PHP - Check A Variable For A Word
I was wondering if it is possible to check the content for a variable for a certain work. For example say a variable called "$variable1" was equal to "one, two, three, four, five". How can I check to see if the variable contain the word "four"? Thanks for any help.
Similar Tutorials<?php $title = "This is an example of a sentence in a paragraph"; $title_array = explode(" ", $title); // splits the string by string $chr_count = array(); foreach($title_array AS $word){ $chr_count[] = strlen($word); } echo $chr_count[0]; $count = count($title_array); for($i=0; $i<$count; $i++) { ??????? } ?> i want to store the count for every word in the $title, in a variable, but i get an error. Actually i need the count of every word so that i can store every word which has greater than 5 characters in an array variable! Then i would use this variable to compare words in another paragraph to check whether sentences in the other paragraph contain these words. If they contain these words then i would add the sentence to a variable $summary which would make the summary of the original paragraph. Any ideas please? Im wanting to not allow people to post any links in the comments section of a form (spammers) and have created a comma delimited list of essentially of every known domain name extension. To apply the filter I have the following code: Code: [Select] $WordAllowed = true; $BannedWords = explode(",", ReadDB($Options["ban_words"])); if (count($BannedWords)>0) { $checkComment = strtolower($_REQUEST["comment"]); for($i=0;$i<count($BannedWords);$i++){ $banWord = trim($BannedWords[$i]); if (trim($BannedWords[$i])<>'') { if(preg_match("/".$banWord."/i", $checkComment)){ $WordAllowed = false; break; } } } } if($WordAllowed==false) { $SysMessage = $OptionsLang["Banned_word_used"]; } else { Insert into my table I could have sworn this was working last time I was in this code but recently checking it again it is blocking pretty much everything claiming a banned word is used. The only thing I can get to post is 'lol'. Trying funny phrases like: first! or Great information, thanks, this is a test of the comment section, etc....they all get flagged Can anyone with fresh eyes assist? Im weary and frustrated and its been forever since I wrapped my head around this. My banned word list: Code: [Select] www,http,com,org,.aero,.asia,.biz,.com,.coop,.edu,.gov,.info,.int,.jobs,.mil,.mobi,.museum,.name,.net,.org, .pro,.tel,.travel,.xxx,.a,.bitnet,.ac,.ad,.ae,.af,.ag,.ai,.al,.am,.an,.ao,.aq,.ar,.as,.at,.au,.aw,.az,.ba,.bb,.bd,.be,.bf,.bg ,.bh,.bi,.bj,.bm,.bn,.bo,.br,.bs,.bt,.bv,.bw,.by,.bz,.ca,.cc,.cf,.cg,.ch,.ci,.ck,.cl,.cm,.cn,.co,.com,.cr,.cs,.cu,.cv,.cx,.cy,.cz ,.de,.dj,.dk,.dm,.do,.dz,.ec,.edu,.ee,.eg,.eh,.er,.es,.et,.fi,.fj,.fk,.fm,.fo,.fr,.fx,.ga,.gb,.gd,.ge,.gf,.gh,.gi,.gl,.gm,.gn ,.gov,.gp,.gq,.gr,.gs,.gt,.gu,.gw,.gy,.hk,.hm,.hn,.hr,.ht,.hu,.id,.ie,.il,.in,.io,.iq,.ir,.is,.it,.jm,.jo,.jp,.ke,.kg,.kh,.ki,.km ,.kn,.kp,.kr,.kw,.ky,.kz,.la,.lb,.lc,.li,.lk,.lr,.ls,.lt,.lu,.lv,.ly,.ma,.mc,.md,.mg,.mh,.mil,.mk,.ml,.mm,.mn,.mo,.mp,.mq,.mr, .ms,.mt,.mu,.mv,.mw,.mx,.my,.mz,.na,.nc,.ne,.net,.nf,.ng,.ni,.nl,.no,.np,.nr,.nt,.nu,.nz,.om,.org,.pa,.pe,.pf,.pg,.ph, .pk,.pl,.pm,.pn,.pr,.pt,.pw,.py,.qa,.re,.ro,.ru,.rw,.sa,.sb,.sc,.sd,.se,.sg,.sh,.si,.sj,.sk,.sl,.sm,.sn,.so,.sr,.st,.su,.sv, .sy,.sz,.tc,.td,.tf,.tg,.th,.tj,.tk,.tm,.tn,.to,.tp,.tr,.tt,.tv,.tw,.tz,.ua,.ug,.uk,.um,.us,.uy,.uz,.va,.vc,.ve,.vg,.vi,.vn,.vu,.wf, .ws,.ye,.yt,.yu,.za,.zm,.zr,.zw Thanks in advance for any help Hi , I have a login page that i acces via www.mydomain.com/logib.php?last_visited_page.php however the passed in variable last_visited_page.com is not always set . once the login script has run , when the variable it is not set i would want jump to myaccount.php otherwise jump to last_visited_page.php How do i check for no variable beinf present and therefore jump to myaccount.php Many Thanks Fraser I want an if statement that not only checks for the existence of a variable, but which also checks all the variables already created for one with a specific value. For example, I have a loop which creates variables, but I don't want it to make two variables with the same value. The problem is, using
if(isset(${'h'.$x}==false) && ${'h'.$x} != 3{ }won't work since the variable equal to 3 could be named h4, whereas this one will be named h5. I hoped I explained this efficiently enough, sorry about any confusion. i am pulling the login date from the databases and i want it to check if the variable is empty and if it is echo Never Loged In and if it not empty echo the date <?php include'db.php'; $id=$_GET['id']; $sql=mysql_query("SELECT * FROM admin WHERE id='$id'")or die(mysql_error()); while($row=mysql_fetch_array($sql)) { $date=$row['login_date']; if($date > 0) { echo"Never Loged In"; } else { echo"$date"; } } ?> Hello, how do you search for a filename containing a date and then match it to a variable? Please note the filename may only contain some of the variable being matched to. Any help appreciated... if ($d = opendir("uploads")) { while ($file = readdir($d)) { if ($file != "." && $file != ".." ) // if( is_file($file) ) { $files[] = $file; } } closedir($d); }if ($file != "." && $file != ".." $file != ???????? ) just a bit stuck here $showCountSql = "select cad_count from counteraccountdtl WHERE cad_userid =".$_SESSION['UID']." LIMIT 1"; $showCountresult = mysql_query($showCountSql); $showCountrow = mysql_fetch_array($showCountresult); $newCount = $showCountrow[cad_count]; if(is_int($newCount)) echo "Value is Integer"; else echo "Value not Integer"; i m fetching value by Mysql "cad_count integer(5)" and feild then i cheak this value is interger or not it show the "Value not Integer". What is wrong in it ??? Hi, How can I check if a variable only has these characters: - number (0-9) - decimal point (.) - positive (+) - negative (-) - dollar ($) I tried is_numeric, but it doesn't like negative values... I need to add the variable value to another variable. I have to accept numbers (including negative and decimals)... ex: 0.1 = TRUE -.1 = TRUE 12 = TRUE 1000.00 = TRUE 12a = FALSE thanks I have the following if statement: Code: [Select] if ((isset($select_category) == 'All') || (!isset($select_category)) && (!isset($most_liked))) { The value for the variable gets taken from a drop down menu, which is a list of categories. The problem I am having is with the isset condition check is that the variable is always set, but it does not consider the check for equality with the 'All' condition. Which basically means no matter which category I choose from the drop down menu, it always goes to this very first if statement, and does NOT go to the other elseif statement, and I think it has to do with the isset condition check, because without it it would work, though without it I am getting a notice warning, that the variables are undefined. Any ideas how I can make it check if its equal to 'All' together with the isset condition check? What I am trying to say is no matter which category is chosen, with the isset condition check, the variable is always set, thus the if statement is true, there basically seems to be a contradiction going on. Hey all, Let's say I want to do something like this: Code: [Select] <?php function exists($a){ $b ||= $a; } echo exists(1); ?> Basically, every time exists is called, it will only assign b to a if b isn't already initialized. What's the most effective way to achieve the equivalent in php? ternary? Thanks for response. Code: [Select] <?php session_start(); $index="1"; $_SESSION[$index]=2; echo "$_SESSION[$index]"; ?> Hi good day check how to have a variable "$index" inside session.. Hello all. I am very new to PHP, and I am not sure where to look or what I'm looking for in my current assignment. My task is to take in two numbers between 0-100. Once I take in that number, it should state beside it "The __ was accepted." The program should not accept any numbers greater than 100 or any characters. Once I do this, I must take a second number and do a similar thing. Finally, I must have a statement show up at the bottom stating which number is greater. Essentially, I need help in determining what I should use to place parameters, and how I can keep the program from echo ing any statement until input has been taken and tested for parameters. Any help you can provide will be greatly appreciated! I am trying to allow the user to update a variable he chooses by radio buttons, which they will then input text into a box, and submit, to change some attributes. I really need some help here. It works just fine until I add the second layer of variables on top of it, and I can't find the answer to this question anywhere. <?PHP require('connect.php'); ?> <form action ='' method='post'> <select name="id"> <?php $extract = mysql_query("SELECT * FROM cars"); while($row=mysql_fetch_assoc($extract)){ $id = $row['id']; $make= $row['make']; $model= $row['model']; $year= $row['year']; $color= $row['color']; echo "<option value=$id>$color $year $make $model</option> ";}?> </select> Which attribute would you like to change?<br /> <input type="radio" name="getchanged" value="make"/>Make<br /> <input type="radio" name="getchanged" value="model"/>Model<br /> <input type="radio" name="getchanged" value="year" />Year<br /> <input type="radio" name="getchanged" value="color" />Color<br /><br /> <br /><input type='text' value='' name='tochange'> <input type='submit' value='Change' name='submit'> </form> //This is where I need help... <?PHP if(isset($_POST['submit'])&&($_POST['tochange'])){ mysql_query(" UPDATE cars SET '$_POST[getchanged]'='$_POST[tochange]' where id = '$_POST[id]' ");}?> I'm going to post the code that I am currently using and then explain what I'm trying to do. I hope I can explain it well enough. <?php if (!isset($_POST['submit'])) { echo'<leftmargin="0" topmargin="0" rightmargin="0" bottommargin="0"> <center><form name="fairlistlist" method="POST" action="'.$_SERVER['PHP_SELF'].'"> <TABLE width="450" height="119" border=0 cellPadding=3 cellSpacing=2 bgcolor="#fff568"> <TBODY> <TR> <TD class=mainText width="100"><b>Event Name</b></TD> <TD width="305" class=frmInput> <INPUT class=mainFormBox style="WIDTH: 320px" type="text" name=" fairname"></TD> </TR> <TR> <TD class=mainText width="100"><B>Event Address</B></TD> <TD class=frmInput> <INPUT name="fairadd" type="text" class=mainFormBox id="fairadd" style="WIDTH: 320px"></TD> </TR> <TR> <TD class=mainText width="100"><b>Event City</b></TD> <TD class=frmInput> <INPUT name="faircity" type="text" class=mainFormBox id="faircity" style="WIDTH: 320px"></TD> </TR> <TR> <TD class=mainText width="100"><b>Event County</b></TD> <TD class=frmInput> <INPUT name="faircty" type="text" class=mainFormBox id="faircty" style="WIDTH: 320px"></TD> </TR> <TR> <TD class=mainText width="100"><b>Event State</b></TD> <TD class=frmInput> <INPUT name="fairstate" type="text" class=mainFormBox id="fairstate" style="WIDTH: 320px"></TD> </TR> <TR> <TD class=mainText width="100"><b>Event Country</b></TD> <TD class=frmInput> <INPUT name="fairctry" type="text" class=mainFormBox id="fairctry" style="WIDTH: 320px"></TD> </TR> <TR> <TD class=mainText width="100"><b>Event Opening Date</b></TD> <TD class=frmInput> <INPUT name="fairopen" type="text" class=mainFormBox id="fairopen" style="WIDTH: 320px"></TD> </TR> <TR> <TD class=mainText width="100"><b>Event Closing Date</b></TD> <TD class=frmInput> <INPUT name="fairclose" type="text" class=mainFormBox id="fairlose" style="WIDTH: 320px"></TD> </TR> <TR> <TD class=mainText width="100"><b>Event Contact Email</b></TD> <TD class=frmInput> <INPUT name="fairmail" type="text" class=mainFormBox id="fairmail" style="WIDTH: 320px"></TD> </TR> <TR> <TD class=mainText width="100"><b>Event Website</b></TD> <TD class=frmInput> <INPUT name="fairweb" type="text" class=mainFormBox id="fairweb" style="WIDTH: 320px"></TD> </TR> <TR> <TD class=frmDescription width="56"> </TD> <TD class=frmInput> <div align="right"> <input type="submit" name="submit" value="Add my Event" /> </div></TD> </TR> </TBODY> </TABLE> </form></center> </body>'; //note that I added a new field called submit and it's hidden .. } else { /*I added addslashes() so it escape any special char in the form .. if you want to show your inserted record , you need to use stripslashes() to remove any slashes from the record .. this is only to avoid some security problems in the query ..*/ $fairname=trim(addslashes($_POST['fairname'])); $fairadd=trim(addslashes($_POST['fairadd'])); $faircity=trim(addslashes($_POST['faircity'])); $faircty=trim(addslashes($_POST['faircty'])); $fairstate=trim(addslashes($_POST['fairstate'])); $fairctry=trim(addslashes($_POST['fairctry'])); $fairopen=trim(addslashes($_POST['fairopen'])); $fairclose=trim(addslashes($_POST['fairclose'])); $fairmail=trim(addslashes($_POST['fairmail'])); $fairweb=trim(addslashes($_POST['fairweb'])); include("Connections/local.php"); $link = mysql_connect($hostname_local,$username_local, $password_local) or die("Could not connect"); mysql_select_db('fair123') or die("Could not select database"); $insert=mysql_query("INSERT INTO events (fairidnum, fairname, fairadd, faircity, faircty, fairstate, fairctry, fairopen, fairclose, fairmail, fairweb) VALUES('NULL', '$fairname', '$fairadd', '$faircity', '$faircty','$fairstate', '$fairctry','$fairopen', '$fairclose', '$fairmail', '$fairweb')")or die('couldn\'t Insert record into database :'.mysql_error()); header( 'Location: event_added.php' ) ; } ?> Especially look at the code part here $insert=mysql_query("INSERT INTO events (fairidnum, fairname, fairadd, faircity, faircty, fairstate, fairctry, fairopen, fairclose, fairmail, fairweb) VALUES('NULL', '$fairname', '$fairadd', '$faircity', '$faircty','$fairstate', '$fairctry','$fairopen', '$fairclose', '$fairmail', '$fairweb')")or die('couldn\'t Insert record into database :'.mysql_error()); header( 'Location: event_added.php' ) ; } ?> this is where I am having problems it was reading echo your record has been successfully added to the database What I want is for it to open up a new page with my menu and my css and all that good crap to a page where it will read the following Your information has been added to our database We have added Event name = "whatever the event's name was" Event address = "address:" so on and so on for all the fields in my form that was submitted to the database. with just using the echo command it always opened to just a blank page no formatting and no css as well as no all important links Can you please tell me what I'm doing wrong or where I can find a good guideline that Is easy to understand on how to do this? Thanks in advance Oh also I don't care if that page get's indexed by google or yahoo or not actually prefer it don't get indexed to be honest Hi guys, I'm trying to export records from php to ms word which appends text + image. i have got this code from http://www.thaicreate.com/php/php-word.application-addpicture.html Code: [Select] <html> <head> <title>ThaiCreate.Com PHP Word.Application Tutorial</title> </head> <body> <? $wdColorDarkRed = "&H80"; $wdAlignParagraphCenter = "1"; $wdAlignParagraphLeft = "0"; $wdParagraph = "4"; $wdHorizontalPositionMargin = "0"; $wdTableLeft = "-999998"; $wdCollapseEnd = "0"; $Wrd = new COM("Word.Application"); $DocName = "MyDoc/MyWord.doc"; //$strPath = realpath(basename(getenv($_SERVER["SCRIPT_NAME"]))); // C:/AppServ/www/myphp $Wrd->Application->Visible = False; $WrdDoc = $Wrd->Documents->Add(); $MyRange1 = $WrdDoc->Paragraphs->Add->Range; $MyRange1->ParagraphFormat->Alignment = $wdAlignParagraphCenter; $MyRange1->Font->Name = "Verdana"; $MyRange1->Font->Size = "30"; $MyRange1->Font->Bold = True; $MyRange1->InsertBefore(chr(13).chr(13)."www.ThaiCreate.Com".chr(13)."Version 2009"); $MyRange1->InlineShapes->AddPicture(realpath("thaicreate-2009.gif")); //$WrdDoc->InlineShapes->AddPicture(realpath("thaicreate-2009.gif")); //$WrdDoc->Shapes->AddPicture(realpath("thaicreate-2009.gif"),0,0,MyRange1); //$WrdDoc->Shapes->AddPicture(realpath("thaicreate-2009.gif"),0,0,Wrd->Selection->Range); $MyRange2 = $WrdDoc->Paragraphs->Add->Range; $MyRange2->ParagraphFormat->Alignment = $wdAlignParagraphCenter; $MyRange2->Font->Name = "Verdana"; $MyRange2->Font->Size = "15"; $MyRange2->Font->Bold = True; $MyRange2->InsertBefore(chr(13).chr(13)."PHP,ASP and ASP.NET Tutorial"); $MyRange2->InlineShapes->AddPicture(realpath("doc.gif")); $MyRange3 = $WrdDoc->Paragraphs->Add->Range; $MyRange3->ParagraphFormat->Alignment = $wdAlignParagraphCenter; $MyRange3->Font->Name = "Verdana"; $MyRange3->Font->Size = "10"; $MyRange3->Font->Bold = True; $MyRange3->Font->Color = $wdColorDarkRed; $MyRange3->Underline = True; $MyRange3->InsertBefore(chr(13).chr(13).chr(13).chr(13)."All Rights Reserved"); //$WrdDoc->SaveAs($strPath."/".$DocName); $WrdDoc->SaveAs(realpath($DocName)); $Wrd->Application->Quit; $Wrd = null; ?> Word Created <a href="<?=$DocName?>">Click here</a> to Download. </body> </html> This is the best code i've found so far that guides on how to format the text in ms word via PHP. All set to go but one thing that I am trying to accomplish : to have a clickable email address (hyperlink) in the same ms word file. i have got this code somewhere from the net: Code: [Select] $MyRange3->Hyperlinks->Add({range}, 'http://www.google.com', '','',' hyperlink text to display'); // where {range} refers to as anchor according to that website this methods could be found in ms word visual basic editor (Alt+F11) then object browser (F2) when i replace the {range} above with let say variable $MyRange3. Code: [Select] $MyRange3->Hyperlinks->Add($MyRange3, 'http://www.google.com', '','',' hyperlink text to display'); The output will be produced but overwriting everything in $MyRange3 and displays only the hyperlink. I would like the email address (hyperlink) to appear at the end of $MyRange3 text. example output Code: [Select] All right reserved [u]hyperlink text to display[/u] anyone can shed some light on this. Hey guys i found this script that works great for what i need .. se i have this script that i did for my body (loan application) now i would like to export the info in a word doc <?php $ExcelFileName="test.doc"; header("Content-type: application/x-ms-download"); header("Content-Disposition: attachment; filename=$ExcelFileName"); header('Cache-Control: public'); $content=<<<EOD echo 'php'; whatever you want to write here including a php script it will be included in a string and then go in the output for a doc file EOD; echo $content; ?> so im trying to eco all the content in the database.. i tryed all the DB connection is there.. ao i place this after the (echo 'php' while($info = mysql_fetch_array($fileLIST)){; echo $info['PERS_F_NAME']; }; i get this? Parse error: syntax error, unexpected T_ENCAPSED_AND_WHITESPACE, expecting T_STRING or T_VARIABLE or T_NUM_STRING in /home/autosspe/public_html/admin/loan/word.php on line 21 I have this code below the browser shows correct data but when i export to word I see $proc output not the switch data like on the the browser page
How should code be written to show the same on word doc .
I'm new to this learning by trial and error Please go easy on me .
Thanks
<td> <? I have just re-installed Xampp and suddenly my sites are now displaying lots of: Notice: Use of undefined constant name - assumed 'name' in ... Notice: Use of undefined constant price - assumed 'price' in ... this is an example of the line its refering too: $defineProducts[1001] = array(name=>'This is a product', price=>123); My login script stores the user's login name as $_SESSION[ 'name'] on login. For some unapparent reason, i'm getting errors stating that $user and $priv are undefined variables, though I've attempted to define $user as being equal to $_SESSION['name'], using $user to look up the the user's privilege level (stored as the su column ) in the SQL table, and then where the result of the sql query is $priv which is then evaluated in an if statement. I can't seem to figure out why this might not be working. The code I'm using: <?php session_start(); function verify() { //verify that the user is logged in via the login page. Session_start has already been called. if (!isset($_SESSION['loggedin'])) { header('Location: /index.html'); exit; } //if user is logged in, we then lookup necessary privleges. $_SESSION['name'] was written with the login name upon login. Privleges // are written in db as a single-digit integer of of 0 for users, 1 for administrators, and 2 for special users. $user === $_SESSION['name']; //Connect to Databse $link = mysqli_connect("127.0.0.1", "database user", "password", "database"); if (!$link) { echo "Error: Unable to connect to MySQL." . PHP_EOL; echo "Debugging errno: " . mysqli_connect_errno() . PHP_EOL; echo "Debugging error: " . mysqli_connect_error() . PHP_EOL; exit; } //SQL Statement to lookup privlege information. if ($result = mysqli_query($link, "SELECT su FROM accounts WHERE username = $user", MYSQLI_STORE_RESULT)) { //LOOP TO CYCLE THROUGH SQL RESULTS AND STORE Privlege information as vairable $priv. while ($row = $result->fetch_assoc()) { $priv === $row["su"]; } } // close SQL connection. mysqli_close($link); // Verify privleges and take action. Only a privlege of "1" is allowed to view this page. A privlege of "2" indicates special //accounts used in other scripts that have certain indermediate additional functions, but are not trusted administrators. if ($priv !== 1) { echo $_SESSION['name']; echo "you have privlege level of $priv"; echo "<br>"; echo 'Your account does not have the privleges necessary to view this page'; exit; } } verify(); ?>
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