB_HOST, DB_USER, DB_PASSWORD, DB_NAME);

if (isset($_POST['submit'])) {

$county = mysqli_real_escape_string($dbc, trim($_POST['country']));

$name = mysqli_real_escape_string($dbc, trim($_POST['name']));

$query = "INSERT INTO table2 (country, name) VALUES ('$country', '$name'')";
$result = mysqli_query($dbc, $query);

if (!$result) {

printf("query error : <br/> %s\n", mysqli_error($dbc));

}



if ($result) {

echo 'Success';

}



      // close dbc

      mysqli_close($dbc);

      exit();

      }

?>

hirealimo.com.au/code1.php

this works as i want it:
Quote

SELECT * FROM price INNER JOIN vehicle USING (vehicleID) WHERE vehicle.passengers >= 1 AND price.townID = 1 AND price.eventID = 1



but apparelty selecting * is not a good thing????

but if I do this:
Quote

SELECT priceID, price FROM price INNER JOIN vehicle....etc


it works but i lose the info from the vehicle table.

but how do i make this work:
Quote

SELECT priceID, price, type, description, passengers FROM price INNER JOIN vehicle....etc


so that i am specifiying which colums from which tables to query??

thanks

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