PHP - Unique Name For File

I append a string to a file by fwrite as

Code: [Select]
$str= 'dynamic text from each run';
$myFile = "testFile.txt";
$fh = fopen($myFile, 'a') or die("can't open file");
$stringData = "$str\n";
fwrite($fh, $stringData);
fclose($fh);
but I want to avoid duplicate to keep the file small. I want to avoid writing if the term is already saved in the file. I want to have a file containing unique lines.

I'm having a problem with getting the timestamp to attach to the filename.  Currently when it's uploaded in the database it says $timestamp in front of the filename instead of the time.

Scroll down towards the bottom of the code to see it.  Thanks for your help!


$username = $_GET['username'];
$item_id = $_GET['id'];

  define( 'DESIRED_IMAGE_WIDTH', 150 );
  define( 'DESIRED_IMAGE_HEIGHT', 150 );

  $source_path = $_FILES[ 'thumb' ][ 'tmp_name' ];
  $timestamp = time();

  //
  // Add file validation code here
  //

  list( $source_width, $source_height, $source_type ) = getimagesize( $source_path );

  switch ( $source_type )
  {
    case IMAGETYPE_GIF:
      $source_gdim = imagecreatefromgif( $source_path );
      break;

    case IMAGETYPE_JPEG:
      $source_gdim = imagecreatefromjpeg( $source_path );
      break;

    case IMAGETYPE_PNG:
      $source_gdim = imagecreatefrompng( $source_path );
      break;
  }

  $source_aspect_ratio = $source_width / $source_height;
  $desired_aspect_ratio = DESIRED_IMAGE_WIDTH / DESIRED_IMAGE_HEIGHT;

  if ( $source_aspect_ratio > $desired_aspect_ratio )
  {
    //
    // Triggered when source image is wider
    //
    $temp_height = DESIRED_IMAGE_HEIGHT;
    $temp_width = ( int ) ( DESIRED_IMAGE_HEIGHT * $source_aspect_ratio );
  }
  else
  {
    //
    // Triggered otherwise (i.e. source image is similar or taller)
    //
    $temp_width = DESIRED_IMAGE_WIDTH;
    $temp_height = ( int ) ( DESIRED_IMAGE_WIDTH / $source_aspect_ratio );
  }

  //
  // Resize the image into a temporary GD image
  //

  $temp_gdim = imagecreatetruecolor( $temp_width, $temp_height );
  imagecopyresampled(
    $temp_gdim,
    $source_gdim,
    0, 0,
    0, 0,
    $temp_width, $temp_height,
    $source_width, $source_height
  );

  //
  // Copy cropped region from temporary image into the desired GD image
  //

  $x0 = ( $temp_width - DESIRED_IMAGE_WIDTH ) / 2;
  $y0 = ( $temp_height - DESIRED_IMAGE_HEIGHT ) / 2;

  $desired_gdim = imagecreatetruecolor( DESIRED_IMAGE_WIDTH, DESIRED_IMAGE_HEIGHT );
  imagecopy(
    $desired_gdim,
    $temp_gdim,
    0, 0,
    $x0, $y0,
    DESIRED_IMAGE_WIDTH, DESIRED_IMAGE_HEIGHT
  );

  //
  // Render the image
  // Alternatively, you can save the image in file-system or database
  //

  header( 'Content-type: image/jpeg' );
  imagejpeg( $desired_gdim, "image_files/".'$timestamp'.$_FILES["thumb"]["name"] );
  
  
  
mysql_connect("localhost", "root", "", "") or die(mysql_error());
mysql_select_db("") or die(mysql_error());

$timestamp = time();
$item_image = '"$timestamp"'.$_FILES['thumb']['name'];
  
$sql="UPDATE product SET thumb='$item_image' WHERE id = '$item_id'";

 if (!mysql_query($sql))

  {

  die('Error: ' . mysql_error());

Hi,

I need some help in saving the filename along with the extension in the database after i upload the file.

Current Scenario:
I am able to upload the file successfully and save the form details in the database.

Problems:
When file uploaded with same file name it overwrites the old file.

How do i give the file a unique name when uploading the file and then saving the form details along with the new file name given?

CODE USED TO SAVE THE FILE TO MYSQL AND UPLOAD THE FILE:

<?php

//This is the directory where images will be saved
$target = "image/";
$target = $target . basename( $_FILES['photo']['name']);

//This gets all the other information from the form
$name=$_POST['name'];
$email=$_POST['email'];
$phone=$_POST['phone'];
$pic=($_FILES['photo']['name']);

// Connects to your Database
mysql_connect("localhost", "data_admin2", "data25") or die(mysql_error()) ;
mysql_select_db("Resumebank") or die(mysql_error()) ;


//Writes the photo to the server
move_uploaded_file($_FILES['photo']['tmp_name'], $target);


//Writes the information to the database
mysql_query("INSERT INTO `employee` VALUES ('$name', '$email', '$phone', '$pic')") ;
echo "The file has been uploaded, and your information has been added to the directory";
?>


What should I do? Please help!

I have a mysql table which will store users email addresses (each is unique and is the primary field) and a timestamp. 
I have added another column called `'unique_code' (varchar(64), utf8_unicode_ci)`.

What I would very much appreciate assistance with is;

a) Generating a 5 digit alphanumeric code, ie: 5ABH6 
b) Check all rows the 'unique_code' column to ensure it is unique, otherwise re-generate and check again 
c) Insert the uniquely generated 5 digit alphanumeric code into `'unique_code'` column, corresponding to the email address just entered. 
d) display the code on screen.

What code must I put and where?


**My current php is as follows:**

Code: [Select]
    require "includes/connect.php";
   
    $msg = '';
   
    if($_POST['email']){
   
    // Requested with AJAX:
    $ajax = ($_SERVER['HTTP_X_REQUESTED_WITH']  == 'XMLHttpRequest');
   
    try{
    if(!filter_input(INPUT_POST,'email',FILTER_VALIDATE_EMAIL)){
    throw new Exception('Invalid Email!');
    }
   
    $mysqli->query("INSERT INTO coming_soon_emails
    SET email='".$mysqli->real_escape_string($_POST['email'])."'");
   
    if($mysqli->affected_rows != 1){
    throw new Exception('You are already on the notification list.');
    }
   
    if($ajax){
    die('{"status":1}');
    }
   
    $msg = "Thank you!";
   
    }
    catch (Exception $e){
   
    if($ajax){
    die(json_encode(array('error'=>$e->getMessage())));
    }
   
    $msg = $e->getMessage();
    }
    }

Hello PHP freaks,   my codes dont allow me to log-in to Student Home with unique id. It says "Invalid Login or Password" this is my form

<tr bgcolor="#E1E1E1" class="stylesmall">
              <td width="35%" align="left" class="style7 style1">Learner Id : </td>
                <td width="65%" align="left"><input name="learner_id" type="text" id="learner_id" action="Student_Home.php" method="post"></td>
              </tr>
            <tr bgcolor="#E1E1E1" class="stylesmall">
              <td align="left" class="style7 style1">Password:</td>
                <td align="left"><input name="student_password" type="password" id="student_password"><
/td>

and this is my handler.

<?php
	session_start();
	include 'Connect.php';
	$flag = "";
	$learner_id = $_POST['learner_id'];
	$student_id = $_POST['student_id'];
	$student_password = $_POST['student_password'];
	$query = "select last_login_date from student_information where student_id='$student_id' and student_password='$student_password'";
	$result = mysql_query($query,$link_id);
	if(mysql_error() != null){
		die(mysql_error());
	}
	if($date = mysql_fetch_array($result))
	{
        $lastdate = $date['last_login_date'];
	$date2 = date("d-m-Y h:i A",strtotime($lastdate));
	$_SESSION["student_id"] = $_POST["student_id"];
        $_SESSION["lastlogin"] =$date2;
	$_SESSION["type"] = "Student";
	mysql_query("UPDATE student_information SET last_login_date=now() where student_id='$student_id'",$link_id);
	if(mysql_error() != null){
	die(mysql_error());
	}
	header("location:  Student_Home.php?id={$student_id}");
		 die();
	}
	else
	{
		$flag = "invalid";
		header("location:Student_login.php?flag=$flag");
		die();		
	} 	
?>

PLease help me PHP friends to correct my codes.