PHP - Adding In Strtotime

Hi, I have a bit of an issue with my application, I didn't notice until today, Sunday... Apparently PHP sees Sunday as the first day of the week, which I cannot fathom where it got hat notion from... but anyway, so I have the following samples of my code:
Code: [Select]
    $mondayoflastweek = date('Y-m-d H:i:s', strtotime('monday last week'));
    $sundayoflastweek = date('Y-m-d 23:59:59', strtotime('sunday last week'));

The crazy and very troublesome thing about the results of that code is that if you run that today, Sunday, it shows today as last week... So therefore, the next bit of code is just as problematic:
Code: [Select]
    $mondayofthisweek = date('Y-m-d H:i:s', strtotime('monday this week'));
    $sundayofthisweek = date('Y-m-d 23:59:59', strtotime('sunday this week'));

As you can imagine, for payroll, this is causing a big problem... My week starts at precisely 12:00 am on Monday and ends at precisely 11:59 pm on Sunday...

Could someone please help me out with this...

Hello!

A user is going to input a date in the form "mm/dd/yyyy".  I'd like to convert this to a time stamp so that I can store it via MySql.  I've heard about the "strtotime" function in PHP but I'm not sure how it can tell that the user 03/04/2011 represents March,4th 2011 and not, say April,3rd 2011 (European version).  Help with the correct syntax for conversion would be greatly appreciated.

Thank you,

Eric

so i have a basic html table and down the left column i have monday,tuesday,wednesday.... sunday.

In the column 2nd from the left, i want to fill it with the current weeks dates, which is really based on the current date. So if today is Jul 29th Friday, then strtotime("last monday") would give me Jul 26th Monday... my issue is "last monday" wont work if today is monday because that will give me 19th of july... and since I technically dont know what day is today i'm not sure how to cleanly work around this without having to use some if statement... if today is monday do "last monday +7 days" or just do "now" etc...

Thanks!

can someone please tell me how to echo the current time or date?  I have the date in the format

1306768978

in the database but I dont want to echo it back that way obviously.   Not only that but does anybody know of a good tutorial on how to use this function?

Good Day,

I'm struggling to get strtotime() to return anything.

I have the following code..
$fields['birth']['day'] = 9;
        $fields['birth']['month'] = 7;
        $fields['birth']['year'] = 1982;
        $dob = $fields['birth']['day'].' '.$fields['birth']['month'].' '.$fields['birth']['year']; // Returns: 9 7 1982
        $dob = strtotime($dob); 
        die($dob);

No matter what I do $dob isn't returning anything once strtotime() is used. I've tried matching my day/month/year 's with examples in the manual on the strtotime() page but using date() on the fields, but it still doesn't want to return anything.

I feel I'm missing something simple here.

Any help is appreciated.

Regards,
Ace

hello,

what am i doing wrong?

Code: [Select]
$starttime=$row['starttime'];
$esttime1=date( 'g:i a', strtotime(-2 hours, $starttime) );

Little confuzzled.

I have got a bunch of listings that will be printed at the end of the page but I need to subtract a time specified in a textbox (send it to itself) on the page.

Code: [Select]
$row['active'] = (strtotime('$row[etd]') + $rwy1 = $_POST['tmatttextfield']);Well this just converts the time in the database which is always going to be a four character number such as: 1300 for 1PM into a time and adds the textbox value to the time.

Code: [Select]
<td width="50" bgcolor="<?php echo $bc?>"><strong><?php echo date('hi', $row['active']);?></strong></td>That just prints it all out formatting the time to only Hours and Minutes.

So just to clarify the user would put in say '10' in the textbox which would constitute 10 minutes.
The code above should then define that '10' as 10 minutes.
Define the database result, ie. 1500 as 3PM and add the 10 minutes to it so it would become 1510.

I have been getting some wierd and wonderful results whilst trying to get it to work. Mainly just 1200 though.

Harry.

Hi!

the following code sucessfully outputs a timestamp.

Code: [Select]
$datealt=strtotime('2012-03-13 ,23:13:00');
The following however does not:

Code: [Select]
$datealt=strtotime('$date ,$hours:$minutes:00');

I have checked if the variables echo out and they do..

any clues much appreciated

x

Hey freaks,

running into a little issue with the use of date and strtotime....

basically I wanna present the date in the format m-d-y to the user and insert it into the DB in the Y-m-d format. 

What seems to be happening is a freaky Y-d-m format and I don't know why this is.  This code is an example that expresses my frustration.

Code: [Select]
$nmon = strtotime("next Monday");
$next = date('m-d-Y', $nmon);
$_SESSION['REPORT_DUE'] = $next;


$nfri = strtotime("Friday");
$due = date('m-d-Y', $nfri);
$_SESSION['WEEK_ENDING'] = $due;
$ses1 = $_SESSION['WEEK_ENDING2'] = date('Y-m-d', strtotime($due));
$ses2 = $_SESSION['WEEK_ENDING3'] = date('d-m-Y', strtotime($ses1));


.....output....

Quote

[WEEK_ENDING] => 09-02-2011 [WEEK_ENDING2] => 2011-02-09 [WEEK_ENDING3] => 09-02-2011 )




Thank you for any assistance.

Hi

I am new to PHP and trying to convert a date from a registration form (in the form 01/01/2011) to Y-m-d so that it can be stored in the database.

This is the code I have, pretty sure it worked before but not it has stopped working! Any ideas?

$dateformat = $_POST['dob'];
$correctformat = date('Y-m-d',strtotime($dateformat));

I have checked what $_POST['dob'] is printing and that is correct, however the $correctformat is printing 1970-01-01 everytime.

Any help would be greatly apreciated.

Thank you

how do I use strtotime() instead of mktime()?

$matchTimea = mktime($mHour, $mMinute, 0, $mMonth, $mDay, $mYear);

if($matchTimea-time() < $cutoffTimea*60)
{

I have this php code:

length is 15 , that is what it is coming out of the database


$length = $get['length'];

$time = date('Y-m-d', strtotime('+$length days'));

But when I echo time it comes out with this result 1969-12-31

What am I doing wrong?

Current time when testing was: 1291064453

I run the following: echo date('m/d/y', strtotime('first day', 1291064453));
Expecting: 11/1/10

What I actually get: 11/30/10

Can anyone explain this?

//
I am trying to calculate the number of days between dates and have a major problem.  When I try the example below, it gives me exactly 201 days, yet the dates have different times, meaning that a full day is impossible.  If it matters, I am testing via xampp 1.7.3 with php version 5.3.1 with Windows XP.  Can anyone explain what I am doing wrong.  Can daylight savings play a role?

        $frmritedate7116    =    strtotime('2010-12-13 23:00');
        $frmritedate7156    =    strtotime('2010-05-27 00:00');
//
        $frmritedate7251    =    $frmritedate7156 - $frmritedate7116;
//
//
1274943600-1292310000=-17366400 // 86400 seconds in a day ( 201.00 )
//
//
//