PHP - Edit Form Using Dropdown/radio Button.

ok i want admin to click on the edit button and a form shows up where you can edit your events and stuff like that but i cant get the edit button to work


Code: [Select]
<?php

require 'scripts/connect.php';

     echo "
       <table width='472' border='0'>
       <tr>
       <th width='43' height='21' scope='col'>Event Id</th>
       <th width='116' scope='col'>Event Nane</th>
       <th width='106' scope='col'>Event Type</th>
       <th width='63' scope='col'>EDIT</th>
       <th width='63' scope='col'>DELETE</th>
       </tr>
       </table>";



$sqlCommand = "SELECT * FROM events"; 

$out = mysql_query($sqlCommand);

while ($row = mysql_fetch_assoc($out)){

  $eventid = $row["id"];
  $eventname = $row["eventname"];
  $eventtype = $row["typeevent"];
  $eventinfo = $row["eventinfo"];
  $date = $row["date"];
  $time = $row["time"];
  $livetickets = $row["sale"];
  $numtickets = $row["numtickets"];
  $pricestudents = $row["studentsprice"];
  $priceseniors = $row["seniorsprice"];
  $priceadults = $row["adultsprice"];

if ($_POST['editbtn']){

echo "<form action='editevent' method='post'>
      <table>
      <tr>
      <td>Event Name</td>
      <td></td> 
      <tr>
      <tr>
      <td></td>
      <td></td> 
      <tr>
      <tr>
      <td></td>
      <td></td> 
      <tr> 
</table>
</form>
";
}else 
       echo"
        <table width='472' border='0'>
        <tr><form action='editevent.php' method='post'>
        <th width='59' height='21' scope='col'>$eventid</th>
        <th width='159' scope='col'>$eventname</th>
        <th width='151' scope='col'>$eventtype</th>
        <th width='85' scope='col'><input type='button' name='editbtn' value='Edit' /></th>
        <th width='85' scope='col'><input type='button' name='deletebtn' value='Delete' /></th>
        </form></tr>
        </table>";

}

?>

I made a table that gets the rows from a mysql table and lists them with the information on each row. What i need is an edit button at the end of the row so i can click it to change the data. What i want it to do is pop up a new window (child) that i can easily change the data by a text box, drop down menu, etc. and click submit to update it on the table. What i also need is a second button that will completely remove the data from that row in the table. I am still learning php and html and have no knowledge of javascript so any help would be appreciated!

I have a function to display some images and allow a user to select a choice via a radio button.The value is then passed to another function.
I have 2 problems
My selection is not being passed back and I cant assign the value to a query sring in a link to another page.
On the form do i need to add checked?
Any help appreciated.

Code: [Select]
function cover() {

            echo'<h2>Please upload your book cover or choose one from the selection</h2>
                <p>All book ideas require a cover. Your choice can be changed at a later date.</p>';


            //process selection of cover
            if (isset($_POST['submit'])) {
                $coverID=$_POST['cover'];
                echo $coverID;
                 ?> &nbsp

                <ul><li class="demo-menu-link"><a href="?page=submenu7&coverID=$coverID">Finnished Cover</a></li></ul><?php
                exit();
            }
            else{
                echo "not Submitted";
            }


            global $wpdb;
            $query = "select * from wp_cover";
            $result = mysql_query($query) or trigger_error("Query: $query\n<br />MySQL Error: " . mysql_error());
            echo mysql_error();

            if (!$result){
                return false;
            }
            
            echo'<div class="wrap"><p>choose from one of the covers below</p></div>';

            ?><form action="<?php $_SERVER['PHP_SELF'] ?>" method="POST" id="cover" enctype="multipart/form-data">
            <table><tr><?php
            /* display picture and radio button */

            while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) {
                
               $coverID=$row['coverID'];
                echo"<img src=\"/wordpress_3/wp-content/plugins/Authors2/jackets/{$row['pix']}\" />";
                echo"<td>";
                echo $coverID;
                echo "<Input type = 'Radio' Name ='cover' value= '$coverID'/>";
                ?>
                </tr></table>
                <input type=submit value=submit>
                </form><?php
                }
          }

I am trying to have the text alongside the radio button trigger the radio button (cannot use < a href )


e.g. () Trigger with this text

The closest I have found is
 <label for="r1"><input type="radio" name="group1" id="r1" value="1" /> button one</label>

But it does not seem to work?

Any help greatly appreciated

What am I doing wrong with this selected radio button?

<form action="Process/privacy.php" method="post" enctype="multipart/form-data" id="privacy">
<div id="privacy_vis">Your profile is visible to:</div>

<div id="privacy_select">
    <label>
      <input name="RadioGroup1" type="radio" id="RadioGroup1_0" value="1" <?if($visible=="1")echo 'checked="checked"';?> />
      Everyone</label>

    <label>
      <input name="RadioGroup1" type="radio" id="RadioGroup1_1" value="0"/>
      Members Only</label>
</div>
<br />
<div id="privacy_vis">Your Password to view your private pictures is:</div>
<div>
<input name="pictures_pw" type="text" id="pictures_pw" value="<? echo "$xxx_pw" ?>" size="50" maxlength="20" />

</div>


<br />

<div>
<input name="submit" type="submit" class="button" id="submit" value="Save Changes" />
</div>


</form>
</div>

Hello,
I had 3 radio buttons with the same name, well, I had created 3 text box that are next to those 3 radio buttons.
When I click save to the form, I need to know which radio button had been pressed, so that I can detect & retrieve its value.
Any help?
Thanks

i would like to display the value of the selected radio button on the same page... what i want is just reload the page and if there is a radio button selected displays it but i cant display it

<?PHP

if (isset($_GET["submit"])) {
echo $_GET["myradio"];
}

?>

<html>
<head>
</head>
<body>
<form action="<?PHP $_SERVER["PHP_SELF"]; ?>" method="get">
One <input type="radio" name="myradio" value="one">
Two <input type="radio" name="myradio" value="two">
<a href="<?PHP $_SERVER["PHP_SELF"]; ?>" name="submit">test </a>

</form>
</body>
</html>



please help guys...thanks

Good Day,

I juz like to know if there any other alternative way for the code below, coz i can't update my form when i use this method for radio the button. It's not passing the value.

Code: [Select]

Edit.php

  <tr>
            <td height="36" align="center" valign="middle" bgcolor="#990000"><div align="left" class="style4">Destroy :</div></td>
            <td align="center" valign="middle" bgcolor="#990000"><div align="left">
              <label>
              <input type=radio name=destroyR value="Yes" <?php echo ($rows['destroy']=='Yes') ?'checked="checked"':''; ?> />Yes</label>
             
              <label>
              <input type=radio name=destroyR value="No" <?php echo ($rows['destroy']=='No') ?'checked="checked"':''; ?> />No</span></label>
             </div></td>
          </tr>

how do you make it so that a radio button is either checked or unchecked based on database?

I have a group of 4 radio buttons. my mysql database knows which one the user selected previously when they stored some information. I now wish to display the same buttons but have radio button checked that the user chose before. I know this can be done but having one of those mind melt moments where I cannot think of the solution

so I have 4 buttons that look like this

Code: [Select]
        <input type="radio" name="clarity" id="clarity" value="Opaque">
      Opaque<br>
      <input type="radio" name="clarity" id="clarity" value="Deep">
      Deep<br>
      <input type="radio" name="clarity" id="clarity" value="Mid">
      Mid<br>
      <input type="radio" name="clarity" id="clarity" value="Pale">
      Pale<br></td>

I just need to attached a checked field to the correct item

I am trying to make a set of radio buttons that when you make a selection, it displays a sorted database from MYSQL.  I have the MYSQL part figured out but I cannot figure out how to properly display it.

I have the following code and I made a select screen just to test:

index.html
<html>
<body>

<form action="select.php" method="post">

<input type="radio" name="table" value="table1"> Table 1
<br>
<br>

<input type="radio" name="table" value="table2">Table 2
<br>
<br>

<input type="radio" name="table" value="table3">Table 3
<br>
<br>

<input type="radio" name="table" value="table4">Table 4
<br>
<br>

<input type="radio" name="table" value="table5">Table 5
<br>
<br>

<input type="Submit" Name = "submit" value="Submit">
<input type="Reset" value="Reset">

</form>
</body></html>


select.php
<?PHP

$selected_radio = $_POST["table"];

if ($selected_radio = = 'table1) {
echo "Table 1 Here.";
}
else if ($selected_radio = = 'table2') {
echo "Table 2 Here.";
}
else if ($selected_radio = = 'table3') {
echo "Table 3 Here.";
}
else if ($selected_radio = = 'table4') {
echo "Table 4 Here.";
}
else if ($selected_radio = = 'table5') {
echo "Table 5 Here.";
}

?>
These are two separate files.  When I go to run the code, no matter what I pick, the next page is always blank.  Again, the select.php is just suppose to be a check, the real code will display the table instead of echoing a message.

This topic has been moved to HTML Help.

http://www.phpfreaks.com/forums/index.php?topic=317717.0

Hi,

I have 2 radio button's within a table and need to pass this array.

All other rows within my table can be sent as array's and captured using $_POST['field_name'][$ROW 1 value etc].

However for radio buttons this doesn't work.

As an example, a standard textbox I can send an array using the following:

 echo "<td width='33%'><input type='Textbox' width='100%' id='test' name='test[]' value='" .$row['test']. "'></td>";
 
I can then capture it using:

$test = $_POST['test'][$iLine];

This works, no problem, however for radio buttons, I can't use a static array name, as presumably it dumps all rows into the array, if I do this, only the last row has a checked button, hence I need to use the following (where $checked includes the logic to decide whether the button should be checked or not, this works correctly):

echo "<input type='radio' name='".$row['venue_id']."[]' value='1'".$checked."/>P1"
echo "<input type='radio' name='".$row['venue_id']."[]' value='0'".$checked2." />P2";

I tried using the following:

var_dump($_POST[$row]['game_id'][$iLine]);

But this just returns a null value.

Any ideas?

This topic has been moved to JavaScript Help.

http://www.phpfreaks.com/forums/index.php?topic=346803.0