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PHP - How To Stream Video Via Ftp Folder Not Accessable To Public
edited: please note all wmv files are not more than 10 or 20 seconds long. also their size is no more than 500kb.
I have this following code that works for photos, but wish to alter this slightly so it will work for video files (wmv) getFtpImage.php Code: [Select] <? header('Content-Type: image/jpg'); $imgdir = '/home/mysite/ftpfolder'; readfile($imgdir . '/' . $_GET['file']); ?> index.php Code: [Select] $imgdir = '/home/mysite/ftpfolder'; // the directory, where your images are stored $allowed_types = array('png','jpg','jpeg','gif'); // list of filetypes you want to show $dimg = opendir($imgdir); while($imgfile = readdir($dimg)) { if(in_array(strtolower(substr($imgfile,-3)),$allowed_types)) { $a_img[] = $imgfile; sort($a_img); reset ($a_img); } } $totimg = count($a_img); // total image number for($x=0; $x < $totimg; $x++) { $size = getimagesize($imgdir.'/'.$a_img[$x]); // do whatever $halfwidth = ceil($size[0]/2); $halfheight = ceil($size[1]/2); ?><img src="getFtpImage.php?file=<? echo ($a_img[$x]); ?>" height="180"><? // echo 'name: '.$a_img[$x].' width: '.$size[0].' height: '.$size[1].'<br />'; } i have the images show to fill the screen and wish for the video page to do the same and with the videos you click the [play] in the center of the video image to play it like most videos play, not like the flash. Similar Tutorials../ tells the php program to go up a level. Code: [Select] require_once '../directory/somefile.php'; Is there a shortcut to go to the public web folder? For example. The following file is placed 3 folders deep: "var/www/deep/deeper/verydeep/index.php" and it requires a file with location: "var/www/thisfile.php" I there a short cut/ quicker method to?? Code: [Select] require_once '../../../thisfile.php'; I have searched around and found this code that suggests that I should be able to read an image file and echo it directly in to the page without hyperlinking to the file that is outside the public folder, but i get the error message that it is not there even though the file is. Warning: getimagesize() [function.getimagesize]: Unable to access "/home/****/upload/AAABBBCCC.JPG" in /home/****/public_html/client.php on line 40 Code: [Select] $image = "AAABBBCCC.JPG"; $path= "/home/****/upload/"; $details = getimagesize($path . $image); header ('Content-Type: ' . $details['mime']); echo file_get_contents($path . $image); I can search for videos by keyword and can fetch videos list from youtube using its api in php. I can fetch video title, description, thumbnail etc. but how can i fetch video url not like this -> youtube.com/watch?id=xyz...
Example: ytpak[dot]com
Evening Everyone,
Been working on this problem for a couple of days and I am stumped. I have a single php file to handle download and streaming of files. It works great with music files, I can download and stream to an <audio> html 5 element just fine. When it comes to my movies, I can download fine but it fails on streaming to a <video> html 5 element. I have done some logging and it looks like after a very short time it just quits.
log when streaming music:
/path/to/music/124 - Mouth Techno -1.mp3 size: 1508731 ctype: audio/mpeg range: 0-1508730/1508731 write chunk: 8192-1508731 write chunk: 16384-1508731 .... write chunk: 1507328-1508731 write chunk: 1515520-1508731 completedlog when streaming movie - this is the complete output, it just stops: Log Started /path/to/movies/AVP_REQUIEM_UNRATED.Title1.DVDRip.mp4 size: 889628920 ctype: video/mp4 range: 0-889628919/889628920 write chunk: 8192-889628920 write chunk: 16384-889628920 write chunk: 24576-889628920 write chunk: 32768-889628920 write chunk: 40960-889628920 write chunk: 49152-889628920 write chunk: 57344-889628920 write chunk: 65536-889628920Here is how I am downloading and streaming the files. Music files work just fine with <audio>, movie files I can only download but want to stream with <video>. This is a hack from multiple sources on the net.
<?php
// sanitize the file request, keep just the name and extension
$filename = $filefix = str_replace('%20', ' ', $_GET["name"]);
$file_path = $filename;
$path_parts = pathinfo($file_path);
$file_dir = $path_parts['dirname'];
$file_name = $path_parts['basename'];
$file_ext = $path_parts['extension'];
$path_default = "/path/to/music/";
$path_types = array(
"mp3" => "/path/to/music/",
"mpg" => "/path/to/movies/",
"avi" => "/path/to/movies/",
"mp4" => "/path/to/movies/",
);
$path = isset($path_types[$file_ext]) ? $path_types[$file_ext] : $path_default;
$file_path = "$path"."$filename";
clearLog();
startLog();
writeLog("$file_path\n");
// allow a file to be streamed instead of sent as an attachment
$is_attachment = isset($_GET["play"]) ? false : true;
// make sure the file exists
if (is_file("$file_path")){
$file_size = filesize($file_path);
$file = @fopen($file_path,"rb");
writeLog("size: $file_size\n");
if ($file){
header("Expires: -1");
header("Cache-Control: public, must-revalidate, post-check=0, pre-check=0");
// set appropriate headers for attachment or streamed file
if ($is_attachment){
header("Content-Disposition: attachment; filename=\"$file_name\"");
}else{
header('Content-Disposition: inline;');
}
// set the mime type based on extension.
$ctype_default = "application/octet-stream";
$content_types = array(
"exe" => "application/octet-stream",
"zip" => "application/zip",
"mp3" => "audio/mpeg",
"mpg" => "video/mpeg",
"avi" => "video/x-msvideo",
"mp4" => "video/mp4",
);
$ctype = isset($content_types[$file_ext]) ? $content_types[$file_ext] : $ctype_default;
header("Content-Type: " . $ctype);
writeLog("ctype: $ctype\n");
$end = ($file_size - 1);
$start = 0;
header("Content-Length: $file_size");
header('Accept-Ranges: bytes');
header("Content-Range: bytes $start-$end/$file_size");
writeLog("range: $start-$end/$file_size\n");
$a=0;
while(!feof($file)) {
$chunk = (1024*8);
echo fread($file, $chunk);
//ob_flush();
flush();
$a=$a+$chunk;
writeLog("write chunk: $a-$file_size\n");
if (connection_status()!=0){
writeLog("failed\n");
fclose($file);
exit;
}
}
// file save was a success
writeLog("completed\n");
fclose($file);
exit;
}else{
// file couldn't be opened
header("HTTP/1.0 500 Internal Server Error");
exit;
}
}else{
// file does not exist
header("HTTP/1.0 404 Not Found");
exit;
}
function startLog(){
$myfile = fopen("newfile.txt", "w");
fwrite($myfile, "Log Started\n");
fclose($myfile);
}
function writeLog($pstr) {
$myfile = fopen("newfile.txt", "a");
fwrite($myfile, $pstr);
fclose($myfile);
}
function clearLog() {
//fclose("newfile.txt");
unlink("newfile.txt");
}
?>
incase it helps, code calling download.php
<!DOCTYPE html>
<html>
<head>
<meta charset="UTF-8">
<link rel="stylesheet" type="text/css" href="movies.css">
</head>
<body>
<a href="javascript:history.back()"><img src="pics/back.png" style=\"height:50px; width=50px;\"/></a>
<a href="index.html"><img src="pics/home.png" style="height:50px; width=50px;display: in-line;"/></a>
<div id="searchContainer" style="height: 40px; width = 700px; display: block; padding: 10px;">
<input type="text" id="SearchString" placeholder="Enter Search Address" style="vertical-align: top;padding: 10px;" class="valid">
<button name="btnSearch" id="btnSearch" type="button"></button>
</div>
<div id="Mainbox" >
<div id="ItemList">
<ol id="List">
<?php
$dir = '/path/to/movies/';
$dirlist = array_diff(scandir($dir), array('..', '.','Thumbs.db'));
asort($dirlist);
$a=0;
foreach ($dirlist as $file) {
$size = round(filesize('/path/to/movies/'.$file)/1048576);
$filefix = str_replace(' ', '%20', $file);
echo "<li><div class=\"item\" id=\"$a\">";
//title
echo "<div id=\"title\">$file</div>";
echo "<div id=\"mb\">$size MB</div>";
echo "<div id=\"dl\"><a href=\"download.php?name=$filefix\"><img src=\"pics/download.png\" style=\"height:25px; width=25px;\"/></a></div>";
if ($size < 1500){
$url = 'download.php?name='.$filefix.'&play=true';
echo "<div id=\"play\" data-value=\"$url\"><a href=\"javascript:void(0)\" onClick=\"updateSource(this);\"><img src=\"pics/play.png\" style=\"height:25px; width=25px;\"/></a></div>";
}
echo "</div></li>";
$a++;
}
?>
</ol>
</div>
</div>
<div id="videocontainer">
<video id="video" controls>
<source id="mp4movie" type="video/mp4">
<source src="movie.ogg" type="video/ogg" codecs="avc1.64001E, mp4a.40.2">
Your browser does not support the video tag.
</video>
</div>
<script type="text/javascript">
function updateSource(element) {
var dvalue = element.parentElement.getAttribute('data-value');
var video = document.getElementById('video');
var source = document.getElementById('mp4movie');
source.src=dvalue;
video.load(); //call this to just preload the audio without playing
video.play(); //call this to play the song right away
}
</script>
</body>
</html>
Thanks for any help!
Edited by AdrianHoffman, 27 September 2014 - 11:51 PM. How can I call a public function inside of another public function? The get_primary_edge() says it's undefined, but it's just another public function in the class so shouldn't this work? Code: [Select] public function get_dynamic_edge($uid) { $uid = (int)$uid; $sql = "( SELECT `users`.`id` FROM partners INNER JOIN `users` ON `partners`.`user_id` = `users`.`id` WHERE partners.friend_id = '${uid}' AND `approved` = 1 ) UNION ALL ( SELECT `users`.`id` FROM `partners` INNER JOIN `users` ON `partners`.`friend_id` = `users`.`id` WHERE `partners`.`user_id` = '${uid}' AND `approved` = 1 )"; $result = mysql_query($sql) or die(mysql_error()); $i = 0; while (($row = mysql_fetch_assoc($result)) !== false) { $dynamic[$i] = array( 'uid' => $row['id'], 'score' => get_primary_edge($row['id']), ); $i++; } print_array($dynamic); } I got this script: But it give me error, file_get_contents cannot open stream. I need to add the FTP connection with user/pass paramaters. then look in set http url, to get the file contents(images) and transfer to ftp server location. Can Anyone take alook and tell me if I am going down the right path and how to get there. Please Code: [Select] function postToHost($host, $port, $path, $postdata = array(), $filedata = array()) { $data = ""; $boundary = "---------------------".substr(md5(rand(0,32000)),0,10); $fp = fsockopen($host, $port); fputs($fp, "POST $path HTTP/1.0\n"); fputs($fp, "Host: $host\n"); fputs($fp, "Content-type: multipart/form-data; boundary=".$boundary."\n"); // Ab dieser Stelle sammeln wir erstmal alle Daten in einem String // Sammeln der POST Daten foreach($postdata as $key => $val){ $data .= "--$boundary\n"; $data .= "Content-Disposition: form-data; name=\"".$key."\"\n\n".$val."\n"; } // Sammeln der FILE Daten if($filedata) { $data .= "--$boundary\n"; $data .= "Content-Disposition: form-data; name=\"".$filedata['name']."\"; filename=\"".$filedata['name']."\"\n"; $data .= "Content-Type: ".$filedata['type']."\n"; $data .= "Content-Transfer-Encoding: binary\n\n"; $data .= $filedata['data']."\n"; $data .= "--$boundary--\n"; } // Senden aller Informationen fputs($fp, "Content-length: ".strlen($data)."\n\n"); fputs($fp, $data); // Auslesen der Antwort while(!feof($fp)) { $res .= fread($fp, 1); } fclose($fp); return $res; } $postdata = array('var1'=>'today', 'var2'=>'yesterday'); $filedata = array( 'type' => 'image/png', 'data' => file_get_contents('http://xxx/tdr-images/images/mapping/dynamic/deals/spot_map') ); echo '<pre>'.postToHost ("localhost", 80, "/test3.php", $postdata, $filedata).'</pre>'; I'm learning MVC and getting a bit confused with the accessibility of variables in classes... Code: [Select] class Load { public $load2; } Does this mean that the variable $load2 will be accessible just by all functions within the class Load? or: Does that mean that the variable $load2 will be accessible by all other classes, eg model, controller...etc inc all the functions within? I have the following static method: public static function query($query){ self::$num_queries++; return mysql_query($query)or die(mysql_error()); } I then call it like this: $oql = Mysql::query("SELECT first FROM members WHERE member_id = '{$this->owner}'"); $rql = mysql_fetch_assoc($oql); I then get the following error: Quote Warning: mysql_fetch_assoc(): supplied argument is not a valid MySQL result resource in /incl/php/classes/Photo.php on line 13 Why am I getting this error? Hi i created a website where you cam view ip webcams via php. I want to make it so people can make the camera private and public. I made two fields in mysql called "Username" and "Puborprivate" I tried to make the "Puborprivate" have two numbers "0" would be private and "1" would be public. How could I do this? My site is cwuforum.com/live/ Hi folks, I had a working, editable profile but it wasn't visible to other users. So I'm trying to make that conversion now. Here's the current 'myprofile' code: <?php session_start(); include('config.php'); include('date.php'); $id = $_GET['id']; $sql = mysql_query("SELECT * FROM members WHERE id = '$id' LIMIT 1"); $check = mysql_num_rows($sql); $check = mysql_query($sql_user_verify) or die('Cannot Execute:'. mysql_error()); if ($check > 1) { echo "No one matches that id number!"; exit(); } if($check == 1) { while($row = mysql_fetch_array($sql)) { $user = $id; echo "<h2>Profile</h2> <table>"; $row = mysql_fetch_array($sql); echo "<tr><th>ID#:</th><td>".$user."</td></tr> <tr><th>Name: </th><td>".$row['callname']."</td></tr> <tr><th>Email: </th><td>".$row['email']."</td></tr> <tr><th>Password: </th><td><input type='password' value='".$row['password']."' disabled='true' /></td></tr> <tr><th>Registered: </th><td>".$row['registered']."</td></tr> <tr><th>Last Login: </th><td>".$row['lastlogin']."</td></tr>"; echo "</table><br />"; } if($id = $_SESSION['id']) { echo "<h2>Profile</h2> <form method='post' action='editprofile.php'> <table>"; $row = mysql_fetch_array($sql); echo "<tr><th>ID#:</th><td>".$user."</td></tr> <tr><th>Name: </th><td>".$row['callname']."</td></tr> <tr><th>Email: </th><td>".$row['email']."</td></tr> <tr><th>Password: </th><td><input type='password' value='".$row['password']."' disabled='true' /></td></tr> <tr><th>Registered: </th><td>".$row['registered']."</td></tr> <tr><th>Last Login: </th><td>".$row['lastlogin']."</td></tr>"; echo "</table><br /> <input type='submit' value='edit profile' /> </form>"; } } else { die (); } ?> <?php include('footer.php'); ?> Here's the link to the user's own profile: <a href=myprofile.php?id='.$id.'>Profile</a> And here's the edit profile link, which works fine: <?php include('config.php'); include('date.php'); if(isset($_POST['btnedit'])){ $callname = $_POST['callname']; $email = $_POST['email']; $password = $_POST['password']; $sql = mysql_query( "UPDATE users SET callname='".$callname."', email='".$email."', password='".$password."' WHERE id='".$_SESSION['id']."'" ); if($sql){ echo "<script>alert('profile updated');window.location='myprofile.php'</script>"; }else{ echo "<script>alert('updating profile failed!');</script>"; } } $sql = mysql_query( "SELECT * FROM users WHERE id='".$_SESSION['id']."'" ); $row = mysql_fetch_array($sql); $userfinal = $_SESSION['id']; $user = $userfinal; echo "<h2>Edit profile</h2> <form method='post'> <table><tr><th>ID#:</th><td>".$user."</td></tr> <tr><th>Name:</th><td><input type='text' name='callname' value='".$row['callname']."'/></td></tr> <tr><th>Email:</th><td><input type='text' name='email' value='".$row['email']."'/></td></tr> <tr><th>Password:</th><td><input type='password' name='password' value='".$row['password']."'/></td></tr> <tr><th>Registered:</th><td>".$row['registered']."</td></tr> <tr><th>Last Login:</th><td>".$row['lastlogin']."</td></tr> </table><br /> <input type='submit' name='btnedit' value='update' /> </form>"; ?> <?php include('footer.php'); ?> It fails, it says the query was empty, even though there are user accounts created and information is being stored (as it worked fine before I tried editing the code to make it public. What am I doing wrong? I am modifying someones existing coldfusion web app. I am adding php processing pages to do various tasks. Up to this point I have just been calling the php pages, and interacting with the web app by passing variables via the url. Current usage: Code: [Select] public.cfm calls processing.php?id=69 Then processing will do what it has too, then ultimately: Code: [Select] header("Location: $publichome?id=$id&importantstuff=$stuff"); exit(); And the webapp will pick up where it has too. But now one of my scripts has to send a JSON object back instead of simple variables. I don't know how to get this done. I tried doing a post with cURL but that wasn't working because I need the public facing coldfusion page to take over and curl returns to the php script (I know I can echo the body of the curl result but this keeps me on the php script domain which I dont want). Is there a way to do the above header location and send an object because thats what I need - the php script to stop and the coldfusion page to be served up with the object to work with. Do I have to create some sort of JSON service in php, that the coldfusion page will call an retrieve the result? If so how? I am writing a script which will be dependent on the client's public ip address. e.g.
if the client is using ip address 203.122.55.124 script A should run and if else then script B should run. Now I know that the If and else will be used but cant guess how will the public ip be captured.
Please help
This topic has been moved to Miscellaneous. http://www.phpfreaks.com/forums/index.php?topic=316783.0 <? for ($i = 1; $i <= $first_day_of_month-1; $i++) { $days_so_far = $days_so_far + 1; $count_boxes = $count_boxes + 1; echo "<td width=\"125\" height=\"100\" class=\"beforedayboxes\"></td>\n"; } for ($i = 1; $i <= $days_in_month; $i++) { $days_so_far = $days_so_far + 1; $count_boxes = $count_boxes + 1; IF($_GET['month'] == $todays_month+1){ IF($todays_date == $day){ $class = "publicholidayhighlightedboxes"; } ELSE { $class = "dayboxes"; } } ELSE { IF($i == $todays_date){ $class = "highlighteddayboxes"; } ELSE { $class = "dayboxes"; } } The problem is I can only display one highlighted box in one month. For example, in November, there are two public holidays, but only 1 public holiday box is highlighted. Would appreciate if someone can help me out asap. Thank you Hi, I want to create a simple online buying site. I have an admin site with login where admin can add items to the database table, and change other fields such as price and description of product and I want to make a public html page to display the updates made in my admin page. I appreciate it if someone give me some suggestions on how to get started. My admin php scripts is working fine (so SQL queries for UPDATE, DELETE, INSERT) but I don't know how to 'sync' it with the an nice html table of products the user can checkbox off to purchase on the public website. Let me know, thanks. I tried these below, Code: [Select] class Site extends Controller { function Site() { public $data = Array(); } } but it fail? Thanks in advanced. Hi, I am making a dating site where I have made the user profile edit page visible to the user when they log in, and I think I can get away with not showing the user their "public" profile view. But I definitely need to show other users on the site the "public" non editing profile page view. But I don't know how to do this. I have yet to create the search, search results, thumbnails with optional descriptions of the possible dating results. But I first want to just get 2 versions of the user profile page view. One that the user sees that I have already done. (The editable one). And the other I need to make which is the page the other users will see, (The public profile) Please if anyone has any idea how to do this I would greatly appreciate it, especially if you have any pseudocode ideas. thank you. Hi ! I'm trying to understand how php://input works. I've read the manual ( http://php.net/manual/en/wrappers.php.php ) and I have an example of a file upload receiving the file with php://input instead of $_FILES. But I can't understand it, does somebody a good tutorial about php://input ? What is the data inside it? is always the same that $HTTP_RAW_POST_DATA ? How can we send a file to PHP and receive it with php://input ? I'm trying to see what's inside php://input with this code: Code: [Select] $in = fopen("php://input", "rb"); echo Debug::vars($in); if ($in) { while ($buff = fread($in, 4096)) { echo $buff . EOL; // fwrite($out, $buff); } } but I get always blank output (Debug is a Kohana class and it returns: Quote resource(stream) php://input Thanks !! I am creating a stream for my website similar to facebook's news feed where users can post to, add photos too ect. When a user uploads a photo it gets added to the photos table and a new row to the stream Code: [Select] mysql_query("INSERT INTO photos VALUES ('','$id','$username','$photo','$time')"); mysql_query("INSERT INTO stream VALUES ('','$id','$username','$time','No comment','$photo','')"); Which displays the image on the stream fine but what i am looking to do is if the user uploads more images one after another instead of adding a new post to the stream for every picture i want to show all of the new pictures in one post like what Facebook does. I can't figure out how i would do this. The following will create a PHP stream. $response = $this->guzzleHttp->get($url); $stream = \GuzzleHttp\Psr7\StreamWrapper::getResource($response->getBody()); How can I return a stream using just PHP's native cURL library? |
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