PHP - On Submit, Form Posts To Two Scripts

Hi.  Pretty straight forward I guess but as the name suggests am a newbie.  I have a form that requires the user to enter certain parameters.  If the values are blank it submits to itself and loads the error messages.  What I want to do is create PHP code that submits the form to a different url.  What I thought was create two forms (the second with hidden fields replicating the first form), each form having a different url in the action"" code.  What I cant work out is the PHP IF ELSE code to submit form 2 if Form1 is is validated correctly.  This is the PHP code relevant to the form validation.  Help?

<?php
      //If form was submitted
      if ($_POST['submitted']==1) {
          $errormsg = ""; //Initialize errors
          if ($_POST[width]){
             $title = $_POST[width]; //If title was entered
          }
          else{
             $errormsg = "Please enter width";
          }
          if ($_POST[drop]){
             $textentry = $_POST[drop]; //If comment was entered
          }
          else{
             if ($errormsg){ //If there is already an error, add next error
                $errormsg = $errormsg . " & content";
             }else{
                $errormsg = "Please enter drop";
             }
          }
      }

      if ($errormsg){ //If any errors display them
          echo "<div class=\"box red\">$errormsg</div>";
      }

      //If all fields present
      if ($title && $textentry){
         //Do something
          
echo 'THIS IS WHERE I WANT THE CODE TO SUBMIT FORM 2 or SUBMIT FORM 1 TO A DIFFERENT URL';
      }   
      ?>

Hi everybody. So I tried to do some research on this and the answers I found were pretty complicated and hard for me (as a newbie) to understand. What I am trying to do is send the results of an HTML form (radio buttons) to more than one php script (currently name_BB1.php but I would also like to send it to name_2.php). Is there a simple way to do this? Is it even possible?   All I need to pass from the script is the name of the department chosen (Music Books or Video) and the first script uses that information to access related databases. However the second script also needs to know the name of the department originally chosen and I don't know how to get that variable over there without asking the user a second time.   HTML:   <form action="name_BB1.php" method="POST">
      </p>Which database would you like to select?<br \><br \>
      <input type="radio" name="choice" value="Music"
      />I want music!<br \>
      <input type="radio" name="choice" value="Books"
      />Give me books!<br \>
      <input type="radio" name="choice" value="Video"
      />I want to see videos!<br \><br \>
      <input type="submit" value="submit">
      </p>
</form>   Thanks!

Hello, first time poster..  I've looked the web over for a long time and can't figure this one out.

- Below is basic code that successfully checks MySQL for a match and displays result.  I was debugging and forced the "height" and "width" to be 24 and 36 to make sure that wasn't the problem.  That's good.. 
- I'd like to give the user ability to select width and height from a form.. and have it do an onchange this.form.submit so the form can be changing as fields are altered (thus the onchange interaction)
- In a normal coding environment I've done this numerous times with no "Page cannot be displayed" problems.  It would simply change one select-option value at a time til they get down the form and click submit...  but in WordPress I'm having trouble making even ONE single onchange work!
- I've implemented the plugins they offer which allows you to "copy+paste" your php code directly into their wysiwyg editor.  That works with basic tests like my first bullet point above.
- I've copied and pasted the wordpress url (including the little ?page_id=123) into the form "action" url... that didn't work...  tried forcing it into an <option value=""> tag.. didn't work.  I'm just not sure. 

I've obviously put xx's in place of private info..

Why does this form give me Page Cannot Be Displayed in WordPress every time?  It won't do anything no matter how simple.. using onchange..

Code..

$con = mysql_connect("xxxx.xxxxxxx.com","xxxxxx","xxxxx");
if (!$con)
  {
  die('Could not connect: ' . mysql_error());
  }
mysql_select_db("xxxxxx", $con);
$myprodwidth=24;
$myprodheight=36;
$result = mysql_query("SELECT * FROM product_sizes WHERE prodwidth='$myprodwidth' and prodheight='$myprodheight'");
while($row = mysql_fetch_array($result))
  {
  echo $row['prodprice'];
  }
mysql_close($con);


<form method="post" action="">
<select name="myheight" onchange="this.form.submit();">
<option selected="selected" value="">select height</option>
<option value="xxxxxxxxx.com/wordpress/?page_id=199&height=36">36</option>
<option value="xxxxxxxxx.com/wordpress/?page_id=199&height=36">48</option>
</select>

Hi-
the code below lets me upload a CSV file to my database if I have 1 field in my database and 1 column in my CSV.
I need to add to my db "player_id" from the CVS file and "event_name" and "event_type" from the form... any ideas???

here's the code:
Code: [Select]
<?php
$hoststring =""; 
$database = "";
$username = "";
$password = "";
$makeconnection = mysql_pconnect($hoststring, $username, $password);
?>
<?php
ob_start();
mysql_select_db($database, $makeconnection);
$sql_get_players="
SELECT * 
FROM tabel 
ORDER BY player_id ASC";
//
$get_players = mysql_query($sql_get_players, $makeconnection) or die(mysql_error());
$row_get_players = mysql_fetch_assoc($get_players);
//
$message = null;
$allowed_extensions = array('csv');
$upload_path = '.'; //same directory

if (!empty($_FILES['file'])) {

if ($_FILES['file']['error'] == 0) {
// check extension
$file = explode(".", $_FILES['file']['name']);
$extension = array_pop($file);

if (in_array($extension, $allowed_extensions)) {

if (move_uploaded_file($_FILES['file']['tmp_name'], $upload_path.'/'.$_FILES['file']['name'])) {

if (($handle = fopen($upload_path.'/'.$_FILES['file']['name'], "r")) !== false) {
$keys = array();
$out = array();
$insert = array();
$line = 1;

while (($row = fgetcsv($handle, 0, ',', '"')) !== FALSE) {

foreach($row as $key => $value) {    

if ($line === 1) {
$keys[$key] = $value;       
} else {       
$out[$line][$key] = $value;              
}       
}                
$line++;          
}        

fclose($handle);            

if (!empty($keys) && !empty($out)) {        
$db = new PDO(
'mysql:host=host;dbname=db', 
'user', 
'pw');   

$db->exec("SET CHARACTER SET utf8");        

foreach($out as $key => $value) {        
$sql  = "INSERT INTO `table` (`";
$sql .= implode("`player_id`", $keys);    
$sql .= "`) VALUES (";    
$sql .= implode(", ", array_fill(0, count($keys), "?"));    
$sql .= ")";    
$statement = $db->prepare($sql);    
$statement->execute($value);       
}      

$message = '<span>File has been uploaded successfully</span>';      
}
}
}
} else {
$message = '<span>Only .csv file format is allowed</span>';
}
} else {
$message = '<span>There was a problem with your file</span>';
}
}
ob_flush();?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
<title>CSV File Upload</title>
</head>
<body>

<form class="form" action="" method="post" enctype="multipart/form-data">
<h3>Select Your File</h3>
<p><?php echo $message; ?></p>
<input type="file" name="file" id="file" size="30" />
<br/>
<label>Event Name:</label><input name="event_name" type="text" value="" />
<br/>
<label>Event Type:</label><input name="event_type" type="text" value="" />
<br/>
<input type="submit" id="btn" class="button" value="Submit" />
</form>

<br/>
<h3>Results:</h3>
<?php do { ?>
<p><?php echo $row_get_players['player_id'];?></p>
<?php } while ($row_get_players = mysql_fetch_assoc($get_players)); ?>
</body>
</html>

Hi all,

What I am trying to achieve is, I thought quite simple!

Basically, a user signs up and chooses a package, form is submitted, details added to the database, email sent to customer, then I want to direct them to a paypal payment screen, this is where I am having issues!

Is their any way in php to submit a form without user interaction? Here is my code for the form process page
Code: [Select]
<?php
include('config.php');
require('scripts/class.phpmailer.php');

$package = $_POST['select1'];
$name = $_POST['name'];
$email = $_POST['email'];
$password = md5($_POST['password']);

$domain = $_POST['domain'];
$a_username = $_POST['a_username'];
$a_password = $_POST['a_password'];


$query=mysql_query("INSERT INTO orders (package, name, email, password, domain, a_username, a_password)
VALUES
('$package', '$name', '$email', '$password', '$domain', '$a_username', '$a_password')");

if (!$query)
{
echo "fail<br>";
echo mysql_error();
}

else
{
$id = mysql_insert_id();
$query1=mysql_query("INSERT INTO customers (id, name, email, password)
values
('$id', '$name', '$email', '$password')");

if (!$query1)
{
echo "fail<br>";
echo mysql_error();
}


if($package=="Reseller Hosting")
{

//email stuff here - all works - just cutting it to keep the code short


if(!$mail->Send())
{
   echo "Message could not be sent. <p>";
   echo "Mailer Error: " . $mail->ErrorInfo;
   exit;
}
?>


<form name="_xclick" action="https://www.paypal.com/cgi-bin/webscr" method="post">
<input type="hidden" name="cmd" value="_xclick-subscriptions">
<input type="hidden" name="business" value="subscription@jollyhosting.com">
<input type="hidden" name="currency_code" value="USD">
<input type="hidden" name="item_name" value="Jolly Hosting Reseller Packages">
<input type="hidden" name="no_shipping" value="1">

<!--1st month -->
<input type="hidden" name="currency_code" value="USD"> 
<input type="hidden" name="a3" value="3.00">
<input type="hidden" name="p3" value="1">
<input type="hidden" name="t3" value="M">
<input type="hidden" name="src" value="1">
<input type="hidden" name="sra" value="1">
</form>';


<?php
}

//last
}
//end
?>

Hi, I have setup a basic enquiry form with a Captcha - once the code has been inserted and is correct I want to action the form (submit) in PHP.

<?php

session_start();
if($_SERVER['REQUEST_METHOD'] == 'POST'){
$vResult = '';
if(strtolower($_SESSION['security_code']) != strtolower($_POST['security_code'])){
$vResult = 'Invalid code!';
}
else{
"/enquiry.php"
}
}
?>

I want to submit the form to /enquiry.php - I tried header(Location.. and realised that just redirects, and doesn't submit the form.

Any suggestions or tips would be great.

Cheers,

Paul

Hi,
I want to submit a form using ajax ans jquery with two fields input text and file.

Code: [Select]
<script>
$(document).ready(
function()
{


$('#basicinfofrm').ajaxForm(function() {
url: ''+PN+'.php',
type:'POST',
data:'action=yes&'+frmFeilds,
success: function(html)
{ 
 alert(html);

}

    }).submit();
</script>
<form action='' method='post'>
    <label>name</label>
    <input type='text' name='txtname' />
    <input type='file' name  = 'txtfile' />
   <input type='submit' value='save' />
</form>

but is is not working...
can anyone tell me how to?
i don't want to refresh my page
Thanks

Code: [Select]
<?php
 
if (isset($_POST['checking'])) { echo $_POST['checking']; }
if (isset($_POST['test'])) { echo $_POST['test']; }
 
?>
 
 
<form id="testform2" action="testform.php" method="post">
 
<select name="checking" onchange="this.form.submit()"><option value="5">5</option><option value="6">6</option></select>
<input type="text" name"test" id="test">
 <a href="#" onclick="this.form.submit()">submit it!</a>
</form>


It works when I try to submit by selecting a new value from the dropdown box but when I try to click the link it won't display the text field value. That is a test case for a problem I m having in one of my codes.

Can anybody see as to why, if any, this form takes forever to execute?
Code: [Select]
<?php
if(isset($_POST['submitted'])){
    $z = $_POST['zipcode'];
    $r = $_POST['radius'];
    
    $sql = mysql_query("SELECT DISTINCT m.LocAddZip, m.MktName,m.LocAddSt,m.LocAddCity,m.LocAddState,m.x1,m.y1,z1.lat,z2.long
    FROM mrk m, zip z1, zip z2
    WHERE m.LocAddZip = z1.zipcode
    AND z2.zipcode = $z
    AND ( 3963 * acos( truncate( sin( z2.lat / 57.2958 ) * sin( z1.lat / 57.2958 ) + cos( z2.lat / 57.2958 ) * cos( z1.lat / 57.2958 ) * cos( z1.long / 57.2958 - z2.long / 57.2958 ) , 8 ) ) ) <= $r ")
    
    or die(mysql_error());
        while($row = mysql_fetch_array( $sql )) {
            $store = $row['MktName']."<br />";
            $store .= $row['LocAddSt']."<br />";
            $store .= $row['LocAddCity'].", ".$row['LocAddState']." ".$row['LocAddZip'];
            $lat1 = $row['lat'];
            $lon1 = $row['long'];
            $lat2 = $row['y1'];
            $lon2 = $row['x1'];
            $dis = distance($lat1, $lon1, $lat2, $lon2);
     
            echo "<p>".$store."</p>";        
            echo ceil($dis) . " mile(s) away";
            echo "<hr/>";
        }
}
?>

I get a timeout error sometimes, and sometimes I don't.
Is it the form, or would it be on the server?

Thanks in advance

I can't submit php form using IE 8.  This works fine on Firefox very well.
I tried following code but none of them is working.   
1.  <button type="submit">Submit</button>

2.  <input type="submit" value="Submit" name="submit">


 I would appreciate if any one help me in this.

hello everyone, I have a php form, everything works, I do not carry any header() at the end of the form because I have to stay on the same page and because I feel it wipes out the message you sent the form successfully, but for this though if reloading  the page shows me the popup asking me to resend the form.  how can i solve?  I found a function in js with replacestate but I saw that it doesn't work with mobile Safari.

if ( window.history.replaceState ) { window.history.replaceState( null, null, window.location.href ); }

 

I've got a form that submits values to itself and the user input values are saved into the database in a table with an auto incrementing ID. After SUBMIT is clicked, it reloads the page and all the values are gone, I'm wondering how I can get it to keep the values so that the user can make a single change and resubmit again.

I know I can save all the values into the session or in the URL or pass them through $_POST in an array but I'm wondering what is the proper way to do this. Thanks.

i have a form for my admin to update the products and their deails on my site. but i have decided to add stock and supplier tables to the database. so i have a products table, stock and supplier. each have an id.   in my admin form, id like the admin to submit once to multiple tables...   php code that i need to improve

<?php
// Parse the form data and add inventory item to the system

if (isset($_POST['product_name'])) {

    $product_name = $_POST['product_name'];
    $price = $_POST['price'];
    $category = $_POST['category'];
    $stock = $_POST['stock'];
    $details = $_POST['details'];
    $rating =$_POST['rating'];
    $letter = $_POST['letter'];
    $supplier = $_POST['supplier'];        

    // See if that product name is an identical match to another product in the system
    $sql = mysqli_query($con, "SELECT id FROM products WHERE product_name='$product_name' LIMIT 1");
    $productMatch = mysqli_num_rows($sql); // count the output amount
    //if product match is greater than 0
    if ($productMatch > 0) {
        echo 'Sorry you tried to place a duplicate "Product Name" into the system, <a href="inventory_list.php">click here</a>';
        exit();
    }
    // Add this product into the database now by sql query
    $sql = mysqli_query($con, "INSERT INTO products (product_name, price, details, category, stock, letter, supplier,  rating, date_added)
        VALUES('$product_name','$price','$details','$category', '$stock' ,'$letter',' $supplier' , '$rating' now())") or die (mysqli_error());        
     $pid = mysqli_insert_id($con);    
    // Place image in the folder
        $newname = "$pid.jpg";
        move_uploaded_file($_FILES['fileField']['tmp_name'], "../inventory_images/$newname"); //_FILES is a global var
    
    header("location: inventory_list.php"); //auto refresh, and it wont try to re add the item
    exit();//not necessary but its always safe to exit
}
?>

html form
<form action="inventory_list.php" enctype="multipart/form-data" name="myForm" id="myForm" method="post">
                <table width="95%" border="0" align="center" cellpadding="5" cellspacing="0" summary="this is where the admin will insert new items">
          <caption><div id="title"><a id="add_new_item"></a>Add New Inventory Item</div>
          </caption>
          <tr >
            <th width="30%" scope="col" align="left">Product Image</th>
            <th width="70%"><label class="desc">
            <input type="file" name="fileField" id="fileField"   autofocus required />
            </label></td>
          </tr>
          <tr >
            <th width="30%" scope="col" align="left">Product Name</th>
            <th width="70%" scope="col" align="left">
            <label class="desc">
                <input name="product_name" type="text" id="product_name" size="64"  autofocus required />
            </label></th>
          </tr>
          <tr>
            <th width="30%" scope="row" align="left">Letter</th>
            <td width="70%"> <label class="desc">
                <input name="letter" type="text" id="letter"  autofocus required />
            </label></td>
          </tr>
          <tr>
            <th width="30%" scope="row" align="left">Product Price</th>
            <td width="70%"> <label class="desc">
                <input name="price" type="text" id="price"  autofocus required />
            </label></td>
          </tr>
          <tr>
            <th width="30%" scope="row"align="left">Category</th>
            <td width="70%"><label class="desc">
            <select name="category" id="category">
            <option value="Fruits">Fruits</option>
            <option value="Vegetables">Vegetables</option>
            <option value="Indoor Plants">Indoor Plants</option>
            <option value="Outdoor Plants">Outdoor Plants</option>
            </select>
            </label></td>
          </tr>
          <tr>
            <th width="30%" scope="row" align="left">Suppliers</th>
            <td width="70%"> <label class="desc">
            <select name="supplier" id="supplier">
            <option value="Kenny's Organic Supplies">Kenny's Organic Supplies</option>
            <option value="Mom's Garden">Mom's Garden</option>
            <option value="Big Brother">Big Brother</option>
            </select>
            </label></td>
          </tr>
          <tr>
            <th width="30%" scope="row" align="left">Stock</th>
            <td width="70%"> <label class="desc">
                <input name="stock" type="text" id="stock"  autofocus required />
            </label></td>
          </tr>
          <tr>
            <th width="30%" scope="row"align="left">Product Details</th>
            <td width="70%"><label class="desc">
            <textarea name="details" id="details" cols="35" rows="5"  autofocus required></textarea>
            </label></td>
          </tr>
              <tr>
            <th width="30%" scope="row" align="left">Rating</th>
            <td width="70%"><label class="desc">
            <select name="rating" id="rating" >
            <option value="1">1 of 3 Stars</option>
            <option value="2">2 of 3 Stars</option>
            <option value="3">3 of 3 Stars</option>
            </select>
            </label></td>
          </tr>

          <tr>
            <th width="30%" scope="row">&nbsp;</th>
            <td width="70%" align="right"><label class="desc">
            <input type="submit" name="button" id="button" value="Add This Item Now" />
            </label></td>
          </tr>
          <tr>
            <th width="30%" scope="row">&nbsp;</th>
            <td width="70%">&nbsp;</td>
          </tr>
      </table>
    </form>

Edited by Ch0cu3r, 17 January 2015 - 04:03 PM.

I have a form on my website and when the user submits it I want all the server processing to be done using AJAX so the page doesn't refresh.  I was wondering what the best way to do this is because if your form has a submit button doesn't that automatically refresh the page?

Thanks for any help. 

Hi Guy,

First Post ..so please help!

I have rows returning from a mYSQL Database which  I put in a form which is php generated and im sending this form to the next page with a SUBMIT button. I want PHP/Javascript to do this automatically when the data is loaded from the MYSQL Table

Ive tried fsockpen and document.form.submit() but it doesnt seem to work

Any help.
Thanks in Adv,
Hittesh Ahuja
<?php session_start();
if(isset($_POST['submit']))
{
header("Location: http://localhost/PHP/brk_plan.php");
}
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>

<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
</head>

<body>

<p>
  <?php 
require_once('connect.php');
$email=$_SESSION['email'];

$query="SELECT glycemic_index.gi_id,glycemic_index.value FROM food_preference JOIN glycemic_index ON glycemic_index.gi_id=food_preference.gi_id WHERE food_preference.email='$email' and glycemic_index.value >= 55 " or die("Update not Possible");
$result=mysql_query($query);

$session_array=array();
echo "<form method='post' action='brk_plan.php' name='recommend'>";
echo "<p>This area is filtered from the user's table showing values only > 55</p>";
while($row=mysql_fetch_array($result))
{


echo "Instead of: ".$row[0]."-".$row[1]."<br/>";




$one=$row[0];

 $one_trimmed=substr($one,2,strlen($one)-5);

 $one_search="%".$one_trimmed."%";


$query2="SELECT glycemic_index.gi_id,glycemic_index.value,glycemic_index.food FROM glycemic_index WHERE glycemic_index.gi_id LIKE '$one_search' AND glycemic_index.value <55 AND glycemic_index.gi_id!='$row[0]' ORDER BY RAND() LIMIT 1  ";
$result2=mysql_query($query2);

while($row2=mysql_fetch_array($result2))
{


echo "<input type='hidden' value='$row2[2]' name='fields[]'></input>";
echo "<p>You can have ".$row2[2].": ".$row2[0]."-".$row2[1]."</p>";

}



}

echo "<input type='submit' name='submit' value='dikha!'></input>";
echo "</form>";










//$_SESSION['higher_gi']=$session_array;
//foreach($session_array as $value)
 //{
// echo $value."<br/>";

 //}
?>
</p>
<p></p>
<p></p>

<p></p>
<p></p>
<p>&nbsp;</p>
</body>
</html>