PHP - Need To Store A Database Variable In A Php Variable
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i need to store a variable from database like if i have "copies" in one of my column in my database then i have to store a particular value for copies store it to $copies here i want that i can store value of copies into $copies $update_book="update book set copies=copies-1 where bookid='$bookid'"; $result=mysql_query($update_book,$linkID1); if($result) { print "<html><body background=\"header.jpg\"> <p>book successfully subtracted from database</p></body></html>"; } else { print "<html><body background=\"header.jpg\"> <p>problem occured</p></body></html>"; } } Similar TutorialsIt seems that in the following script I am not able to make $page contain some values as it always acts as it contains 0. The script will give you more idea about what I wanna do with it. Code: [Select] <?php include('dbinfo.inc'); session_start(); $connect= mysql_connect($host,$dbuser,$password) or die("connect to database fails"); mysql_select_db($dbname, $connect); //This will set the number of messages we want to display on each page $rows_per_page = 5; function show_msg() { echo "<tr align='center'> <td>$row[message]</td> </tr> <tr><td><strong>Sent By: $_SESSION[username] ON Date: $row[date]</strong></td></tr> <tr><td></td></tr>"; } //This will set the necessay variables required to set the page layout function page_vars() { $sql = "select * from msgs"; $result = mysql_query($sql, $connect); $numrows = mysql_num_rows($result); $total_pages = ceil($numrows/$rows_per_page); //Check whether page is given or not if(isset($_GET["page"])) { $page = $_GET["page"]; } else { $page = 1; } if($page < 1): { $page = 1; } elseif($page > $total_pages): { $page = $total_pages; } endif; } if($_SESSION[loggedin] == TRUE && $_SESSION[actype] == lecturer) { echo "<form action='postmsg.php' method='POST'>"; echo "<table width='80%' border='1'><tr align='center'><td><strong>To send a new message type it in the below box and press SUBMIT</strong> </td></tr>"; echo "<tr align='center'> <td><textarea name='msgarea' cols='40' row='5'></textarea></td> </tr> <tr align='center'> <td><input type='submit' value='Send Message' /></td> </tr> </table>"; $limit .= 'LIMIT '.($page - 1)*$rows_per_page.', '.$rows_per_page; echo $limit; $sql = "select * from 'msgs' $limit"; $result = mysql_query($sql); echo "<table width='80%' border='1'>"; $row = mysql_fetch_assoc($result); while($row) { show_msg(); } } else { page_vars(); $limit .= 'LIMIT '.($page - 1)*$rows_per_page.', '.$rows_per_page; $sql = "select * from msgs $limit"; $result = mysql_query($sql,$connect); echo "<table width='80%' border='1'>"; while($row = mysql_fetch_assoc($result)) { show_msg(); } echo "<tr align='center'> <td> <a href='$_SERVER[php_self]?page=1'>First Page</a> <a href='$_SERVER[php_self]?page=($page - 1)'>$page</a> <a href='$_SERVER[php_self]?page=$page'>$page</a> <a href='$_SERVER[php_self]?page=($page + 1)'>$page</a> <a href='$_SERVER[php_self]?page=($total_pages)'>>>>Last Page</a> </td> </tr>"; echo "</table>"; } ?> now when i echo $limit it always shows "-5, 5" , that's not what i want from this script. Instead I want limit to store "0, 1" with the same concept not direct because it will change according to what $_GET[page] holds. Hope I will get the solution here.... hello, um i got a form that stored an array of variables upon users clicks. it submits to another page fine as an array and i can print them using if(!empty($_POST['langSpoken'])) { echo "\n<p><strong>You selected the following LangSpoken:</strong></p>\n<ul>"; foreach($langSpoken as $lang) { // exclude any items with chars we don't want, just in case someone is playing if(!preg_match('/^[-A-Z0-9\., ]+$/iD', $lang)) continue; // print the lang echo "\n\t<li>" . htmlspecialchars($lang) . "</li>"; } echo "\n</ul>"; } else { echo "\n<p>No items selected</p>"; } it prints a list a of array like english spanish but i need to store each one in one variable so i can store in a database is there a way? thanks Currently I am adding the concept of "entitlements" to my website. In the past, my "article.php" script would simply look to the URL for which article was being requested and then load it. However now that I am also adding the concept of "premium content" for "paid members", I need a way to control who sees what. What I am wondering is - from a security standpoint - how much information I should load into the $_SESSION variable. For instance, right now when a user logs in, I think I just store the "memberID" and "FirstName" and possibly "Username". It would be more efficient when a Member logs in to also retrieve their "Membership Plan" and store that in the $_SESSION variable, so that as they browse my website, each page can simply grab $_SESSION['MembershipPlan'] and run that through a function that I need to build and then determine if the user gets to access said page. However, maybe it would be more secure to have it so when a user lands on page XYZ, I would look at their "memberID" and query the database to get their "MembershipPlan"? Any thoughts on each approach? Again, my main concern is *security*, but I also suppose this plays into "performance".
//multi query $sql= "SELECT option_value FROM settings WHERE option_name = 'email_temp_issue';"; //1 $sql .="SELECT title FROM books WHERE id = '$bookid';"; //2 $sql .="SELECT fullName from students WHERE email = '$username'"; //3 $sql_run = mysqli_multi_query($connection,$sql); if(mysqli_num_rows($sql_run)>0) { foreach ($sql_run as $row) { $email_template = $row['option_value']; //retrieve from query 1 $title = $row['title']; //retrieve from query 2 $name = $row['fullName']; //retrieve from query 3 } } I am trying to store the data from the multi query into each variable, which I am not sure how to do..Anyone can help? :) the same page? Hi, I want to be able to let user type in xml text and it will be parsed and uploaded to db, but it doesn't work, it just keeps redirecting me back to this form below! here is html form: Code: [Select] <html> <body> <form method='post' method='form.php'> <p> <textarea name="pastedXML" rows="10" cols="30"> Please paste your xml file here. </textarea> </p> <p> <input type="submit" value="Convert to SQL" name="textXML" /> </p> </form> </body> </html> Here is script (form.php;I just want to retrieve the contents typed in text area to store to variable...how??) Code: [Select] <?php //get the text in textarea and shred it! if(isset($_POST['textXML'])) print $_POST['pastedXML']; ?> Any help much appreciated! Hi, I want to store files to variable array using glob() like $files[0] = xyz.txt $files[1] = pqr.txt . . . $files[n] = nfile.txt I know how to list files from directory using glob() Code: [Select] <?php foreach (glob("*.txt") as $filename) { echo "$filename size " . filesize($filename) . "\n"; } ?> How can I do that ? I'm stumped on what's causing this problem. $descriptor2 is entering "0". But $_POST['States'] does have a value. I put $testable in as a variable to test that in place of descriptor2 and it works just fine. Code: [Select] $descriptor1 = isset($_GET['id']) ? (int)$_GET['id'] : null; $descriptor2 = isset($_POST['States']) ? (int)$_POST['state'] : null; $descriptor3 = isset($_POST['continent_regions']) ? (int)$_POST['continent_regions'] : null; $descriptor4 = isset($_POST['Continents']) ? (int)$_POST['Continents'] : null; $descriptor5 = isset($_POST['Country']) ? (int)$_POST['Country'] : null; $testable = $_POST['States']; // my test variable $query = "INSERT INTO plant_locations_link(plant_id,state,continent_regions,continents,country) VALUES ($descriptor1,$descriptor2,$descriptor3,$descriptor4,$descriptor5)"; // if I change descriptor2 to testable, it inputs the number I need. This is driving me crazy .... Need to use a variable for the database name on this code ... Code: [Select] <!DOCTYPE html> <html> <head> <title>Table Definition's Tool</title> <style type="text/css"> th { font-size: 110%; border-bottom: 2px solid black; } td { padding: 3px; border-bottom: 1px solid #aaa } </style> </head> <body> <h1>ITG's table's definition</h1> <table> <?php error_reporting (E_ALL ^ E_NOTICE); //Variables $instance=$_REQUEST['instance']; $database_name= $_REQUEST['database_name']; $table=$_REQUEST['table']; require 'utils.php'; // Connect via Windows authentication $server = $instance; $connectionInfo = array( 'CharacterSet' => 'UTF-8' ); $db = sqlsrv_connect($server, $connectionInfo); if ($db === false) { exitWithSQLError('Database connection failed'); } /* Set up and execute the query. */ $query = "SELECT COLUMN_NAME, ORDINAL_POSITION, COLUMN_DEFAULT, DATA_TYPE, CHARACTER_MAXIMUM_LENGTH FROM $database_name.INFORMATION_SCHEMA.COLUMNS WHERE TABLE_NAME='$table'"; // Run query $qresult = sqlsrv_query($db, $query); if ($qresult === false) { exitWithSQLError('Query of product data failed.'); } echo '<tr><th>COLUMN NAME</th><th>POSITION</th><th>DEFAULT</th><th>TYPE</th><th>LENGHT</th></tr>'; // Retrieve individual rows from the result while ($row = sqlsrv_fetch_array($qresult)) { echo '<tr><td>', htmlspecialchars($row['COLUMN_NAME']), '</td><td>', htmlspecialchars($row['ORDINAL_POSITION']), '</td><td>', htmlspecialchars($row['COLUMN_DEFAULT']), '</td><td>', htmlspecialchars($row['DATA_TYPE']), '</td><td>', htmlspecialchars($row['CHARACTER_MAXIMUM_LENGTH']), "</td></tr>\n"; } // null == no further rows, false == error if ($row === false) { exitWithSQLError('Retrieving schema failed.'); } // Share Release result liststatement resource and close connection sqlsrv_free_stmt($qresult); sqlsrv_close($db); ?> </table> </body> </html> Is a simple code where the main MS-SQL query is Code: [Select] SELECT COLUMN_NAME, ORDINAL_POSITION, COLUMN_DEFAULT, DATA_TYPE, CHARACTER_MAXIMUM_LENGTH FROM $database_name.INFORMATION_SCHEMA.COLUMNS WHERE TABLE_NAME='$table' The user should be able to introduce the database and table's name and above query will display the table's schema. However, does not work. I am able to use a variable for the table, but the program does nothing when I use $database_name inside the query. What am I doing wrong? Help, please .... Hi, I'm trying to use a variable- "$newdbname" in a script that sets up a new database. I'm using this variable because I have an include file that sets all login info and the database name as variables. here's the code. or at lest the relevant part. <?php require 'dbinfo.inc.php'; $db = mysql_connect($servname,$dbusername,$dbpassword) or die ('Unable to connect. Check your connection parameters.'); mysql_select_db($database, $db) or die(mysql_error($db)); // create the user table $query = 'CREATE TABLE ($newdbname)( user_id int(30) NOT NULL AUTO_INCREMENT, username varchar(20) NOT NULL, password varchar(41) NOT NULL, PRIMARY KEY (user_id) ) ENGINE=MyISAM'; mysql_query($query, $db) or die (mysql_error($db)); if I run the script like this, I get the following error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '($newdbname)( user_id int(30) NOT NULL AUTO_INCREMENT, usernam' at line 1 if I run the code as this, without parentheses around the variable, it creates a table named "$newdbname" <?php require 'dbinfo.inc.php'; $db = mysql_connect($servname,$dbusername,$dbpassword) or die ('Unable to connect. Check your connection parameters.'); mysql_select_db($database, $db) or die(mysql_error($db)); // create the user table $query = 'CREATE TABLE $newdbname ( user_id int(30) NOT NULL AUTO_INCREMENT, username varchar(20) NOT NULL, password varchar(41) NOT NULL, PRIMARY KEY (user_id) ) ENGINE=MyISAM'; mysql_query($query, $db) or die (mysql_error($db)); what am I doing wrong? Quote i want to store a value from a database and use it as variable in php code can anyone help me out in this code i want to store value of copies in a php variable and want that it should be more than 0 (zero) for furthur calculations $update_book="update book set copies=copies-1 where bookid='$bookid'"; $result=mysql_query($update_book,$linkID1); if($result) { print "<html><body background=\"header.jpg\"> <p>book successfully subtracted from database</p></body></html>"; } else { print "<html><body background=\"header.jpg\"> <p>problem occured</p></body></html>"; } Hello Guys, I have a column named message_status it can only have the values "read" or "unread" in it. I would like to show an image in the column next to it. If the message is "read" then I would like to display a green dot, and if it is unread I would like to display a red dot. I would also like to be able to have anything in the row that's "unread" to appear in bold. I completely stumped by this! I have written the following code, which doesn't seem to work, presumably because it is run after the table has been displayed? I am very new to this so please be gentle! Regards, AJLX $result = mysql_query("SELECT * FROM messages where username ='$username'ORDER BY {$_GET['orderbycol']} $sort"); echo "<table border='1'> <tr width='200'> <th>View</th> // code to display table removed </tr>"; $green_dot = $message_status; $red_dot = $message_status; $green = ""; $red = ""; $bold = ""; while ($row = mysql_fetch_array($result)) { echo "<tr>"; $id = $row['ID']; echo "<td><a href='/view_message.php/?view_message=$id'>View</a></td>"; echo "<td>" .$green . $red."</td>"; echo "<td>" .$bold . $message_status = $row['message_status'] . "</td>"; echo "<td>" .$bold. $row['date_sent'] . "</td>"; echo "<td>" .$bold. $row['contact_name'] . "</td>"; echo "<td>" .$bold. $row['subject'] . "</td>"; echo "</tr>"; } if ($green_dot = 'read'){ $green ='<img src=\"assets/red.jpg\"/>'; echo $green; } else { $red ='<img src=\"assets/red.jpg\"/>'; $bold = "<b>"; echo $red; Hey all Im working on an assignment for school and currently I am trying to inser the variable $uid which currently = 2.. But for someone reason when the post happens it inserts a 0 instead of a 2. Here is my insert Code: [Select] mysql_query( "INSERT INTO blog_posts (title, post, author_id, date_posted) ". "VALUES ('$btitle', '$bpost', '$uid', CURDATE())" ); I am trying to take a variable from a database. But it keeps equaling nothing. Ive tried using mysql_error() and sI get nothing. I also keep tryed mysql_num_rows() and I get 3(just what Id exspect). Here is the code. Code: [Select] <?php if($userb) { $q1 = " SELECT sub FROM login_info WHERE user='$user_log' LIMIT 1 "; $s1 = mysql_query($q1); $scribe = mysql_fetch_assoc($s1); $sub = explode('![sep]!' ,$scribe['sub']); foreach($sub as $key => $name) { $q2 = " SELECT * FROM subscribe WHERE user = '$name' "; echo 'Llama'; $s2 = mysql_query($q2); $num1 = mysql_num_rows($s2); echo '<h3>' .$name .' Posted ' .$num1 .' Storie(s)! </h3>'; while($stor = mysql_fetch_assoc($s2)); { $story = $stor['stor']; $sid = $stor['sid']; $q3 = " SELECT * FROM story_info WHERE id = $sid "; echo $q3 .'<br />'; $s3 = mysql_query($q3) or die(mysql_error()); $rows = mysql_fetch_assoc($s3); $viewsdb = $rows['views']; $titledb = $rows['title']; $userdb = $rows['user']; $catdb = $rows['cat']; $ratdb = $rows['rating']; $id_db = $rows['story_id']; $sumdb = shorten($rows['sum']); echo "<h3><a href='?p=page&id=$id_db'> $titledb </a> </h3>"; echo "<div id='fun_info'>"; echo "$sumdb <br />"; echo "By <a href='?p=profile&user=$userdb'> $userdb </a> <br /> "; echo "$viewsdb Views | Rated: $ratdb | Catagory: <a href='?p=cat_view&gen=$catdb'> $catdb </a> </div>"; } } } else { login('?p=sub'); } I have a table that has 5 columns Quote player_id fname lname team I'm trying to get all the values from that table using this sql command Code: [Select] include_once('../database_connection.php'); $player_id = addslashes($_REQUEST['edit_player']); $sql_query = "Select * from nba_info where player_id = '$player_id'"; $result = MYSQL_QUERY($sql_query); "edit_player" above is came from a different page. They I'm fetching the data using while Code: [Select] while($row = mysql_fetch_array($result)) { $row['player_id']; $row['fname']; $row['lname']; $row['team']; $row['email']; } Then I'm trying to pass that values to a variable here Code: [Select] $id = $row['player_id']; $fname = $row['fname']; $fname = $row['lname']; $lname = $row['team']; $email = $row['email']; When I'm trying to put that variables in a textbox value, they are not showing up Here Code: [Select] <table> <form name="edit_player_form" method="post" action=""> <tr> <td>Players ID</td> <td><input type="text" name="playerid" size="20" value="<?php echo $id; ?>" /></td> </tr> <tr> <td>First Name</td> <td><input type="text" name="fname" size="20" value="<?php echo $fname; ?>" /></td> </tr> <tr> <td>Last Name</td> <td><input type="text" name="lname" size="20" value="<?php echo $lname; ?>" /></td> </tr> <tr> <td>Team</td> <td><input type="text" name="team" size="20" value="<?php echo $team; ?>" /></td> </tr> <tr> <td>Email</td> <td><input type="text" name="email" size="20" value="<?php echo $email; ?>" /></td> </tr> <tr> <td><div align="center"> <input type="submit" name="Submit" value="Edit This Player"> </div></td> </tr> </form> </table> I wonder why it ain't showing up on the textbox value? tried almost everything... Anyone? I am trying to allow the user to update a variable he chooses by radio buttons, which they will then input text into a box, and submit, to change some attributes. I really need some help here. It works just fine until I add the second layer of variables on top of it, and I can't find the answer to this question anywhere. <?PHP require('connect.php'); ?> <form action ='' method='post'> <select name="id"> <?php $extract = mysql_query("SELECT * FROM cars"); while($row=mysql_fetch_assoc($extract)){ $id = $row['id']; $make= $row['make']; $model= $row['model']; $year= $row['year']; $color= $row['color']; echo "<option value=$id>$color $year $make $model</option> ";}?> </select> Which attribute would you like to change?<br /> <input type="radio" name="getchanged" value="make"/>Make<br /> <input type="radio" name="getchanged" value="model"/>Model<br /> <input type="radio" name="getchanged" value="year" />Year<br /> <input type="radio" name="getchanged" value="color" />Color<br /><br /> <br /><input type='text' value='' name='tochange'> <input type='submit' value='Change' name='submit'> </form> //This is where I need help... <?PHP if(isset($_POST['submit'])&&($_POST['tochange'])){ mysql_query(" UPDATE cars SET '$_POST[getchanged]'='$_POST[tochange]' where id = '$_POST[id]' ");}?> Hello all. I am very new to PHP, and I am not sure where to look or what I'm looking for in my current assignment. My task is to take in two numbers between 0-100. Once I take in that number, it should state beside it "The __ was accepted." The program should not accept any numbers greater than 100 or any characters. Once I do this, I must take a second number and do a similar thing. Finally, I must have a statement show up at the bottom stating which number is greater. Essentially, I need help in determining what I should use to place parameters, and how I can keep the program from echo ing any statement until input has been taken and tested for parameters. Any help you can provide will be greatly appreciated! Hello guys,
I do not know if anyone work or have worked with the "elFinder (file manager)" .. I incorporate "elFinder" to my platform .. I have the following question .. Have its connector: <?php error_reporting(0); // Set E_ALL for debuging include_once dirname(__FILE__).DIRECTORY_SEPARATOR.'elFinderConnector.class.php'; include_once dirname(__FILE__).DIRECTORY_SEPARATOR.'elFinder.class.php'; include_once dirname(__FILE__).DIRECTORY_SEPARATOR.'elFinderVolumeDriver.class.php'; include_once dirname(__FILE__).DIRECTORY_SEPARATOR.'elFinderVolumeLocalFileSystem.class.php'; // Required for MySQL storage connector include_once dirname(__FILE__).DIRECTORY_SEPARATOR.'elFinderVolumeMySQL.class.php'; // Required for FTP connector support include_once dirname(__FILE__).DIRECTORY_SEPARATOR.'elFinderVolumeFTP.class.php'; /** * Simple function to demonstrate how to control file access using "accessControl" callback. * This method will disable accessing files/folders starting from '.' (dot) * * @param string $attr attribute name (read|write|locked|hidden) * @param string $path file path relative to volume root directory started with directory separator * @return bool|null **/ function access($attr, $path, $data, $volume) { return strpos(basename($path), '.') === 0 // if file/folder begins with '.' (dot) ? !($attr == 'read' || $attr == 'write') // set read+write to false, other (locked+hidden) set to true : null; // else elFinder decide it itself } $opts = array( // 'debug' => true, 'roots' => array( array( 'driver' => 'LocalFileSystem', // driver for accessing file system (REQUIRED) 'path' => '/home/', // path to files (REQUIRED) 'URL' => dirname($_SERVER['PHP_SELF']) . '/home/', // URL to files (REQUIRED) 'accessControl' => 'access' // disable and hide dot starting files (OPTIONAL) ) ) ); // run elFinder $connector = new elFinderConnector(new elFinder($opts)); $connector->run();I want him to make the call the "$screen" (folder will be created automatically by the user) of each user .. and not the "/home/" (as an example of put) .. the "$screen" comes from my platform, and I add the "elFinder" to it .. Imagine that each user creates "1/2/3 or 4, etc .." folders .. Hello all! I am somewhat new to PHP and SQL, but I think I have a basic understanding of how the language works. I have read through a million different websites and forums, and have tried a million different ways but am just not getting anywhere! This is what I am trying to do... I have a text link that I want to click through to an outside URL from my website. This outside URL was already entered into an SQL database, and I just cant seem to get the text link to bring up the outside URL from the database. This is what I have so far... 1.) My webpage that I am working on is www.mywebsite.com/articles.php 2.) I want the text "Read more..." on this webpage to click through to an outside URL, like "http://www.google.com", which was already entered into an SQL database under the title of "article_link" in a new window 3.) So I would like for "Read more..." to click through the outside URL that was entered into "article_link" in the database Code: [Select] <?php echo <p><a href="\' . $article_link . '\" target="_blank">Read more...</a></p>; ?> Nothing I have tried has worked so far, nothing clicks through to the outside URL in the "article_link" entry from the database. Sorry if I am being redundant, I have been at this all day! Please help and thank you in advance!! Hello Guys, I want to insert an array variable into the database e.g Code: [Select] foreach($html->find('div[class=PostContent]') as $element) { echo $element; $sq = "INSERT INTO articles(original_text) VALUES ('$element') WHERE article_link='$item_url'"; $result = mysql_query($sql1) or die('Query failed: ' . mysql_error()); } i want to insert the variable $element into the database but i'm not able to do so for some reason! $element contains only a paragraph of text. how can i insert the variable $element? |