PHP - Rename The Default File Name To Something Else?

Hello I am new to programming, coding, php... and need some help. I have some code that uploads a file and does some basic checks but I also want it to rename the file possibly adding the time stamp.

Heres what I have so far.

cheers.

$tbl_name="guestbook"; // Table name
$email = $_REQUEST["email"];
$name = $_REQUEST["name"];
$comment = $_REQUEST["comment"];
$_FILES["file"]["name"];
$_FILES["file"]["type"];
$_FILES["file"]["size"];
$_FILES["file"]["tmp_name"];
$_FILES["file"]["error"];
$datetime = date("dmy");
$uploaddir = "upload/";
$filename = $_FILES["file"]["name"];
$pathinfo = pathinfo($_FILES['userfile1']['name']);


mysql_connect("$host", "$username", "$password")or die("cannot connect server ");
mysql_select_db("$db_name")or die("cannot select DB");

$sql="INSERT INTO $tbl_name(name, email, comment, datetime)VALUES('$name', '$email', '$comment', '$datetime')";
$result=mysql_query($sql);

if($result){
echo "Successful added update to the Melody Bear Bulletin Board";
echo "<BR>";
echo "<a href='ViewBulletinBoard.php'>View Bulletin Board</a>"; }

else {
echo "ERROR";
}


if ((($_FILES["file"]["type"] == "image/gif")
|| ($_FILES["file"]["type"] == "image/jpeg")
|| ($_FILES["file"]["type"] == "image/pjpeg"))
&& ($_FILES["file"]["size"] < 2000000))
  {
  if ($_FILES["file"]["error"] > 0)
    {
    echo "Return Code: " . $_FILES["file"]["error"] . "<br />";
    }
  else
    {
    echo "Upload: " . $_FILES["file"]["name"] . "<br />";
    echo "Type: " . $_FILES["file"]["type"] . "<br />";
    echo "Size: " . ($_FILES["file"]["size"] / 1024) . " Kb<br />";
    echo "Temp file: " . $_FILES["file"]["tmp_name"] . "<br />";

    if (file_exists("upload/" . $_FILES["file"]["name"]))
      {
      echo $_FILES["file"]["name"] . " already exists. ";
      }
    else
      {
      move_uploaded_file($_FILES["file"]["tmp_name"],
      "upload/" . $_FILES["file"]["name"]);
      echo "Stored in: " . "upload/" . $_FILES["file"]["name"]. "<br>";
      }
    }
  }
else
  {
  echo "Invalid file";
  }
   
   
      
mysql_close();
?>
 

Hi everyone, im a newbie and have written this script, has taken me a day to get here.
The form inserts data into the database, uploads a file and sends an email.
All this works fine, what i am trying to do is rename the file to the id of the record and check to make sure it is a pdf.
I would really appreciate any help. I've tried and tried and just cant get it to work.

<?php
switch ($_REQUEST['action']) {
case 'recruit':
foreach($_POST as $key=>$value){
$$key = $value;
}
if ((!$name) || (!$email) || (!$phone)) {
$error_msg = 'Fields marked<span class="gold"> * </span>are required to submit the form';
}elseif (!eregi("^[_a-z0-9-]+(\.[_a-z0-9-]+)*@[a-z0-9-]+(\.[a-z0-9-]+)*(\.[a-z]{2,3})$", $email)) { 
    $error_msg = 'Invalid email address'; 
}
echo "$error_msg","<br><br>";
if ($error_msg == ''){

$date=date("d/m/y", time());
$add="recruitment/".$_FILES[userfile][name];
$cleaned = stripit($add);
    $add2 = $cleaned;

   if(move_uploaded_file ($_FILES[userfile][tmp_name], $add2));
    $Q = mysql_query("INSERT INTO recruitment (`name`,`phone`,`email`, `qual`,`exper`,`file`) VALUES ('$name','$phone','$email','$qual','$exper','$cleaned')");
  
foreach($_POST as $key=>$value){
$$key = htmlentities(stripslashes($value));
}
$companyname = 'Mead Business college';
$companyemail = 'ross@emediastudios.com.au';
$headers  = "MIME-Version: 1.0\r\n";
$headers .= "Content-type: text/html; charset=iso-8859-1\r\n";
$headers .= "From: ".$name." <".$email.">\r\n";
$headers .= "Reply-To: ".$name." <".$email.">\r\n";
$to = "".$companyname."<".$companyemail.">";
$subject = "Mead Business College Recruitment Form Submission";
$message = '<style type="text/css>";


<!--
.style {
font-family: Verdana, Arial, Helvetica, sans-serif;
font-size: 10px;
}
-->
</style>
<table width="100%" border="0" cellspacing="0" cellpadding="0">
  <tr>
    <td class="style">
<b>Details:</b><br /><br />
<b>Name:</b> '.$name.'<br />
<b>Email:</b> '.$email.'<br />
<b>Mobile No:</b> '.$phone.'<br />
<b>Qualifications:</b><br> '.$qual.'<br />
<b>Experience:</b><br /><br />'.$exper.'<br /><br />
<b>Uploaded resume:</b> http://www.mydomain.com.au/'.$cleaned.'
    </td>
   </tr>
</table>';
mail($to, $subject, $message, $headers);

echo '<table width="99%" border="0" cellpadding="0" cellspacing="0">

   <tr>

    <td class="mybody">Hi '.$name.',<p />Thank you for your enquiry. An MBC Consultant will contact you shortly.<br />
      <br />
      </td>
   </tr>
</table>';

}else{

foreach($_POST as $key=>$value){

$$key = htmlentities(stripslashes($value));

}
echo '
<FORM ENCTYPE="multipart/form-data" id="form" name="Contact Form" method="post" action="'.$_SERVER['PHP_SELF'].'?action=recruit">
  <table width="489" border="0" cellspacing="5" cellpadding="0" class="formsw">
    <tr>
      <td width="227">Name:</td>
      <td width="358"><input type="text" name="name" id="name" value="'.$name.'" /></td>
    </tr>
    <tr>
      <td>Contact Mobile:</td>
      <td><input type="text" name="phone" id="phone" value="'.$phone.'" /></td>
    </tr>
    <tr>
      <td>Email:</td>
      <td><input type="text" name="email" id="email" value="'.$email.'" /></td>
    </tr>
    <tr>
      <td>Relevent Qualifications:</td>
      <td><textarea name="qual" id="qual" cols="45" rows="5" value="'.$qual.'"></textarea></td>
    </tr>
    <tr>
      <td>Recent Experience:</td>
      <td><textarea name="exper" id="exper" cols="45" rows="5" value="'.$exper.'"></textarea></td>
    </tr>
    <tr>
      <td>Upload Resume:</td>
      <td><input type="file" name="userfile" id="userfile" /></td>
    </tr>
    <tr>
      <td><input type="submit" name="submit" id="submit" value="Submit" /></td>
      <td>&nbsp;</td>
    </tr>
  </table>
</form>';

}

break;
}
?>

anyone can show example how i could remane the uploaded file name with users id along with some number?

Code: [Select]
//////////////////////////////////////uploader
else if($action=="uploader")
{



echo "Upload your picture and copy the link <br/>after uploading to user it at gallery.<br/><br/>";

echo "<form method=\"post\" enctype=\"multipart/form-data\" action=\"index.php?action=uploaded&amp;sid=$sid\">";
echo "Choose Pictu <br />";
echo "<input name=\"uploaded\" type=\"file\" /><br /><br />";
echo "<input type=\"submit\" value=\"Upload\" />";
echo "</form><br/>";


echo "<p align=\"center\">";
echo "<a href=\"index.php?action=main&amp;sid=$sid\">Home</a>";
echo "</p>";
}


//////////////////////////////////////uploader
else if($action=="uploaded")
{



$blacklist = array(".php", ".php.jpg", ".php.jpeg", ".php.gif", ".php.png", ".phtml", ".php3", ".php4");
foreach ($blacklist as $item) {
if(preg_match("/$item\$/i", $_FILES['uploaded']['name'])) {
echo "<p align=\"center\">";
echo "Oops sorry we do not allow those files.<br/>";
echo "<a href=\"index.php?action=main&amp;sid=$sid\">Home</a>";
echo "</p>";
exit;
}
}

$target = "../images/";
$target = $target . basename( $_FILES['uploaded']['name']) ;
$ok=1;

if (file_exists("../images/" . $_FILES["uploaded"]["name"]))
      {
echo "<p align=\"center\">";
      echo $_FILES["file"]["name"] . "Oops file name already exists<br/> kindly rename your picture and upload again. <br/>";

echo "<a href=\"index.php?action=main&amp;sid=$sid\">Home</a>";
echo "</p>";   
 }else{

//This is our size condition
if ($uploaded_size > 25600){

echo "Your file is too large. We have a 25kb limit.<br/>";
$ok=0;
}

$types = array('image/jpeg', 'image/gif', 'image/png');

if (in_array($_FILES['uploaded']['type'], $types)) {
// file is okay continue
} else {
$ok=0;
}


//Here we check that $ok was not set to 0 by an error
if ($ok==0){
echo "<p align=\"center\">";
Echo "Sorry your file was not uploaded.<br/> It may be the wrong filetype. <br/>We only allow JPG, GIF, and PNG filetypes.<br/>";

echo "<a href=\"index.php?action=main&amp;sid=$sid\">Home</a>";
echo "</p>";
}

//If everything is ok we try to upload it
else{
if(move_uploaded_file($_FILES['uploaded']['tmp_name'], $target)){
echo "<p align=\"center\">";

echo "The file ". basename( $_FILES['uploadedfile']['name']). " Picture uploaded successfully.<br/><br/><b>$target <br/>";

echo "<a href=\"index.php?action=main&amp;sid=$sid\">Home</a>";
echo "</p>";
}
else{
echo "<p align=\"center\">";

echo "Sorry, there was a problem uploading your file.<br/>";
echo "<br/><a href=\"http://index.php?action=main&amp;sid=$sid\">Wml Home</a><br />";
echo "<a href=\"index.php?action=main&amp;sid=$sid\">Home</a>";
echo "</p>";
}
}
}
}
[code]

Hello,

I've looked everywhere for help, is there any chance anyone here that knows of PHP can help me out?

I have this snippet of code for uploading files. I really want it to rename the files with a date and/or time or anything random at the end of the image's name as it uploads. Would be an amazing help!! Thanks!

Here is the code.

Code: [Select]
<?php
// Set the uplaod directory
$uploadDir = '/images/';

if (!empty($_FILES)) {
    $tempFile   = $_FILES['Filedata']['tmp_name'][0];
    $uploadDir  = $_SERVER['DOCUMENT_ROOT'] . $uploadDir;
    $targetFile = $uploadDir . $_FILES['Filedata']['name'][0];

    // Validate the file type
    $fileTypes = array('jpg'); // Allowed file extensions
    $fileParts = pathinfo($_FILES['Filedata']['name'][0]);

    // Validate the filetype
    if (in_array($fileParts['extension'], $fileTypes)) {

        // Save the file
        move_uploaded_file($tempFile,$targetFile);
        echo 1;

    } else {

        // The file type wasn't allowed
        echo 'Invalid file type.';

    }
}
?>

Hi i have a simple triple upload file script that upload files with its own name it works fine but what i want is to be able to specify the name of the image like file 1 give name (blue) file 2 name (tree) file 3 name (sky)

<?php

//set where you want to store files

//in this example we keep file in folder upload

//$HTTP_POST_FILES['ufile']['name']; = upload file name

//for example upload file name cartoon.gif . $path will be upload/cartoon.gif

$path1= "images/posters/".$_FILES['ufile']['name'][0];

$path2= "images/posters/".$_FILES['ufile']['name'][1];

$path3= "images/posters/".$_FILES['ufile']['name'][2];





//copy file to where you want to store file

copy($_FILES['ufile']['tmp_name'][0], $path1);

copy($_FILES['ufile']['tmp_name'][1], $path2);

copy($_FILES['ufile']['tmp_name'][2], $path3);



//$HTTP_POST_FILES['ufile']['name'] = file name

//$HTTP_POST_FILES['ufile']['size'] = file size

//$HTTP_POST_FILES['ufile']['type'] = type of file

echo "File Name :".$_FILES['ufile']['name'][0]."<BR/>";

echo "File Size :".$_FILES['ufile']['size'][0]."<BR/>";

echo "File Type :".$_FILES['ufile']['type'][0]."<BR/>";

echo "<img src=\"$path1\" width=\"150\" height=\"150\">";

echo "<P>";



echo "File Name :".$_FILES['ufile']['name'][1]."<BR/>";

echo "File Size :".$_FILES['ufile']['size'][1]."<BR/>";

echo "File Type :".$_FILES['ufile']['type'][1]."<BR/>";

echo "<img src=\"$path2\" width=\"150\" height=\"150\">";

echo "<P>";



echo "File Name :".$_FILES['ufile']['name'][2]."<BR/>";

echo "File Size :".$_FILES['ufile']['size'][2]."<BR/>";

echo "File Type :".$_FILES['ufile']['type'][2]."<BR/>";

echo "<img src=\"$path3\" width=\"150\" height=\"150\">";



///////////////////////////////////////////////////////



// Use this code to display the error or success.



$filesize1=$_FILES['ufile']['size'][0];

$filesize2=$_FILES['ufile']['size'][1];

$filesize3=$_FILES['ufile']['size'][2];



if($filesize1 && $filesize2 && $filesize3 != 0)

{

echo "We have recieved your files";

}



else {

echo "ERROR.....";

}



//////////////////////////////////////////////



// What files that have a problem? (if found)



if($filesize1==0) {

echo "There're something error in your first file";

echo "<BR />";

}



if($filesize2==0) {

echo "There're something error in your second file";

echo "<BR />";

}



if($filesize3==0) {

echo "There're something error in your third file";

echo "<BR />";

}



?>

I have this code, for an Upload Form, that works successfully renaming and moving an uploaded file to the upload/ folder. 

My 1st try practice uploading file to the server and it was successful.

Now I wonder how can I set a default file name to the file that will be uploaded and overwrite the existing one.

I have tried experimenting on the code but I can't get it to work.


Here's my simple code..

edit_logo.php

Code: [Select]
<?php

<form enctype="multipart/form-data" method="post"  action="uploaded_logo.php">

<input type="hidden" name="MAX_FILE_SIZE" value="100000" />

<tr>
<td>Choose a Logo to Upload: </td>
    <td><input name="uploaded_file" type="file" /></td>
</tr>

<tr>
<td>&nbsp;</td>
    <td><input type="submit" value="Upload File" name="submit>"</td>
</tr>




</form>

?>

uploaded_logo.php
Code: [Select]
<?php

if($_FILES['uploaded_file']["type"] == "image/gif")
{

$target_path = "logo/";

$target_path = $target_path. basename($_FILES['uploaded_file']['name']);



if(move_uploaded_file($_FILES['uploaded_file']['tmp_name'], $target_path))
{
echo "<span class=\"error_validation\">The Logo has been successfully changed!<br></span>";
echo "<span class=\"error_validation\">Upload Logo Again? <a href=\"edit_logo.php\">Click Here</a><br></span>";
}
else
{
echo "<span class=\"error_validation\">There was an error uploading the logo. Pls. try again.<br></span>";
echo "<span class=\"error_validation\">Upload Logo Again? <a href=\"edit_logo.php\">Click Here</a><br></span>";
}

}
else
{
echo "<span class=\"error_validation\">Invalid file format. We are only accepting image file. Pls. try again.<br></span>";
echo "<span class=\"error_validation\">Upload Logo Again? <a href=\"edit_logo.php\">Click Here</a><br></span>";
}


?>

So what the code suppose to do is.. If I upload an image file as the new logo it should have the default logo name "my_logo.gif", then it will overwrite the existing one...

Anyone?

hello and good day dear Linux-experts,

i want to install a new opensuse linux on a notebook. i want to upgrade is the following:

this one: Akoya P 6512 15" OpenSuse 13.1: AMD Athlon X2 P320, 2,10 GHz, 4 GB 320 GB hdd-drive

what is wanted:
i want to do a total fresh installation
i want to have not tooo much partitions!
i only want to run opensuse 13.2
i want to have some kind of native linux partitions - such as ext 4 - #


what do you suggest - should go with the new default BTRFS file system?!?

well to begin with the beginning: i applied the following commands

a. lsblk

b. fdisk -l


see the results,,,, ;

linux-c5sz:/home/martin # lsblk
NAME MAJ:MIN RM SIZE RO TYPE MOUNTPOINT
sda 8:0 0 465,8G 0 disk
├─sda1 8:1 0 4G 0 part [SWAP]
├─sda2 8:2 0 102M 0 part
├─sda4 8:4 0 1K 0 part
├─sda5 8:5 0 2G 0 part
├─sda6 8:6 0 4G 0 part
├─sda7 8:7 0 10G 0 part
├─sda8 8:8 0 20G 0 part /
└─sda9 8:9 0 389,6G 0 part /home
sr0 11:0 1 1024M 0 rom




and the following fdisk -l

linux-c5sz:/home/martin # fdisk -l

Disk /dev/sda: 500.1 GB, 500107862016 bytes, 976773168 sectors
Units = Sektoren of 1 * 512 = 512 byte
Sector size (logical/physical): 512 bytes / 512 bytes
I/O size (minimum/optimal): 512 bytes / 512 bytes
Disk label type: dos
Disk identifier: 0xb8fa3ecd

Gerät boot. Anfang Ende Blöcke Id System
/dev/sda1 63 8385929 4192933+ 82 Linux swap / Solaris
/dev/sda2 8385930 8594774 104422+ 83 Linux
/dev/sda4 * 8803620 976768064 483982222+ 5 Extended
/dev/sda5 8803683 12996584 2096451 83 Linux
/dev/sda6 12996648 21382514 4192933+ 83 Linux
/dev/sda7 21382578 42347339 10482381 83 Linux
/dev/sda8 117821440 159766527 20972544 83 Linux
/dev/sda9 159768576 976766975 408499200 83 Linux
linux-c5sz:/home/martin #




subsequently the questions; which partition logic should i choose.

what is wanted: i want to have not tooo much partitions!
i only want to run opensuse 13.2

note: i want to erase all the existing partition logic /(that is currently existing)
i do this with Gparted.

which partitions should i take?
which file system ?


i am curious to get to know your ideas

Hello Everyone.. I have a different sort of a question here.. I was looking if its possible to check the no. of files in a folder (wheather they be in any format) and if thts possible can i manupulate those files like renaming them.. like for instance i have 1000 files in a folder nd i wanna rename them all according to sum criteria.. like if there are 300 mp3 songs in a folder..  1st i wanna do i check how many are in the folder exactly.. then i wanna rename each song cuz they have sum extra information of artist on the file name.. like hello darling (alize).mp3 i wanna rename them to hello darling.mp3.. nd i wanna do the same to all the files in that folder.. is der a way i can make this possible..?

1st check the total no. of files in a folder..
renaming each file according using a special symbol.. like if "(" symbol cums up it can explode the name.. nd we can have the correct name in title[0] nd the (alize).mp3 part in title[1].  we can just join title[0].mp3 to get the correct name out of each file..!!

i hope u understand wat i need to doo!!

wud be thankfull if anyone can help

Ok, so i've managed to upload images, but now i'm trying to rename them to avoid replacement and i've done something like this:

mysql_query( "INSERT INTO `softmarket`.`internet_securitate` (`internet_securitateID`, `nume_produs`, `descriere`, `versiune`,`poza`, `pret`, `disponibilitate_produs`)
VALUES ('', '$_POST[titlu]', '$_POST[descriere]', '$_POST[versiune]', '$foto', '$_POST[pret]', '$_POST[disponibilitate]');"); 

Code: [Select]
 
 function findexts ($filename) {
 $filename = strtolower($filename) ;
 $exts = split("[/\\.]", $filename) ;
 $n = count($exts)-1; $exts = $exts[$n];
 return $exts; }
 

 $ext = findexts ($_FILES['foto']['name']) ;   
 $ran2 = $foto."."; 
 $target = "../images/";

 $target = $target . $ran2.$ext;
while (file_exists($target)) {
    $ran2 = 'copyof'.$ran2;
    $target = $target . $ran2.$ext;
}
 if(move_uploaded_file($_FILES['foto']['tmp_name'], $target))  {
echo "The file has been uploaded as ".$ran2.$ext; }
 
 else { echo "Sorry, there was a problem uploading your file."; }
 
 

header('Location: succes.php');
but it renames them in a wierd way...what is wrong?

<?php
$zip = new ZipArchive;
$res = $zip->open('test.zip');
if ($res === TRUE) {
    $zip->renameName('currentname.txt','newname.txt');
    $zip->close();
} else {
    echo 'failed, code:' . $res;
}
?>

I can rename a text file name but I can't rename a folder name.Can you help me?

This topic has been moved to HTML Help.

http://www.phpfreaks.com/forums/index.php?topic=354370.0

I need to rename several hundred mp3's in a directory.  I've tried this php script...but it seems to have missed every file from 19 to 29 (119-129, 219-229, 319-329 etc).

The original names are in no particular order or fashion in how they're named.

What's my best choice to rename these files to song1.mp3, song2.mp3 song3.mp3 etc.?

Code: [Select]
<?php
$i = 1;
foreach (glob("/xmas/*.mp3") as $filename) {
copy ("$filename", "/newpopaudio/xmas$i.mp3");
$i++;
}
?>

i am trying to display all the image from a dir and let the use lick on a image that takes them to other page where they can rename that image.

or let them rename the image from the first page.

here is what i have.


Code: [Select]
<?php 
SESSION_START(); 
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en">
<head>
<meta http-equiv="content-type" content="text/html; charset=utf-8" />
<meta name="author" content="vs" />
<meta name="robots" content="index, follow" />

<title></title>
</head>
<body>

<div id="centerColumn">
<div id="header">

</div>
<p><span class="small"></span><br />


</p><br>


<form method="post" action="data2file.php">
<?php 

echo '
            
<table> 
<tr><td>'; 
     $username = $_SESSION['user']; 
        $url = $username."./"; 
        $handle = opendir ($url); 
        while (false !== ($file = readdir($handle))) { 
            if($file != "." && $file != ".." && $file != basename(__FILE__)) {                    
                                                             
                  //echo '<table border=1><tr><td>';                    
                   echo '<a href="edit.php" ><img border=1 src="'.$file.'"></a>'; 
                   echo '<br />'; 
                    
                   echo "<input type=submit name=$file value=Edit>" ; 
                  print $file; 
                  echo '<br>'; 
                  
                   echo "Enter new name: <input type='text'  name='new-name' length='30'>
                   <textarea type=text size='1' height='1'style='display:none' name='file-name' >". $file ."</textarea>"; 
                  
                  echo '<hr>'; 
                  //echo '</td></tr></table>';            
            
            } 
        } 
echo '</td>'; 

echo ' 

</table>'; 
 
?>

</body>
</html>
it works i loads all the images.

and here is the data2file.php code

Code: [Select]
<?php 
SESSION_START(); 


echo $_POST['new-name'];
echo '<br>';
echo $_POST['file-name']; 
echo '<br>';
echo "Successfully!"; 
?>
it's just display the name of the file and the new name i want to give it.

But it only does the last image in the dir.

How can i make the first code work so if the user clicks on the edit button it will pull only that image file name to the data2file.php and then from the data2file.php it will rename the file name.