|
PHP - Unexpected Semicolon Error, Anyone Know Why?
I'm getting this error:
PHP Parse error: syntax error, unexpected ';' in [...] on line 44 This is line 44: $file_string .= ($article_id == count($xml->channel->item) ? '<a>></a>' : '<a href="#' . $article_id-1 . '">></a>'; EDIT: Nevermind, I found it! The parenthesis at the end, duh. Similar TutorialsParse error: syntax error, unexpected T_STRING in C:\xampp\htdocs\mywork\unique.php on line 15 <html> <head> <title> </title> </head> <body bgproperties="fixed"> <?php $dbhost = 'localhost'; $dbuser = 'root'; $dbpass = ''; $con = mysql_connect($dbhost, $dbuser, $dbpass) or die ('Error connecting to mysql'); $dbname = 'mywork'; mysql_select_db($dbname, $con); $sql=mysql_query(insert into users (regno,name,gender,date,month,year,emailid,cell,paddress,caddress,incometype,incomeamt,dad,fyes,dadocup,mom,myes,momocup,password) VALUES ('$_POST[regno]','$_POST[name]','$_POST[gender]','$_POST[date]','$_POST[month]','$_POST[year]','$_POST[emailid]','$_POST[cell]','$_POST[paddress]','$_POST[caddress]','$_POST[incometype]','$_POST[incomeamt]','$_POST[dad]','$_POST[fyes]','$_POST[dadocup]','$_POST[mom]','$_POST[myes]','$_POST[momocup]','$_POST[password]')"); $sql1=mysql_fetch_array($sql); $result = @mysql_query($SQl1); $result="SELECT * FROM users WHERE regno='$regno'"; while($row = mysql_fetch_array($result)) { //echo $row['regno']."regno<br>"; //echo $row['name']."name<br>"; //echo $row['gender']."gender<br>"; //echo $row['date']."date<br>"; //echo $row['month']."month<br>"; //echo $row['year']."year<br>"; //echo $row['emailid']."emailid<br>"; //echo $row['cell']."cell<br>"; //echo $row['paddress']."paddress<br>"; //echo $row['caddress']."caddress<br>"; //echo $row['incometype']."incometype<br>"; //echo $row['incomeamt']."incomeamt<br>"; //echo $row['dad']."dad<br>"; //echo $row['fyes']."fyes<br>"; //echo $row['dadocup']."dadocup<br>"; //echo $row['mom']."mom<br>"; //echo $row['myes']."myes<br>"; //echo $row['momocup']."momocup<br>"; //echo $row['password']."password<br>"; } echo "Thanks for Register!"; if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } echo "1 record added"; mysql_close($con); ?> <form name="security" action="index.php" method="post"> <input type="submit" value="click here to login"> </form> </body> </html> Code: [Select] <?php mysql_connect ("-","-","-") or die ('Error'); mysql_select_db ("-"); $out = mysql_query("SELECT * FROM guestbook ORDER BY id DESC"); while($row = mysql_fetch_assoc($out); --and this one if that braces is deleted { ----this is where im getting the error $name = $row['name']; $email = $row['email']; $txt = $row['comment']; $msg = "Are you sure you want to delete"; /* @var $_REQUEST <type> */ if (isset($_REQUEST ["action"]) && $_REQUEST["action"] == "del") { $id = intval($_REQUEST['id']); mysql_query("DELETE FROM guestbook WHERE id=$id;"); echo "<action=index.php>"; } echo "<font face='verdana' size='1'>"; echo "<table border='0'> <tr><td>Name: ".$name."</td></tr>"." <tr><td>Email: ".$email."</td></tr> <tr><td colspan='2'>Comment:</td></tr> <tr><td colspan='2' width='500'><b>".$txt."</b></td></tr> <tr><td><a onclick=\"return confirm('.$msg.');\" href='index.php?action=del&id=".$row['id']."'><span class='red'>["."Delete"."]</span></a> </td></tr> </table><br />"; echo "<hr size='1' width='500' align='left'></font>"; } ?> Kindly help me please. When i delete ({) the error will become the ( i dont know what to do already. Thanks. I have been trying to get my files to upload onto a computer and I receive this message: Parse error: syntax error, unexpected T_STRING in /home/content/19/6550319/html/listing.php on line 27. Line 27 is how the php logs into my SQL. The problem is that I was able to log in before. I just made changes to the form by adding a dropdown menu and price and now it says it doesnt parse. Can anyone figure this out. I will include the code without the login information because the forum is public but I did put the words left out for you to see where I took out the passcodes. Code: [Select] <?php //This is the directory where images will be saved $target = "potofiles/"; $target = $target . basename( $_FILES['photo']['name']); //This gets all the other information from the form $price=$_POST['price']; $gig=$_POST['giga']; $yesg=$_POST['yesg']; $pic=($_FILES['photo']['name']); $pic2=($_FILES['phototwo']['name']); $pic3=($_FILES['photothree']['name']); $pic4=($_FILES['photofour']['name']); $description=$_POST['iPadDescription']; $condition=$_POST['condition']; $fname=$_POST['firstName']; $lname=$_POST['lastName']; $email=$_POST['email'] // Connects to your Database mysql_connect ("left out", "left out", "left out") or die(mysql_error()) ; mysql_select_db("left out") or die(mysql_error()) ; //Writes the information to the database mysql_query("INSERT INTO listing (price,giga,yesg,photo,phototwo,photothree,photofour,iPadDescription,condition,firstName,lastName,email) VALUES ('$price', '$gig', '$yesg', '$pic', '$pic2', '$pic3', '$pic4', '$description', '$condition', '$fname', '$lname', '$email')") ; //Writes the photo to the server if(move_uploaded_file($_FILES['photo']['tmp_name'], $target)) { //Tells you if its all ok echo "The file ". basename( $_FILES['uploadedfile']['name']). " has been uploaded, and your information has been added to the directory"; } else { //Gives and error if its not echo "Sorry, there was a problem uploading your file."; } echo date("m/d/y : H:i:s", time()) ?> I don`t get it, waht is wrong?! Code: [Select] <?php require_once 'auth.php'; if (!isset($_SESSION['SESS_VERIFY'])) { header("location: access-denied.php"); exit(); } if ($_SESSION['lang'] == 'Ro') { // setare data romania date_default_timezone_set('Europe/Bucharest'); $today = getdate(); $zi = $today['mday']; $luna = $today['mon']; $lunastring = $today['month']; $an = $today['year']; $data = $zi.$luna.$an; $data = (string)$data; $ora = date('H:i:s'); $msg = array(); $err = array(); $luni = array ( 1=>'Ianuarie', 2=>'Februarie', 3=>'Martie', 4=>'Aprilie', 5=>'Mai', 6=>'Iunie', 7=>'Iulie', 8=>'August', 9=>'Septembrie', 10=>'Octobrie', 11=>'Noiembrie', 12=>'Decembrie'); // comun const SQL_ERR = 'SQL statement failed with error: '; const ADD_MODEL = 'ADAUGA UN MODEL NOU'; . .many constants.. . } elseif ($_SESSION['lang'] == 'It') {... Thank you! Hi folks, I am a complete n00b at php and mysql. I am teaching myself from books and the WWW, but alas I am stuck... the error I get is: Parse error: syntax error, unexpected T_STRING in X:\xampp\htdocs\search.php on line 7 here is the code: <?php mysql_connect ("localhost", "user", "password") or die (mysql_error()); mysql_select_db ("it_homehelp_test") or die (mysql_error()); $term = $_POST['term']; $sql = $mysql_query(select * from it_homehelp_test where ClientName1 like '%term%'); <<<------this is line 7 while ($row = mysql_fetch_array($sql)){ echo 'Client Name:' .$row['ClientName1']; echo 'Address:' .$row['Address1']; echo 'Phone:' .$row['Tel1']; } ?> Any help you can offer would be great. I can also post the ".html" file that creates the search bar if it is needed. Thanks
Hello everyone,
1 <?php
7 // Create connection
10 // Check connection
14 $firstname = $conn->real_escape_string($_REQUEST['firstname']); 25 $sql2 = "INSERT INTO countries VALUES ('$country')"; 27 $sql3 = "INSERT INTO Contacts (firstname, lastname, address, city, country, phone, email) VALUES ('$firstname', '$lastname', '$address', $city, $country, '$phone_number','$email')";
29 SELECT * FROM cities;
if($conn->query($sql2) === true){
if($conn->query($sql3) === true){ I just enabled error reporting and I am not that familiar with it. I know I have an error some where around line 33. I know I am missing a bracket or a comma or some other syntax error I just cannot find where the error is. Below is my script. Thanks for any help. Code: [Select] <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title>Airline Survey</title> <meta http-equiv="content-type" content="text/html; charset=iso-8859-1" /> <meta name="author" content="Revised by abc1234"/> </head> <body> <?php $WaitTime = addslashes($_POST["wait_time"]); $Friendliness = addslashes($_POST["friendliness"]); $Space = addslashes($_POST["space"]); $Comfort = addslashes($_POST["comfort"]); $Cleanliness = addslashes($_POST["cleanliness"]); $Noise = addslashes($_POST["noise"]); if (empty($WaitTime) || empty($Friendliness) || empty($Space) || empty($Comfort) || empty($Cleanliness) || empty($Noise)) echo "<hr /><p>You must enter a value in each field. Click your browser's Back button to return to the form.</p><hr />"; else { $Entry = $WaitTime . "\n"; $Entry .= $Friendliness . "\n"; $Entry .= $Space . "\n"; $Entry .= $Comfort . "\n"; $Entry .= $Cleanliness . "\n"; $Entry .= $Noise . "\n"; $SurveyFile = fopen("survey.txt", "w") } if (flock($SurveyFile, LOCK_EX)) { if (fwrite($SurveyFile, $Entry) > 0) { echo "<p>The entry has been successfully added.</p>"; flock($SurveyFile, LOCK_UN; fclose($SurveyFile); else echo "<p>The entry could not be saved!</p>"; } else echo "<p>The entry could not be saved!</p>"; } ?d> <p><a href="AirlineSurvey.html">Return to Airline Survey</a></p> </body> </html> This topic has been moved to PHP Applications. http://www.phpfreaks.com/forums/index.php?topic=344105.0 can't seem to find the error. helppp Parse error: syntax error, unexpected T_STRING, expecting ',' or ';' in /export/SOI-50/students/m2009/abhr428/web/WebIbs/view_user.php on line 20 <?php require_once( "common.inc.php"); require_once( "config.php" ); require_once( "users.class.php" ); require_once( "LogEntry.class.php" ); $userid = isset( $_GET["userid"] ) ? (int)$_GET["userid"] : 0; if ( !$user = user::getuser( $userid) ) { displayPageHeader( "Error" ); echo "<div>User not found.</div>; displayPageFooter(); exit; } $logEntries = LogEntry::getLogEntries( $userid ); displayPageHeader( "View user: ". $user->getValueEncoded( "usr_name") ." ". $user->getValueEncoded( "usr_surname") ); ?> <dl style="width: 30em;"> <dt>Username</dt> <dd><?php echo $user->getValueEncoded( "usr_username" ) ?></dd> <dt>First name</dt> <dd><?php echo $user->getValueEncoded( "usr_name" ) ?></dd> <dt> Last name</dt> <dd><?php echo $user->getValueEncoded( "usr_surename" ) ?></dd> <dt>Joined on</dt> <dd><?php echo $user->getValueEncoded( "usr_recordtime") ?></dd> <dt>Last time active</dt> <dd><?php echo $user->getValueEncoded( "usr_lastlogintime" ) ?></dd> </dl> <h2> Access Log </h2> <table cellspacing="0" style="width":30em; border: 1px solid #667;"> <tr> <th>Web Page</th> <th>Number of visits</th> <th> Last visit</th> </tr> <?php $rowCount = 0; foreach ~( $logEntries as $logEntry ) { $rowCount++; ?> <tr<?php if ( $rowCount % 2 == 0 ) echo ' class="alt"' ?>> <td><?php echo $logEntry->getValueEncoded( "pageUrl" ) ?></td> <td><?php echo $logEntry->getValueEncoded( "numVisits") ?></td> <td><?php echo $logEntry->getValueEncoded( "lastAccess") ?> </td> </tr> <?php </table> <div style="width: 30em; margin-top: 20px; text-align: center;"> <a href="javascript:history.go(-1)">back</a> </div> <?php displayPageFooter(); ?> sorry this was the actuall php code for this error... <?php require_once "DataObject.class.php"; class LogEntry extends DataObject { protected $data = array( "userid" => "", "pageUrl" => "", "numVisits" => "", "lastAcces" => "", ); public static function getLogEntries( $userid ) { $conn = parent::connect(); $sql = "SELECT * FROM " . TBL_accesslog . " WHERE userid = : userid ORDER BY lastAcces DESC"; try { $st = conn->prepare( $sql ); $st->bindValue( ":userid", $userid, PDO::PARAM_INT ); $st->execute(); $logEntries = array(); foreach ( $st->fetchAll() as $row ) { $logEntries[] = new logEntry( $row); } parent::disconnect( $conn ); return $logEntries; } catch ( PDOExeception $e ) { parent::disconnect( $conn ); die( "Query failed: " . $e->getMessage() ); } } } ?> i keep getting the above error.. help this is a class of the log entry <?php require_once "config.php"; abstract class DataObject { protected $data = array(); public function__construct( $data ) { foreach ( $data as $key => $value ) { if ( array_key_exists( $key, $this->data )) $this->data[$key] = $value; } } public function getValue( $field ) { if ( array_key_exists( $field, $this->data )) { return $this->data[$field]; } else { die( "field not found" ); } } public function getValueEncoded( $field ) { return htmlspecialchars( $this->getValue( $field )); } protected function connect() { try { $conn = new PDO(DB_DSN, DB_USERNAME, DB_PASSWORD ); $Conn->setAttribute( PDO::ATTR_PERSISTENT, true ); $conn->setAttribute( PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION ); } catch ( PDOException $e->getMessage() ); die( "connection failed: " . $e->getMessage() ); } return $conn; } protected function disconnect( $conn ) { $conn = ""; } } ?> I am getting syntax error, unexpected T_CONSTANT_ENCAPSED_STRING on the date stamp line below but I can't see what is causing the problem. when I comment it out the problem goes away so I know I it is there. please help. $email_message = "Form details below.\n\n"; $email_message = date("m/d/Y")"\n"; Code: [Select] <?php if (!isset($_POST['submit'])) { ?> <h2>Todays Special</h2> <p> <form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post"> <select name="day"> <option value="1">Monday/Wednesday <option value="2">Tuesday/Thursday <option value="3">Friday/Sunday <option value="4">Saturday </select> input type="submit" name="submit" value="Go"> </form> <?php // get form selection $day = $_POST['day']; // check value and select appropriate item switch ($day) { case 1: $special = 'Chicken in oyster sauce'; break; case 2: $special = 'French onion soup'; break; case 3: $special = 'Pork chops with mashed potatoes and green salad'; break; default: $special = 'Fish and chips'; break; } ?> I have been getting that error and I cannot figure out why it is happening Here is the error: Parse error: syntax error, unexpected T_ENDWHILE, expecting ',' or ';' in /home/scswc188/public_html/index.php on line 23 Here is my Code (Database Credentials removed for obvious reasons) <?PHP // Conect to the Mysql Server $connect = mysql_connect("IP","USER","PASS"); //connect to the database mysql_select_db("TABLE"); //query the database $query = mysql_query("SELECT * FROM users_online WHERE online = 1"); // fetch the results / convert into an array WHILE($rows = mysql_fetch_array($query)): $users = $rows['name']; echo "'<font color='black'>Online:<font color='green'>$users, </font></font>;" endwhile; ?> or here http://pastebin.com/ZYh4t2pD Thanks Edit: Found the php tag Hey Everyone, I'm getting this error when I submit my contact form. Parse error: syntax error, unexpected $end in /home1/user/public_html/contact/process.php on line 22 I got this code from a video on youtube. http://www.youtube.com/watch?v=rdsz9Ie6h7I If I made a mistake or TYPO please let me know. Thanks! Here's my code: <?php $emailSubject = 'Contact Form Submission'; $sendto = 'info@mydomain.com'; $nameField = $_Post['name']; $emilField = $_Post['email']; $phoneField = $_Post['phone']; $SubjectField = $_Post['subject']; $messageField = $_Post['message']; $body = <<<EOD <br><hl><br>This Form was submitted from the Domain.com contact page.<br> Name: $name<br> E-Mail: $email<br> Phone: $phone<br> Subject: $subject<br> Message: $message<br> BOD; $headers = "FROM: $email\r\n"; $headers .="Content-Type: text/html\r\n"; $success = mail($sendto, $emailSubject, $body, $headers); ?> <?php require_once('nusoap.php'); $soap_server = 'http://www.domain.com/api/api.cfc?wsdl'; $client = new soapclient($soap_server); $client->call() $params = array('user' => 'username@domain.com', 'password' => 'PASSWORD'); $return_string = $client->call('getKey', $params); print_r($return_string); $subId = 'XXXXXX'; $params = array('keyStr' => $keyStr, 'subId' => $subId); $return_string = $client->call('getTodaySubIDStats', $params); print_r($return_string); unset($client); ?> spits out Parse error: syntax error, unexpected T_VARIABLE in /home/site82/public_html/stats.php on line 12 Line 12 is... $params = array('user' => 'username@domain.com', |
|||||||