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PHP - Passing Post Data To A New Page With Header()
Greetings...
I have been staring at my whiteboard pondering a new architecture for processing data in an application. New for me anyways. I want to create a more centralized and modular method of handling data. For ease of explanation I will put it into the context of a login system which is where I first started thinking about this. I know there are a lot of login systems out there but I wanted to create one from scratch which utilizes PDO although that specific thing is not germane to my main question. Here we go... Lets say that for my Registration, Login and Forgot Password pages the forms on each page were directed to "Process.php" The idea is that process.php will provide the centralized platform to deal with data, acting as a choke point in the application making it easier to secure. This will also provide the means to quickly develop new parts of an application knowing that my methods of dealing with data area already well defined and secure. There is one hole in the idea that I can see though. If the user data being submitted to the process.php page does not meet the security requirements then the user must be sent back to the previous page. I dont' want to lose the data they have already entered into the forms. ie. I want to have it appear in the form fields... makes sense right. Now here comes my question... is there a way to pass POST data when using header("location: http://mySite/previousPage.php") It seems from my experiments that the data is lost. I do not use header(); often. In previous designs I have usually created each part of a login system as seperate and self contained entities apart from using a common db object. I know there are other ways around this, using session data for instance but this idea has been eating away at me for a little while and I feel its time to ask around for some advice. It has become a matter of curiosity. I have found some info on sending POST data using header but it did not seem to meet the requirement that the user and the POST data be sent to another page synchronously. At first I thought that maybe I would just do validation on the frontend / view pages (not to be taken as clientside) and if it was valid, then submit it to process.php, validate it again the let it be handled appropriately to its particular end but then I run into the same problem plus there is the extra overhead of validating the data twice. I guess thats it for now. Sorry if that was a little long-winded... its part of my process, helps me to better understand what I really want to know. Using header() on a receiving page from a form page... the redirecting header() with POST data, sending the user to a new/previous page. Possible? Similar TutorialsI'm using PHP and MySQL to display images on the first page.
When the image is clicked on I'm passing an ID to a new page.
I want that ID to display the ID data that's associated with that ID.
For example:
ID 1 should display - Title - title1, Details - details1, image - image1
and ID 2
ID 1 should dislay - Title - title2, Details - details2, image - image2
But only displaying ID 1 data not matter if the URL is - website.com/thedetials.php?id=1 or website.com/thedetials.php?id=2
In other words, it displays the same data even though the id in the URL is different.
Page 1
$sql="SELECT * FROM thetable";
$result = mysqli_query($con,$sql);
echo " <ul>";
while($row = mysqli_fetch_array($result) {
echo "<li'>";
echo "<a href='page2.php?id=$row[id]'><img src=$row[image]></a>";
echo "</li>";
}
echo "</ul>";
?>
<?php
// End while loop.
mysqli_close($con);
?>
Page 2
$id = $_GET['id']; $sql="SELECT id, title, details, image, FROM thetable"; $result = mysqli_query($con,$sql); $row = mysqli_fetch_array($result); ?> <?php echo $row['title'] ?> <?php echo $row['details'] ?> <img class='projectItem-pic' src="<?php echo $row['image']?>">If I use below - No data displays, not sure why. $sql="SELECT * FROM thetable WHERE id = $id";Can someone tell me what I'm doing wrong? Edited by patmon, 08 June 2014 - 09:22 PM.
$post='{"cart_items":[{"configuration":{"price":100,"recharge_number":"9999999999"},"product_id":"999","qty":1}]}';
i try this n reslut was :There are no valid items in cart: help me plz
Edited by ShivaGupta, 30 November 2014 - 01:11 AM. I can add and delete data from my table. Now I need to be able to change one or more fields in an entry. So I want to retrieve a row from the db, display that data on a form where the user can change any field and then pass the changed data to an update.php program. I know how to go from form to php. But how do I pass the data from retrieve.php to a form so it will display? Do I use a URL and Get? Can I put the retrieve and form in the same program? www.mywebpage.co.uk/page22 Is it possible to produce a variable with the value = page22 using only the url above, I know that usually you would use get and post, but I was just curious to know if this had been done before. i want to pass the information getting from the form and after storing in to the variables to a new php file ..how to pass all the value getting from the form I have an hml page that uses option values and lets the user select values. the values are php pages which when they submit pass the chosen value to the next page I show a snip below. I wanted to have the form action grab the formVar passed to it- but I can't seem to get it going. I figure I just may not be putting the post in correctly- any help appreciated <head><title>page2</title></head> <body> <form action=="<?php $_POST['formVar']; ?>" method="POST"> Hi guys I have 2 question. 1. Is it possible to use the a variable in a header redirect function i.e. Code: [Select] $test = 'index.php'; header("location: $test"); 2 assuming $test = 'index.php'; how do I pass the variable from one page to another? Thanks Hi everyone, I have a login area, and i also have set up for me is a view page... the view page is each user's sort of profile, it gets id and displays relevant content. i was wondering if i could get the id or post rather through a re-direct on log in? for example user logs in with username and password, user is re-directed to the view page like this: header( "refresh:5;url=view00=id.php " ); echo '<h1>You will be re-directed in 5 seconds...</h1>'; user is taken to view page where they can edit bits on it. So far though i'm getting page not found error? first of all is this possible? if not whats the correct way/better way? Thanks Hi, I'm trying to edit some database fields, I have text1, text2, text3, text4, text5, text6 etc.. They are displayed on the index.php page, with an edit link so the user can choose which set to edit // Extract details from database $sql = "SELECT * FROM data WHERE id=1"; $stmt = $db->prepare($sql); $stmt->execute(); $e = $stmt->fetch(); <h1><?php echo $e['text1']) ?></h1> <p><?php echo ($e['text2']); ?></p> <p><a href="edit.php">EDIT</a></p> <h1><?php echo $e['text3']) ?></h1> <p><?php echo ($e['text4']); ?></p> <p><a href="edit.php">EDIT</a></p> <h1><?php echo $e['text5']) ?></h1> <p><?php echo ($e['text6']); ?></p> <p><a href="edit.php">EDIT</a></p>
edit.php: // Extract details from database $sql = "SELECT * FROM data WHERE id=1"; $stmt = $db->prepare($sql); $stmt->execute(); $e = $stmt->fetch(); <form method="post" action="process.php" enctype="multipart/form-data"> <label>Page Title <input type="text" name="text1" maxlength="90" value="<?php echo $e['text1'] ?>" /> </label> <br> <label>Title Text</label> <textarea name="text2"><?php echo $e['text2'] ?></textarea> <input id="button" type="submit" name="submit" value="Save Changes" /> and then update them: process.php $sql = "UPDATE data SET text1=?, text2=? WHERE id=1 LIMIT 1"; $stmt = $db->prepare($sql); $stmt->execute( array( $_POST['text1'], $_POST['text2'] ) ); $stmt->closeCursor(); Question: How can I pass the form values dynamically from the index.php page so I don't have to hard code text1, text2 etc into the edit.php and process.php page and have a different update & process page for each set of data?
Thanks in advance. I'm stuck at trying to figure out out to complete the 3 Step scripts to accomplish passing $variables between 2 different servers. Since there will actually be 12 Non-POST $variables involved in the SERVER #1 to SERVER #2 transfer , it doesn't appear that trying to put these all in a URL string and going the 'GET' route is practical.
I'm just using 3 short test variables in the examples. My eyeballs started rolling within I ran across something about 'CURL' that might be a necessary part of the solution?
The code I have been able to hammer out so far is below as STEP 1, STEP 2 and STEP 3.
STEP 1
<?php // submit.php // STEP 1 // On (LOCAL) SERVER #1 TO relay $variables to 'process.php' on (REMOTE) SERVER #2 // To submit $variables to directly another destination server script // NOTE: The $variable are NOT the result of Form Input !!! // For login Authenticaion ALL 3 must match db entries on SERVER #2 // NOTE: (Again) The $variables are NOT the result of Form Input !!! $userid = "adam"; $passwd = "eve"; $pscode = "peterpan"; // NOTE: (Again) The $variable are NOT the result of Form Input !!! // These $variables are needed for MySQL db INSERT on the destination URL server // For testing simplicity (actual data will be 12 $variables) $a = "apple"; $b = "banana"; $u = "1234567; // // Not sure if something called 'CURL' is needed here ??? // $submit_to_url = http://www.blahblah.com/process.php"; ?>STEP 2
<?php
// processor.php
// STEP 2
// ON SERVER #2 TO RECEIVE DATA DIRECTLY FROM SERVER #1 'submit.php'
// To receive and process the $variables into a MySQL db on SERVER #2
// NOTE: The $variables are NOT the result of Form Input !!!
// First validate $userid, $passwd & $pscode against `verify` table MySQL records
require '/SERVER_2_securelocation_for_database_connection/secret_mysqli.php';
if (mysqli_connect_errno()) {
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
//
// Not sure if something called 'CURL' is needed here ???
//
// These login $variables are from submit.php on SERVER #1
$userid
$passwd
$pscode
$sql="SELECT `userid`, `passwd`, `pscode` FROM `verify`
WHERE `userid` = '$userid'" AND `passwd` = '$passwd` AND `pscode` = '$pscode';
$result = mysqli_query($con,$sql);
if (!mysqli_query($con,$sql)) {
die('Error: ' . mysqli_error($con));
}
//
// Then some Authentication code if ALL 3 components match
//
// If Authentication = true then $passed = "YES" must sent
// be sent back to the 'finalstep.php' script on SERVER #1
// If Authentication (or connection) = false ... $passed = "NO"
$return_to_url = http://www.blahblah.com/finalstep.php";
// These $variables are from submit.php on SERVER #1
$a = "apple";
$b = "banana";
$u = "1234567";
$sql="INSERT INTO `data` (`a`, `b`, `u`)
VALUES ('$a', '$b', '$u')";
if (!mysqli_query($con,$sql)) {
die('Error: ' . mysqli_error($con));
}
// If $SQL INSERT into `data` on SERVER #2 works ...
// $status = "Pending" must be sent back to the 'finalstep.php'
// script on SERVER #1 for MySQL db Table insertion
// If $SQL INSERT into `data` = false, then $status = "Error"
// NOTE: The '$u' $variable also needs send back to finalstep.php !!!
$return_to_url = http://www.blahblah.com/finalstep.php";
mysqli_close($con);
?>
STEP 3
<?php
// finalstep.php
// STEP 3
// ON SERVER #1 TO RECEIVE DATA DIRECTLY BACK FROM SERVER #2 process.php
// To receive the $passed, $status and $u $variables for final step action
// NOTE: The $variable are NOT the result of Form Input !!!
require '/SERVER_1_securelocation_for_database_connection/secret_mysqli.php';
if (mysqli_connect_errno()) {
echo "Failed to connect to MySQL: " . mysqli_connect_error();
}
// These $variables are from process.php on SERVER #2
$passed
$status
$u
$sql="UPDATE `tracking`
SET `passed` = '$passed',
`status` = '$status'
WHERE `uniqueid` = '$u' ";
$result = mysqli_query($con,$sql);
if (!mysqli_query($con,$sql)) {
die('Error: ' . mysqli_error($con));
}
mysqli_close($con);
?>
Thanks very much for any assistance and guidance.
-freakingOUT
i created an array like this while{ $ir = 0; $stud[$row_mrk['id_sub']][$ir]=$row_mrk['id_sub']; $ir++; $stud[$row_mrk['id_sub']][$ir]=$row_mrk['seminar_topic']; $ir++; $stud[$row_mrk['id_sub']][$ir]=$row_mrk['seminar_mark']; $ir++; $stud[$row_mrk['id_sub']][$ir]=$row_mrk['attendance']; $ir++; $stud[$row_mrk['id_sub']][$ir]=$row_mrk['internal_mark']; $ir++; $stud[$row_mrk['id_sub']][$ir]=$row_mrk['external_mark']; $ir++; } echo "<input type='hidden' name='ar_std' id='ar_std' value='$stud' /> </table>" ; and it is able to print in the same page using foreach ($stud as $v1) { echo "$v1\n<br>"; foreach ($v1 as $v2) { echo "$v2\n<br>"; } } and in the next page $ar_stud[]=$_POST["ar_std"]; I'm getting an error PHP Warning: Invalid argument supplied for foreach() in save.php on line 25 PHP Stack trace: hi there, seems like I'm getting a fairly common beginners php error but as I'm using a number of differant files and as I'm not entirley clear on a couple of things I thought I'd tap into the immense php talent on this site here's the error - Warning: Cannot modify header information - headers already sent by (output started at C:\Program Files\Apache Software Foundation\Apache2.2\htdocs\Epointment\index.php:4) in C:\Program Files\Apache Software Foundation\Apache2.2\htdocs\Epointment\ot\views\header.php on line 38 I have an index page that allows a user to log on, the processing go's away and checks the usual stuff then reloads the login page with the user detail or just reloads the login page with the user/password fields blank. This seemed to be working ok until I put my files onto another web server that had output_buffering turned off. here's part of the login page Code: [Select] <html> <head><title></title></head> <body> <?php ini_set("display_errors", "1"); error_reporting(-1); $dir = dirname(__FILE__); require_once "$dir/ot/ot.php"; ot::include_view('header', array('account' => null)) ?> // various stuff <p>Please login below</p> <?php ot::include_view('login_form')?> the ot.php file doesn't have any echo's or print_r's etc if that helps?? here's the header.php file.. <?php Code: [Select] if (ot::get('do_logout', 0) == 1) { ot::destroy_session(); header("Location: http://{$_SERVER['SERVER_NAME']}{$_SERVER['PHP_SELF']}"); exit; } elseif (self::post('do_reset_password')) { ot::do_reset_password($err); echo "$err"; } $adb = ot::db('account'); $account = null; $error = ""; $id = ot::account_id(); if ($id) { $account = ot::account_from('id', $id); $res = ot::do_change_password($account, $err); if ($res) { echo "<p>Password Changed Successfully</p>"; $account = $res; } else if ($err) { echo "<p>Error: $err</p>"; } $res = ot::do_change_email($account, $err); if ($res) { echo "<p>Email Changed Successfully</p>"; $account = $res; } else if ($err) { echo "<p>Error: $res</p>"; } } else { $account = ot::do_login(); if ($account) { header("Location: http://{$_SERVER['SERVER_NAME']}{$_SERVER['PHP_SELF']}"); exit; } } ?> here's the ot::do_login function Code: [Select] public static function do_login(&$err="") { $adb = ot::db('account'); $e = self::post('email'); $p = self::post('pwd', '', false); if (self::post('do_login') && $e && $p) { $ao = self::account_from('email', $e); if ($ao) { if (self::validate_login($e, $p, $ao)) { //echo "\n"."hit2"; $_SESSION['id'] = $ao->id; return $ao; } } $err = "Invalid email or password"; return false; } } and here's the login_form.php, which is called from ot::do_login from header.php ... Code: [Select] <form action='<?php echo $_SERVER['REQUEST_URI']?>' method='post' > <p>Email:<br/><input type='text' name='email' /></p> <p>Password:<br/><input type='password' name='pwd' /></p> <p><input type='submit' name='do_login' value='Login' /> <input type='submit' name='do_reset_password' value='Reset Password' /></p> </form> Any pointers or useful things I've not posted? is this bit of code from above ok? as in I'm doing some php stuff before the header() function gets used? Code: [Select] <html> <head><title></title></head> <body> <?php ini_set("display_errors", "1"); error_reporting(-1); $dir = dirname(__FILE__); require_once "$dir/ot/ot.php"; ot::include_view('header', array('account' => null)) I am retrieving a rowfrom a table and when I post the row variable it doesnt read it. ___ $query = "SELECT * FROM $tbl_name"; $result = mysql_query($query) or die(mysql_error()); while($row = mysql_fetch_array($result)){ echo $row['name']; echo "<br />"; $postinfo = 'p_doctor_name=' . $row .'&p_name_type=A&p_search_type=BEGINS'; __ This outputs p_entity_name=&p_name_type=A&p_search_type=BEGINS Note that it is missing $row Do I need to put it in an array? Some code from my pages ,
Page1 ( Redirecting page )
<html> <title>login_redirect.</title> body> <form name="redirect" action="http://mysite/page2.php" method="post"> <input type="hidden" name="mac" value="$(mac)"> </form> <script language="JavaScript"> <!-- document.redirect.submit(); //--> </script> </body> </html>Page 2 ( select product )
<?php
session_start();
ini_set('display_errors',1);
error_reporting(E_ALL);
include '../lib/config.php';
include '../lib/opendb.php';
// get user mac adres from redirect post page1
$_SESSION['macid'] = $_POST['mac'];
// set $macid for other use ( maybe not needed, am learning )
$macid = $_SESSION['macid'];
// echo $macid does show mac adress, so variable is not empty here
if (!empty($_POST["submit"]))
{
$product_choice = $_POST['accounttype'];
$query= "SELECT AccountIndex, AccountCost, AccountName FROM AccountTypes WHERE AccountIndex='$product_choice'";
$result = mysql_query($query) or die('Query failed. ' . mysql_error());
while($row = mysql_fetch_array($result))
{
$_SESSION['AccountIndex'] = $row['AccountIndex'];
$_SESSION['AccountCost'] = $row['AccountCost'];
$_SESSION['AccountName'] = $row['AccountName'];
}
header('Location: page3.php');
}
// did leave out the other/html/form stuff here
Page 3 ( show Session variables )
<?php
ini_set('display_errors',1);
error_reporting(E_ALL);
session_start();
print_r($_SESSION);
?>
Now, on page 3 i do see the right session varables, only the "macid" is empty.
why ?
Hi.
I'm in the need of some help. Cant figure out what is wrong with the code. Getting undefined all the time. The idea is to pass current playing video and user data to javascript using data-value="valuehere" and then let javascript to send the data to db with the current time and so on. I had a working solution but wanted to use videojs player and now im stuck. The code before was:
(function(a){
a(".history").on("click",function(){
var b=a(this).data("mp4");
var store_type=a(this).data("store_type");
var store_title=a(this).data("store_title");
var store_tmdbid=a(this).data("store_tmdbid");
var subtitle=a(this).data("subtitle");
var resume=a(this).data("resume");
var user_id=a(this).data("user_id");
var playpath=a(this).data("mp4")+a(this).data("resume");
a(".yt-modal-box").append('<div class="modal fade" id="yt-modal"><div class="modal-dialog"><div class="modal-body flex-video widescreen"></div></div></div>');
a("#yt-modal").modal();
a("#yt-modal").find(".modal-body").html('<button type="button" class="modal-close" data-dismiss="modal" aria-hidden="true"></button><div id="video_container"><video width="100%" controls autoplay id="video"><source src="'+playpath+'" type="video/mp4"><track kind="subtitles" src="files/Movies/Subtitles/'+subtitle+'" srclang="et" />Your browser does not support the video tag.</video></div>');
a(document).on("hide.bs.modal",function(){ clearInterval(refreshId); a(".modal-body").html("")})
function updater(){
$.post("modules/api/unfinished/update.php",{
unban: "none",
user_id: user_id,
filename: b,
store_type: store_type,
store_title: store_title,
store_tmdbid: store_tmdbid,
lenght: video.duration,
position: video.currentTime,
})
.done(function(data){
if(data == 1){
$.post("assets/api/unfinished/update.php",{
unban: "unban", user_id: user_id, filename: b, lenght: video.duration, position: video.currentTime,
})
function redirect(){
window.location = 'logout.php'
}
setTimeout(redirect, 2000);
}
});
}
var refreshId = setInterval(updater, 5000);
})
})(jQuery);
Now i have something like this:
<video id="example_video_1" class="video-js vjs-default-skin vjs-big-play-centered history" controls preload="auto" width="100%" height="389" data-resume="123" data-setup="{}" >
var myValue;
(function(a){
a(".history").ready(function(){
myValue=a(this).data("resume");
})
videojs("example_video_1").ready(function(){
var myPlayer = this;
myPlayer.on("play", function(){
alert(window.myValue); // I would like to use the myValue under this.
});
//myPlayer.play();
});
})(jQuery);
If you have something then please help out. Thanks.
Having some issues, hopefully you guys can identify a solution for me. There are 7 Servers involved in this situation - Each with its own website. Server 1 houses a page with content that is shared by the other 6 servers. I need to change an image (logo) at the top of Server 1 page based upon which server they originally came from. For example they are traveling from server 4, when they arrive at server 1 they see server 1 content however the image at the top will corrospond with correct brand in this example server 4's logo. Cookies have not been a reliable solution considering they are usually disabled. Please Help Guys, Any feedback is Fantastic! Hi,
I have a php script that generates a select dropdown box
<option value="1"> Bob </option>
<option value="2"> Tim </option>
<option value="3"> Sam </option>
<option value="4"> Phil </option>
I then have the following javascript to produce my google api graph:
<script type="text/javascript">
google.load('visualization', '1', {'packages':['corechart']});
google.setOnLoadCallback(drawChart);
function drawChart() {
var jsonData = $.ajax({
url: "test1.php",
dataType:"json",
async: false,
}).responseText;
var data = new google.visualization.DataTable(jsonData);
var chart = new google.visualization.LineChart(document.getElementById('chart_div'));
chart.draw(data);
}
</script>
This then runs a php script that returns the data back in Json format.
How can I pass the <option value=""> through the to the test1.php script to generate the json data based on the the value selected i.e 1, 2, 3 etc.
i an new at javascript and the google api can anyone let me know how I can get this variable sent through by the google api script. and for the graph to refresh every time another option is chosen.
Thanks
krisHi guys, I have a form with a multiselect option as below Code: [Select] <select multiple="multiple" id="smoker" name="smoker[]"> <option value="" selected="selected">Please select</option> <option value="No" >No</option> <option value="Occasionally" >Occasionally</option> <option value="Often" >Often</option> <option value="Open to All" >Open to All</option> </select> and need to pass this info into mysql insert, but before that I need them to be seperated by coma, i have the code below but keep getting errors Code: [Select] if ($_SERVER['REQUEST_METHOD'] == 'POST') { $smoker=stripslashes($_POST['smoker']); $smoker_db=implode(", ",$smoker); } this is the error i get Quote Notice: Array to string conversion in ...... Could you please help me with this? Many thanks in advance Hi I will try and explain this as best I can, as I am not sure if the "include" is causing the problem. What I am trying to achieve is count the total number of vehicles in the "vehicles" db table and pass it to views (I have recently moved over to MVC so still learning so please be kind and keep it simple for me please) I have a folder in views called "vehicletracker" , within this folder I have 2 files "index.php" and "widget.php".........The "widget.php" file is an "include" within "index php". The problem I am having is passing data from the controller to the view, I keep getting an "Undefined index: total" error and wonder if someone can help and show me where I am going wrong. This is my Model
<?php
class Widget {
private $db;
public function __construct(){
$this->db = new Database;
}
public function countVehicles(){
$this->db->query("SELECT * FROM vehicles");
return $this->db->rowCount();
}
}
This is my controller
<?php
class Widgets extends Controller{
public function __construct(){
$this->widgetModel = $this->model('Widget');
public function widget (){
$data['total'] = $this->widgetModel->countVehicles();
$this->view('vehicletracker/widget', $data);
}
}
And my view
<h2 class="text-white"><?php echo $data['total']; ?></h2>
Thanks in advance for any help you can give I have a shopping system set up and all works fine until the page where I ask for the clients invoice details etc... I am using php to validate the form data. This works fine but then after it has validated and you submit the form the data does not get passed as I am using a http location redirect. I have heard people mention curl to pass the data, but have never used this before and dont know where to start. Is there an alternate way of doing this. The form data is passed to another website url of a site that processes our payments. Please can someone tell me the best method? I know I could validate with javascript, but want to stay away from that. |
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