PHP - Results Not Showing After First One
I am working on building a code that will check the results returned from and xml pull to see if they match the database and print back pass or fail on the screen, it works for the first result but then fails to display anything else. any help on where I went wrong would be helpful.
Code: [Select] <?php function pass($name, $level) { $sql1 = "SELECT * FROM `reqskills` WHERE `level` > 0 and `name` = '$name'"; $result1 = mysql_query($sql1); while($row1 = mysql_fetch_array($result1)) { if($level >= $row1['level']) { echo "Pass"; } Else { echo "Fail"; } } } $API = "address removed"; $xml = simplexml_load_file($API); $sql = "SELECT * FROM `reqskills` WHERE `level` > 0"; $result = mysql_query($sql); echo "<table width=100%"; echo "<tr><td>Skill</td><td>Level</td><td>Pass</td></tr>"; while($row = mysql_fetch_array($result)) { ?> <tr> <td><?php echo $row['name'] ?></td> <td><?php echo $row['level'] ?></td> <td><?php foreach ($xml->result->rowset[0] as $value) { $typeID = $value['typeID']; $sql = "select * from `invTypes` WHERE `typeID` = $typeID"; $result = mysql_query($sql); while ($row = mysql_fetch_array($result)) { echo pass($row['typeName'],$value['level']); }} echo "</td></tr>"; } echo"</table>"; ?> Similar TutorialsCode: [Select] if (isset($_POST['update'])) { $signature = $_POST['signature']; $type = $_POST['type']; $name = $_POST['name']; $b=0; While ($b < $i) { echo $signature[$b]."<br>"; echo $type[$b]."<br>"; echo $name[$b]."<br><br>"; $b++; }} I did echo '<pre>'; print_r($_POST); echo '</pre>'; The results are Code: [Select] Array ( [sname] => [notes] => [signature] => Array ( [0] => 1-1 [1] => 1-2 [2] => 1-3 ) [type] => Array ( [0] => Test1 [1] => Test2 [2] => Test3 ) [name] => Array ( [0] => Testa [1] => Testb [2] => Testc ) [update] => Update ) But for some reason nothing is showing up on the screen. Does anybody know how to show the below php results in a table format? <?php if(isset($_POST['submit'])){ if(isset($_GET['go'])){ $fname = $_POST['fname']; $lname = $_POST['lname']; $skill = $_POST['skill']; //connect to the database $db=mysql_connect ("127.0.0.1", "root", "") or die ('I cannot connect to the database because: ' . mysql_error()); //select the database to use $mydb=mysql_select_db("resource matrix"); //query the database table $sql="SELECT DISTINCT First_Name, Last_Name, l.Resource_ID FROM ((resource l inner join resource_skill ln on l.Resource_ID = ln.Resource_ID) inner join skill n on ln.Skill_ID = n.Skill_ID) WHERE First_Name LIKE '$fname' OR Last_Name LIKE '$lname' OR Skill_Name LIKE '$skill'"; //run the query against the mysql query function $result=mysql_query($sql); //create while loop and loop through result set while($row=mysql_fetch_array($result)){ $First_Name =$row['First_Name']; $Last_Name=$row['Last_Name']; $Resource_ID=$row['Resource_ID']; //display the result of the array echo "<ul>\n"; echo "<li>" . "<a href=\"a.php?id=$Resource_ID\">" .$First_Name . " " . $Last_Name . "</a></li>\n"; echo "</ul>"; } } else{ echo "<p>Please enter a search query</p>"; } } Hi people. I am creating a carpet website for a good friend of mine as a favour. I am storing the carpets info in a MYSQL database and am currently trying to relay the info on a page. I have the array kind of done but it is not producing the results I want. Let me explain further: The columns in my database under the table "carpets" a id (auto incremented) colour type title price description imageloc ------ under the type I have various types of carpet (6-ish). They a Twist, Striped etc etc... Heres the php problem. I have all the images there and ready on the page and want to link them all with linking commands. i.e: the main page is at: http://www.ircdirect.co.uk/FTPServers/supremecarpets/index.php the carpets results page is at: http://www.ircdirect.co.uk/FTPServers/supremecarpets/carpetlist.php on the index.php page I want to link them so that for example: If he looks for a striped carpet he clicks "striped" and is shows carpetlist.php but with the striped carpets displayed. example link: <A HREF="carpetlist.php?type=striped">IMAGE HERE</A> I have tried various coding on the carpetlist.php and cant seem to get it to work. here is the snippets: <?php // Make a MySQL Connection $query = "SELECT * FROM carpets GROUP BY type"; $result = mysql_query($query) or die(mysql_error()); while($row = mysql_fetch_array($result)){ echo "<TABLE CELLPADDING=0 CELLSPACING=0 WIDTH=100% />"; echo "<TR />"; echo "<TD WIDTH=23 /><IMG SRC=images/main/search/topleft.png /></TD />"; echo "<TD BACKGROUND=images/main/search/top.png /> </TD />"; echo "<TD WIDTH=23 /><IMG SRC=images/main/search/topright.png /></TD />"; echo "</TR />"; echo "<TR />"; echo "<TD BACKGROUND=images/main/search/left.png />"; echo " "; echo "</TD />"; echo "<TD BACKGROUND=images/main/search/bg.png />"; echo "<FONT FACE=VERDANA SIZE=1 />"; echo $row['title']; echo "</TD />"; echo "<TD BACKGROUND=images/main/search/right.png />"; echo " "; echo "</TD />"; echo "</TR />"; echo "<TR />"; echo "<TD WIDTH=23 /><IMG SRC=images/main/search/bottomleft.png /></TD />"; echo "<TD BACKGROUND=images/main/search/top.png /> </TD />"; echo "<TD WIDTH=23 /><IMG SRC=images/main/search/bottomright.png /></TD />"; echo "</TR />"; echo "</TABLE />"; echo "<BR />"; } ?> It displays ALL the results which is not what I want. I want only striped carpets, blue carpets etc.... Help is needed and VERY much appreciated! Kind Regards, Ian I am writing a CRON job that will execute daily. First it will identify from a MySql table the date in a field 'FAPforSale_repost35' If the date is the today date it will then execute commands to delete photo images in a directory, delete the directory, and finally remove the record from the database.
I am on step one which is to build the array of records that match the days date. When I run the code, there are no errors but I am not getting results even though the records in the test table are set for today. Below is the select
<?php define( "DIR", "../zabp_employee_benefits_processor_filesSm/", true ); require( '../zipconfig.php' ); require( DIR . 'lib/db.class.php' ); require_once( $_SERVER['DOCUMENT_ROOT'] . '/_ZABP_merchants/configRecognition.php' ); require_once( $_SERVER['DOCUMENT_ROOT'] . '/_ZABP_merchants/libRecognition/MailClass.inc' ); $todayRepost35 = date("Y-m-d"); echo $todayRepost35; function repostEndSelect() { global $db; $this->db = $db; $data = $this->db->searchQuery( "SELECT `FAPforSale_IDnumber`, `FAPforSale_image1`, `FAPforSale_image2`, `FAPforSale_image3`, `FAPforSale_repost35` FROM `FAP_forSaleTest` Where `FAPforSale_repost35` = '$todayRepost35' "); $this->FAPforSale_IDnumber = $data[0]['FAPforSale_IDnumber']; $this->FAPforSale_image1 = $data[0]['FAPforSale_image1']; $this->FAPforSale_image2 = $data[0]['FAPforSale_image2']; $this->FAPforSale_image3 = $data[0]['FAPforSale_image3']; $this->FAPforSale_repost35 = $data[0]['FAPforSale_repost35']; echo $this->FAPforSale_IDnumber; echo $this->FAPforSale_image1; echo $this->FAPforSale_image2; echo $this->FAPforSale_image3; echo $this->FAPforSale_repost35; } // ends function... echo( ' Finished...' ); ?>Thanks in advance for any suggestions or direction. Chapter two will be when I start testing the commands to delete. Hi
I have 2 tables that I am searching infor for. One holds the phone info and the other the repairs that are available.
I have the code below and it displays on the webpage in a table for the phone information and then another table the repairs but they seem to be separate tables and headers. inbetween them is the phone and the details which separates the repairs but its not in a table.
Hopefully the code below will explain better.
What I would like it the phone details in one table and then a table full of all the repairs (I am not bothered about a new heading for each repair).
$result = mysql_query("SELECT * FROM phone, phonerepairs WHERE phone.model_no='".$_POST['model']."' AND phone.phone = phonerepairs.phone"); while($row = mysql_fetch_array($result)) { echo '<td width="70" align="center"><img src="'.$row['icon'].'" width="66"></td>'; echo '<td width="100" align="center">'.$row['model_no'].'</td>'; echo '<td width="130" align="center">'.$row['model'].'</td>'; echo '<td width="50" align="center">'.$row['year'].'</td>'; echo '<td width="150" align="center">'.$row['capacity'].'</td>'; echo '</tr>'; echo '</table><br>'; echo '</p>'; echo '<p>'; echo '<div id="pageheading"><h3><div id="title">Repairs we carry out for '.$row['model'].'</div></h3></div>'; echo '<table width="99%" cellpadding="5" cellspacing="0" border="1">'; echo '</p>'; echo '<p>'; echo '<tr>'; echo '<td align="center"><strong>Image</strong></td>'; echo '<td align="center"><strong>Fault</strong></td>'; echo '<td align="center"><strong>Repair</strong></td>'; echo '<td align="center"><strong>Cost</strong></td>'; echo '</tr>'; echo '<tr>'; echo '<td width="70" align="center"><img src="'.$row['icon'].'" width="66"></td>'; echo '<td width="100" align="center">'.$row['fault'].'</td>'; echo '<td width="130" align="center">'.$row['description'].'</td>'; echo '<td width="50" align="center">£'.$row['cost'].'</td>'; echo '</tr>'; echo '</table><br>';Thanks in advance Martyn So I have 2 queries, that has the potential to return alot of data, foreach loops running. The first shows each group heading, and the foreach nested is calling another query specific to the group heading. The result currently is a lengthy delay in results showing. (Now this may/may not be the most ideal code practise in this instance however... short term solution discussion please). For Each State Read Each States Details from DB For Each State Listing Display Details Next Next Is there a command or other where I can say, Display HTML page as it stands while it continues to process the FOREACH loops? EG: For Each State Read Each States Details from DB For Each State Listing Display Details REFRESH HTML DISPLAYED Next Next This topic has been moved to Ajax Help. http://www.phpfreaks.com/forums/index.php?topic=330251.0 i have built pages that paginate with 10 rows per page (some pages show more but for the moment i want to focus on this particular page)
//Define Some Options for Pagination $num_rec_per_page=10; if (isset($_GET["page"])) { $page = $_GET["page"]; } else { $page=1; }; $start_from = ($page-1) * $num_rec_per_page; $results = mysql_query("SELECT * FROM `ecmt_memberlist` WHERE toonCategory='Capital' AND oldMember = 0 ORDER BY CONCAT(MainToon, Name) LIMIT $start_from, $num_rec_per_page") or die(mysql_error()); $results_array = array(); while ($row = mysql_fetch_array($results)) { $results_array[$row['characterID']] = $row; }The above sets the variables for the pagination and below the results are echo with 10 rows per page then i show the pagination links: <?php $sql = "SELECT * FROM `ecmt_memberlist` WHERE toonCategory='Capital' AND oldMember = 0 ORDER BY CONCAT(MainToon, Name)"; $rs_result = mysql_query($sql); //run the query $total_records = mysql_num_rows($rs_result); //count number of records $total_pages = ceil($total_records / $num_rec_per_page); ?> <table width="100%" border="0" cellspacing="0" cellpadding="0"> <tr> <td align="center"><div style="width:100%; text-align:center;"> <ul class="pagination"> <li class="selected"> <?php echo "<a href='capitalmember.php?page=1'>".'«'."</a> ";?> </li> <? for ($i=1; $i<=$total_pages; $i++) { echo "<li><a href='capitalmember.php?page=".$i."'>".$i."</a></li> "; }; ?> <li class="selected"> <? echo "<a href='capitalmember.php?page=$total_pages'>".'»'."</a> "; // Goto last page ?></li> </ul></div> <?php $pageNr = $page; // Get Current Page Number $from = $pageNr * $rowsPerPage; // 3 * 10 = 30 // 3 * 10 = 30 $to = $from + $rowsPerPage; // 30 + 10 = 40 echo $pageNr; /* Result: From page 30 to 40 */ ?></td> </tr> </table>this works great and shows me 10 results per page, what i need to work out and work on next is: echo the number of results above the records (for example: "showing records 1 to 10" and then on page 2 "showing records 11 to 21" and page 3 "showing records 22 to 32" how can i work out the maths for this echo? i was thinking along the lines of; <?php $pageNr = $page; // Gets Current Page Number $from = $pageNr * $rowsPerPage; // 3 * 10 = 30 $to = $from + $rowsPerPage; // 30 + 10 = 40 // Now Show Results echo $from; // Echo from echo $to // Echo to ?>but i'm still working on this.. then i need to look at shortening the amount of page links on the page if for example i have 500 records it shows me links 1 to 50 and eats up the page.... Appreciate any help and light onto my problems. Many thanks Edited by jacko_162, 11 January 2015 - 05:43 PM. Our product is running on LAMP(PHP) architecture. For MySQL operation PDO library has been used. We are in the process of moving the product to a new Linux server. On the new server we are facing MySQL query output related issue. At the end of the post I have listed the server configuration details of both the servers and the sample PHP program with the output. It works fine in server 1 but when the same code moved to Server 2, the output is not correct. Would appreciate any points to solve this problem The following piece of code is tested and output is also given. <?php /*** mysql hostname ***/ $hostname = 'localhost'; /*** mysql username ***/ $username = 'ram'; /*** mysql password ***/ $password = 'tellmehow'; try { $dbh = new PDO("mysql:host=$hostname;dbname=inhouse", $username, $password); $sql = "SELECT first_name,last_name,user_id,email FROM users LIMIT 1"; $stmt = $dbh->prepare($sql,array(PDO::MYSQL_ATTR_USE_BUFFERED_QUERY => TRUE)); $stmt->execute(); $result = $stmt->fetch(PDO::FETCH_OBJ); $stmt->closeCursor(); /*foreach($result as $key=>$val) { echo $key.' - '.$val.'<br />'; }*/ print_r($result); $dbh = null; } catch(PDOException $e) { echo $e->getMessage(); } ?> Output for server 1: stdClass Object ( [first_name] => super [last_name] => admin [user_id]=>1 [email] => ram@greynium.com ) output for server 2: stdClass Object ( [first_name] => super [last_name] => admin [users] => ram@greynium.com ) On server 2 I am not getting the output for field 'user_id' from the table 'users'. For the field 'email' from 'users' table, it is displaying the name of the table itself (users). Not sure what is wrong. The configuration of the servers are given below Server 1 -------- OS Details: Linux 2.6.9-5.ELsmp PHP Details: PHP 5.2.3 (cli) (built: Aug 28 2007 11:48:30) Copyright (c) 1997-2007 The PHP Group Zend Engine v2.2.0, Copyright (c) 1998-2007 Zend Technologies with Suhosin v0.9.22, Copyright (c) 2007, by SektionEins GmbH PDO details: PDO PDO support => enabled PDO drivers => sqlite2, sqlite, mysql PDO Driver for MySQL, client library version => 5.0.37 PDO Driver for SQLite 3.x => enabled Server 2 --------- OS Details: Linux 2.6.18-8.el5 PHP Details: eAccelerator requires Zend Engine API version 220060519. The Zend Engine API version 220090626 which is installed, is newer. Contact eAccelerator at http://eaccelerator.net for a later version of eAccelerator. PHP 5.3.2 (cli) (built: Jul 6 2010 17:57:31) Copyright (c) 1997-2010 The PHP Group Zend Engine v2.3.0, Copyright (c) 1998-2010 Zend Technologies PDO Details: PDO PDO support => enabled PDO drivers => mysql, sqlite, sqlite2 PDO Driver for MySQL => enabled PDO Driver for SQLite 3.x => enabled I was wondering how does one go about showing results from SELECT query in columns in a html table. I have a list of products in a table, and would like to show them on the page in 4 columns. I have done many searches on google to try and find the sulution, but the majority of what im finding instead is about displaying a table from phpmyadmin as a table in html. If its a large operation to do this, I would be very happy if someone could poiint me in the direction of a tutorial maybe. Here is the code I have so far to display the products, but for some reason, it only show 1 row instead of all the rows from my table. Code: [Select] <?php $dbhost = "localhost"; $dbuser = "user"; $dbpass = "pass"; $dbname = "dbname"; mysql_connect ($dbhost, $dbuser, $dbpass)or die("Could not connect: ".mysql_error()); mysql_select_db($dbname) or die(mysql_error()); $result = mysql_query("SELECT * FROM mcproducts"); while($row = mysql_fetch_array($result)) { $products_local_id = $row['products_local_id']; $productname = $row['product_name']; $thumburl = $row['image_from_url']; $productlink = $row['product_local_url']; $thumbnail = $row['product_image_small']; $currencysymbol = $row['product_currency']; $price = $row['product_price']; $flagicon = $row['product_country_from']; } ?> <html> <head> <link href="style/stylesheet.css" rel="stylesheet" type="text/css" /> </head> <body> <div class="displaybox"> <div class="productimage"> <a href="<?php echo $productlink; ?><?php echo $products_local_id; ?>"><img src="<?php echo $thumburl; ?><?php echo $thumbnail ?>" width="150" height="150"></a> </div> <div class="productdescription"> <div class="pro_name"> <a href="<?php echo $productlink ?><?php echo $products_local_id; ?>"><?php echo $productname; ?></a> </div> <div class="pro_description"> </div> <?php if ($flagicon=="Ireland") { $flagicon = "<img src=\"flags/ireland.jpg\">"; } elseif ($flagicon=="UK") { $flagicon = "<img src=\"flags/uk.jpg\">"; } else echo ""; ?> <div class="pro_description"><?php echo $flagicon; ?><?php echo $currencysymbol ?> <?php echo $price ?></div> </div> </div> </body> </html> Many thanks, DB I am using html5 and all the pages have h2 headings as titles. They all show up in google search results fine. The only thing that doesn't show up fine are some of the descriptions under each heading. Some meta descriptions show up fine under the correct heading title, while rest shows ALL the heading tags AS description under each search result.
For eg.
Cars
www.mywebsite.com/category?id=5&name=cars I am pretty new to PHP and am trying to create a simple (so I assumed) page to takes data from one html page(works fine) and updates a MYSQL Database. I am getting no error message, but the connect string down to the end of the body section is showing up as plain text in my browser window. I do not know how to correct this. I have tried using two different types of connect strings and have verified my names from the HTML page are the same as listed within the php page. Suggestions on what I need to look for to correct would be great. I have looked online, but so far all I am getting is how to connect, or how to create a comment, so I thought I would try here. Thank you for any assistance I may get!! - Amy - Code: [Select] <body><font color="006600"> <div style="background-color:#f9f9dd;"> <fieldset> <h1>Asset Entry Results</h1> <?php // create short variable names $tag=$_POST['tag']; $serial=$_POST['serial']; $category=$_POST['category']; $status=$_POST['status']; $branch=$_POST['branch']; $comments=$_POST['comments']; if (!$tag || !$serial || !$category || !$status || !$branch) { echo "You have not entered all the required details.<br />" ."Please go back and try again."; exit; } if (!get_magic_quotes_gpc()) { $tag = addslashes($tag); $serial = addslashes($serial); $category = addslashes($category); $status = addslashes($status); $branch = addslashes($branch); $comments = addslashes($comments); } //@ $db = new mysqli('localhost', 'id', 'pw', 'inventory'); $db = DBI->connect("dbi:mysql:inventory:localhost","id","pw") or die("couldnt connect to database"); $query = "insert into assets values ('".$serial."', '".$tag."', '".$branch."', '".$status."', '".$category."', '".$comments."')"; $result = $db->query($query); if ($result) { echo $db->affected_rows." asset inserted into Inventory."; } else { echo "An error has occurred. The item was not added."; } $db->close(); ?> </fieldset> </div> </body> I decided to redo the individual roster page I have on my site and came up with this. <?php if(isset($_GET['username']) && $_GET['username'] != '') { $username = $_GET['username']; $query = "SELECT bio.username AS username, bio.charactername AS charactername, bio.id AS id, bio.style_id AS style FROM `efed_bio` AS bio ON bio.id = ebw.bio_id WHERE bio.username = '$username'"; if(!$result = mysql_query($query)) while ($row = mysql_fetch_assoc($result)) { $fieldarray=array('id','username','charactername','style'); foreach ($fieldarray as $fieldlabel) { if (isset($row[$fieldlabel])) { $$fieldlabel=$row[$fieldlabel]; $$fieldlabel=cleanquerydata($$fieldlabel); } } } } ?> <h1><?php echo $charactername; ?>'s Biography</h1> <?php echo getBioMenu($style,$username); ?> <? //If the GET page variable is biography, display the biography page if ($page == 'biography') { echo getBiopgrahy($style,$id); } //Or if the GET page variable is gallery, display the gallery page elseif ($page == 'gallery') { echo getGallery($style,$id); } //If the GET page variable is news, display the news page elseif ($page == 'news') { echo getNews($$id); } //If the GET page variable is segments, display the segments page elseif ($page == 'segments') { echo getBioSegments($id,S); } //If the GET page variable is matches, display the matches page elseif ($page == 'matches') { echo getBioSegments($id,M); } elseif ($page == 'chronology') { echo getChronology($id); } //Otherwise display the bio else { echo getBio($style,$id); } ?> The list of characters are listed he http://kansasoutlawwrestling.com/roster An example of someone's individual roster page is located he http://kansasoutlawwrestling.com/bio?username=oriel hi all, I am testing live and the data is downloading to the database but when it goes to the next page it gets this message. Warning: Wrong parameter count for mysql_result() in /home/ebermy5/public_html/html/login.php on line 25 Could not execute query THIS IS MY CODING ANY IDEAS WHERE I AM GOING WRONG. YES I HAVE THE OPEN AND CLOSE PHP? if (@$_SESSION['auth'] != "yes") @include('Connections/connect_to_mysql.php'); $query = "SELECT firstName, lastName FROM `Members` WHERE email='{$_SESSION['id']}'"; $result = mysql_result($query) or die("Could not execute query"); echo "<html> <head><title>New Member Welcome</title></head> <body> <h2 style='margin-top: .7in; text-align: center'> Welcome $firstName </h2>\n"; Okay, after successfully getting a form to input data to a MySQL database, I'm now trying to get the data back out by searching. Search form code: Code: [Select] <form name="search" method="post" action="process_search.php"> Seach for: <input type="text" name="find" /> in <select name="columns"> <option value="">Please choose one:</option> <option value="status">Status</option> <option value="date">Date</option> <option value="species">Species</option> <option value="breed">Breed</option> <option value="sex">Sex</option> <option value="primary_colour">Primary Colour</option> <option value="colour">Colour</option> <option value="distinctive_traits">Distinctive Traits</option> <option value="fur_length">Fur Length</option> <option value="age">Age</option> <option value="desexed">Desexed</option> <option value="microchipped">Microchipped</option> <option value="suburb">Suburb</option> <option value="pound_area">Pound Area</option> <option value="contact">Contact</option> <option value="link">Link</option> </Select> <input type="hidden" name="searching" value="yes" /> <input type="submit" name="search" value="Search" /> </form> All good there! Form displays how I want it to, and submits correctly. The bit I'm struggling with is the process_search.php side of things. This is what I have (note that i'm trying to get the results into a formatted table and I'd like more results if the match is in more than one column): Code: [Select] <? //Here we display stuff if they have submitted the form if ($searching =="yes") { echo "<h2>Results</h2><p>"; //If they stuffed up and didn't search for anything, we show them this if ($find == "") { echo "<p>Oh, Bianca, you need to enter SOMETHING to search!"; exit; } //If everything is all good, we connect to the database mysql_connect("localhost", "******", "******") or die(mysql_error()); mysql_select_db("******") or die(mysql_error()); //Let's not forget the register globals off crap $status = $_POST['status']; $date = $_POST['date']; $species = $_POST['species']; $breed = $_POST['breed']; $sex = $_POST['sex']; $primary_colour = $_POST['primary_colour']; $colour = $_POST['colour']; $distinctive_traits = $_POST['distinctive_traits']; $fur_length = $_POST['fur_length']; $age = $_POST['age']; $desexed = $_POST['desexed']; $microchipped = $_POST['microchipped']; $suburb = $_POST['suburb']; $pound_area = $_POST['pound_area']; $contact = $_POST['contact']; $link = $_POST['link']; $columns = $_POST['columns']; // We perform a bit of filtering $find = strtoupper($find); $find = strip_tags($find); $find = trim ($find); //Now we search for our search term, in the field the user specified $data = mysql_query("SELECT * FROM animal_info WHERE upper($columns) LIKE'%$find%'"); //And we display the results where($result = mysql_fetch_array( $data )) { echo "<tr>"; echo "<td>".$row['status']."</td>"; echo "<td>".$row['date']."</td>"; echo "<td>".$row['species']."</td>"; echo "<td>".$row['breed']."</td>"; echo "<td>".$row['sex']."</td>"; echo "<td>".$row['primary_colour']."</td>"; echo "<td>".$row['colour']."</td>"; echo "<td>".$row['distinctive_traits']."</td>"; echo "<td>".$row['fur_length']."</td>"; echo "<td>".$row['age']."</td>"; echo "<td>".$row['desexed']."</td>"; echo "<td>".$row['microchipped']."</td>"; echo "<td>".$row['suburb']."</td>"; echo "<td>".$row['pound_area']."</td>"; echo "<td>".$row['contact']."</td>"; echo "<td>".$row['link']."</td>"; echo "</tr>"; } else { echo "ERROR: ".mysql_error(); } //This counts the number or results - and if there wasn't any it gives them a little message explaining that $anymatches=mysql_num_rows($data); if ($anymatches == 0) { echo "Nope, couldn't find anything here! Maybe refine your search criteria?<br><br>"; } //And we remind them what they searched for echo "<b>Searched For:</b> " .$find; } ?> Trouble with this is that I'm not getting any errors OR results! ANY help would be appreciated HUGELY! Cheers, Dave Hi, I just connect to my server through ftp. i want to edit php.ini file. which is placed in /etc/php.ini "etc" folder. but i'm unable to see etc folder. there are only two folders one is cgi-bin and other is www. can anyone help me to find out etc folder. i've check to show hidden files in filezilla. Thanks Hi guys
I am using the code below to show distinct months using one query then for each month I am trying to show a list of fixtures for the month, the problem I have is only one month is showing.
where am i going wrong?
<?php //find distinct months $sql="SELECT DISTINCT MONTH( match_date ) AS MONTH FROM tbl_fixtures WHERE season_id =$current_season UNION SELECT DISTINCT MONTH( match_date ) AS MONTH FROM tbl_gp WHERE season_id =$current_season"; $result=mysqli_query($dbConn, $sql); if(mysqli_num_rows($result)>0){ while($row=mysqli_fetch_assoc($result)){ $month=$row['MONTH']; echo '<div class="fixtureMonth"> <h2>'.$months[$month].'</h2> </div> <div class="fixtures">'; //find fixtures for month $sql="SELECT Opposition, match_date, competition, tbl_clubs.club_name AS club, image, HomeAway, team, opposition_points, points FROM tbl_fixtures INNER JOIN tbl_clubs ON tbl_fixtures.club = tbl_clubs.club_id WHERE season_id =$current_season and MONTH(match_date)=$month UNION SELECT Opposition, match_date, \"SGP\" AS competition, \"SGP\" AS club, \"sgp.png\" AS image, \"\" as HomeAway, \"\" as team, \"\" as opposition_points, points FROM tbl_gp WHERE season_id =$current_season and MONTH(match_date)=$month ORDER BY match_date"; $result=mysqli_query($dbConn,$sql)or die(mysqli_error($dbConn)); if(mysqli_num_rows($result)==0){ echo no_fixtures_found; } else{ echo '<table class="fixturesTable">'; while($row=mysqli_fetch_assoc($result)){ echo'<tr> <td>'.date("d-M-Y",strtotime($row['match_date'])).'</td> <td><img src="'.$shopConfig['url'].'images/'.$row['image'].'"/></td> <td>'.$row['Opposition'].'</td> <td>'.$row['HomeAway'].'</td> <td><b>'.$row['team'].'</b>-'.$row['opposition_points'].'</td> <td>'.$row['team'].'</td> </tr>'; } echo '</table>'; } echo '</div>'; } } ?> |