|
PHP - Changing Session Value On Drop Down Menu Submit
Hi all
I am trying to write a piece of code that allows a user to select a country from the drop down menu and them submit it so that it changes the delivery cost in the session. Here's the code for the drop down menu: echo "<form method=\"post\" action=\"basket.php\">"; echo "<select name=\"postal_area_name\" >"; echo "<option value=\"\">--Please Select--</option>"; echo "<option value=\"England\">England</option><option value=\"Scotland\">Scotland</option><option value=\"Wales\">Wales</option>"; echo "</select>"; echo "<input type=\"submit\" name=\"submit_postal_area\" value=\"Go\" class=\"go\">"; echo "</form>"; Then here's my code to grab the delivery change from the form: if(isset($_POST['postal_area_name'])) { $_SESSION['postal_area'] = ($_POST['postal_area_name']); header("Location: basket.php"); exit; } Then this is to set the session price: if(isset($_SESSION['postal_area']) && $_SESSION['postal_area'] == "England") { $set_delivery = "5.95"; } elseif(isset($_SESSION['postal_area']) && $_SESSION['postal_area'] == "Wales") { $set_delivery = "10.00"; } elseif(isset($_SESSION['postal_area']) && $_SESSION['postal_area'] == "Scotland") { $set_delivery = "20.00"; } else { $set_delivery = "5.95"; } $subtotal += $set_price * $qty; $delivery += $set_delivery * $qty; Then I echo out the $delivery in the basket. This doesn't seem to update, it shows the value as being 0 all the time? Please help Thanks Pete Similar TutorialsHi all I am trying to get my drop down menu to use a session variable as the selected menu option. Here's my code: echo "<option value=\"\">Delivery Area</option>"; $selected = ""; if(isset($_SESSION['postal_area']) && $_SESSION['postal_area'] == "England") { $selected = "selected"; } elseif(isset($_SESSION['postal_area']) && $_SESSION['postal_area'] == "Wales") { $selected = "selected"; } elseif(isset($_SESSION['postal_area']) && $_SESSION['postal_area'] == "Scotland") { $selected = "selected"; } else { $selected = ""; } echo " <option value=\"England\" selected=\"".$selected."\">England</option>"; echo "<option value=\"Scotland\" selected=\"".$selected."\">Scotland</option>"; echo "<option value=\"Wales\" selected=\"".$selected."\">Wales</option>"; echo "</select>"; However, this shows the 'Wales' one all the? Please help! Many thanks Pete Hi everyone, as the title stated, I would like to know how I could submit a form in one page(cart) and unset a session variable on other page.
Right now my form is setting a variable within the page back to 0, however I would like the form to unset the session variable from other page as well.
The issue with my code is that every time I attempt to clear out all items, my code can empty out the cart. But whenever I close and reopen the cart, the same content will show up again. So I need to unset the session variable.
Please let me know what should I do in order to solve the problem and I greatly appreciate your help.
My code is currently looking like this:
cart.php
if(!empty($_GET['aID']))
{
$aID = $_GET['aID'];
echo $aID;
if(isset($_POST['removeAll']))
{
$aID = "0";
}
$cartSQL = "SELECT * from article where aID in ($aID)";
echo "cart sql :$cartSQL";
$cartQuery = mysqli_query($dbc, $cartSQL) or die (mysqli_error($dbc));
while($row = mysqli_fetch_array($cartQuery, MYSQLI_BOTH))
{
$aTitle[] = $row[ 'name' ];
}
}
<form action = "" method = "POST">
<td style = "width = 200px"><input type="submit" value="Empty cart" name="removeAll"></td>
</form>
And this is the session variable from other page where I would like it to be unset upon submitting the form.
if(!empty($cartSubmit))
$_SESSION["cartSubmit"] = $cartSubmit;
else
$cart = $_SESSION["cartSubmit"];
<a href="javascript:popup('cart.php?aID=<?php if(empty($cartSubmit)) echo "$cart"; else echo "$cartSubmit";?>')">Cart</a>
How would you do a drop down box using session So far I have <?php $_SESSION['username']; $query="SELECT DISTINCT u.Use_Name, u.Use_ID, u.Use_Name, us.Sub_ID, s.Sub_Name FROM user u, user_x_subject us, subject s WHERE u.Use_Name = '$username' AND u.Use_ID = us.Use_ID AND s.Sub_ID = us.Sub_ID"; $result = mysql_query($query); while($nt=mysql_fetch_array($result)){ echo "<option value=$nt[Sub_ID]>$nt[Sub_Name]</option>"; } echo "</select>";// ?> I am trying to create a page for customers to enter their details. I am using a html form.
When the submit button is pressed the form posts the inputs to the same page, which then checks if the inputs are empty. If they are not then each post variable is allocated a session variable so this info can be accessed late on in the system.
If some of the inputs are empty then the value of the input forms become equal to the session variables that they were just allocated to so that the customer doesn’t have to retype their information.
This is where the problem occurs. When I load the page each input box has a slash inside it and when the submit button is pressed a mother slash is added.
My code is below:
<?php
session_start();
if(isset($_POST['NextPage'])){
if (!empty($_POST['CName'])){
$_SESSION["CName"] = $_POST['CName'];
if (!empty($_POST['CStreet'])){
$_SESSION["CStreet"] = $_POST['CStreet'];
if (!empty($_POST['CTown'])){
$_SESSION["CTown"] = $_POST['CTown'];
if ($_POST['Counties'] != "-"){
$_SESSION["CCounty"] = $_POST['Counties'];
if (!empty($_POST['CPostcode'])){
$_SESSION["CPostcode"] = $_POST['CPostcode'];
if (!empty($_POST['CEmail'])){
$_SESSION["CEmail"] = $_POST['CEmail'];
if (!empty($_POST['CNumb'])){
$_SESSION["CNumb"] = $_POST['CNumb'];
$NotEmpty = true;
}else{
$ErrorMsg = "Number is empty. </br>";
}
}else{
$ErrorMsg = "Email is empty. </br>";
}
}else{
$ErrorMsg = "Postcode is empty. </br>";
}
}else{
$ErrorMsg = "County is empty. </br>";
}
}else{
$ErrorMsg = "Town is empty. </br>";
}
}else{
$ErrorMsg = "Street is empty. </br>";
}
}else{
$ErrorMsg = "Name is empty. </br>";
}
}
$content = ' <h3 id="CTitle"> Customer Details </h3>
<p><i>'.$ErrorMsg.'</i></p>
<form action=" " method="POST" name="CDetails" id="CDetails">
Name: * <input type="text" name="CName" size="30" value='.$_SESSION["CName"].'/></br>
First line of your address: * <input type="text" name="CStreet" size="40" value='.$_SESSION["CStreet”];.’/></br>
Town: * <input type="text" name="CTown" size="25" value='.$_SESSION["CTown"].'/></br>
Postcode: * <input type="text" name="CPostcode" size="11" value=‘.$_SESSION["CPostcode"].'/></br>
Email address: * <input type="text" name="CEmail" size ="35" value='.$_SESSION["CEmail”];.’/></br>
Phone Number: * <input type="text" name="CNumb" value='.$_SESSION["CNumb"].'/></br>
<input type="submit" name="NextPage" value="Next" id="Next”/>
</form>
?>
I am trying to make a Web Form for people to fill out that has two drop down menus where i want the first drop down menu's selection changes the values of the selections in the second drop down. ((IE. If the first drop down value is "product 01" then the second drop down shows values "Red, Green, Blue" while if the first drop down value is "product 02" then the second drop down shows values "Yellow, Green")) Anyone have any ideas? Thanks in Advance. I'm trying to repopulate a dropdown list when the user hits the submit button to add another item to the dropdown. I'm trying to use the isset method, but am having some issues implementing it properly. Can anyone steer me in the right direction? <html> <head><title>Dynamic List</title></head> <body> <form action="test.php"><select name="list">; <? if (isset($_POST['submit'])){ $file = file("test.txt"); sort($file); foreach($file AS $country){ echo "<option>".$country."</option>\n"; } } ?> </select> </form> please enter your new country:<br> <form action=test.php method="post"> <input type="text" name="name">: enter your country<br> <input type="submit" name="submit"> </form> <? $file = "test.txt"; $tf = @fopen("$file", "a+"); $name = "\n" . $_POST["name"]; $write = fwrite($tf, $name); @fclose($file); ?> </body> </html> I'm simply trying to set up a form where, if when a user clicks 'Submit', and then 'Back', the values from the form are preserved. My question is, how do I preserve the values of drop down menus. The following is a snippet of my code: Code: [Select] <select name="dropdown_dept" id="dept_list"> <option value=0><?php echo "Please select one..."?></option> <?php $dropdown_dept = "select dept_name from departments"; $result_dept = $db_conn->query($dropdown_dept); if (!$result_dept) { echo '<p>Unable to get department data.</p>'; return false; } for($i=0; $i<$result_dept->num_rows; $i++) { $app_name_row = $result_dept -> fetch_array(); ?> <option><?php echo($app_name_row[0]); ?></option> <? } ?> </select> Above is where I have set up a drop down menu of departments. Given that code, how can I preserve the department name after a user clicks 'Submit'? This topic has been moved to Ajax Help. http://www.phpfreaks.com/forums/index.php?topic=341998.0 Hi all !
I wish to post the value of an auto submit dropdown value to another page, be redirected to that page, and use it on that page. I am unable to achieve this in php and so I tried as :-follows:-
dropdown.php
<form method="post" action = dropdownaction.php>
<select name="myselect" onchange="this.form.submit();">
<option>blue</option>
<option>red</option>
</select>
</form>
and now I need the equivalent of
dropdownaction.php
<?php if(isset($_POST(['myselect']))) echo " I am selected".$_POST['myselect']; ?>Please can someone tell me how I may retrieve the value of 'myselect' in the dropdownaction.php after being redirected to it. Thanks loads. Hello, I have the following function function make_agent_drop($dropname,$parent=''){ $agents = mysql_query("SELECT * FROM ad_category WHERE cat_status='1' AND parent_id='".(is_numeric($parent)?$parent:"0")."'") or die(mysql_error()); $anum = mysql_num_rows($agents); if($anum>0){ $agentdrop='<select style="width:150px; height:20px; margin-left:100px; font-size:11px;" name="'.$dropname.'" id="'.$dropname.'" class="text" '.(is_numeric($parent)?'':'onchange="update_subcatdrop($(this).val());').'"> <option value="0">Select a Category</option>'; while($row= mysql_fetch_array($agents)){ $agentdrop.='<option value="'.$row['cat_id'].'">'.$row['cat_name'].'</option>'; } $agentdrop.='</select>'; }else{ $agentdrop= 'No '.(is_numeric($parent)?'Sub':'').'Categories Found.'; } return $agentdrop; ; } I creates a drop down from database cats and sub cats.. I am trying to figure out how to add a submit button to dynamically appear when it displays the sub category... Thanks! Dan This topic has been moved to JavaScript Help. http://www.phpfreaks.com/forums/index.php?topic=310879.0 Hi. I have just one question (I have searched for an answer for this but have not been able to locate one): How do you go about changing the text on a "Submit Query" button to display simply "Submit"? Below is the current code for the page that displays said button. Thank-you in advance for any help or direction. <?php include 'connection.php'; $query = "SELECT * FROM people"; $result = mysql_query($query) or die(mysql_error()); while ($person = mysql_fetch_array($result)){ echo $person ['name']; echo $person ['descrip']; } ?> <H1>Add Your Review:</H1> <form action="create.php" method="post"> Subject <input type="text" name="inputName" value=""/> </br > Review <textarea cols="50" rows="4" name="inputDesc" value=""/></textarea> </br > <input type= "submit" name= "submit"/> </form> <html> <head></head> <body> <p>The current second is <span style='font-size:16px;font-weight:bold;color:red;position:absolute;right:25px;'><?php echo time(); ?></span> on this computer.</p> </body> </html> hello all, I was hoping someone could help me figure out how to add sizes to my shopping cart. Right now the items add just fine. The site sells shirts and I'm having trouble displaying the sizes once selected and added to the cart. It will post the size selected, but if the customer tries to add another shirt the size will overwrite the last. Any help is appreciated. Heres how I add items to the cart... Code: [Select] session_start(); // Process actions $cart = $_SESSION['cart']; $action = $_GET['action']; switch ($action) { case 'empty': if($cart) { unset($cart); } break; case 'add': if ($cart) { $cart .= ','.$_GET['product_id']; } else { $cart = $_GET['product_id']; } break; The form with the size selection and add to cart button.. Code: [Select] <form action="cart.php?action=add&product_id=<?php echo $row_rs_products['product_id'] ?>" method="POST" name="addcart" id="addcart"> <table width="300" border="0"> <tr> <td><label for="sizes"></label> <select name="product_size" id="product_size" title="<?php echo $row_rs_products['product_size']; ?>"> <?php do { ?> <?php } while ($row_rs_sizes = mysql_fetch_assoc($rs_sizes)); $rows = mysql_num_rows($rs_sizes); if($rows > 0) { mysql_data_seek($rs_sizes, 0); $row_rs_sizes = mysql_fetch_assoc($rs_sizes); } ?> </select></td> <td><input type="submit" name="submit" id="submit" value="add to cart"> function displaying the cart.. Code: [Select] function showCart() { global $db; $cart = $_SESSION['cart']; if ($cart) { $items = explode(',',$cart); $contents = array(); foreach ($items as $item) { $contents[$item] = (isset($contents[$item])) ? $contents[$item] + 1 : 1; } $output[] = '<form action="cart.php?action=update" method="post" id="cart">'; $output[] = '<table>'; // start div $output[] = '<div id="cart_table">'; // $output[] = '<tr>'; $output[] = '<td><h4>Product</h4></td>'; $output[] = '<td><h4>Item No.</h4></td>'; $output[] = '<td><h4>Price</h4></td>'; $output[] = '<td><h4>Size</h4></td>'; $output[] = '<td><h4>Quantity</h4></td>'; $output[] = '<td><h4>Price Total</h4></td>'; $output[] = '<td><h4> </h4></td>'; $output[] = '</tr>'; //new row foreach ($contents as $product_id=>$qty) { $sql = 'SELECT * FROM products WHERE product_id = '.$product_id; $result = $db->query($sql); $row = $result->fetch(); extract($row); // $output[] = '<tr>'; $output[] = '<td><a href="product.php?product_id='.$product_id.'">'.$product_title.'</a></td>'; $output[] = '<td>'.$product_plu.'</td>'; $output[] = '<td>$'.$product_price.'</td>'; // //$output[] = '<td>'.$product_size.'</td>'; $output[] = '<td>'.$_POST['product_size'].'</td>'; // $output[] = '<td><input type="text" name="qty'.$product_id.'" value="'.$qty.'" size="3" maxlength="3" /></td>'; $output[] = '<td>X $'.($product_price * $qty).'</td>'; $total += $product_price * $qty; $output[] = '<td><a href="cart.php?action=delete&product_id='.$product_id.'" class="r">Remove</a> </td>'; $output[] = '</tr>'; //end div $output[] = '</div>'; } $output[] = '</table>'; $output[] = '<p>Grand total: <strong>$'.$total.'</strong></p>'; $output[] = '<div class="float-right"><button type="submit">Update cart</button>'; $output[] = '</form>'; Hi, i know this is probably very basic but i have been banging my head and looking for tuts. i have built a mysql php dropdown menu. all displays fine. now, how do i get the menu to actualy take me to a new url? the new url should be www.mysite.com/"menu selection" Code: [Select] <? include_once 'includes/db.php'; $result = mysql_query("select * from crimerate WHERE DISTRICT = 'Limpopo'", $con); if (!$result) { die('Invalid query: ' . mysql_error()); } $options=""; while ($row=mysql_fetch_array($result)) { $id=$row["id"]; $crime=$row["CRIME"]; $options.="<OPTION VALUE=\"$id\">$crime</option>"; } ?> <SELECT NAME=crime> <OPTION VALUE=0>Choose <?=$options?> </SELECT> Hi I have a temporary web page with a drop down menu. Problem is to get rid of the gap on the drop down menus. Any help please
www.des-otoole.co.uk/top_menu
Hi i currenlty have adrop box filled with companies so the user can select which company they woudl like services from but the default is currently 0 and is to selecvt all firms but im unsure how to do this. Current code: Code: [Select] <td>Taxi Firm</td><td> <select name="taxifirm"> <option value="0" selected>All Taxi Firms</option> <?php $sql = mysql_query("SELECT * FROM taxi_Firms"); while($row = mysql_fetch_array($sql)){ $uid = $row["Firm_ID"]; $username = $row["Firm_Name"]; echo '<option value="'.$uid.'">'.$username.'</option>' ; } ?> amny help is welcomed thanx I did search this up but all of them were lists.
I want to make a menu drop down like so....
Non-clicked...
Clicked...
The grey boxes would be images (unless it is easier to code them).
I am a complete noob so please don't use technical terms
Thanks
im fairly new to php so tend to do trial and error..... more error than trial tbh. im wondering if it is possible to get a drop down menu to fill from a mysql database and to arrange it alphabetically. i have created the menu just dont know how to arrange it better. also how can i use the items id in drop menu to load other info from that row on the database. hope you can help me. Code: [Select] <FORM> <?php $result = mysql_query( "SELECT * FROM movie_info" ) ; echo "<select name= film onChange='submit()' >film name</option>"; while ($nt=mysql_fetch_array($result)){ ?> <?php echo "<option value='$nt[id]'>$nt[title] </option>"; } ?> </select> </FORM> Okay, so, here's the scenario. I have a form that is editing an item that is already in the database. The text fields fill in just fine with that info. However, the drop down menus don't retrieve that info, rather resorting to the defaults, which can be a problem if you don't remember what you originally had. Is there anyway to make the dropdown menus pull the info from the table and use that rather than resorting back to the default? I tried using this: Code: [Select] <tr><td width="20%">Bonus:</td><td><select name="bonus" value="{{bonus}}"> <option value="Attack" {{bonus1select}}>Add to the attack power of weapon</option> <option value="Defense" {{bonus2select}}>Add to the defensive power of armor</option> <option value="None" {{bonus3select}}>No effect</option> </select><br /></td></tr> So, it's obvious the "value" portion not working. Any help would be great!! |
|||||||