PHP - File_exists On Network Share From An Ubuntu Server

This topic has been moved to Miscellaneous.

http://www.phpfreaks.com/forums/index.php?topic=322565.0

Please tell me how  to connect php and mysql in ubuntu 14.04

Code: [Select]
<?php
$myServer = "<remote ip>";
$myUser = "<username>";
$myPass = "<password>";
$myDB = "FAP2"; 
//create an instance of the ADO connection object
$conn = new COM ("ADODB.Connection")
  or die("Cannot start ADO");
 
?>

No error messages reported, but page "dies" at this point.
The ubuntu machine can see the sql machine, but yet this is happening.

I've been doing a lot of studying of Linux lately. I enabled the root acount to do some work. When done, even if I logout, close the terminal, or reboot, I can still access the root account without supplying the root password. So what am I not understanding or what am I doing wrong? I don't really need to disable the root account, but this is just a learning experience, and I'm not understanding why I still have access. See below:     # I needed to enable root access for something skunkbad:~$ sudo passwd root   # I did what I needed to do skunkbad:~$ sudo -i root@ubuntu-Inspiron-3647:~#   # I logout from root root@ubuntu-Inspiron-3647:~# logout   # I disable the root access per instructions from many internet references skunkbad:~$ sudo passwd -dl root   # Root access is still available, even if I close and reopen the terminal skunkbad:~$ sudo -i   # I logout from root root@ubuntu-Inspiron-3647:~# logout   # Trying to access root via su prompts for password, and old password is wrong skunkbad:~$ su Password: su: Authentication failure

This topic has been moved to Linux.

http://www.phpfreaks.com/forums/index.php?topic=307024.0

I am trying to do a loop which uses file_exists to check if an image exists and if so display it using the following code:

<?php
$i = 1;
while ($i <= 8) {

$filename = $img_loc . "/hovers-800px/" . $image . "-" . $i . ".jpg";

if (file_exists($filename)) {
?>
<a class="fuglybox" rel="gxr" href="<?php echo $filename; ?>"> <!--Main thumbnail image-->
      <img src="<?php echo $img_loc; ?>/product-detail-90px/<?php $image . "-" . $i . ".jpg"; ?>" alt="" width="90" height="90" /></a>
<?php

}

$i++;

}

?>

I have echoed out $filename to check my directory structure and filename is fine and copied the echoed directory out. The structure is however http://Http://www.xxxxxx.com/img/filename.jpg. Could this be whats causing the problem?

I've read as many previous posts as I can find and tried all the suggested solutions but the following simple test code will not work for me (the session variable has been echoed and is correct).   Instead of echoing the correct answer, the if(file_exists($target_file)) skips the true result and always displays the false one.  I've tested it with files that do and don't exist of course.  Here is the code :-

$filename = $_SESSION["filename"];
$target_file = $_SERVER['CONTEXT_DOCUMENT_ROOT'] . '/folder/' . $_SESSION["filename"];

if (file_exists($target_file)) {
    echo 'Selected file is ' . $filename . ' and will be written.';
} else {
    echo "Selected file " . $filename . " doesn't exist.";
} 

I'd really appreciate any help on this please.

Edited July 11, 2020 by oldcelt

<code>
$jpg_path = '../../../users/user_avatars/' . $_SESSION['the_user'] . '.jpg';
$jpeg_path = '../../../users/user_avatars/' . $_SESSION['the_user'] . '.jpeg';
$gif_path = '../../../users/user_avatars/' . $_SESSION['the_user'] . '.gif';
$png_path = '../../../users/user_avatars/' . $_SESSION['the_user'] . '.png';
$jpg_test = file_exists($jpg_path);
$jpeg_test = file_exists($jpeg_path);
$gif_test = file_exists($gif_path);
$png_test = file_exists($png_path);
</code>

the path is EXACTLY correct I've checked and rechecked and everything. echoed the path and everything else that is relevant. but later when I call if ($png_test == '1') {
blah blah blah
}
it won't return 1. even though I KNOW that the picture is there and it is at that path. if i echo the path in a src for an image it appears. hmm?

Hi,


I am trying to verify if the given url exists or not, by using file_exists() function.

It always returns 'FALSE' , according to my understanding it happening because the file to be checked on the given url is located in safe mode.

Could anyone please suggest as to how this could be overcome, by similar function or by using alternative method.

Regards
Abhishek Madhani

I want to get suggested keywords from yahoo api service. When xml file is empty (no keyword), it gives error. To resolve this problem I used this code:
if (file_exists('http://search.yahooapis.com/WebSearchService/V1/relatedSuggestion?appid=YahooDemo&query=Madonna&results=2')) {
$xmlmetades = simplexml_load_file('http://search.yahooapis.com/WebSearchService/V1/relatedSuggestion?appid=YahooDemo&query=Madonna&results=2');
}


Since it is not a normal .xml file, it is always considered no file, and return nothing.

I'm just trying to find out if php has the ability to check if any file exists, with only part of the filename given..

I have this path:

if (file_exists($dir.'/'.$c_file.'/templ_*')) {

I added a little star.. That star represents whatever the rest of that file is named for this example.. It could be anything.. So can php match any files that start with "templ_", and say that it does or does not exist??

Thanks

Hello all,

I am a real newby to this but need some help with a file_exists / while loop issue i have.

I am trying to show a table of pictures (with their own ID's) but also if someone hasn't uploaded a picture to the server a default picture will be shown instead.

I get the error: Parse error: syntax error, unexpected T_VARIABLE, expecting ',' or ';' in /home/thefrien/public_html/members1.php on line 103

Here is my code:

$i = 1;
echo "<table border='1' align='center'><tr>";
$result = mysql_query( "SELECT * FROM membership order by L_ID asc" );
while ( $row = mysql_fetch_assoc( $result ) ) {
    echo "<td align='center' bgcolor='#DDDEFF'><a href='profile_view.php?L_ID=".$row["L_ID"] ."'>"
   $pic = 'images/avatar/'. $row["L_ID"] .'s.jpg';   
if (file_exists($pic)) {
   echo '<img src=http://www.thefriendzconnection.co.uk/images/avatar/'.$row["L_ID"] ."s.jpg>";
} else {
   echo '<img src=http://www.thefriendzconnection.co.uk/images/0s.jpg border='0'>';
}
   "</a>
   <br><font size='1' face='Arial, Helvetica, sans-serif'>".$row["name"] ."</font>
   <br><font size='1' face='Arial, Helvetica, sans-serif'>ID: ".$row["L_ID"] ."</font>
   <br>&nbsp;</td>";
    if ( $i % 6 == 0 ) { echo "</tr><tr>"; }
    $i++;
}
mysql_free_result( $result );
echo "</tr></table>";



The line I am having issues with seems to be: $pic = 'images/avatar/'. $row["L_ID"] .'s.jpg';

Any suggestions would be greatfully received

Thanks.

I'm working on a WordPress theme and I'm trying to build in a simple if statement which will check if the user has add his own logo into the images folder if he doesn't then the name of the blog will appear as normal text in place of the graphic logo.

This is how it looks like:


<?php

$logo_dir = get_template_directory_uri() . "/images/logo.png";

if (file_exists($logo_dir)) { ?>

<li><img src="<?php bloginfo ('template_directory'); ?>/images/logo.png" alt="<?php bloginfo('description'); ?>" /></li>

<?php } else { ?>

<li id='blog_name'><a href="<?php bloginfo('url'); ?>"><?php bloginfo('name'); ?><font>*</font></a></li>

<?php } ?>




I've echo'd out $logo_dir, the URL is correct, but still for some reason it's seeing it as if there would no file exist. If I turn it around into !file_exists then the graphic logo WILL show up. So it's always seeing it as non-existent.

Any ideas why this could be or am I using this function in a wrong fashion? As far as I've understood the PHP manual, this is the correct way of using it.

From my old gentoo server I run the following code with success. "/mnt/images" is a cifs mount!
Code: [Select]
<?php
$source = '/mnt/images/1001.jpg';
$target = '/tmp/1001.jpg';

if ( file_exists($source) )
echo "file_exists: TRUE<br/>";
else
echo "file_exists: FALSE<br/>";

if ( is_file($source) )
echo "is_file: TRUE<br/>";
else
echo "is_file: FALSE<br/>";

if ( copy($source, $target) )
echo "copy: TRUE<br/>";
else
echo "copy: FALSE<br/>";

echo "filesize source: ".filesize($source)."<br/>";
echo "filesize target: ".filesize($target)."<br/>";
?>The output is
Quote

file_exists: TRUE
is_file: TRUE
copy: TRUE
filesize source: 4715
filesize target: 4715

When I try this on my newly installed CentOS machine I get
Quote

file_exists: FALSE
is_file: FALSE

Warning: copy(/mnt/images/1001.jpg) [function.copy]: failed to open stream: Permission denied in /var/www/html/filetest.php on line 16
copy: FALSE

Warning: filesize() [function.filesize]: stat failed for /mnt/images/1001.jpg in /var/www/html/filetest.php on line 21
filesize source:

Warning: filesize() [function.filesize]: stat failed for /tmp/1001.jpg in /var/www/html/filetest.php on line 22
filesize target:

Every function fails. Then I found that when I disable SELinux with "echo 0 > /selinux/enforce" file_exists() and copy() works.
Quote

file_exists: TRUE
is_file: FALSE
copy: TRUE

Warning: filesize() [function.filesize]: stat failed for /mnt/images/1001.jpg in /var/www/html/filetest.php on line 21
filesize source:
filesize target: 4715

But is_file() and filesize() still doesn't work. They all work when I run them on local files so it is somewhat related to the cifs mount.
What could be the problem here?

Hi ppl

got code problem cant get it show users avatar & blank avatar at same time not that good at
php ppl.

avatar box page

Code: [Select]
<style type="text/css">
#name_area{height:20px; padding:3px;};
</style>
<script language="javascript">
<!--
function member_change(id){
<?php
$allgames = mysql_query("SELECT * FROM games") or die (mysql_error());
$allgames_total = @mysql_num_rows($allgames);
if($allgames_total!=0)
{
$i=0;
while($i<$allgames_total)
{
?>
document.getElementById('<?php echo mysql_result($allgames, $i, 'game_id'); ?>').style.display = "none";
<?php
$i++;
}
}
?>
document.getElementById(id).style.display = "block";
}
function show_name(name){

document.getElementById('name_area').innerHTML = name;
}
function hide_name(){
document.getElementById('name_area').innerHTML = '';
}
//-->
</script>

<div style="text-align:left;">
Choose Squad: <select name="D1" onchange="member_change(this.options[this.selectedIndex].value)" class="standardforms">
<?php
$allgames = mysql_query("SELECT * FROM games") or die (mysql_error());
$allgames_total = @mysql_num_rows($allgames);

if($allgames_total!=0)
{
$i=0;
while($i<$allgames_total)
{
$game = mysql_result($allgames, $i, 'game_title');
$members_total2 = mysql_num_rows(mysql_query("SELECT * FROM members WHERE game = '$game'"));

if($members_total2!=0)
{
?>
<option value="<?php echo mysql_result($allgames, $i, 'game_id'); ?>"><?php echo mysql_result($allgames, $i, 'game_title'); ?></option>
<?php
}
$i++;
}
}
?>
</select><br /><br />
</div>
<?php
$allgames = mysql_query("SELECT * FROM games") or die (mysql_error());
$allgames_total = @mysql_num_rows($allgames);
if($allgames_total!=0)
{
$i=0;
while($i<$allgames_total)
{
$game = mysql_result($allgames, $i, 'game_title');
$members = mysql_query("SELECT * FROM members WHERE game = '$game'");
$members_total = @mysql_num_rows($members);

if($allgames_total!=0)
{
?>
<div id="<?php echo mysql_result($allgames, $i, 'game_id'); ?>" style="display: block; text-align:left;">
<?php

if($members_total!=0)
{
$d=0;
while($d<$members_total)
{

?>
<a href="index.php?page=members&amp;id=<?php echo mysql_result($members, $d, 'id'); ?>"><img onmouseover="show_name('<?php echo mysql_result($members, $d, 'username'); ?>')" onmouseout="hide_name()" src="user/<?php

  echo mysql_result($members, $d, 'avatar_link');

$filename = 'avatar_link';

if (file_exists($filename)) {
     echo "avatar_link";
} else {
     echo "avatars/blank.jpg";
}


?>" width="50" height="50" alt="<?php echo mysql_result($members, $d, 'username'); ?>" title="<?php echo mysql_result($members, $d, 'username'); ?>"/></a>
<?php
$d++;
}
}
}
echo "</div>";
$i++;
}
}
?>
<div id="name_area"></div>