PHP - Php On The Command Line

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http://www.phpfreaks.com/forums/index.php?topic=350801.0

can anyone help me with an overwhelming problem ?

I want to use this command in the php curl code.

curl -v --data "WSCommunityStringRW?2=1200ve50set&Submit=Submit" http://10.2.3.111/Forms/SnmpCommunityString -u "admin:a1s2d3" --anyauth

Hello everyone
I have a question?
I run a PHP script loads about 200 calls simultaneously on Linux environment,
so my question is what is best way to run
a command line As an example php-f example.php
or make it through the apache
example "curl http://localhost/example.php"

Thank you
woren

Hi, suppose I want to write a PHP script that checks whether a valid email address exists or not. There are a number of GUI-based tools to verify this, but is there any command line tool to do the same so that I can use PHP to capture the output?

hello dear php-experts


how to testrun a drive with command-line?

note: i had several blank screens during the last week

does this somewhat have to  do with the hard-drive?

which tests can be done?

So, I'm trying to read a file from a different filepath than the current working directory.    I have some simple PHP like this :

<?php
 
    $input_map = "readfile.php";
    $map_contents = file_get_contents($input_map);
    echo $map_contents."<br />\n";
?>

And this'll work fine because it's in the same directory but if I try to set $input_map = "/home/...", the browser will return an empty string. This script will work from the command line though. So how do I get file_get_contents() to read from the server's file structure instead of just the working directory?   Edit : For example, this will not work through the browser :

<?php
 
    $input_map = 
"/home/...";
    $map_contents = file_get_contents($input_map);
 
    echo $map_contents."<br />\n";
    var_dump($map_contents);
?>

Edited by MutantJohn, 21 January 2015 - 06:35 PM.

Hello all

 

I'm new to this forum.

I've been struggling on this problem for a few days now.

I’m writing a script to automatically push code to a git server.
I’m using php and running the script via the command line.
After asking the user to enter the branch and commit message, the following code runs:
 

exec(‘git config user.name "’ . $userName . ‘"’);
exec(‘git config user.email "’ . $userEmail . ‘"’);

exec('git checkout -b ’ . $branch);
exec(‘git add --all’);
exec(‘git commit -m "’ . $message . ‘"’);

exec('git push origin ’ . $branch);

 

When running the last command, the script stops and asks for a user name, then a password.
How can I enter that username and password via the script?
I don’t want to have to type in the user name and password each time.
As I said, I've been stuck on this for 2 days now.

I tried other forums, searching the net.

I'm frustrated...

Thanks in advance.
Have a lovely day.

I would like to update the DB when a service ends and thought about doing so in the destructor, but I did not make much progress.  Then tried using pcntl_signal(), but also didn't get far.  Is doing so possible?  Thanks

/usr/lib/systemd/system/test123.service

[Unit]
Description=bla
After=syslog.target

[Service]
ExecStart=/usr/bin/php /var/www/testing/__destruct.php

[Install]
WantedBy=multi-user.target

 

/var/www/testing/__destruct.php

<?php
ini_set('display_errors', 1);

pcntl_signal(SIGTERM, function() {
    syslog(LOG_INFO, 'Caught SIGTERM');
    die;
});
pcntl_signal(SIGHUP, function() {
    syslog(LOG_INFO, 'Caught SIGHUP');
    die;
});
pcntl_signal(SIGUSR1, function() {
    syslog(LOG_INFO, 'Caught SIGUSR1');
    die;
});
pcntl_signal(SIGINT, function() {
    syslog(LOG_INFO, 'Caught SIGINT');
    die;
});
pcntl_signal(SIGABRT , function() {
    syslog(LOG_INFO, 'Caught SIGABRT ');
    die;
});
/*
pcntl_signal(SIGSTOP , function() {
    syslog(LOG_INFO, 'Caught SIGSTOP ');
    die;
});
*/
/*
pcntl_signal(SIGKILL , function() {
    syslog(LOG_INFO, 'Caught SIGKILL ');
    die;
});
*/

class Bla
{
    private $bla;
    public function __construct($bla) {
        syslog(LOG_INFO, '__construct');
        $this->bla = $bla;
    }

    public function __destruct()
    {
        syslog(LOG_INFO, '__destruct');
    }

    public function start()
    {
        $counter=0;
        $counter2=0;
        while(true) {
            $counter++;
            if($counter>10000000) {
                $counter2++;
                $counter=0;
                syslog(LOG_INFO, '.');
            }
            if($counter2>5) {
                die('all done!');
            }
        }
    }

}

$bla = new Bla('hello');
$bla->start();

 

Hi all,

In the process of moving websites off an old win 2008 server and onto a new win 2016 server. I discovered that dns_get_record is failing on the new server. I made a simple test page:

$dnsrecs = dns_get_record('google.com'); 

When i call this as a webpage, it comes back with dns query failed. It comes back instantly, so it's not like it's timing out. But, if i just call the webpage from the command line, it comes back with the dns record. Why would dns_get_record fail when used in a webpage, but work from the command line?  I can make outside connections since I was able to send an email to an smtp server. I thought maybe this is a permission issue, but seems odd I'd be able to send an email using php but not do a dns query.

Oh, and I have two versions of php installed on this server - 5.4.10 and 7.4.9. The old version is a direct copy from the 2008 server. 7.4.9 is a clean install. Both of them behave the same way. webpage fails, command line works. Also, nslookup works. I also tried switching to using google's name server, but it had no effect on anything.

Anyone have any suggestions? 

  No idea how to add a new line so it's easier to read in the terminal. Debugging this way is absolutely horrible.
Edited by Monkuar, 03 December 2014 - 09:06 AM.

I have a PHP file that is executed via batch file very frequently for live updating. This is a sort of "sync" file for reading/writing to a MySQL database. I am able to get it functioning absolutely fine when executed manually via a web browser (and my echo debug lines output the expected information), yet when I run the same PHP file via the command line, it seems to just not be capable of opening any file for reading, so the equivalent variables that are correct when executed on a web browser are blank when echoed through the command line.

Is there a different way of handling reading of files when running a php script via the command line, or should it function exactly the same as when run via a browser?

For instance:

$k = "0";
$line = file("examplefile.log")[$k];
echo $line;

what im trying to do is take a youtube embed code find the URL code for that video and remove all other parts of the code keeping only the URL of the video
after i get the URL by it self then replace the http://www.youtube.com/ part of the URL with http://i2.ytimg.com/vi/

to do this i know that i need something like this to get the URL of the video
http://www.youtube.com/((?:v|cp)/[A-Za-z0-9\-_=]+)
but how to only return just the URL is something idk how to do

then use str_replace http://www.youtube.com/(?:v|cp)/" with  http://i2.ytimg.com/vi/

so in the end im asking if anyone know how to remove all other codes i dont want  and only keep the URL


this may have to be done using "regex" im not sure as i dont know to much about regex and what it can do but does sound like it would help lol

Dear All

           Good Day, i am new to PHP (a beautiful server side scripting language). i want to send a mail with line by line message i tried with different types like by placing the things in table and using  <br /> but the thing is the tags are also visible in the message of the mail.

Here is my code:

$message1  = "Name       :".  $_REQUEST['name']."<br />";
$message1 .= "Surname    :".  $_REQUEST['surname']."<br />";
$message1 .= "Cellphone  :".  $_REQUEST['mobileno']."<br />";
$message1 .= "Telephone  :".  $_REQUEST['landno']."<br />";
$message1 .= "Fax        :".  $_REQUEST['fax']."<br />";
$message1 .= "Company    :".  $_REQUEST['company']."<br />";
$message1 .= "Email      :".  $_REQUEST['email']."<br />";
$message1 .= "Country    :".  $_REQUEST['country']."<br />";
$message1 .= "Enquity    :".  $_REQUEST['enquiry']."<br />";
$message1 .= "Date&Time  :".  $date."<br />";

For this code if try to print/echo it it is working fine it is displaying line by line, but using this variable ($message1) in the mail these <br /> are also visible.
Can any one guide me to resolve(to remove these tags from the message part) this issue.
Thanks in Advance. :confused:

i have to read a single line from a csv,  its a really big file and i only need one column. i need the response to be a string ,i made a search and found the following code but i dont have any idea how to get a single line from a single string per run .

<?php
$row = 1;
//open the file
if (($handle = fopen("file.csv", "r")) !== FALSE)
{
    while (($data = fgetcsv($handle, 0, ",")) !== FALSE)
    {
        $num = count($data);
        echo "<p> $num fields in line $row: <br /></p>\n";
        $row++;
        for ($c=0; $c < $num; $c++)
        {
            echo $data[$c] . "<br />\n";
        }
    }
    fclose($handle);
}
?>

Edited by bores_escalovsk, 16 May 2014 - 06:38 PM.

Hi.

I want a simple textbox, that when submited, will replace very every new line, with the <br> tag.

What will happen, when it submits, it will take the contents of a textbox, add the <br> tag where a new line is suposed to be, and save the string to a MySQL Database.

I think this is the easiest way of allowing a user to edit what appears on a website when logged in, but if there is a easier way, then please tell me.

What I am trying to do, is a login page, and once logged in, you enter new text into the textbox, click submit, and on the website homepage, the main text will change to what was submitted. But if there is a new line, I think the only way in HTML to make one is to put a <br> tag, so I want the PHP to but that tag wherever there is a new line.

Sorry if I am confusing, I am not that advanced at PHP, but I would be very happy if you could supply me with the correct code. Time is running out...

If you do not understand me, please tell me

--
PHPLeader (not)