PHP - Get Content Of Website

I'm trying to make a League of Legends (a video game) community website, both as a personal project and for practice.
Now the game has a lot of champions, each of whom have 5 unique abilities. Now, I thought about manually inputting all the details about each champion into a MySQL database, but that would long and tedious, and I don't really have the time for it now. Also, the game patches very oftern (like, once every 2 weeks) which changes many of the stats, etc. of the champion, and it is not possible for me to keep manually updating these every time there is a patch.

Fortunately, there is a League of Legends Wiki which has all the data I need in their specific champion pages, which they keep updated per patch. So I was wondering if there was any way to get the data from the divs in the wiki, and have it display on my site. What I want to do in my website is that whenever someone types a champion's name (in a post or whatever), I want it to display a hover-over dialog with some of the champions details. And a lot of other features such as that.

In plain English I need a way to :
> Tell PHP to go to the wiki's source code on a specific page
> Find a specific div container
> Get X data from there
> Pass X data into a function to display the hover-over

I think this way, I would not have to maintain a database as I can leech off the wiki's data.
I have not coded anything like this before, so I would like a few pointers as to how to achieve this. Any help will be appreciated!

hello
My database is in a same server with seperate domain name , then I want to insert from website1 mysql data on website2 mysql data.
can anyone help me?

I tried searching on google but couldn't find any relevant information, please redirect me to relevant source or help me with the code.

I want to pass a domain name in text field which will be scanned and then the script will display entire site map.

Not external links or links on a page. Sorry it is not easy for me to explain.

Eg. if i pass abc.com

Script will display

abc.com/12/adn.php
abc.com/asd/asd/
etc

Whatever their url format is.

All the links on that domain.

This is the Code i am using.
This is show error:
Fatal error: Call to a member function item() on a non-object in /home/domain/public_html/forum/file/Test.php on line 35


Code: [Select]
<?php

  $xml=("http://www.vn-zoom.com/external.php?type=RSS2&forumids=77");
 

$xmlDoc = new DOMDocument();
$xmlDoc->load($xml);

//get elements from "<channel>"
$channel=$xmlDoc->getElementsByTagName('channel')->item(0);
$channel_title = $channel->getElementsByTagName('title')
->item(0)->childNodes->item(0)->nodeValue;
$channel_link = $channel->getElementsByTagName('link')
->item(0)->childNodes->item(0)->nodeValue;
$channel_desc = $channel->getElementsByTagName('description')
->item(0)->childNodes->item(0)->nodeValue;

//output elements from "<channel>"
echo("<p><a href='" . $channel_link
  . "'>" . $channel_title . "</a>");
echo("<br />");
echo($channel_desc . "</p>");

//get and output "<item>" elements
$x=$xmlDoc->getElementsByTagName('item');
$i=1; // $i = 1 to n (I use For here).
  {
  $item_title=$x->item($i)->getElementsByTagName('title')
  ->item(0)->childNodes->item(0)->nodeValue;
  $item_link=$x->item($i)->getElementsByTagName('link')
  ->item(0)->childNodes->item(0)->nodeValue;
  $item_desc=$x->item($i)->getElementsByTagName('description')
  ->item(0)->childNodes->item(0)->nodeValue;
  // If i remove this, it will work....////////////
$item_content=$x->item($i)->getElementsByTagName('content')
  ->item(0)->childNodes->item(0)->nodeValue;
/////////////////////////////////////////////////////
  echo ("<p><a href='" . $item_link
  . "'>" . $item_title . "</a>");
  echo ("<br />");
  echo ($item_desc . "</p>");
echo ("<br />");
  echo ($item_content . "</p>");
  }
?>

Please help me Fix this Code to Get content of Tag Name <content:encoded>
Thanks

Is it possible to download files from a website to my online websites root directory? reason I'm asking is because I have been downloading large video files to my computer which take about 20 minutes!! Then I use FTP to upload them to my site but it takes about 2-3 hours per video!! I was looking for a faster way! All help would be great!

I've used get_file_contents() before but it seems like it took a long time to load... what is the best or most efficient way to get certain content from a webpage? Like all the posts on a single forum page for example, without loading any images or styles, just the "source"

Hi all,
I have table, named: tb_event (id, f_date, f_title, f_image, f_status)
How to manage, while if 'f_status' from all records NOT EQUAL to 'Published' then show ABCDE
Note: on tb_event should be only the latest record (1 record only) that will be shown/published

I have code:

<?
$qry = mysql_query(
"SELECT * FROM tb_event WHERE f_status = 'Published'") or die(mysql_error());
while($res = mysql_fetch_array($qry))
{
if ($res[f_status] = "Published") {
   echo '
   <img src="images/uploads/'.$res[f_image].'" border="0" />
   ';
   }
   else
   {
   echo '
   ABCDE
   ';
   }
}
?>

The result is 'ABCDE' not shown while f_image (all records) is OFF 

Please help me.. thanks

There's many options available for downloading a URL - but I'm stuck.

I've looked through all the ones I know, but none seem to pay attention to partial content.

I'm trying to retrieve a URL that gives the following header:
HTTP/1.1 206 Partial Content
Content-Range:   bytes 0-100000/631723

As you can see it dishes out the file in 100,000 byte chunks.

Trouble is, when I use any method in PHP, ie file_get_contents, fopen, or even cURL, none of these continue on after retrieving the 100,000 bytes.

End result, I have a 100,000 byte file.

What I need is to get the PHP script to grab all the data, in the example above, all 631,723 bytes.

How can I do this?

Hi,

Say you had, <business_name type="string">L Choong</business_name>, contained inside a variable(content before and after this in the same var), how would you extract the 'L Choong' information as a new var?

Thanks

Hi all,

Maybe someone can help me with this, I am looking to copy specific content from one website to another automatically. So when ever one website updates the certain content the other site is automatically updated with it to. I have tried using file_get_contents but this wasnt working. Does anyone have any ideas? Im looking to copy https://annablais.scentsy.us/Home starting at line 270, the end is determined by how many Parties there are.

Thanks all

I have html files with this format
Code: [Select]
.....
<!--ImageSection--><div class="image"><!--ImageSection--><div align="top"><b>Image Link</b>
<br />http://www.something.com
<br />http://www.another_url
<br /></div><!--ImageEnd--></div><!--ImageEnd--></div>
.....
I tried to get the content of a <div> with this code:
Code: [Select]
preg_match_all('/<div class=\"image\">\<!--ImageSection-->\<div align=\"top\">([^`]*?)<\/div>/', $html, $imglinks);
foreach ($imglinks as $imglink){
echo $imagelink;
}
but it returns empty, where did I wrong? 

Hello,  

What I'm trying to figure out how to do is when its getting the content for the field it needs to get the ID of the field that way it can get the content of the field. I'm not sure what I'm doing wrong.

Code: [Select]
<?php require ('php/bios.php'); ?>

<script type="text/javascript" src="forms/edit/js/bios.js"></script>

<!-- Title -->
<div id="title" class="b2">
    <h2>Character Management</h2>
</div>
<!-- Title -->

<!-- Inner Content -->
<div id="innerContent">
   
    <form action="#" id="bioForm" >
        <?php 
            while ($row = mysqli_fetch_array($groupsResult, MYSQL_ASSOC)) {
                echo "<fieldset>
                <legend>" . $row['groupName'] . "</legend>";
                $fieldsResult = mysqli_query ( $dbc, sprintf($fieldsQuery,$row['ID']) );
                while ($row2 = mysqli_fetch_array($fieldsResult, MYSQL_ASSOC)) {
                   echo "<div class=field required>";
                   if ($row2['inputType'] == "text") {
                   echo "<label for=" . $row2['ID'] . ">" . $row2['fullName'] . "</label>";
                       echo "<input type=text name=" . $row2['ID'] . " id=" . $row2['ID'] . " class=text biofield title=" . $row2['fullName'] . " />";     
                   } elseif ($row2['inputType'] == "textarea") {
                       echo "<label for=" . $row2['ID'] . ">" . $row2['fullName'] . "</label>";
                       echo "<textarea name=" . $row2['ID'] . " id=" . $row2['ID'] . " class=textarea biofield title=" . $row2['fullName'] . " />";
                   } else {
                       echo "<label for=" . $row2['ID'] . ">" . $row2['fullName'] . "</label>";

echo "<select name=" . $row2['ID'] . " id=" . $row2['ID'] . " class=dropdown biofield title=" . $row2['fullName'] . " >";
echo "<option value= >None</option>";
if ($styleID == 1 || $styleID == 2 || $styleID == 6) {
                         $charactersQuery = "
                                SELECT 
                                    characters.ID, 
                                    characters.characterName 
                                FROM 
                                    characters 
                                WHERE 
                                    characters.styleID = 3
                                ORDER BY 
                                    characters.characterName";
}
else {
                         $charactersQuery = "
                                SELECT 
                                    characters.ID, 
                                    characters.characterName 
                                FROM 
                                    characters 
                                WHERE 
                                    characters.styleID IN (1,2,6)
                                ORDER BY 
                                    characters.characterName";
}

$charactersResult = mysqli_query ( $dbc, $charactersQuery ); // Run The Query

while ( $row3 = mysqli_fetch_array ($charactersResult, MYSQLI_ASSOC)) { 
   echo "<option value=" . $row3['ID'] . ">" . $row3['characterName'] . "</option>\r";
}

   echo "</select>";
}


                   echo "</div>";
                }
                echo "</fieldset>";
            } 
        ?>
        <fieldset>
            <input type="hidden" name="defaultCharID" id="defaultCharID" value="<?php echo $defaultCharID; ?>" />
            <input type="submit" class="submit" id="editBio" title="Edit Bio" value="Edit Bio" />
        </fieldset>
    </form>

</div>
<!-- /Inner Content -->

Code: [Select]
<?php

session_start(); // Access the existing session

// Include the database page
require ('../../inc/dbconfig.php');

$defaultCharID = $_SESSION['defaultCharID'];

$styleIDQuery = "
    SELECT
        characters.styleID
    FROM
        characters
    WHERE
        characters.ID = '" . $defaultCharID . "'";
$styleIDResult = mysqli_query ( $dbc, $styleIDQuery ); // Run The Query
$row = mysqli_fetch_array( $styleIDResult, MYSQL_ASSOC );
$styleID = $row[ 'styleID' ];

$groupsQuery = "
    SELECT 
        groups.* 
    FROM 
        groups 
    WHERE 
        groups.styleID = '" . $styleID . "'
    ORDER BY 
        groups.ID";
$groupsResult = mysqli_query ( $dbc, $groupsQuery ); // Run The Query

$fieldsQuery = "
    SELECT 
        fields.* 
    FROM 
        fields 
    WHERE 
        fields.styleID = '". $styleID . "' AND fields.groupID = '%d' AND fields.statusID = 1";
        
$fieldContent = "
    SELECT
        fieldsContent.*
    FROM 
        fieldsContent
    WHERE
        fieldsContent.characterID = '". $defaultCharID . "' AND fieldsContent.fieldID = = '". $fieldID ."'";        

?>

Hi, I am building function to convert the db table to an XML file. But I want to retrieve the root node value from the FIRST row in that db table before I build a for loop to traverse that db table.

Let's say I have this table NodeInfo:
node_Id     source   target
======    =====  =====
 1               email     to
 2               to          toFirstName

pseudocode for what I want:
1) store root (the source field of table NodeInfo
2)for each entry in table NodeInfo, do:
     build XML
   END FOR-EACH

Any help much appreciated!