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PHP - Random Image
Im Am Trying To Display A Random Image Every Time The Page Refreshs
i dont know if this will help??? <?php /* User Pets (user_pets.php) */ $rank_check = 1; $page_title = "User Pets"; include "header.inc.php"; print $openHTML; $array = fetch("SELECT * FROM user_pets2 WHERE id = '$id' AND game = '$game'"); if (!$array[id]) { die("<p align=center class=error>That is not a real pet</p>$closeHTML"); } if ($array[pet_desc]) { $petNote = "<tr><td colspan=2><p align=center><font size=-1><i>$array[pet_desc]</i></font></p></td></tr>"; } print "<center><table>$petNote<tr> <td width=200> "; $id = $array[id]; $getPet = fetch("SELECT * FROM pets2 WHERE id = '$array[species]' AND game = '$game'"); $getOwner = fetch("SELECT display_name,username FROM members2 WHERE id = '$array[owner]' AND game = '$game'"); $image = "pet_$getPet[id]"; if ($array[wearing] != 0) { $findLook = fetch("SELECT * FROM pet_looks WHERE change_from = '$array[species]' AND item_name = '$array[wearing]'"); if ($findLook[id]) { $image = "pet2_$findLook[id]"; } } $hunger = $array[$hunger]; $hungerLevel = $hungerArray[$hunger]; if (($array[hunger] > 10) OR ($array[hunger] < 0)) { $hungerLevel = "Unknown ($array[hunger])"; } $percentHealth = ($array[current_hp] / $array[max_hp]) * 100; if ($percentHealth > 0) { $healthLine = "<font color=red>$array[current_hp]/$array[max_hp]</font>"; } if ($percentHealth > 35) { $healthLine = "<font color=orange>$array[current_hp]/$array[max_hp]</font>"; } if ($percentHealth > 75) { $healthLine = "<font color=green>$array[current_hp]/$array[max_hp]</font>"; } ECHO <<<END <br> <CENTER><TABLE BGCOLOR="#$tableOutline" CELLSPACING=1 CELLPADDING=0 WIDTH=400> <tr> <td colspan=2 bgcolor=#$topAndBottomBG><font color=#$topAndBottomText><b>View Pet:</b></font></td></tr> <TR> <TD BGCOLOR=#$middleBG> <p> <font size=-1> Name: $array[name]<br> Level: $array[level]<br> Experience: $array[experience]<br> Next Level: $nextLevel[$id]<br> Health: <b>$healthLine</b><br> Strength: $array[strength]<br> Intelligence: $array[intelligence]<br> Speed: $array[speed]<br> Defense: $array[defense]<br> Hunger: $hungerLevel<Br> </font> </p> <p> <font size=-1> 1-Player Wins: $array[one_p_wins]<br> 1-Player Loses: $array[one_p_loses] </font> </p> </TD> <TD WIDTH=175 BGCOLOR=#FFFFFF> <p align=center> <img src=$base_url/images/user_images/opg_$game/pets/$image.gif border=1> <br><a href=view_pet.php?id=$array[id]&game=$game><b>$array[name]</b> the $getPet[name]!$petNote[$id]</a></P> <p align=center>$attitude[$id]</p> </TD> </TR> </TABLE> </CENTER> <p align=center><a href=user_profile.php?game=$game&user=$getOwner[username]>Back to $getOwner[display_name]'s Profile!</a></p> END; print "$closeHTML"; ?> Please Help Me Jackthumper Similar TutorialsHi Everyone, I was wondering if anyone could help me make this code I wrote better and a bit more readable and shorter. I have 8 images on the home page so the php code is like this: Code: [Select] <?php $images = array('image1', '8', 'image2', 'image7', 'image5', 'image4', '9', 'image6'); $i = rand(0, count($images)-1); $selectedImage1 = "_images/showreel/{$images[$i]}.jpg"; ?> <?php $images = array('image1', '8', 'image2', 'image7', 'image5', 'image4', '9', 'image6'); $i = rand(0, count($images)-1); $selectedImage2 = "_images/showreel/{$images[$i]}.jpg"; ?> <?php $images = array('image1', '8', 'image2', 'image7', 'image5', 'image4', '9', 'image6'); $i = rand(0, count($images)-1); $selectedImage3 = "_images/showreel/{$images[$i]}.jpg"; ?> <?php $images = array('image1', '8', 'image2', 'image7', 'image5', 'image4', '9', 'image6'); $i = rand(0, count($images)-1); $selectedImage4 = "_images/showreel/{$images[$i]}.jpg"; ?> <?php $images = array('image1', '8', 'image2', 'image7', 'image5', 'image4', '9', 'image6'); $i = rand(0, count($images)-1); $selectedImage5 = "_images/showreel/{$images[$i]}.jpg"; ?> <?php $images = array('image1', '8', 'image2', 'image7', 'image5', 'image4', '9', 'image6'); $i = rand(0, count($images)-1); $selectedImage6 = "_images/showreel/{$images[$i]}.jpg"; ?> <?php $images = array('image1', '8', 'image2', 'image7', 'image5', 'image4', '9', 'image6'); $i = rand(0, count($images)-1); $selectedImage7 = "_images/showreel/{$images[$i]}.jpg"; ?> <?php $images = array('image1', '8', 'image2', 'image7', 'image5', 'image4', '9', 'image6'); $i = rand(0, count($images)-1); $selectedImage8 = "_images/showreel/{$images[$i]}.jpg"; ?> And the HTML is like this: Code: [Select] <div id="slider1" class="nivoSlider"> <img src="<?php echo $selectedImage1; ?>" alt="John Richard Cleckheaton West Yorkshire" /> <img src="<?php echo $selectedImage2; ?>" alt="John Richard Cleckheaton West Yorkshire" /> <img src="<?php echo $selectedImage3; ?>" alt="John Richard Cleckheaton West Yorkshire" /> <img src="<?php echo $selectedImage4; ?>" alt="John Richard Cleckheaton West Yorkshire" /> <img src="<?php echo $selectedImage5; ?>" alt="John Richard Cleckheaton West Yorkshire" /> <img src="<?php echo $selectedImage6; ?>" alt="John Richard Cleckheaton West Yorkshire" /> <img src="<?php echo $selectedImage7; ?>" alt="John Richard Cleckheaton West Yorkshire" /> <img src="<?php echo $selectedImage8; ?>" alt="John Richard Cleckheaton West Yorkshire" /> </div> I no this code is terrible but I am still learning. Just a few months ago I had never touched PHP. Any help would be greatly appreciated. Regards Barry The purpose of this function is to go to the characters table and grab all of the characters that have a statusID of one however I want it to limit it to any ONE of those characters as this is a random image it's going to show and then I want it to have that charactes shortName and then use it to find their spotlight image from inside of the images/spotlight folder. All its showing right now in its spot is the the filename of the image when I call this function. function spotlight(){ $query = "SELECT * FROM characters WHERE characters.statusID = 1 LIMIT 1"; $result = mysql_query($query); $row = mysql_fetch_assoc($result); $labels = array('shortName'); $img = array(); if($handle = opendir('images/spotlight/')) { $count = 0; while (false !== ($file = readdir($handle))) { if(strlen($file) > 2){ $img[$count] = $file; $count++; } } } echo $img[rand(0, (count($img)-1))]; } This is going to be tricky for everyone but here is goes. I have a random image function however I want the image attatched to a link that will go to the person's bio page. Even if I query anything how can I make sure that it matches up with what the right link person. <a href="bio/".$shortname.""><img src="images/spotlight/<?php randlogo(); ?>" alt=".::Spotlight A KOW Superstar::." /></a> <?php function randlogo(){ $img = array(); if($handle = opendir('images/spotlight/')) { $count = 0; while (false !== ($file = readdir($handle))) { if(strlen($file) > 2){ $img[$count] = $file; $count++; } } } echo $img[rand(0, (count($img)-1))]; } ?> Hey guys, i've made a script to display a random image. Works perfect on firefox, ie but not chrome =/. Rotate.php <?php // rotate images randomly but w/o dups on same page - format: // <img src='rotate.php?i=0'> - rotate image #0 - use 'i=1' // for second, etc // (c) 2004 David Pankhurst - use freely, but please leave in my credit $images=array( // list of files to rotate - add as needed "images/1.jpg", "images/2.jpg", "images/3.jpg", "images/4.jpg", "images/5.jpg", "images/6.jpg", "images/7.jpg", "images/8.jpg", "images/9.jpg" ); $total=count($images); $secondsFixed=2; // seconds to keep list the same $seedValue=(int)(time()/$secondsFixed); srand($seedValue); for ($i=0;$i<$total;++$i) // shuffle list 'randomly' { $r=rand(0,$total-1); $temp =$images[$i]; $images[$i]=$images[$r]; $images[$r]=$temp; } $index=(int)($_GET['i']); // image index passed in $i=$index%$total; // make sure index always in bounds $file=$images[$i]; header ("Location: $file"); header ("Content-Length: 0"); exit; ?> and then to call it, script.php <img src='rotate.php?i=0' width="90%" height="90%" alt="" /> Hi all, I have an issue with an image upload script. So far the script will upload the image to the server and rename it with a random 5 digit number on the end. I then INSERT this data into a table for sourcing the image later on. the only problem is that the data in the table is the image's original name not the new one. how do I get it to change that name too? Thanks. Code: [Select] <?php $idir = "uploads/"; // Path To Images Directory if (isset ($_FILES['fupload'])){ //upload the image to tmp directory $url = $_FILES['fupload']['name']; // Set $url To Equal The Filename For Later Use if ($_FILES['fupload']['type'] == "image/jpg" || $_FILES['fupload']['type'] == "image/jpeg" || $_FILES['fupload']['type'] == "image/pjpeg") { $file_ext = strrchr($_FILES['fupload']['name'], '.'); // Get The File Extention In The Format Of , For Instance, .jpg, .gif or .php $copy = copy($_FILES['fupload']['tmp_name'], $idir. basename($_FILES['fupload']['name'], $file_ext).rand(10000 , 99999).$file_ext); // Move Image From Temporary Location To Perm } } error_reporting (E_ALL ^ E_NOTICE); $usr = "user"; $pwd = "pword"; $db = "db"; $host = "host"; # connect to database $cid = mysql_connect($host,$usr,$pwd); if (!$cid) { echo("ERROR: " . mysql_error() . "\n"); } if ($_POST['submit']) { $logo = mysql_real_escape_string("$idir" . $_FILES['fupload']['name']); $SQL = " INSERT INTO mhhire "; $SQL .= " (logo) VALUES "; $SQL .= " ('$logo') "; $result = mysql_db_query($db,$SQL,$cid); $last=mysql_insert_id(); if (!$result) { echo("ERROR: " . mysql_error() . "\n$SQL\n"); } header("location:thanks.php"); exit(); } ?> I have a very simple piece of code to create a grid based gallery. The thumbnails are loaded from a single directory and are name 1.jpg... 2.jpg... 3.jpg etc At the moment the images appear to be loaded in randomly. I want them to load in numerically in terms of their filename. I know I may need to use 'sort' or 'natsort' but where in the code? Thanks for any help you can give me Code: [Select] <? $images = "Images/Bag Thumbs/"; # Location of small versions $big = "ruxxwomens.php?id="; # Location of big versions (assumed to be a subdir of above) $cols = 4; # Number of columns to display if ($handle = opendir($images)) { while (false !== ($file = readdir($handle))) { if ($file != "." && $file != ".." && $file != rtrim($big,"/")) { $files[] = $file; } } closedir($handle); } $colCtr = 0; echo '<table width="800" cellspacing="0" cellpadding="0" border="0"><tr>'; foreach($files as $file) { if($colCtr %$cols == 0) echo '</tr><tr>'; echo '<td align="center"><a href="' . $big . $file . '"><img src="' . $images . $file . '" cellspacing="0" cellpadding="0" border="0"></a></td>'; $colCtr++; } echo '</table>' . "\r\n"; ?> My images generator comprises
an array of image names extracted form an images table from a database using a select statement
a random number generator,
and a string that builds the correct pathname for the selected file.
To select one of the images for display, i generate a random number between 1 and the length of the array.
Though the generator is working, I noticed one of the random numbers is throwing up this error:
Warning: getimagesize(images/): failed to open stream: No such file or directory in
An inspection of the array reveals 2 array elements (representing my number of images) but one array element is NULL ( the first entry in the banner table
image_generator.php
require_once('connection.inc.php');
$sql = 'SELECT `filename` FROM banner';
$result = $mysqli->query($sql, MYSQLI_STORE_RESULT) or die(mysqli_error());
$row = $result->fetch_array(MYSQLI_ASSOC);//an array of image names
$count = $result->num_rows;
for ($i = 1; $i <= $count; ++$i)
{
$row[$i] = $result->fetch_array(MYSQLI_ASSOC);
}
$i = rand(1, $count); //a random number generator,
//The random number is used in the final line to build the correct pathname for the selected file.
$selectedImage = "images/{$row[$i]['filename']}";
if (file_exists($selectedImage) && is_readable($selectedImage))
{
$imageSize = getimagesize($selectedImage);
}
var_dump($row)
array (size=1)
'filename' => string 'ginsomin2.jpg' (length=13)
null
RANDON IMAGE DISPLAY
require_once 'image_generator.php';
<div id="banner" class="wrapper clearfix">
<img src="<?php echo $selectedImage; ?>" alt="banner">
</div>
Kindly advice how i may proceed from here?
Thanks.
As above, I have a lottery style site that picks a random number between 1-8 but my users complain for some reason that this is not enough. So i was told to look into using fopen and random.org to generate a random number. Anyone have experience of this and perhaps a code snippet for me to look at and possibly use? help will be appreciated. I'm attempting to set up a script that will choose a "random" image from a directory and then place it in an article when it's posted. I currently have a php file that randomly assigns a picture on each refresh, however my employer wants the image to be static after posting. So I guess the short of my question is, what would be the best way to go about something like that or is it even doable with PhP. I know this is not coding.. However... How tolerant is PHP from generating a random output from 1000s of entry columns in a mysql database. I would like to make a script that would potentially pick one of a 1000 results at random. is this a problem with being ran multiple times? Wow, I have no clue what I'm doing.. I'm trying to make a random game and if you roll a 6, you will win 500 rp and I'm trying to insert the 500 rp into the user who is logged in ($_SESSION['username'). But I... just don't know where to begin. Here is my crappy coding that I just.. am stumped on: <p><?php $dice = rand(1,6); if($dice == 1){ echo "You rolled a <br><b>1</b>"; }if($dice == 2){ echo "You rolled a <br><b>2</b>"; }if($dice == 3){ echo "You rolled a <br><b>3</b>"; }if($dice == 4){ echo "You rolled a <br><b>4</b>"; }if($dice == 5){ echo "You rolled a <br><b>5</b>"; }if($dice == 6){ echo "You rolled a <br><b>6</b>"; } $winner = "500"; if($dice == 6); { include("haha.php"); $cxn = mysqli_connect($dbhost,$dbuser,$dbpassword,$dbdatabase); $sql = "INSERT INTO Member (rp) VALUES ('$winner')"; mysqli_query($cxn,$sql); } ?> is there a way to make a random number input into mysql? like if i add a new customer to a table, i want to assign a random number to that customer. Is there anyway in MySQL you can select a random record in a table? I normally do this by generating a random number first and then using that number to find a record but was wondering if there is an easier way. Thanks for any help. Hi, I want to pick out a random letter from a to h. How can I do this? So everytime the page re-loads, a random letter (range a-h) will show. Thanks alot for any help. Im trying to figure out the best way to random a line from a text file and after the random delete that line from the file. This way the same username cannot be picked twice thanks for any input I want to loop through all the values of an array.. but each time, JUST FOR THE LOOP, i want to go through the array values randomly. How do you suggest I do this? How would I make it so that for every set of data where a fieldname is 1+ it picks a random one out. For example User Hit Luke 0 Peter 1 Alex 3 Peter 1 For every value where Hit is 1 or over it selects out of the query results a random username. I dont know how to word this really. what I want to do is Code: [Select] $Var[] = 3; $Var[] = 6; $Var[] = 2; $Var[] = 17; for($i=0; $i!=count($Var); $i++) { echo "#$i: ".$Var[$i]."\n"; } I know I might be able to use rand() but I need it to echo ALL of the variables in the array in a random order, I know if I use count to find out how many variables there are that it would echo them 4 times randomly but might echo the same variable 2 times making it to where it only echos 3 different varables, if I am being confusing please let me know, I just want to get this resolved, thanks! hello, i am trying to see how i can pick a random number between 1-15 and exclude certain numbers. so i have a staff list that once a random number is created it inserts it into the staffnumber field. so the next time i create a random number for a staff, i want to make sure that the random number doesnt select an existing staffnumber. thanks! how do I pull out two random integers at the same time without ever possibly choosing the same integer twice? |
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