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PHP - Passing Variables Between Functions
I have a little problem.
I have made a script(function) to connect to the database. this is the script: connect(php) Code: [Select] <?php $server = "localhost"; $username = "username"; $password = "password"; function connectdatabase($type,$database) { if($type == "mysql") { $mysql = mysql_connect($server, $username, $password); mysql_select_db($database, $mysql); } else if($type == "mysqli") { $mysqli = new mysqli($server, $username, $password, $database); } else if($type == "mssql") { $mssql = mssql_connect($server, $username, $password); mssql_select_db($database, $mssql); } function query($query) { if($type == "mysql") { mysql_query($query); } else if($type == "mysqli") { $mysqli->query($query); } else if($type == "mssql") { mssql_query($query); } } } ?> and aanmelden(php) Code: [Select] <?php include("config.php"); connectdatabase("mysql", "[ledensysteem]"); //example if(!empty($_POST)) { if(!preg_match('/^[A-Za-z1-9-]{'.$Minimale_Gebruikersnaam_Karakters.',}$/', $_POST['gebruikersnaam'])) { if(!isset($error)){ $error=1;}else{$error=$error+1;} echo "Je gebruikersnaam moet minimaal {$Minimale_Gebruikersnaam_Karakters} tekens bevaten en mag geen komma of andere onbedoelde tekens zijn<br>Toegestaan is <br>A t/m Z <br>a t/m z <br>1 t/m 9 <br>en -"; } else { echo "geldige gebruikersnaam(goedgekeurd)"; } if(preg_match('/^[A-Za-z1-9-]{'.$Minimale_Wachtwoord_Karakters.',}$/', $_POST['wachtwoord']) && preg_match('/^[A-Za-z1-9-]{'.$Minimale_Wachtwoord_Karakters.',}$/', $_POST['herhaalwachtwoord'])) { if($_POST['wachtwoord'] != $_POST['herhaalwachtwoord']) { if(!isset($error)){ $error=1;}else{$error=$error+1;} echo "niet hetzelfde wachtwoord"; } /*else { echo "hetzelfde wachtwoord (goedgekeurd)"; }*/ } else { if(!isset($error)){ $error=1;}else{$error=$error+1;} echo "wachtwoord moet minimaal {$Minimale_Wachtwoord_Karakters} tekens bevatten!"; } if(!preg_match("/^[A-Za-z1-9_.-]{1,}@[A-Za-z1-9-]{1,}\.[A-Za-z1-9]{2,3}$/", $_POST['email'])) { if(!isset($error)){ $error=1;}else{$error=$error+1;} echo "onjuiste email"; } else { echo "goedgekeurd!"; } if(!isset($error)) // this problem is fixed yesterday on phpfreaks.com forum! { echo "goedgedaan geen errors!"; query("SELECT username FROM phpfreaks WHERE password = private"); // example } } else { ?> <HTML> <HEAD> <TITLE>New Document</TITLE> </HEAD> <BODY> <form method="post"> <input type="text" name="gebruikersnaam" value="gebruikersnaam" maxlength="20" size="20"> <input type="password" name="wachtwoord" value="wachtwoord" maxlength="20" size="20"> <input type="password" name="herhaalwachtwoord" value="herhaalwachtwoord" maxlength="20" size="20"> <input type="text" name="email" value="voorbeeld@domeinnaam.extensie" maxlength="50" size="20"> <input type="submit" name="login" value="inloggen"> </form> </BODY> </HTML> <?php } ?> the problem is, is that i want to pass a variable between functions like $type (the database type) between connectdatabase(); and query(); in the 'aanmelden.php' file is an example of how i use the function (on line 3 and 45 the ones with //example comment) thanks for reading. please help. ps. config.php contains include("connect.php"); Similar TutorialsI'm making a registration form and I'm really new at it. I've had a look about at similar issues but feel like I've got my code set up right, I obviously don't. I have a registration_handler.php and a functions.php file. I'm simply trying to pass an array ($errors[]) from the functions that generate them to a function that prints them out on registration_handler.php. It seems so easy, but I'm not getting it. Here's my code: from functions.php: (this is just an example of one of the functions)
// USERNAME (MANDATORY)
//uses the clean_names() and checks for empty input
function assign_username() {
global $conn;
$username = $_POST['username'];
if(!$username){
$errors[] = "A username is mandatory";
echo "A username is mandatory <br>";
} else {
$username = clean_names($username);
}
//check for duplicate username and return $username if doesn't exist already
$username_check = mysqli_query($conn, "SELECT username FROM users WHERE username='$username'");
$number_rows = mysqli_num_rows($username_check);
if($number_rows > 0) {
$errors[] = "Username already in use <br>";
echo "Username already in use <br>";
} else {
return $username;
}
return $errors;
} // END USERNAME
Also from functions.php, the function to print out the error array:
//display error array
function show_errors($errors) {
print_r($errors);
}
and the function call from registration_handler.php:
if(isset($_POST['register_button'])) {
//assign clean form variables
$firstname = assign_firstname();
$lastname = assign_lastname();
$username = assign_username();
$email = assign_email();
$password = assign_password();
$date = date("Y-m-d");
$errors = array();
show_errors($errors);
}
I'm intentionally leaving the username out to test this on the form but I only get returned Array() It echos "Username is mandatory" but it seems like it's not passing the error string to the error array Can anyone point me towards what I'm doing wrong, please. I appreciate the replies Edited June 11 by TechnoDiverhi guys im back for more php questions hope you dont get annoyed <?php function getvalue($num) { echo "<input type='text' name='txt1' value='$num'>"; } ?> <html> <head> <title>Home</title> </head> <body> <form action="" method="POST"> <input type="text" name="txt1" id="txt1" value="0"> <input type="button" name="btn1" id="btn1" value="1" onclick="getvalue(1);"> <input type="button" name="btn2" id="btn2" value="2" onclick="getvalue(2);"> </form> </body> </html> here is my code my question is how can i pass the values at the php function? how can i display the passed value to the textbox txt1? is this code correct? echo "<input type='text' name='txt1' value='$num'>"; i have two functions. In function two it has $id=9. how do i get function one to echo $id? how do i adjust the below example to accomplish this? Code: [Select] $newdb = new Database(); class Database { function one() { $newdb->two(); echo $id; } function two() { $id = 9 return $id; } } I have a database that holds a list of companies. the database includes and ID, and name of each company. Now when an articles gets submitted to my site it can then be related to company. We a relate a company to an article its related through its ID. What I want to do is create a function that would let me easly convert my company ID into company name within having to write out the queries over and over again in my code. Only problem is I can't get it to work. I have two files, index.php and functions.php. functions.php Code: [Select] function cname($pubid) { global $db; $company= $db->query("SELECT * FROM my_database WHERE id='$pubid'") or die(mysql_error()); while($company= $db->fetch_array($company)) { $cname = $company['name']; } return $cname; } and within index.php I put Code: [Select] echo cname($companyID); Now, when I first looked at index.php I was getting an error. I know it had something to do with me using my variables within the function and after some searching I ended up getting rid of the error by adding "global $db;" to my code. Please note that I include functions.php at the top of index.php. What am I doing wrong and why wont it work? HELP PLEASE! also note that my i've rechecked and all the database info is correct and names spelt right. Just dont know what else to do. Learning something new here so if anyone can tell me why I this wont return a value? page1.php Code: [Select] <?php require "page2.php"; getuserid(); echo $userID; ?> page2.php Code: [Select] <?php function getuserid() { $user =& JFactory::getUser(); $userID = $user->id; global $userID; } ?> Still working on my project, and i have been learning a lot here! Thank you so much. But as you may have guessed, i still have problems. User registration is working, and new users are put in the database with a rank of 0. This means they can't do anything. (can there be trouble with this. I mean, a rank of "0"?) An admin needs to give access to these accounts, but that is where it becomes difficult. The following code is showing the new accounts to the admin. Code: [Select] <?php include("navbar.php"); if ($admin<2) //normal guy or not { die ("Du har ikke rettigheder til at se denne side!"); } else if(isset($_POST['submit'])) { //code to make the user able to use stuff } { $connect = mysql_connect("localhost","root",""); mysql_select_db("eksamen - phoenix"); $query = mysql_query("SELECT * FROM users WHERE rank='0'"); ?> <form action='admin.php' method='POST'> <table> <?php while($row = mysql_fetch_assoc($query)) { echo " <tr> <td> ".$row['username']." </td> <td> ".$row['email']." </td> <td> ".$row['real_name']." </td> <td> <input type=\"checkbox\" name=".$row['username']." value=\"Godkend\"> </td> </tr> ";} ?> <tr> <td> <input type='submit' name='submit' value='Register'> </td> </tr> </table> </form> <?php } ?> As you may see, there is a lot of turning php on and off. I made it work this way, but i guess there is nothing wrong with it. The problem is that the username is not stored, so i can connect to the database and change the "rank" value. Changing that value should be easy, but storing the username is as easy as i thought. Any ideas? I have this function: Code: [Select] function echo_exist($pre1,$ee,$post1) { if ($ee!='') { return $pre1; return $ee; return $post1; } else { //do nothing } } But when I try to echo it Code: [Select] echo_exist("(","$row['payment_type']",")"); I get syntax error, unexpected T_ENCAPSED_AND_WHITESPACE If $row['payment_type'] exists, I want it to be displayed in parentheses like: (AUTO) I suspect it has to do with my ' characters for the associative array, but I am new with functions so perhaps it is the multiple arguments that are wrong? I think I need to use $this, but I need to be able to add the two values returned from both of my functions. How would I do that? Code: [Select] public function get_users_edge($uid) { $users_primary->get_users_primary_edge($uid); $users_dynamic->get_users_dynamic_edge($uid); echo $users_primary + $users_dynamic; } I've written the following code: Code: [Select] $mode = 'development'; // 'Development' or 'Public' // Writes a buffer to a file /** * ob_file_callback() * Writes the generated CSS to a file. * @param mixed $buffer * @return void */ function ob_file_callback($buffer) { // stylesheet-public.css is the output generated file $ob_file = fopen('stylesheet-' . $mode . '.css','w'); fwrite($ob_file, $buffer); } $buffer = 'test'; ob_start('ob_file_callback'); $mode is always empty when I run this code. Is it an issue because ob_file_callback is an overridden function? I everyone, I'm developing a small MVC framework for my personal work, now, in order to have access from all the classes to certain variables I've created a registry class, for this to work I have 2 options: 1.- passing every time the registry object to the constructor class(controllers, models, etc) or 2.- create in the registry static set and get so I can reach the variables by Registry::set(name, value) and Registry::get(name) My question is, which one of this two options takes less resources(is faster)? I hope anyone can help me with this, thanks in advance I have some questions about the scope of navigation : if i define a constant like define('constant'), php manuel says it's global, does this mean that i can use of different files also? like, i defined in define.php and used in anotherfile.php, or shoud the latter file be included then? what about file a.php includes file b.php which in turn includes file c.php. Can functions of a use variables of file c? ultimately: what about variables that are declared global inside a function but this variables is not initialized in that script, like in wordpress: function date_i18n( $dateformatstring, $unixtimestamp = false, $gmt = false ) { global $wp_locale; // more code } $wp_locale can be initialized in another script file? thanks in advance Hi, In all my classes, I need to declare globals for everything else, from site variables even to objects (other classes). I obviously don't want to as globals are horrible and I need to have functions clean without globals. I have included a list of all the global vars in the construct and it still doesn't work. Example: start.php <?php $vars = array(some values); $some = more; $variables = foo; $helper = new Helper(); $home = new Home(); This is a little bit simplistic, but for some reason, the variables just don't want to go in the main class without a global. Functions will not run if they require any of these variables. I have the following code that outputs a url. It searches my MySQL database for the name of a given item within a theme: $relative = 'http://www.domain.com/wp-content/'; $url1= $relative . 'themes/arjuna-x/itemspec.php?type='; $url2='&item='; <a class="entry-thumbnails-link" href="<?php echo $url1.'Themes'.$url2.$rowThemes['Theme']; ?>"> The output is as follows: http://www.domain.com/wp-content/themes/arjuna-x/itemspec.php?type=Themes&item=(insert variable here) All is good up to this point. My problem however, is that some items (in this case: theme names) have apostrophes in them. For example: April Fool's. This results in breaking my php code. How can I get php to call these variables with apostrophes so that they don't break my php? I'm a newbie here and to php and Javascript. So hello all. I am trying to get a portion of a file name passed from one file (first.php) which displays a MySql table. One of the fields is a link that is supposed to open a popup window (second.php) and begin playing a mp3 file with the flash media player. I have everything (almost) working. The table displays as it should, the link is fine. However, I can not get the popup to open with the dimensions I asked for. It opens in a full size new window. And the mp3 will not play. I get the message from the player "we are unable to connect...etc etc". The file name shows up in the status bar and in the URL window. In the file first.php, the table displays, the links appear to be active. when clicked the new window opens, the file names carry over but I can not get the file to play. The player loads (in file second.php) but I get the message from the player "we are unable to connect...etc etc". I suspect it is in the syntax. I have tried so many combinations I can't list them here and so far I have been unable to find anything on google, etc to answer this. After almost three days I have resorted to here. This may not even be the right place for me. Javascript may be my best bet for all I know. Can someone please look over what I have and at least point me in the right direction? Any help is greatly appreciated as this is my first attempt at a website. Thanks first.php Code: [Select] <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> <html> <head> <script language="JavaScript"> <!-- Begin function popUp(URL) { playwindow=window.open(URL, 'name', 'toolbar=0,scrollbars=1,location=1,statusbar=1,menubar=0,resizable=1,width=350,height=250'); } // End --> </script> <script language="JavaScript"> <!-- function openPlayer(URL) { player = window.open('player10.php?','width=350,height=275') } // End --> </script> <?php $username="myusername"; $password="mypassword"; $database="mydb"; mysql_connect('mydb',$username,$password); @mysql_select_db($database) or die( "Unable to select database"); $query="SELECT * FROM mytable"; $result=mysql_query($query); $num=mysql_numrows($result); mysql_close(); ?> </head> <body> <table border="1" cellspacing="2" cellpadding="2"> <tr> <th><font face="Arial, Helvetica, sans-serif">Listen</font></th> <th><font face="Arial, Helvetica, sans-serif">f2</font></th> <th><font face="Arial, Helvetica, sans-serif">f3</font></th> <th><font face="Arial, Helvetica, sans-serif">f4</font></th> <th><font face="Arial, Helvetica, sans-serif">f5</font></th> <th><font face="Arial, Helvetica, sans-serif">f6</font></th> </tr> <?php $i=0; while ($i < $num) { $f1=mysql_result($result,$i,"listen"); $f2=mysql_result($result,$i,"field2"); $f3=mysql_result($result,$i,"field3"); $f4=mysql_result($result,$i,"field4"); $f5=mysql_result($result,$i,"field5"); $f6=mysql_result($result,$i,"field6"); ?> <tr> <td><font face="Arial, Helvetica, sans-serif"><a href="javascript:openPlayer('player10.php?<?php echo $f1?>')">Listen</a></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f2; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f3; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f4; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f5; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f6; ?></font></td> </tr> <?php $i++; } ?> </body> </html> SECOND.PHP Code: [Select] <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8" > <meta http-equiv="X-UA-Compatible" content="IE=8" > <title>My Title </title> <link rel="shortcut icon" type="image/x-icon" href="/favicon.ico" > <script language="JavaScript" type="text/javascript"> <!-- // // Make sure there's some data // if (location.search) { // // Extract the name of the graphics file // var mp3_filename = location.search.substring(1) // // Write the <IMG> tag using the name of the graphics // file (you may need to adjust the SRC text) // document.write('<a href="http://mywebsite.com/+mp3_filename">') } // End --> </script> </head> <body> <object width="400" height="300"> <param name="movie" value="http://fpdownload.adobe.com/strobe/FlashMediaPlayback.swf"> </param> <param name="flashvars" value="src=http%3A%2F%2Fmywebsite.com%2Faudio%2F+mp3_filename"> </param> <param name="allowFullScreen" value="true"> </param> <param name="allowscriptaccess" value="always"> </param> <embed src="http://fpdownload.adobe.com/strobe/FlashMediaPlayback.swf" type="application/x-shockwave-flash" allowscriptaccess="always" allowfullscreen="true" width="400" height="300" flashvars="src=http%3A%2F%2Fmywebsite.com%2Faudio%2F+mp3_filename"> </embed> </object> </body> </html> Hi, I'm trying to pass a variable into a URL and apparently I'm doing it wrong this code is OK Code: [Select] $id = $3; echo '<a href="newPage.php?id=3"></a> If I use Code: [Select] $id = $_GET['id']; echo $id; on the newPage.php, I echo 3 whereas, if I do Code: [Select] $id = $3; echo '<a href="newPage.php?id="'.$id.'"></a> when echo out on the newPage.php it prints out nothing also, in current url look like this: Code: [Select] www.site.com/newPage.php?id= What am I doing wrong? Many thanks I'm creating this URL to pass variables to use from one Page to another:
http://eg10basketbal...Borgman&team=16
My WP site is seeing the first variable but not the second. After some searching I've found this suggestion, but it's not working for me:
function add_query_vars_filter( $vars ) {
$vars[] = "nameFull";
$vars[] = "team";
return $vars;
}
add_filter( 'query_vars', 'add_query_vars_filter' );
I tried putting this in the wp-includes/functions.php file of the, but ended up with a fatal error. I have since added it to my theme's functions.php file. There isn't an error, but it doesn't yield recognition of my second variable.
The code below is a form the gets information from a database and post it into the appropriate field. I am having a problem with the while loop. All the variables before the while loop work just great and echo out how they should. But everything after the while loop does not work. I know it has something to do with the while loop because when I take the while loop out everything works as it should. Can anyone please help me with this? <? $id = $_POST["id"]; $therapy = $_POST["therapy"]; db_connect(); $query=mysql_query("select * from student where student_id = $id") or die ("invalid query"); $row=mysql_fetch_array($query); print "<table width='330' border=0 align='center'> <form method='POST' action='table.php'> <td>*First Name:</td> <td>*Last Name:</td> <tr>"; ?> <td width="157"><input size="23" name="first_name" value="<?php echo "$row[first_name]"; ?>" /></td> <td width="138"><input type="text" size="23" name="surname" value="<?php echo "$row[surname]"; ?>" /></td> </tr> <tr> <td>Level:</td> <td>Therapy:</td> </tr> <tr> <td> <select name="program_level"> <option <?php if ($row[program_level]=='1') echo "selected=yes"; ?> value="1">O&A</option> <option <?php if ($row[program_level]=='2') echo "selected=yes"; ?> value="2">Student</option> <option <?php if ($row[program_level]=='3') echo "selected=yes"; ?> value="3">Supervisor</option> <option <?php if ($row[program_level]=='4') echo "selected=yes"; ?> value="4">Manager</option> <option <?php if ($row[program_level]=='5') echo "selected=yes"; ?> value="5">Director</option> <option <?php if ($row[program_level]=='6') echo "selected=yes"; ?> value="6">Graduate</option> </select> </td> <td> <!-- Auto drop down for therapist names--> <? $query2=mysql_query("select * from therapy_info;"); ?> <select name='therapy'> <? while ($row=mysql_fetch_assoc($query2)){ ?> <option value="<? echo "$row[therapy_name]"; ?>"> <? echo "$row[therapy_name]"; } ?> </option> </select> <!-- End Auto drop down for therapist names--> </td> </tr> <tr> <td>Active:<?php echo "$row[active]"; ?></td> </tr> <tr> <td><select name='active' value='$row[active]'> <option <?php if ($row[active]=='1') echo "selected=yes"; ?> value='1'>Active</option> <option <?php if ($row[active]=='0') echo "selected=yes"; ?> value='0'>Inactive</option> </select> </td> </tr> <?php print "<tr> <td><input type='submit' value='Change' name='button' /></td> <input type='hidden' name='id' value='$id' />"; ?> <input type='hidden' name='$hardcode_session' /> <? print "</tr> </form> </table>"; hai everybody....
1. can any one let me know how to pass a variable from view to controller in CodeIgniter...
2. if possible send me a complete login application...developed by using CodeIgniter....
Thanks & Regards,
Shankaar.
I normally don't work with PHP or rather I'm learning as I go..and this is pretty much my last barrier between completing this project. Anyway here are my two files: http://pastebin.com/aThU3akC - file i want to grab values from and pass to the file below http://pastebin.com/kTYHr99p - file that is suppose to display the values in $transmessage Basically I need the variables defined in the first file to be passed and usable in the second and I'm not sure why I can't |
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