PHP - Passing Value Of Variable From One Php File To Another Using $_post

I've been poking around the Internet for the answer to this without any success.  This query APPEARS to run, but NOTHING GETS INSERTED.  The QuestionID in the Questions table is set to auto-increment, so I only need the QuestionText data for this table. the QuestionID in the Answers table is not because there might be four or five options per question.  The snippets of code under consideration is pasted below

snipped from index.php:

Code: [Select]
<form action="./newquestion.php" method="post">
Question Text:<br><input type="text" size=100 name="QuestionText" /><br><br>
 <input type="submit" value="Enter next question"/>
</form>

Then snipped from newquestion.php


mysql_select_db(quiz);
$query = mysql_query("INSERT INTO Questions VALUES ('$_POST[QuestionText]'");
$result = mysql_query($query);


Thank you all.  I'm sure I'll learn this pretty fast, but I still need a little help.

I have a form that creates rows of data input textboxes depending on a user input number of things.  I have a naming convention for all these textboxes that basically just keeps incrementing a number suffix for each row.  All this is working fine.

My problem is I need to get the data inserted into this table of textboxes into an array.

Here's my code where I attempt to to this (it does not work):

Code: [Select]
$temp = $_SESSION['Num_Part'];
$count = 1;
while ($count <= $temp){
  $temp2[$count] = "'Participant_P".$count."'";
  //echo $temp2[$count]."<br/>";
  $temp3[$count]=$_POST[$temp2[$count]];  //here's the problem
  $temp4[$count] = "'Result_P".$count."'";
  $temp5[$count]=$_POST[$temp4[$count]];  //here's the problem
  //echo $temp4[$count]."<br/>";
  $count++;
}

The problem is that the $_POST does not work with the variable in the argument position - even though the argument is formatted with single quotes.

Can a variable be used in a POST argument and if so what is the correct syntax?

If not, is there some other simple solution to harvest the data into an array.  I understand I can harvest by explicitly accessing each key in the post assoc array.  But this could be dozens of rows of input fields.

Thanks in advance for your help here.  I couldn't find anything online re this topic.

Code: [Select]
$amountBoxName = "amount".$id; // Constructs the name of the input field
$amountToPay = strip_tags($_POST["$amountBoxName"]);
$amountBoxName then goes to 'amount22' says, however $amountToPay is then showing also as 'amount22', not getting the value of the text field whose name/id is amount22 on the previous page. How do I do this? I tried having " around the $amountBoxName, ' and no quotes although still can't get it working.

Why doesn't this code work...

Code: [Select]
// Initialize variables.
$form_value = '';
$form_value = $_POST['form_value'];


I get this error...

Quote

Notice: Undefined index: form_value


Thanks,


Debbie

Hi Everyone,

I'm trying to make an userlist where I have a button (or better a picture with a hyperlink) which if I click it I will be forwarded to a new page where the user name is send as a $_Post variable.
The code below is what I have this far. In some way when I click the send button it always gives the last username in the table in the $_Post variable. Can anyone help me please.

Thnx Ryflex
<?php

    require_once('auth.php');
    require_once('config.php');

$global_dbh         = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD)
                      or die("Could not connect to database");
                      mysql_select_db(DB_DATABASE, $global_dbh)
                      or die("Could not select database");

$user_query = "SELECT *
   FROM members";
$user_result = mysql_query($user_query);
?>
<form ID="gotoresource" NAME="gotoresource" METHOD="POST" ACTION="resource_compose.php"> 
<table width="500" border="1" align="center" cellpadding="2" cellspacing="0">
<tr>
<td><b>User</b></td>
<td><b>Resource</b></td>
</tr>
<?php
while($row = mysql_fetch_assoc($user_result))
{
echo "<tr>";
echo "<td>"; 
echo $row['login'];
$user = $row['login'];
?> 
<input name="User" type="hidden" maxlength="15" id="user" value="<?php echo $user; ?>"/>
</td>
<td>
<input type="submit" name="Submit" value="Send" />
</td>
    <?php
echo "</tr>";
}


?>
<html>
<head>
<title>Userlist</title>
<link href="loginmodule.css" rel="stylesheet" type="text/css" />
</head>
<body>

</body>

</html>

what would be the $_POST variable name for a radio button option?

User clicks on a url, ie: example.com/AEQ438J

When I perform this in the code below:

Code: [Select]
    $referrer = $_GET['_url'];
    // echo $referrer displays the referrer ID contents correctly as "AEQ438J"
   
    if ( ! empty($referrer))
    {
    $mysqli->query("UPDATE coming_soon_emails SET clicks = clicks + 1 WHERE code='" . $referrer ."'");
    }
    // this also updates the database correctly as it should

    if (!empty($_POST['email'])){

   // echo $referrer displays the referrer ID contents as BLANK. It should display "AEQ438J"!
    .....
$referrer displays correctly BEFORE if($_POST['form']), however during the if($_POST['form']) $referrer is empty.
How can I fix my code so that $referrer is not empty during the time the user posts their email address in the form?

Thank you!

Complete PHP and HTML

Code: [Select]
    <?php
    
    require "includes/connect.php";
    //var_dump($_GET);die;
    
    function gen_code($codeLen = 7) {     
    $code = '';     
    for ($i=0; $i<$codeLen; $i++) {         
     $d=rand(1,30)%2;       
     $code .= $d ? chr(rand(65,90)) : chr(rand(48,57));      }  
     return $code; 
     }  
    
    
     function add_code($email_id) {
     global $mysqli;
     $code = gen_code(7); 
     $mysqli->query("UPDATE coming_soon_emails SET code='" . $code ."' WHERE email_id='" . $email_id . "'");  
     if($mysqli->affected_rows != 1) {   
     add_code($email_id);  
     } else return $code; } 
    
    $msg = '';
    $referrer = $_GET['_url'];
    // echo $referrer displays the referrer ID contents correctly
    
    if ( ! empty($referrer))
    {
    $mysqli->query("UPDATE coming_soon_emails SET clicks = clicks + 1 WHERE code='" . $referrer ."'");
    }
    
    if (!empty($_POST['email'])){
    
    // echo $referrer displays the referrer ID contents as BLANK
    
        // Requested with AJAX:
        $ajax = ($_SERVER['HTTP_X_REQUESTED_WITH']  == 'XMLHttpRequest');
    
        try{
            if(!filter_input(INPUT_POST,'email',FILTER_VALIDATE_EMAIL)){
                throw new Exception('Invalid Email!');
            }
    
            $mysqli->query("INSERT INTO coming_soon_emails
                            SET email='".$mysqli->real_escape_string($_POST['email'])."'");
    
            if($mysqli->affected_rows != 1){
                throw new Exception('This email already exists in the database.');
            } else {   
              $email_code = add_code($mysqli->insert_id); 
            } 
    
     $msg = "http://www.example.com/" . $email_code;
    
     //the following doesn't work as referrer is now empty :(
     if ( ! empty($referrer))
     {
     $mysqli->query("UPDATE coming_soon_emails SET signup = signup + 1 WHERE code='" . $referrer ."'");
            }
    
     if($ajax){
     die(json_encode(array('msg' => $msg)));
     }
    
        }
        catch (Exception $e){
    
            if($ajax){
                die(json_encode(array('error'=>$e->getMessage())));
            }
    
            $msg = $e->getMessage();        
        }
    }
    
    ?>
   
   
    <!DOCTYPE html>
    <html>
    <head>
    <meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
    <title></title>
   
    <link rel="stylesheet" type="text/css" href="css/styles.css" />
   
    </head>
   
    <body>
   
    <div id="launch">
   
       
        <form id="form" method="post" action="">
        <input type="text" id="email" name="email" value="<?php echo $msg;?>" />
            <input type="submit" value="Submit" id="submitButton" />
        </form>
       
        <div id="invite">
        <p style="margin-top:20px;">The ID of who referred you: <?php echo $referrer; //this displays correctly?>)</p>
        <p style="margin-top:20px;"><span id="code" style="font-weight:bold;">&nbsp;</span></p>
    </div>
   
       
    </div>
    <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.3/jquery.min.js"></script>
    <script src="js/script.js"></script>
    </body>
    </html>
script.js

Code: [Select]
    $(document).ready(function(){
   
    // Binding event listeners for the form on document ready
   
    $('#email').defaultText('Your Email Address');
   
    // 'working' prevents multiple submissions
    var working = false;
   
    $('#form').submit(function(){
   
    if(working){
    return false;
    }
    working = true;
   
    $.post("./index.php",{email:$('#email').val()},function(r){
   
    if(r.error){
    $('#email').val(r.error);
    } else {
        $('#email').val(r.msg); // not needed but gets hidden anyways...
    $('#launch form').hide();
    $("#code").html(r.msg);
    $("#invite").fadeIn('slow');
    }
   
   
    working = false;
    },'json');
   
    return false;
    });
    });
   
    // A custom jQuery method for placeholder text:
   
    $.fn.defaultText = function(value){
   
    var element = this.eq(0);
    element.data('defaultText',value);
   
    element.focus(function(){
    if(element.val() == value){
    element.val('').removeClass('defaultText');
    }
    }).blur(function(){
    if(element.val() == '' || element.val() == value){
    element.addClass('defaultText').val(value);
    }
    });
   
    return element.blur();
    }
htaccess

Code: [Select]
    RewriteEngine on
   
    RewriteCond %{HTTP_HOST} ^my-url.com
    RewriteRule (.*) http://www.my-url.com/$1 [R=301,L]
   
    RewriteCond %{REQUEST_FILENAME} !-f
    RewriteCond %{REQUEST_FILENAME} !-d
    RewriteRule ^([a-z0-9]+)$ /index.php?_url=$1 [NC,L,QSA]
table.sql

Code: [Select]
    CREATE TABLE IF NOT EXISTS `coming_soon_emails` (   
      `email_id` int(11) NOT NULL auto_increment,   
      `email` varchar(64) collate utf8_unicode_ci NOT NULL,   
      `code` char(7) collate utf8_unicode_ci DEFAULT NULL,
      `clicks` int(64) collate utf8_unicode_ci DEFAULT 0,
      `signup` int(64) collate utf8_unicode_ci DEFAULT 0,
      `ts` timestamp NOT NULL default CURRENT_TIMESTAMP,   
      PRIMARY KEY  (`email_id`),   
      UNIQUE KEY `email` (`email`),
      UNIQUE KEY `code` (`code`)
    ) ENGINE=MyISAM DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci;

I have tilbud.php file that has no output. Just receives data and adds them into MySQL table. Inside tilbud.php file I have JavaScript code that calls products.php. Product.php has the following code:

if(!isset($_POST['userid'])) {
  echo "<script type='text/javascript'>";
    echo "window.location = 'index.php'";
  echo "</script>";
 
  exit;
}

So, I you call product.php without submitting $_POST['userid'] it redirects you into index.php. How to submit $_POST['userid'] into products php without using <form method='POST' action='product.php'> ?

Hi all,

I've done a LOT of googling on this and found things that match what I need but nothing actual achieves what I need.

I've used one php file before for doing multiple jobs (ie registration?step=2 / 3 etc), but I've boo-booed somewhere and it only works up until step 2, step 3 doesn't work.  Here's what I have currently, it also leads me on to the next question.

Code: [Select]
<?php if(isset($_GET['step']) == 2) { ?>
   Please select the problem you are encountering.
   <a href="registration.php?step=3&console=<?php $_GET['console'] ?>&issue=1rrod"><img src="store/image/data/1rrod.gif" width="92" height="92" /></a>
   <?php } if (isset($_GET['step']) == 3) { ?>
   END
   <?php } else {?>
   Please select which type of Xbox 360 you have<br />
    <a href="registration.php?step=2&console=xbox"><img src="images/xbox360.gif"></a>
    <a href="registration.php?step=2&console=xboxslim"><img src="images/xbox360e.gif"></a>   
    <?php } ?>
So, first step (which is bottom), lets you select which type of console it is - only two possible choices.  That then passes that data to step 2, which is what issue the console is having. 

Now I've tried this with $_POST, as I would prefer to work that way.  I've experimented with $_SESSION to try and pass everything I need, using code found elsewhere.  But I just can't get it to pass from page to page and finally be able to use it to email in the final step.

Final issue - I want to use images instead of buttons to be able to pass the variables.  I've found that using hidden type input does work but I think this issue is related to the above one.

Thanks!

Jason

Hi, can anybody please tell me how i can make "Arson" into a php variable

Code: [Select]

<script type="text/javascript" src="js/swfobject.js"></script>
<script type="text/javascript">

swfobject.embedSWF(
  "open-flash-chart.swf", "my_chart",
  "550", "400", "9.0.0", "expressInstall.swf",
  {"data-file":"ofc-chart.php?crime=Arson"} );
 
</script>
 

I had an iframe working for the last few months on a site at hostgator.  Yesterday, it quit working (403 permissions error).  After a long bout of trouble-shooting, I found out that it has something to do with mod_security that they have suddenly enabled (have no idea as I'm not a Linux guy). 

They told me they fixed the problem on my domain by whitelisting it as an exception, but strangely, even though the permissions error went away, the actual src= box of the iframe, which was the url variable I was passing in the url, no longer loads. 

So.. I'm trying to break this down into the simplest form to figure it out.  I just understand php basics so needing some verification that I'm doing this right/wrong. 

Here's my code.. 

page1.php
Code: [Select]
<? $testurl = "http://google.com"; ?>
<a href="http://mysite.blah/page2.php?url=<? echo $testurl; ?>">page2.php</a>
page2.php
Code: [Select]
if (isset($_GET['testurl'])) echo $testurl;
else echo "sorry dude";
I am only able to print "sorry dude". 
Am I doing something wrong or shouldn't this send the url? 

Thanks for the help!

I'm an hour worth of searches into this. It's 2:30. I just want some nice person to give me the answer.

I'm trying to pass a variable using href to another page. It works great if the variable is only one word. But it only passes the first word. There are multiple posts on this topic, but I can't seem to get any of those fixes to work for me.

Here the code.
Code: [Select]
<?php
$query = "select DISTINCT city from daily where open_bid>0 order by city ASC";
$result = mysql_query($query);
while ($row = mysql_fetch_array($result, MYSQL_ASSOC))
{
$details='';
$details.='<li class="menu"><span class="name"><a href=list.php?city='.$row['city'].'>'.$row['city'].'</a>';
$details.='</li>';
echo($details);
}
?>

As you can imagine, some cities names are made up of two words. This is only passing the first word.

Thanks for your help.

This is driving me MAD!

The Variable gets passed through the URL but when I try and echo the result I gte NOTHING.

First Page.

Code: [Select]
<?php include'config.php';


$result = mysql_query("SELECT * FROM carbontrust");

while($entry = mysql_fetch_array($result))


Print "$entry[contact] - $entry[company] :: <a href='edit.php?id=$entry[id]'>Edit</a><br>";

exit;

?>


Second Page. (Where I want the Variable passed to)
Code: [Select]
<?php include'config.php';


$id = $_GET['id'];
echo "ID: $id";


}


?>

Its probably just a stupid error but iv looked through a load of tutorials and this should be correct. :/

Trying to set up an error message when someone tries to upload a file without the approved .ext.
I have it working so it won't up load but I am trying to get an error to print out.

I was thinking that I could do something like this

if the ext are wrong set
$errorMsg1 == 1;
and then the page will refresh and I would pass that variable to echo out

if ($errorMsg1 == 1){
echo "Invalid"; }
else {

but it isn't passing can anyone help me with this? Tyring to keep it simple

this is the code to select an image

else{
 
  $result = mysql_query("SELECT * FROM photos WHERE userID LIKE '$clientID'");
  while ($r=mysql_fetch_array($result))
  {
     $photo_1=$r['photo_1'];
     $photo_2=$r['photo_2'];
     $photo_3=$r['photo_3'];
     $photo_4=$r['photo_4'];
     $photo_5=$r['photo_5'];

   echo " 
    <form enctype='multipart/form-data' action='' method='POST'>
      <input type='hidden' name='MAX_FILE_SIZE' value='500000' />
      <div id='imageTop'>Image &#38;#35;1</div>
        ";
        if ($errorMsg1 == 1){
       echo "Invalid"; }
       echo "

       <div id='imageBottom'>
         <span class='image'>";
           if (empty($photo_1)) { 
            echo " <img src='uploads/noPhoto.gif' width='75' height='75' class='zip'> ";
              }
            else {
             echo "<a href='uploads/$photo_1' ><img src='uploads/$photo_1' width='75' height='75' class='zip'></a> ";
              }
            echo " 
         </span>
         <span class='action'>
            &nbsp;<input type='file' name='photo_1' class='zip'><br><br>
            <input type='checkbox' name='delete_1'>Select to Delete image
          </span>
       </div>

}


this is the code of what to do with that image

  if (isset($_POST['delete_1']))  {
    $query = "UPDATE photos SET photo_1='' WHERE userID='$clientID'";
    $result = mysql_query($query) or die(mysql_error());
    echo " <div id='aboutUpdate'><img src='img/loader.gif'> Information is updating</div> ";
    echo "<meta http-equiv=refresh content=\"0; URL=photos.php\">";
  }
  else if ($one != NULL) {
    $extension = strrchr($_FILES['photo_1']['name'],'.');
    $extension = strtolower($extension);

    if($extension != '.jpg' && $extension != '.gif' && $extension != '.png' && $extension != '.bmp' ){
      $errorMsg1 == 1;
      echo "<meta http-equiv=refresh content=\"0; URL=photos.php\">";
    }
    else {
    $photoNumber="_1";
    $finalName="$clientID$photoNumber";
    $save_path = "uploads/";
    $target_path = $save_path . basename( $_FILES['photo_1']['name']); 
    $NewPhotoName = $finalName; 
    $withExt = $NewPhotoName . $extension;
    $filename = $save_path . $NewPhotoName . $extension; 
    if(move_uploaded_file($_FILES['photo_1']['tmp_name'], $filename)) {
      $query = "UPDATE photos SET photo_1='$withExt' WHERE userID='$clientID'";
      $result = mysql_query($query) or die(mysql_error());
        echo " <div id='aboutUpdate'><img src='img/loader.gif'> Information is updating</div> ";
        echo "<meta http-equiv=refresh content=\"0; URL=photos.php\">";
      }
    }
    else  {

Hi,
I am trying to pass a variable when posting a form.
This is my form with the select:
Code: [Select]
<form id="form1" name="form1" method="post"  action="products_2.php?id_subcategoria= WHAT SOULD I PUT HERE?">
<select name="subcats" class="subcatsSelectMenu" id="subcats" onchange="this.form.submit()">
<option value="">Ver placas por tipos</option>
<?php
do {  
?>
<option value="<?php echo $row_subcats_RS['id_subcategoria']?>"><?php echo $row_subcats_RS['subcategoria_esp']?></option>
<?php
} while ($row_subcats_RS = mysql_fetch_assoc($subcats_RS));$rows = mysql_num_rows($subcats_RS);
  if($rows > 0) {
      mysql_data_seek($subcats_RS, 0);
  $row_subcats_RS = mysql_fetch_assoc($subcats_RS);
  }
?>
</select>
</form>How can I pass the variable in the URL?
Thanks