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PHP - How To Determine If A File Is Missing From My Server
When I upload new files, their file name is stored into my database. I have been told that a couple of the file downloads weren't working. Upon further investigation I figured out that the file the person wanted to download was nowhere to be seen in my downloads directory. How can I determine if a file exists in my directory? I assume I can somehow use the location that is stored inside my database (ex: myfile.pdf) and compare that with what's in the folder.
Similar TutorialsHow to reliably determine if server is Apache using PHP? For example isApache() function? I have a page using forms to help build listing templates for eBay. I have a folder where I have hundreds of logos stored. I know the logo names but not their extensions. . . . I have to test each potential (jpg, jpeg, gif, png, etc.) until I guess right. Here is an example code for the web form:
<form action="extension_test2.php" method="post"> <p>Logo: <input name="e" value="" type="text" size="15" maxlength="30" /><p> <input name="Submit" type="Submit"/> </form> and the form's result: <? $e =$_POST['e']; if(!empty($e)) { echo '<img src="http://www.gbamedica...ebayimg/logos/'.$e.'">'; }; ?> Here is a link to the example: http://www.gbamedica...ension_test.php Use "olympus.jpg" for test. I am looking for code that can determine the file type and dynamically add the extension. Can it be done? My uploader allows the following file formats: jpg gif png I tested that if someone was to name a file configure.php.jpg, my uploader allows it to upload I want to do a check to see if the user has 2 extensions, and if so it will not allow them to upload. I was thinking of just checking if the file name has two "." (dots) in the name. What function could I use to do this? Or .. is there a better way? I can determine which radio button is selected for each file upload prompt because I have a name and a value. So the array name=image can have one of three values for each file upload prompt. Is there a way to determine which of the three file upload prompts was loaded (clicking browse & select image) with an image and which was not? There doesn't seem to be a value like there is with radio buttons. I want to be able to replace an already uploaded image with another. Thanks. <input type='radio' name='image[image0]' value='keep' checked='checked'/> <input type='radio' name='image[image0]' value='delete' /> <input type='radio' name='image[image0]' value='replace' /> <input type="file" name="image[]" /> <input type='radio' name='image[image1]' value='keep' checked='checked'/> <input type='radio' name='image[image1]' value='delete' /> <input type='radio' name='image[image1]' value='replace' /> <input type="file" name="image[]" /> <input type='radio' name='image[image2]' value='keep' checked='checked'/> <input type='radio' name='image[image2]' value='delete' /> <input type='radio' name='image[image2]' value='replace' /> <input type="file" name="image[]" /> if (isset($_POST['submitted']) && ($image = $_POST['image'])) { foreach($image as $imageKey => $imageValue) { if ($imageValue == 'keep') { do this } } } I have a PHP web system that store in a windows server. In the system, there is a function for user to upload files to another server (Shared server in Unix). When i try to upload a file, it gives warning: Warning: move_uploaded_file(\\unixserver/sharedfolder/upload/test.txt) [function.move-uploaded-file]: failed to open stream: Permission denied in C:\wamp\www\upload\index.php on line 40 For your information, my username has been assigned in xxx's group that has access to read and write on that folder. Besides, i'm able to open,create and delete files on that folder's server manually (samba). The safe mode setting is off. Does anybody has any idea why this thing happen? Hey. I am wanting to move a couple of files from my current server to another. If i am uploading the file this is fine but if it is already on the server then im not sure how to move it. When uploading I can just use ftp_put($conn_id, $destination_file, $myFile, FTP_BINARY); What i need to do is figure out how to get a hold of the file and store it in $myFile then this would work fine. Is this possible? Cheers i am trying to pull a .txt file for a class assignment and it is pulling everything except for line 1 any suggestions would be great html: <html> <head> <title>Weekly Report</title> <link rel ="stylesheet" type="text/css" href="sample.css" /> </head> <body> <h1>Weekly Report</h1> <p> <form action = "weeklyReport1Boles.php" method = "post" > <p> <input type = "submit" value = "Display the Report" /> </p> </form> </body> </html> txt.file 1 236.00 2 284.00 3 148.00 4 128.00 5 0.00 6 110.00 7 0.00 8 php file: <?php $total = $_POST['total']; $avgDailyIncome = $_POST['avgDailyIncome']; $badDays = $_POST ['badDays']; $paintFile = $_POST ['paintfile']; $nextDay = $_POST['nextDay']; $paintFile = fopen("weeklyDataBoles.txt","r"); $week = fgets($paintFile); $total = 0; for ($count = 1; $count <=8; $count = $count +1) { $nextDay = fgets($paintFile); $total = $total + $nextDay; } $avgDailyIncome = $total/7; print("<p>TOTAL INCOME FROM PAINT CONTRACTS: "); print("$".number_format($total, 2)."</p>"); print("<p>AVG DAILY INCOME FROM PAINT CONTRACTS: "); print("$".number_format($avgDailyIncome, 2)."</p>"); print("<p>NUMBER OF DAYS with NO INCOME: $badDays.</p>"); ?> </body> </html> Hey guys, I have a script that grabs data from a separate .txt file which is used to perform certain actions within a user's account. The data I'm having trouble with is user key which is used to authenticate an http header. An example of what the txt file would hold is this: 360235276 PbI1c5+PGHSshccYd58AklmTgf5u+tbWZplMRYYxFSivRYw4AZhaVNHwADozYZhZhPnXRSV1rmsrhf1td7w6bJbySZmPHLl+hleyz/Ht4iM= 477947328 cXTnFEVP74RWtAgqM5BlwtgW2i9rP/v44oANzwF+yJZ+9mpvaschyo/HaYP1qUXgIK8nK7jy74iSCEHAgpPgPdryzpReM5cbnVDjRw7h9S0= 503724987 XXEJsklZTFaTx8MLjuNIz0S65Sn02rgbHl2sahdReQdadKP39 evIXUoYdr5NyQMWDVE7cRpvn+zJ7mteH7WJzVh0U/sOcSG7kfcuaWpAOfo= The format I have is: account_ID user_key New account on a fresh line. So in my script I have it grabbing the data as so: $User_DataFile = "accountdata.txt"; $AccData = file($User_DataFile, FILE_SKIP_EMPTY_LINES); foreach($AccData as $line_num => $line) { $AccData = explode(" ", htmlspecialchars(str_replace(" "," ",$line))); if(stristr($AccData[1], "\n")) $AccData[1] = substr($AccData[1], 0, strlen($AccData[1])-2); $AccountID = $AccData[0]; $UserKey = $AccData[1]; echo "Account ID: ".$AccountID."<br/>User Key: ".$UserKey."<br/><br/>"; I have it set to simply echo out the data for debugging which is where I noticed that any slashes or plus or equal signs were not included. When run in Apache it returns this: Account ID: 360235276 User Key: PbI1c5+PGHSshccYd58AklmTgf5u+tbWZplMRYYxFSivRYw4AZhaVNHwADozYZhZhPnXRSV1rmsrhf1td7w6bJbySZmPHLl+hleyz/Ht4iM Account ID: 477947328 User Key: cXTnFEVP74RWtAgqM5BlwtgW2i9rP/v44oANzwF+yJZ+9mpvaschyo/HaYP1qUXgIK8nK7jy74iSCEHAgpPgPdryzpReM5cbnVDjRw7h9S0 Account ID: 503724987 User Key: XXEJsklZTFaTx8MLjuNIz0S65Sn02rgbHl2sahdReQdadKP39 evIXUoYdr5NyQMWDVE7cRpvn+zJ7mteH7WJzVh0U/sOcSG7kfcuaWpAOfo So as you can see by comparison there is no slashes or plus or equal signs present, which is going to be a major problem. Is there any way of getting around this problem? Thanks. Anyone know how I can print a file (specifically a PDF) that is stored on the server to the clients computer with a button? I don't want them to be able to view it, just print it. I've done some research and understand that there is no way to print directly without popping up the Windows Print dialog. And that is fine. I just want them to print this file, but not no where it is or be able to type in a URL to access it. Thanks Mike Hello all, I need to basically run a PHP file stored on a server when other specific files are modified, but only then. Is this possible with PHP? Thank you for the feedback, i am making song site i want to upload songs files on another instread on which m running my script for uploading songs and adding information in data... mean want to know is there any function or method that i upload files through the panel of www.site1.com and my files upload on an other server www.site2.com. which code i have to write for doing this Is it possible to allow a script running on another server to write/read a specific file on my server? I can set file permissions, but not having any luck with file paths due to php5 blocking http:// urls. Hi I have a form which is used to upload files to my server, now i need to move files to another server as soon they are uploaded, but move_uploaded_file will work with local server where form has been submitted. i was thinking to add some ftp functions to upload that file to remote server but is there any better way? that user dont notice ftp connection timing. i wants to use less ftp connections and user should not notice delay timing for image upload. Thanks for any suggestion. Hello all. I have a script that exports data from mysql to a csv file. Everything works great. However, I do not know how to save the csv file to the server. Does anyone have any ideas how I would do that? The script is below. Thanks for all help! Code: [Select] <?php $host = 'localhost'; $user = ''; $pass = ''; $db = ''; $table = ''; $file = 'export'; function escape_csv_value($value) { $value = str_replace('"', '""', $value); // First off escape all " and make them "" if(preg_match('/,/', $value) or preg_match("/n/", $value) or preg_match('/"/', $value)) { // Check if I have any commas or new lines return '"'.$value.'"'; // If I have new lines or commas escape them } else { return $value; // If no new lines or commas just return the value } } $link = mysql_connect($host, $user, $pass) or die("Can not connect." . mysql_error()); mysql_select_db($db) or die("Can not connect."); $result = mysql_query("SHOW COLUMNS FROM ".$table.""); $i = 0; if (mysql_num_rows($result) > 0) { while ($row = mysql_fetch_assoc($result)) { $csv_output .= $row['Field'].", "; $i++; } } $csv_output .= "\n"; $values = mysql_query("SELECT * FROM ".$table.""); while ($rowr = mysql_fetch_row($values)) { for ($j=0;$j<$i;$j++) { $csv_output .= escape_csv_value($rowr[$j]).','; //$csv_output .= $rowr[$j].", "; } $csv_output .= "\n"; } $filename = $file."_".date("Y-m-d_H-i",time()); //header( "Content-Type: application/save-as" ); header("Content-type: application/vnd.ms-excel"); header("Content-disposition: csv" . date("Y-m-d") . ".csv"); header( "Content-disposition: attachment; filename=".$filename.".csv"); //header( "Content-disposition: filename=".$filename.".csv"); print $csv_output; exit; ?> I have a script that uploads my file, but this script requires apache. I want to get this file onto my other server that's running nginx. Is there a way for PHP to write a file to nginx? Alternatively, is there a way for PHP to copy a file from one server to another? Because that will work as well. How do I do this? Hello There , I want to download a file from the server to the computer . How can i do this ?? i found out this code: header("Content-type: image/jpg"); header("Content-Disposition: attachment; filename=test.jpg"); the problem is , what i get is the file that the code was executed from saved in the .jpg format. how can i direct to a specified path to select a certain file then download it . example let's say i have a folder that contains 2 files: download.php and image.jpg how can i download the image.jpg from the server with the Save As window?? Thank You Hello, Ive got a script that downloads a file to my server. I want to be able to download a file from a site such as FileServe using my premium details. Ive tried http://username:password@fileserve.com/file.rar but that dosent work, It just downloads a tiny small 30kb file. Is there a way i can set a cookie or somthing so my script has access to download file using my premium account? Thanks in advance Hi, I have switched to a unix server from a windows one and my dir.php now displays in date order which makes things very hard to find Below is the code I use, can anyone tell me what to put, and where ? to make it sort by file name, or point me to a freeware script that has already invented the wheel so to speak. <?php function humansize($size) { $kb = 1024; // Kilobyte $mb = 1024 * $kb; // Megabyte $gb = 1024 * $mb; // Gigabyte $tb = 1024 * $gb; // Terabyte if($size < $kb) return $size."B"; else if($size < $mb) return round($size/$kb,0)."KB"; else if($size < $gb) return round($size/$mb,0)."MB"; else if($size < $tb) return round($size/$gb,0)."GB"; else return round($size/$tb,2)."TB"; } $path= dirname($_SERVER['SCRIPT_FILENAME']); ?> <h3>Files in <?php print $path; ?>:</h3> <ul> <?php $d = dir($path); $icon = ''; while (false !== ($entry = $d->read())) { if ( substr($entry, 0, 1)=='.' ) continue; $size = filesize($path.'/'.$entry); $humansize = humansize($size); $dotpos = strrpos($entry, '.'); if ($dotpos) { $ext = substr($entry, $dotpos+1); if ($ext === 'jpeg' || $ext === 'gif' || $ext === 'png') { $icon = "<img src='$entry' style='width: 48px; height: auto; vertical-align: text-top;' alt='icon' title='$entry' />"; } } print "<li><a href='$entry'>$entry</a> ($humansize) $icon</li>\n"; $icon= ''; } $d->close(); ?> Please help an old fellow who should know better Regards Topshed hi, I want to download the file, where i have the search query in session variable, in my local system its working good, but in server its not working, any guidance please Code: [Select] <?php include("global.php"); // Original PHP code by Chirp Internet: www.chirp.com.au // Please acknowledge use of this code by including this header. function cleanData(&$str) { $str = preg_replace("/\t/", "\\t", $str); $str = preg_replace("/\r?\n/", "\\n", $str); if(strstr($str, '"')) $str = '"' . str_replace('"', '""', $str) . '"'; } $sql = $_SESSION['emp_search_sql']; // file name for download $filename = "employees_" . date('Ymd') . ".xls"; header("Content-Disposition: attachment; filename=\"$filename\""); header("Content-Type: application/vnd.ms-excel; charset=UTF-8"); header("Pragma: no-cache"); $flag = false; $result = $DB_site->query($sql) or die('Query failed!'); while(false !== ($row = mysql_fetch_assoc($result))) { if(!$flag) { // display field/column names as first row echo implode("\t", array_keys($row)) . "\n"; $flag = true; } array_walk($row, 'cleanData'); echo implode("\t", array_values($row)) . "\n"; } ?> Thanks I need to reach Win server, scan shared folder and find out what is last created file name on this folder, and than copy this file to local folder. BUT main problem is smb, never used it before, and this is what i came up with, but no luck.
require_once('smbclient.php');
$latest = null;
$smbc = new smbclient ('//10.1.1.10/Share/Address Verification/', 'domain\\username', 'password');
if ($handle = opendir($smbc)) {
$latest = null;
while (($cur = readdir($handle) !== false)) {
if ($latest == null || filectime($cur) > filectime($latest)) {
$latest = $cur;
}
}
closedir($handle);
}
return $latest;
please help, returns Warning: opendir() expects parameter 1 to be string
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