PHP - Retaining Text In A Form After Pressing Submit

Hi I have a list of states using the array method in a form. The drop down menu works fine.  I want to save the user choice,if the form is re-displayed due to a blank field or pattern mismatch.  I know I can use the selected=selected, but don't know wher to put the statement:
My array is:
state_province = array ("list of states", "provinces")
Var in my labels array is "state"=>"state"
Here is my code for the select/option statement:

{
 if($field == "state")
   {
      echo "<div class='province_state'><label for='state' size='10'>* Province/State</label><select>";
            
      foreach($state_province as $state)
         {
         echo "\n<option value='$state_province' /> ";   
          echo $state ;
          echo "</option>";
         }
      echo "</select></div>\n";   

   }
?Is this the correct code to add and where would I add  it?
          if(@$_POST['state'] == $value)
     {
         echo "selected='selected'  ";
     }          

Say I have an "Entries" table. I want to submit same multiple entries using a form submission. And If I have other queries submitted in the same form, I want those quarries to be submitted only once.  Is that possible to do? 

Here's my code.

if(isset($_POST['submit'])) {

  $entries = 10;

  $id   = 55;
  $name = 'Smith';

  $insert = $db->prepare("INSERT INTO entries(id, name) VALUES(:id, :name)");
  $insert->bindParam(':id', $id);
  $insert->bindParam(':name', $name);
  $result_insert = $insert->execute();
  if($result_insert == false) {
    echo 'Fail';
  } else {
    echo 'Success';
  }

}
?>
<form action="" method="post">
  <input type="submit" name="submit" value="SUBMIT" />
</form>

 

Edited January 13, 2019 by imgrooot

Hi.  Pretty straight forward I guess but as the name suggests am a newbie.  I have a form that requires the user to enter certain parameters.  If the values are blank it submits to itself and loads the error messages.  What I want to do is create PHP code that submits the form to a different url.  What I thought was create two forms (the second with hidden fields replicating the first form), each form having a different url in the action"" code.  What I cant work out is the PHP IF ELSE code to submit form 2 if Form1 is is validated correctly.  This is the PHP code relevant to the form validation.  Help?

<?php
      //If form was submitted
      if ($_POST['submitted']==1) {
          $errormsg = ""; //Initialize errors
          if ($_POST[width]){
             $title = $_POST[width]; //If title was entered
          }
          else{
             $errormsg = "Please enter width";
          }
          if ($_POST[drop]){
             $textentry = $_POST[drop]; //If comment was entered
          }
          else{
             if ($errormsg){ //If there is already an error, add next error
                $errormsg = $errormsg . " & content";
             }else{
                $errormsg = "Please enter drop";
             }
          }
      }

      if ($errormsg){ //If any errors display them
          echo "<div class=\"box red\">$errormsg</div>";
      }

      //If all fields present
      if ($title && $textentry){
         //Do something
          
echo 'THIS IS WHERE I WANT THE CODE TO SUBMIT FORM 2 or SUBMIT FORM 1 TO A DIFFERENT URL';
      }   
      ?>

Am new here - looks like a great foru!

I would sincerely appreciate any help anyone can give me. I have been
trying to solve my problem for hours and I am not having any luck, so I
thought I would post and see if anyone can help. I am very stuck and am
not making much progress on this project, and I am certain the answer is
very simple.

I am constructing a form to collect data for a specialized purpose. 

The form and program actually work for its intended function, but I am
trying to enhance the user experience by preventing customers from
having to reenter all of their data should there be a problem with any
of the data submitted.

I have been able to do that with the contact form portion, but what I am
having trouble with is the portion which has as many as 400 possible
entries.

So, in a nutshell, if the customers contact data is incomplete or in
error, the form will ask them to return to the page and correct things.
The previous data entered has been saved in the session and the input
value will equal the previous entry.

i.e.

<tr>
  <td align="right" class="infoBox"><?php echo ENTRY_EMAIL_ADDRESS; ?></td>
  <td align=left><?php echo "<input type=text name='cemail' value=\"$cemail\" size=35 maxlength=35>" ?></td>
</tr>

Works perfectly, all well and good there.

On the other 400 more or less entries, I am having a difficult time
tweaking the string concatenation to work to achieve similar results.

There are 4 columns each with $points entries asking for a dimension in
either feet or inches. 

The <input name=>  is one of ptaf,ptai,ptbf,ptbi, appended programatically with the corresponding
row number or data point.  i.e. "ptaf1", "ptai1", etc...  This is produced by the example
below and works perfectly also.

<?php {
$points=100;
$i=1;
while ($i <= $points)
{echo '
  <tr><td align="center" width="6"><b>  ' .$i . '</b></td>
     <td align="right" NOWRAP>A' .$i . ' (ft) <input type="text" name="ptaf'.$i.'" size=4 maxlength=3> </td>
      <td align="right" NOWRAP>A' .$i . ' (in) <input type="text" name="ptai'.$i.'" size=4 maxlength=4> </td>
     <td align="right" NOWRAP>B' .$i . ' (ft) <input type="text" name="ptbf'.$i.'" size=4 maxlength=3> </td>
      <td align="right" NOWRAP>B' .$i . ' (in) <input type="text" name="ptbi'.$i.'" size=4 maxlength=4> </td>

';

     $i++;
}   
}
?>


I am trying to add <input value=$ptai.$i> for each field but as I mentioned I
am not having any luck.  It seems as if I have tried every combination
imagineable, but still no luck. My head is spinning!

The closest I seem to have gotten was with this:

<td align="right" NOWRAP>A' .$i . ' (ft) <input type="text" size=6 maxlength=3 name="ptaf'.$i.'"  value="' . "$ptaf" . $i . '" ></td>

But line 17 for example returns this:

<input type="text" value="17" name="ptaf17" maxlength="3" size="6">

To recap, I am trying to have the value set to whatever the customer may
have entered previously.

Again, I would most appreciate any help anyone can give me. If you need
 clarification on anything please let me know.

Thanks

AJ

 

Hello all , here is another problem of my project.

I need to create a textarea , drop down list and submit button .

At first , I can type whatever I want in the textarea , but for certain part I can just choose the word I want from drop down list and click submit , then the word will appear in the textarea as my next word .

But I have no idea how to make this works , is there any simple example for this function ?
Thanks for any help provided .

Hello, first time poster..  I've looked the web over for a long time and can't figure this one out.

- Below is basic code that successfully checks MySQL for a match and displays result.  I was debugging and forced the "height" and "width" to be 24 and 36 to make sure that wasn't the problem.  That's good.. 
- I'd like to give the user ability to select width and height from a form.. and have it do an onchange this.form.submit so the form can be changing as fields are altered (thus the onchange interaction)
- In a normal coding environment I've done this numerous times with no "Page cannot be displayed" problems.  It would simply change one select-option value at a time til they get down the form and click submit...  but in WordPress I'm having trouble making even ONE single onchange work!
- I've implemented the plugins they offer which allows you to "copy+paste" your php code directly into their wysiwyg editor.  That works with basic tests like my first bullet point above.
- I've copied and pasted the wordpress url (including the little ?page_id=123) into the form "action" url... that didn't work...  tried forcing it into an <option value=""> tag.. didn't work.  I'm just not sure. 

I've obviously put xx's in place of private info..

Why does this form give me Page Cannot Be Displayed in WordPress every time?  It won't do anything no matter how simple.. using onchange..

Code..

$con = mysql_connect("xxxx.xxxxxxx.com","xxxxxx","xxxxx");
if (!$con)
  {
  die('Could not connect: ' . mysql_error());
  }
mysql_select_db("xxxxxx", $con);
$myprodwidth=24;
$myprodheight=36;
$result = mysql_query("SELECT * FROM product_sizes WHERE prodwidth='$myprodwidth' and prodheight='$myprodheight'");
while($row = mysql_fetch_array($result))
  {
  echo $row['prodprice'];
  }
mysql_close($con);


<form method="post" action="">
<select name="myheight" onchange="this.form.submit();">
<option selected="selected" value="">select height</option>
<option value="xxxxxxxxx.com/wordpress/?page_id=199&height=36">36</option>
<option value="xxxxxxxxx.com/wordpress/?page_id=199&height=36">48</option>
</select>

Hi all,

What I am trying to achieve is, I thought quite simple!

Basically, a user signs up and chooses a package, form is submitted, details added to the database, email sent to customer, then I want to direct them to a paypal payment screen, this is where I am having issues!

Is their any way in php to submit a form without user interaction? Here is my code for the form process page
Code: [Select]
<?php
include('config.php');
require('scripts/class.phpmailer.php');

$package = $_POST['select1'];
$name = $_POST['name'];
$email = $_POST['email'];
$password = md5($_POST['password']);

$domain = $_POST['domain'];
$a_username = $_POST['a_username'];
$a_password = $_POST['a_password'];


$query=mysql_query("INSERT INTO orders (package, name, email, password, domain, a_username, a_password)
VALUES
('$package', '$name', '$email', '$password', '$domain', '$a_username', '$a_password')");

if (!$query)
{
echo "fail<br>";
echo mysql_error();
}

else
{
$id = mysql_insert_id();
$query1=mysql_query("INSERT INTO customers (id, name, email, password)
values
('$id', '$name', '$email', '$password')");

if (!$query1)
{
echo "fail<br>";
echo mysql_error();
}


if($package=="Reseller Hosting")
{

//email stuff here - all works - just cutting it to keep the code short


if(!$mail->Send())
{
   echo "Message could not be sent. <p>";
   echo "Mailer Error: " . $mail->ErrorInfo;
   exit;
}
?>


<form name="_xclick" action="https://www.paypal.com/cgi-bin/webscr" method="post">
<input type="hidden" name="cmd" value="_xclick-subscriptions">
<input type="hidden" name="business" value="subscription@jollyhosting.com">
<input type="hidden" name="currency_code" value="USD">
<input type="hidden" name="item_name" value="Jolly Hosting Reseller Packages">
<input type="hidden" name="no_shipping" value="1">

<!--1st month -->
<input type="hidden" name="currency_code" value="USD"> 
<input type="hidden" name="a3" value="3.00">
<input type="hidden" name="p3" value="1">
<input type="hidden" name="t3" value="M">
<input type="hidden" name="src" value="1">
<input type="hidden" name="sra" value="1">
</form>';


<?php
}

//last
}
//end
?>

Hi-
the code below lets me upload a CSV file to my database if I have 1 field in my database and 1 column in my CSV.
I need to add to my db "player_id" from the CVS file and "event_name" and "event_type" from the form... any ideas???

here's the code:
Code: [Select]
<?php
$hoststring =""; 
$database = "";
$username = "";
$password = "";
$makeconnection = mysql_pconnect($hoststring, $username, $password);
?>
<?php
ob_start();
mysql_select_db($database, $makeconnection);
$sql_get_players="
SELECT * 
FROM tabel 
ORDER BY player_id ASC";
//
$get_players = mysql_query($sql_get_players, $makeconnection) or die(mysql_error());
$row_get_players = mysql_fetch_assoc($get_players);
//
$message = null;
$allowed_extensions = array('csv');
$upload_path = '.'; //same directory

if (!empty($_FILES['file'])) {

if ($_FILES['file']['error'] == 0) {
// check extension
$file = explode(".", $_FILES['file']['name']);
$extension = array_pop($file);

if (in_array($extension, $allowed_extensions)) {

if (move_uploaded_file($_FILES['file']['tmp_name'], $upload_path.'/'.$_FILES['file']['name'])) {

if (($handle = fopen($upload_path.'/'.$_FILES['file']['name'], "r")) !== false) {
$keys = array();
$out = array();
$insert = array();
$line = 1;

while (($row = fgetcsv($handle, 0, ',', '"')) !== FALSE) {

foreach($row as $key => $value) {    

if ($line === 1) {
$keys[$key] = $value;       
} else {       
$out[$line][$key] = $value;              
}       
}                
$line++;          
}        

fclose($handle);            

if (!empty($keys) && !empty($out)) {        
$db = new PDO(
'mysql:host=host;dbname=db', 
'user', 
'pw');   

$db->exec("SET CHARACTER SET utf8");        

foreach($out as $key => $value) {        
$sql  = "INSERT INTO `table` (`";
$sql .= implode("`player_id`", $keys);    
$sql .= "`) VALUES (";    
$sql .= implode(", ", array_fill(0, count($keys), "?"));    
$sql .= ")";    
$statement = $db->prepare($sql);    
$statement->execute($value);       
}      

$message = '<span>File has been uploaded successfully</span>';      
}
}
}
} else {
$message = '<span>Only .csv file format is allowed</span>';
}
} else {
$message = '<span>There was a problem with your file</span>';
}
}
ob_flush();?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8" />
<title>CSV File Upload</title>
</head>
<body>

<form class="form" action="" method="post" enctype="multipart/form-data">
<h3>Select Your File</h3>
<p><?php echo $message; ?></p>
<input type="file" name="file" id="file" size="30" />
<br/>
<label>Event Name:</label><input name="event_name" type="text" value="" />
<br/>
<label>Event Type:</label><input name="event_type" type="text" value="" />
<br/>
<input type="submit" id="btn" class="button" value="Submit" />
</form>

<br/>
<h3>Results:</h3>
<?php do { ?>
<p><?php echo $row_get_players['player_id'];?></p>
<?php } while ($row_get_players = mysql_fetch_assoc($get_players)); ?>
</body>
</html>

I'm not sure how this would be done with php or something else, what I want is to have a button and when the button is pressed it creates a drop down menu and if it's pressed again then it creates a second drop down menu.  I've been googling but haven't found anything yet if someone has an idea or a tutorial that they could direct me to that would be very helpful!!!!

Any help is greatly appreciated, thanks in advance!!!

Hi,
I am developing a web application using PHP and MySQL. I am filling my combobox with the value fetched from the MySQL database. I want to retain the selected value of the combo box in postback. I am able to do it with the statiic values. But in this case I am binding the combbox   dynamically with the values from the database. Can anybody please help me?
Thanks,
Regards,
Viji

not sure if this will find an answer but I am posting anyway. Any help is appreciated....my coder has left the team and no matter how I invite her to come and do some bug squashing, her new schedules won't fit a re-visit into my little aplication...I am eager to delve into the codes at my very low knowledge of php. I have initiated reading and is still trying to teach myself...but of course not as fast as the app needs the patch...here's the meat:

Hi,   I have the following submit button and would like to change it into a link with a class.  

<input type="image" alt="Click here to Continue" name="I2" src="altimages/buttons/continue.gif" id="submit">

  How would I do this using jQuery?   Thanks!

I have a form where I have inserted 7 pre-populated relational lists.  All of the information is pulling correctly from the databases, but when it posts, it's posting the value "ids" instead of the chosen text. 

The files a   www.kcwell.com/gcc_form.php and www.kcwell.com/gccsuccess_form.php

How do I set up a query to obtain the data that I need?  Help!

I have a form and on each input I set the value as the post variable of it's self.  I do this so that if the user submit the form and it has errors they haven't lost the data they have inputted.  For example

<input name="input1" type="text" value="<?php echo($_POST['input1']); ?>" />

This works fine for text field and textarea's but how do I retain the value of radio boxes and checkboxes?

Hi,
I want to submit a form using ajax ans jquery with two fields input text and file.

Code: [Select]
<script>
$(document).ready(
function()
{


$('#basicinfofrm').ajaxForm(function() {
url: ''+PN+'.php',
type:'POST',
data:'action=yes&'+frmFeilds,
success: function(html)
{ 
 alert(html);

}

    }).submit();
</script>
<form action='' method='post'>
    <label>name</label>
    <input type='text' name='txtname' />
    <input type='file' name  = 'txtfile' />
   <input type='submit' value='save' />
</form>

but is is not working...
can anyone tell me how to?
i don't want to refresh my page
Thanks