|
PHP - Moved: Mysql Query - Order By Count
This topic has been moved to MySQL Help.
http://www.phpfreaks.com/forums/index.php?topic=312690.0 Similar TutorialsThis topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=330871.0 This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=332593.0 Hello there, i'm not sure if this goes to mysql, or this section, but since it's PHP based, i would say here. So, here's the thing, i have full set up table that reads from mysql database and display it as table. Everything is working just fine, even "order" buttons that i made, now i would like to have below the table some counts, for example: My table name "canonkickoff" has column named "Prevoz" which contain only Yes and No answers, i would like to see below the table how much "Yes" answers are inside the column. Also i have other column called "VelicinaMajice", which contain 6 different answers ( XS, S, M, L, XL, XXL ), i would like to see (again, below the table) how much of every has been answered. Like: There a XS = 6 S = 1 M = 2 L = 3 And 32 answered with Yes. Could anyone help me out? Here's the full php table: <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> <html> <head> <title>CanonKickOff 2012 Tabela.</title> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1"> <link rel="stylesheet" href="table.css" type="text/css"> </head> <body style="margin: 0 0 0 0;"> <? include("passwd.php"); @$start = $_GET["start"]; if($start =='') $start =0; include("lib.php"); $link = mysql_connect($host,$username,$password); if (!$link) { die('Could not connect: ' . mysql_error()); } $db_selected = mysql_select_db($db, $link); if (!$db_selected) { die ("Can't use $db : " . mysql_error()); } //total number of records in the table $orderBy = array('Kompanija', 'id', 'ImePrezime', 'Email', 'Prevoz', 'VelicinaMajice', 'SlazemSe'); $order = 'id'; if (isset($_GET['orderBy']) && in_array($_GET['orderBy'], $orderBy)) { $order = $_GET['orderBy']; } $res = mysql_query("SELECT * from `$table` ORDER BY '.$order"); $res2 = mysql_query("SELECT * from `$table` "); @$rows = mysql_num_rows ($res2); $result = mysql_query("SELECT * from `$table` ORDER BY $order limit $start,40"); if (!$result) { die('Invalid query: ' . mysql_error()); } echo 'Sortiraj Po: <br>'; echo '<a href="?orderBy=id">ID:</a> '; echo '<a href="?orderBy=ImePrezime">Ime i Prezime:</a> '; echo '<a href="?orderBy=Kompanija">Kompanija:</a> '; echo '<a href="?orderBy=email">Email adresi:</a> '; echo '<a href="?orderBy=Prevoz">Prevoz:</a> '; echo '<a href="?orderBy=VelicinaMajice">Velicina majice:</a> '; echo '<a href="?orderBy=SlazemSe">Slazu se:</a> '; echo "<p align=center class = 'menu'> Ocitana tabela: $table </p>"; $cols = mysql_num_fields($result); $records = mysql_num_rows ($result); echo "<table align='center' width='1200' >"; echo "<tr bgcolor='BBCCDD' class='menu'>"; for ($i = 0; $i < $cols;$i++) { echo "<td align='center'>".mysql_field_name($result,$i)."</td>"; } echo "</tr>"; while ($row = mysql_fetch_array($result, MYSQL_NUM)) { echo "<tr bgcolor='F6F6F6' class='normal'>"; foreach ($row as $value) { echo "<td align='center'>".$value ."</td>"; } echo "</tr>"; } $end = $start + $records; echo "<tr align = 'center' bgcolor = 'BBCCDD' class='menu'><td colspan=$cols> $start do $end od ukupno: $rows </td></tr>"; echo "<tr align = 'center' class='mylink'><td colspan=$cols> "; if($start != 0) { $prev = $start - 40; echo "<a href='tabela.php?start=$prev'> Prethodna </a> "; } if($start<$rows-10) { $next = $start + 40; echo "<a href = 'tabela.php?start=$next'>Sledeca</a> "; } echo "</td></tr>"; echo "</table>"; ?> </body> </html> I am loading notifications from a database table called "notifications" and I am having a little trouble getting them to order in the correct way. my query I'm using right now: Code: [Select] $query = mysql_query("SELECT B.* FROM (SELECT A.* FROM notifications A WHERE A.user_id='$session' AND A.from_id!='$session' ORDER BY A.id ASC ) AS B ORDER BY B.state ASC LIMIT 7"); this works well as far as showing the unread notifications on top, then the read notifications below, however it's not ordering the two sets by ID (which the id auto increments so the higher id number is the newest) from newest on top to the oldest on bottom, still keeping them separated by the unread on top, read on bottom (column name is state for showing whether they're read or not). The order the notifications are displaying by their ID is: 3 5 2 4 1 when it should be: 5 3 2 4 1 I insert data in mysql table row using multiple method : 1#2#3 . 1 is ID of country, 2 is Id of state, 3 is ID of town . now i have this table for real estate listings. for each list(home) i have country/state/town (1#2#3). in country table i have list of country - in country table i have list of state - in country table i have list of town. i need to The number of houses in country / state / town . my mean is : Code: [Select] USA [ 13 ] <!-- This Is equal of alabama+alaska+arizona --> ----Alabama [8] <!-- This Is equal of Adamsville+Addison+Akron --> -------Adamsville [2] -------Addison[5] -------Akron[1] ......(list of other City) ----Alaska [ 3 ] -------Avondale[3] ......(list of other City) ----Arizona [ 2 ] -------College[2] ......(list of other City) Lisintg Table : Code: [Select] ID -- NAME -- LOCATION -- DATEJOIN -- ACTIVE 1 -- TEST -- 1#2#3 -- 20110101 -- 1 2 -- TEST1 -- 1#2#3 -- 20110101 -- 1 3 -- TEST2 -- 1#3#5 -- 20110101 -- 1 4 -- TEST3 -- 1#7#6 -- 20110101 -- 1 Country Table : Code: [Select] id -- name 1 -- USA stats Table : Code: [Select] id -- countryid -- name 1 -- 1 -- albama 2 -- 1 -- alaska 3 -- 1 -- akron town Table : Code: [Select] id -- countryid -- statsid -- name 1 -- 1 -- 1 -- adamsville 2 -- 1 -- 1 -- addison 3 -- 1 -- 1 -- akron Thanks For Any Help. This topic has been moved to PHP Applications. http://www.phpfreaks.com/forums/index.php?topic=344992.0 This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=347726.0 This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=321929.0 This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=320026.0 This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=349226.0 This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=345631.0 This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=321906.0 This topic has been moved to Third Party PHP Scripts. http://www.phpfreaks.com/forums/index.php?topic=328623.0 This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=325846.0 Hi guys, I need your help. I am trying to insert the rows in the mysql database as I input the values in the url bar which it would be like this: Code: [Select] www.mysite.com/testupdate.php?user=tester&pass=test&user1=tester&email=me@shitmail.com&ip=myisp However i have got a error which i don't know how to fix it. Error: Column count doesn't match value count at row 1 <?php session_start(); define('DB_HOST', 'localhost'); define('DB_USER', 'mydbusername'); define('DB_PASSWORD', 'mydbpassword'); define('DB_DATABASE', 'mydbname'); $errmsg_arr = array(); $errflag = false; $link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD); if(!$link) { die('Failed to connect to server: ' . mysql_error()); } $db = mysql_select_db(DB_DATABASE); if(!$db) { die("Unable to select database"); } function clean($var){ return mysql_real_escape_string(strip_tags($var)); } $username = clean($_GET['user']); $password = clean($_GET['pass']); $adduser = clean($_GET['user1']); $email = clean($_GET['email']); $IP = clean($_GET['ip']); if($username == '') { $errmsg_arr[] = 'username is missing'; $errflag = true; } if($password == '') { $errmsg_arr[] = 'PASSWORD is missing'; $errflag = true; } if($errflag) { $_SESSION['ERRMSG_ARR'] = $errmsg_arr; echo implode('<br />',$errmsg_arr); } else { $sql = "INSERT INTO `members` (`username`,`email`,`IP`) VALUES ('$adduser','$email','$IP')"; if (!mysql_query($sql,$link)) { die('Error: ' . mysql_error()); } echo "The information have been updated."; } ?> Here's the name of the columns i have got in my database: Code: [Select] username IP I have input the correct columns names, so I can't correct the problem I am getting. Please can you help? This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=331562.0 This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=358872.0 This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=315161.0 This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=328677.0 This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=348309.0 |
|||||||