PHP - Variable Inside Header Question

I dont know why I'm having so many problems with this. I need to get a variable that defined in an included file inside of a function I've got this

Inside file.php I've got the $variable1 and $variable2 defined (they're dynamic/different to each user)

include('file.php');

function foo() {
GLOBAL $variable1, $variable2;

echo $variable1;
echo $variable2;
}

foo();

Yet it outputs nothing?

If I Include file.php right inside of the function it works however. Any idea?

If I have a for loop with a variable called $counter, how can I use the value of this inside a variable name. For example:

If I want a bunch of variables called $d1name, $d2name, $d3name ...etc. what's the correct syntax to use? The following gives me a string but not a variable name:

$myVariable = "$"."d".$counter."name";

Hi Everyone,

I have built a website utilizing a PHP abstract Webpage class to create the pages. When creating another class that inherits from Webpage class I rewrite abstract functions, etc. where needed. When instantiating an object of the extended classes I pass the constructor the $page_title, $css_file, $meta_data, $keywords, etc., etc.. I am able to pass html markup in a string variable to a class level "Setter" function  to populate a "main area" of the website and all works perfectly.

However, I have a contact form which I send the "Submit Message" button click to a PHP function that takes care of making sure the form fields are not empty, then sends email and returns a success message back to the calling page, if they are empty, the function returns what fields are empty(required). If the page includes empty and populated fields I want to put the populated fields into session variables so that I may populate the fields when the user is taken back to the page and display to the user the required fields that were empty(this functionality is already within the function).

This brings me to my question(see code below for reference):

Seeing that I am populating a variable with a string it seems I cannot use an if statement, echo or the like, my IDE gives me errors. How may I insert an if statement where needed to populate the empty form fields?
Code: [Select]
include('../php_functions/functions.php');//for the chechData() function

$error_message = NULL;

if(isset($_POST['submit']))
{
    $error_message = checkData($_POST, 'Renovation & Consulting');
}
$main_content =
'<form method="post" action="">
    <fieldset id="contactform">
        <legend>Renovations &amp; Consultations</legend>'.

        [color=red]//placing a variable here works fine![/color]
            $error_message
       
            .'<div class="row_div">
                <div class="label_div">
                    <label>First Name:</label>
                </div>
                <div class="input_div">
                    <input name="First Name" type="text" maxlength="50" size="50" value="'.[color=red]if(session variable not empty) echo it here;.'"[/color] />
                </div>
            </div>
            <div class="row_div">
                <input name="submit" type="submit" value="Send Message" />
            </div>
      </fieldset>
</form>';

Thanks for any and all responses.

Chuck

how can you increase the page number in the following line until $status returns an empty result?

curl_setopt($ch, CURLOPT_HTTPHEADER, array("Accept: application/xml", "Authorization: xxxxxxxxxxxxx:xxxxxxxxxxxxxxxx", "Page: 2"));

I'm trying to build a math game.

But I'm having trouble trying to make a variable calculate that contains an operator.

Example:


$c1_op = "+";
$a1_num_user = $_POST['a1_num'];
$e1_num_user = $_POST['e3_num'];

$row_1 = $a1_num_user . $c1_op . $e1_num_user;
echo "result: " . $row_1;



If I now input a 10 and a 2 I will get echo'd out:

result: 10+2

It's not calculating. When I don't use any quotation marks then I will get the error "unexpected ;".

I need the operator inside a variable, it's the nature of the math game, any idea how I can make it work so it calculates?

I'm redoing my login script using functions and a basic switch function checking against a $_GET variable (hope you guys know what I'm talking about).

What I want to do is create two functions:

1 that displays the login form
and 1 that processes the information

The form tag would look like this:
<form action=\"<?php $_SERVER['PHP_SELF']?>?action=process\" method=\"post\">
</form>

Here's my switch statement:
Code: [Select]
<?php

//****************************************
//****************Action******************
//****************************************

switch ($_GET["action"]) {
default:
case "index":
if (!$_SESSION["member"]) {
if (!$timeout) {
display_form();
} else {
echo $timeout_error;
}
} else {
echo "You are already logged in.";
}
break;
case "process":
if (!$_SESSION["member"]) {
if (!$timeout) {
process_form();
} else {
echo $timeout_error;
}
} else {
echo "You are already logged in.";
}
break;
}

?>

This runs as soon as "login.php" loads.

It'll automatically run the commands under case "default" and "index". It'll first check to see if the member's logged in. If not, it'll then check to see if "$timeout" is true ($timeout becomes true if the member has attempted to login 5 times and failed). If not, it'll display the login form, by running "display_form()".

Once the form has been filled and submitted, the commands under case "process" will be performed. Again it will first check to see if the member's logged in. If not, it'll check to see if "$timeout" is true. If not, it'll start validating the forms.

For the validation, I've created a variable called "$errors_found", and scripted one if statement checking to see if the email and password exist. If so, the variables "$rm_field_un" and "$rm_field_pw" become true, as well as "$errors_found".

So, back to submission of the form...

If "$errors_found" is true, display the form (when the form is displayed, there will be an if statement within that says "<?php if ($rm_field_un) { echo "Username is wrong."; } ?>", which will be displayed right underneath the username field and label. Same with the password elements). If "$errors_found" is not true, go ahead and register the member.

Now, here's where I need help, because I'm really confused as to how to accomplish this.

The "display_form()" function will contain a single variable called "$login_form". It will contain a value of the HTML constructed login form, and the function will return the variable.

Remember how I stated in the third paragraph up that I will have <php> statements within the form which would display errors if necessary? Well, how do I put those if statements within the HTML, which is contained within the variable?

If that last question confuses you, allow me to present you with an instance:
Code: [Select]
<?php

function display_form() {
$login_form = "
<form name=\"login_form\" method=\"post\" action=\"<?php $_SERVER['PHP_SELF']?>?action=process\">
Username:
<input type=\"text\">
<?php if ($rm_field_un) { echo "Username is wrong"; } ?>
";

return $login_form;
}

?>

See what I mean?

This code confuses me ALOT. I'm not sure if the <php> tags are needed as it is already contained within existing ones, or what. Can somebody please help me out?

Any and all help is much appreciated. =D

Hi,
The array shown below is causing problems. I know this for sure because when I comment the array out the script runs. Is it: 'pswrd1'=>SHA1('$_POST['pswrd1']') inside the array causing the script not to run?? All help will be greatly appreciated.

$register_data =
array('username'=>$_POST['username'], 'first_name'=>$_POST['first_name'], 'last_name'=>$_POST['last_name'], 'address'=>$_POST['address'], 'postcode'=>$_POST['postcode'], 'country'=>$_POST['country'], 'e_mail'=>$_POST['e_mail'], 'pswrd1'=>SHA1('$_POST['pswrd1']'), 'phone_no'=>$_POST['phone_no']);

Trying to figure out how to make it so name is a link to the profile when its echo
anyone know how to do this?

im at a huge stand still


Code: [Select]
<?php 

                                                $sql = "SELECT name FROM users WHERE DATE_SUB(NOW(),INTERVAL 5 MINUTE) <= lastactive ORDER BY id ASC"; 
$query = mysql_query($sql) or die(mysql_error());
$count = mysql_num_rows($query);
$i = 1;
while($row = mysql_fetch_object($query)) {
 $online_name = htmlspecialchars($row->name);


   echo '<a href="Inbox.php">"'[$goauld]'</a>"'; ?>

I am echoing a variable that is an array.  I want to change the first part of the variable but don't know how to manipulte names inside the ['brackets']
Code: [Select]

echo $row['v1_name']);?>



lets say I have a value called $var = v1.  How do I substitute that like this:
Code: [Select]
echo $row[$var.'_name']);?>
I know the above doesnt work, but thats what i want it to do :-)

I currently have a login script in place on my site and to get to certain pages you have to be logged in to get to.

So when a user tries to go to one of those pages and is not logged in it sends them to the login page (which is great)
But on the login page once they login it uses "   header('Location: index.php')    " to automatically send them to the index page logged in.

How can i dynamically see what page they are coming from that way when they login I can send them back to where they where trying to get to to begin with. (like if they click on "Profile" and they are not logged in it sends them to "login" then they login and it currently sends them to "index" I want it to dynamically know to send them back to "profile" instead)

If this doesn't make sense and i will try and explain it better
But if you understand and know how to do this please help

Thanks ahead of time!

I tried these below,
Code: [Select]
class Site extends Controller
{
  function Site()
 {
    public $data = Array();
 }
}

but it fail?

Thanks in advanced.

this question seems so stupid, but i really want to know the best way to write this code.

let say i have this code:

if(empty($num))
{
header("Location:index.php");
}

is it okay if i write it down like this?

if(empty($num))
{
  header("Location:index.php");
}

i mean there is a whitespace behind header()

thanks in advance

Hi, I have a connection set up to an API using a PHP script - the API sends back data in JSON format, and if I capture it and echo it, it displays in extremely unfriendly format on the screen.

I've tried to find a way to convert this data into readable format, ideally in a HTML table, but although there are articles on converting manually inputted JSON data into a HTML table using Javascript, I can't find a way to do it from a PHP variable.

This is what I have so far:

if ($_POST['getcompany']) {
$companyname = $_POST['_Name'];
	
$ch = curl_init();

$data_array2 =  array(
      'token' => $token
);
$make_call2 = json_encode($data_array2);
	//echo 'Token is '.$token;
	$token2 = substr($token, 14);
	$token3 = substr($token2, 0, -3);
	
	//echo 'Token 2 is '.$token3;
	//echo 'Company Name is '.$companyname;

//curl_setopt($ch, CURLOPT_GET, 1);
//curl_setopt($ch, CURLOPT_POSTFIELDS, $make_call2);
curl_setopt($ch, CURLOPT_HTTPHEADER, array('Content-Type: application/json','Authorization: '.$token3.'')); 
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_URL, 'https://connectionurl?countries=GB&name='.$companyname);

//Execute the request
$result = curl_exec($ch);

echo 'Companies: '.$result; //This displays the data provided by the search, but is in JSON format

 

So I need a way to get the data held in $result, into a HTML table. Any idea how I can do this?

Hello, people!   I was watching some php tutorials in youtube and, in a video, the guy was showing how put php script inside html code. I would like to know why in the following code he didn't use only one php script? 1- Code used in the video:

<html>
<body>

<?php
$color = $_GET['clr'];
?>

<b><font color="<?php echo $color;?>">This is a test.</font></b>

</body>
</html>

  2- Modified code by me to test with one script:

<html>
<body>

<?php
$color = $_GET['clr'];

echo "<b><font color=\"$color\"> This is a test. </font></b>";

?>

</body>
</html>

  Is his code more correct(with two scripts)? Why?

I have a web site with a user login requirement that has worked splendidly for months.  I also have a development version of my site on my laptop, localhost.  At the moment, I have identical code on both the development and production sites.  I'm getting some header error in production, but not on development.

Is it guaranteed that my page is generating some white space, or is it possible that there may be another issue at hand (I'm fairly non-technical, so I'm grasping here - my web host upgraded to a different PHP version that is creating whitespace in production while development on my laptop is a different version of php, my web host has done something else that is causing this, fill in the blank with your own conspiracy theory)?  Any reading material out there (besides the php.net manual) that explores what may be going on?

Thanks in advance - this community has been wonderfully helpful for me over the last year!