PHP - Get Filenames From Directory And Display Each In A Cell No Wider Than 5 Columns
Hi guys. Just a quick PHP question. I have a script running that gets the files from a directory. There is then a switch function that decides what to do with the file, ie... if it is a PNG... DO THIS.. if it is a docx... DO THIS.. etc.
And i want each file to be in a different cell on the table. The table can be longer wider than 5 columns (however it can be as high as it wants). I currently have this bit working... but instead of one item in each cell... it is displaying every item in each cell. Any ideas Chaps? Here is my code Many thanks in advance if you could possibly help.. echo "<table><tr>"; $count = count(glob("../../shared/files/*.*", GLOB_BRACE)); for($i=1; $i <= $count; $i++) { /// echo "<td>"; /// if ($handle = opendir('../../shared/files/')) { while (false !== ($file = readdir($handle))) { if ($file != "." && $file != "..") { $break = pathinfo($file); $b = $break['extension']; switch (@$break[extension]) { case 'bmp' : echo 'A BMP<br>'; break; case 'png' : echo 'A PNG<br>'; break; case 'doc' : case 'docx' : echo 'A DOC OR DOCX<br>'; break; default: echo 'FILE NOT RECOGNISED<br>'; } } } closedir($handle); } /// echo "</td>"; /// if($i % 3 == 0) echo "</tr><tr>"; } echo "</tr></table>"; ?> Similar TutorialsHi, I've tried various methods (ie. glob etc.) but haven't had any success, the purpose is to scan through all directories for php files, then place those php files along with their path ($dir/$filename) into an array (to use elsewhere) So if I have the following file/directory structure (example): Code: [Select] --forums: ---topic.php ---forum.php --func: ---functions.php Would produce the following array: $files = array('topic.php' => 'forums/topic.php', 'forum.php' => 'forums/forum.php' 'functions.php' => 'func/functions.php'); How can i display all the images in a certain directory and echo the image names. So if a new image is uploaded, it will still display without edited the gallery.php file. Cheers. I have this code which works fine. I want to improve it by displaying it into multiple columns. Current output: TITLE 1 JOB1 --------- TITLE 2 JOB 2 --------- ETC... I want it to display like this instead: TITLE 1 | TITLE 2 JOB 1 | JOB 2 Here is my code: $sql = "SELECT * FROM coaches WHERE position = 'Junior Coach'"; $result = mysql_query ($sql); while ($row = mysql_fetch_array($result)){ $id = $row["id"]; $firstname = $row["firstname"]; $lastname = $row["lastname"]; $position = $row["position"]; $image = $row["image"]; ?> <table width="183" border="1"> <tr> <td align="center" height="18"> <?php echo "<img id='image_shadowCoaches' src=" . $image . ">"; ?><br /> <?php echo "<div id='Coaches_Detail'>".$firstname." ".$lastname."</div>" ?> <?php echo "<div id='Coaches_DetailLower'>".$position."</div>" ?> </td> </tr> </table> <?php } ?> hi, Is it possible to display an image that is above the root directory using php? for example if i have an image in /home/user/uploads/test.jpg and lets say my root directory for my site is /home/user/public_html/ is it possible to display test.jpg on /home/user/public_html/index.html ? i am trying to create a secure file upload script and i think not having the file be directly accessed by the public is one of the main steps. I am trying to display images on a html page alphabetically in descending order by their filename. This script inserts all the images in a directory on the page. Just can't figure out how to maintain this with a sorting option <?php $dir = "./plate_cache"; $handle = opendir($dir); while (($file = readdir($handle))!==false) { if (strpos($file, '.png',1)) { echo "<img id=\"plates\" src=\"/tags/plate_cache/$file\"></a><br />;"; } } closedir($handle); } ?> I have a blog on my website and the blogs content is stored in a database. On my home page I have the two recent articles displayed on my home page but I have to change them manually so I add the recent article on the home page in the first column and the second most recent one in the next column so they are side by side. What I want to do is automatically display the blogs image and blog title from the database and display on the home page so I don't have to keep changing it manually My current code looks like the following <div class="block"> <div class="container"> <h3 class="text-center"><span class="color">Recent Blog Articles</span></h3> <div class="row"> <div class="col-md-6"> <div class="text-img animation" data-animation="fadeInLeft" data-animation-delay="0.5s"> <a href="https://www.it-doneright.co.uk/blog/one-year-to-go-until-end-of-support-for-windows-7"> <div class="image"> <img class="img-responsive" src="https://www.it-doneright.co.uk/images/blog/windows7-eos-new.jpg" alt="One year to go until end of support for Windows 7"> </div> <p>One year to go until end of support for Windows 7</p> </a> </div> </div> <div class="col-md-6"> <div class="text-img animation" data-animation="fadeInLeft" data-animation-delay="0.5s"> <a href="https://www.it-doneright.co.uk/blog/windows-10-is-going-to-require-7gb-of-storage-for-future-updates"> <div class="image"> <img class="img-responsive" src="https://www.it-doneright.co.uk/images/windows-ten-updates-needing-7gb-space-on-hard-drive.jpg" alt="Windows 10 is going to require 7gb of storage for future updates"> </div> <p>Windows 10 is going to require 7gb of storage for future updates</p> </a> </div> </div> </div> </div> </div> I did look on Google before posting but could not get my head around how to do it, could anyone point me in the right direction or start me off and will have a go When displaying data from a mysql table, what php code can I use to display the number of columns in said table? Like, say I'm displaying comments by users. I want to be able to put "displaying 'thismany' comments". Any suggestions? hi to all.Im currently displaying the images from my upload directory but the image does not display.please help thanks Code: [Select] <?php $path = "../assets/tattoos/"; $path2 = "../assets/tattoos-thumbs/"; if(isset($_POST['file']) && is_array($_POST['file'])) { foreach($_POST['file'] as $file) { unlink($path. "/" . $file) or die("Failed to delete file"); unlink($path2. "/" . $file) or die("<meta http-equiv=\"refresh\" content=\"0; url=index.php\" />"); } } ?> <form name="form1" method="post"> <?php $imageDir = "../assets/tattoos/"; $dir_handle = @opendir($path) or die("Unable to open folder"); while (false !== ($file = readdir($dir_handle))) { if($file == "index.php") continue; if($file == ".") continue; if($file == "..") continue; echo "<input type='CHECKBOX' name='file[]' value='$file'>"; echo "<img src='../assets/tattoos/$file' style='height:auto;width:8%;' alt='$file'>"; } closedir($dir_handle); ?> <input type="submit" name="Delete" value="Delete"> </form> I have this code, which calls an image directory and adds a checkbox next to it, you check the boxes you wish, hit delete and the pictures are removed from the server. I need them to display in a grid view, like 4 columns by X amount of rows. Any help would be greatly appreciated. Image name will come from database. It can be displayed in divs or table cells. Which is better using divs or table cells? Can anyone post sample code? http://img28.imageshack.us/i/44233003.png/ i have checkboxes on the database page and if checked they send to the shopping basket i have the items selected to display but like this
Array ( [0] => Imagine DragonsImagine DragonsRockI Bet My LifeKIDinaKORNER1.25Brand new single from the incredible Imagine Dragons )
i'm trying to echo out the results from a query onto a page, but rather than having them echo out as rows in a table, i want them to be displayed in columns, i.e. first column would have the first 10 results and the second column would have the next to. Any ideas on how i could do this? at the moment i'm using this code to display my results $read=mysql_query("SELECT * FROM entry WHERE category_id=".$id." ORDER BY entry_title") or die("query failed".mysql_error()); $result=mysql_num_rows($read); for($j = 0; $j < $result; $j++) { $row = mysql_fetch_array($read); echo "<a href=article.php?id=".$row['entry_id']. ">".$row['entry_title']."</a><br />"; } but this just displays it as a list down the middle thanks Now I am stumped this is far any help would be awesome This is what I have gotten so far, this is what it does right now is display each Header above each bit of data and spans across 5 columns for each foreach loop but what i am trying to understand here is i am trying to get the header then the data then another header and data and so on but only about 4 or number of my choosing grouped header/data but select how many are in each column up to 5 columns. Heres an example of what i am trying to do. A D K N S AlexandraHeadlands DickyBeach KingsBeach Nambour SandstonePoint Aroona Diddillibah KielMountain Ninderry ShellyBeach Doonan KundaPark NoosaHeads SippyDowns B Dulong Kuluin Ningi SunriseBeach Beachmere DeceptionBay Kilcoy NorthArm SunshineBeach BanksiaBeach Noosaville Scarborough Beerburrum E L Beerwah EerwahVale Landsborough O T Bellara Elimbah Tanawha Bellmere Eudlo M P TowenMountain Birtinya Eumundi Maleny Petrie Tewantin Bongaree Mapleton Palmview TwinWaters Bokarina F Marcoola Palmwoods BribieIslandArea Flaxton MarcusBeach Parklands U Buddina ForestGlen MaroochyRiver Parrearra UpperCaboolture Burnside Maroochydore PeregianBeach Buderim G Minyama Pinbarren V Burpengary GlassHouseMountains MoffatBeach PointArkwright Valdora BliBli Mons PelicanWaters H Montville PacificParadise W C Highworth Mooloolaba WeybaDowns CoolumBeach Hunchy Mooloolah Q Warana Caboolture MountainCreek WestWoombye CabooltureSouth I MountCoolum R Woombye Caloundra ImageFlat Morayfield Rosemount Woorim CastawaysBeach Mudjimba Redcliffe WamuranBasin Chevallum J Woodford CoesCreek WoodyPoint Cooroy Wamuran Currimundi Wurtulla X Y YandinaCreek Yandina Z This is an example of how it is being displayed right now A Airlie Beach Andergrove Alexandra Armstrong Beach Alligator Creek B Bucasia Blacks Beach Beaconsfield Bakers Creek Balberra Bloomsbury Breadalbane Ball Bay Belmunda C Cannonvale Calen Crystal Brook Cremorne Chelona Campwin Beach Cape Hillsborough Conway Heres The Code i have so far. Code: [Select] <?php $file = "widget.csv"; @$fp = fopen($file, "r") or die("Could not open file for reading"); $outputArray = array(); $count = 0; while(($shop = fgetcsv($fp, 1000, ",")) !== FALSE) { $outputArray[array_shift($shop)] = array_filter($shop); } echo "<table>"; foreach ($outputArray as $alphabetical=>$value){ echo "<th colspan='4'><b>" . $alphabetical ."</b></th>"; echo "<tr>"; foreach ($value as $key){ $afterkey=preg_replace('/\s+/','-',$key); if ($count == 4){ echo '</tr><tr><td><a href="map.php?mapaddress='.$afterkey.'-qld&mapname='.$key.'">'.$key.'</a></td>'; $count = 0; }else{ echo '<td><a href="map.php?mapaddress='.$afterkey.'-qld&mapname='.$key.'">'.$key.'</a></td>'; } $count++; } echo "</tr>"; $count = 0; } echo "</table>"; echo "\n<br />"; ?> Heres my CSV File: Quote A,Airlie Beach,Andergrove,Alexandra,Armstrong Beach,Alligator Creek,,,,,,,,,,,,,, B,Bucasia,Blacks Beach,Beaconsfield,Bakers Creek,Balberra,Bloomsbury,Breadalbane,Ball Bay,Belmunda,,,,,,,,,, C,Cannonvale,Calen,Crystal Brook,Cremorne,Chelona,Campwin Beach,Cape Hillsborough,Conway,,,,,,,,,,, D,Dows Creek,Dumbleton,Dolphin Heads,,,,,,,,,,,,,,,, E,Eimeo,Eton,Erakala,,,,,,,,,,,,,,,, F,Foulden,Foxdale,Flametree,Farleigh,Freshwater Point,,,,,,,,,,,,,, G,Glen Isla,Glenella,,,,,,,,,,,,,,,,, H,Homebush,Hampden,,,,,,,,,,,,,,,,, I,,,,,,,,,,,,,,,,,,, J,Jubilee Pocket,,,,,,,,,,,,,,,,,, K,Kinchant Dam,Kolijo,Koumala,Kuttabul,,,,,,,,,,,,,,, L,Laguna Quays,,,,,,,,,,,,,,,,,, M,McEwens Beach,Mackay,Mackay Harbour,Mandalay,Marian,Mia Mia,Middlemount,Midge Point,Mirani,Moranbah,Mount Charlton,Mount Jukes,Mount Julian,Mount Marlow,Mount Martin,Mount Ossa,Mount Pelion,Mount Pleasant,Mount Rooper N,Narpi,Nebo,Nindaroo,North Eton,,,,,,,,,,,,,,, O,Oakenden,Ooralea,,,,,,,,,,,,,,,,, P,Palmyra,Paget,Pindi Pindi,Pinevale,Pioneer Valley,Pleystowe,Preston,Proserpine,,,,,,,,,,, Q,,,,,,,,,,,,,,,,,,, R,Racecourse,Richmond,Riordanvale,Rosella,Rural View,,,,,,,,,,,,,, S,St Helens Beach,Sandiford,Sarina,Seaforth,Slade Point,Shoal Point,Shute Harbour,Shutehaven,Strathdickie,Sugarloaf,Sunnyside,,,,,,,, T,Te Kowai,The Leap,,,,,,,,,,,,,,,,, U,,,,,,,,,,,,,,,,,,, V,Victoria Plains,,,,,,,,,,,,,,,,,, W,Wagoora,Walkerston,Woodwark,,,,,,,,,,,,,,,, X,,,,,,,,,,,,,,,,,,, Y,Yalboroo,,,,,,,,,,,,,,,,,, Z,,,,,,,,,,,,,,,,,,, I could use some help on naming my PHP files... The approach I have settled on for now is that I have some PHP page that does something (e.g. "change_password.php") and then another page to which the user is redirected (e.g. "change_password_results.php") which displays an outcome message like "Your Password has been re-set." Questions: 1.) Is it a problem having multi-word PHP File Names? 2.) Is it a problem separating them with underscores? 3.) Will it look *strange* to users looking at the URL to see a file name like "create_account_results.php" ?? 4.) Will this impact SEO? Thanks, Debbie Hi, I have the following situation: Code: [Select] Array ( [5] => GeoLiteCity_20090601.zip [6] => GeoLiteCity_20090701.zip [7] => GeoLiteCity_20090801.zip [8] => GeoLiteCity_20090901.zip [9] => GeoLiteCity_20091001.zip [10] => GeoLiteCity_20091101.zip [11] => GeoLiteCity_20091201.zip [12] => GeoLiteCity_20100101.zip [13] => GeoLiteCity_20100201.zip [14] => GeoLiteCity_20100301.zip [15] => GeoLiteCity_20100401.zip [16] => GeoLiteCity_20100501.zip [17] => GeoLiteCity_20100601.zip [18] => GeoLiteCity_20100701.zip [19] => GeoLiteCity_20100801.zip [20] => GeoLiteCity_20100901.zip [21] => GeoLiteCity_20101001.zip [22] => GeoLiteCity_20101101.zip [23] => GeoLiteCity_20101201.zip ) I have this array with filenames, the patern for the name of the file is NAME_DATE.zip I need to get from this array the most recent file(GeoLiteCity_20101201.zip). Which is the best way of doing this task? Give me some clues. Best Regards, Hello PHPFreaks! I have a question for somebody to answer Code: [Select] <?php //This is the directory where images will be saved $target = "gallery/"; $target = $target . basename( $_FILES['photo']['name']); //This gets all the other information from the form $username=$_POST['username']; $photo=($_FILES['photo']['name']); $caption=$_POST['caption']; $ip=$_POST['ip']; //Writes the information to the database mysql_query("INSERT INTO `photo` (username, photo, caption, ip) VALUES ('$username', '$photo', '$caption', '$ip')") ; //Writes the photo to the server if(move_uploaded_file($_FILES['photo']['tmp_name'], $target)) { //Tells you if its all ok echo "The file ". basename( $_FILES['uploadedfile']['name']). " has been uploaded, and your caption has been added to the directory"; } else { //Gives and error if its not echo "Sorry, there was a problem uploading your file."; } ?> When pictures are uploaded; they upload the name they have named them. Is it possible to add to the script $username somewhere to the file name? For example; DSC_0077_SOLAR.JPG Thanks for your time! Hello:
How could I use php to automatically insert the correct 3 letter month abbreviations and four digit year in the following pdf filenames on the first of each month?
(For example "...Feb2015.pdf" then "...Mar2015.pdf" and so on....
<div>Book One: <a href="http://monthlybookfi...One_Jan2015.pdf">Download Here</a></div> <div>Book Two: <a href="http://monthlybookfi...Two_Jan2015.pdf">Download Here</a></div> <div>Book Three: <a href="http://monthlybookfi...ree_Jan2015.pdf">Download Here</a> </div> <div>Book Four: <a href="http://monthlybookfi...our_Jan2015.pdf">Download Here</a> </div> Please advise, Eggie Hi all I hope I have come to the right place. My system reads files stored on a drive and lists them to users through plain HTML, I made it 11 years ago and have to refresh my memory. My problem is that filenames seem to come in different formats, to how to decode/encode them is an issue...
My users use Scandinavian letters (æøåäöüõ) and it seems like one filename is in one format and another in another format. There is no logic to what format the filenames comes it. All files are ok and downloads as they should, they just dont list well. Any idea how I can handle this issue?
PHP script return 20 UL LIST values like, < ul >
A < /ul > How to display UL LIST into row wise 5 columns like
A B C D Hey guys, I have a folder which has images. In this folder there are images that start with "refl_". I want to make sure those are not displayed. This is what I tried and it does not work. I want to show all images that don't start with "refl_". I am new to this as I am sure some can see. Thanks for the help if possible! <?php $dir = opendir("img/portfolio/"); while (false !== ($file = readdir($dir))) { $pos = strpos($file, "refl_"); if ($pos == false) { echo '<img src="img/portfolio/' . $file . '" longdesc="img/portfolio/' . $file . '" /></a>'; } } ?> |