|
PHP - Dynamic Titlei Am Posting This Into The Newbie Forum Cause This Seems Nebieish T
I am posting this into the Newbie forum cause this seems nebieish to me...
Ok i have a few files that make up a set of pages Topbar.php index.php info_birmingham.php ( i want the title to match the info page i have a few cities ) footer.php OK so obviously the <title> is in top bar and i am trying to display the city name in the title which would be gotten from the info_city page so in topbar i have... <title><?php echo ("$city"); ?> - <?php echo COMPANY; ?></title> and then in the info_city page i have at the top of the page <?php $city = "Birmingham"; ?> So i guess my question is why does the title not display the city name? SOMEONE please help i have been pulling my hair out on this you can see form the URL string that index.php controls all of the pages and the info page has the data for each city http://www.skbk.com/OaklandCounty/index.php?section=Birmingham Thanks to anyone that might be able to shed some insight on this for me T Similar TutorialsHow do I post to a forum where the Submit button doesn't have a name? I haven't found anything like post=Post or post=Submit or anything of that sort. I have used curl in several different forums, but I have never seen anything like this. I'm sure it's simple though. <input type="submit" value="Post" tabindex="3" onclick="return submitThisOnce(this);" accesskey="s" class="button_submit" /> This forum also has a hidden variable where the name is never the same, but generated: <input type="hidden" name="ee40576" value="6d412be2ae8f344b177ad5b8ef2575d2" /> I'm pretty sure I can just send ee40576=6d412be2ae8f344b177ad5b8ef2575d2 though. The forum is an smf forum, and I have been able to log in. I have also posted at other smf forums similar to this, only there the submit button had a name. Working on a project for school and I am trying to code a form that feeds into a DB. I have been studying the syntax, reading and doing everything I can to get this to work. A little help, pointers, direction would be greatly appreciated. It may be my database structure so I included a image for anyone to see... and the files. Thanks in advance [attachment deleted by admin] Folks, I need help (Php code ) to generate a Dynamic Text on a Base Image. What i want to do is, to make this Image as header on my Site and to make this Header Specific to a Site, i want to Add the Domain Name on the Lower Left of the Image. Got the Idea? Here is the Image link: Quote http://img27.imageshack.us/i/shoppingheader1.jpg/ PHP Variable that holds the Domain name is: $domain All i need the Dynamic PHP Codes that i can put on all my sites to generate this Text on Image (Header) Dynamically... May Anyone Help me with this Please? Cheers Natasha T. Hi all I need to combine these two scripts: Firstly, the following decides which out of the following list is selected based on its value in the mySQL table: <select name="pack_choice"> <option value="Meters / Pack"<?php echo (($result['pack_choice']=="Meters / Pack") ? ' selected="selected"':'') ?>>Meters / Pack (m2)</option> <option value="m3"<?php echo (($result['pack_choice']=="m3") ? ' selected="selected"':'') ?>>Meters / Pack (m3)</option> <option value="Quantity"<?php echo (($result['pack_choice']=="Quantity") ? ' selected="selected"':'') ?>>Quantity</option> </select> Although this works OK, I need it also to show dynamic values like this: select name="category"> <?php $listCategories=mysql_query("SELECT * FROM `product_categories` ORDER BY id ASC"); while($categoryReturned=mysql_fetch_array($listCategories)) { echo "<option value=\"".$categoryReturned['name']."\">".$categoryReturned['name']."</option>"; } ?> </select> I'm not sure if this is possible? Many thanks for your help. Pete i'm doing a form that posts values to XML, and i don't know how. can someone help me with a quick lesson in passing variables/XML data? i don't even know what question to ask, actually - the XML format i've been given is: Code: [Select] <?xml version="1.0" encoding="UTF-8"?> <lead> <innerNode></innerNode> <last_name>Smith</last_name> <first_name>John</first_name> </lead> and what i've come up with so far is this, but i don't even know if i'm on the right track: Code: [Select] $last_name = $_REQUEST['l_name']; $first_name = $_REQUEST['f_name']; $url = "http://url.com/leads"; $post_string = '<?xml version="1.0" encoding="UTF-8"?> <lead> <innerNode></innerNode> <last_name>'.$last_name.'</last_name> <first_name>'.$first_name.'</first_name> </lead>'; $header = "POST HTTP/1.0 \r\n"; $header .= "Content-type: text/xml \r\n"; $header .= "Content-length: ".strlen($post_string)." \r\n"; $header .= "Content-transfer-encoding: text \r\n"; $header .= "Connection: close \r\n\r\n"; $header = $post_string; $ch = curl_init(); curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, 0); curl_setopt($ch, CURLOPT_URL,$url); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt($ch, CURLOPT_TIMEOUT, 4); curl_setopt($ch, CURLOPT_CUSTOMREQUEST, $header); $data = curl_exec($ch); if(curl_errno($ch)) { print curl_error($ch); } else { echo "yay"; curl_close($ch); } i'm being told "should return a response.xml with either a success or failure post status." which is confusing me can someone help a bit? thanks very much... GN How can I post this variable $healspell when I already have an echo within a php? Here's what I have: echo '<p>You cast Nature\'s Cure (Recovered <?=$healspell?>)</p>'; It's not printing anything out at the moment, obviously, and if I just put $healspell, it just echos out: $healspell. Thanks! hello, i have a while loop that displays multiple tables of data depending on how many are in the database... i have a link if you click it will redirect to another page that prompts you to save an xls file with the table data... this was all working for me before when i had the while loop display rows of data in one table...well i decided that i would like the while loop to display a separate table each time... when i changed it... the xls file only shows one table of data... how can i set up so it will export all tables of data... is there some kind of loop i can set up for it to append the tables?? i have the table data all in a variable $table which i put into a hidden form field that redirects to the xls export page.... any help is appreciated... <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8" /> <title>Admin</title> </head> <body> <?php $sql= mysql_query("SELECT * FROM programs") or die (mysql_error()); while($row = mysql_fetch_array($sql)){ $table = "<table border='1' width='600' style='border-collapse:collapse;'>" . "<th colspan='4'>Programs</th>" . "<tr>" . "<td>ID</td>" . "<td>Views</td>" . "<td>Enabled</td>" . "</tr>"; $prog_titles = $row['titles']; $prog_titles = explode(',' , $prog_titles); $table .= "<tr>" . "<td>".$row['id']. "</td>" . "<td>".$row['views']. "</td>" . "<td>".$row['enabled']. "</td>" . "<td></td>" . "</tr>" . "<tr>" . "<td>Title ID</td>" . "<td>Name</td>" . "<td>Description</td>" . "<td>Image</td>" . "</tr>" ; foreach ( $prog_titles as $title ) { $sql2= mysql_query("SELECT * FROM titles WHERE title = '$title' "); $row2 = mysql_fetch_array($sql2); $table .= "<tr>" . "<td>" . $row2['id'] . "</td>" . "<td>" . $row2['title'] . "</td>" . "<td>" . $row2['description'] . "</td>" . "<td>". "<img width='50px' src='images/" . $row2['img'] . "'/></td>" . "</tr>" ; } // close foreach $table .= "</table>"; echo $table; echo "<br /><br /><br />"; } // close while ?> <br /> <br /> <FORM action="export.php"> <INPUT type="submit" value="Export to XLS"> <INPUT type="hidden" value="<?php print $table;?>" name="export"> </FORM> </body> </html> I am working on a PHP/MySQL authorization script. The script seems to work initially, but when I try to Login and post the Form ( echo '<form method="post" action=authorize_1.php">'; echo '<table>'; echo '<tr><td>Userid:</td>'; echo '<td><input type="text" name="userid"></td></tr>'; echo '<tr><td>Password:</td>'; echo '<td><input type="password" name="password"></td></tr>'; echo '<tr><td colspan="2" align="center">'; echo '<input type="submit" value="Log in"></td></tr>'; echo '</table></form>'; ) Internet Explorer returns the error that the page is not found.... but I am using one .php file for the authorization so I am sure the page is found because i can see the Login portion. Any ideas as to what is going wrong? TWO questions: I haven't actually CONNECTED and POSTED. My form has two input fields that combine in a TOTAL field. I notice that the address bar is carrying TOTAL=input1+input2 when it TRIES to connect. Do I need to include the TOTAL field in the database if the info is NOT relavant data? the strg and chick TOTALS? Will the database accept PARTIAL data from a form that has 25 field with only 6 being populated for testing? I have this code with clears the input box onclick... Code: [Select] <input type="text" name="username" value="Username" onclick="value=''"/> however is there any way to use php to get the value of username, before its posted? that way i can make it so it only clears if the value of username is "username" Hi, i have written a form that uses 3 dropdown boxes, one of them being populated from a database. The form code is as follows; Code: [Select] <form id="pointsForm" name="pointsForm" method="post" action="points-engine.php"> <select name="car" id="car"> <?php // result of car name collection $result = mysql_query ($query); //Array stored in $cars while($cars=mysql_fetch_array($result)){ //option values added by looping through array echo "<option value=$cars[id]>$cars[carName]</option>"; } ?> </select> <select name="season" id="season"> <option value="low">Low season</option> <option value="mid">Mid season</option> <option value="high">High season</option> <option value="peak">Peak season</option> </select> <select name="period" id="period"> <option value="day">One day</option> <option value="weekend">Weekend</option> <option value="week">One week</option> </select> <input type="submit" name="Submit" value="Submit" /> </form> which posts to; Code: [Select] <?php $car=$_POST['car']; echo $car; $season=$_POST['season']; echo $season; $period=$_POST['period']; echo $period; ?> The initial form code is working fine, the car field is being populated from the database. My problem is the post value for car isn't working... points-engine.php is echoing $season & $period fine but not $car can anyone tell me why? many thanks Richard You guys helped me create a function to gather information for my database. Now I need some help with posting that information. Function code and Form: <?php include("opendatabase.php"); ?> <?php function createMatchup($week, $game) { $query1 = "SELECT team_name FROM schedule, teams WHERE schedule.week_id = $week AND schedule.game_id = $game AND schedule.A_team = teams.team_id"; $query2 = "SELECT team_name FROM schedule, teams WHERE schedule.week_id = $week AND schedule.game_id = $game AND schedule.H_team = teams.team_id"; $result1 = mysql_fetch_assoc(mysql_query($query1)); $result2 = mysql_fetch_assoc(mysql_query($query2)); $output = " <input type=\"text\" size = \"3\" name=\"w$weekg$gameA\"> {$result1['team_name']} vs. {$result2['team_name']} <input type=\"text\" size = \"3\" name=\"w$weekg$gameH\">"; return $output; } $game1 = createMatchup(1, 1); $game2 = createMatchup(1, 2); $game3 = createMatchup(1, 3); $game4 = createMatchup(1, 4); $game5 = createMatchup(1, 5); $game6 = createMatchup(1, 6); $game7 = createMatchup(1, 7); $game8 = createMatchup(1, 8); $game9 = createMatchup(1, 9); $game10 = createMatchup(1, 10); $game11 = createMatchup(1, 11); $game12 = createMatchup(1, 12); $game13 = createMatchup(1, 13); $game14 = createMatchup(1, 14); $game15 = createMatchup(1, 15); $game16 = createMatchup(1, 16); mysql_close($con); ?> <form action="insert_spreads.php" method="post"> <?php echo $game1; ?> <br> <?php echo $game2; ?> <br> <?php echo $game3; ?> <br> <?php echo $game4; ?> <br> <?php echo $game5; ?> <br> <?php echo $game6; ?> <br> <?php echo $game7; ?> <br> <?php echo $game8; ?> <br> <?php echo $game9; ?> <br> <?php echo $game10; ?> <br> <?php echo $game11; ?> <br> <?php echo $game12; ?> <br> <?php echo $game13; ?> <br> <?php echo $game14; ?> <br> <?php echo $game15; ?> <br> <?php echo $game16; ?> <br /><br /> <input type="Submit" value="Submit Spreads"> </form> I'm wondering if I can use this code for posting to the database (insert_spreads.php): <?php header("Location: admin_schedule.php"); include("opendatabase.php"); $w$weekg$gameA=("$_POST['w$weekg$gameA']"); $w$weekg$gameH=("$_POST['w$weekg$gameH']"); $sql=" UPDATE schedule SET A_pt_spread= '$w$weekg$gameA',H_pt_spread= '$w$weekg$gameH' WHERE week_id = '$week' AND game_id = '$game'; $result = mysql_query($sql) or die(mysql_error().$sql); mysql_close($con) ?> Thanks for helping. the code is in a form whose method = "post". i have failed to echo $r_in. i eed help on this. $lowest_time = 30 - 14; $adder = 2*5*9; echo '<table width="526" border="0"><tr> <td width="169"> <input type="text" name="$r_in" value="'.$lowest_time.'" style="width:169px" readonly="readonly" class="text_non_color"/></td> <td width="169"> <input type="text" name="$r_out" value="'.$adder.'" style="width:169px" readonly="readonly" class="text_non_color"/></td> </tr></table>'; Is there anyway to do this: my form is posting to self, then checking login creds. if they are incorrect it spits out "invaild bla bla" but if they are correct send them to a different page? here is the short version of what I have. if(isset($_POST['submit'])) { //check inputs vs db if ($check) { header("Location: http://". $_SERVER['SERVER_NAME']."/include/process_renew.php"); } else { echo "<font color='red'>Username or Password did not match.</font> <br /><br />"; } } } I tested it using echo first and it worked fine then replaced the echo with header and now when I submit it just refreshes the page. is this not possible? i am basically trying to retrieve the response of a chatbot from mysql database with query below. As i run script i don't get any error from the server but it seems the post doesn't take $data2 which is an array that includes the keys "user_id" and "text" that are normally accepted (eg: $dmessage->post('direct_messages/new/wrap_links=true', 'text'->'example', '12345'); As result of the above i can't post to Twitter the chatobot response as the recipient (my other twitter account) doesn't get the answer...what do you think? Code: [Select] include_once ('connect.php'); connect_to_database(); $query2 = mysql_query ("SELECT response FROM conversation_log WHERE id = (SELECT MAX(id) FROM conversation_log)") or die (mysql_error()); $row = mysql_fetch_row($query2); $response = $row[0]; //this is the array with the parameters to be used to send bot responses via Twitter API. It normally takes $data2 = array("text"=>"$response" , "user_id"=> "$userid"); //this modifies the array values with response e userid fields $data2["text"] = "$response"; $data2["user_id"] = "$userid"; require_once('config_oauth.php'); // includes the applications Oauth keys require_once($_SERVER['DOCUMENT_ROOT'].'Program-O/gui/xml/oauth/twitteroauth.php'); //Full path to twitteroauth.php library $dmessage = new TwitterOAuth($consumer_key,$consumer_secret, $oAuthToken, $oAuthSecret); // create new instance with the credentials //sends the bot response via Twitter API by going through the array $data2 $dmessage->post('direct_messages/new/wrap_links=true', $data2); I have an issue with my script, the date for some reason stopped posting after I changed the format in the date() section, I wanted it to post so it shows month-day-year, and it seems for some reason all it accepts is Y-m-d... Can someone help me out here please? Code: [Select] <?php require_once('connectvars.php'); if (isset($_POST['submit'])) { // Connect to the database $dbc = mysqli_connect(DB_HOST, DB_USER, DB_PASSWORD, DB_NAME); $PO_Date = date('MM "/" DD "/" YY',strtotime($_POST['PO_Date'])); $query = "INSERT INTO ncmr (PO_Date) VALUES ('$PO_Date')"; mysqli_query($dbc, $query); // Confirm success with the user echo '<p>The date have been successfully entered</p>'; mysqli_close($dbc); // Clear the score data to clear the form $PO_Date = ""; } echo'<form form id="all" method="post">'; echo '<div id="abd"><span class="b">On: </span><input type="text" name="Added_By_Date" value="" /></div>'; echo '<div id="button"><input type="submit" value="Submit Edits" name="submit" /></div>'; echo '</form>' ?> I've tried this: <?php $xsblock = $_SERVER['HTTP_REFERER']; $url = "testchan"; $pos = strpos($xsblock, $url); if ($pos == false) { die(); } else { echo "content content content content content content content content"; } ?> How can I do this correctly? Thanks in advance! can anyone help me as to whay I get this error: Problem with the query: INSERT INTO options (item_id, option ) VALUES('1', 'hi' ) You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'option ) VALUES('1', 'hi' )' at line 1 with this code: Code: [Select] foreach($_POST["user"] AS $key => $val) { $user = $val; $id1 = $_POST['id1'][$key]; $sql = "INSERT INTO options (item_id, option ) VALUES('$id1', '$user' )"; $rs = mysql_query($sql) or die ("Problem with the query: $sql <br />" . mysql_error()); } Code: [Select] <input type="checkbox" name="yes" id="checkme" /><div id = "extra"> <div id="user"> Enter User Names:<br> <input type="text" name="user[]"/><br></div> <div id="add_user" style="display: none;"><input type="text" name="user[]"/> might have it nevermind. Hi guys, I have a list box. say the code is Code: [Select] <select name="drop1" id="Select1" size="4" multiple="multiple"> <option value="1">item 1</option> <option value="2">item 2</option> <option value="3">item 3</option> <option value="4">item 4</option> <option value="0">All</option> </select> The user will select few items. How do i capture the data through the "POST" method. Code: [Select] $data = $_POST['drop']; would not work coz there is an array if data. Can any one help or point me in the right direction? Thanks in advance |
|||||||