PHP - Getting Images From Database
Hi all, while I was coding a script for my website something struck me which ive not really got an idea how to code it, but anyway, in my Database ive got a table which holds image URL's but how could I echo them out in PHP which will show the image? Not just the writing.
Thanks for your help. Similar TutorialsHello, I am new to PHP coding, and I have some issues trying to upload multiple images into database. The code works only for 1 image, but when I try to add foreach, I receive this message: Warning: Invalid argument supplied for foreach() . Can anyone help me ?
I have this code which uoploads and resizes the images into a folder without a problem. My problem is I am unable to view the Thumb or Full image which has uploaded to the folder and the database with the other data. How do i correct this problem code below. Thanks upload form and script Code: [Select] <?php //database properties $dbhost = 'localhost'; $dbuser = 'user'; $dbpass = 'pass'; $dbname = 'DB'; // make a connection to mysql here $conn = mysql_connect ($dbhost, $dbuser, $dbpass) or die ("I cannot connect to the database because: " . mysql_error()); mysql_select_db ($dbname) or die ("I cannot select the database '$dbname' because: " . mysql_error()); /******** start function ********/ function errors($error){ if (!empty($error)) { $i = 0; echo "<blockquote>\n"; while ($i < count($error)){ echo "<p><span class=\"warning\">".$error[$i]."</span></p>\n"; $i ++;} echo "</blockquote>\n"; }// close if empty errors } // close function // ----------------Create Smaller version of large image--------------------- function createthumbfull($src_filename, $dst_filename_full) { // Get information about the image list($src_width, $src_height, $type, $attr) = getimagesize( $src_filename ); // Load the image based on filetype switch( $type ) { case IMAGETYPE_JPEG: $starting_image = imagecreatefromjpeg( $src_filename ); break; case IMAGETYPE_PNG: $starting_image = imagecreatefrompng( $src_filename ); break; case IMAGETYPE_GIF: $starting_image = imagecreatefromgif( $src_filename ); break; default: return false; } // get the image to create thumbnail from $starting_image; // get image width $width = imagesx($starting_image); // get image height $height = imagesy($starting_image); // size to create thumnail width $thumb_width = 600; // divide iwidth by specified thumb size $constant = $width/$thumb_width; // round height by constant and add t thumb_height $thumb_height = round($height/$constant, 0); //create thumb with true colours $thumb_image = imagecreatetruecolor($thumb_width, $thumb_height); //create thumbnail resampled to make image smooth imagecopyresampled($thumb_image, $starting_image, 0, 0, 0, 0, $thumb_width, $thumb_height, $width, $height); $ran = rand () ; $thumb1 = $ran.".jpg"; global $thumb_Add_full; $thumb_Add_full = $dst_filename_full; $thumb_Add_full .= $thumb1; imagejpeg($thumb_image, "" .$dst_filename_full. "$thumb1"); } //-------------------- create thumbnail -------------------------------------------- //$src_filename = source of image //$dst_filename_thumb = location to store final image function createthumb($src_filename, $dst_filename_thumb) { $size = getimagesize($src_filename); // get image size $stype = $size['mime']; //get image type : gif,png,jpg $w = $size[0]; // width of image $h = $size[1]; // height of image //do a switch statment to create image from right image type switch($stype) { //if image is gif create from gif case 'image/gif': $simg = imagecreatefromgif($src_filename); break; //if image is jpeg create from jpeg case 'image/jpeg': $simg = imagecreatefromjpeg($src_filename); break; //if image is png create from png case 'image/png': $simg = imagecreatefrompng($src_filename); break; } $width = $w; // get image width $height = $h; // get image height // size to create thumnail width $thumb_width = 150; $thumb_height = 150; //use true colour for image $dimg = imagecreatetruecolor($thumb_width, $thumb_height); $wm = $width/$thumb_width; //width divided by new width $hm = $height/$thumb_height; //height divided by new height $h_height = $thumb_height/2; //ass new height and chop in half $w_height = $thumb_width/2; //ass new height and chop in half //if original width is more then original height then modify by width if($w> $h) { $adjusted_width = $w / $hm; // add original width and divide it by modified height and add to var $half_width = $adjusted_width / 2; // chop width in half $int_width = $half_width - $w_height; // take away modified height from new width //make a copy of the image imagecopyresampled($dimg,$simg,-$int_width,0,0,0,$adjusted_width,$thumb_height,$w,$h); //else if original width is less or equal to original height then modify by height } elseif(($w <$h) || ($w == $h)) { $adjusted_height = $h / $wm; // diving original height by modified width $half_height = $adjusted_height / 2; // chop height in half $int_height = $half_height - $h_height; // take away modified height from new width //make a copy of the image imagecopyresampled($dimg,$simg,0,-$int_height,0,0,$thumb_width,$adjusted_height,$w,$h); } else { // don't modify image and make a copy imagecopyresampled($dimg,$simg,0,0,0,0,$thumb_width,$thumb_height,$w,$h); } $ran = "thumb_".rand (); // generate random number and add to a string $thumb2 = $ran.".jpg"; //add random string to a var and append .jpg on the end global $thumb_Add_thumb; //make this var available outside the function as it will be needed later. $thumb_Add_thumb = $dst_filename_thumb; // add destination $thumb_Add_thumb .= $thumb2; // append file name on the end //actually create the final image imagejpeg($dimg, "" .$dst_filename_thumb. "$thumb2"); } /********end functions ***********/ // if form submitted then process form if (isset($_POST['submit'])){ // check feilds are not empty $imageTitle = trim($_POST['imageTitle']); if (strlen($imageTitle) < 3 || strlen($imageTitle) > 255) { $error[] = 'Title must be at between 3 and 255 charactors.'; } // check feilds are not empty or check image file size if (!isset($_FILES["uploaded"])) { $error[] = 'You forgot to select an image.'; } // check feilds are not empty $imageDesc = trim($_POST['imageDesc']); if (strlen($imageDesc) < 3) { $error[] = 'Please enter a description for your image.'; } // location where inital upload will be moved to $target = "productimages/" . $_FILES['uploaded']['name'] ; // find the type of image switch ($_FILES["uploaded"]["type"]) { case $_FILES["uploaded"]["type"] == "image/gif": move_uploaded_file($_FILES["uploaded"]["tmp_name"],$target); break; case $_FILES["uploaded"]["type"] == "image/jpeg": move_uploaded_file($_FILES["uploaded"]["tmp_name"],$target); break; case $_FILES["uploaded"]["type"] == "image/pjpeg": move_uploaded_file($_FILES["uploaded"]["tmp_name"],$target); break; case $_FILES["uploaded"]["type"] == "image/png": move_uploaded_file($_FILES["uploaded"]["tmp_name"],$target); break; case $_FILES["uploaded"]["type"] == "image/x-png": move_uploaded_file($_FILES["uploaded"]["tmp_name"],$target); break; default: $error[] = 'Wrong image type selected. Only JPG, PNG or GIF accepted!.'; } // if valadation is okay then carry on if (!$error) { // post form data $imageTitle = $_POST['imageTitle']; $imageDesc = $_POST['imageDesc']; //strip any tags from input $imageTitle = strip_tags($imageTitle); $imageDesc = strip_tags($imageDesc); // add slashes if needed if(!get_magic_quotes_gpc()) { $imageTitle = addslashes($imageTitle); $imageDesc = addslashes($imageDesc); } // remove any harhful code and stop sql injection $imageTitle = mysql_real_escape_string($imageTitle); $imageDesc = mysql_real_escape_string($imageDesc); //add target location to varible $src_filename $src_filename = $target; // define file locations for full sized and thumbnail images $dst_filename_full = 'productimages/'; $dst_filename_thumb = 'productthumb/'; // create the images createthumbfull($src_filename, $dst_filename_full); //call function to create full sized image createthumb($src_filename, $dst_filename_thumb); //call function to create thumbnail image // delete original image as its not needed any more. unlink ($src_filename); // insert data into images table $query = "INSERT INTO table (imageTitle, imageThumb, imageFull, imageDesc) VALUES ('$imageTitle', '$thumb_Add_thumb', '$thumb_Add_full', '$imageDesc')"; $result = mysql_query($query) or die ('Cannot add image because: '. mysql_error()); // show a message to confirm results echo "<h3 align='center'> $imageTitle uploaded</h3>"; } } //dispaly any errors errors($error); ?> <form enctype="multipart/form-data" action="" method="post"> <fieldset> <legend>Upload Picture</legend> <p>Only JPEG, GIF, or PNG images accepted</p> <p><label>Title<br /></label><input type="text" name="imageTitle" <?php if (isset($error)){ echo "value=\"$imageTitle\""; }?> /></p> <p><label>Image<br /></label><input type="file" name="uploaded" /></p> <p><label>Description<br /></label><textarea name="imageDesc" cols="50" rows="10"><?php if (isset($error)){ echo "$imageDesc"; }?></textarea></p> <p><label> </label><input type="submit" name="submit" value="Add Image" /></p> </fieldset> </form> view data Code: [Select] <?php // Connects to your Database mysql_connect("localhost", "user", "pass") or die(mysql_error()) ; mysql_select_db("DB") or die(mysql_error()) ; //Retrieves data from MySQL $data = mysql_query("SELECT * FROM table") or die(mysql_error()); //Puts it into an array while($info = mysql_fetch_array( $data )) { ?> <?php echo "<img src=http://www.web.com/productimages/" .$info['imagefull'] ." > <br>"; ?> <?php echo "<img src=http://www.web.com/productthumb/" .$info['imageThumb'] ." > <br>"; ?> <?php echo "<b>imageTitle:</b> ".$info['imageTitle'] . "<br> "; ?> <?php echo "<b>imageDesc:</b> ".$info['imageDesc'] . " <hr>"; ?> <?php }?> I want users to be allowed to upload images to a table in a database but I cannot seem to find a suitable way to implementing using the code I already have, here is the code below; Code: [Select] <?php error_reporting(E_ALL ^ E_NOTICE); ini_set("display_errors", 1); require_once ('./includes/config.inc.php'); require_once (MYSQL); $add_cat_errors = array(); if ($_SERVER['REQUEST_METHOD'] == 'POST') { if (!empty($_POST['product'])) { $prod = mysqli_real_escape_string($dbc, strip_tags($_POST['product'])); } else { $add_cat_errors['product'] = 'Please enter a Product Name!'; } if (filter_var($_POST['prod_descr'])) { $prod_descr = mysqli_real_escape_string($dbc, strip_tags($_POST['prod_descr'])); } else { $add_cat_errors['prod_descr'] = 'Please enter a Product Description!'; } // Check for a category: if (filter_var($_POST['cat'], FILTER_VALIDATE_INT, array('min_range' => 1))) { $catID = $_POST['cat']; } else { // No category selected. $add_page_errors['cat'] = 'Please select a category!'; } if (filter_var($_POST['price'])) { $price = mysqli_real_escape_string($dbc, strip_tags($_POST['price'])); } else { $add_cat_errors['price'] = 'Please enter a Product Description!'; } if (filter_var($_POST['stock'])) { $stock = mysqli_real_escape_string($dbc, strip_tags($_POST['stock'])); } else { $add_cat_errors['stock'] = 'Please enter a Product Description!'; } if (empty($add_cat_errors)) { $query = "INSERT INTO product (product, prod_descr, catID, price, image, stock) VALUES ('$prod', '$prod_descr', '$catID', '$price', '$image', '$stock')"; $r = mysqli_query ($dbc, $query); if (mysqli_affected_rows($dbc) == 1) { echo '<p>Record Successfully Added!!!!!</p>'; $_POST = array(); } else { trigger_error('OH NOOOOO!!!!'); } } } require_once ('./includes/form_functions.inc.php'); ?> <form action="add_product.php" method="post"> Product Name: <?php create_form_input('product', 'text', $add_cat_errors);?> Product Description: <?php create_form_input ('prod_descr', 'text', $add_cat_errors);?> Category: <select name="cat"<?php if (array_key_exists('cat', $add_cat_errors))?>> <option>Select a Category</option> <?php $q = "SELECT catID, cat FROM category ORDER BY cat ASC"; $r = mysqli_query($dbc, $q); while ($row = mysqli_fetch_array($r, MYSQLI_NUM)) { echo "<option value=\"$row[0]\""; if (isset($_POST['cat']) && ($_POST['cat'] == $row[0])) echo 'selected="selected"'; echo ">$row[1]</option>\n"; } ?> Price: <?php create_form_input('price', 'text', $add_cat_errors);?> Upload an Image: <?php if(array_key_exists('image', $add_cat_errors)) { echo '<input type="file" name="image" />'; } ?> Stock: <?php create_form_input('stock', 'text', $add_cat_errors);?> <input type="submit" name="submit_button" value="ADD RECORD" /> </form> Everything else writes perfectly but I have been trying ways to create a file upload and write successfully to the database. The 'image' field has a data type of 'varchar'. I apologise immensely for the long winded explanation but if anyone could help me please that would be much appreciated. Hi guys its me again, I am having a problem that I cant figure out... Here is my code: <?php $sqlCommand = "SELECT image FROM background"; $query = mysqli_query($myConnection, $sqlCommand) or die (mysqli_error()); $sqlCommand2 = "SELECT backgroundimage FROM site"; $query2 = mysqli_query($myConnection, $sqlCommand2) or die (mysqli_error()); while ($row = mysqli_fetch_array($query)) { while ($row2 = mysqli_fetch_array($query2)) { if($row['image'] == $row2['backgroundimage']){ echo '<img src="site_background/'.$row['image'].'" width="75px" height="75px" style="border:2px solid red;" /><br /><br />'; } if($row['image'] != $row2['backgroundimage']){ echo '<img src="site_background/'.$row['image'].'" width="50px" height="50px" style="border:2px solid black;" />'; } } } mysqli_free_result($query); mysqli_free_result($query2); ?> What is will do is get the images from the "backgrounds" table and the image from the "site" table (the current image). I am then wanting to pick out the current image and give it a red border and then display the other left over images smaller with a black border. I can get the images to all display with the black border or the current image to display with a red border but the other images dont show... I have tried mixing things around but I have not been able to get all the images to display with the formatting I want. I dont know if it is a simple syntax error or I am doing things completely wrong... I have been looking at it for so long its just become one big mess of code to me lol Any help to get this working as I want would be great! Cheers Ben Is it better to store uploaded images as 'content' in the database? (like he http://www.techsupportforum.com/forums/f49/tutorial-upload-files-to-database-176804.html).. Or just as a regular file which is referenced in the database..? I want to display 3 clickable images in a single row which repeats as long as there is data in the database, so far it is displaying a single clickable image from the database. below is all the code.. <table width="362" border="0"> <?php $sql=mysql_query("select * from `publication` GROUP BY `catsue`") or die(mysql_error()); $num=mysql_num_rows($sql); while($rowfor=mysql_fetch_array($sql)) { $cat=$rowfor['catsue']; $pic=mysql_query("select * from `category` where `catsue`='$cat'") or die(mysql_error()); $picP=mysql_fetch_array($pic); $base=basename($picP['title']); ?> <tr> <td width="352" height="88"><table width="408" border="0"> <tr> <td width="113" rowspan="5"><a href="archive_detail.php?id=<?php echo $rowfor['id'];?>&category=<?php echo $rowfor['catsue'];?>"><img src="ad/pic/<?php echo $base;?>" width="100" height="100" border="0"/></a></td> <td width="94">Title</td> <td width="179" height="1"><?php echo $rowfor['catsue'];?> </td> </tr> <tr> <td> </td> <td width="179" height="3"> </td> </tr> <tr> <td> </td> <td width="179" height="8"> </td> </tr> <tr> <td> </td> <td width="179" height="17"> </td> </tr> <tr> <td> </td> <td width="179" height="36"> </td> </tr> </table></td> </tr> <?php }?> </table> One image is displaying but when i choose image 2 it overlaps image 1..
gallery.php 8.77KB
7 downloads
this is the line in my script that I have to show the image: Code: [Select] $output .= "<img>{$row['disp_pic']}</img></br>\n"; As you can see I added the image tag, but it wont show the actual image. IE shows it as a small square with another small square picture icon in the middle of it (i'm sure you guys know what i mean). I am trying to add a second image upload to a form I have, but I can't figure out how to get the insert statement and upload statement working properly. The first file uploads and inserts to the database properly, but can anyone tell me how to add a second image to the mix? Here is what I currently have: Code: [Select] //if ((($_FILES["file"]["type"] == "image/gif") //|| ($_FILES["file"]["type"] == "image/jpeg") //|| ($_FILES["file"]["type"] == "image/pjpeg")) //&& ($_FILES["file"]["size"] < 20000)) // { if ($_FILES["file"]["error"] > 0) { echo "Return Code: " . $_FILES["file"]["error"] . "<br />"; } else { //echo "Upload: " . $_FILES["file"]["name"] . "<br />"; //echo "Type: " . $_FILES["file"]["type"] . "<br />"; //echo "Size: " . ($_FILES["file"]["size"] / 1024) . " Kb<br />"; //echo "Temp file: " . $_FILES["file"]["tmp_name"] . "<br />"; if (file_exists("upload/" . $_FILES["file"]["name"])) { echo $_FILES["file"]["name"] . " already exists. "; } else { move_uploaded_file($_FILES["file"]["tmp_name"], "upload/" . $_FILES["file"]["name"]); //echo "Stored in: " . "http://www.webdesignsbyliz.com/wdbl_wordpress/wp-content/themes/twentyten_2/upload/" . $_FILES["file"]["name"]; $image = $_FILES["file"]["name"]; $query = "INSERT INTO gallery VALUES ('', '$cut', '$color', '$carats', '$clarity', '$size', '$metal', '$other', '$total', '$certificate', '$value', '$image', '$name', '$desc', '$item_no', '$type', '$image2')"; $query_res = mysql_query($query) or die(mysql_error()); } } I thought I could simply add a second move_uploaded_file line and replace "file" with "file2" (the name of my second file upload field from the form), but it's not working. Can anyone tell me the right way to do this, please? Thanks in advance! I'm not experienced with file uploads yet :-( Hi, here's my problem: I am trying to make a simple online buying website and I want to display a table with all the fields for each item. So I got that part down which is to just use mysql_fetch_assoc("SELECT * FROM myTable") and use the html table tags stuff, but now I want to display my images in the table, so here's my code to display my mysql database table in html's table tag along w/ php: <html> <head> <title>My Online buying website project</title> </head> <body> <?php mysql_connect("localhost","root"); mysql_select_db("myTable"); $imagesArray=array("Apple_iPhone3GS.jpg","Apple_iPhone4.jpg","product3.jpg","product4.jpg","product5.jpg"); $result=mysql_query("SELECT Name, Manufacturer, Price, Description, SimSupport FROM myTable"); if(mysql_num_rows($result))//if there is at least one entry in bellProducts, make a table { print "<table border='border'>"; print "<tr> <th>Name</th> <th>Manufacturer</th> <th>Price</th> <th>Description</th> <th>SimSupport</th> </tr>"; //NB: now output each row of records while($row=mysql_fetch_assoc($result)) { extract($row); print "<tr> <td>$Name</td> <td>$Manufacturer</td> <td>$Price</td> <td>$Description</td><td>$SimSupport</td> </tr>"; }//END WHILE }//END IF ?> </table> </body> </html> *So how do I go about adding my images in this table? Hey guys, i'm new to this site and would need some help with coding. So i'm making a car part website which should has brand/model search. It's a dropdown search which will get the brand / model from database and should display all the parts for that exact model, from folder. Database structure which i have is id, master, name. ( Here's some pictures to clear out what i'm doing. http://imgur.com/a/7XwVd ) So the problem is that it does not get the images from folder named ex: *_audi_a3.jpg. And link to codes what have been written already. Parts.php: http://pastebin.com/q6vdypge Update.php: http://pastebin.com/DymhGQ17 Search_images.php: http://pastebin.com/LF5Q0i8f Core.js: http://pastebin.com/bgc0y4TS I don't know what's wrong with it sadly. One thing i noticed when i used firebug it gives error on category when searching error:true. Hope you guys understand what i mean here, and also all help is appreciated. And move this post if it's in wrong place. Thanks! Edited by aeonius, 17 October 2014 - 12:15 PM. Dear all, I have a problem that I need to be helped with using one form and storing the images in database. I would like to upload multiple images with same title from "title" field. Can somebody help me with this? <?php $db_host = 'localhost'; // don't forget to change $db_user = 'mysql-user'; $db_pwd = 'mysql-password'; $database = 'test'; $table = 'ae_gallery'; // use the same name as SQL table $password = '123'; // simple upload restriction, // to disallow uploading to everyone if (!mysql_connect($db_host, $db_user, $db_pwd)) die("Can't connect to database"); if (!mysql_select_db($database)) die("Can't select database"); // This function makes usage of // $_GET, $_POST, etc... variables // completly safe in SQL queries function sql_safe($s) { if (get_magic_quotes_gpc()) $s = stripslashes($s); return mysql_real_escape_string($s); } // If user pressed submit in one of the forms if ($_SERVER['REQUEST_METHOD'] == 'POST') { // cleaning title field $title = trim(sql_safe($_POST['title'])); if ($title == '') // if title is not set $title = '(empty title)';// use (empty title) string if ($_POST['password'] != $password) // cheking passwors $msg = 'Error: wrong upload password'; else { if (isset($_FILES['photo'])) { @list(, , $imtype, ) = getimagesize($_FILES['photo']['tmp_name']); // Get image type. // We use @ to omit errors if ($imtype == 3) // cheking image type $ext="png"; // to use it later in HTTP headers elseif ($imtype == 2) $ext="jpeg"; elseif ($imtype == 1) $ext="gif"; else $msg = 'Error: unknown file format'; if (!isset($msg)) // If there was no error { $data = file_get_contents($_FILES['photo']['tmp_name']); $data = mysql_real_escape_string($data); // Preparing data to be used in MySQL query mysql_query("INSERT INTO {$table} SET ext='$ext', title='$title', data='$data'"); $msg = 'Success: image uploaded'; } } elseif (isset($_GET['title'])) // isset(..title) needed $msg = 'Error: file not loaded';// to make sure we've using // upload form, not form // for deletion if (isset($_POST['del'])) // If used selected some photo to delete { // in 'uploaded images form'; $id = intval($_POST['del']); mysql_query("DELETE FROM {$table} WHERE id=$id"); $msg = 'Photo deleted'; } } } elseif (isset($_GET['show'])) { $id = intval($_GET['show']); $result = mysql_query("SELECT ext, UNIX_TIMESTAMP(image_time), data FROM {$table} WHERE id=$id LIMIT 1"); if (mysql_num_rows($result) == 0) die('no image'); list($ext, $image_time, $data) = mysql_fetch_row($result); $send_304 = false; if (php_sapi_name() == 'apache') { // if our web server is apache // we get check HTTP // If-Modified-Since header // and do not send image // if there is a cached version $ar = apache_request_headers(); if (isset($ar['If-Modified-Since']) && // If-Modified-Since should exists ($ar['If-Modified-Since'] != '') && // not empty (strtotime($ar['If-Modified-Since']) >= $image_time)) // and grater than $send_304 = true; // image_time } if ($send_304) { // Sending 304 response to browser // "Browser, your cached version of image is OK // we're not sending anything new to you" header('Last-Modified: '.gmdate('D, d M Y H:i:s', $ts).' GMT', true, 304); exit(); // bye-bye } // outputing Last-Modified header header('Last-Modified: '.gmdate('D, d M Y H:i:s', $image_time).' GMT', true, 200); // Set expiration time +1 year // We do not have any photo re-uploading // so, browser may cache this photo for quite a long time header('Expires: '.gmdate('D, d M Y H:i:s', $image_time + 86400*365).' GMT', true, 200); // outputing HTTP headers header('Content-Length: '.strlen($data)); header("Content-type: image/{$ext}"); // outputing image echo $data; exit(); } ?> <html><head> <title>MySQL Blob Image Gallery Example</title> </head> <body> <?php if (isset($msg)) // this is special section for // outputing message { ?> <p style="font-weight: bold;"><?=$msg?> <br> <a href="<?=$PHP_SELF?>">reload page</a> <!-- I've added reloading link, because refreshing POST queries is not good idea --> </p> <?php } ?> <h1>Blob image gallery</h1> <h2>Uploaded images:</h2> <form action="<?=$PHP_SELF?>" method="post"> <!-- This form is used for image deletion --> <?php $result = mysql_query("SELECT id, image_time, title FROM {$table} ORDER BY id DESC"); if (mysql_num_rows($result) == 0) // table is empty echo '<ul><li>No images loaded</li></ul>'; else { echo '<ul>'; while(list($id, $image_time, $title) = mysql_fetch_row($result)) { // outputing list echo "<li><input type='radio' name='del' value='{$id}'>"; echo "<a href='{$PHP_SELF}?show={$id}'>{$title}</a> – "; echo "<small>{$image_time}</small></li>"; } echo '</ul>'; echo '<label for="password">Password:</label><br>'; echo '<input type="password" name="password" id="password"><br><br>'; echo '<input type="submit" value="Delete selected">'; } ?> </form> <h2>Upload new image:</h2> <form action="<?=$PHP_SELF?>" method="POST" enctype="multipart/form-data"> <label for="title">Title:</label><br> <input type="text" name="title" id="title" size="64"><br><br> <label for="photo">Photo:</label><br> <input type="file" name="photo" id="photo"><br><br> <label for="password">Password:</label><br> <input type="password" name="password" id="password"><br><br> <input type="submit" value="upload"> </form> </body> </html> Basically i have a folder with 100+ images they are NOT all the same extension, what im wanting to do is use PHP to find all the images and put them all in a database. how would i go about doing this? thanks I have this script from http://lampload.com/...,view.download/ (I am not using a database) I can upload images fine, I can view files, but I want to delete them. When I press the delete button, nothing happens
http://www.jayg.co.u...oad_gallery.php
<form>
<?php $dir = dirname(__FILENAME__)."/images/gallery" ; $files1 = scandir($dir); foreach($files1 as $file){ if(strlen($file) >=3){ $foil = strstr($file, 'jpg'); // As of PHP 5.3.0 $foil = $file; $pos = strpos($file, 'css'); if ($foil==true){ echo '<input type="checkbox" name="filenames[]" value="'.$foil.'" />'; echo "<img width='130' height='38' src='images/gallery/$file' /><br/>"; // for live host //echo "<img width='130' height='38' src='/ABOOK/SORTING/gallery-dynamic/images/gallery/ $file' /><br/>"; } } }?> <input type="submit" name="mysubmit2" value="Delete"> </form>
any ideas please?
thanks
I have a very tricky php problem here. At least for me. On a page that is editing a job entry. I have a database generated group of checkboxes some of which have been checked when the job was entered. So the script has to do two things generate the complete list of checkboxes and check the ones that have already been selected in the job request. The below script is what I've done trying to figure it out. Description of what I'm trying to do: I'm generating the the boxes with a call to my database for the list of checkboxes. Then I'm building an array with all the possible items that could be checked to compare against. Ok here is where I think my first problem is. I need to make a second query to another table "worklog" in the same database. This is where the list of checked items are stored. What is the best way to do this? A second query seems wrong "or at least not efficient" Code: [Select] <div class="text">Job Type (<a class="editlist" href="javascript:editlist('listedit.php?edit=typelist',700,400);">edit list</a>):</div> <div class="field"> <?PHP $connection=mysql_connect ("localhost", "user", "password") or die ("I cannot connect to the database."); $db=mysql_select_db ("database", $connection) or die (mysql_error()); $query = "SELECT type FROM typelist ORDER BY type ASC"; $sql_result = mysql_query($query, $connection) or die (mysql_error()); $i=1; echo '<table valign="top"><tr><td>'; while ($row = mysql_fetch_array($sql_result)) { $type = $row["type"]; if ($i > 1 && $i % 26 == 0) echo '</td><td>'; else if ($i) echo ''; ++$i; $aTypes = array ("Spec Ad Campaign", "100 x 100 Logo", "100 x 35 (Featured Developer/Broker)", "100 x 40 (Featured Lender)", "120 x 180 (Home Page Auto)", "120 x 45 (Half Tile - Jobs)", "120x60 (Section Sponsor)", "125 x 40 (Profile Page logo)", "135 x 31 (Autos)", "135 x 60 (Autos)", "135 x 60 (Logotile - Jobs)", "150 x 40 (Auto Logo)", "160 x 240 (monster tile)", "160 x 400 (Skyscraper)", "160 x 600 (Tower)", "170x30 (Section Sponsor)", "240 x 180 JPG/GIF Auto Video", "240 x 180 size FLV video ", "300 x 250 (Story Ad)", "300 x 600 (Halfpage)", "468 x 60 (Banner Jpg/Gif)", "728 x 90 (Leaderboard)", "95 x 75 (Sweeps Logo) ", "Agent Profile Page", "Contest", "Creative Change", "Employer Profile", "Holiday Shop", "Home of the Week", "HP Half Banner (234 x 60 Static)", "Mobile Ads (320x53 *300x50*216x36*168x28)", "Newsletter", "Peelback", "Pencil Ad", "Print", "Real Deals", "Resize ad campaign", "Roll-Over Skyscraper", "Site Sponsor logo (170x30)", "Splash Page Production", "Travel Deals Update", "Video Ad", "Web Development", "Web Maintenance", "Web Quote (or Design)"); $dbTypes = explode(',',$row['type']); foreach ($aTypes as $type){ if(in_array($aType,$dbTypes)){ echo "<input style='font-size:10px;' name='type[]' type='checkbox' value='$type' CHECKED><span style='color:#000;'>$type</span></input><br/>"; }else { echo "<input style='font-size:10px;' name='type[]' type='checkbox' value='$type'><span style='color:#000;'>$type</span></input><br/>"; } } } echo '</td></tr></table>'; ?> </div> At the moment I am creating a search function for my website. The approach I have in mind is a pseudo-PHP database. To give an example: A HTML form will submit the results to a PHP file. HTML FORM - Colour: Black PHP RESULT PAGE - if ($_POST['color'] == 'Black') {readfile("./products/black/*.html");} HTML FORM - Price: <$50 PHP RESULT PAGE - if ($_POST['Price'] == '<$50') {readfile("./products/less50/*.html");} The problem here is if there is an item that is black and costs less than $50, then its going to be listed twice. There is probably some code I can write to ommit the listing of duplicate entries, but it is probably going to be messy, so I am wondering if its better to use a centralized MySQL database, rather than a pseudo-PHP database? I've never used MySQL and don't know much about it and this is my first real attempt at using PHP. hello everyone, I am about to start coding my pages to display results from a database but before i do i want to know information about the following : Is it best to upload images to a database?and display them accordingly? or is it best to use images from a directory? What is most commonly used and or more reliable? Another topic i have trouble finding information on is actually positioning the output from you mysql database, is this practice done with tables?fields and rows? What is this method called? And is there more then one way to go about controlling result layout on your page? Sorry about the 1001 questions , but i am unable to find a clear answer on the topic ..especially question two . Thanks in advance. after cloasing connection of database i still got the values form database. Code: [Select] <?php session_start(); /* * To change this template, choose Tools | Templates * and open the template in the editor. */ require_once '../database/db_connecting.php'; $dbname="sahansevena";//set database name $con= setConnections();//make connections use implemented methode in db_connectiong.php mysql_select_db($dbname, $con); //update the time and date of the admin table $update_time="update admin set last_logged_date =CURDATE(), last_log_time=CURTIME() where username='$uname'limit 3,4"; //my admin table contain 5 colums they are id, username,password, last_logged_date, last_log_time $link= mysql_query($update_time); // mysql_select_db($dbname, $link); //$con=mysql_connect('localhost', 'root','ijts'); $result="select * from admin where username='a'"; $result=mysql_query($result); mysql_close($con); //here i just check after closing data baseconnection whether i do get reselts but i do, why? echo "after the cnnection was closed"; if(!$result){ echo "cont fetch data"; }else{ $row= mysql_fetch_array($result); echo "id".$row[0]."usrname".$row[1]."passwped".$row[2]."date".$row[3]."time".$row[4]; } // echo "<html>"; //echo "<table border='1' cellspacing='1' cellpadding='2' align='center'>"; // echo "<thead>"; // echo"<tr>"; // echo "<th>"; // echo ID; // echo"</th>"; // echo" <th>";echo Username; echo"</th>"; // echo"<th>";echo Password; echo"</th>"; // echo"<th>";echo Last_logged_date; echo "</th>"; // echo "<th>";echo Last_logged_time; echo "</th>"; // echo" </tr>"; // echo" </thead>"; // echo" <tbody>"; //while($row= mysql_fetch_array($result,MYSQL_BOTH)){ // echo "<tr>"; // echo "<td>"; // echo $row[0]; // echo "</td>"; // echo "<td>"; // echo $row[1]; // echo "</td>"; // echo "<td>"; // echo $row[2]; // echo "</td>"; // echo "<td>"; // echo $row[3]; // echo "</td>"; // echo "<td>"; // echo $row[4]; // echo "</td>"; // echo "</tr>"; // } // echo" </tbody>"; // echo "</table>"; // echo "</html>"; session_destroy(); session_commit(); echo "session and database are closed but i still get values from doatabase session is destroyed".$_SESSION['admin']; ?> session is destroyed but database connection is not closed. thanks I have a standard form that displays users current data from a mysql database once logged in(code obtained from the internet). Users can then edit their data then submit it to page called editform.php that does the update. All works well except that the page does not display the updated info. Users have to first logout and login again to see the updated info. even refreshing the page does not show the new info. Please tell me where the problem is as i am new to php.
my form page test.php
<?PHP require_once("./include/membersite_config.php"); if(!$fgmembersite->CheckLogin()) { $fgmembersite->RedirectToURL("login.php"); exit; } ?> <form action="editform.php?id_user=<?= $fgmembersite->UserId() ?>" method="POST"> <input type="hidden" name="id_user" value="<?= $fgmembersite->UserId() ?>"><br> Name:<br> <input type="text" name="name" size="40" value="<?= $fgmembersite->UserFullName() ?>"><br><br> Email:<br> <input type="text" name="email" size="40" value="<?= $fgmembersite->UserEmail() ?> "><br><br> Address:<br> <input type="text" name="address" size="40" value="<?= $fgmembersite->UserAddress() ?> "><br><br> <button>Submit</button>my editform.php <?php $con = mysqli_connect("localhost","root","user","pass"); if (mysqli_connect_errno()) { echo "Failed to connect to MySQL: " . mysqli_connect_error(); } mysqli_query($con,"UPDATE fgusers3 SET name = '".$_POST['name']."', email= '".$_POST['email']."', address= '".$_POST['address']."' WHERE id_user='".$_POST['id_user']."'"); header("Location: test.php"); ?> Hi guys, I was just wondering if anyone could help me. I've got a My_SQL database containing articles, a summary for the article and a date. I have a basic CMS system set-up, but I want to create a script that when users sign up to a mail list it forwards the summary and dates of the articles database. If that makes sense? But I only want it to forward the most recent 5 rows. I'm pretty new to PHP and I've been mostly following tutorials thus far, but this is quite specific. Thanks in advance! |