PHP - Repeating Mysql Stored Data
sorry if i have posted this in the wrong place, wasnt sure wether to post here or mysql.
I have made a php calendar, and i am now wanting it to show if there is an event on that day and if so show it in a tool tip. the tool tip is populated by what is in the title="" of the link so i need my events to be shown in there. I have figured out how to show the event but now i am stuck on how to show all events if there is more than one one that day, how i have set it seems to only the second event, probably as the second variable overwrote the first variable. this is the code i have at the minute .............. $result = mysql_query("SELECT * FROM events WHERE day='$day_num' AND month='$fullmonth' AND year='$year'") or die(mysql_error()); $rows= mysql_num_rows($result); if ($rows !="false"){ while($rowout = mysql_fetch_array($result)) { $todayis = $rowout['day'] ."-". $rowout['month'] ."-". $rowout['year'] ."<br>"; $title= $rowout['event'] ."<br><br>";} $firstl = "<a href='' title='". $todayis . $title ."'>"; $lastl = "</a>";} else {$firstl = ""; $lastl = "";} then to display the day and links ................. Code: [Select] <td><? echo $firstl; ?><? print $day_num; ?><? echo $lastl; ?></td> could some one be so kind and help me write it so that it displays all events? here is a link to the calendar, incase its needed. http://www.scripttesting.htmlstig.com/calendar/index.php Many thanks Carl Similar TutorialsOften times I need to convert between PHP Arrays, MySQL, XML, JSON sqlite etc. Lately I've been just building PHP arrays with all the data. Its a big hassle though when theres a lot of data. I'm thinking I should have one central location that I store data in, then export to other formats from there, but I dont know what that central location should be. I like MySQL because I'm used to it. Sometimes its not an option though, like if I need to make a really light script, I dont want the hassle of connecting to MySQL. Would XML be the best place to store data, then from the XML file I can convert it to whatever format I want?
Hey Guys, I have got 3 chained select boxes working. Basically what you do is check for a region with the country, then once you pick a region, you select a club within that region. Once you have selected the club, you can then choose a team from within that club. Screenshot: Attchment As part of this chained select boxes's, a user can register. Although, the user has to FIRST check if the TEAM has already been registered in the database. I have taken a screenshot of my database, which shows the regions, clubs, and teams from the chained select boxes. What i want to do now is be able to check if a TEAM is already registered in the database. So as you can see in the database, the team 'NPOB, Senior As' has already been taken. Database Screenshot: Attachment *** How do i check if a user has been registered to one of the teams? And if there is not a registered user to that team, they can then register it. Here is my code: <?php include"database.php"; ?> <script type="text/javascript"> /* Triple Combo Script Credit By Philip M: http://www.codingforums.com/member.php?u=186 Visit http://javascriptkit.com for this and over 400+ other scripts */ var categories = []; categories["startList"] = ["Taranaki","Auckland"] // Regions + Clubs categories["Taranaki"] = ["NPOB","Tukapa"]; categories["Auckland"] = ["Marist","Takapuna"]; // Clubs + Teams within that Club categories["NPOB"] = ["Senior As","Senior Bs","Colts U21s"]; categories["Tukapa"] = ["Senior As","Senior Bs","Colts U21s"]; categories["Marist"] = ["Senior As","Senior Bs","Colts U21s"]; categories["Takapuna"] = ["Senior As","Senior Bs","Colts U21s"]; var nLists = 3; // number of select lists in the set function fillSelect(currCat,currList){ var step = Number(currList.name.replace(/\D/g,"")); for (i=step; i<nLists+1; i++) { document.forms['tripleplay']['List'+i].length = 1; document.forms['tripleplay']['List'+i].selectedIndex = 0; } var nCat = categories[currCat]; for (each in nCat) { var nOption = document.createElement('option'); var nData = document.createTextNode(nCat[each]); nOption.setAttribute('value',nCat[each]); nOption.appendChild(nData); currList.appendChild(nOption); } } // function getValue(L3, L2, L1) { // alert("Your selection was:- \n" + L1 + "\n" + L2 + "\n" + L3); // } function init() { fillSelect('startList',document.forms['tripleplay']['List1']) } navigator.appName == "Microsoft Internet Explorer" ? attachEvent('onload', init, false) : addEventListener('load', init, false); </script> <form name="tripleplay" action="testingdropdown.php" method="post"> <select name='List1' onchange="fillSelect(this.value,this.form['List2'])"> <option selected>Choose Region</option> </select><br /><br /> <select name='List2' onchange="fillSelect(this.value,this.form['List3'])"> <option selected>Choose Club </option> </select><br /><br /> <select name='List3' onchange="getValue(this.value, this.form['List2'].value, this.form['List1'].value)"> <option selected >Choose Team </option> </select> <input type="submit" name="tripleplay" value="Register"> </form> <?php if (isset($_POST['tripleplay'])) { $region = addslashes(strip_tags($_POST['List1'])); $club = addslashes(strip_tags($_POST['List2'])); $team = addslashes(strip_tags($_POST['List3'])); $email = 'email'; $check = mysql_query("SELECT * FROM managers WHERE email='$email'"); if ($email == '') { echo "You can register that club"; } else { echo "Sorry that team has already been registered"; } } ?> hey guys i have this code FILE NAME "index.php" Code: [Select] <?php // make a connection to the database mysql_connect ("localhost", "root", "vertrigo") or die ('Error: I Failed To Connect To The Database ' . mysql_error()); mysql_select_db ("test"); // Get Data $query = mysql_query("SELECT * FROM TestTable"); // display the data and loop while ($row = mysql_fetch_array($query)) { echo "<br /> ID: ".$row['ID']."<br /> First Name: ".$row['FName']."<br /> Last Name: ".$row['LName']."<br /> Contact Number: ".$row['CNumber']."<br />";} ?> <form method="post" action="update.php"> <table border="1" align="center"> <tr> <td align="right" width="220">ID: </td> <td align="left" width="220"> <input type="text" name="ID" size="30" /></td> </tr> <tr> <td align="right" width="220">First Name: </td> <td align="left" width="220"> <input type="text" name="FName" size="30" /></td> </tr> <tr> <td align="right" width="220">Last Name: </td> <td align="left" width="220"> <input type="text" name="LName" size="30" /></td> </tr> <tr> <td align="right" width="220">Contact Number: </td> <td align="left" width="220"> <input type="text" name="CNumber" size="30" /></td> </tr> <tr> <td align="right" width="220"><input type="reset" value="Reset" /> </td> <td align="left" width="220"> <input type="submit" value="Update Database" /></td> </tr> </table> </form> and i also have this code FILE NAME "update.php" Code: [Select] <?php $ID = $_POST['ID']; $FName = $_POST['FName']; $LName = $_POST['LName']; $CNumber = $_POST['CNumber']; mysql_connect ("localhost", "root", "vertrigo") or die ('Error: I Failed To Connect To The Database ' . mysql_error()); mysql_select_db ("test"); $query="INSERT INTO testtable (ID, FName, LName, CNumber)VALUES ('".$ID."','".$FName."', '".$LName."', '".$CNumber."')"; mysql_query($query) or die ('Error Updating Database'); echo "Database Updated Sucsessfully With: ".$ID." ".$FName." ".$LName." ".$CNumber ; ?> ok so the script is working like a charm its sending the data to the database as i want it to. the problem i have is that i want to be able to update the info that is already on the database lets say i want to change a phone/contact number i have typed the ID number into the ID text field and the same first and last name into there correct boxes and then typed in the new phone number i then click submit and i get the error ""Error Updating Database"" i have looked all over the forum and net to see what i have done wrong to not allow this code to update can anyone help me out here please im quite new to the php language and could really do with some pointers thanks Steve i want the name of a picture stored in my db after i upload it the data is not stored in the db after i run this script, but i dont get errors either i print the two vars before sending them, and they get printed fine any help on this would be greatly appreciated thanks ! <?php error_reporting(E_ALL); ini_set("display_errors", 1); // INCLUDE THE CLASS FILE include('ImageLib.Class.php'); include("./includes/egl_inc.php"); $displayMessage = ''; if($_POST){ if(isset($_FILES['image_file'])){ // SEE THE MAGIC HAPPEN $destination_path = 'uploads/'; $post_file_name = 'image_file'; $width = 600; $height = 400; $scale = false; $trim = true; $uniqueName = true; $img = ImageLib::getInstance()->upload($post_file_name, $destination_path, $uniqueName)->resize($width, $height, $scale, $trim)->save(); $imgstr = mysql_real_escape_string ($img); $fileName = $_FILES['image_file']['name']; $displayMessage = '<div class="image"><img src="'.$destination_path.$fileName.'" /><br />Uploaded And Resized...With new file name : "'.$img.'"</div><br /><br />'; $playerid=$_SESSION['tid']; $matchdetails = mysql_fetch_array(mysql_query("SELECT id FROM ffa_matches WHERE status=2 and admin=$playerid")); $id = $matchdetails[id]; print $img;print $imgstr; print $id; mysql_query(" INSERT INTO ffa_screens (imgname,match) VALUES( '" . mysql_real_escape_string($imgstr) . "', '" . mysql_real_escape_string($id) . "' )"); }} ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html> <head> <title>ImageLib Samples By Rahul Kate</title> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <style> body{font-family: arial; font-size:12px; color:#444444; padding:20px;} li{margin-top:10px;} .image{color:green;} .image img{margin-bottom:5px;} </style> </head> <body> <h1>ImageLib | Upload Image, move it to Uploads folder and Resize it and Trim</h1> <?php echo $displayMessage; ?> <form method="post" enctype="multipart/form-data"> Select Image<br /> <input type="file" name="image_file" id="image_file" /> <br /> <br /> <input type="submit" name="submit" value="Submit" /> <br /> <br /> <a href="index.html">Back TO Home</a> </form> </body> </html> I have stored supplier information in a table and same form user will select multiple products for that supplier and that will be stored in a seperate table against that supplier id. Now when i would like to display all supplier information with muliple products in a single line. Now all the information will be displayed as many time as the products are. How to display all the products in a same line.
Now my display is like this
if(isset($_POST['submit']) && ($_POST['vendor']!='') && ($_POST['item']!='')) { $sql="SELECT supplier.id AS sid, supplier.name AS SNAME, supplier.category, supplier.website, supplier.email, supplier.phone, supplier.vat, supplier.pan, supplier_location.id, supplier_location.supplier_id, supplier_location.location, supplier_products.id, supplier_products.supplier_id, supplier_products.product_id, location.loc_id, location.name AS locname, products.product_id, products.name AS pname FROM supplier INNER JOIN supplier_location ON supplier.id = supplier_location.supplier_id INNER JOIN supplier_products ON supplier.id=supplier_products.supplier_id INNER JOIN location ON supplier_location.location = location.loc_id INNER JOIN products ON supplier_products.product_id=products.product_id WHERE supplier.id=".$sup." AND supplier_products.product_id=".$product; $sql1 = mysql_query($sql) or die(mysql_error()); <table> <thead><tr> <th>Vendor ID</th> <th>Vendor</th> <th>Category</th> <th>Website</th> <th>Email</th> <th>Phone</th> <th>Products</th> <th>Locations</th> <th>VAT</th> <th>PAN</th> </tr> </thead> <tbody> <tr> <?php while($row = mysql_fetch_array($sql1)) { ?> <td><?php echo $row['sid'] ?></td> <td><?php echo $row['SNAME'] ?></td> <td><?php echo $row['category'] ?></td> <td><?php echo $row['website'] ?></td> <td><?php echo $row['email'] ?></td> <td><?php echo $row['phone'] ?></td> <td><?php echo $row['iname']; ?></td> <td><?php echo $row['locname']; ?></td> <td><?php echo $row['vat'] ?></td> <td><?php echo $row['pan'] ?></td> </tr> <?php } ?> </tbody></table> } Hi Guys, I have a webpage which has subsequent pages stored in a database e.g. index.php?id=1 The problem being, is that id=1 has it's data pulled from a database. This was fine & dandy until I started to insert PHP...I am trying to get the below to executre <?php $rater_id=1; $rater_item_name='Rate This'; include("rater.php");?> However nothing shows & nothing happens, I know eval can be used but have not been succesfull in implementing this, can someone please help! Hello coders, I'm using this code to grab random results from a table and it works well but I need it to be a non-repeating event. Code: [Select] $offset_result = mysql_query( " SELECT FLOOR(RAND() * COUNT(*)) AS `offset` FROM `jobs_board` "); $offset_row = mysql_fetch_object( $offset_result ); $offset = $offset_row->offset; I'm using this query followed by the html which is a set of divs with inline echo statements for the various variables I've localised from the table. Then I'm repeating that process a number of times to create a small list (I wanted to use a single while loop but cant figure it out at the moment). Anways, how can I make it so each query is random but also not repeated? At the moment they are indeed random but sometimes one same entry will appear a number of times consecutively... Nice one guys, L-plate Please check the img link and you will understand Code: [Select] for ($index = 1; $index <= $numdays; $index++) { $users="SELECT invoice_date, DAY(invoice_date) as invoiceday, sum(total_amount) as fullamount from invoices WHERE MONTH(invoice_date)='".$month."' AND YEAR(invoice_date)='".$year."' GROUP BY invoiceday"; $res=mysql_query($users); $row=mysql_num_rows($res); while($fetch=mysql_fetch_array($res)){ echo "<tr id='". ( ( $j %2 == 0 ) ? 'row3' : 'row4' ) . "'>"; $explodedate=explode("-",$fetch['invoice_date']); $days=$explodedate[2]; $month1=$explodedate[1]; $year1=$explodedate[0]; $dates=date("jS", strtotime($fetch['invoice_date'])); echo "<td style='text-align:left;padding-left:12px'>".$index."</td>"; if($index==$dates){ echo "<td style='text-align:right;padding-right:12px'>".$fetch['fullamount']."</td>"; }else{ echo "<td style='text-align:right;padding-right:12px'>--</td>"; } echo "</tr>"; } } $total="SELECT SUM(total_amount) as fulltotal from invoices where MONTH(invoice_date)='".$month1."' AND YEAR(invoice_date)='".$year1."';"; $totres=mysql_query($total); $totfetch=mysql_fetch_assoc($totres); if($totfetch['fulltotal']==""){ echo "<tr><td>NOTHING FOUND</td></tr>"; }else{ ECHO "<TR>"; echo "<td style='color:#BD0000;padding-left:12px;border:1px solid #ccc;width:20%;height:40px;text-align:left'>TOTAL AMOUNT FOR ".$displaydate."</td>"; echo "<td style='color:#BD0000;border:1px solid #ccc;width:20%;height:40px;text-align:right;padding-right:12px'>".$totfetch['fulltotal']."</TD></TR>"; } echo "</table>"; Hi! I was wondering if there is a way to execute php code which is stored in mysql database using php. At the minute I am using a echo to try and run php code stored in a mysql database but this just displays the code and does not run the php code. Thanks for any help! Hi Please take a look at my code snippet. I don't know how to get the number of rows returned from a MySQL stored procedure so that I can handle it accordingly. Any ideas please? Thanks I'll walk you first through what is working: <?php echo($user['biz_site'] != '' ? "<h4>Web Site</h4>" . $user['biz_site'] : ""); ?> In a results page, the code renders something that looks like: Quote Web Site http://www.somecoolsite.com What I'd like instead is something like this: Quote Web Site Visit Site ...where the "visit site" links to the site. I'm trying to address a problem of some sites, especially government sites, having 75+ character-long addresses, which messes up the finite space I have allotted for site addresses. Everything I've tried thus far has rendered blank white pages. (the original code posted up top does not produce a hyperlink) Hello, First post here! I am using a script to store small files into a database. I know it is not highly recommended but this is the only solution I can find in this case. All seems fine when inserting but when retrieving all documents are corrupt. I am working with PHP 5 on Windows server. Part script after upload: (the document is uploaded to the server first and this is working fine) Code: [Select] if (!empty($_FILES)) { $folder = "kenya/docs_temp/";//including last / $tempFile = $_FILES['Filedata']['tmp_name']; $targetPath = dirname(__FILE__); $targetPath = substr($targetPath,0,strrpos($targetPath, "uploadify")). $folder; $targetFile = str_replace('\\','/',$targetPath) . $_FILES['Filedata']['name']; $fileName = $_FILES['Filedata']['name']; $tmpName = $_FILES['Filedata']['tmp_name']; $fileSize = $_FILES['Filedata']['size']; $fileType = $_FILES['Filedata']['type']; $conn=odbc_connect('xxx','xxx','xxxx'); $content = file_get_contents($tmpName,true); $content = addslashes($content); if(!get_magic_quotes_gpc()){ $fileName = mysql_real_escape_string($fileName); } $file_info = pathinfo($_FILES['Filedata']['name']); $addDoc = "INSERT INTO tblfiles (file_name,file_type,file_size,file_content,file_extension) VALUES ('".addslashes($fileName)."','".$fileType."','".$fileSize."','".$content."','".$file_info['extension']."')"; odbc_exec($conn,$addDoc); } The the script to retrieve and output to the browser: Code: [Select] $conn=odbc_connect('xxxx','xxx','xxxx'); //get the document $getF = "SELECT * FROM tblfiles WHERE userId = '".$_GET['userId']."' AND fileId = '".$_GET['fileId']."'"; $rsF = odbc_exec($conn,$getF); $size = floor(odbc_result($rsF,'file_size')); $type = odbc_result($rsF,'file_type'); $name = odbc_result($rsF,'file_name'); $content = odbc_result($rsF,'file_content'); ob_end_clean(); header("Content-length: ".$size.""); header("Content-type: ".$type.""); header('Content-Disposition: attachment; filename="'.$name.'"'); echo $content; And finally here is the structure for the table: Code: [Select] CREATE TABLE `tblfiles` ( `fileId` int(11) NOT NULL auto_increment, `userId` int(11) NOT NULL, `file_name` varchar(100) NOT NULL, `file_type` varchar(100) default NULL, `file_size` int(11) default NULL, `file_content` mediumblob, `file_extension` varchar(50) NOT NULL, PRIMARY KEY (`fileId`) ) ENGINE=InnoDB AUTO_INCREMENT=6 DEFAULT CHARSET=latin1 AUTO_INCREMENT=6 ; many thanks for any assistance. Okay, so here is the deal. Have a table which stores image as blob files. Now i want to read the image width and height directly from the blob field. Is this possible and if yes, how? Things i tried so far; list($size[0],$size[1],$type, $attr) = getimagesize('image.php?i=26ddd45b02859e836d13d4b9fde34281'); print_r($size); $img = 'image.php?i=26ddd45b02859e836d13d4b9fde34281'; echo imagesy($img); image.php grabs the image from DB and show's it with header("Content-type: image/jpg"); It works for just showing the images with the <img> tag. Any ideas of help would be great! Hi all: I have been going nuts trying to get this to work. I have gone through many attempts based on internet searches and examples that simply do not work. I have files stored in my MySQL db. The files cna be of any type and are being displayed in a listed report. The files are hyperlinked and clickable, but here is the issue: When I click on a file in: http://development.products-and-services.ca/cms/test.php I get: http://development.products-and-services.ca/cms/test2.php?content=DHall_CV_webdev_eng.pdf as a blank page result. The objective is to get a file download alert or to see the file in the browser. Any ideas? Hi All, I need to subtract dates and display the number of days left. I have a 'Start' date and an 'End' date in DATETIME format in the DB. Not quite sure where to start. A simply start - end doesn't work . Start = 2011-11-01-00:00:00 End = 2011-11-30-23:59:59 Since it is now 2011-11-27, my output should equal 3. Any help is appreciated. Hello to all, I have problem figuring out how to properly display data fetched from MySQL database in a HTML table. In the below example I am using two while loops, where the second one is nested inside first one, that check two different expressions fetching data from tables found in a MySQL database. The second expression compares the two tables IDs and after their match it displays the email of the account holder in each column in the HTML table. The main problem is that the 'email' row is displayed properly while its while expression is not nested and alone(meaning the other data is omitted or commented out), but either nested or neighbored to the first while loop, it is displayed horizontally and the other data ('validity', 'valid_from', 'valid_to') is not displayed.'
Can someone help me on this, I guess the problem lies in the while loop? <thead> <tr> <th data-column-id="id" data-type="numeric">ID</th> <th data-column-id="email">Subscriber's Email</th> <th data-column-id="validity">Validity</th> <th data-column-id="valid_from">Valid From</th> <th data-column-id="valid_to">Valid To</th> </tr> </thead> Here is part of the PHP code:
<?php while($row = $stmt->fetch(PDO::FETCH_ASSOC)) { echo ' <tr> <td>'.$row["id"].'</td> '; while ($row1 = $stmt1->fetch(PDO::FETCH_ASSOC)) { echo ' <td>'.$row1["email"].'</td> '; } if($row["validity"] == 1) { echo '<td>'.$row["validity"].' month</td>'; }else{ echo '<td>'.$row["validity"].' months</td>'; } echo ' <td>'.$row["valid_from"].'</td> <td>'.$row["valid_to"].'</td> </tr>'; } ?>
Thank you. This could be PHP or MySql so putting it in PHP forum for now... I have code below (last code listed) which processes a dynamically created Form which could have anywhere from 0 to 6 fields. So I clean all fields whether they were posted or not and then I update the mySQL table. The problem with this code below is that if, say, $cextra was not posted (i.e. it wasnt on the dynamically created form), then this code would enter a blank into the table for $cextra (i.e. if there was already a value in the table for $cextra, it gets overwritten, which is bad). What is the best way to handle this? I'm thinking i have to break my SQL query into a bunch of if/else statements like this... Code: [Select] $sql = "UPDATE cluesanswers SET "; if (isset($_POST['ctext'])){ echo "ctext='$ctext',"; } else { //do nothing } and so on 5 more times.... That seems horribly hackish/inefficient. Is there a better way? Code: [Select] if (isset($_POST['hidden']) && $_POST['hidden'] == "edit") { $cimage=trim(mysql_prep($_POST['cimage'])); $ctext=trim(mysql_prep($_POST['ctext'])); $cextra=trim(mysql_prep($_POST['cextra'])); $atext=trim(mysql_prep($_POST['atext'])); $aextra=trim(mysql_prep($_POST['aextra'])); $aimage=trim(mysql_prep($_POST['aimage'])); //update the answer edits $sql = "UPDATE cluesanswers SET ctext='$ctext', cextra='$cextra', cimage='$cimage', atext='$atext', aextra='$aextra', aimage='$aimage'"; $result = mysql_query($sql, $connection); if (!$result) { die("Database query failed: " . mysql_error()); } else { } Hi I am trying to select and order data/numbers from a colum in a mysql data base however i run the code and it returns no value just a blank page no errors or any thing so i think the code is working right but then it returns no result? Please help thanks Here is the code: <?php $host= "XXXXXX"; $mysql_user = "XXXXXX"; $mysql_password = "XXXXXX"; $mysql_database = "XXXXXXX"; $connection = mysql_connect("$host","$mysql_user","$mysql_password") or die ("Unable to connect to MySQL server."); mysql_select_db($mysql_database) or die ("Unable to select requested database."); $row = mysql_fetch_assoc( mysql_query( "SELECT XP FROM Game ORDER BY number DESC LIMIT 1" ) ); $number = mysql_result(mysql_query("SELECT XP FROM Game ORDER BY number DESC LIMIT 1"), 0); echo "The the highest XP is $number"; ?> hi guys, im new to this forum I'm new also to php, I need help from you guys: I want to display personal information from a certain person (the data is on the mysql database) using his name as a link: example: (index.php) names 1. Bill Gates 2. Mr. nice Guy i want to click Bill Gates (output.php) Name: Bill Gates Country:xxxx Age: xx etc. How can i make this or how to learn this? wrote a stored procedure this morning and i don’t know how to get the values out of it through a class function in php or phpmyadmin. here is what i wrote : public function totalProcedures($friend_name,$session_id) { /* *query to fetch stored procedure */ try { //executing the stored procedure $sql_sp="CALL timeline (:friend, :session,@updates, @group_posts)"; $stmt_sp= $this->_db->prepare($sql_sp); $stmt_sp->bindValue(":friend",$friend_name); $stmt_sp->bindValue(":session",$session_id); $stmt_sp->execute(); $rows=$stmt_sp->fetch(PDO::FETCH_ASSOC); $stmt_sp->closeCursor(); // closing the stored procedure //trying to get values from OUT parameters. $stmt_sp_2=$this->_db->prepare("select @updates,@group_posts"); $stmt_sp_2->execute(); return $stmt_sp_2->fetch(PDO::FETCH_ASSOC); } catch (PDOException $ei) { echo $ei->getMessage(); } } can someone helpme how to get results. here is the storedprocedu DELIMITER $$ CREATE DEFINER=`root`@`localhost` PROCEDURE `timeline`(IN `friend` VARCHAR(255), IN `session_id` VARCHAR(255), OUT `updates` VARCHAR(62555), OUT `group_posts` VARCHAR(62555)) BEGIN select * FROM updates where author in (friend,session_id) order by time desc limit 5; select * FROM group_posts where author_gp in (friend,session_id) order by pdate desc limit 5; END$$ DELIMITER ; i get the result in php myadmin as follows:
how do i do this inside a php class function. CALL timeline('shan2batman','aboutthecreator', @updates, @group_posts);
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