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PHP - Wondering About New Line Behaviour.
I have 2 pieces of different code that get run at different times, but act on the same text file.
(The first example writes data and the second rewrites data with some expired data removed from the rewrite.) The first code example appends data to a new line each time it is run except when it is run just after the second code example has ran. When run after the second example, the first code example will append the data to the last line of the text file instead of appending to a new line. Why is this? Here is the first code example... Code: [Select] <?php $message = "Hello, World! \nGoodbye!"; $message_br = str_replace("\n", '<br />', $message); // couldn't use nl2br because i needed to remove the \n completely. $userName = "Anon"; $coordinates = "1234567890"; $locationType = "geo"; $dateDay = "23"; $dateMonth = "2"; $dateYear = "2011"; $timeHour = "9"; $timeMins = 45; $timeAMPM = "AM"; // Format the time/Date date_default_timezone_set('UTC'); $inputTime = date('c', mktime((int)$timeHour, (int)$timeMins, 0, (int)$dateMonth, (int)$dateDay, (int)$dateYear)); // Send all data so far, to an array. $entry_array = array(); array_push($entry_array, $inputTime, $locationType, $coordinates, $userName, $message_br); // write the array to CSV file. $fp = fopen('messages.txt', 'a'); fputcsv($fp, $entry_array, "|"); fclose($fp); ?> Here is the second... Code: [Select] <?php $one_day = 60*60*24; $timestamp = time(); date_default_timezone_set('UTC'); $expiry_date = date('c', $timestamp+$one_day); $future_date = array(); $delete_line = array(); // Open existing data in the text file. $lines = file('messages.txt', FILE_IGNORE_NEW_LINES | FILE_SKIP_EMPTY_LINES); foreach ($lines as $line){ list($field1, $field2, $field3, $field4, $field5) = explode('|', $line); if ($field1 < $expiry_date){ array_push($delete_line, $line); // add to the to-be-deleted array. } else { array_push($future_date, $line); } } $array2string = implode("\n", $future_date); // convert array data to string. // write the data to CSV file. $fp = fopen('messages.txt', 'w'); fwrite($fp, $array2string); fclose($fp); ?> Similar TutorialsJust wondering if I have an if statement like: if ( true || true || true ) { // do this } Is PHP clever enough to do this: if ( true || skip_me|| skip_me) { // do this } if ( false || true || skip_me ) { // do this } Like precedence for the leftmost conditions? Thanks for any help. Hey guys wondering if this is possible or not im wanting to add the b_x with the b_y so i select it out of the data base as 1 number. The math im really going to do is more complex but just using add to simplifly what i want to do. i would obviously need to assign it in some way so I can grab it to like $variable = $star_check1[]; This will acctually become a loop grabing several rows so if i could change it into one number would be alot easier. $star_check3 = "SELECT b_x,b_y FROM planets WHERE x = '".($x)."' AND y = '".($y)."'"; $star_check2 = mysql_query($star_check3) or trigger_error("SQL", E_USER_ERROR); $star_check1 = mysql_fetch_array($star_check2); What is the difference between EXTR_PREFIX_SAME and EXTR_PREFIX_IF_EXISTS? I don't know if this is the correct type of question to ask here - I built a sandbox about 3 months ago with the latest XAMPP. I know that it came with PHP 5.x [5.2 I think]. I am not at home right now to check it. I just found out that the host server is running 4.4.9. I have no control over the host, or host selection. I am going to attempt to get a database online using basic [I hope] PHP scripts to query the otherwise static database. Are there major differences in the versions that I need to watch out for? I realize that I will now have to get 4.4.9 installed on my sandbox. I plan on using Dreamweaver CS5 to get my pages built. The main site is built and managed by another person using Expression Web 2. I am also unaware if the master.dwt built in Expression can be somehow brought into my PHP for site consistency. I am open to all comments and suggestions. Hi, I have a form that I am trying to get working. The page is named "reserv_test.php". Not sure if I am trying to do to much, but can anyone tell me if this will work? If so, what do I need to do to make it work? Here is the code... Code: [Select] <html> <head> <title>Booking Form</title> <script type="text/javascript"> function showMonth(str) { if (str=="") { document.getElementById("txtHint").innerHTML=""; return; } if (window.XMLHttpRequest) {// code for IE7+, Firefox, Chrome, Opera, Safari xmlhttp=new XMLHttpRequest(); } else {// code for IE6, IE5 xmlhttp=new ActiveXObject("Microsoft.XMLHTTP"); } xmlhttp.onreadystatechange=function() { if (xmlhttp.readyState==4 && xmlhttp.status==200) { document.getElementById("txtHint").innerHTML=xmlhttp.responseText; } } xmlhttp.open("GET","reserv_test.php?q="+str,true); xmlhttp.send(); } </script> </head> <body> <div> <p align="left"><font face="arial" size="4"><u>Booking Form</u></font></p> <form method="post" action="resersend.php"> <p><font face="arial" size="2" color="#336600">Reservation month:</font> <select name="months" onChange="showMonth(this.value)"> <option value="" selected="selected">Choose One</option> <option value="May 2011">May 2011</option> <option value="June 2011">June 2011</option> <option value="July 2011">July 2011</option> <option value="August 2011">August 2011</option> <option value="September 2011">September 2011</option> <option value="October 2011">October 2011</option> <option value="November 2011">November 2011</option> <option value="December 2011">December 2011</option> <option value="January 2012">January 2012</option> <option value="February 2012">February 2012</option> <option value="March 2012">March 2012</option> <option value="April 2012">April 2012</option> </select> </form></p><br /> <?php $q=$_GET["q"]; $con = mysql_connect('my_host', 'my_user', 'my_pwd'); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("my_db", $con); $sql="SELECT * FROM daterange WHERE DEND > DATE(NOW()) AND STATUS='A' AND MONTH = '".$q."' ORDER BY RID, DATE, SITE"; $result = mysql_query($sql); // Determine the number of reservation dates $number = mysql_numrows($result); // Create drop-down menu of reservation dates print "<font size=\"3\" face=\"Arial\"><b>Select Your Reservation:</b><br> <form action=\"resersend.php\" method=\"post\"> <select name=\"RID\"> <option value=\"\">Choose One</option>"; for ($i=0; $i<$number; $i++) { $RID = mysql_result($result,$i,"RID"); $DATE = mysql_result($result,$i,"DATE"); $SITE = mysql_result($result,$i, "SITE"); $PRICE = mysql_result($result,$i, "PRICE"); print "<option value=\"$RID\">$DATE, $SITE, $PRICE</option>"; } print "</select><p align=left><label><font size=\"3\" face=\"Arial\">First Name: <input type=\"text\" name=\"FNAME\" size=\"50\" maxlength=\"50\" tabindex=\"1\"<br>"; print "<p align=left><label>Last Name: <input type=\"text\" name=\"LNAME\" size=\"50\" maxlength=\"50\" tabindex=\"2\"<br>"; print "<p align=left><label>Address Line 1: <input type=\"text\" name=\"ADDR1\" size=\"50\" maxlength=\"50\" tabindex=\"3\"<br>"; print "<p align=left><label>Address Line 2: <input type=\"text\" name=\"ADDR2\" size=\"50\" maxlength=\"50\" tabindex=\"4\"<br>"; print "<p align=left><label>City: <input type=\"text\" name=\"CITY\" size=\"50\" maxlength=\"50\" tabindex=\"5\"<br>"; print "<p align=left><label>State (abbrev.): <input type=\"text\" name=\"STATE\" size=\"2\" maxlength=\"2\" tabindex=\"6\"<br>"; print "<p align=left><label>Zip Code: <input type=\"text\" name=\"ZIP\" size=\"5\" maxlength=\"5\" tabindex=\"7\"<br>"; print "<p align=left><label>Contact Phone Number: (<input type=\"text\" name=\"PHONE1\" size=\"3\" maxlength=\"3\" tabindex=\"8\""; print "<label>)<input type=\"text\" name=\"PHONE2\" size=\"3\" maxlength=\"3\" tabindex=\"9\""; print "<label>-<input type=\"text\" name=\"PHONE3\" size=\"4\" maxlength=\"4\" tabindex=\"10\"<br>"; print "<p align=left><label>Email: <input type=\"text\" name=\"EMAIL\" size=\"50\" maxlength=\"50\" tabindex=\"11\"<br>"; Any help would be appreciated. Thanks. I'm having a lot of trouble validating things using custom regex. I'm trying to validate usernames without spaces using numbers and/or letters with optional underscores. This is my code but it isn't validating anything, nothing is ever validated. Whatever I write it says the username isn't valid. if(isset($_POST['submit'])){ if(filter_var($_POST['value1'], FILTER_VALIDATE_REGEXP, array("options"=>array("regexp"=>"/^[\w.-]{{3},{28}}$/")))){ echo "Value is a valid username."; } else { echo "Value is NOT a valid username."; } } ?> Any help regarding this issue will be greatly appreciated. Thanks! Commented in red is the code that doesn't produce anything. It is 3/4 of the way down the page.. Thanks for looking! Code: [Select] <?php error_reporting(E_ALL); ini_set("display_errors", 1); $host= ""; $db_name= ""; $db_user= ""; $db_password= ""; ob_start(); if(isset($_POST['newBidder'])) { $newBidder= isset($_POST['newBidder']) ? $_POST['newBidder'] : ''; $bidderId= $newBidder; mysql_connect("$host", "$db_user", "$db_password")or die("cannot connect to server"); mysql_select_db("$db_name")or die("cannot select DB"); $sql="SELECT * FROM bidders WHERE biddersId='$bidderId'"; $result=mysql_query($sql); // Mysql_num_row is counting table row $count=mysql_num_rows($result); // If result matched $myusername and $mypassword, table row must be 1 row if($count==0){ // Add $biddersId and redirect to anypage mysql_Query("INSERT INTO bidders (biddersId) VALUES ('$bidderId')"); header("Location: index.php"); exit(); } } //////////////////////////////////// if(isset($_POST['deleteBidder'])) { $deleteBidder= isset($_POST['deleteBidder']) ? $_POST['deleteBidder'] : ''; mysql_connect("$host", "$db_user", "$db_password")or die("cannot connect to server"); mysql_select_db("$db_name")or die("cannot select DB"); mysql_query("DELETE FROM bidders WHERE biddersId='$deleteBidder'"); header("Location: index.php"); exit(); } //////////////////////////////////// if (isset($_POST['itemDescription'], $_POST['itemPrice'], $_POST['winningBidder'], $_POST['itemQty'])) { $itemDescription= isset($_POST['itemDescription']) ? $_POST['itemDescription'] : ''; $itemPrice= isset($_POST['itemPrice']) ? $_POST['itemPrice'] : ''; $winningBidder= isset($_POST['winningBidder']) ? $_POST['winningBidder'] : ''; $itemQty= isset($_POST['itemQty']) ? $_POST['itemQty'] : ''; mysql_connect("$host", "$db_user", "$db_password")or die("cannot connect to server"); mysql_select_db("$db_name")or die("cannot select DB"); $sql="SELECT * FROM bidders WHERE biddersId='$winningBidder'"; $result=mysql_query($sql); $count=mysql_num_rows($result); // If result matched, table row must be 1 row if($count==0){ echo "That Bidder Number is NOT logged in, "; echo "would you like to set this bidder as active?"; echo " Enter 1 for NO or 2 for YES"; echo "<form action= \"process.php\" method= \"POST\">"; echo "<input type =\"text\" name= \"logUser\"/>"; echo "<input type= \"submit\" value = \"Submit\"/>"; exit(); } } $logUser= isset($_POST['logUser']) ? $_POST['logUser'] : ''; if ($logUser= '1') { header("Location: inprogress.php"); exit(); } if ($logUser= '2'){ // Add $biddersId and redirect to anypage mysql_connect("$host", "$db_user", "$db_password")or die("cannot connect to server"); mysql_select_db("$db_name")or die("cannot select DB"); mysql_Query("INSERT INTO bidders (biddersId) ////This won't add biddersid to database///////[ VALUES ('$winningBidder')"); mysql_query("INSERT INTO transactions /////This won't add details to the database either?///// VALUES('$itemDescription', '$itemPrice','$winningBidder', '$itemQty', '$totalPrice')") or die(mysql_error()); header("Location: inprogress.php"); exit(); } //////////////////////////////////////// echo "<font color= \"red\" face=\"calibri\" size=\"4\">That bidder is already logged, Please press your browsers back button and try again.</font>"; ob_end_flush(); ?> I have one database with 2 tables as follows bidders table ONLY has biddersId field; transactions has (in order) itemDescription, itemPrice, bidderId, itemQty, totalPrice everything else works, except updating the database with the above? Am I doing something wrong in MySql. I have all eroors on , but i get NONE when running the script? I think I put this in the wrong forum, as it seems to be more of a php problem (I think) I'm trying to populate a profile page with information from the database. Really bizarrely, every $row variable that isn't null returns as 'website', which is the database username. I have absolutely no idea why this is. It might be worth noting I have just changed hosts...the only thing I can think might make a difference. Any help would be great, thankyou $query = "SELECT * FROM member WHERE username='$member'"; $result = mysqli_query ($dbc, $query) or trigger_error ("query: $query\n<br />MySQL Error: " . mysqli_error($dbc)); if ($result) { while ($row = mysqli_fetch_array($result, MYSQLI_ASSOC)) { $member_id = $row['member_id']; $username = $row['username_id']; $photo = $row['photo']; $about = $row['about']; $slink = $row['soundcloud_link']; $mlink = $row['mixcloud_link']; $flink = $row['facebook_link']; $dlink = $row['divshare_link']; $mylink = $row['myspace_link']; $plink = $row['postbocks_links']; $website = $row['personal_website']; $type = $row['member_type']; $status = $row['status']; } } } I've echo'd the $query and put the result into sql directly and it comes out fine. I have a development machine running WAMP on a win7 64 bit box. php 5.3.13
I have a server that runs Apache 2.2, php 5.3.12 MySql, etc.
I am running joomla 2.5.27 on both machines.
I require a number of php includes to many of the joomla articles (this works great via a plugin called Directphp)
After considerable time getting the site fully working on the dev machine, I ran into an unforseen problem when I uploaded to the production box.
For some unknown reason, the includes work fine on the dev machine using $DOCUMENT_ROOT to define the root (then tag the correct path and file to this)
However, on the production box, this doesn't work - but... $_SERVER['DOCUMENT_ROOT'] does.
Annoyingly, $_SERVER['DOCUMENT_ROOT'] won't work on the dev machine - and $DOCUMENT_ROOT doesn't work on the production box.
So, I can't come up with a generic method to keep both machines happy.
I've checked the php.ini files on both boxes and the register global is OFF on both.
They also seem to interperate the syntax differently in the actual include files - one box hates double quotes - the other has issues with single quotes.
This is really annoying as most of the includes are HTML snippets, coded into php.
The double/single quote problem means I would need to have two versions of the include files.
Can anyone help me with this? - serious hair pulling has started!
I have something strange going on with sessions set after a user logs in. After posting the form, the following code (only part of the log in script) correctly assigns the users ID to $_SESSION['id'] but after a while it starts showing up as the users level ($_SESSION['level']). I have rechecked all of my code to see if something mistakenly assigns the level to $_SESSION['id'] but everything seems fine. I am going to rewrite the log in script today, as I am sure that I can streamline it but wondered if anyone can give any advice on what it happening here to make sure I do not fall into the same trap! Thanks Steve $username = mysql_escape_string($_POST['Lname']); $password = mysql_escape_string(md5($_POST['Lpassword'])); $search = mysql_query("SELECT userid, username, password, active, level FROM users WHERE username like binary '".$username."' AND password='".$password."' AND active='1'") or die(mysql_error()); $match = mysql_num_rows($search); $level = mysql_fetch_assoc($search); if($match > 0) //The username and password is correct {//START MANUAL LOGIN & SET SESSION VARIABLES $_SESSION['user'] = $username; $_SESSION['level'] = $level['level']; $_SESSION['loggedin'] = '1'; $_SESSION['id'] = $level['userid']; Please help. I have tried to condense the following code to make it easier for someone to shed insight. The results make totally no sense to me.
I have the following two lines of code:
require_once('/var/www/bidjunction/application/classes_3rd/htmlpurifier/library/HTMLPurifier.auto.php');
$config = HTMLPurifier_Conf::createDefault();
Let me explain what happens in these two lines of code. First....
require_once('/var/www/bidjunction/application/classes_3rd/htmlpurifier/library/HTMLPurifier.auto.php'):
HTMLPurifier.auto.php is shown below:
<?php /** * This is a stub include that automatically configures the include path. */ set_include_path(dirname(__FILE__) . PATH_SEPARATOR . get_include_path() ); require_once 'HTMLPurifier/Bootstrap.php'; require_once 'HTMLPurifier.autoload.php'; // vim: et sw=4 sts=4The only thing Bootstrap.php does is define a class and execute the following line:
define('HTMLPURIFIER_PREFIX', realpath(dirname(__FILE__) . '/..'));
The only thing HTMLPurifier.autoload.php does is execute HTMLPurifier_Bootstrap::registerAutoload() (which was one of the classes defined in Bootstrap.php). The only thing HTMLPurifier_Bootstrap::registerAutoload() does is:
spl_autoload_register(array('HTMLPurifier_Bootstrap','autoload'), true, true);
Now the second line:
$config = HTMLPurifier_Conf::createDefault();I expected that HTMLPurifier_Conf::createDefault() would be executed, but no, instead the script goes to HTMLPurifier_Bootstrap:autoload() which returns false. Next, the script goes to function PHPMailerAutoload() which is in PHPMailerAutoload.php. What!!! What does PHPMailerAutoload have to do with this? While a perfect answer would be great, general comments and a strategy to troubleshoot be the next best thing. I am stumped! Please help. Hi Guys, I am fairly new to PHP, and I recently changed my whole site to use PHP sessions, which worked fine. Then I added PHP parts in my pages that display different menu choices depending on if a PHP session exists. This also works fine, until I found that any HTML/PHP pages that have form/submits no longer work, and I get kicked back to the index.php After slow backtracking, I removed new parts, and found the forms started working again if I removed the PHP part that chooses which JavaScript file to reference, as follows from contact.php <?php if (isset($_SESSION['SESS_MEMBER_ID'])){ echo "<script language=\"JavaScript\" type=\"text/javascript\" src=\"menu_horz.js\"></script>"; } else {echo "<script language=\"JavaScript\" type=\"text/javascript\" src=\"log_menu_horz.js\"></script>"; } ?> I tried changing the echo ".." to use single quotes ' ' instead, but then it doesn't work at all then with a form or no form on the page. I assume I am doing something wrong, but I can't find any resources that give me a definitive way of referencing Javascript files. What freaked me out was only the ones with forms were an issue. I am using <?php session_start(); ?> at the beginning of every page (before any output). Other PHP code on the page is working fine. Only the above part seems to be the problem, and works too, as long as I don't submit a form. - Could it be more weirder :-) - I tried also to find a workaround, but it would mean having PHP inside my JavaScript file, but I am not sure it would work, since JS is client side, and PHP server... Essentially, I just want to run certain JS menus depending if the person is logged in or not. - Example contact.php attached Any ideas of what the problem might be with the code above? Will be grateful for any help you can give. Regards D This topic has been moved to JavaScript Help. http://www.phpfreaks.com/forums/index.php?topic=306496.0 what im trying to do is take a youtube embed code find the URL code for that video and remove all other parts of the code keeping only the URL of the video after i get the URL by it self then replace the http://www.youtube.com/ part of the URL with http://i2.ytimg.com/vi/ to do this i know that i need something like this to get the URL of the video http://www.youtube.com/((?:v|cp)/[A-Za-z0-9\-_=]+) but how to only return just the URL is something idk how to do then use str_replace http://www.youtube.com/(?:v|cp)/" with http://i2.ytimg.com/vi/ so in the end im asking if anyone know how to remove all other codes i dont want and only keep the URL this may have to be done using "regex" im not sure as i dont know to much about regex and what it can do but does sound like it would help lol i have to read a single line from a csv, its a really big file and i only need one column.
i need the response to be a string ,i made a search and found the following code but i dont have any idea how to get a single line from a single string per run .
<?php
$row = 1;
//open the file
if (($handle = fopen("file.csv", "r")) !== FALSE)
{
while (($data = fgetcsv($handle, 0, ",")) !== FALSE)
{
$num = count($data);
echo "<p> $num fields in line $row: <br /></p>\n";
$row++;
for ($c=0; $c < $num; $c++)
{
echo $data[$c] . "<br />\n";
}
}
fclose($handle);
}
?>
Edited by bores_escalovsk, 16 May 2014 - 06:38 PM. Dear All Good Day, i am new to PHP (a beautiful server side scripting language). i want to send a mail with line by line message i tried with different types like by placing the things in table and using <br /> but the thing is the tags are also visible in the message of the mail. Here is my code: $message1 = "Name :". $_REQUEST['name']."<br />"; $message1 .= "Surname :". $_REQUEST['surname']."<br />"; $message1 .= "Cellphone :". $_REQUEST['mobileno']."<br />"; $message1 .= "Telephone :". $_REQUEST['landno']."<br />"; $message1 .= "Fax :". $_REQUEST['fax']."<br />"; $message1 .= "Company :". $_REQUEST['company']."<br />"; $message1 .= "Email :". $_REQUEST['email']."<br />"; $message1 .= "Country :". $_REQUEST['country']."<br />"; $message1 .= "Enquity :". $_REQUEST['enquiry']."<br />"; $message1 .= "Date&Time :". $date."<br />"; For this code if try to print/echo it it is working fine it is displaying line by line, but using this variable ($message1) in the mail these <br /> are also visible. Can any one guide me to resolve(to remove these tags from the message part) this issue. Thanks in Advance. :confused: Hi. I want a simple textbox, that when submited, will replace very every new line, with the <br> tag. What will happen, when it submits, it will take the contents of a textbox, add the <br> tag where a new line is suposed to be, and save the string to a MySQL Database. I think this is the easiest way of allowing a user to edit what appears on a website when logged in, but if there is a easier way, then please tell me. What I am trying to do, is a login page, and once logged in, you enter new text into the textbox, click submit, and on the website homepage, the main text will change to what was submitted. But if there is a new line, I think the only way in HTML to make one is to put a <br> tag, so I want the PHP to but that tag wherever there is a new line. Sorry if I am confusing, I am not that advanced at PHP, but I would be very happy if you could supply me with the correct code. Time is running out... If you do not understand me, please tell me -- PHPLeader (not) I have a script that reads a .gz file into an array and prints the name of each record but will not work on larger files. Is there a way to read 1 line at a time? Here is the code I have so far. Code: [Select] <?php if ($handle = opendir('.')) { print "<ol>"; while (false !== ($file = readdir($handle))) { if($file != '..' && $file!="." && $file!="start_update.php" && $file!="sharons_dbinfo.inc.php" && $file!="root.php" && $file!="read_directory.php" && $file!="read_dir.php" && $file!="new_category.php" && $file!="index.php" && $file!="file_count.php" && $file!="dir_loop2.php" && $file!="dir_loop1.php" && $file!=".htaccess" && $file!="Answer.txt" && $file!="Crucial_Technology-Crucial_US_Product_Catalog_Data_Feed.txt"){ $filename = $file; $go = filesize($filename); if($go >= 1){ $filename2 = explode("-", $filename); $filename2 = $filename2[0]; echo str_replace("_"," ",$filename2) . ' | Filesize is: ' . filesize($filename) . ' bytes<br>'; $gz = gzopen($filename, 'r'); $lines = gzfile($filename,10000); foreach ($lines as $line) { $line2 = explode(",", $line); $line2 = str_replace("," , "-" , $line2); echo "<li>".str_replace("," , "-" , $line2[4])."</li><br>"; } } } } closedir($handle); } ?> </ol> How to get this echo line to display as one line? No matter what I have done it displays as two lines. I even tried <nobr></nobr> Teachers Name: John Jones $userid = mysql_real_escape_string($_GET['user_id']); $sql = "select * from users where `id`='$userid' "; $rs = mysql_query($sql); while($row = mysql_fetch_array($rs)) { echo "<h3>Teachers Name: </h3>" . $row["first_name"] . " " . $row["last_name"] ; } Thanks for your help. |
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