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PHP - Updating A Count In A Form
I want to write a guessing game that gives a user four tries to guess a number between 1 and 10.
The problem is that every time the user hits submit, count is reset to zero and 1 is added. Please help. Here is my code: <html> <head> <title>Guessing Game </title> </head> <h1>Guessing Game </h1> <form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post"> <input type="hidden" name="count" value="<?php $count++; ?>" /> <p><input type="text" name="guess" /></p> <p><input type="submit" value="Guess" /></p> </form> </body> </html> <?php $random = rand(1,10); $guess = $_POST['guess']; if ($guess >= 10) { echo"Guess has to be lower than 10"; } elseif (isset($guess) && ($guess <= 1)) { echo "Guess has to be higher than 1"; } else { if ($guess == $random) { echo "Congratulations. You Win!!!!"; $count = 4; } elseif (isset($guess) && ($guess != $random)) { echo "Try again"; $count++; } elseif (($count == 4) && ($guess != $random)) { echo "Game Over. You Lose!!!"; } } ?> Similar TutorialsI can't get my form to update the database with user personal information. Any help greatly appreciated. Upon submitting the form, it just reloads the page, no information added to the DB. I used the update statement because I want the users to be able to update the info at a later date. Not sure if that was the right thing to do. thank you. Code: [Select] <?php ini_set ("display_errors", "1"); error_reporting(E_ALL); include('bouncer.php'); $host = ""; $database = ""; $username = ""; $password = ""; $tbl_name = "users"; $conn = mysql_connect($host, $username, $password) or die("Could not connect: " . mysql_error()); if($conn) { mysql_select_db($database); } else { echo "failed to select database"; } $currentUser = $_SESSION['myusername']; // get user from login and make it current user to use for update statement echo "Login success!<br/>"; echo "Please fill out the form below to add your personal information to the database<br/>"; ////////////////////////////////////////////////////////////////////////////////////////////////// if(isset($_POST['submit'])) { $firstname = mysql_real_escape_string( $_POST['first']); $lastname = mysql_real_escape_string( $_POST['last']); $dob = mysql_real_escape_string( $_POST['dob']); $gender = mysql_real_escape_string( $_POST['gender']); $result= mysql_query ( "UPDATE users SET firstname = '$firstname', lastname = '$lastname', dob = '$dob', gender='$gender' WHERE username='$currentUser'") or die(mysql_error()); if($result) { echo "your information was updated in the database and is as follows <br/>"; //put the results on the screen echo "<br/> $firstname <br/>"; echo "<br/>$lastname <br/>"; echo "<br>$dob <br/> "; echo ">$gender <br>"; } else { echo "error, could not update your info to the database </br>";//end if result } }//end if sumbit post statement at top ?> <html> <body> <p> </p> <p> </p> <p> <form action="login_successERROR.php" method="post"> <p> <input type="text" name="first" size="20" /> First name<br /> <input type="text" name="last" size="20" /> Last name<br /> <input name="dob" type="text" size="20" id="dob" /> Date of Birth<br /> <input type="text" name="gender" size="20" id="gender" /> Gender <br /> <input type="submit" value="Add personal information to database" /> <input type="reset" value="Reset fields" /> </p> </p> </form> <p><a href="index.php">HOME</a></p> <p> </p> </body> </html> Hi there im going a little bit mad now.... i spent a while trying to work out why my form didnt update or redirect... After head scratching i remade a test form... That also doesnt update or redirect?? I must be missing something here?? So basically when the user clicks submit nothing happens, why?? Code: [Select] <?php require_once('Connections/swb.php'); ?> <?php session_start(); if (!function_exists("GetSQLValueString")) { function GetSQLValueString($theValue, $theType, $theDefinedValue = "", $theNotDefinedValue = "") { $theValue = get_magic_quotes_gpc() ? stripslashes($theValue) : $theValue; $theValue = function_exists("mysql_real_escape_string") ? mysql_real_escape_string($theValue) : mysql_escape_string($theValue); switch ($theType) { case "text": $theValue = ($theValue != "") ? "'" . $theValue . "'" : "NULL"; break; case "long": case "int": $theValue = ($theValue != "") ? intval($theValue) : "NULL"; break; case "double": $theValue = ($theValue != "") ? "'" . doubleval($theValue) . "'" : "NULL"; break; case "date": $theValue = ($theValue != "") ? "'" . $theValue . "'" : "NULL"; break; case "defined": $theValue = ($theValue != "") ? $theDefinedValue : $theNotDefinedValue; break; } return $theValue; } } $editFormAction = $_SERVER['PHP_SELF']; if (isset($_SERVER['QUERY_STRING'])) { $editFormAction .= "?" . htmlentities($_SERVER['QUERY_STRING']); } if ((isset($_POST["MM_update"])) && ($_POST["MM_update"] == "form1")) { $updateSQL = sprintf("UPDATE player SET `Day`=%s WHERE PlayerName=%s", GetSQLValueString($_POST['days'], "int"), GetSQLValueString($_POST['playername'], "text")); mysql_select_db($database_swb, $swb); $Result1 = mysql_query($updateSQL, $swb) or die(mysql_error()); $updateGoTo = "logout.php"; if (isset($_SERVER['QUERY_STRING'])) { $updateGoTo .= (strpos($updateGoTo, '?')) ? "&" : "?"; $updateGoTo .= $_SERVER['QUERY_STRING']; } header(sprintf("Location: %s", $updateGoTo)); } ?> <head> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> <title>Untitled Document</title> </head> <body> <form action="<?php echo $editFormAction; ?>" id="form1" name="form1" method="POST"> <input type="button" value="End Turn" /> <input name="days" type="hidden" id="days" value="1"/> <input name="playername" type="hidden" id="playername" value="<?php echo $_SESSION['MM_Username']; ?>"> <input type="hidden" name="MM_update" value="form1"> </form> </body> </html> Thanks Hi, when someone logs in to my page, i have a form displayed with names, address, etc...what i need to do is when i hit the update button for that information to go into the MYSQL table I have created and over write that information if a user updates...so how do i do that? hi, I've looked around and not seen an answer that fits my situation, so here goes. I've got a database and I have a script that displays the values from that database in editable fields and has an update button this is that script: <?php session_start(); include("dbinfo.inc.php"); mysql_connect($servname,$dbusername,$dbpassword); @mysql_select_db($database) or die( "Unable to select database"); $query="SELECT * FROM ($newdbname) "; $result=mysql_query($query); $num=mysql_numrows($result); mysql_close(); $i=0; while ($i < $num) { $username=mysql_result($result,$i,"username"); $password=mysql_result($result,$i,"password"); //$real_name=mysql_result($result,$i,"real_name"); echo "$username, $password, $real_name"; ?> <form action="updated.php"> <input type="hidden" name="ud_id" value="<? echo "$id"; ?>"> Username: <input type="text" name="username" value="<? echo "$username"?>"><br> Password: <input type="text" name="password" value="<? echo "$password"?>"><br> <input type="Submit" value="Update"> </form> <?php ++$i; } ?> it passes the "updated" values to this script: <?php session_start(); include("dbinfo.inc.php"); mysql_connect($servname,$dbusername,$dbpassword); $query="INSERT $newdbname SET username (user_id, username, password)='$ud_username', password= PASSWORD('$ud_password') WHERE id='$ud_id'"; @mysql_select_db($database) or die( "Unable to select database"); mysql_query($query); echo "Record Updated"; mysql_close(); ?> I get no errors, and everything runs just fine. except it doesn't update any thing. I'm sure it's a simple thing I'm missing, stupid lack of experience hindering me. any help would be greatly appreciated! Code: [Select] <?php $host="xxxx"; // Host name $username="xxxx"; // Mysql username $password="xxxx"; // Mysql password $db_name="xxxx"; // Database name $tbl_name="xxxx"; // Table name // Connect to server and select database. mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); // get value of id that sent from address bar $model_id=$_GET['model_id']; // Retrieve data from database $sql="SELECT model_id, model_name, location, email_1 FROM $tbl_name WHERE model_id='$model_id'"; $result=mysql_query($sql); $rows=mysql_fetch_array($result); ?> <table width="400" border="0" cellspacing="1" cellpadding="0"> <tr> <form name="form1" method="post" action="updated.php"> <td> <table width="100%" border="0" cellspacing="1" cellpadding="0"> <tr> <td> </td> <td colspan="3"><strong>Update data in mysql</strong> </td> </tr> <tr> <td align="center"> </td> <td align="center"> </td> <td align="center"> </td> <td align="center"> </td> </tr> <tr> <td align="center"> </td> <td align="center"><strong>Name</strong></td> <td align="center"><strong>Location</strong></td> <td align="center"><strong>Email</strong></td> </tr> <tr> <td> </td> <td align="center"><input name="name" type="text" id="name" value="<? echo $rows['model_name']; ?>"></td> <td align="center"><input name="location" type="text" id="location" value="<? echo $rows['location']; ?>"></td> <td><input name="email" type="text" id="email" value="<? echo $rows['email_1']; ?>"></td> </tr> <tr> <td> </td> <td><input name="id" type="hidden" id="id" value="<? echo $rows['model_id']; ?>"></td> <td align="center"><input type="submit" name="Submit" value="Submit"></td> <td> </td> </tr> </table> </td> </form> </tr> </table> <? // close connection mysql_close(); ?> This is the part that isn't working Code: [Select] <td align="center"><input name="name" type="text" id="name" value="<? echo $rows['model_name']; ?>"></td> <td align="center"><input name="location" type="text" id="location" value="<? echo $rows['location']; ?>"></td> <td><input name="email" type="text" id="email" value="<? echo $rows['email_1']; ?>"></td> The echo values aren't being fetched and left blank when I run the script. Any ideas? Hey guys, I have made an admin page for a game Im working on to quickly allow me to update many aspects of the game. My form is sending the correct data because i can echo the $_post but for some reason it isnt updating my database. I just get a blank white page. Could anyone see what i have done wrong. Thanks Code: [Select] <?php require($DOCUMENT_ROOT . "/game/includes/connection.php"); require($DOCUMENT_ROOT . "/game/includes/settings.php"); ?> <?php $name = $_POST['admin_name']; $img = $_POST['admin_img']; $current_hp = $_POST['admin_current_hp']; $max_hp = $_POST['admin_max_hp']; $current_energy = $_POST['admin_current_energy']; $max_energy = $_POST['admin_max_energy']; $level = $_POST['admin_level']; $exp_total = $_POST['admin_exp_total']; $exp = $_POST['admin_exp']; $exp_level = $_POST['admin_exp_level']; $pos_x = $_POST['admin_pos_x']; $pos_y = $_POST['admin_pos_y']; $potion = $_POST['admin_potion']; $ether = $_POST['admin_ether']; $elixir = $_POST['admin_elixir']; $zenni = $_POST['admin_zenni']; $sector = $_POST['admin_sector']; $battle = $_POST['admin_battle']; ?> <?php $sql_1 = "UPDATE game_character SET name='$name', img='$img', current_hp='$current_hp', max_hp='$max_hp', current energy='$current_energy', max_energy='$max_energy', level='$level', exp_total='$exp_total', exp='$exp', exp_level='$exp_level', pos_x='$pos_x', pos_y='$pos_y', potion='$potion', ether='$ether', elixir='$elixir', zenni='$zenni' WHERE id=1"; $sql_2 = "UPDATE game_status SET sector='$sector', battle='$battle' WHERE id=1"; $statement_1 = $dbh->prepare($sql_1); $statement_2 = $dbh->prepare($sql_2); $statement_1->execute(); $statement_2->execute(); ?> <SCRIPT LANGUAGE="JavaScript"> redirTime = "1"; redirURL = "<?php echo $r_admin ?>"; function redirTimer() { self.setTimeout("self.location.href = redirURL;",redirTime); } </script> <BODY onLoad="redirTimer()"> Hi I have a single page submission update page which incorporates 7 drop down menus and 2 text input fields, everything works fine with the data updating back to the database, the only thing is that when the page is updated all the drop down menus are updated which includes ones that I don't want updated? I need to only update the drop down menus that have been selected? but am unsure how I do it? This is the code from the page, sorry if its a mess but I am not that experienced at the moment. This is a snippet of one of the drop down menus Code: [Select] <tr> <td class="heading">Current Status</td> <td><?php echo $statusdescrip ['status_description']; ?> <select name="status_id" > <?php $status_set = findstatus(); $statuslist = mysql_fetch_assoc ($status_set); ?> <?php do { ?> <option value="<?php echo $statuslist ['status_id']; ?>" ><?php echo $statuslist ['status_description']; ?></option> <?php } while ($statuslist = mysql_fetch_assoc ($status_set)); ?></select> <span class="compuls">*</span></td> </tr> Hi I making some forms that write to mysql database, Im now in the process of making the update form so the user can update there details on the form, I want it to populate the form with existing data but its not doing it at all. Thanks in advance
Attached Files
delete.php 210bytes
2 downloads
modify.php 4.03KB
4 downloads
index.php 473bytes
3 downloads Here goes.
I am trying to retrieve info. from mySql database and update 3 textfields.
I also have 4 selects on the form that need populating during the running of the program. My problem is using console I can see the info - Customer name - but it does not appear in the text field. The onchange request in the DIV container seems to be where it fails. Here are the files I am using:
1. add_an_order.php
<html> <head> <title>Add an Order</title> <link href = "css/style.css" rel="stylesheet" type="text/css" /> <script type="text/javascript" src="include/jquery-1.11.1.min.js"></script> </head> <body> <div id="header"><img src="images/logo.png" /></div> <div id="nav"> <div id="nav_wrapper"> <ul> <li><a href="index.php">Orders</a></li><li> <a href="customers.php">Customers</a></li><li> <a href="contacts.php">Contacts</a></li><li> <a href="batteries.php">Batteries</a></li><li> <a href="#">Queries</a> </li> </ul> </div> </div> <div id="main"> <?php echo '<h3 id="menOpt">Add an Order</h3><hr>'; // Check for a form submission. /* if ($_SERVER['REQUEST_METHOD'] == 'POST') { $errors = array(); $required_fields = array('customer_name', 'customer_address', 'city', 'telephone'); foreach ($required_fields as $fieldname) { if (!isset($_POST[$fieldname]) || empty($_POST[$fieldname])) { $errors[] = strtoupper($fieldname); } } if (empty($errors)) { include ('include/dbconnect.php'); $name = mysqli_real_escape_string($con, trim(strip_tags($_POST['customer_name']))); $contact = mysqli_real_escape_string($con, trim(strip_tags($_POST['contact']))); $address = mysqli_real_escape_string($con, trim(strip_tags($_POST['customer_address']))); $city = mysqli_real_escape_string($con, trim(strip_tags($_POST['city']))); $telephone = mysqli_real_escape_string($con, trim(strip_tags($_POST['telephone']))); $telephone = preg_replace('/[^0-9]/', '', $telephone); if (isset($_POST['deepc'])) { $deepc = 1; } else { $deepc = 0; } if (isset($_POST['problemc'])) { $problemc = 1; } else { $problemc = 0; } $problem = mysqli_real_escape_string($con, trim(strip_tags($_POST['problem']))); if (isset($_POST['blacklist'])) { $blacklist = 1; } else { $blacklist = 0; } if (isset($_POST['pickup'])) { $pickup = 1; } else { $pickup = 0; } $query = "INSERT INTO customers ( customer_name, contact, customer_address, city, telephone, deep_cycle, problem_customer, problem, blacklist, pickup) VALUES ('$name', '$contact', '$address', '$city', '$telephone', $deepc, $problemc, '$problem', $blacklist, $pickup)"; $r = mysqli_query($con, $query); if (mysqli_affected_rows($con) == 1) { echo '<p class="success">Customer has been successfully added.</p>'; } else { $message = "Could not add customer."; $message .= "<br />" . mysqli_error($con); } mysqli_close($con); } else { // We have errors. $message = count($errors) . " error(s) on the form."; } } // End: if ($_SERVER['REQUEST_METHOD'] == 'POST'). */ // Leave PHP and display the form. ?> <?php if (!empty($message)) { echo '<p class="error">' . $message . '</p>'; } ?> <?php // Output list of fields that have errors. if (!empty($errors)) { echo '<p class="error">'; foreach ($errors as $error) { echo $error . '<br />'; } echo '</p>'; } ?> <div class="container"> <form action="<?php $_SERVER['PHP_SELF']; ?>" method="post"> <fieldset> <label>Business: <span class="important"> *</span><select name="customer_name" id="customer_name" onchange="request_fill(this.value)" value="<?php if (isset($_POST['customer_name'])) echo $_POST['customer_name']; ?>" ></select></label> <label>Address: <input type="text" name="address" id="add_a" value="<?php if (isset($_POST['customer_address'])) echo $_POST['customer_address']; ?>" /></label> <label>City: <input type="text" name="city" id="city" value="<?php if (isset($_POST['city'])) echo $_POST['city']; ?>" /></label> <label>Phone: <input type="text" name="telephone" value="<?php if (isset($_POST['telephone'])) echo $_POST['telephone']; ?>" /></label> <label>Manufacturer: <span class="important"> *</span><select name="manufacturer" id="manufacturer" onchange="request_mod(this.value)" value="<?php if (isset($_POST['manufacturer'])) echo $_POST['manufacturer']; ?>" ></select></label> <label>Model: <span class="important"> *</span><select name="model" id="model" onchange="form_yr(this.value)" value="<?php if (isset($_POST['model'])) echo $_POST['model']; ?>" ></select></label> <label>Year: <span class="important"> *</span><select name="battery" id="bat_disp" value="<?php if (isset($_POST['battery'])) echo $_POST['year'] ?>" ></select></label> <label>Quantity: <span class="important"> *</span><input type="text" name="quantity" id="quantity" value="<?php if (isset($_POST['quantity'])) echo $_POST['quantity']; ?>" /></label> <label>Warranty ? <input type="checkbox" name="warranty" <?php if ($_POST['warranty']) echo " checked"; ?> /></label> <label>Exchange ? <input type="checkbox" name="exchange" <?php if ($_POST['exchange']) echo " checked"; ?> /></label> <input type="submit" name="submit" value="Add Order" /> or <a href="index.php">Cancel</a> </fieldset> </form> </div> <script type="text/javascript" src="include/functions.js"></script> <script> $(document).ready(function() { $('.container').hide(); $('.container').fadeIn(1000); request_cust(); request_man(); }); </script> <?php include ('include/footer.php'); 2. request_fill function request_fill() { var cust2 = 'customer'; var ad = document.getElementById("add_a"); var hr = new XMLHttpRequest(); hr.open("POST", "battery_parser.php", true); hr.setRequestHeader("Content-type", "application/x-www-form-urlencoded"); hr.onreadystatechange = function() { if(hr.readyState == 4 && hr.status == 200) { var dataArray = hr.responseText; ad.innerHTML = dataArray[1]; } } hr.send("&cust2="+cust2); } 3. battery_parser.php <?php include_once("include/dbconnect.php"); if (isset($_POST['cust2'])) { $cust2 = $_POST['cust2']; $sql = "SELECT customer_address FROM customers WHERE customer_id = 2"; $query = mysqli_query($con, $sql); $dataString = ''; while($row = mysqli_fetch_array($query, MYSQLI_ASSOC)){ $add = $row["customer_address"]; $dataString = $add; } mysqli_close($con); echo $dataString; exit(); } else { exit(); } ?> Hi guys, I need your help. I am trying to insert the rows in the mysql database as I input the values in the url bar which it would be like this: Code: [Select] www.mysite.com/testupdate.php?user=tester&pass=test&user1=tester&email=me@shitmail.com&ip=myisp However i have got a error which i don't know how to fix it. Error: Column count doesn't match value count at row 1 <?php session_start(); define('DB_HOST', 'localhost'); define('DB_USER', 'mydbusername'); define('DB_PASSWORD', 'mydbpassword'); define('DB_DATABASE', 'mydbname'); $errmsg_arr = array(); $errflag = false; $link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD); if(!$link) { die('Failed to connect to server: ' . mysql_error()); } $db = mysql_select_db(DB_DATABASE); if(!$db) { die("Unable to select database"); } function clean($var){ return mysql_real_escape_string(strip_tags($var)); } $username = clean($_GET['user']); $password = clean($_GET['pass']); $adduser = clean($_GET['user1']); $email = clean($_GET['email']); $IP = clean($_GET['ip']); if($username == '') { $errmsg_arr[] = 'username is missing'; $errflag = true; } if($password == '') { $errmsg_arr[] = 'PASSWORD is missing'; $errflag = true; } if($errflag) { $_SESSION['ERRMSG_ARR'] = $errmsg_arr; echo implode('<br />',$errmsg_arr); } else { $sql = "INSERT INTO `members` (`username`,`email`,`IP`) VALUES ('$adduser','$email','$IP')"; if (!mysql_query($sql,$link)) { die('Error: ' . mysql_error()); } echo "The information have been updated."; } ?> Here's the name of the columns i have got in my database: Code: [Select] username IP I have input the correct columns names, so I can't correct the problem I am getting. Please can you help? Hello.
I'm not sure whether this would come under PHP or HTML, but some sites display how many shares an article has had in a font, like this:
https://dl.dropboxus...0726.183853.png
What would the best way of doing this be?
Thanks.
This topic has been moved to MySQL Help. http://www.phpfreaks.com/forums/index.php?topic=331562.0 Hi All, I've searched long and hard accross the web for an answer to this and finnally given in and requesting help. Here's what i have, i have a database setup and working fine. What i would like to do is for an administrator to be able to update my users details. It may sound odd, why don't you let your users update their own details? Well the administrators are dispatchers if you like, and my users are the 'dispatchees', for want of a better word. So i would like my administrators to be able to dispatch my users with routes and my users be able to see the routes that have been dispatched to them. I've setup a login area and a page that pulls there routes off the database, depending on their login details, i.e. jack will see his routes and jill will see her's independantly. This works by me editing the appropriate columns/rows of my database using phpmyadmin. What i'd like now is for administrators (who are directed to a seperate page, with more controls) to be able to do the same as me (updating the database) but by using a php form/script. I'd like to be able to select the routes from a second table on the same database if possible, to try and keep everything tidy. So my dispatcher would select Route001 from a drop down list, this would fill in the text fields next to the route field with From To, so my dispatcher would know what route001 actually is from/ too, choose a username (now being driven from my other table) and hit dispatch. My user would login to their area, hit view dispatched routes and it would display Route 001 with the correct information. The login area was a downloaded script i modified to suit and is called Login-Redirect_v1.31_FULL Many thanks in advance, hope you can sort of understand what i want Josh PHP/MySQL ability:Novice Why am I getting this error when there are 3 Fields with 3 values? Column count doesn't match value count at row 1 Code: [Select] $sql5="INSERT INTO participants (participant_name, team_no, sport) VALUES ('".implode("','$_POST[team]'),('",$_POST['participant_name'])."','$_POST[team]','$sport')"; Anyone can help me? <?php $tbl_name="menu"; $kategorije = mysql_query("SELECT * FROM $tbl_name WHERE Left(menu_name, 1) BETWEEN 'A' AND 'M' ORDER BY menu_name ASC"); if (!$kategorije) { die("Database query failed: " . mysql_error()); } while ($row=mysql_fetch_array( $kategorije )) { echo "<div id=lista-header><h4>{$row["menu_name"]}</h4></div>"; $id_sub=$row['id_menu']; $podkategorije = mysql_query("SELECT * FROM submenu WHERE id_menu=$id_sub ORDER BY sub_name ASC", $connection); if (!$podkategorije) { die("Database query failed: " . mysql_error()); } echo "<ul class=\"pod\">"; while ($pod=mysql_fetch_array( $podkategorije )) { echo "<li><a href=index.php?=podkate?".$pod["id_sub"]." class=black>{$pod["sub_name"]}</a><hr size=1 align=left width=100px color=#cccccc></li>"; } echo "</ul>"; } ?> In this way, I get list with categories and hes subcategories. How to count how many subcategories have each categories, and count how many articles have each categories? Example (I wanna get this kind of look): Categories name (3) subcategoriesname (2) subcategoriesname (4) subcategoriesname (7) Categories name (5) subcategoriesname (1) subcategoriesname (14) subcategoriesname (9) subcategoriesname (2) subcategoriesname ( Categories name (2) subcategoriesname (28) subcategoriesname (17) Where the numbers represent how many categories and sub-items have articles hey i'm just woundering how i would go abouts on echoing unread messages sent to a user i want to beable to see how many unread messages i have returns -30. how can i remove the minus so it just returns 30 Code: [Select] $days = (strtotime(date("Y-m-d")) - strtotime($info['expiredate'])) / (60 * 60 * 24) echo $days Hey All, I need to count and display the number of rows I have. <?php //declare the SQL statement that will query the database $query = " SELECT COUNT(id) FROM connectvisits WHERE staffid = '$staffid' "; //execute the SQL query and return records $result = mssql_query($query); $thismonth = mssql_num_rows($result); echo "Total Meetings This Month: "; echo $thismonth; echo "<br />"; ?> For some reason I keep getting a result of 1. Everything else I try gives me a "Resource ID" number. Any help would be apprecaited. Maybe I have the completely wrong code. Thanks! |
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