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PHP - If Statements Keep Running - Stop!!
I have made a script that allows a user to change their email address. It works BUT if the email address they have chosen is already registered the script does not cut off - it continues to the next if statement and changes the email address anyway.
I am trying to put a stop to it using exit() and exit; but it does not work. Any tips? <?php //////////////////// checking new email is not already registered ///////////////// if ($_POST['newemail'] && $_POST['newemail1'] !="") { if ($_POST['newemail'] == $_POST['newemail1']) { $sql2 = "SELECT email FROM Members WHERE email='$_POST[newemail]'"; $result2 = mysqli_query($cxn,$sql) or die ("Couldn't execute query 2"); $num2 = mysqli_num_rows($result2); if ($num2 > 0) { $updateerror = "The email address you have chosen is already registered."; include("my-account.php") exit(); // TRYING TO STOP THE SCRIPT HERE (IF $num2 > 0) exit; } else { echo "You can have this new email address";} } else { echo "Your email addresses do not match. Please try again."; } } else {} // THIS SCRIPT CONTINUES TO CHANGE THE EMAIL ADDRESS DESPITE IT ALREADY BEING REGISTERED. if ($_POST['newemail'] == "") { $newemail = $_POST['currentemail']; } else { $newemail = $_POST['newemail']; } $newemail1 = $_POST['newemail1']; ?> Similar TutorialsHey Guys, I am creating an array and I have a need to put a if statement inside it. Is this even possible? Here is where I am at so far, its just not working. function load_permissions($gid) { $data = array(); $this->db->select('`groups`.`name` AS `permission_name`, `permissions`.``'); $query = $this->db->get('`groups`,`permissions`'); if ($query->num_rows() > 0){ foreach ($query->result_array() as $row){ $data[] = array( "name" => $row['permission_name'], "read" => if($row['level'] >= 1) { img("img/true.gif") } else { img("img/false.gif") }, ); } } $query->free_result(); return $data; Thanks, Peter I am trying to write an if statement that checks to make sure the information put in the text box is an imbedded file. Does anyone know how to do that? Hello, I am learning PDO SQL statements, I have mananged to connect using PDO: Code: [Select] try { $this->link = $dbh = new PDO('mysql:host='.$this->dbhost.';dbname='.$this->dbname.'', $this->dbuser, $this->dbpass); } catch (PDOException $e) { echo 'Connection failed: ' . $e->getMessage(); } I am not getting any error, so I guess that is a good start. I then tried the PDO SQL statement out. My old mySQL query is commented out in the Code: [Select] if (isset($_SESSION['id']) && isset($_SESSION['password'])) { $_SESSION['id'] = ( isset( $_SESSION['id'] ) ) ? $_SESSION['id'] : FALSE; $_SESSION['password'] = ( isset( $_SESSION['password'] ) ) ? $_SESSION['password'] : FALSE; //$logged = mysql_query("SELECT * FROM `db_members` WHERE `id`='".$_SESSION['id']."' AND `password` = '".$_SESSION['password']."'"); //$logged = mysql_fetch_array( $logged ); // the new pdo statement $ff = $dbh->prepare('SELECT * FROM db_members WHERE id = '.$_SESSION['id'].' AND password = '.$_SESSION['password'].''); $ff->execute(); $logged = $ff->fetchAll(); echo $logged['username']; } I am trying to assign the session to logged variable. So all I am asking is go into db_members and check the id and password that is the same as session id and password and collect the rows data such as username. My login script and everything works perfectly, even session id and password is valid when echo'd but I cannot assign it to the logged variable like my old sql statements. Code: [Select] $logged = mysql_query("SELECT * FROM `db_members` WHERE `id`='".$_SESSION['id']."' AND `password` = '".$_SESSION['password']."'"); $logged = mysql_fetch_array( $logged ); I used other PDO statements and it works perfectly but I just don't understand why this is not working.... can I please get some help if you have any solution to this? Anything wrong with this because I got a parse error ONLY after adding to create this. <?php $visible = array('Yes', 'No'); foreach($visible as $visible): $visible2 = array('yes', 'no'); foreach($visible2 as $visible2): ?> The below is constantly loading the password page no matter what is enter in the password input on the form (on another page). I have checked the $login variable by echoing it and it is carrying the value from the field. <?php $off="yes"; $login=$_POST['login']; if($off=="yes" && (!isset($_SESSION['login']) || $_SESSION['login']!="pass")){ if($login=="" || $_SESSION['login']!="pass"){ header('Location: ./index2.html'); exit(); } elseif(!isset($_SESSION['login'])){ session_start(); $_SESSION['login']=$login; header('Location: ./index.php'); exit(); } } elseif($off=="no" || $_SESSION['login']=="pass"){ content goes here. } ?> How to write 2 "if" statements together? if($userResult==$myResult) and ($userResult<0) { Hey guys, is there any way to have a LIKE condition on an IF statement? Something like: Code: [Select] if $GET_['WTV'] LIKE %LOVE% { $category=romance Any clues? Thanks in advance. Hi Guys, Newbie trying to understand PHP conditionals. In the below Code: [Select] [[*id]] is a global variable which equates to my current page id so it could have the value of 1 for example. I tested it using echo and the correct values pass to it in the cms I'm using. What I cant achieve is for the conditionals below to work correctly so perhaps you can see a syntax error or show me away of doing the same using an array or something perhaps? THANKS Code: [Select] <?php $id='[[*id]]' if ($id=="1" || $id=="2") echo "we are in 1 or 2"; elseif ($id=="3" || $id=="4") echo "we are in 3 or 4"; else echo "not in 1 to 4"; ?> Okay i'm trying to compare these sets of variables. code looks like this.. Code: [Select] if( $row->cash > $finalcash && $row->core1 > $finalcore1 && $row->core2 > $finalcore2 && $row->core3 > $finalcore3 && $row->core4 > $finalcore4 ) { return true; } else { return false; } First question is this the appropriate way of doing this? Or would a nested if statement work better? example: Code: [Select] if ($row->cash > $finalcash) { if ($row->core1 > $finalcore1) { if ($row->core2 > $finalcore2) { if ($row->core3 > $finalcore3) { if ($row->core4 > $finalcore4) { } else { return false; } } else { return false; } } else { return false; } } else { return false; } } else { return false; } I know it looks pretty messy, so i'm wondering if anybody is aware of an alternative to achieving this? I need to insert a large variable number of records into a mysql table. I can do this using a while loop and insert queries in the loop but its slow and ive been given to understand its a bad idea. I have heard that I can insert multiple rows with one query, but how to construct the query? This code can perfectly and reliably display a statement with echo: Code: [Select] <?php $querytestquery='"INSERT INTO test(qval1, qval2) VALUES'; echo $querytestquery; $querymax=10; $querystart=0; while ($querystart<$querymax) { $qval1=1*$querystart; $qval2=2*$querystart; $queryadd="($qval1, $qval2)"; echo $queryadd; if ($querystart<$querymax-1) { echo ','; } $querystart++; } echo '"'; ?> "INSERT INTO test(qval1, qval2) VALUES(0, 0),(1, 2),(2, 4),(3, 6),(4, ,(5, 10),(6, 12),(7, 14),(8, 16),(9, 18)" But I don't understand how to set a variable equal to the displayed query so that I can have php construct the statement based on the values and the number of records I want to update or insert. I can't get these two if, elseif and else statements too work, here is the code: if(empty($this->password)){ $this->errors[] = 'You must enter a password!'; } elseif(!strlen($this->password) >= 6){ $this->errors[] = 'Your password must be longer than 6 characters!'; } if(empty($this->email)){ $this->errors[] = 'You must enter an email address!'; } elseif(!preg_match('/^[a-zA-Z0-9._-]+@[a-zA-Z0-9._-]+\.[a-zA-Z]{2,4}$/',$this->email)){ $this->errors[] = 'Your password can only contain these characters: a-z, A-Z and 0-9!'; } if(empty($this->confemail)){ $this->errors[] = 'Please confirm your email address!'; } elseif(!$this->confemail == $this->email){ $this->errors[] = 'The email addresses you entered did not match!'; } The if and elseif statements for "email" work just fine but the other 2 doesn't. With the "password" i first want to check if the field is empty, and when it is, it works as it should. But when i for example type "test" too check if the password is longer than 6 characters i don't get any message at all? With the "confemail" i want to first check if the field is empty, and when it is, it works as it should. But when i type in "test@test.com" in both fields to try to compare "confemail" to "email" i still get the "Please confirm your email address!" message? this is working fine : Code: [Select] while($tags=mysql_fetch_array($d_b->sql_answer,MYSQL_ASSOC)){ echo $tags['tag_name'] . "<br/>"; } display : Code: [Select] html css javascript c++ php but when i try to do some sql statements inside like this : Code: [Select] while($tags=mysql_fetch_array($d_b->sql_answer,MYSQL_ASSOC)){ $sql="SELECT * FROM user WHERE user_languages LIKE '% {$tags[tag_name]} %'"; //to apply the $sql $d_b->apply($sql); //number of results $num=$d_b->num_rows(); $sql="UPDATE tags SET tag_folowers={$num}"; $d_b->apply($sql); } it return an error : Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given Hello: I am writing this code: Code: [Select] <?php include('include/myConn.php'); include('include/myCodeLib.php'); $zip_id = $_REQUEST['zip_id']; $query=mysql_query("SELECT zip_id,city,full_state,zip FROM zip_codes WHERE zip_id = $zip_id") or die("Could not get data from db: ".mysql_error()); while($result=mysql_fetch_array($query)) { $zip_id=$result['zip_id']; $city=$result['city']; $full_state=$result['full_state']; $zip=$result['zip']; } ?> <!DOCTYPE HTML> <head> <title></title> </head> <body> <?php echo $city; ?>, <?php echo $full_state; ?> <?php echo $zip; ?> </body> </html> It works fine as far as writing out the "City, State Zipcode", but I wanted to see if there is a way to "join" the 3 statements together so it can be written as just 1 statement. Like: Code: [Select] <?php echo $city, $full_state $zip; ?> What is the trick to doing this? Thanks in advance. I have a general dbInsert class method that accepts three arguments: table, fields, and values - the last two each as an array. I am using a PDO connection and prepared statements to sanitize everything. I am having a problem with the bindParam() function accepting the parameter ID's though... here's my code and the result I am getting, any advice? My arguments: $this->_table = "testdata"; $this->_fields = array('product_id', 'store_id', 'description', 'price', 'colors', 'sizes'); $this->_values = array("20002157", "2005", "Kids polo shirt", "12.59", "White", "Large"); My object: $_crud = new Crud(); $_makeCrud = $_crud->dbInsert($this->_table, $this->_fields, $this->_values); My class: public function dbInsert($table, $fields, $values) { $_table = $table; $_fields = implode(", ", $fields); // Create and format the list of insert values $_values = ""; // replaces values with "?" placeholders foreach ($values as $value) { $_values .= "?" . ", "; } // trims off last comma and space $_values = substr($_values, 0, -2); // checks database connection if (isset($this->_dbh)) { // Create the SQL Query $this->_sql = 'INSERT INTO ' . $_table . ' (' . $_fields . ') VALUES (' . $_values . ')'; // Build the query transaction $this->_dbh->beginTransaction(); // Build the prepared statement $this->_stmt = $this->_dbh->prepare($this->_sql); // Bind the parameters to their properties foreach ($values as $key => $val) { // starts $key at 1 $key = (int) $key + 1; $this->_stmt->bindParam($key, $val); } // Execute the query $this->_stmt->execute(); $this->_affectedRows = $this->_stmt->rowCount(); } } What my new table row should look like: Code: [Select] product_id store_id description price colors sizes ---------------------------------------------------------------------------------------------- 20002157 2005 kids polo shirt 12.59 white large But this is what my new row DOES look like: Code: [Select] product_id store_id description price colors sizes ---------------------------------------------------------------------------------------------- Large 0 Large 0.00 Large Large So it's taking the value of that last $value and inserting it in all the fields, the store_id and price are 0 and 0.00 because of their numeric type... I assume it is a syntax error, missing quotes somewhere, but where? Hi, What is a shorter way instead of having all these if statements? Here it is: Code: [Select] if($matchno==1) return 66; elseif($matchno==2) return 67; elseif($matchno==3) return 68; elseif($matchno==4) return 69; elseif($matchno==5) return 70; elseif($matchno==6) return 71; elseif($matchno==7) return 72; elseif($matchno==8) return 73; elseif($matchno==9) return 74; elseif($matchno==10) return 75; elseif($matchno==11) return 76; elseif($matchno==12) return 77; elseif($matchno==13) return 78; elseif($matchno==14) return 79; elseif($matchno==15) return 80; elseif($matchno==16) return 81; elseif($matchno==17) return 82; elseif($matchno==18) return 83; elseif($matchno==19) return 84; elseif($matchno==20) return 85; elseif($matchno==21) return 86; elseif($matchno==22) return 87; elseif($matchno==23) return 88; elseif($matchno==24) return 89; elseif($matchno==25) return 90; elseif($matchno==26) return 91; elseif($matchno==27) return 92; elseif($matchno==28) return 93; elseif($matchno==29) return 94; elseif($matchno==30) return 95; elseif($matchno==31) return 96; elseif($matchno==32) return 97; someone please code shorter? I will learn this way. Thanks. If my SQL statement returns a result I want to change the background color of a cell. If the user is logged in I want to then show one of two buttons. either book, or cancel, depending on whether the cell is available or not. So far I have this: $sql = "SELECT * FROM diary WHERE day = '$mon' AND studio_id ='mon11'"; $query = mysql_query($sql) or die (mysql_error()); if (mysql_num_rows($query) < 1) { $bgcolour= '#5DFC0A'; if(isSet($_SESSION['logged'])) { $book = '<form action="../book.php" method="POST"><input type="hidden" name="day" value='.$mon.' type="text"/><input type="hidden" name="month" value='.$month.' type="text"/><input type="hidden" name="year" value='.$year.' type="text"/><input type="hidden" name="book_id" value="mon11" type="text"/><input type="submit" name="submit" value="Book!"></form>'; }} else { $bgcolour= '#FF0000'; } if(isSet($_SESSION['logged'])) { $book = '<form action="../cancel.php" method="POST"><input type="hidden" name="day" value='.$mon.' type="text"/><input type="hidden" name="month" value='.$month.' type="text"/><input type="hidden" name="year" value='.$year.' type="text"/><input type="hidden" name="book_id" value="mon11" type="text"/><input type="submit" name="submit" value="Cancel!"></form>'; } echo "<td rowspan='3' bgcolor=".$bgcolour.">"; if (isset($book)) { echo $book; } I want to use the $session(logged) variable to show the appropriate button, but I can't get it to work in the other if statement, Any ideas? I always have trouble reading shorthand statements, as i am used to always using brackets. So when i view someones code and they use shorthand, i get confused. Can i get a clear explanation on the example below:
if ( have_posts() ) : while ( have_posts() ) : the_post(); the_content(); endwhile; else: echo "<p>Sorry, no posts matched your criteria.</p>"; endif;I've always been accustomed to using brackets, so i have trouble understanding the above quickly. How could I make it so that if the $date variable is past than $memberdate then something shows else something else does. <?php $date = date('Y-m-d H:i:s', time()-3600); $memberdate = '2011-01-29 01:03:28'; ?> Thanks in advance, I realised I could convert it into a unix timestamp but there must be a better way. Ty. Hey everyone, i am currently working on a "contact us" script. I want the form to first allow the user which department they want to email. E.g. "Sales" and "Support" By changing this drop down box it will change which email the form is sent to. Im having trouble setting the PHP side of this script up to change the emails. Any help regarding this matter is much appreciated. HTML FORM: Code: [Select] <form name="contactForm" method="post" action="forms/contactUs.php"> <table width="350" border="0"> <tr> <td width="150" class="bold">Department:</td> <td width="200" align="left"> <select name="department" class="dropDown"> <option value="sales">Sales</option> <option value="support">Support</option> </select> </td> </tr> <tr> <td class="bold">Full Name:</td> <td> <input name="name" type="text" class="contactTextBox" /> </td> </tr> <tr> <td class="bold">Company:</td> <td> <input name="company" type="text" class="contactTextBox" /> </td> </tr> <tr> <td class="bold">Email:</td> <td> <input name="email" type="text" class="contactTextBox" /> </td> </tr> <tr> <td class="bold">Comments:</td> <td> <textarea name="com" id="com" cols="5" rows="5" class="contactTextArea" /></textarea> </td> </tr> <tr> <td> </td> <td align="right"> <input type="submit" class="button" value="Submit" /> <input type="reset" class="button" value="Reset" /> </td> </tr> </table> </form>PHP <?php $department = $_POST['department']; $confirm = "sales"; if(isset($_POST['email'])) { if($department == $confirm) { $email_to = "sales@pixemadesigns.com"; $email_subject = "Sales Question"; } else { $email_to = "support@pixemadesigns.com"; $email_subject = "Support Question"; } $fullName = $_POST['name']; $company = $_POST['company']; $email_from = $_POST['email']; $comments = $_POST['com']; $email_message = "Form details below.\n\n"; function clean_string($string) { $bad = array("content-type","bcc:","to:","cc:","href"); return str_replace($bad,"",$string); } $email_message .= "Full Name: ".clean_string($fullName)."\n"; $email_message .= "Company: ".clean_string($company)."\n"; $email_message .= "Email: ".clean_string($email_from)."\n"; $email_message .= "Comments: ".clean_string($comments)."\n"; // create email headers $headers = 'From: '.$email_from."\r\n". 'Reply-To: '.$email_from."\r\n" . 'X-Mailer: PHP/' . phpversion(); @mail($email_to, $email_subject, $email_message, $headers); header("location: ../contactSubmit.html"); ?> <? } ?> I'm sure you can do this in PHP, but for some reason when I view news.php - It automatically tells me I liked the post, when I haven't even clicked like yet! while($fetch = mysql_fetch_assoc($query)) { if($_GET['like'] == $fetch['id']) { $like = mysql_real_escape_string($_GET['like']); $has_liked = mysql_query("SELECT * FROM likes WHERE id = '$like' AND username = '". $_SESSION['user'] ."'"); if(mysql_num_rows($has_liked) > 0) { echo " <div id='post-1' class='post'> <h2 class='title'><font color='white'>#". $i." ".$fetch['title'] ."</font> <h3 class='date'>". $fetch['date'] ."</h3> <div class='entry'> <p>". nl2br(stripslashes($fetch['content'])) ."</p> </div> <p class='meta'><b>You've already liked this announcement.</b></p> </div> "; } else { mysql_query("UPDATE news SET likes = likes + 1 WHERE id = '". $_GET['id'] ."'"); echo " <div id='post-1' class='post'> <h2 class='title'><font color='white'>#". $i." ".$fetch['title'] ."</font> <h3 class='date'>". $fetch['date'] ."</h3> <div class='entry'> <p>". nl2br(stripslashes($fetch['content'])) ."</p> </div> <p class='meta'><b>You liked this announcement.</b></p> </div> "; } } else { echo " <div id='post-1' class='post'> <h2 class='title'><font color='white'>#". $i." ".$fetch['title'] ."</font> <h3 class='date'>". $fetch['date'] ."</h3> <div class='entry'> <p>". nl2br(stripslashes($fetch['content'])) ."</p> </div> <p class='meta'><a href='news.php?like=". $fetch['id'] ."'>Like</a></p> </div> "; } } |
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