PHP - Link To A Variable
Hy,
How can I put a link to a variable without doing like: Code: [Select] <a href='#'>$var</a> I heard that can be other ways. Thanks Similar Tutorialsive done a page that works fine but id like to add links to the results so i can view the models. working page here http://sts.hostei.com/dsgi/list_records.php in the make column i want a link that will only show the make clicked. if this was a fixed page i no how to do it but i cannot figure out to make it from the way ive discribed. i know i have to alter this line <td><div align="center"><?php echo $rows['make']; php?></div></td> but no idea how to do this. do i create a new page for the query? if so how do i pass the $var? is it possable to do this from the same page? ie appear undr the main table. Thanks <?php include("config.php"); // Connect to server and select database. mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); $sql = "SELECT make, COUNT(*) AS total, SUM(IF(comments = \'pass\', 1, 0)) AS withComments FROM dsgi_serval GROUP BY make ORDER BY COUNT(*) DESC"; $result=mysql_query($sql); php?> <table width="319" border="1"><tr> <td colspan="4"><font size="4" face="Verdana"> <strong><div align="center">Validation Total's </div></strong></font> </td> </tr> <tr> <td width="137" align="center"><strong>Make</strong></td> <td width="85" align="center"><strong>Total</strong></td> <td width="75" align="center"><strong>Validated</strong></td> </tr> <?php while($rows=mysql_fetch_array($result)){ php?> <tr> <td><div align="center"><?php echo $rows['make']; php?></div></td> <td><div align="center"><?php echo $rows['total']; php?></div></td> <td><div align="center"><?php echo $rows['withComments']; php?></div></td> </tr> <?php } php?> <tr> <td><div align="center">Totals</div></td> <td> <div align="center"> <?php // counts all rows $query = "SELECT make, COUNT(make) FROM dsgi_serval "; $result1 = mysql_query($query) or die(mysql_error()); // Print out result while($row1 = mysql_fetch_array($result1)){ echo $row1['COUNT(make)']; } ?> </div></td> <td><div align="center"> <?php // counts passes $query = "SELECT make, COUNT(make) FROM dsgi_serval where comments like 'pass'"; $result2 = mysql_query($query) or die(mysql_error()); while($row2 = mysql_fetch_array($result2)){ echo $row2['COUNT(make)']; } ?> </div></td> </tr> </table> <?php mysql_close(); php?> trying to post a link to the database Code: [Select] $amessage ="<a href="link.php">this is a link </a>"; then return that link later on another page. Hi. I have a sort of security script which checks a few things, how can i save the url of the link that was clicked, so i can pass it through the script then if all is good, continue on to the url, if not send them somewhere else let me try to explain better with a little text picture user clicks link ----------------------> link goes to my security script --------------------> if the check passes, continue to original links url so basically i just need to know how to save the links url as a variable I have a page that lists out some basic information about each quiz this particular student has taken (call it "quiz summary"). I am creating another page that will have all details of a particular quiz by itself (call it "quiz detail"). If I have a link for each quiz on the "quiz summary" page, how do I tell the "quiz detail' page which link they clicked on? Or which quiz they have selected. I was thinking it would work if I assigned a session variable to each link and then the "quiz detail" page could verify which returns true still and show details for that quiz. Would this logic work? Npot sure how to do it anyone though. thanks for any help! Hi guys, I want to find the most efficient way of setting a php variable through a link.
What I'm trying to achieve is to allow the user to select a category and their location and store the two variables to update my database results. I first used the GET method, but since the page refreshes when the user selects any other Get variable, so it ends up reseting the variables. Currently I have the category and locations as drop down menu with links to each of the options. I'll appreciate any help. Thank you. :]
I have this link "https://localhost/what/index.php?album=parent%2Fsubalbum&image=1coffee.jpg" Am trying to insert a variable(eid=86) so that it comes before all other variables to read thus "https://localhost/what/index.php?eid=86&album=parent%2Fsubalbum&image=1coffee.jpg" Regards $link = ?><a href="post?id=<?php echo $id; ?>&title=<?php echo $slug_title; ?>"><?php echo $title; ?></a><?phpBasically what I am trying to do is get a url link of a current page that I'll be sending in an email. I have all the $_GET variables I need to duplicate the current url. For some reason it's giving me an error. Can you please fix what is shown above into something that'll work? Thanks. Edited by man5, 15 July 2014 - 07:09 PM. Hi everyone, first of all let me thank you for this wonderful forum I come back here always when i need help... i'm trying to learn so soon i hope, i'll be helping others... I have a question for now, i have a code which goes like this: Code: [Select] <? $b = time (); $date1 =date( "Y-m-d;h:i:s" , mktime(date("h")+6, date("i"), date("s"), date("m") , date("d"), date("Y"))); $str_time = "&receivedtimestamp="; $str_msg = "&msg=bkt"; $str_from = "from="; ?> <a href="http://testext.i-movo.com/api/receivesms.aspx?<?echo $str_from;?><?=$getuser[0]['phone'];?><?echo $str_time;?><?echo $date1;?><?echo $str_msg;?>">Get a Cupon</a> What i need is that when the URL is generated, one of those variables to be hidden, for example the $str_from to be in the link but not visible... I must tell you that the link on the Get Cupon goes to an external link so i don't know if i can do it with .httpaccess as i've heard... Hi everybody,
I want to cloak my affiliate links or mask it so it looks like a pretty url. Also if possible, I want to track the clicked link with Google Analytics so I think I need a page where I can log the click.
I found lots of information but not for the situation I have. I get my links from my database like this:
echo '<a href="'.$info['url'].'">the link</a>';How can I accomplish this? So I need a url like www.mydomain.com/click and when a user click on the link the get a new page with a tracking code and a redirect script to the right url. Thanks so much for the help! Kind regards, Mark Hello all! I am somewhat new to PHP and SQL, but I think I have a basic understanding of how the language works. I have read through a million different websites and forums, and have tried a million different ways but am just not getting anywhere! This is what I am trying to do... I have a text link that I want to click through to an outside URL from my website. This outside URL was already entered into an SQL database, and I just cant seem to get the text link to bring up the outside URL from the database. This is what I have so far... 1.) My webpage that I am working on is www.mywebsite.com/articles.php 2.) I want the text "Read more..." on this webpage to click through to an outside URL, like "http://www.google.com", which was already entered into an SQL database under the title of "article_link" in a new window 3.) So I would like for "Read more..." to click through the outside URL that was entered into "article_link" in the database Code: [Select] <?php echo <p><a href="\' . $article_link . '\" target="_blank">Read more...</a></p>; ?> Nothing I have tried has worked so far, nothing clicks through to the outside URL in the "article_link" entry from the database. Sorry if I am being redundant, I have been at this all day! Please help and thank you in advance!! Hey, I'm trying to save a MySQL-Link source as an instance variable in my query class. The problem is that MySQL sees it as an invalid MySQL-Link (supplied argument is not a valid MySQL-Link resource). What I'm I doing wrong? //Walle Code: [Select] private $connection; //Construct public function __construct(&$connection) { $this->connection = $connection; } //Where the error occurs public function exe_query($sql) { $result = mysql_query($sql, $this->connection); if(!$result) { throw new Exception(mysql_error()); } return $result; } Hi All, I'm sending an email with a link to a web page with a form on. Code: [Select] <tr style="padding:10px;"> <td align="center"> <a style="text-decoration:none;" href="http://www.foo.co.uk/bar.php?id=123"> <img src="/header.jpg" border="0" style="display: block;" width="380" height="64" alt="Logo" /> </a> </td> </tr> I currently GET the id from the URL and add it to a hidden field in the form which then sends the ID to the database on submit so I know from which email the user came from to fill out the form. This doesn't always work as I guess some people move from the form page to look at other pages on my site then come back to fill in the form. I think I need to use SESSION to keep the id 'active' but cannot figure out how to GET the id from the URL and put it into a SESSION, alas I am struggling to even start and finish a basic SESSION. Thanks in advance, Ben. Hi, I know it is probely not a regex question but I don't know the right category. I have 2 variables like $variable1 and $ variable2 which are placed in a loop now I want the $variable to be echo't in a link like <a href="http://exampe.com/$variable1"/> On this dynamicly generated page I want to output the $varible1 of this link and $variable2 while($row = mysql_fetch_assoc($result)) { echo " <tr>"; echo " <td>" . $row["variable1"] . "</td>"; echo " <td>" . $row["variable2"] . "</td>"; echo " </tr>"; I have to put a link that can be clicked around the first name and last name variables in the echo statement below. I also need to add a variable from the Select query to the link such as: 'www.phpfreaks.com/admin/customers.php?page=1&cID="VARIABLE HERE" &action=edit' I've tried a bunch of things and none seem to work. while($row = mysql_fetch_array($result)){ echo '<tr><td>' . $row['customers_firstname'] . " " . $row['customers_lastname'] . '</td><td>' . date("M. d, Y", strtotime($row['date'])) . '</td><td>' . $row['plan_id'] . '</td></tr>'; David This topic has been moved to Third Party PHP Scripts. http://www.phpfreaks.com/forums/index.php?topic=359149.0 Trying to figure out how to make it so name is a link to the profile when its echo anyone know how to do this? im at a huge stand still Code: [Select] <?php $sql = "SELECT name FROM users WHERE DATE_SUB(NOW(),INTERVAL 5 MINUTE) <= lastactive ORDER BY id ASC"; $query = mysql_query($sql) or die(mysql_error()); $count = mysql_num_rows($query); $i = 1; while($row = mysql_fetch_object($query)) { $online_name = htmlspecialchars($row->name); echo '<a href="Inbox.php">"'[$goauld]'</a>"'; ?> Hello Everyone, I'm using PHP with MySQL. One of the fields in the database is website. The code I'm using is as follows: variable: $web=mysql_result($result,$i,"web"); html/php code: <td><font face="Arial, Helvetica, sans-serif"><a href="<? echo "$web"; ?>">Website</a></font></td> What it should do is have the clickable word Website with the correct url from the database. Instead it's repeating the website the page is on. For example it's doing this: http://mywebsite/www.enteredwebsite.com Any help is appreciated. Hello all. I am very new to PHP, and I am not sure where to look or what I'm looking for in my current assignment. My task is to take in two numbers between 0-100. Once I take in that number, it should state beside it "The __ was accepted." The program should not accept any numbers greater than 100 or any characters. Once I do this, I must take a second number and do a similar thing. Finally, I must have a statement show up at the bottom stating which number is greater. Essentially, I need help in determining what I should use to place parameters, and how I can keep the program from echo ing any statement until input has been taken and tested for parameters. Any help you can provide will be greatly appreciated! I am trying to allow the user to update a variable he chooses by radio buttons, which they will then input text into a box, and submit, to change some attributes. I really need some help here. It works just fine until I add the second layer of variables on top of it, and I can't find the answer to this question anywhere. <?PHP require('connect.php'); ?> <form action ='' method='post'> <select name="id"> <?php $extract = mysql_query("SELECT * FROM cars"); while($row=mysql_fetch_assoc($extract)){ $id = $row['id']; $make= $row['make']; $model= $row['model']; $year= $row['year']; $color= $row['color']; echo "<option value=$id>$color $year $make $model</option> ";}?> </select> Which attribute would you like to change?<br /> <input type="radio" name="getchanged" value="make"/>Make<br /> <input type="radio" name="getchanged" value="model"/>Model<br /> <input type="radio" name="getchanged" value="year" />Year<br /> <input type="radio" name="getchanged" value="color" />Color<br /><br /> <br /><input type='text' value='' name='tochange'> <input type='submit' value='Change' name='submit'> </form> //This is where I need help... <?PHP if(isset($_POST['submit'])&&($_POST['tochange'])){ mysql_query(" UPDATE cars SET '$_POST[getchanged]'='$_POST[tochange]' where id = '$_POST[id]' ");}?> My login script stores the user's login name as $_SESSION[ 'name'] on login. For some unapparent reason, i'm getting errors stating that $user and $priv are undefined variables, though I've attempted to define $user as being equal to $_SESSION['name'], using $user to look up the the user's privilege level (stored as the su column ) in the SQL table, and then where the result of the sql query is $priv which is then evaluated in an if statement. I can't seem to figure out why this might not be working. The code I'm using: <?php session_start(); function verify() { //verify that the user is logged in via the login page. Session_start has already been called. if (!isset($_SESSION['loggedin'])) { header('Location: /index.html'); exit; } //if user is logged in, we then lookup necessary privleges. $_SESSION['name'] was written with the login name upon login. Privleges // are written in db as a single-digit integer of of 0 for users, 1 for administrators, and 2 for special users. $user === $_SESSION['name']; //Connect to Databse $link = mysqli_connect("127.0.0.1", "database user", "password", "database"); if (!$link) { echo "Error: Unable to connect to MySQL." . PHP_EOL; echo "Debugging errno: " . mysqli_connect_errno() . PHP_EOL; echo "Debugging error: " . mysqli_connect_error() . PHP_EOL; exit; } //SQL Statement to lookup privlege information. if ($result = mysqli_query($link, "SELECT su FROM accounts WHERE username = $user", MYSQLI_STORE_RESULT)) { //LOOP TO CYCLE THROUGH SQL RESULTS AND STORE Privlege information as vairable $priv. while ($row = $result->fetch_assoc()) { $priv === $row["su"]; } } // close SQL connection. mysqli_close($link); // Verify privleges and take action. Only a privlege of "1" is allowed to view this page. A privlege of "2" indicates special //accounts used in other scripts that have certain indermediate additional functions, but are not trusted administrators. if ($priv !== 1) { echo $_SESSION['name']; echo "you have privlege level of $priv"; echo "<br>"; echo 'Your account does not have the privleges necessary to view this page'; exit; } } verify(); ?>
|